'i University of California • Berkeley The Theodore P. Hill Collection Early American Mathematics Books cx/^. A ^.^ A- / / /. 93 as o M u 5 p c u p w H e M ■• P) P w M M o B o o o o o o o o o o o o o o o o o o 0) ■4-1 rt C )a ts I-** Has ca P w en o tic M .2 a Q B ^ H «.- (X C O c •S' r-« I Wr o 'td'-H ^ fM s 3 B V q£ rH >o i-H ■4-* OS c ■§ o c <^ ^ ^H *.? .2 ^ l-H t; rH " .• 05 t- s ^ g o 6 3 b. C C ^ O cd P4 .2 "< - a 01 - 1^ a> o 4> fa * NEW UNIVERSITY ARITHMETIC, EMBRACING THE SCIEJ^CE OF I^^UMBERS, AND TUEIR APPLICATIONS ACCORDIXG TO TIIK MOST I3IPKOVED METHODS OF ANALYSIS AND CANCELLATION. BY CHARLES DA VIES, LL. D., AUTHOR OF rnniAKT, INTELLECTUAL, AND SCHOOL ARITHMETICS ; ELEMENTART ALQEBUA ; ELEMENTARY GEOMETKY ; PRACTICAL MATHEMATICS : ELEMENTS OF SURVEYING ; ELEMENTS OF ANALYTICAL GEOMETRY ; DESCRIPTIVE GEOMETRY ; f-UADES, SHADOWS, AND PERSPECTIVE ; DIFFER- ENTIAL AND INTEGRAL CALCULUS ; AND LOGIC AND UTILITY OF MATHEMATICS. NEW YOrvK: PUBLISHED BY A . S. BARNES & CO., No. 51 & 53 .1 O I! \ - L^ T 11 E E T . 1858. Entered according to act of Congress, in the year eighteen hundred and fifty-six, BY CnATtLES DAVIES, In the Clerk's OfRce of the District Court of the United States, for the Southern District of New York. JONES & DENYSE, STEREOTYPErtS AND ELECTROTYPERS, 1S3 AViUiam-Strect. PEEFACE. Science, in its popular signification, means knoAA'ledga reduced to order ; that is, knowledge so classified and arranged, as to he easily remembered, readily referred to, and advanta- geously applied. Arithmetic is the science of numbers. It is the foundation of the exact and mixed sciences and a knowledge of it is an important element either of a liberal or practical education. While Arithmetic is a science in all that concerns the properties of numbers, it is an art in all that relates to their practical application. It is the first subject in a well-arranged course of instruction to which the reasoning powers of the mind are applied, and i? the guide-book of the mechanic and man of business. It is the first fountain at which the young votary of knowledge drinkf the pure waters of intellectual truth. It has seemed, to the author, of the first importance that this subject should be well treated in our Elementary Text Books. In the hope of contributing something to so desirable an end, he has prepared a series of arithmetical works, embracing luur books enthled, Primary Arithmetic ; Intellectual Arithmetics School Arithmetic; and University Arithmetic — the latter of which is the present volume. PuiMAny AraTKMETic. This first book is adapted to the capacities and wants of young children. Sensible objects are employed to illustrate and make familiar the simple combi- nations and relations of numbers. Each lesson embraces one combination of numbers, or one set of combinations. VI PEEFACE. Intellectual Arithmetic. This work is designed to pro- sent a thorough analysis of the science of numbers, and to form a complete course of mental arithmetic. It is thought to be accessible to young pupils by the simplicity and gradation of its methods, and to be particularly adapted to the wants of advanced students, as the attempt has been faithfully made to give the subjects of which it treats a scientific arrangement and logical connection in all the higher methods of arithmeti- cal analysis. School Arithmetic. Great pains has been taken in the preparation of this book to combine theory and practice ; to explain and illustrate principles, and to apply them to the common business transactions of life — to make it einjyhatically a 2y''(^ctical work. The student is required to demonstrate every principle laid down, by a course of mental reasoning, before deducing a proposition or making a practical application of a rule to examples. He is required to fix upon the U7tit or unity as the bane of all numbers, whether integral or frac- tional — to reason with constant reference to this base, and thus make it the key to the solution of all arithmetical questions. It is thought, that the language used in the statement of princi- ples, in the definitions of terms, and in the explanation of methods, will be ibund to be clear, exact, brief and compre- hensive. Univeksity Auitiimetic. This work is designed to answer another object. Here, the entire subject is treated as a science. The scholar is supposed to be familiar with the simple operations in the four ground rules, and with the first principles of fractions, these being now taught to small children either orally or from elementary treatises. This being premised, the language of figures, which are the representatives of numbers, is carefully taught, and the different .significations of which the figures are susceptible, depending on the manner in whicli they are written, are fully explained. It is shown, for example, that the simple numbers in which the value of the unit PREFACE. Vll increases from right to left according to the scale of tens, and the Denominate or Compound numbers in which it increases according to a varying scale, belong to the same class of num- bers, and that both may be treated under the same rules. Hence, the rules for Notation, Addition, Subtraction, Multipli- cation and Division, have been so constructed as to apply equally to all numbers. This arrangement, which the author has not seen elsewhere, is deemed an essential improvement in the science of Arithmetic. Li developing the properties of numbers, from their elemen- tary to their highest combinations, great labor has been bestowed in classification and arrangement. It has been a leading object to present the entire subject of arithmetic as forming a series of ilepeiident and coyinccled joropositions : so that the pupil, while acquiring useful and practical knowledge, may at the same time be introduced to those beautiful methoda of reasoning, v.'hich science alone teaches. Great care has been taken to demonstrate every proposition — to give a complete analysis of all the methods employed, from the simplest to the most difficult, and to explain fully, the reason of every rule. A full analysis of the science of Num- bers has developed but one law ; viz , ihe law tchich connects all the units of arithmetic with the rinit one, and which points out the relations of these loiits to each other. In the Appendix, which treats of Units, Weights and Mea- sures, &c., the methods of determining the Arbitrary Unit, as well as the general law which prevails in the. formation of numbers, are fully explained. 1 cannot too earnestly recom- mend this part of the work to the special attention of Teachers and pupils In fine, the attention of teachers is especially invited to this work, because general methods and general rules are employed to abridge the common arithmetical processes, and to give to them a more scieniific and practical character. In the present edition the matter is presented in a new form ; the arrange- Vlll PEEFACE. mcnt of the subjects is more natural and scientific ; the methods have been carefully considered ; the illustrations abridged and simplified ; the definitions and rules thoroughly revised and corrected ; and a very large number and variety of practical examples have been added. The subjects of Frac- tions, Proportion, Interest, Percentage, Alligation, Analysis, and Weights and Measures, present many new and valuable fea- tures, which are not found in other works. A Key to the present work has also been published for the use of such Teachers as may desire it, — prepared with great care, containing not only the answers and solutions of all the examples, but a full and comprehensive analysis of the more difficult ones. The author has great pleasure in acknowledging the interest which Teachers have manifested in the success of his labors : they have suggested many improvements, both in rules and methods, not only in his elementary, but also in his advanced works. The school room is the tribunal, and the intelligent and practical teacher the judge, before whom all text-books must stand or fill. The terms, " Cause and Effect," used in developing the sub- ject of Pi'oportion, were supposed by the author, at tlie time of their introduction into his works, to be common literary property. But he has since been informed, that Prof H. N. Robinson, the distinguished author of a full course of Mathematics, chiims to have been the first who made a practical application of these terms, in a tangible form, to Proportion, as published in liis Aritlimetic of 185-i. I have great pleasure, tlierefore, in assifrn- ing to their proper author, the invention of so ingenious and practical a method, and of acknowledging the courtesy of beinw permitted to continue its use in my books, with, however, as I deem, important differences in the definitions and development of the rule. FiSHKiLL Landing. ") My, 1858. CONTENTS. FIRST FIVE El'LES. PAGES. Definitions , 13 Expressing N^umbers 1<, Notation and Numeration 15-24 Formation and Nature of Number? 24—26 Scales 26 United States Money 2Y-29 Integral Units 29 Properties of the 9's 30 Reduction 31-35 Addition 35-44 Subtraction 44—53 Multiplication 63-67 Division 67-83 Practice .84*-85* Longitude and Time 84-86 Applications in the Four Rules 86-95 Properties of Numbers 95-97 Divisibility of Numbers 97-99 Greatest Common Divisor 99-102 Least Common Multiple 102-104 Cancellation 104-108 COMMON FRACTIONS. Definition of, and First Principles 108-1 11 The six Kinds of Fractions 111-113 Six Propositions 113-117 Reduction of Common Fractions 117-124 Addition of Common Fractions 124—129 Subtraction of Common Fractions 129-133 Multiplication of Common Fractions 133-137 1 COINTENTS. PAGES Division of Common Fractions 137-141 Complex Fractions l-il-142 Applications in Fractions 142-141 Duodecimals 144-150 DECIMAL FRACTIONS. Definition of Decimals, &c 150-151 Decimal Numeration Table — First Principles, &c 151-156 Addition of Decimals 156-15S Subtraction of Decimals, 158-160 Multiplication of Decimals 160-162 Contractions in Multiplication 162-164 Division of Decimals , 164-168 Contractions in Division 168-170 Reduction of Common Fractions to Decimals 170-171 Reduction of Denominate Decimals 171-175 Circulating or Repeating Decimals — Definition of, &c 175-179 Reduction of Circulating Decimals 179-184 Addition of Circulating Decimals 184 Subtraction of Circulating Decimals 184-185 Multiplication of Circulating Decimals 185-186 Division of Circulating Decimals 186 CONTINUED FEACTIONS. Definitions and Principles 186-189 RATIO AND PROPORTION. Ratio Defined 189 Proportion Defined 190 Simple and Compound Ratio 102 Simple Proportion, or Rule of Three 193 Cause and Ellect 198 Inverse Proportion 199-205 Compound Proportion 205-209 Partnership 209-214 OONTEKTS. XI PERCENTAGE PAGES Percentage Defined and Illustrated 214-219 Simple Interest 219-232 Compound Interest 282-235 Discount 235-237 Banking 237-240 Bank Discount 240-242 Commission , 242-245 Stocks and Brokerage 245-250 Profit and Loss 250-255 Insurance 255-257 Life Insurance 257-259 APPLICATIONS. Endo-wments 259-261 Annuities 261-263 Assessing Taxes 263-267 Custom House Business 267-272 Equation of Payments 272-275 Alligation 275 Alligation Medial 275-276 Alligation Alternate 276-282 Coins and Currencies 282-283 Exchange 283-295 General Average 295-298 Tonnage of Vessels 298-300 PO'WEES AND ROOTS. Involution 300-301 Evolution 301-302 Extraction of Square Root 302-31 1 Cube Root 311-317 AEITHMETICAt PROGRESSION. Definition of, -''255 tens^ hundreds. In the number five hundred and ninety-five, there are " « 2 5 units of the first order, 9 of the second, and five of the ^ 5 a third ,• and it is read from the right, units, tens, hundreds. 5 9 5 In the number six hundred and four, there are 4 units '^ x Z of the first order, of the second^ and 6 of the third. ^ 5 § TJie right hand figure ahvays expresses units of the first order ; the second, units of the second order ; and the third, units of the third order. 18. To express ten units of the third order, or one thousand, we form a new combination by writing three ciphers on the right of 1 ; thus, 1000. Now, tliis is but one single thousand, and may be regarded as a unit of the fourth order. 17. How do you write one hundred ? To how many units of the second order is it equal ? To liow many of the first order ! How may it be roiiardcd 1 Of what order 1 How many units of the third order in 200 ! In 600 ! fii 900 ! 18 To what are ten units of the tiiird order equal 1 Hew do you write it 1 How do you write a single unit of the first order 7 How do you writo a unit of the second order 1 Of the third T Of the fourth \ NOTATION. 19 Thus, we may form as many orders of units as we please : a single unit of ihe first order is expressed hy - - 1, a unit of the second order by 1 and 0; tlius, - - 10, a unit of tlie third order by 1 and two O's ; - - 100, a unit of the fourth order by 1 and three O's ; - - 1000, a unit of the fifth order by 1 and four O's ; - - 10000 ; and so on, for units of higher orders : 19. Therefore, 1st. The same jrgure expresses different units according to the place tc/n'ch it occupies : 2d. Units ofthejirst order occupy the place at the right ; units of the second order, the second place ; units of the third order, the third place, and so on for places still to the left: 3d. Ten units of the first order make one of the second ; ten of the second, one of the third ; ten of the third, one of the fourth ; and so on for the higher orders : 4tli. IVhen figures are written by the side of each other, ten units in any one place male one unit of the place next at tlie left. EXAHPLKS IN WRITING THE ORDERS OP UNITS. 1. Write 7 units of the 1st order. 2. Write 8 units of tlie 2d order. 3. Write 9 units of the 4th order. 4. Write 3 units of the 1st order, with 9 of the 2d. 5. Write 9 units of the 3d order, with 6 of the 2d, and 1 of the 1st. G. Write units of the 2d order, 8 of the 1st, with 4 of the 3d, and 7 of the 4th. 19. On what does the unit of a figure depend 1 What is the unit of the place on the right 1 What is the unit of the second place 1 What of the third place 1 What of the fourth 1 &c. How many units of the first order make one of the second 1 IIo';» many of the second make one of the third ] How many of the third one of the fourth 1 &c. When figures are written by the side of each oilier, how many units of any place make one unit of the place next at the \eft 1 20 NOTATION. 7. "Write 8 units of the 6tli order, 7 of the 4th, 9 of the 5th, of the od, 2 of the 2d, and 1 of the 1st. 8. 'Write 8 units of the 8th order, 6 of the 7th, of the 1st, 3 of tlie 2a, 4 of the 3d, 9 of the 4th, of the Gtli, and 2 of the 5th. 9. AVrite 4 units of the 10th order, 8 of the 7th, 3 of the 9th, 2 of tlie 8th, of the 6th, 3 of the 1st, G of the 2d, of the Sd, 1 of the 4th, and 2 of the 5th. 10. Write 3 units of the 2d order, 2 of the 1st, 9 of the 3d, of the 4th, 9 of the 9th, G of the 8th, 7 of the 7th, of the Gth, and 4 of the 5th. 11. Write 3 units of the 11th order, of the 10th, 8 of the 4th, of the 5th, 2 of the Gth, of the 7th, 3 of the 8th, 4 of the 9tli, 1 of tlie 3d, % of the 2d, and 3 of the 1st. 12. Write 3 units of the 12th order, G of the 11th, 3 of the 8th, 7 of the Gth, 2 of the 4th, and 1 of the 2d. 13. Write 5 units of the 13th order, 8 of the 12th, of the 9th, G of tlie 7th, 8 of the 3d, and 12 of the 1st. 14. Write 7 units of the 14th order, 5 of the 13th, G of the 12th, 5 of the 10th, 7 of the 8th, 9 of the Gth, 5 of the 4th, and 8 of the 1st. 15. Write 9 units of the 15th order, 4 of the 13th, 8 of the 9 til, 2 of the Gth, 7 of the 3d, and 2 of the 2d. IG. Write G units of the IGth order, 9 of the 12th, 7 of the 9th, 4 of the 7th, of the Gth, 8 of the 4th, 9 of the 5th, and 2 of the 2d. 17. Write 8 units of the 20th order, 5 of the 18th, G of the 13th, 4 of the 11th, 9 of the 9th, 1 of the 17th, 4 of the 5th, and 9 of the 3d. 18. Write 6 units of the 10th order, 5 of the 8th, 9 of the Gth, of the 4th, and 1 of the 1st. 19. Write 9 units of the 18th order, and then diminish the figure of each order by 1 till you come to and include ; then increase the figure of each order by 1, till you reach the first order; and then read each order. 20. Write tJie number which has 20 units of the 17tli order, NUMEEATION. 21 ol the 14tli, 8 of the 16th, 4 of the 13th, of the 8th, of the 9th, and one in each of the other places. NUMERATION. 20. Numeration is the art of reading correctly any number expressed by figures or letters. The pupil has already been taught to read all numbers from one to one thousand. The Numeration Table will te^ch him to read any number whatever; that is, to express numbers in words. TABLE. 7th Period. 6th Period. 5th Period. 4th Period. 3d Period. 2d Period. 1st Period. Quintiilioiis. Quadrillions. Trillions. Billions. Millions. Thousands. Units. 09 s - • o . , « W • o ^<-j m X/2 ^ DQ ' ." <» s ■ W r* • rt . • I • t- !=< _o f-; o W OT s-i • n3 O . O •i-H ^ w o a • o-S • G"! : H-2 ..— ( (—1 P3 3 ^ o E— 1 <« "— -iS -A tt- rt » c*.^ , 1 V-. '.^ t— "~^ u^ o = 5 ^ § s O'm o 'z3 o • — 1 =>- m • K C?" 3 ^a° «=H Kpq w cc H 'Cl M ^ O i^ go _o 1^ o Cm O a; a o 1^ 1 4) • S J^ TO s J2 •3 T3 cc O r^ CO a s § c J2 -2 D o '3 C3 a> ^ s § S-l 3 O f^ ^ o s a O -3 p o '3 KHC^ KHGf ffiHH KHpq H KHH EH^ 3 7 8 9 4 2 1 6 6 3 6 8 6 3 4 6 2 5 Notes. — 1. Numbers expressed by more than three figures are written and read by periods^ as shown in the above table. 2. Each period always contains three figures, except the left hand period, which may contain one, two or three figures. 3. The unit of the first, or right-hand period, is 1 ; of the second period. 1 thousand ; of the third, 1 million ; of the fourth, 1 billion ; and so on, for periods, still to the left. 4. To Quintillions succeed Sextillions, Septillions, Octillions, Non- lllions, Decillions, UiidecilIion.=5, Daodecillions, &c. 5. The pupil should be required to commit, thoroughly, the names 20. What is Numeration 1 "What is the unit of the first period 1 Wha} is the unit of the second 1 Of the third 1 Of the fourth 1 Fifth ? Sixth T Seventh 1 &c. Give the rule for reading numbers. ' Give the rule for writing numbers. 22 NUMEKATION. of the periods, so as to repeat tlicm in their regular order from left to right, as well as from right to lefc. 6. Formerly, in the English Notation, six places Avere given to Millions, Trillions, Quadrillions. &:c. They were read, Millions, Tens of Millions, Hundreds of Millions, Thousands of Millions, Tens of Thousands of Millions, Hundreds of Thousands of Millions ; and the same for Billions, Trillions, Quadrillions. Sec. This method produc- ed great irregularity in the Notation, as it gave three places to the units of the first two periods, (viz. : units and thousands,) and six places to each of the others. The French method, which gives three places to the unit of each period, is fully adopted in this country, and must soon become universal. RULE FOR READING NUMBERS. I. Separate the number into periods of three ficjures each, beginning at the riijht'hand. II. Name the unit of each figure, beginning at the right hand. III. T7ie7i, beginning at the left hand, read each period as if it itood alone, naming its unit. EXAMPLES IN READING NUMBERS. Let the pupil point oflf and read the following numbers — then write them in words. 1. 97 6. 32045607 11. 784236704 2. 326 7. 90464213 12. 7403026054 3. 3302 8. 47364291 13. 217040S0495 4. 65042 9. 4037902169 14. 21896720421 5. 742604 10. 91046302 15. 8140290308097 16. 8504680467023 19. 30467214302704 17. 90403040720156 20. 167320410341204 18. 1723047368 93210 2 1. 2164032189765421 Let each of the above examples, after being written on tliQ \)lack board, be analyzed as a class exercise ; thus : 1. In how many ways may the number 97 be read? 1st. The common way, 97. 2d. Wo may read, 9 tens, and 7 units. NATUKE OF NUMBEKs, 23 2. Ill how many ways may 32 G be read ? 1st. By the common way, tliree hundred and twenty-six. 2d. Three hundreds, 2 tens, and 6 units. 3d. Tliirty-two tens, and six units. 3. In how many ways may the number 5302 be read? 1st. Five tliousand three hundred and two. 2d. Five tliousand, tliree Iiundreds, tens, and 2 units. 3d. Fifty-three hundreds, tens, and 2 units. 4th. Five hundred and tliirty tens, and 2 unita. 4. In 65042, liow many ten thousands ? How many thou- sands ? How many hundreds ? IIow many tens ? How many units ? 5. In 742604, how many hundred thousands? How many ten tliousands ? How many thousands ? How many hundreds ? How many tens ? IIow many units ? RULE FOR WRITING NUMBERS, OR NOTATION. I. Begin at the left hand and write each period in order, as if it were a period of units. II. When the nuynher, in any period except the left-hand period, can he expressed hy less than three fgures, prefix one or two ciphers ; and when a vacant period occurs, fill it with ciphers. EXAMPLES IN NOTATION. Express the following numbers in figures : 1. Six hundred and twenty-one. 2. Five thousand seven hundred and two. 3. Plight thousand and one. 4. Ten thousand four hundred and six. 5. Sixty-five thousand and twenty-nine. 6. Forty millions two hundred and forty-one. 7. Fifty-nine millions tliree hundred and ten. 8. Fleven thousand eleven hundred and eleven. 9. Three hundred millions, one thousand and six. 10. Sixty-nine billions, three millions, two hundred and eleven. 24 DEKOMINATh NUMBERS. 11. Forty-seven quadrillions, sixty-nine billions, four bun- dred and sixty-five thousands, two hundred and seven. 12. Eight hundred quintillions, four hundred and twenty-nine millions, six thousand and nine. 13. Ninety-five sextiliions, eighty-nine millions, eighty-nine thousands, three hundred and six. 14. Six quintillions, four hundred and fifty-one billions, sixty- five millions, forty -seven thousands, and one hundred and four. 15. Write, in figures, nine hundred and ninety-nine billions, sixty-five millions, eight hundred and forty-one thousands, four hundred and eleven, 1 G. Four hundred and seventy nonillions, forty octillions, four millions, six thousands, two hundred and four. 17. Sixty-five sextiliions, eight hundred quadrillions, seven hundred and fifty billions, seven hundred and fifty-one millions, nine hundred and seventy-five thousands, three hundred and ten. FORMATION AND NATURE OF NUMBERS. 21. The term, one, may refer to any single thing : it has no reference to kind or quality : it is called an abstract unit. 22. The term, one foot, refers to a single foot, and is called a concrete or denominate unit. 23. An abstract number is one whose unit is abstract : thus, three, four, six, &c., are abstract numbers. 24. A concrete or denominate number, is one whose unit is concrete or denominate : thus, three feet, four dollars, five pounds, are denominate numbers. 25. A Simple Number is a single unit, or a single collection of units, either abstract or denominate. 21. Docs the term, one, refer to the kind of thing to which it is applied 1 What is it called? 22. To what docs one foot refer 1 What is it called ' 23. What is an abstract number? 24. What is a concrete, or denominate number 1 25. What is a simple number' DENOMINATE NUMBERS. 25 26. Quantity is anything which can be measured. 27. Numbers which have the same unit are of the same denomination : and numbers having different units are of differ- ent denominations. Tims, 4 yards and 6 yards are of the same denomination i but 4 yards and G feet are of different denomi- nations. 28. If two or more denominate numbers, having different units, are connected together, forming a single expression, this is called, a compound denominate numbei*. Thus, 3 yards 2 feet and 6 inches, is a cotnpotind denominate number. 29. We have seen (Art. 19) that when figures are written by the side of each other, thus, 678904, the language implies that ten units of any place make one unit of the place next to the left. 30. When figures are written to express English Currency, thus: £ s. d. far. 4 17 10 3 the language implies, that four units of the lowest denomination make one of the second ; twelve of the second, one of the third ; and twenty of the third, one of the fourth. 31. "When figures are written to express Avoirdupois weight, thus : T. cwt. qr. lb. oz. dr. 27 17 2 24 11 10 the language implies, that 16 units of the lowest denomination 26. What is quantity \ 27. When are numbers paid to be of the same denomination 1 When of different denominations ! 28. What is a compound denominate number 1 29. When several figures are simply written by the side of each other, what docs the language imply 1 33. In the English Currency, how many units of the lowest denomina- tion make one of the second '\ How many of the second one of the third ! How many of the third one of the fourth ! 31. In the Avoirdupois weight, how many of the lowest make ^ the second 1 How many of the second one of the third ? 2 26 DENOMINATE NUMBEKS. make one of the second; 16 of the second, one of the third; 25 of the third, one of the fourth ; 4 of the fourth, one of the 6fth ; and 20 of the fifth, one of the sixth. All the other compound denominate numbers are foi'med on the same principle ; and in all of them, we pass from a lower to the next higher denomination hy considering how many units of the lower make one unit of the next Jiigher* 32. A Scale expresses the relations between the different units of a number. There are two kinds of scales — uniform and varying. In the common scale, the number of units which make 1 of the next higher is 10. In English Currency, 4, 12, and 20, make up the varying scale ; and 16, 16, 25, 4 and 20, in Avoirdupois weight. SCALE OF TENS. 33. Let us write a row of O's, thus ; o rag S .2 H a o rt p J^or:^ '-'^ud So,^ J^ort GHPq KHS KHH SHP 0, 0, 0, 0, The language of figures determines the unit of each place, and also, the laip of change in passing from one place to another. This is called the decimal system, in v»'hich the units change according to the scale of tens. If it be required to express a given number of units, of any * For the Tables of Denominate Numbers, see Appendix, page 383. 32. What is a scale 1 How many kinds of scales are there'? "What are they ? What is the scale in the common system of numbers ! ^^'llat is tlie scale in English Currency 1 What in Avoirdupois weight ? 33. If a row of O's be written, what does the language of figures deter- mine ? What is such a system called 1 How does the unit change' How do you express a given number of units of any order ? INTEGRAL UNITS. 27 Older, we first select from tlie arithmetical alphabet the figure which designates tlie number, and then write it in the place corresponding to the order. Thus, to express three millions, we write 3000000; and similarly for all numbers. UNITED STATES MONEY. 34. United States money atlbrds an example of a system of denominate units, increasing according to the scale of tens: thus, ^ a (O ^ _r- Of) ;z5 g S " W Q P O S 11111 may be read 11 thousand 1 hundred and 11 tnills ; or, 1111 cents and 1 mill; or, 111 dimes, 1 cent, and 1 mill; or, 11 dol- lars, 1 dime, 1 cent, and 1 mill ; or, 1 eagle, 1 dollar, 1 dime, 1 cent, and 1 mill. Thus, we may read the number with any one of its units as a base, or we may name them all ; as 1 eagle, 1 dollar, 1 dime, 1 cent, 1 mill. Generally, in United States money, we read in the denominations of dollars cents and mills ; and say, 11 dollars 11 cents and 1 mill. United States money is denoted by the character, $. The figures expressing dollars are separated from those which denote cents and mills by a comma ; thus, $11,111 is read, 11 dollars 11 cents 1 mill; the figures on the left of the comma always denote dollars ; the first two on the right denote cents, and the third, mills. ALIQUOT TARTS. One number is said to be an aliquot part of another, when 84. Are the numbers used in United States nionej' abstract or denomi- nate ? According to what scale do the units change 1 How are <^ separated from cents and mills I A\ hat is an rdiquot parti aliquot parts of a dollar ' 28 VARYING SCALKS. it is contained in that other an exact number of times. Thus ; 50 cents, 25 cents, &c., are aliquot parts of a dollar : so also, 2 months, 3 months, 4 months an.l 6 months are aliquot parts of a year. The parts of a dollar are sometimes expressed frac- tionally, as in the following TABLE, cents. $1 i of a dollar = 100 50 cents. 1 of a dollar = 33 J cents. cents. 20 cents. 1- of a dollar = 25 1 of a dollar = l of a dollar Jq of a dollar 121 cents. 10 cents. J^ of a dollar = 61 cents. 5 cents. 5 mills. o\j^ of a dollar J of a cent VAKYING SCALES. 35. If we write the well-known signs of the English currency, and place 1 under each denomination, we shall have £ s. d. far. 1111 Now, the signs £.s. d. and far. fix the value of the unit 1 in each denomination ; and they also determine the relations between the different units. For example, this simple language expresses the following ideas : 1st. That the unit of the right hand place is 1 farthing — of the place next at the left, 1 penny — of the next place, 1 shilling — of the next place, 1 pound ; and 2c?. That 4 units of the lowest denomination make one unit of the next higher; 12 of the second, one of the third; and 20 of the third, one of the fourth. Hence, 4, 12 and 20, make up the scale. 36. If we take the denominate numbers of Avoirdupois weight, we have Ton act. qr. lb. oz. dr. 111111; 35 In En^lisli currency, is the scale uiiiforni or varying ? How does it vary 1 30. Name the units of the scnle in AvoirJupois weii^Iit. INTEGRAL UNITS. 29 in which the units increase in the following manner ; viz. : counting from the right, IG units of the lowest denomination make 1 unit of the second; IG of the second, 1 of the third; 25 of tlie third, 1 of tlie fourth ; 4 of the fourth, 1 of the fifth ; 20 of the fifth, 1 of the sixth. The scale, therefore, for this class of denominate numbers, varies according to the above law. 37. If we take any other class of denominate numbers, as Troy weight, or any of the systems of measures, Ave shall have different scales for the formation of the dilFerent numbers. But in all the formations, we shall recognize the application of the same general principles. There are, therefore, two general methods of forming the different systems of integral numbers from the unit one. The first consists in preserving a uniform law of relation between the different units. If that law of relation is expressed by 10, we have the system of common numbers. The second method consists in the application of known, though varying laws of change in the units. These changes in the units, produce difl'erent systems of denominate numbers, each of which has its appropriate scale. INTEGRAL UNITS OF ARITHMETIC. 38. The Integral units of Arithmetic may be divided into ei2;ht classes : 1st. Abstract units : 2d. Units of currency : 3d. Units of length : 4:ih. Units of surface : 5th. Cubic units, or units of volume : (J/h. Units of weight : 7ih. Units of time : 8lh. Units of circular measure. First among the units of arithmetic stands the abstract unit 1. This is the primary base of all abstract numbers, and becomes the base, also, of all denominate numbers, by merely naming, in succession, the particular thing to which it is applied. 37. How many general methods are there of forming numbers from tlie unit one ] What is the first ? WTiat is the second 1 38. Into liow many general classes may the units of Arithmetic bo arranged ^ What are they 1 30 rr.oPERTiES of 9's. OF THE SIGNS. 39. The sign ~, is called the sign o^ equality. When placed between two numbers it denotes that they are equal ; that is, that each contains the same number of units. The sign +, is called p^us, which signifies jnore. When placed between two numbers it denotes that they are to be added together : thus, 3 + 2 = 5. The sign — , is called minus, a term signifying less. When placed between two numbers it denotes that the one on the right is to be taken from the one on the left : thus, 6 — 2 = 4. The sign x , is called the sign of multiplication. When placed between two numbers it denotes that they are to be mul- tiplied together; thus, 12 X 3, denotes that 12 is to be multi- plied by 3. The parenthesis is used to indicate that the sum of two or more numbers is to be considered as a single number : thus, (2 4- 3 + 5) X G shows, that the sum of 2, 3 and 5 is to be multiplied by 6. The parenthesis is also used to denote that the difference be- tween two numbers is to be considered as a single number ; thus, (5 - 3) X 6, denotes that the difference between 5 and 3 is to be multiplied by 6. The sign -r-, is called the sign of division. When placed between two numbers it denotes that the one on the left is to be divided by the one on the right : • thus, 4-^-5, denotes that 4 is to be divided by 5. PKOPERTIES OF THE 9's. 40. In any number, written with a single significant figure, as 4, 40, 400, 4000, &;c., the excess over exact 9's is equal to 39. What is the sign of equaHty \ AVliat is the sign of adJilioii ? Wiiat of siil)traction 1 What of niuhipHcation ! For wliat is tlie i)aien- thesis used ! What is Ihe sign of division 1 40. What will be the excess over exact 9's in any number expressed by a single significant figure 1 How may the excess over exact 9's be found in any number whatever'! REDUCTION. 31 the number of units in the significant figure. For, any such number may be written, 4 = 4. Also, - - - - 40 = (9 -f 1) X 4, « - - - - 400 = (99 + 1) X 4, « - - - - 4000 r= (999 + 1) X 4, &c., &c., &c. Each of the numbers 9, 99, 999, &c., contains an exact number of 9's ; hence, when muUipliecl by 4, the several products will contain an exact number of 9's : therefore, TJie excess over exact 9's, in each mmiber, is 4 ; and the same may be shotvn for each of the other significant figures. If we write any number, as 6253, we may read it 6 thousands 2 hundreds 5 tens and 3. Now, the excess of 9's in the thousands is 6 ; in 2 hundreds it is 2 ; in 5 tens it is 5 ; and in 3 it is 3 : hence, in them all, it is 16, which is one 9 and 7 over : therefore, 7 is the excess over exact 9's in the number 6253. In like manner, The excess over exact 9's in any number whatever, is found by addi?ig together the sign'ficmit fgurcs and rejecting the exact 9's from the sum. Note. — It is best to reject or drop the 9 as soon as it occurs : thus we say, 3 and 5 are 8 and 2 are 10 ; then, dropping the 9, we f^ay, 1 to 6 is 7, which is the excess ; and the same for all similar operations. 1. What is the excess of 9's in 48701 ? In €7498 ? 2. What is the excess of 9"s in 9472021 ? In 2704962 ? 3. What is the excess of 9's in 87049612 ? In 4987051 ? REDUCTION. CHANGE OF UNITS. 41. Reductiox is the operation of changing the unit of a number without altering its value. Thus, if we have 4 yards, 41. What is Reduction 1 How do you change yards to feet 1 How do you change feet to inches 1 How do you change inches to feet 1 How do you change feet to yards '' / 32 RKDCCTION. in whicli the unit is 1 yard, and wisli to change to feer, the units of the scale will be 3, since 3 feet make 1 yard : there- fore, the number of feet will be 4x3 = 12 feet. If it were required to reduce 12 feet to inches, the units of the scale would be 12, since 12 inches malie 1 foot. Hence, 4 yards =z 4 x 3 =z 12 feet = 12 x 12 = 144 inches. H', on the contrary, we wash to change 144 inches to feet, and then to yards, we should first divide by 12, the units of the scale in passing from inches to feet ; and then by 3, the units of the scale in passing from feet to yards. Hence, Reduction is of two kinds : 1st. To reduce a number from a higher unit to a lower: Multiply tlie units of the Idgliesl denomination by the number of units ill the scale which connect-^ it with the next lower, and then, add to t e product the un'ts er to be taken called! What docs the multiplier denote 1 What is the result called ! What are the multiplier and multiplicand called 1 Why is Multiplication called a short method of Addition 1 54 MULTIPLICATION. 49. Thei'e are three parts in every operation of multiplica* tion. First, the multiplicand: second, the muUiplier : and third, the product. From the definition of Multiplication, we see that, Is;;. If the multiplier is 1, the product Avill be equal to the multiplicand. 2c?. If the multiplier is greater than 1, the product will be as many times greater than the multiplicand, as the multiplier is greater than 1. 3d. If the multiplier is less than 1, that is, if it is a proper fraction, then the product will be such a part of the multipli- cand as the multiplier is of 1. 50. Let it be required to multiply any two numbers together, say 6 to 4. Analysis. — If we write, in a horizontal line, fi as many stars as there are units in the nmlti- , '^ \ plicand, and write as many such lines as there are units in the multiplier, it is evident that, 4 ■ all the stars will represent the number of units which arise from taking the multiplicand as many times as there are units in the multiplier. Change now the multiplier into the multiplicand : that is, multi- ply 4 by 6. Make in a vertical line, as many stars as there are units in the new multiplicand, (4), and as many vertical lines are there are units in the new multiplier, (6), when it is again evident that, all the stars will represent the number of units in the product. Hence, T7ie product of two factors is the same whichever factor is used as the midtipUer. 3x7 = 7x3 = 21: also, Gx3 = 3x6 = 18. 9x5 = 5x9 = 45: also, 8x6 = 6x8 = 48. and, 8x7 = 7x8 = 56: also, 5x7 = 7x5 = 35. 49. How many parts . are there in every operation of Multiplication 1 Wliat are they ? How many principles follow from the definition of Mul- tiplication ■? What arc they ! 50. In how many way.s mny 6 and 4 be multiplied together I How do the two produf.ts compare with each other 1 \\'lial docs this proved vf> ^ 9f- ^ 9f ^ •ff- ^ ^ ^ ^ ^ ^ ^ *• ^ ^ ^ MULTIPLICATION. 55 52. A Composite Number is one that may be produced by the multiplication of two or more numbers, called factors^ Thus, 2 X 3 rz: 6, in which G is the composite number, and 2 and 3 the factors. Also, 16 r=: 8 X 2, in which IG is a com- posite number, and 8 and 2 the factors ; and since 4 X 4 = 16, we may also regard 4 and 4 as factors of 1 G. A Prime Number is one which cannot be produced by mul- tiplication, and is divisible only by itself and 1. 53. Let it be required to multiply 7 by the composite number 6, of which the factors are 2 and 3. 7 _3 21 42 C£> 7 « * * * * * * * * * * * * * * * * * * 1 * J '* 1 1-2 X 7= 14 » 3 » * * * * * * * J ;-2 42 * * * * * « * 1 *2 * * * * * * * J 1 If we write 6 horizontal lines with 7 units in each, it is evi- dent that the product of 7 X 6 = 42, will express the number of units in all the lines. Let us first connect the lines in sets of two each, as at the right ; the number of units in each set will then be expressed by 7 X 2 = 14. But there are 3 sets; hence, the number of units in all the sets, is 14 x 3 = 42. Again, if we divide the lines into sets of 3 each, as at the left, the number of units in each set will be equal to 7 x 3 = 21, and since there are two sets, the whole number of units will be expressed by 21 X 2 = 42. 53. What is a composite number 1 Give an example of a composite number 1 What are its factors 1 What are the factors of 161 What is a prime number 1 53. If several factors are multiplied together, will the product be altered jy changing their order 1 How do you multiply by a composite number ' 56 irULTIPLI'JATlON. Since the product of either two of the three factors 7, 3 and 2, will be the same whichever be taken for the multiplier (Art. 50), and since the same principle will apply to that product and lo the other foctor, as well as to any additional factor, if intro- iuced, it follows that, The product of any number of factors will he the same in vhatever order they are multiplied : Hence, to multiply by a composite number, I. Separate the composite number into its factors : II. Midtiply the midtiplicand and the partial products hy the factors, in succession, and the last product will be the entire pro- duct sought. Note. — Any number whatever, as 440, ending with 0. is a com- posite number of which 10 is a factor: for, 440 = 44 x 10. If there are two O's on the right of the significant figures, then 100 is a fac- tor, and so on for a greater number of ciphers. Hence, when there are ciphers on the right of significant figures, either in the multipli- cand or multiplier, or both, Multiply the significant figures together, and then annex the ciphers to the product. 54. 1. Multiply G27 by 214. Analysis. — The multiplicand 627 is to be ta- operation. ken 214 times : that is, 4 units times, 1 ten times, 627 and 2 hundred times. Taking it 4 units times, 214 gives 2508 ; taking it 1 ten times gives 627, of 2508 which the lowest unit is 1 ten ; hence. 7 is written 627 in the tens place : taking it 2 hundred times, gives 1 254 1254. the lowest unit of which is 1 hundred. 134178 Adding, we have 134178 for the product. Note. — What is one factor of a number ending in ' "What is one factor of a number ending in two O's ! In throe 0"s ! &c. How du vou multiply by such a number when there are cipliers in one or both factors ? 54. Explain the operation of niulliplying 6'-i7 by 214. Explnin the five principles which come from this analysis. What is a partial produ -t ! Give the general rule for multiplication. What must be observed in tli« multiplication of United States money? MULTIPLICATION. 57 It is seen, from the preceding analysis, that 1. If units be multiplied hy units, the unit of the product will he 1. 2. If tens be multiplied by units, the unit of the product will he 1 ten. 3. If hundreds be multiplied by imits, the unit of the product will he 1 hundred; and so on: And since the product of the factors is the same whichever is taken for the multiplier (Art. 50), it follows that, 4. If units of the first order he multiplied hy units of a higher order, the units of the product will be the same as that of the higher order. 5. If units of any order he multiplied hy units of any other order, the iinit of the product luill he of an order one less than the sum of the units denoting the two orders. Note. — When the multiplier contains more than one figure, the product obtained by multiplying the multiplicand by a single figure, is called a •partial product. In the last example there are three partial products, 2508, 627, and 1254. The sum of the partial pro- ducts is equal to the product sought : 2. Multiply £3 8s. M. 3/ar. by 6. Analysis. — Multiplying 3 farthings by 6, we operation. have 1 8 farthings, equal to Ad. and 2far. : set £ s. d. far. down the 2/ar. : then, 6 times Qd. are 36rf., and 3 8 6 3 4 pence to carry are 40fZ., equal to 3 shillings 6 and Ad.: then, 6 times 85. are 485. and 3s. to 20 11 4 2 carry are 51 shillings, equal to £2 and 11 shil- lings: then, 6 times jC3 are jClS and jC2 to carry are jC20, which set down. Note. — The vmit of each product will be the same as the unit of the multiplicand. Hence, for the multiplication of all numbers, we have the following Rule. — Multiply every order of units in the multiplicand, in succession, beginning with the lowest, hy each figure in the mul- tiplier, and divide each product so formed hy so many units as naJce one unit of the next higher denomination : write down each 3* 5S MULTIPLICATION. remainder under the units of its oivn order, and carry the quo* tient to the next product. Note. — In multiplj-ing United States money, care must be taken to point off as many places for cents and mills as there are in the multiplicand. 1- Multiply 14 dollars IG cents and 8 mills, by 5, 6, and 7. $14,168 $14,168 $14,168 5 6 7 (2.) (3.) (4.) $870,40 $894,120 $2141,096 9 14=i7 X 2 36 = 6 X 6. PROOFS OF MULTIPLICATION. 55. There are three methods of proof for multiplication : I. Write the multiplier in the place of the multiplicand, and h'.d the product as before : if the two products are the same, t>6 ycvk ia supposed to be right (Art. 50). II, 7>:vide the product by one of the factors, and the quotient "wijl be ths^- ol\\2x factor. HI. L'y iSa method of casting out the 9's. FIRST METHOD. MuLiply • - 80432 506 by - - 506 80432 482592 4048 402 160 2024 40o98592 1518 1012 40698592 Note 1. — Althougii wc generally begin the multiplication by tho figure of the lowcsi unit, yet we may multiply in any order, if we only preserve the places of the different orders of units. In the ex- ample at the right, we began with the order of tens of tlicusands (r 5tl: order. 55. How many proofs are there for multiplication'! What is the first 1 What is the second 1 Wliat is the third 1 OPERATION. 641 = 639 + 2 232 = 225 + 7 4473 + 14 450 3195 1278 1278 148698 + 14 MULTIPLICATION. 59 2. Although either factor may be used as tlie multiplier (Art. 50), Etill it is best to use that one which contains the fewest figures. For, if \vc change the process and use the multiplicand as the mul- tiplier, there -vvill be more multiplications, as shown in the last example. PROOF BY THE O'S. 56. Let it be required to multiply any two numbers together, as 641 and 232. Analysis. — We first find the excess over exact 9's in both factors, and then separate each factor into two parts, one of which shall contain exact 9's, and the other the excess, and unite the two by the sign plus. It is now required to take 639 + 2 = 641, as many times as there are units in 225 + 7 = 232. Every partial product, in this multiplica- tion, contains exact 9's, except 14, which contains one 9 and 5 over; and as the same may be shown for any two numbers, we see that, If we find the excess of 9's in each of two factors, and then multi'ply them together, the excess of 9's in their product will be equal to the excess of 9's in the product of the factors. (1.) Ex. (2.) Ex. Multiply 87G03 - - 6 818327 - - 2 by 98G5 ^ 9874 1 Prod. 864203595 - - 6 80S01G0798 - - 2 3. By multiplication we have Ex.4. Ex.8. Ex.4. Ex. of product, 2. 7285 X 143 X 976 = 1016752880. Note. — Is it necessary to commence the multiplication with the lowest unit 1 Which factor is it most convenient to use as a multiplier 1 56. How do you find the excess of 9's in the product of two factors'! If the excess of 9's in any factor is 0, what is the excess of 9's in the product 1 60 MULTIPLICATION. Ex.5. Ex.4. Ex.0. Ex.0. 4. We also have 869 x 49 X 36 = 1532916. Note. — When the excess of 9's in any factor is 0, the excess of 9's ill the product is always 0. EXAIIPLES. (1.) (2.) (3.) (4.) 847046 9807602 570409 216987 8 7 6 9 (5.) (6.) (7.) 103672 8163021 90031746 42 - 126 274 (8.) (9.) (10.) $14,168 $894,126 $20034,645 5 14 48 (11.) (12.) (13.) 47321809 1237506 437024 4261 3460 400 (14.) (15.) (16.) 8703600 107030 30671200 34600 5700 482 (17.) (18.) (19.) £ s. d. T. qr. lb. oz. yd. ft. in. 20 6 8 3 3 21 14 16 2 9 4 8 7 (20.) (21.) (22.) hlid. gal. qt. pt. E.F. qrs. na. 12° 42' 55" 4 42 2 1 24 2 3 9 12 24 23. Mulfiply IStons 2qrs. IGlbs. Ooz. by 48. 24. JMultiply Oyr. 8ino. 2ivL Ma. 42m. by 56. 25. Multiply 68 by the factors 9 and 8 of the composit > number 72. MULTIPLICATION. 61 26. Multiply 3657 by the factors of 64. 27. Multiply 37046 by the factors of 121. 28. Multiply 2187406 by the factors of 144 29. Multiply 430714934 by 743. 30. Multiply 37157437 by 14972. 31. Muhiply 47157149 by 37049. 32. Multiply 57104937 by 40709. 33. Multiply 79861207 by 890416. 34. Multiply 9084076 by 9908807. 35. Multiply 2748 by 200. 36. Multiply 67046 by 10 : also by 100. 37. Multiply 57049 by 100 : also by 1000. 38. Multiply 4980496 by 1000 : also by 10000. 39. Multiply 90720400 by 100 : also by 10000. 40. Multiply 74040900 by 1 : also by 10. 41. Multiply 674936 by 100 : also by 100000. 42. Multiply 478400 by 270400. 43. Multiply 367000 by 37409000. 44. Multiply 7849000 by 84694000. 45. Multiply 89999000 by 97770400. 46. Muhiply 9187416300 by 274987650000. 47. Multiply 86543291213456 by 12637482965. 48. Multiply 76729835645873 by 217834569. 49. If it costs 2479 dollars to build one mile of plank road, bow much would it cost to build 25 miles ? 50. How far would a vessel sail in 9 days, of 24 hours each, at the rate of 15 miles an hour ? 51. A man bought two farms, one of 125 acres, at 26 dollars an acre ; another of 96 acres, at 32 dollars an acre ; he paid at one time 2500 dollars ; at another time 1725 dollars : what remained to be paid ? 52. In 9 pieces of kersey, each containing lAyd. 3qr. 2na., how many yards ?* * NorE. — When the multiplicand is a compound denominate number, and the multiplier a composite number, it is best always to multiply by the factois of the composite number. 62 MULTIPLICATION. 53. Wliat will 15 gallons of wine cost at 5s. S^d. per gallon ? 54. What will be the value of 416 sheep at $2,48 a head ? 55. Bought 40 barrels of flour at $8,75 a barrel, and sold them for $9,121 a barrel : what was the whole gain ? 56. What is the weight of 11 hogsheads of sugar, each weighing 7cwL 2qr. 18lb., and what would be its value at 6 cents a pound ? 57. A merchant bought 36 pieces of broadcloth, each piece containing 44 yards, at 4 dollars a yard : what did the whole cost? 58. A gentleman whose annual income is $3479, expends for pleasure and travelling $600 ; for books and clothing $570 ; for board and other expenses $1200 : how much will he save in 5 years ? 59. The number of milch cows in the state of New York in 1850 was 931324 : Avhat would be their value at 18 dollars each ? 60. If a man travel 20/?u*. ofur. IQrd. in one day, how far will he travel in 24 days ? 61. How long will it take a man to mow 14 acres of grass, allowing 10 working hours a day, if he mow one acre in 4Jir. 4omt. SOsec. ? 62. If a man spend six cents a day for segars, how mucli will he spend in thirty years, allowing three hundred and sixty- five days to the year ? 63. A farmer sold 118 bushels of barley for 62^ cents a bushel, and receives 5 barrels of flour at $9,87^ a barrel, and the remainder in cash : how much cash did he receive ? 64. Two persons start at the same point and travel in oppo- site directions, one at the rate of 34 miles a day, the other at the rate of 28 miles a day : how far apart will they be at the end of 14 days? 65. An apothecary sold 8 bottles of laudanum, each con- taining 10 T 6 5 2 9 14^7*. : what was the weight of the whole ? GO. A farmer took 7 loads of oats to market, each load MULTIPLICATION. 63 having 20 bags, and each bag containing 2hush. opk. Qqi. : how many bushels of oats did he take to market ? 67. If in a woollen factory 4G8 yards, of cloth are made in one day, how many yards will be made in 313 days ? G8. The greatest number of whales ever captured in the northern seas, in one season, was 2018. Estimating the oil produced from each to have been 212 barrels, what was the amount of oil produced ? 69. What will be the value of an ox weighing 7cwf. 2qr. IQlh., at 11 cents a pound ? 70. What will be the cost of 245 hogsheads of sugar, each weighing 984 pounds, at 7 cents a pound ? 71. Bought 6 loads of hay, each weighing 18cw^ Sqis. 21/6. ; after letting a neighbor have 2tons Ibcwt. Iqr. bib,, how much will there be Left ? 72. In an orchard there are 136 apple trees, each tree yield- ing 17 bushels of apples : how many bushels did the whole orchard yield, and what would they be worth at 42 cents a bushel? 73. A flour mei'chant bought 1845 barrels of flour at 7 dol- lars per barrel. He sold at one time 528 barrels, at 9 dollars a barrel ; at another time 856 barrels at 8 dollars a barrel ; how many barrels had he left, and at what cost ? 74. What are 25 hogsheads of sugar worth, each weighing 872 pounds, at 6^ cents a pound ? 75. It is estimated that the whole amount of land appropriat- ed by the General Government for educational purposes, to the 1st of January, 1854, was 52770231 acres. What would be the value of this land at the Government price of one dollar and twenty-five cents an acre ? 76. If 30 men can do a piece of work in 25 days, how long will it take one man to do it ? 77. A man desired that his property should be equally divided omono- his 5 children, giving each twenty-seven hundred dol- lars : what was the amount of his property ? 78. Bought 9 chests of tea, each containing 72 pounds, at 37:^ cents a pound : wha/ was the cost of the whole ? 64: MULTIPLICATION. 79. A farm consisting of 127 acres, was sold at auction foi S37,565 an acre : what sum of money did it bring ? 80. A drover bought 127 head of beef cattle at an average of 39 dollars per head ; he sold 86 of them for 43 dollars per head; for how much per head must he sell the remainder, to clear on the first cost 1246 dollai's ? 81. What will 75 firkins of butter cost, each firkin weighing 56 pounds, at 16 cents a pound? 82. A merchant bought a box of goods containing 37 pieces, each piece containing 46 yards, worth 7 dollars a yard : what did the box of goods cost ? .. 83. A bond was given April 20th, 1850, and was paid Sept. 4th, 1856 : what will be the product, if the time which elapsed from the date of the bond to the time it was paid be multiplied by 45 ? 84. "What distance will a Wheel 16 feet 8 inches in circum- ference measure on the ground, if rolled over 84 times ? 85. What is the difference between twice eight and fifty, and twice fifty-eight ? 86. How much wood in 4 piles, each containing 5 cords, 6 cord feet and 32 cubic feet ? 87. A man bought 56 acres of land for $25 an acre, and 94 acres for $32 an acre ; if he sells the whole at $30 an acre, will he gain or lose, and how much ? 88. If 12 men can build a wall in 16 days, how many men will be required to build a wall nine times as long m half the time ? 89. A former sold 4 cows for $25,50 each; 12 sheep for $2,12-1^ each ; and 3 calves for $7,25 each ; what was the amount of the sale ? 90. If it requires 116 tons of iron to construct one mile of railroad, how much would it require to construct a railroad from Albany to Buff;ilo, it being 326 miles? 91. A merchant bought 960 pounds of cheese at 9 cents a pound ; 148 pounds of butter at 12^ cents a pound. He gave in payment, 12 yards of cloth, at $4,75 a yard ; 186 pounds of MTTLTIPLICATION, 65 sugar at 7 cents a pound, and the remainder in cash : how much cash did he pay ? 92. If a family consume 12^'/. 25-1;. \pt. of ale in a week, how much will they consume in 14 weeks? 93. How much brandy will supply an army of 25,000 men for one month, if each man requires Igal. 2qf. Ijyt. 2gi. 94. It is estimated that the French, during the years 1854 and 1855, transported to the Crimea 80000 horses, and that 70000 of them were lost in the same time. Supposing the first cost of each horse to be $100, and the cost of transporta- tion $95 per head, what was the value of the horses lost ? 95. A man purchased a piece of woodland containing 27 acres, at 39 dollars per acre ; each acre produced on an average 70 corda of wood, which, being sold, yielded a nett profit of 45 cents a cord : how much did the profit on the wood fall short of paying for the land ? BILLS OF PAKCELS. 9G. Chicago, June 10, 1856. J/r. John C. Smith, Bought of David Toombs. 14 pounds of tea, at 75 cents, - - $ 9 " " coffee. 14 " 42 « " sugar, 11 " 3 " " pepper, 12^ " 5 " " chocolate. 56 " 12 " " candles. 16 " Received payment, David Toombs. 97 New York, March 20th, 1857. Mr. Jacob Johns, Bought of George Bliss Sf Co 48 pounds of sugar at 9i cents a pound, - - - $ 6 hogs, of molasses, each containing 63 gallons, at 27 cents a gallon, 8 casks of rice, 285 lbs. each, at 5 cts. a pound, 9 chests of tea, 86 lbs. each, at 87^ cts. a pound, 4 bags of coffee, each 67 lbs., at 11 cts. a poiuid, Received payment, ^ 4 Geo. Bliss &'. C-o- 66 MULTIPLICATION. 98. Hartford, Novembet 21s<, 1856. Gideon Jones, Bought of Jacoh Thrifty. 78 chests of tea, at $55,G5 per chest, - - % 251 bags of coffee, 100 pounds each, at) 12^ cts. per pound, - - ) 317 boxes of raisins, at $2,75 per box, 1049 barrels of shad, at $7,50 per barrel, - - - 76 barrels of oil, 32 gallons each, at $1,08 per gal., Amount, $ Received the above in full, Jacob Thrifty. 99. Baltimore, Jan. \st, 1855. Mr. Abel Wirt, Bought of Timothy Stout. 10 yards of broadcloth, at $4,37i, - - - $ 75 " " sheeting, " ,09 - 42 " " plaid prints '' ,45 - 5 barrels of Genesee flour, at $7,87^, - 7 pairs of boots, at $1,60 per pair, 18 bushels of corn, at 72 cts. per bushel, "$ 100. Montreal, Oct. 16th, 1855. 3fr. Chas. Snow, Bought of Vose, Duncan Sf Co. 45 yai-ds of broadcloth at 9s. M. - - £ s. d. 56 " " " 12s. ^d. - 16 " vesting?, " 6s. 8^d. - - - 24 lbs. colored thread, " os. Ad. - - - 72 pairs silk hose, " 7s. 5|(/. - 108 yards carpeting, " 14s. 10c?. - - - Received payment, £ VosE, Duncan & Co. DIVISION. 67 DIVISION 57. Division is the operation of finding from two munhers a ihird, which midtiplied by the first, to ill produce the second. The first number, or number by which we divide, is called the divisor. The second number, or number to be divided, is called the divide7id. The third number, or result, is called the quotient. The quotient shows how many times the dividend contains the divisor. When the quotient is expressed by an integral number, the division is said to be exact. When it cannot be so expressed, the part of the dividend that is undivided, is called the remainder. 58. There are always three numbers in every division, and sometimes four : 1st. the dividend ; 2d. the divisor ; od. the quotient ; and 4th, the remainder. There are three methods of denoting division ; they are the following : 12 -r 3 expresses that 12 is to be divided by 3. -L2 expresses that 12 is to be divided by 3. 3)12 expresses that 12 is to be divided by 3. When the last method is used, if the divisor does not exceed 12, we draw a line beneath the dividend and set the quotient under it. If the divisor exceeds 12, we draw a curved line on the right of the dividend, and set the quotient at the right. 59. Short Division is the operation of dividing when the work is performed mentally, and the results only written down. It is limited to the cases in which the divisors do not exceed 12. 57. What is division l What is the number to be divided called 1 What is the number called by which we divide 1 What is the answer called 1 What is the number called which is left 1 58. How many parts are there in division 1 Name them. How many eigns arc there in division 1 Mako and name them. 59. What is short division ? How is it generally performed 1 Where is the quotient written ] To what cases is it limited 1 68 DIYISTON. 1. Divide 45G by 4. Analysis. — Tlie number 456 is made up of 4 hundreds, 5 tens, ?nd 6 units, each of which is to be divided by 4. Dividing 4 hundreds by 4, we have the quotient, operation. 1 hundred : 5 tens divided by 4, gives 1 ten and 4)456 1 ten over : reducing this to units and adding in 114 die 6, we have 16 units, which contains 4, 4 times: hence, the quotient is 114: that is, the dividend contains the divisor 114 times. 2. Divide £11 8s. Id. Zfar. by 5. Analysis. — Dividing £11 by 5, the quofient is £2 and £1 re- maining. Reducing this to shillings and adding in the 8, we have 28s., which divided by 5, gives operation. 5s. and 35. over. This being reduced to pence £ s. d. far. and Id. added, gives 43J. Dividing by 5, we 5)11 8 7 3 have ^d. and 3c?. remainder. Pteducing 2d. io 2 5 8 3 farthings, adding 3 farthings, and again dividing by 5, gives the last quotient figure 3/ar. 3. Divide £6 85. M. by 8. operation, £ s d Here we have to pass to shillings before making the first division. S)6 8 8 16 1 4. Divide 11772 by 327. Analysis. — Flaving set down the divisor on the left of the dividend, it is seen that 327 is not contained in the first three iigvues on the left, which are 117 hundreds. opekation. But by observing that 3 is contained in 11, 327)11772(36 3 times and something over, we conclude that the 981 divisor is contained af least 3 times in the first 1962 four figures, 1177 tens, which is a pnrtialdividcnd. 1962 Set down the quotient figure 3, and multiply the divisor by it : we thus get 981 tens, which being less than 1 177. the quotient figure is not too great: we subtract the 981 tens from the first four figures of the dividend, and find a remainder 196 tens, which being less than the divisor, the quotient figure is not too small. Reduce this remainder to units and add in the 2, and we have 1962. As 3 is contained in 19, 6 times, we conclude that the divisor is contained in 1962 as many as 6 times. Setting down 6 in the quo- DIVISION. 69 tient and mnltipJymg the divisor by it, we find the product to be 19C2. Therefore the entire quotient is 36. or the divisor is contained 36 times in the dividend. 60. From the above analysis, we have the following rule for the division of numbers. 1. Begin icith the highest order of miits of the dividend, and pass on to the lower orders until the fewest nmnher of figures he found that will contain the divisor : divide these figures by it for the first figure of the quotient : the unit of this figure will be the same as that of the lowest order in the partial dividend. II. Mnhiplg the divisor by the quotient figure so found, and subtract the product from the partial dividend. III. Reduce the remainder to units of the next loiver order, and add in the units of tJiat order found in the dividend: this gives a new partial dividend. Proceed in a similar manner until units of every order shdl have been divided. DIRECTIONS FOR THE OPERATIONS. Notes. — There are tivc operations in Long Division. 1st. To write down the numbers : 2d. To divide, or find how many times : 3d. Tc multiply: 4th. To subtract: 5th. To bring down, to Ibrm the partia dividends. 2. The product of a quotient figure by the divisor must never b larger than the corresponding partial dividend : if it is, the quotien figure is too large and must be diminished. 3. When any one of the remainder.s is greater than the divisor, the quotient figure is too Fmall and must be increased. 4. Tlie unit of any quotient figure is the same as that of the partial dividend from which it is obtained. The pupil should always name the unit of every quotient figure. 60. Give the rule for the division of numbers. Notes. — 1. How many operations are there in division 1 Name them. 2. If a partial product is greater than the partial dividend, what does it indicate '^ What then do you do ? 3. What do you do when an}' one of the remainders is greater than the divisor '\ 4. What is the unit of any figure of the quotient \ \^'hen the divisoi 18 contained in simple units, what will be the unit of tlic quotient figure 70 DIVISION. 0. If any partial dividend is less than the divisor, the correspond ing quotient figure is 0. 6. When there is a remainder, after division, write it at the right of tiie quotient, and place the divisor under it. PRINCIPLES RESULTING FROM DIVISION. 1. When the divisor is equal to the dividend, the quotient will he 1. 2. When the divisor is less than the dividend, the quotient will ha greater than 1. The quotient will be as many times greater than 1 as the dividend is times greater than the divisor. 3. Wlien the divisor is greater than the dividend, the quotient will be less than 1. The quotient will be such a part of 1, as the divi- dend is of the divisor. 4. When the divisor is 1, the quotient will be equal to the divi- dend. PROOF. 61. There are two methods of proof for division : 1st. By multiplication ; 2d. By the excess of 9's. FIRST METHOD. By the definition of division, the quotient is such a number as multiplied by the divisor will produce the dividend (Ai-t. 57). In example 4, each product of the divisor by a figure of the quo- tient is a partial product, and the sum of these products is the product of the divisor and quotient (page 57, Note). Each product is taken, M'hcn it is contained in tens, what will be the unit of the quotient figure 1 Wlien it is contained in hundreds'! In thousands] 5. If any partial dividend is less than the divisor what is the correspond- ing figure of the quotient ? 6. When there is a remainder after division, what do you do witli it? Note. — 1. When the divisor is equal to the dividend, what will the quo- tient be 1 2. When the divisor is less than the dividend, how will the quotient compare with 1 1 How many times will it be greater than 1 ? 3. When tlie divisor is greater than the dividend, how will the quotient compare with 1 ? What part will the quotient be of 1 ? 4. When the divisor is 1, what will the dividend be ! 61. How many methods of proof are there for division ! What are they ! What is the proof by multiplication ! What is the proof by the 9's ? DIVISION. 71 geparately, from the dividend, and nothing operation remains. But, taking each product away, in 327)11772(36 succession, leaves the same remainder as would 1981 be left if their sum were taken away at once. 1962 Hence, the number 36, when multiplied by 1962 the divisor 327, gives a product equal to the dividend 11772; therefore, 36 is the quotient (Art. 57): hence, to prove division, Blidtiply tlie divisor hy the quotient and add in the remainder, if any. If the work is right, the result will be the same as the dividend. Note. — Divide 325 by 19. The quotient is 17, and 16 remainder: the true quotient is 17^| , for. this being multiplied by the divisor 19, will give the dividend. If the pupil knew how to dispose of the frac- tional part, we should simply say, " Multiply the divisor by the quoticntj^' which is exactly what we do under the rule. PROOF BY 9's. Since the dividend is equal to the product of the divisor and quotient, it follows that if the excess of 9's in the divisor be multiplied by the excess of the 9's in the quotient, the excess of 9's in the product will be equal to the excess of 9's in the dividend (Art. 56). Hence, Find the excess of 9's in the divisor and in the quotient : mul- tiply them together, and note the excess of 9's in the product : if this is equal to the excess of 9's in the dividend, the work may he regarded as Hght. Divisor, 327, excess of 9's - - 3 ] Quotient, 36, « - - . o\ ^''^^^^^> ^' Dividend, 11772, " - - - EXAMPLES. (1.) (2.) (3.) (4.) 3)19737 4)147308 5)1346840 6)1650930 (5.) (6.) (7.) 6)47689872 9)10324683 7)506321494 72 DIVISION. £ 3)47 (8.) s. 19 A. 9)37 (9.) i?. 3 P. 17 (11.) $ cts. 8)634 75 6 (10.) yd. qr. na. 5)47 3 1 (12.) $ cts. m. 7)1468 96 (13.) $ 12)802346 16 Divide $29,25 by 26. Divide $10,125 bv 27. Divide $347,49 by 429 Divide $751,50 by 150. Divide $571 1,04 by 108. Divide $315 by $35. Divide $50065 by $527. Divide $432 by 54. 14. Divide 734947644 by 48. 22. 15. Divide 8536752 by 36. 23. 16. Divide 3367598 by 19. 24. 17. Divide 49300 by 725. 25. 18. Divide 6477150 by 145. 26. 19. Divide 770 by 28. 27. 20. Divide $87,256 by 5. 28. 21. Divide $495,704 by 129. 29. 30. Divide 334422198 by 438. 31. Divide 714394756 by 1754. 32. Divide 47159407184 by 3574. 33. Divide 5719487194715 by 45705. 34. Divide 4715714937149387 by 17493. 35. Divide 671493471549375 by 47143. 36. Divide 571943007145 by 37149. 37. Divide 1714347149347 by 57143. 38. Divide 49371547149375 by 374567. 39. Divide 171493715947143 by 571007. 40. Divide 6754371495671594 by 678957. 41. Divide 7149371478 by 121. 42. Divide 71900715708 by 57149. 43. Divide 14714937148475 by 123456. 44. Divide 729^. 2R. IP. by 41. 45. Divide oQMa. Qhr. by 240. 46. Divide 1298mi. 2fur. 33rd. by 37. 47. Divide 95Md. Ggal by 120. 48. Divide 232bush. 3ph. Igt. by 105. 49. Divide $18306,25 by 725. 50. Bonp;ht 7 yds. of clDtli for 1 6.«. Ad. : wlint did it cost per yd. ? DIVISION. 73 51. A man travelled 2Gomi. Gfur. IQrd. in 12 clays : how far did he travel in one day? 52. If 569^. 2Ii. 23P. be equally divided between 9 per- sons, how much will 5 of them have ? 53. The annual income of a gentleman is $10000: how much is that per day, counting 365 days to the year ? 54. What number multiplied by 9999 will produce 987551235 ? 55. A gentleman owning an estate of $75000, gave one-fourtL of it to his wife, and the remainder was divided equally among his five children : liow much did each receive ? 56. The expenditure of the United States for 1853 was $54026818 : how much Avould that be per day, allowing 365 days to^the year ? 57. If 28 yai'ds of cloth cost $133, what will one yard cost? 58. If I pay $637,50 for 51 yards of cloth, what is the price per yard ? 59. The city of New York, in 1850, had 104 periodical i)ub- lications, with an aggregate circulation of 78747600 copies: what would be the average circulation of each ? 60. Bought 19. bushels of wheat for $30,875 : what was the cost of one bushel ? 61. How long will 9125 loaves of bread last 5 families, if each family consume 5 loaves a day ? 62. The product of two numbers is 7207272072, and the multiplier 9009 : what is the multiplicand ? 63. How many rings, each weighing Adwt. 12g7\, can be made from lOor. 11 dwt. 12gr. of gold ? 64. If iron is worth 2 cents a pound, how much can be bought for $67,50 ? 65. If 14 sticks of hewn timber measure 12 2^. 38/;!. 118m., how much does each stick contain ? 66. In 1850, Pennsylvania manufactured 285702 tons of pig iron, and employed 9285 hands : what was the average product of each hand ? 67. The number of collesre libraries in the United States in 1850, was 213, containing 942321 volumes : what would be the average number of volumes in each ? ■1 74 OONTEAOTIONS CONTRACTIONS AND APPLICATIONS. CONTRACTIONS IN MULTIPLICATION. 62. Contractions in Multiplication are short methods of find- ing products when the multipliers are particular numbex'S. 63. To multiphj hy 25. 1. Multiply 356 by 25. Analysis. — If we annex two ciphers to the niul- operation. tiplicand, we multiply it by 100 (Art. 5a): this 4)35600 product is 4 times too great; for the multiplier is 8900 but one-fourth of 100 ; hence, to multiply by 25, Annex two ciphers to the multiplicand and divide the result hy 4:. EXAMPLES. 2. IMultiply 287 by 25. 3. Multiply 184 by 25. 4. IMultiply 6741 by 25. 5. Multiply 3074 by 25. OPERATION 15 3^ 3 45 48 Ans 64. When the multiplier contains a fraction. AVhat is the jjroduct of 15 multiplied by 31 ? Analysis. — The multiplicand is to be taken 3 and one-fifth times : taking it one-fifth times, gives 3, wliich we write in the units place : then, taking it 3 times, gives 45, and the sum 48 IS the product ; hence Rule. — Take such a pari of the multi- plicand as the fraction is of 1 ; then multiply hy the integral number, and the sum of the products will be the required product. 2. Multiply 327 by 8.}. 5. Multiply 1272 by 12|. 3. Multiply 23474 by 16^. I 6. Multiply 9824 by 272^. 4. Multiply 34700 by 127"^. | 7. Multiply 3828 by 731. 62. Wliat are contractions in multiplication 1 G3 How do you multiply by 251 C4. How do you multiply when the multiplier contains a fraction! IN MULTIPLICATION. 76 65. To multiplij hj 12?,. 1. Multiply 286 by 12J. Analysis. — Since 121 is one-eighth of 100, Annex two ciphers to the multiplicand and divide the result by 8. EXAMPLES. OPERATION. 8)28600 1. Multiply 384 by 121. 2. Multiply 476 by 12^. 3. Multiply 14800 by 12^ 4. Multiply G70418 by 12-1. G6. To multiply hy 331. 1. Multiply 975 by 33 J. Analysis. — Aunoxiiig Uxo cipliers to the multiplicand, multiplies it by 100: but the multiplier is one-third of 100 : hence, Annex two ciphers and divide the result by 3. operation. 3)97500 32500 EXAMPLES. 1. Multiply 1670252 by 33i 2. Multiply 1480724 by 33i 67. 2"o multiply hy 125. ]. Multiply 1125 by 125. Analysis. — Annexing three ciphers to the multiplicand, multiplies it by 1000 : but 125 is but one-eighth of one thousand : hence, Annex three ciphers and divide the result by 8 EXAMPLES. 3. Multiply 10675512 by 331. 4. Multiply 4442172 by 33i. OPERATION. 8)1125000 140625 1. Multiply 59264 by 125. 2. Multiply 17593408 by 125. 3. Multiply 1940812 by 125. 4. Multiply 140588 by 125. COXTRACTIO^VS IN DIVISION. 68. Contractions in Division are short methods of finding the quotient, when the divisors are particular numbers. 65. How do you multiply by 12.| 1 66. How do you multiply by 33^1 67. How do you multiply by 125 ] 68. What are Contractions in Division? 76 CONTKACTIONS 69. By revei'siiig the last four processes, we have the four following rules : 1. To divide any number by 25 : Multiply the number by 4, and divide the product. by 100. 2. To divide any number by 12i : Multiply the number by 8, and divide the product by 100. 3. To divide any number by 33 J : Multiply the number by 3, and divide the product by 100. 4. To divide any number by 125 : Multiply by 8, and divide the product by 1000. EXAMPLES. 1. Divide 6350 by 25. 2. Divide 21345 by 25. 3. Divide G5G280 by 25. 4. Divide 7278675 by 25. 5. Divide 5287215 by 25. 6. Divide 12225 by 12^. 7. Divide 10650 by 12i. 8. Divide 11925 by 121. 9. Divide 1760000 by 12^. 10. Divide 67500 by 331. 11. Divide 1308400 by 331. 12. Divide 15851400 by 331. 13. Divide 8072400 by 33J. 14. Divide 281250 by 125. 15. Divide 6015750 by 125. 16. Divide 2026875 by 125. 70. Wlien the divisor is a composite number. 1. How many feet and yards are there in 288 inches ? Analysis. — Since there are 12 inches in 1 foot, there will be as many feet in 288 inches as 12 is contained times in 288 ; viz., 24 feet, in which the unit is 1 foot. operation. Since 3 feet make 1 yard, there will be as many 12)288 yards in 24 feet as 3 is contained times in 24 ; 3)24 viz., 8 yards : in which the unit is 1 yard. We 8 have thus passed, by division, from the unit 1 inch to the unit 1 foot, and then to the unit 1 yard ; that is, in each 69. What rules do you get by reversing the four previous rules ? Gito them. 70 What is a composite number 1 Under ". romposile nunibor ' When there are remainders after division, how do -ov And tli remainder in units of the dividenrl ■" IN DIVISION. 77 operation, we have increased the unit as many times as there are units in the divisor. Let us now use the same numbers, ii an entirely difFerent question.' 2. If 288 dollars be equally divided among 3G men, what will be the share of each ? Analysis. — Since 288 dollars is to 36 = 12 x 3 operation. be equally divided among 36 men, each 12)288 ■will liavo as many dollars as 36 is con- 3)24 tained times in 288. Dividing 288 into 8 12 equal parts, we find that each part is 24 dollars. If each of these parts be now divided into 3 equal parts, there will then be 36 parts in all, each equal to 8 dollars : here, the unit of the result is the same as that of the dividend. Hence, we may regard division under two points of view : 1. As a process of reduction, in which the unit of each suc- ceeding dividend is increased as many times as there arc units in the divisor : 2. As a process of separating a number into equal parts ; in %vhich case the unit of a part will he the same as that of the dividend. Hence, the follow^ing rule when the divisox* is a composite number : RuLii;. — Divide the dividend hy one of the factors of the divi- sor ; then divide the quotient, thus arising, hy a second factor, and so on, till every factor has been used as a divisor: the last quotient will be the answer. EXAMPLES. Divide the following numbers by the factors : 1. 2322 by 6 = 2 x 3. 5. 1145592 by 72 = 8 X 9 2. 37152 by 24 = 4 x G. 3. 19152 by 36 z= G X G. 4. 38592 by 48 = 4 X 12. G. 185760 by 96 = 8 X 12 7. 115776 by 64= 8 x 8. 8. 4G3104 by 144 = 12 x 12 Note. When there are remainders, after division, the operation la to be treated as one of Reduction. 78 CONTE ACTIONS 9. Divide the number 3671 by 3C = 2 X 3 x 5. Analysis. — Dividing 3671 by 2, yve have a quotient 1S35, and a remainder, 1. Alter the second division, we have a quotient 611, operation. and a remainder, 2 ; and after the 2)3671 third division, the quotient 122, 3)1835 . . 1. and the remainder, 1. Now. it is 5)611 . . 2. plain, from the first analysis, that, 122 .. 1. 1. The unit of the first quotient 1X3 + 2= 3 + 2= 5; is as many times greater than the 5X2 + 1 = 10 + 1 = 11 rem. unit of the dividend, as the divi- Ans. 122^^. sor is times greater than 1 ; and similarly for all the following quotients. 2. The unit of the first remainder is the same as the unit of the dividend ; and the unit of any remainder is the same as that of the corresponding dividend. , 3. The unit of any dividend is reduced to that of the preceding dividend, by multiplying it by the preceding divisor. Hence, to find the remainder in imits of the given dividend, is simply a case of reduction in which the divisors denote the units of the scale : therefore, I. Multiphj the last remainder hy the last divisor hut one, and add in the preceding remainder. II. Multiphj this residt hy the next preceding divisor, and add in the remainder, and so on, till you reach the unit of the divi- dend. Divide the following numbers by the factors, and find the remainders : 1. 41G705 by 315 - 7x9x5. 2. 80410G by 462 = S x 2 x 7 x 11. 3. 756807 by 3456 = 4 X 8 x 9 x 12. 4. 8741659 by 105 =: 3 x 5 x 7. 5. 917043 by 385 = 5 x 7 x 11. 6. 4704967 by 1155 = 11x7x5x3. 7. 71874607 bv 7560 = 8x7x9x5x3. IN DIVISION. 79 71. When the divisor is 10, 100, 1000, S^c. 1. Divide 3278 by 1000 = 10 x 10 x 10. Analysis. — We divide 3278 by 10, by operation. simply cutting off 8, giving 327 tens and 10)327|8 8 units remainder. We again divide by 10)32|7 . 8 rem. 10, by cutting ofT the 7, giving 32 hun- 10)3|2 . . 7 rem. dreds and 7 tens remainder. We again 3 . . 2 rem divide by !0 by cutting ofF tlie 2, giving ^^-^^ Ans. a quotient of 3 tliousands and 2 Imndreds remainder. The quotient then is 3, and a remainder of 2 hundreds 7 tens and 8 units, or 278. Rule. — Cut off from the right of the dividend as many fgurcs as there are ciphers in the divisor, considering the figures at the left the quotient, and those at the right the remainder. 72. When any divisor contains significant figures with one or more ciphers at the right hand. 2. Divide 87589G by 32000. Analysis. — The divisor 32000 = 32 x 1000. operation. Dividing by 1000 gives a quotient 875, and 896 32l000)875l896(27 remainder. Then dividing by 32 gives a quo- 64 tient 27, and 11 remainder, Vi^hicli gives the 235 result 271^11}. Hence, 224 Rule. — Cut off, by a line, the ciphers from ^ , ^ „ „ **^ ^115. 27 A — . the right of the divisor, and an equal num- ' 3 2000- ber of fgurcs from the right of the dividend : divide the remain' ing figures of the dividend by ilie remaining figures of the divisoVy and the remainder^ if any, with the figures cut off from the divi' dend annexed, will form the true remainder. EXAMPLES. Divide the followinjr numbers : 1. 1972G54 by 420000. 2. 1752000 by 12000. 3. 73199006 by 801400. 4. 11428729800 by 72000. 5. 3G981400 by 14G000. 6. 141614398 by 63000. 71. How do you divide when the divisor is 1, with ciphers annexed 1 72. How do you divide when the divisor contains significant figures, with ciohers annexed^ How do vou find the true remainder 1 80 APFLICATiO.N.S 78. When the divisor contains a fraction. 1. Divide 856 by 4i operation. -Analysis. — There are 5 filthy in 1 ; hence, 21=3x7 3)4280 in 4 there are 20 fifths; therefore, 4^ = 21 7)142(i -2 fifths. In the dividend 856, there are 5 times 203 -5 as many fifths as units 1 ; that is, 4280 fifths ; Ans. 203t4. therefore, the quotient is 4280 divided by 21, equal 203-^|^. Hence, when the divisor contains a fractional part, Reduce the divisor and dividend to the fractional unit of the divisor, and then divide as in integral numbers. Find the quotients in the following examples : 1. 3245-^ -16^. 5. 87317^ 9|. 2. 47804-^ -15}. 6. 87906 ^12f 3. 870631 -f- -14i. 7. 95675 ^ 15f. 4. 37214-^ -511. 8. 71096 -M7f. APPLICATIONS IN MULTIPLICATION. 74. The analysis of a practical question, in Multiplication, requires that the multiplier be an abstract number ; and then the unit of the product will be the same as the unit of the mul- tiplicand. 75. To find the cost of several things, lohen we kiwio the price of one and the numher of things : 1. What will six yards of cloth cost at 8 dollars a yard ? Analysis. — Six yards of cloth will cost 6 times as much as 1 yard. Since 1 yard of cloth cost 8 dollars, 6 yards Avill cost 6 times 8 dol- lars, which are 48 dollars ; therefore. 6 yards of cloth at 8 dollars a yard, will cost 48 dollars : hence, TJie cost of any numher of things is equal to the price of a single thing midtiplied by the nu7nber of things. But we have seen that the product of two numbers will be the same, (that is, will contain the same number of units) which- 73. How do you divide when the divisor contains a fraction ! 74. What docs the analysis of a practical question lequire! 75. How do you find the cost of a single thing 1 How is it done in practice 1 ATPLICATIONS. 81 ever be talcen for the multiplicand (Art, 50). Hence, in prac- tice, we may multiply the two factoi-s together, taking either for the muhi2)lier, and then assign the 2>^'oper unit to the product. We generally take the less number for the multiplier. 76. To find the cost when the price is an aliquot part of a dollar : 1. Find the cost of 45 bushels of apples, at 25 cents a bushel. Analysis. — If the price were 1 dollar a bushel, operation. the cost would be as many dollars as there aie 4)45,00 bushels. But the price is 25 cents = ^ of a dol- $11,25 ]ar; hence, the cost will be one-fourth as many dollars as there are bushels ; that is, as many dollars as 4 is contained times in 45 = 11 dollars and 1 dollar over. This is reduced to cents by adding two ciphers j then dividing again by 4, we have the entire cost : hence. Tithe such a part of the number which denotes the amount (f the commodity, as the price is of 1 dollar : the result ivill be the cost in dollars. EXAMPLES. 1. What would be the cost of 284 bushels of potatoes, at 50 cents a bushel ? 2. At 331 cents a gallon, what will 51 gallons of molasses cost? 3. What cost 112 yards of calico, at 12^ cents a yard ? 4. If a ponnd of butter cost 20 cts., what will 175 pounds cost ? 5. What will 576 bushels of 2)S576 cost at 1 dollar a bushel. wheat cost, at $1,50 a bushel ? J^ '' j^^e^its i?>64 " Sfl,50 " 6. What will it cost to dig a ditch 129 rods long, at §1,331 a rod ? 7. At $1,25 a barrel, what will 96 barrels of apples cost? 8. What will 5 pieces of cloth cost, each piece containing 25 yards, at $1,20 a yard ? 77. To find the cost of articles sold by the 100 or 1000. 1. What will 544 feet of lumber cost at 2 dollars per 100 ? 76. How do you find the cost, when the price is an aliquot part of a dollar 1 77. How do you find the cost of articles sold by the hufidred or thou- sand 1 4* 82 APPLICATIONS^ S. Analysis. — At 2 dollars a foot, the cost would be 544 x 2 = 1088 dollars : but as 2 dollars is the price of 100 feet, it foJlows that 1088 dollars is 100 times the cost of the lumber; therefore, if ^ye divide 1088 dollars by 100 (which is done by cutting off two of the right hand figures, Art. 71), we obtain the cost. Note. — Had the price been so much per 1000, we should have divided by 1000 : hence, Multiply the quantity hy the number denoting the price ; if the price he by the 100, cut of two figures on the right hand of the product ; if by the 1000, cut off three, and the remaining fig- ures will be the answer in the same denomination as the price, tvhich, if cents or mills, may be reduced to dollars. EXAMPLES. 1. What will be the cost of 3742 feet of timber at $3,25 per 100 ? 2. At $12,50 per 1000, what will 5400 feet of boards cost? 3. Richard Ames, Bought of John Maple. 1275 feet of boards at $9,00 per 1000 3720 u 15,25 it 715 scantling 8,75 u 1200 timber 12,0G u 2550 lathing 75 lOi 965 plank 1,121 (< Received payment, John Maple. *76. To find the cost of articles sold by the ton. What is the cost of 640 pounds of hay at $11,50 per ton? Analysis. — Since there arc 2000 operation. pounds in a ton, the cost of 1000 2)$1].50 l)ouiids will be half as much a.s of 5.75 price of 1000 lbs 1 ton : viz., $5,75. Mulliply this 640 by the number of pounds (640). and 23000 cut off three places from the right 3450 (Art. 71), in addition to the two $3^68000 places cut off for cents ; hence, *76. How do you find the cost of articles sold by the toni APPLICATIONS. 83 MxdiqAy one-half the price of a ion by the number of pounds, and cut ojf three figures from the right hand of the product. The remaining figures will be the ansiver in the same denomination as the price of a ton. EXAMPLES. 1. What will be the cost of 1575 pounds of plaster at $3,84 per ton ? 2. At $7,37-1- a ton, what will 3496 pounds of coal cost ? 3. What will 1260 pounds of hay cost at $9,40 per ton ? at $10,25 ? at $14,60 ? 4. What will be the cost of transportation of 5482 pounds of iron from Pittsburgh to New York at $6,65 per ton ? APPLICATIONS IN DIVISION. *77. Abstractly, the object of division is to find from two given numbers a third, which, multiplied by the first, will produce the second. Practically, it has three objects : 1. Given the number of things and their cost, to find the price of one thing. 2. Given the cost of a number of things and the price of one thing, to find the number of things. 3. To divide any number of things into a given number ot equal parts. Analysis. — Consider the number denoting cost or price as abstract; then make the division and assign the proper unit to the quotient. Hence, we have the following RULES I. Divide the number denoting the cost ly the number of things : the quotient will be the price of one. II. Divide the number denoting the cost hy the price of one : the quotient will be the number of things. III. Divide the whole number of things by the number of 2)arls into which they are to be divided: the quotient will be the number in each part. ^77. What is the object of Division abstractly? How many objects haa it practically ^ Name the objects. Give the rules for the three cases. 84* PRACTICE. PRACTICE. 77*. Practice is an easy method of applying the rules oS Anthraetic to questions which occur in trade and business. An aliquot part of a number is an exact part : hence, if a number be divided by an aliquot part, the quotient will be an integral number. TABLE OF ALIQUOT PARTS. Cts. Parts of$l. Parts of£l. Parts of 1 f'>'oduct will be the corresponding time in minutes. 2. If the minutes in longitude be multiplied by 4, the jyroduct will be the corresp)onding time in seconds. 1. What is the time in hours, minutes and seconds in 56° 47' ? Analysis. — First reduce the de- operation. grees to hours and minutes ; then m. hr. m. sec. reduce the minutes to minutes and 56° x 4 = 224 =3 44 seconds, and take the .svim. 47' X 4 = 18S sec. = 3 8 3 47 8 81. When the sun is on the meridian of any place, it is 12 o'clock, or noon, at that place. 78. How is the equator of the earth supposed to be divided i 79. How does the sun appear to move ' "What is a day 1 How far docs the sun appear to move in 1 hour ! 80. How do you reduce degrees of longitude to time 1 How do you reduce minutes of longitude to time ? 8L What is the hour when the sun is on tlie meridian 1 When the eun is on the meridian of any place, how will the time be for all places east 1 How for all places west 1 If you have the difference of time, how do you find the time 1 LONGITUDK AND TIME. 85 Now, as the sun apparently goes from east to west, at the instant of noon, at one place, it will be past noon for all places at the east, and before noon for all places at the west. If then, Ave find the difference of time between two places and know the exact time at one of them, the corresponding time at the other will be found by adding their difference, if that other be east, or by subtracting \i,\i west. 82. 2^0 reduce time to degrees and minutes of longitude. 1. The difference of time between Boston and New Orleans is 1 hour 11 minutes and 48 seconds : what is the difference of lonfritude ? Analysis. — Since 1 hour corresponds operation. to 15° of longitude, there will be as 15° x 1 = 15° many times 15° as thei-e are hours: 11 -i- 4= 2° 45' Since 1° corresponds to 4 minutes of 48 -i- 4= 12' time, there will be as many degrees as Diff. 17° 57' 4 is contained times in the minutes : Since 1' corresponds to 4 seconds of time, there will be as many minutes as 4 is contained times in the seconds : hence, 1. Multiply 15° by the number of hours, and the 'product will he degrees of longitude : 2. Divide the minutes by 4, and the quotient will be degrees and minutes of longitude : 3. Divide the seconds by 4, and the quotient ivill be minutes and secunds of longitude. The sum of these results will be the difference of longitude. EXAIMPLES. 1. The longitude of Albany is 73° 42' west, and that of Buffalo 78° 55' west : what is the difference of longitude and what the difference of time ? 2. The longitude of New York is 74° 1' west, and that of Springfield, Illinois, 89° 33' west: what would be the time at New York when it is 12 M. at Springfield ? 82. How do you reduce time to degrees and minutes of longitude '^ 86 APPLICATIONS. 3. When it is 12 M. at New York, it is 11 o'clock 6 minutea and 28 seconds at Cincinnati : wliat is their difference of lon- gitude ? 4. The longitude of Philadelphia is 75° 10' Avest, and that of New York 74° 1' west: what is the difference of time be- tween these two places ? 5. Washington is in longitude 77° 2' west, New Orleans in 89° 2' west. When it is 9 o'clock A. M. at Washing-ton, what is the time at New Orleans ? 6. If the difference of time between two places be 42/».z. IGiCc, what is the difference of longitude? 7. What is the difference of longitude between two places if the difference of time is 2//. 20»i/. 44sec, ? 8. The longitude of St, Louis is 90° 15' west; a person at that place observed an eclipse of the moon at lOA. 40;/i?. P. M. ; another person, in a neighboring state, observed the same eclipse 22/m/. 125fr. earlier: what was the longitude of the latterplace, and the time of observation ? 9. If the difference of time between London and Ore"-on Citj is 8 hours, what is the difference in longitude ? 10. The difference of longitude between St. Louis and New l^ork is 15° 35'. In travelling from New York to St. Louis will a watch, keeping accurate time, be fast or slow at St. Louis, and how much ? APPLICATIONS OF THE PRECEDING RULES. 1. What will it cost to build a wall 9G rods long, at $1,33} a rod ? 2. A farmer wishes to put lOGGiws/^ Iph. of potatoes into 474 barrels, how much nuist he put into each barrel ? 3. At $4,32 a yard, what will 121 yards of cloth cost ? 4. How many barrels of apples, each containing 1\ bushels, can I buy for $3G, at 45 cents a bushel ? 5. The quotient arising from a certain division is 123G ; the divisor is 375, and the remainder 184 : what is the dividend 1 APPLICATIONS. 87 G. The Croton Water Works of New York are capable of discharging 60000000 gallons of water every 24 hours : what would be the average amount per minute ? 7. The population of the United States, in 1850, was 23191876. It has been estimated that 1 person in every 400 dies from intemperance : how many deaths then may be attributed to this cause, in the United States, during that year ? 8. At the rate of 45 miles an hour, how long would it take a railroad car to pass around the globe, a distance of 25000 miles ? 9. If a quantity of provisions will last 25 men 2mo. owl:. Gda., how long will it last 10 men ? 10. If a man's salary is $1200 a year, and his expenses are $640 annually, how many years will it be before he will save $6720 ? 11. How long will it take to count 20 millions at the rate of 80 per minute ? 12. If 3160 barrels of pork cost $47400, how many barrels can be bought for $11475? 13. What will be the cost of 6 firkins of butter, each con- taining 96 pounds, at 12^ cents a pound ? 14. What will 1000 quills cost, at 1 cent a piece ? 15. What will be the cost of 851- yards of cloth, at $9i a yard? 16. What will be the cost of l/thJ. 2gcd. oqt. of brandy, at 56^ cents a quart ? 17. What will be the cost of 196 yards of cotton goods, at Is. 6d. per yard ? 18. At 2s. 8d. per bushel, what will 1246 bushels of oats cost ? 19. If 112Z5. of cheese cost £2 16s., what is that per pound ? 20. What will be the cost of 1426 pounds of hay, at $9,75 per ton ? 21. How much must I pay for the transportation of 3840 pounds of iron, from Albany to Buflxilo, at $4,50 per ton ? 22. Bought 124 barrels of potatoes, each containing 2\ bush els, at 33i cents a bushel : what is the whole cost ? 88 APl'I.ICATIONS. 23. If fifteen hundred tons of coal cost $11812,50, what will one ton cost ? 24. If 789 pounds of leatlier cost $142,02, what is that per lb. ? 2a. There are three numbers, whose continued product is 10)200; one of the numbers is 25; another 18: what is the third number? 2G. If Idwt. of gold is worth 92 cents, what would be the weight of $10059,28 in gold? 27. A man sold his house and lot for $4200, and took his pay in railroad stock, at 84 dollars a share ; how many shares did he receive ? 28. A person bought 640 acres of land, at 15 dollars an acre. He afterwards sold 160 acres at 20 dollars an acre ; 240 acres at 18 dollai's, and for the remainder he received 84560. What was his entire gain, and what did he receive per acre on the last sale ? 29. A piece of ground 60 feet long and 48 feet wide is en- closed by a wall 12 feet high and 2^ feet thick : how many cubic feet in the wall ? 30. What will be the cost of transportation, from Montreal to Boston, of 325640 feet of lumber at $2,37i per thousand ? 31. Bought 684 pounds of hay, at $12.40 a ton : what will it cost me ? 32. At $2,121 a hundred, what will 786 feet of lumber cost? 33. How many shingles will it require to cover the roof of a building 40 feet long and 26 feet wide, witli rafters 16 feet long, allowing one shingle to cover 24 square inches ? 34. If 14/3. %oz. 12dwt. 3ffr. of silver be made into 9 tea-pots of equal weight, what will be the weight of each? 35. A man bought 320 barrels of flour for $2688: at what rate must he sell it to gain $1,60 on each barrel ? 36. A farmer has a granary containing Ai[)bi(s/i. Ipk. 2qt. of wheat ; he wishes to put it into 182 bags: how much must he put in each bag ? 37. A trader bought 750 barrels of flour for which he paid $4875 ; ho sold the same for $7,25 a barrel : what was his profit on each banei ? AI'l'LICATIONS. 89 38. How many sheep, at $1,62J a head, can be bought for $1 G9 ? 39. If a person save $6,87-l- a day, how long will it take hira to save $267,75 ? 40. How many canisters, each holding 3lb. lOoz., can be filled from a chest of tea containing 58lb. 41. In 26 hogsheads the leakage has reduced the whole amount to l35Sff(il. 2qt. ; if the same quantity has leaked out of each hogshead, how much still remains in each ? 42. The number of college libraries in the United States in 1850 was 213, containing 942312 volumes : what would be the average number of volumes to each ? 43. A man bought a piece of land for $3475,25, and sold the same for $3801,65, by which transaction he made $3,40 an acre : how many acres were there ? 44. The whole amount of gold produced in California in the year 1855, was as follows : $43313281, sent to the Atlantic States ; $6500000, sent directly to England ; and $8500000 retained in the country. In 1854, the total product of gold in California was $57715000 : how much more was produced in 1855 than in 1854 ? 45. If the forward wheels of a carriage are 12 feet in cir- cumference, and the hind wheels 16 feet 6 inches, how many more times will the forward wheels turn round than the hind wheels, in runninfj a distance of 264 miles ? 46. If a certain township is 9 miles long, 41 miles wide, how many farms of 192 acres each does it contain ? 47. The total number of land warrants issued during the year ending Sept. 30th, 1855, was 34337, embracing 4093850 acres of land : what was the average number of acres to each warrant ? 48. The amount of foreign imports brought into the Uniled States during the fiscal year of 1855 Avas $261382960; during the year 1854 it was $305780253 : how much was the decrease ? 49. The longitude of Philadelphia is 75" 10', and that of New Orleans 89° 2' ; when it is 12 M. at Philadelphia, what is the time at New Orleans .'' 90 APPLICATIONS. 50. The sun passes the meridian at 12 M., the moon at %hr. 30m. P. M. : what is the difference in longitude between the sun and moon ? 51. Two persons, A and B, observed an eclipse of the moon ; A observed its commencement at Qhr. A2mi. P. INI. ; B was in longitude 73° 20', and observed its commencement 23 minutes eai-lier than A: what was A's longitude, and B's time of observation ? 52. If in 11 piles of wood there are 120 cords, 7 cord feet, 5 cubic feet, how much is there in each pile ? 53. If IQavL 2q)\ lllb. lOoz. of flour be put into 9 barrels, how much will each barrel contain ? 54. A miller bought a quantity of wheat for $G25,40, which he floured and put into barrels at an expense of Si 10,12^: what profit did he make by selling it for $900 ? 55. America was discovered Oct. 11th, 1492 : liow long to the commencement of the Revolution, April 19th, 1775 ? 56. From a hogshead of wine a merchant draws 18 bottles, each containing Ijyt. Zgills ; he then fills three 6 gallon demi- jons, and 4 dozen bottles each containing 2qt. Iq^t. Skills: how much remained in the cask ? 57. In 753 G89 yards, how many degrees and statute miles ? 58. In 189mz. 3fur. 6rd. \ft. how many feet ? 59. If 24 men can build 768 rods of wall in 1 day, how many rods can 48 men build in 9 days ? 60. A certain number increased by 1764, and the sum mul- tiplied by 209, gives the product of 7913576 : what is the number ? 61. If a man travel 146mi. Ifur. Ih-d. 14/L in 5 days, how much is that for each day ? 62. If 325 acres of land cost $17712,50, how many acres can be bought for $545 ? 63. A merchant having $324 wishes to purchase an equal number of yards of two kinds of cloth ; one kind was worth 4 dollars a yard, the other was worth 5 dollars a yard : how many yards of each can he buy? APPLICATIONS. 91 64. From one-fourth of a piece of cloth containing QSyd. 3qr. a tailo" cut 5 suits of clothes : how much did each suit contain ? Go. A manufacturer having £5 lO.v,, distributed it among his laborers, giving every man 18d., every woman 12c/., and every boy lOd. ; the number of men, women and boys, were equal : what was the number of each ? GG. It is estimated that 1 out of every 1585 persons in Great Britain is deaf and dumb. The population, according to the census of 1851, was 2093G4G8 : how many deaf and dumb persons were there in the entire population ? 67. A grocer in packing 6 dozen dozen eggs broke half a dozen dozen, and sold the remainder for 1^- cents a piece : how much did he receive for the e2:2;s ? 68. How much time will a man save in 50 years, beginning witli a leap year, l)y rising 45 minutes earlier each day ? GD. liichard Roe was born at 6 o'clock, A. M., June 24th, 18-32 : what will be his age at 3 o'clock, P. M., on the 10th day of January, 1858? 70. During the year 1855, there were shipped to Great Britain, from the United States, 408434 barrels of tloiir ; 2550092 bushels of wheat; 1048540 bushels of corn. Supposing the flour to have sold for $10,25 a barrel, the wheat for $2,121 a bushel, and the corn for $0,94 a bushel, what was the value of the whole ? 71. A man dying without making a will, left a vridow and 4 children. The law provides, in such cases, that the Avidow shall receive one-third of the personal propei'ty, and thai the re- mainder shall be equally divided among the children. The estate was valued as follows : a farm, at $5000 ; 5 horses, at $85 each; a yoke of oxen, for $110; 25 cows, at $22 each; 150 sheep, at $2 each ; some lumber, at $45 ; forming utensils, at $174; household furniture, at $450 ; grain and hay, at $380 : what was the share of the widow and each child ? 72. The amount of gold coin in the United States in 1855 was estimated at about $241200000. Adopting the same ratio of increase as from 1850 to 1855, the population of the United 92 APPLICATIONS. States in 1855 would be about 26800000. In an equal distri- biition of the gold, how much would eacli person receive ? 73. How many sliingles will it take to cover the two sides of the roof of a building, 55 feet long, with rafters IGi feet in length, allowing each shingle to be 15 inches long and" 4 inches wide, and to lay one-third to the weather ? 74. If the longitude of St. Petersburgh is 30° 45' east, and that of Washington 77° 2' west, what is the difference of lon- gitude between the two places, and the difference of time ? 75. When it is 6 o'clock, A. M., at Washington, what is the time at St. Petersbursrh ? 76. A vessel sails from New York to Liverpool. After a number of days the captain, by taking an observation of the sun, finds that his chronometer, which gives New York time, differs \hr. 4:4-m. from the time at the place of observation. If his chronometer shows the time to be Shi: 12 mi. P. M., what is the correct time, at the place of observation, and how far is he east from New York ? 77. A cistern containing 960 gallons, has two pipes; 45 gallons ]-un in every hour by one pipe, and 25 gallons run out by the other: how long a time will be required to fdl the cistern ? 78. A speculator sold 840 bushels of wheat for $2180, which was S500 more than he gave for it : what did it cost him a bushel ? 79. The wliole number of gallons of rum manufactured in the United States in 1850, was 6500500 gallons ; if it be valued at 50 cents a gallon, how many schoolhouses could be built, worth $750 each, with the proceeds ? 80. A farmer sold a grocer 30 bushels of potatoes at 37-i cents a bushel, for which he received 6 gallons of molasses at 45 cents a gallon ; GO pounds of mackerel at 6^- cents a pound, and tlie remainder in sugar at 10 cents a pound : how many pounds of sugar did he receive ? 81. If a man travel 12;///. Sfu?: 20a/. in one day, how long will it take him to travel 174////. \far. at the same rate ? APPLICATIONS. 93 82. If a man sell '2har. 12^/al. 2qi. of beer in one week, Low much will he sell in 12 weeks ? 83. A hquoi- merchant had ooO pint bottles, 400 quart bottles, 350 two quart bottles, 375 three quart bottles, and 150 jugs, liolding a gallon each : hew many barrels of wine will fill them ? 84. How many yards of carpeting, one yard wide, will it take to cover the floors cf two parlors, each 18 feet long, and IG feet wide, and what will it cost at $l,o3i a yard? 85. How many rolls of wall paper, each 10 yards long and 2 feet wide, will it take to cover the sides of a room 22 feet long and 1 6 feet wide and 9 feet high ? 8G. Two persons ai'e Imi. Afiir. 20/ d. apart, and are travel- ling the same way. The hindmost gains upon the foremost 5 rods in travelling 25 rods : how far must he travel to over- take the foremost ? . 87. A man sold 500 bushels of wheat at $1,75 a bushel, and took his pay in sugar at 5 cents a pound. He afterwards sold one-half of it : what quantity of sugar had he left ? 88. A man bought 7 barrels of sugar at Sl2,87-l- a barrel; he kept two barrels for his own use, and sold the remainder for what the whole cost him : what did he receive per barrel ? 89. A flour merchant bought a quantity of flour for $18750, and sold the same for $26250, by which he gained $3 a barrel how many barrels were there ? 90. Three men rented a farm and raised d64:biish. 2jjI: AqL of grain, which was to be divided in proportion to the rent paid by each. The first was to have one-half the whole ; the second one-third the remainder; and the third had what was left : how much did each have ? 91. A vessel in longhude 70^ 25' east, sails 105° 30' 56'- west, then 40° 50' east, then 10' 5' 40" west, then 39° 11' 36" east ; in what longitude is she then, and how many days will it take her to sail to longitude 77° west, if she sail 3° 20' each da,}' ? 92. A privateer took a prize worth $25000, which was divided into 125 shares, of which the captain took 12 shares ; 94 APPLICATIONS. 2 lieutenants, eacli 5 shares ; 6 midshipmen, each 3 shares ; ajid the remainder was divided equally among 85 seamen : how much did each receive ? 93. If the longitude of Boston is 71° 4', and a gentleman in travelling from Boston to Chicao;o iinds that his watch is Ihr. 5m. 44sec. too fast by the time of the latter place, what is the longitude of Chicago, provided his watch has kept time accurately ? 94. What time would it be in Boston when it was 8/ir. 21 mi. ZOsec, A. M., in Chicago ? 95. What time would it be at Chicago when it was 12 M. at Boston ? 96. Two places lie exactly east and west of each other, and by observation it is found that the sun comes to the meridian of the latter place 1 hour and 16 minutes after the former: bow far apart are they in degrees and minutes of longitude ? 97. In 12 bales of cloth, each bale containing 16 pieces, and each piece containing 20 ell English, how many yards ? 98. How many eagles can be made from 2Ub. 4oz. (5pwt. ISgr. of gold, making no allowance for waste, if each eagle weighs llpwls. 9(/r. ? 99. A man paid $3284,82 for some wheat. He sold 740 bushels at 2 dollars a bushel ; the remainder stood him in $1,42 a bushel : how many bushels did he purchase ? 100. A speculator gave $8968 for a certain number of barrels of flour, and sold a part of it for $2618, at $7 a barrel, and by so doing lost $2^ on each barrel ; for how much must he sell the remainder to gain $1060 on the whole? 101. A man sold 105/1. 2R. 2QF. of land ibr as many dollars as there were perches of land, payable in instalments, at the rate of 1 dolhu- an hour. If the contract was closed at 12 o'clock, M., April 1st, 1856, what length of time will be allowed the purchaser to pay the debt, reckoning 365 days 6 hours to the year ? PKOPERTIKS OF NUMBERS. 95 PROPERTIES OF NUMBERS. PRIME AND COMPOSITE NUMBERS. 83. An Integral Number is the unit 1, or a collection of Buch units. 84. One number is said to be divisible by another when the quotient is an integral number. The division is then said to be exact. 85. A Composite Number is one that may be produced by the multiplication of two or more numbers, called factors ; thus, 30 = 2 X 3 X 5, is a composite number, in which the factors are 2, 3 and 5. Note 1. — A composite number is exactly divisible by any one of its factors. 86. A Prime Number is a number that is divisible only by itself and by 1 ; thus, 1, 2, 3, 5, 7, 11, 13, &c., are prime numbers. 87. Two numbers are said to be prime to each other when they have no common factor ; thus, 4 and 9 are 2^r//?ie to each other, though both are composite numbers. 88. Any number (prime or composite), as 26, may be put under the form, 1 X 26; hence, every number is divisible by itself and by 1, and therefore, these are not reckoned among i\iQ factors or divi'sos either of prime or composite numbers. 83. What is an integral number 1 84. When is one number said to be divisible by another] How is the division then said to be 1 85. What is a composite niamber 1 Bv what is a composite numbej always divisible 1 86. What is a prime number '; 87. When are two numbers prime to each other 1 88. What numbers are not reckoned among the divisors of prime or composite numbers 1 96 PKOPEKTIES OF NrHIBERS. 89. Every factor of a composite number is a divisor, and is either prime or composite ; and, since every composite factor may be again divided, it follows that Every number is equal to the product of all its prime factors. For example, 24 = 3 X 8 ; but 8 is a composite number of which the factors are 2 and 4 ; and 4 is a composite number of which the factors are 2 and 2 ; hence, 24 = 3x 8 = 3x2x4=33x2x2x2; and 60 = 5x12 = 5x3x4 = 5x3x2x2. Hence, to find the prime factors of any number : Divide the number by any prime member that will exactly divide it: then divide the quotient by any prime number that will exactly divide it^ and so on, till a quotient is found which is prime ; the several divisors and the last quotient will be the prime factors of the given number. Note. — It is most convenient, in practice, to use at each division the least prime number that is a divisor. 1. What are the prime factors of 105 ? Analysis. — Three being the least divisor that operation. is a prime number, Ave divide by it, giving the 3)105 quotient 35 ; then 5 is the least prime divisor 5)35 of this quotient : hence, 3, 5 and 7 are the 7 prime factors of 105. EXAMPLES. 1. What are the prime factors of 9? 10? 12? 14? IC? 1«? 24? 27? 28? 2. What are the prime factors of 30? 22? 32? BG? 38? 40? 45? 49? 3. What are the prime factors of 50 ? 56? 58? 60? 64 66? 68? 70? 72? 4. What are the prime foctors of 7G ? 78? 80? 82? 84? 86? 88? 90? 89. To what product is every number equal ] How do you find the prime factors of any number 1 PROPERTIES OF NUMBERS. 97 5. What are the prime factors of 92? 94? 96? 98? 99? 100? 102? 104? G. What are the prime fxctors of 105? lOG ? 108? 110? 115? 116? 120? 125? 7. What are the prime foctors of 302 ? 305 ? 604 ? 875 ? 975 ? 055 ? Note. — The prime factors, "when the numbers are small, may generally be seen by inspection. The teacher can easily increase the number of examples. 90. When there are several numbers, and it is required to find the prime factors common to all of them : Find the in'une factors of carh, and then select thoae factors ivhich are common to all the members. 8. What are the puime factors common to 150, 210 and 270 ? 9. What are the prime factors common to 42, 126, and 168? 10. What are the prime factors common to 105, 315 and 525 ? 11. Wliat are the prime factors common to 84, 126 and 210? 12. What are the prime factors common to 168, 25.6, 410, and 820 ? 13. What are the prime factors common to 420, 630, 1050, and 2100 ? 91. DIVISIBILITY OF NUMBERS. 1. Two is the only even number which is prime. 2. Two divides every even number, and no odd number. 3. Three divides every number the sum of Avhose figures is divisible by 3. 4. Four divides every number when the two right hand figures are divisible by 4. 5. Five divides every number which ends in or 5. 6. Six divides every even number that is divisible by 3. 7. Ten divides every number ending in 0. 90. How do you find the prime factors common to several numbers ? 91. 1. How many even numbers arc prims'! 2. What numliers will 2 divide ! 3 What numbers will 3 divide 1 4. What numbers will 4 divide 1 5. What numbers will ^ divide 1 6. ^^'hat numbers will 6 divide 1 7. What 98 PKOPERTIES OF NUitBERS. 8. When the divisor is a composite number, and when fhe iividend and partial quotients arc successively divisible by i/i factors, the division will be exact (Art. 57)- For, dividing by the factors separately, gives the same quo tient as dividing by their product (Art. 70). 9. Any number u-hich will divide one factor of a product loil divide the product. Thus, take any number, as 30 = 5x6; any number which will divide 5 or 6 will divide 30. 10. Any number which will exactly divide each of ta-o num- bers will divide their sum : and any number which will divide their sum and one of the numbers, toill divide the other. For, take any two numbers, an 9 and 12 ; then, 9 + 12 = 21. Now, any divisor that will divide two of these numbers will divide the other ; else, we should have a whole number equal to a fraction, which is impoi>sible. 11. Any number which unll exactly divide each of two num- bers will divide their difference : and any number ivhich will divide their diffirence and one of the numbers, will divide the other. For, let 24 and 8 be any two numbers ; then, 24-8 = 16. Now, any divisor that will divide two of these numbers will divide the other ; else, we shoidd have a whole number equal to u fraction, which is impossible. 12. Jf there is a remainder after division, any number which wilt exactly divide the dividend and divisor will also divide the remainder. numbers will 10 divide 1 8. "When will llif divi-or exactly divide the divi- dend ! 9. When will any minihor divide a p rod net ! 10. \\ hen u ill a number divide the sum of two numbers ! When will it divide either .)f them separately ! 11. When will a number exactly divide the dilVereiico of two numbers ! 12. If a nmnher divides the dividend and divisor whil kthcr number will it alwavs divide'' GREATEST COMMON DIVISOR. 99 For, we always have Dividend = Divisor x Quotient -|- Eem. or Dividend — Divisor X Quotient = Rem. ; hence, by principle (11) any number which will divide the divi- dend and divisor will also divide the remainder, after division. GREATEST COMMON DIVISOR. 92. A Common Divisor of two or more numbers is any number that will divide each of them without a remainder; hence, it is merely a common factor of the numbers. 93. The Greatest Common Divisor of two or more numbers is the greatest number that will divide each of them without a remainder; hence, it is their greatest coxanon factor. For example, 2 and 3 are common divisors of 12 and 18; but G is their greatest common divisors, since there is no num- ber greater than 6 that will exactly divide both of them ; hence, it is their greatest common factor. Note. — Since 1 and the number itself will divide every number, they are not reckoned among the common divisors. Hence, to find the greatest common divisor of two or more numbers, I. Resolve each number into its 2>i'ime factors : n. Tlie product of all the factors common to each result will be the greatest common divisor. EXAMPLES. 1. "What is the greatest common divisor of 12 and 20? Analysis. — There are three prime fac- tors in 12 ; viz., 2, 2 and 3 : there are three operation. prime factors in 20; viz., 2, 2 and 5 : the 12 = 2X2x3 factors 2 and 2 are common; hence, 2x2 ==4 20 = 2x2x5 is the greatest common divisor. 92. Wliat is a common divisor of two or more numbers ? 93. Wbat is the sreatest common divisor of two or more numbers ? Ho^v o 4o you find the greatest common divisor of two or more numbers I 100 GREATEST COMMON DIVISOR. 2. What is the greatest common divisor of 18 and 36. 3. What is the greatest common divisor of 12, 24 and 60 4. What is the greatest common divisor of 15, 50 and 40 ? 5. What is tlie greatest common divisor of 24, 18 and 144? 6. Wliat is the greatest common divisor of 50, 100 and 80 ? 7. What is the greatest common divisor of 56, 84 and 140 ? 8. What is tlie greatest common divisor of 84, 154 and 210 ? SECOND METHOD, 94. When the numbers are large, another method is used for finding their greatest common divisor. 1. Let it be required to find the greatest common divisor of the numbers 216 and 408. Analysis. — The greatest common divisor opkration. cannot be greater than the least number 216. 216)408(1 Now, as 216 will divide itself, let us see if it 216 will divide 408; for if it will, it is the great- 192)216(1 est common divisor sought. Making the 192 division, we find a quotient 1 and a remain- 24)192(8 der 192; hence, 216 is not a common di- 192 visor. The greatest common divisor of 216 and 408 will divide the remainder 192 (Art. 91-12); and if 192 will exactly divide 216, it will be the greatest common divisor. Wc find that 192 is contained in 216 once, aud a remainder 24. The greatest comtnon divi.^^or of 192 and 216 will divide the remainder 24; and if 24 will exactly divide 192, it will also divide 216, and consequently 408 ; now 24 exactly divides 192, and hence is the, greatest common divisor sought. Hence, to find the greatest common divisor, Divide the greater number hy the leas, and then, divide the preceding divisor by the remainder, and so on, till nothing remains : the last divisor will be the greatest coinmon divisor. No FES. — 1. If the last remainder is 1, the numbers haA^c no com mon divisor ; that is, they are prime with respect to each other (Art. 87). 94. ^"^'l^at is tlic rule when the numbers are large ? GREATEST COMMON DIVISOK. 101 2. If, in the course of tne opcralion, any one of the remainders is a prime number^ and will not exactly divide the ■preceding divisor, it is certain that no common divisor exists, aud it is unnecessary to divide further. EXAMPLES. 1. "What is the greatest common divisor of 3328 and 4592 ? 2. What is the greatest common divisor of 2205 and 4501 ? 3. What is the greatest number that -will divide 1G082 and 25740 ? 4. What is the greatest number that will divide 620, 1116 and 1488 ? 5. What is the greatest common divisor of 5270, 5952, 5394 and 3038 ? 6. What is the greatest common divisor of 4617, 7695, 6642 and 8424 ? 7. A farmer has 315 bushels of corn, and 810 bushels of wheat ; he wishes to draw the corn and wdieat to market separately in the fewest number of equal loads : how many- bushels must he draw at a load ? 8. The Illinois Central Railroad Company have 15750 acres of land in one location, and 21725 acres in another. They wish to divide the whole into lots of equal extent, containing the greatest number of acres that will give an exact division : how many acres will there be in each lot ? 9. A man has a corner lot of land 1044 feet long, and 744 feet wide. The adjacent sides are bounded by the highway and he wishes to build a boai'd fence with the fewest panels of equal length : what must be the length of the panels ? 10. A farmer has 231 bushels of barley, 369 bushels of oats, and 393 bushels of wheat,' all of which he wishes to put into the smallest number of bags of equal size, without mixing : how many bushels must each bag contain ? 11. Three persons. A, B, and C, agree to purchase a lot of 63 cows at the same price per head, provided each man can thus invest his whole money. A has $286, B .^462, and C 8638 ; how many cows could each man purchase ? 102 LEAST COMMON MULTIPLE. LEAST COMMON MULTIPLE. 95. A Multiple of a number is any product in -which th« number enters as a factor ; hence, a muhiple of any number is exactly divisible by the number. 96. A Common Multiple of two or more numbers is any number which each -will divide -without a remainder. 97. The Least Common Multiple of two or more num- bers is the least number -svhich they will -separately divide with out a remainder. Notes. — 1. Since the least common multiple is exactly divisible by a divisor, it can be resolved into two factors, one of which is the divisor and tlie other the quotient. 2. !f the divisor be resolved into its prime factors, the equal factoi of the least common multiple maybe resolved into the same factors hence, the least common multiple will contain every prime factor of it. divisor. 3. The question of finding the least common multiple of several numbers, is therefore reduced to finding a number which shall con- tain all their prime factors and none others. 1. What is the least common multiple of 6, 12 and 18 ? A.NALTSIS. — Havmg placed the given num- bers in a line, if we divide by 2, we find the operation. quotients 3, 6 and 9 ; hence, 2 is a prime fac- 2 )6 . . 12 . . 18 tor of all the numbers. Dividing by 3, -we 3)3 . . 6 . . 9 find that 3 is a prime factor of the quoti- 1 . . 2 . . 3 ents 3, 6, and 9 ; and hence, the quotients 2X3X2x3 = 36 2 and 3 are prime factors of 12 and 18; hence, the prime factors of all the numbers are 2, 3, 2 and 3, and their product 36 is the least common multiple. 98. Therefore, to find the least common multiple of several numbers : 95. Wliat is a multiple of a number \ 96. What is a common multiple of two or more numbers 1 97. What is the least common multiple of two or more numbers ? 9S. How do you find the least common multiple ol several numbers' COMMON MULTIPLIi. 103 I. Place the numbers on the same line, and divide by any prime number that tuill exactly divide tiuo or more of them, and set doivn in a line below the quotients and the undivided members. II. Then divide as before, until there is no prime number greater than 1 that will exactly divide any two of the numbers. III. Then multiply together the divisors and the numbers of the lower line, and their product tvill be the least common multiple. Note. — If the numbers have no common prime factor, their pro- duct will be their least common midtiple. EXAMPLES. 1. What is the least common multiple of 4, 9, 10, 15, 18, 20, 21 ? 2. What is the least common multiple of 8, 9, 10, 12, 25, 32, 75, 80 ? 3. What is the least common multiple of 1, 2, 3, 4, 5, 6, 7,9? 4. What is the least common multiple of 9, 16, 42, 63, 21 14, 72 ? 5. What is the least common multiple of 7, 15, 21, 28, 35, 100, 125 ? 6. What is the least common multiple of 15, 16, 18, 20, 24, 25, 27, 30 ? 7. What is the least common multiple of 9, 18, 27, 36, 45^ 54? 8. What is the least common multiple of 4, 10, 14, 15, 21 ? 9. What is the least common multiple of 7, 14, 16, 21, 24? 10. What is the least common multiple of 49, 14, 84, 108, 98? 11. A can dig 9 rods of ditch in a day; B 12 rods in a day; and C 1 6 rods in a day : what is the smallest number of rods that would afford exact days of labor to each, working alone ? In what time would each do the whole work ? 12. A blacksmith employed 4 classes of workmen, at $15, $16, 121 and $24 per month, for eacli man respectively, paying to each class the same amount of wages. Required the least 104 CANCELLATION. amount that will j^ay either class for 1 month ; also, the num- ber of men in each class ? 13. A farmer has a number of ba"js containinsr 2 bushels each ; of barrels, containing 3 bushels each ; of boxes, containing 7 bushels each ; and of hogsheads, containing 15 bushels each : what is the smallest quantity of wheat that would fill each an exact number of times, and hoio many times would that quan- tity fill each ? 14. Four persons start from the same point to travel round a circuit of 300 miles in circumfei'cnce. A goes 15 miles a day, B 20 miles, C 25 miles, and D 30 miles a day. How many days must they travel before they will all come together again at the same point, and how many times will each have gone round ? Note. — First find the number of days that it will take each to travel round the circuit. CANCELLATION. 99. Cancellation is a method of shortening Arithmetical operations by omitting or cancelling common factors. 1. Divide 36 by 18. First, 36 = 9 x 4 ; and 18 = 9 x 2 2. Analysis. — Thirty-six divided by 18 is operation. equal to 9 X 4 divided by 9 x 2 : by can- 36 x 4 _ celling, or striking out the 9's, we have 18 ~ 0X2 4 divided by 2, which is equal to 2. Note. — The figures cancelled arc slightly crossed. The operations, in cancellation, depend on two principles : 1 . JVie cancelling of a factor, in any number, is equivalent to dividing the number by that factor 2. If the dividend and divisor he both divided by the same number, the quotient will not be changed. 99. What is cancellation 1 On what principles do the operations of cancellation depend ? CANCELLATION. 105 PRINCIPLES AND EXAMPLES. 1. Divide 5G by 32. Analysis. — Resolve the dividend and ' operation. divisor into factors, and tlien cancel those 56 S x 7 7 which are common. 32 ;8 x 4 4 2. In 72 times 25, how many times 45 ? Analysis. — We see that 9 is a factor of 72 and 45. Divide by 9, and write the q^uotient 8 over 72, and the quotient 5 below 45. Again, 5 is a fac- operation. tor of 25 and 5. Divide 25 by 5, and 8 5 write the quotient 5 over 25. Dividing "^^ ^ ^-■^ _ .„ 5 by 5, reduces the divisor to 1, which A? need not be set down : hencC; the true quotient is 40. Note. — The operation may be performed in another way, by wri- ting the divisor on the left of a vertical line, and the dividend on the right: in operation. which case, the quotients, in cancelling, ^ are written above, and at the side of the numbers, as 5, 8 and 5. If we conceive 5 the horizontal line, first used, to be turn- a .^ ed up from left to right, the dividend, which was above the line, will fall at the right, and the divisor, which was below it, at the left. 100. Hence, to perform the operations of cancellation : I. Resolve the dividend and divisor into such factors as shall give all the factors common to both. II. Cancel the common factors and then divide the product of the remaining factors of the dividend hy the product of the re- maining factors of the divisor. Notes. — 1. Since every factor is cancelled by division^ the quotient 1 always takes the place of the cancelled factor, but is omitted when it is a multiplier of other factors. 2 If one of the numbers contains a factor equal to the product of two or more factors of the other, all such factors may be cancelled. 100. How do you perform the operations of cancellation T 106 OA]S-CELLATION. 3. If the product of two or more factors of the dividend is equal to the product of two or more factors of the divisor, such factors may be cancelled. 4. It is generally more convenient to set the dividend on the right of a vertical line and the divisor on the left. EXAMPLES. 1. What is the quotient of 2x4x8x13x7x16 divid- ed bj 26 X 14 X 8 ? 2. What is the quotient of 42 X 3 X 25 x 12 divided hj 28 X 4 X 15 X 6? 3. What is the quotient of 125 x 60 X 24 X 42 divided by 25 X 120 X 36 X 5? 4. How many times isllx39x7x2 contained in 44 x 18 X 26 X 14? 5. What is the quotient of 8 times 240 multiplied by 5 times 114, divided by 24 time.s 57 multiplied by 6 times 15 ? 6. What is the value of (22 + 8 + 16) X (18 + 10 + 21) divided by (9 + 5 + 7) x (15 + 8) ? 7. Divide (140 + 86 - 34) x (107 - 19) by (237 - 141) X (17 + 20 - 15) ? 8. Divide [12 X 5 - 2 X 9] x (42 + 30) by (5 x 8) X (2 X 9) X (10 + 17) ? 9. What is the quotient of 240 x 441 X 16 divided by 175 X 56 X 27? 10. What is the quotient of 64 times 840 multiplied by 9 times 124, divided by 32 times 560 multiplied by 4 times 31 ? 11. How many dozens of eggs, worth 14 cents a dozen, must be given for 18 pounds of sugar, woi'th 7 cents a pound ? 12. A dairyman sold 5 cheeses, each weigliing 40 pounds, at 9 cents a pound : how many pounds of tea, worth 50 cents a pound, must he receive for the cheeses ? 13. Bought 12 yards of cloth at Sl,84 a yard, and paid for it in potatoes at 48 cents a bushel : how many bushels of pota- toes will pay for the cloth ? 14. How many firkins of butter, each containing 56 pounds, CANCELLATION. 107 at 25 cents a pound, will pay for 4 barrels of sugar, each weighing 175 pounds, at 8 cents a pound ? 15. A man bought 10 cords of wood, at 20 shillings a cord, and paid in labor at 12 shillings a day : how many days must he labor ? 16. How many pieces of cloth, each containing 36 yards, av $3,50 a yard, must be given for 96 barrels of flour, at $10,50 a barrel ? 17. A farmer exchanged 492 bushels of wheat, worth §1,84 a bushel, for an equal number of bushels of barley, at 87 cents a bushel, of corn at GO cents a bushel, and of oats at 45 cents a bushel : how many bushels of each did he receive ? IS. How many barrels of flour, worth $7 a barrel, must be given for 250 bushels of oats, at 42 cents a bushel ? 19. If 48 acres of land produce 2484 bushels of corn, how many bushels will 120 acres produce? 20. A man works 12 days at 9 shillings a day, and receives in pay wheat at two dollars a bushel : how many bushels did he receive ? 21. A grocer sold 6 hams, each weighing 14 pounds, at 10 cents a pound, and took his pay in apples at 48 cents a bushel : how many bushels of apples did he receive? 22. How long will it take a man, travelling 36 miles a day, to go the same distance that another man has travelled in 15 days at the rate of 27 miles a day ? 23. A man took 4 loads of apples to market, each load con- tainins: 12 barrels, and each barrel 3 bushels. He sells them at 45 cents a bushel, and receives in payment, a number of boxes of tea, each box containing 20 pounds, Avorth 72 cents a pound : how' many boxes of tea did he receive ? 108 COMMON FRACTIONS. COMMON FRACTIONS. 101. The unit 1 denotes an entire thing, as 1 apple, 1 chair, 1 pound of tea. If the unit 1 be divided into two equal parts, each part is called one-half. If the unit 1 be divided into three equal parts, each part is called one-third. If the unit I be divided into four equal parts, each part is called one-fourth. If the unit 1 be divided into twelve equal parts, each part is called one-twelfth ; and if it be divided into any number of equal parts, we have a like expression for each part. The parts are thus written : 1 is read, one-half. 1 - - one-third. J- - - one-fourth, 4 i - - one-liflh. i - - one-sixth. 1 is read, one-seventh. •|- - - one-eighth. one-tenth. one-fifteenth. one-fiftieth. 1 15 JL 50 The ^, is an entire half ; the 1, an entire third ; the 1, an entire fourth ; and the same for each of the other equal parts ; hence, each equal part is an entire thing, and is called a frac- tional unit. The unit, or whole thing which is divided, is called the unit of the fraction. NoTK. — In every fraction let the pupil distinguish carefully, be- tween the unit of the fraction and the fractional unit. The first is the whole thing from which the fraction is derived; the second, orie of the equal parts into which that thing is divided. 101. Wha» is a unit 1 What is each part called when the unit 1 is divid- ed into two equal parts ! When it is divided into 3] Into il Into 51 Into lai COMMON FRACTIONS. 109 102. Each fractional unit may, like the unit 1, become the base of a collection : thus, suppose it were required to express 2 of each of the fractional units : we should then write 2 2 which is read 2 halves = i x 2. 2 3 _ . . . 2 thirds = ^ x 2. 2 4 _ - - _ 2 fourths = 1x2. * - - . _ 2 fifths = i X 2. &;c., &;c., &c., &c. If it were required to express 3 of each of the fractional units, we should write |- which is read 3 halves —1x3. f - - - - 3 thirds =1x3. f - - - - 3 fourths = 1x3. 3 . . . . 3 fifths =1x3. &c., &c., &c., &c. ; hence, A Fraction is one of the equal parts of a unit, or a collec- tion of such equal parts. Eractions are expressed by two numbers, one written above the other, with a line between them. The lower number is called the denominator, and the upper number the numerator. The denominator denotes the number of equal parts into which the unit is divided ; and hence, determines the value of the fractional unit. Thus, if the denominator is 2, the fractional unit is one-half; if it is 3, the fractional unit is one-third ; if it is 4, the fractional unit is one-fourth, &cc., Sec. The numerator denotes the number of fractional units taken. Thus, f denotes that the fractional unit is i, and that 3 such units are taken; and similarly for other fractions. How may the one-half be regarded 1 The one-third ? The one fourth ? What is each part called ! "What is the unit of a fraction 1 What is a fractional unit ! How do you distinguish between the one and the other ! 102. May a fractional unit become the base of a collection 1 What is a fraction ? How are fractions expressed ? What is the lower number called ? What is the uppemumber called \ What does the denominator denote 7 What does trhe numerator denote ! In the fraction .'} fifths, what 110 COMMON FRACTIONS. In the fraction f , the base of the collection of fractional units is ^, but this is not the primary base. For, ^ is one-Jrfth of the unit 1 ; hence, the primary base of every fraction is the u?iit 1. 103. If we suppose a second unit to be divided into the eame number of equal parts, such parts may be expi'essed in the same collection with the parts of the first : thus, I is read 3 halves. •^ - - - 7 fourths. i_6 . . . 16 fifths. i_8 . . . 18 sixths. ^-f - - - 25 sevenths. 104. A %\hole number may be expressed fractionally by writing 1 below it for a denominator. Thus, 3 may be written y and is read, 3 ones. 5 --.- A ---5 ones. 6 ---- |. -.. 6 ones. 8 ---- ^ _._ 8 ones. But 3 ones are equal to 3, 5 ones to 5, 6 ones to 6, and 8 ones to 8 ; hence, the value of a number is not changed by placing 1 under it for a denominator. 105. If the numerator of a fraction be divided by its denomi- nator, the integral part of the quotient will express the number of entire units used in forming the fraction ; and the remainder will show how many fractional units are over. Thus, y are equal to 3 and 2 thirds, and is written y = 3|- : hence, A fraction has the same form as an unexecuted division. is the fractional base 1 What is the primary base 1 What is the primary base of every fraction 1 103. If a second unit be divided into the same number of equal parts, may the parts be expressed with those of the first I How many unita have been divided to obtain G thirds 1 To obtain 9 halves 1 12 fourths 1 104. How may a whole number bo expressed fractionally] Does this chanrre the value of the number ! 105. If the numerator be divided by the denominator, what does the quotient show 1 What does the remainder show 1 What form has a frai> lion 1 Wluit arc the seven i)rinciplc8 which foiliiw ? COMMON FRACTIONS. Ill From what has been said, we conclude that, 1st. A fraction is one of the equal parts of a unit, or a col- lectioji of such equal parts : 2d. Tlie denominator shous into hoxo many equal parts the unit is divided, and hence indicates the vcdue of the fractiomd unit : 3d. 27ie numerator shows how inany fractional units are taken . 4th. 'llie value of every fraction is equal to the quotient arising from dividing the numerator hy the denominator : 5th. When the numerator is less than the denominator, the value of the fraction is less than 1 : 6th. When the numerator is equal to the denominator, the value of the fraction is equal to 1 : 7th. When the numerator is greater than the denominator, the value of the fraction is greater than 1. EXA3IPLES IN WRITING AND READING FRACTIONS. 1. Read the following fractions : S 7 5 _6 2J ]_6 j_a_ 9' 12' 3' 15J 9 ' 7 ' 104' What is the unit of the fraction, and what the fractional unit in each example ? How many fractional units are taken in each ? 2. Write 15 of the 19 equal parts of 1. Also, 37 of the 49 equal parts of 1. 3. If the unit of the fraction is 1, and the fractional unit one-fortieth, express 27 fractional units. Also, 95. Also, 106. Also, 87. Also, 41. 4. If the unit of the fraction is 1, and the fractional unit one 68th, express 45 fractional units. Also, 56. Also, 85. Also, 95. Also, 37, 5. If the unit of the fraction is 1, and the fractional unit one 90th, express 9 fractional units. Also, 87. Also, 75. Also, 65. Also, 85. Also, 90. Also, 100. DEFINITIONS. 106. A Proper Fraction is one whose numerator is less than the denominator. 100. What is a proper fraction ? Give examples. 112 COMMOX FK ACTIONS. The following are proper fractions : 1 JL 1 3. 3^ S JL 8. 5 2' 3' 4' 4' 7' 8' 10' 9' 6' 107. Ax Improper Fraction is one whose numerator is equal to, or exceeds the denominator. Note. — Such a fraction is called improper because its value equals or exceeds 1. The following are improper fractions : 3 A 6. 8^ 1 12. JLt ±9_ 2' 3' 5' 7' 8' 6 ' 7 ' 7 * 108. A Simple Fraction is one whose numerator and de- nominator are both whole numbers. Note. — A simple fraction may be either proper or improper. The following are simple fractions : J.3^5_8.98..6X 4' 2' 6' 7' 2' 3' 3' 5* 109. A Compound Fraction is a fraction of a fraction, or eeveral fractions connected by the word of. The following are compound fractions : 1 of 1 1 of 1 of 1 i of 3 J- of 1 of 4 2^4' 3 "^ 2 3' 6 ' 7 Ul g Ui "i. 110. A Mixed Number is made up of a whole number and a fraction. The following are mixed numbers : 31, 41, 6f, 5f, Gf, 31. 111. A Complex Fraction is one whose numerator or de- nominator is fractional ; or, in which both are fractional. The following are complex fractions : {}) J_ (t) ^ 5' 191' (!') 691- 107. Wliat is an improper fraction? Wliy improper 1 Give examples 108. Wliat is a simple fraction 1 Give examples. May it be proper or improper 1 109. M'liat is a compound fraction 1 Give examples, 110. ^\■hat is a mixed numberl Give examples, 111. What is a complex fraction 1 Give examples. COMMON FJRACTIONS. 113 112. The numerator and denominator of a fraction, taken together, are called the terms of the fraction : hence, every fraction has two terms. FUNDAMENTAL PROPOSITIONS. 113. By multiplying the unit 1, we form all the whole numbers, 2, 3, 4, 5, G, 7, 8, 9, 10, &c.; and by dividing the unit 1 by these numbers we form all the fractional units, 2' 3' 4' 5' 6' 7' 8' 9' TO' "^^* Now, since in 1 unit there are 2 halves, 3 thirds, 4 fourths, 5 fifths, 6 sixths, &;c., it follows that the fractional unit becomes less as the denominators are increased: hence, Any fractional imit is such apaj-i ofl, as 1 is of the denominator. Thus, ^ is one-half of 1, since 1 is one-half of the denomi- nator 2 ; i is one-third of 1, since 1 is one-third of 3 ; i is one fourth of 1 ; |-, one-fifth of 1, &c. &c. 114. Let it be required to multiply ^ by 4. Analysis. — In f there arc 3 fractional units, operation. each of which is i, and these are to be taken -1x4=: ^^ = J^. 4 times. But .3 things taken 4 times, gives 12 things of the same kind ; that is, 12 eighths ; hence, the product is 4 times as great as the multiplicand : therefore, we have Proposition I. — If the numerator of a fraction he multiijlicd by any number^ the fraction will he muIti'pUed as many times as there are units in that number. 112. How many terms has every fraction 1 "What are they 1 113. How may all the whole numbers be formed ? How may the frac- tional units be formed ? What part of one, is one-half] What part of 1 is any fractional unit ] 114. What is proved in proposition 11 6 114 PRINCIPLES OP EXAMPLES. 1. Multiply f by 6, by 7. 2. Multiply I by 4, by 9. 3. Multiply g?,- by 11, by 12. 4. Multiply^^by 12, by 14, 115. Let it be required to multiply -^ by 4. Analysis. — In ^ there are 5 fractional lits, each of which is -^^- ^^ ''^'® '^'"^"ide operation. the denominator by 4, the quotient is 3, and -^ X 4 r= -pr^ 5. Multiply fj- by 3, by 4. G. Multiply If by 7, by 9. 7. Multiply A|. by 5, by 10. 8. Multiply -1^- by 3, by 11. the fractional unit becomes ^, which is 4 times as great as -^j because, if ^ be divided into 4 equal parts each part will be j\j. If wc take this fractional unit 5 times, the result ^ will be 4 times as great as ^ ; therefore, we have Proposition II. — If the denominator of a fraction be divided by any number^ the value of the fraction will be increased as many times as there are units in that number. EXAMPLES. 1. Multiply I by 2, by 4. 2. Multiply 1^ by 8, by 4, 2. 3. Multiply ^\ by 2, 3, 4, 6,8. 4. Multiply ^ by 6, by 5, 10, 15. 5. Multiply -}| by 2, 3, 4, G, 8, 12, 16, and 24. 116. Let it be required to divide -^j by 3 G. Multiply fo by 2, 4, 5, 10, 20. 7. Multiply 3^3- by 7, and by 5. 8. Multiply ^y by 21, 6, 7, 3, and 2. 9. Multiply i;i- by 2, 3, 4, % 9, and 12. Analysis. — In -,"1. there are 9 fractional 1 1 OPERATION. 9 ^3 _ 8 units, each of whic'.i is -jlj, and these are to ^^ -7- 3 be divided by 3. But 9 things, divided by 3, gives 3 things of the same kind lor a quotient : hence, the quotient is 3 elevenths, a number Avhich is one-third of ^^ ; hence, we have Proposition III. — If the nuuxrator of a fraction be divided Inj any number, the fraction will be diminished as many times as there are units in that number. 11. "j. Wiiat is proved in projiosition 11 ! 116. What in piovcd in proposition III ! COMMON FKACTIONS. 115 EXAMPLES. 1. DivideJf by2,4,8, 16. 2. Divide jf by 2, 7 and 14. 3. Divide ^ by 2, 5, 4 and 10. 4. Divide fl by 5, G, 10, 15 and 20. 5. Divide l| by 2, 3, 6, and G. Divide If by 3, 6, 8, and 12. 7. Divide f | by 3, 9 and 27 8. Divide fA by G, 9, 27 and 54. 117. Let it be required to divide -^ by 3. Analysis. — In -^, there are 9 fractional operation. units, each of which is ^V- Now, if we J--:_3 = -? — = A. ; 11 ' 11- 11X833 multiply the denominator by 3, it becomes 33. and the fraciioual unit becomes -^j which is one-third part of ^. If, then, we take this fraciioiial unit 9 times, the result -^ is just one-tliird part of ^j : hence, we have divided the fraction y\ by 3 : therefore, we have, Proposition IV. — Jf the denominator of a fraction he mul- tiplied hy any niimhrr, the fraction will be diminished as many times as there are units in that number. EXAMPLES. 1. Divide f by G, 7 and 8. 2. Divide | by 5, 4 and 9. 3. Divide If by 3, 4 and 12. 4. Divideff byG, 8andll. 5. Divide |f by 7, 5 and 3. G. Divide \\ by 7, 8 and 6. 7. Dividers by 3, 7 and 11. 8. Divide -fi by 8, 4 and 10. 118. Let it be required to multiply both terms of the frac- tion 1^ by 4. Analysis. — In f . the fractional unit is -^, and it is taken 3 times. By multiplying the denomi- nator by 4. the fractional unit becomes -^. the value of which is is one-fourth of \. By multiplying the numerator by 4. we increase the number of fraclional units taken. 4 times ; that operation. 3X4 12^ 5X4 ~ '2 117. If the denominator of a fraction be multiplied by any number, how will the value of the fraction be effected ? 118. If both terms of a fraction be multiplied by any number, how will the value of the fraction be effected ^ 116 PRINCIPLES OF is, we increase the number of parts taken just as many times as we decrease the value of the fractional unit ; hence the value of the trac- tion is not changed : therefore, we have Pkoe^sition V. — //■ both terms of a fraction he multl^^lied by the same number, the value of the fraction will not be changed. EXAMPLES. 1. Multiply both terms of the fraction |- by 4, by 6, and by 5. 2. Multiply both terms of -fj by 5, by 8, by 9, and 11. 3. Multiply both terms of if by 7, by 8, and 9. 4. Multiply both terms i^- by 5, 8, 6, and 12. 5. Multiply both terms of |-| by 2, 3, 4, and 5. 119. Let it be required to divide the numerator and denomi. nator of -^ by 3. Analysis. — In ^^, the fractional unit is ■^, operation. and it is taken 6 times. By dividing the dcnonii- 6 h-3^2 nator by 3. the fractional unit becomes \, the 15^3 5 value of which is 3 times as great as ■^^. By ; dividing the numerator by 3, we diminish the number of fractional luiits taken 3 times ; that is. we diniinish the number of parts taken just as many ti77ies as we increase the value of the fractional tinit : hence, the value of the fraction is not changed ; therefore, we have Proposition VI. — If both terms of a fraction be divided by the same number, the value of the fraction will not be changed. EXAMPLES. 1. Divide both terms of |- by 2 and by 4. 2. Divide botli terms of \ by 3. 8. Divide both terras of || by 2, 3, 4, 6, and 12. 4. Divide both terms of A| by 2, 4, 8, and 16. 5. Divide both terms of ^ by 2, 3, 4, G, and 12. G. Divide both terms of -f-^ by 2, 3, 4, G, and 36. 119. If botli trrins of a fraction be divided by any number, how will the ■ iuo of the fraction be ctlectcd \ KEDUOTION OF FJi ACTIONS. 117 REDUCTION OF FRACTIONS. 120. Reduction of Fkactions is the operation of cliang- in-T the fractional unit without alterinjjr the value of the fraction. A fraction is in its loioest terms, when the numerator and denominator have no common factor. CASE I. 121. To reduce a fraction to its lowest terms. 1. Reduce y'/'g- to its lowest terms. Analysis. — By inspection, it is seen that 5 is 1st. operation. a common factor of the numerator and denomi- ^)i-^ — W' nator. Dividing by it, we have ^. We then see that 7 is a common factor of 14 and 35 : divid- 7)|^ — ^. iug by it, we have -|. Now, there is no factor common to 2 and 5 : therefore, f is in its lowest terms. 2d. The greatest common divisor of 70 and 175 is 35. (Art. 93) ; if we divide both terms of the fraction by it, we ob- ^ tain, -S-. The value of Ihe fraction is not chang- 2d operation. ed in either operation, since the numerator and ^5)^-ts ~ !• denominator are both divided by the same num- ber (Art. 119): hence, the following ]^ULE. — Divide the numerator and denominator hy their com' mon factors, until they become prime toith respect to each other. Or : 2d. Divide the numerator and denominator hy their greatest common divisor. exa:\iples. Reduce the following fractions to their lowest terms : 6. Reduce y|-i. 7. Reduce jVy"^- 1. Reduce -^-^. 2. Reduce j^o- 3. Reduce ^^. 4. Reduce i^4.|. 5. Reduce \y^. 8 Reduce ff-hy 2d. method. 9. Reduce f^f " " 10. Reduce V^^ " 120. What is reduction of fractions 1 When is a fraction in its lowest terms 1 121. How do you reduce a fraction to its lowest terms 1 118 REDUCTION OF FRACTIONS. 1 1. Reduce y^g^^ by 2(i. metL 12. Reduce yVaV 13. Reduce ||{}. li. Reduce j^.%. 15. Reduce f|A|. IG. Reduce yYA- 17. Reduce f ^. 18. Reduce jViV 19. Reduce iQff§. 20. Reduce g'^Z/aV 21. Reduce sffo^- 22. Reduce J^V'sV CASE II. 122, To reduce an improper fractio)i to an equivalent whole or mixed number. 1. In ^l^ how many entire units ? Analysis. — Since there are 5 fifths in 1 unit, operation. there will be in 278 fifths as many units 1 as 5)278 5 is contained times in 278, viz.. 55 and -f times. 55|-. Hence, the following Rule. — Divide the numerator hy the denominator, and the qm tient will be the equivalent whole or mixed number. EXAMPLES. Reduce the following fractions to whole, or mixed numbers 1. Reduce \^^. 9. Reduce ^VrV^ acres 2. Reduce ^-^. 10. Reduce \\\\ 3. Reduce \^*. 11. Reduce Y-,Y6^- 4. Reduce ^^T- 12. Reduce ^|^?|". 5. Reduce Y/ pounds. 13. Reduce ''ff ". 6.' Reduce 2||8 ^ays. 14. Reduce Vgr . 7. Reduce ^|f * yards. 15. Reduce ='VW- 8. Reduce "gV/. 16. Reduce ^'H^''*. CASE in. 123. To reduce a mixed manber to an equivalent imprope fraction. 1. Reduce 12|- to its equivalent improper fraction. 122. What is an improper fraction 1 How do you reduce an irapropev fraction to its equivalent whole, or mixed number ! 123 What iii a mixed number! How do you reduce a mixed numbei to an improper fraction 1 How do you reduce a whole number to a frac- tion having a given denominator! REDUCTION OF FE ACTIONS. 119 Analysis. — Since in any number there are 7 times as many 7tlis as operation. units 1, there will be 84 sevenths in 12 x 7 = 84 sevenths. 12: To these add 5 sevenths, and add 5 sevenths, the equivalent fraetion becomes 89 gives 12|=89 sevenths, sevenths, hence, the following Aiis. = %p. Rule. — Midiipli/ the ivhole number by the denominator : to the 2)roducl add the numerator, and place tlie sum over the given denominator. EXAIUPLES. 1. Reduce 39|- to its equivalent improper fraction. 2. Reduce 112j?q to its equivalent improper fraction. 3. Reduce 427ii to its equivalent improper fraction. 4. Reduce G7G|y to an improper fraction. 5. Reduce 367^^^ to an improper fraction. 6. Reduce 847 y^-^ to an improper fraction. 7. Reduce G7426 |^yf to an improper fraction. 8. How many 200ths in 6751^ J ? 9. How many 151 ths in 187yVr? 10. Reduce 149g- to an improper fraction. 11. Reduce 375^^ to an improper fraction. 12. Reduce 17494^|-|f3- to an improper fraction. 13. Reduce 4834|^|- to an improper fraction. 14. Reduce 1789|- to an improper fraction. 15. In 125|- yards, how many sevenths of a yard ? IG. In 375|- feet, how many fourths of a foot ? 17. In 4641^ hogsheads, how many sixty-thirds of a hogs- head ? 18. In 96Jj'j5- aci'es, how many 640ths of an acre ? 19. In 984y'y'2- pounds, how many 112ths of a pound ? 20. In 353?^ years, how many 366ths of a year? 21. How many one hundred and thirty-fifths are there in the mixed number 87j'*Jy ? 22. Place 4 sevens in such a manner that they shall express the number 78. 23 By means of 5 threes write a number that is equal to 334. 120 REDUCTION OF FKACTI0N8. CASE IV. 123.* To reduce a wliole number to a fraction having a given denominator : 1. Reduce 17 to a fraction of whicli tlie denominator shall be 5. Analysis. — There are 17 times as many operation. fifths in 17 as there are in 1. In 1, there 17 X 5 = 85 are 5 fifths ; therefore, in 17 there are 17 17 = ^ times 5 fifths or 85 fifths ; hence, Rule. — Multiply the whole number by the denominator, and write the product over the required denominator. EXA3IPLES. 1. Change 18 to a fraction whose denominator shall be 7. 2. Change 25 to a fraction whose denominator shall be 12. 3. Change 19 to a fraction whose denominator shall be 8. 4. Change 29 to a fraction whose denominator shall be 14. 5. Change 65 to a fraction whose denominator shall be 37. 6. Reduce 145 to a fraction haviner 9 for its denominator. 7. Reduce 450 to a fraction having 12 for its denominator. 8. Reduce 327 to a fraction having 36 for its denominator. 9. Reduce 97 to a fraction having 128 for its denominator. 10. Reduce 167 to a fraction whose denominator shall be 89. 11. Reduce 325 to a fraction whose denominator shall be 75. CASE V. 124. To reduce a compound fraction to a simple fraction. 1. What is the equivalent fraction of f of |-? Analysis. — Three-fifths of \ is three times \oi i^: 1 fifth of -^ is -gij (Art. 117) : and 3 opkration. times ^\ is H (Art. 1 14) ; hence, | of ^ - ^ ^ ^ = ^ hence, the following 123.* How Jo you reduce a vvliole number to a fraction having a given denominator ! 124. \\'hat is a compound fraction 1 How do you reduce a compound fraction to a simple fraction 1 KEDCrCTION OF FKACTIONS. 121 Rule. — Multiply the numerators together for a new nurnera^ tor, and the denominators tog e titer fur a new denominator. Note. — 1. If there are mixed numbers, reduce them to their equivalent improper fractions. 2. Cancel every factor common to the numerator and denominatpr before multiplying. EXAMPLES. 1. Reduce |- of -| of |- to a simple fraction. 2. Reduce -| of | of |- to a simple fraction. 3. Reduce |- of f of 2^ to a simple fraction. 4. Change -| of f of f of 3^- to a simple fraction. 5. Change -f^ of f of |- of -f-^ to a simple fraction. 6. What is the value of i of i of | of 12i ? 7. What is the value of f of | of 4| ? 8. What is the value of ,% of 7^ of o-V ? 9. Reduce -^ of 9|- of 6f of 2| to a whole or mixed number- 10. Reduce j\ of -^^ of 21|^ to a whole or mixed number. 11. Reduce |- of f of f of y^^^ ^^ T3 ^^ ^ simple fraction. 12. Reduce yY^ of j^g- of j^^- of f to a simple fraction. 13. Reduce 3f off of ^^^-j of 49 to a simple fraction. CASE VI. 125. To reduce fractions of different denominators to equiva- lent fractions that shall have a common denominator. 1. Reduce -|, |- and |- to a common denominator. Analysis. — Multiplying both terms of the first fraction by 20, the product operation. of the olher denominators, gives |5.. 2X5x4 = 40 1st num. Multiplying both terms of the second 4 x 3 x 4 = 48 2d num. fraction by 12, the product of the other 3 X .5 X 3 = 45 3d num. denominators, gives |§. Multiplying 3 x 5 X 4 = 60 denom. both terms of the third by 15. the pro- duct of the other denominators, gives ||-. In each case both terms 125. How do you reduce fractions of different denominators to equiva- lent fractions having a common denominator 1 Note 1. — What reductions are first made T 2. When the numbers are small, how may the work be done'' 3. How may the work often be shortened"! 122 REDUCTION OF FRACTIONS. of the fraction have been multiplied by the same number ; there- fore, the value is not changed (Art. 118) : hence, the following ]^ULE. — Multiply the numerator of each fraction by all the denominators except its own, for the new numerators, and all the denominators together for a common denominator. Nq-j-j. — 1 Before multiplying, reduce to simple fractions when necessary. 2. When the numbers are small, the work may be performed mentally ; thus, 1, 1 I become, |^, if, ^ ; and f , 1, f become, if, |f, ff . EXAMPLES. Eeduce the following fractions to common denominators : 1. Reduce f , 51 and f . 2. Reduce f , f , \ and i of 5. 3. Reduce 9i ' 4i, 2| and f 4. Reduce f , l, f , ^ and 2i. 5. Reduce 21 of 3, f , f and f . 6. Reduce 2i of 31 of f , and G3 of |. 7. Reduce | of f of -| and f of f of |. 8. Reduce 4§, 21 5iand 6. 9. Reduce 51 f, 3i and 3f . 10. Reduce f"'of 5i i of 3i and J 2 of 8^. 11. Reduce 61 of 2, f , ^ and i. IS^OTE. — 3. We may often shorten tlie work by multiplying the numerator and denominator of each fraction by such a number as will make the denominators the same in all. Reduce the following fractions to common denominators by this method : 1. Reduce ^, -j^, |- and f to a common denominator. 2. Reduce f, ^y and f to a common denominator. 3. Reduce 41, -f^ and 71 to a common denominator. 4. Reduce 10|, f and 71 to a common denominator. 5. Reduce Gl. # and 71 to a common diMiominator. G. Reduce ■^-, ^, 141 and 3|- 1o a common denominator. 7. Reduce -^, |, 2f and If to a common denominator. 8. Reduce f, i, ^% and ^ to a common denominator. 9. Reduce W* f ' ^t ''^"'^ I *° ^ common denominator. ''^ Reduce 24,, 51, -^^^r 'i"^^ "^tV *" -"^ common denominator. EEDUCTION OF FRACTIONS. 123 CASE VII. 125*. To reduce fractions io their hast common denominator. The least common denominator of two or more fractions is the number which contains only the prime foctors of their denominators. Hence, before beginning the operation, reduce every fraction to a simple fraction and to its lowest terms. 1. Reduce |-, |- and | to their least common denominator. OPERATION. (36^4) X 3 = 27 1st numerator. 2)4 . 6 . 9 (36 -=-6) X 5 = 30 2d numerator. 3)2 . 3 . 9 (36 -^ 9) X 4 = 16 3d numerator. 2.1.3 2X3X2X3 = 36, least common denominator : therefore, the fractions, reduced to their least common de- nominator, are 3 6' 3 6' '*"^ 3 6' Hence, the following Rule. — I. Find the least common multiple of the denomina-' tors (Art. 98) : this ivill be the least common denominator of the fractions. H. Divide the least common denominator hy the denominator of each fraction, sejwratehj ; multiply the quotient hy the nume- rator and place the product over the least common denominator : the results will be the new and equivalent fractions. EXAMPLES. 1. Reduce I, ^ and -^-^ to their least common denominator. 2. Reduce fj, |- and iy to their least common denominator. -3. Reduce 2|, yV and -^-^ to their least common denominator. 4. Reduce 5|, 4:-f^ and -^^ to their least common denominator. 5. Reduce 8y^, f and 3^ to their least common denominator. 6. Reduce 9^, -^^^ and r^^ to their least common denominator. 125*. What is the least common denominator of two or more fractions 1 How do you find the least common denominator of two or more fractions J 124 ADDITION OF FRACTIONS. 7. Reduce 2-|, 3-j^y and y^^ to their least common denominator. 8. Reduce o^, |-, f and j-^ to their least common denominator. 9. Reduce |, -jy and -jg to their least common denominator. 10. Reduce Aj-, 7-^^ and ~ to their least common denominator. 11. Reduce 3^, 6j^ and 1 Jg- to their least common denominator. 12. Reduce 6|, Sy^- and 2-^ to their least common denominator. 13. Reduce Oyy, G^^ and 3-3 to their least common denominator. 14. Reduce j^y, 2^ and 1^''^- to their least common denominator. 15. Reduce 5|^, Gj-^, -^ and -^ to their least common de- nominator. ADDITION OF COMMON FRACTIONS. 126. The Sum of two or more fractions is a number which contains the unit 1 as many times as it is contained in the frac- tions taken together. Addition op Fractions is the operation of finding the sum of two or more fractions. There are two cases : Is/. When the fractions have the same unit. 2d. When they have different units. CASE I. 127. When the fractions have the same rmit. 1. What is the sum of i, f , | and ^ ? Analysis. — In this example, the unit operation. of the fraction is 1, and the fractional 1 + 3 + 6+3 = 13 unit ^. There is 1 half in the first. 3 hence, ^^ = 6-J sum. halves in the second. 6 in the third, and 3 in the fourth : hcnce^there are 13 halves in all, equal to 6 J. 2. "What is the sum of 1£ and g£ ? Analysis. — The unit of both fractions is operation. l£. In the first, the fractional unit is ^£, ^.£ = f £ and in the second, ^£. These fractional |-jG = ^£ units, being dilTerent, cannot be expressed. |£ + ^£ = £^ = £\^. 126. What is the sum of two or more frartions ? What is idditijn of fractions 1 How many rases are there ? M'hat arc they 1 127. How do you add fractions which have the same unit ? COMMON FRACTIONS. 125 in one collection. But ^£ = f jC and fjC = ^£, in each of which the fractional unii is -JjG : hence, their sum is |-jC = £1-^. Note. — Only ur.its of the same value, ickether fractional or integral^ can be expressed in the same collection. From the above analysis, we have the following Rule. — I. When the /radians have the same denominator, add their niunerators^ and -place the sum over the common de- nominator : II. When they have not the same denominator, reduce them to a common denominator, and then add as before. JVoTE. — 1. After the addition is performed, reduce every result to its simplest form ; that is, improper fractions to mixed numbers, and the fractional parts to their lowest terms. 2. It often abridges the operations in fractions to reduce them to f^ieir least common denominators, before adding (Art. 125*.) 1. Add f , f, f and f 2. Add f £, f £, f £ and ii-£. 3. Add $ i-L , %fj, $if and $/y 4- Add 1^- i^ i^ and -^- 5. Add f , f , f, -If and Jf . 6. Add ^2, ^2, 3?2 ' T2 '^"t^ f 1 7. Add i f and ^^. 8. Add f , I, I and ,\. EXAMPLES. 9. Add f , f , f and ^\. 10. Add I, j^, ^ and fl. 1 1 Add 7 7 13 J 1 „„,] 1 9 19 Arid 3 5 9 5 „,-,/i ] 5 J. 4. j^\.aa -J, -g-, jg, g^ ana g^. 13. Add j\, f, f and |. 14. Add 1 41 and |. 15. Add y\, j5-^, -2^ and |. 16. Add j% fV I and l.* Note. — Reduce each fraction to its least common denominator be- fore adding. 17. What is the sum of } and } ? Analysis. — Reducing to a common denominator, we find the fractions to be ^ and /^, and their sum to be H- That is, 128. The sum of two fractions whose numerators are each 1, is equal to the sum of their denominators divided by their product. OPERATION. 128. What is the sura of two fractions equal to when each numerator is equal to 1 1 i2G ADDITION uF 18. What is the sum of i and i? of i and i? of 1 and i? of 1 and yV ? 19. What is the sum of yV and ^\ ? of yV and jL? of i and 1? of i. audi? 20. What is the sum of 12|, llf and lof ? OPERATION. IVi^o/e Numbers. Fractions. 12 + 11 + 15 = 38 14-1^-1-4— -63_ 4- _7_Q_ 1 _7 5 208_iJL03 . then, 38 + 11^3 = 391 o|. ^,,5 Note. — When there arc mixed numbers, add the whole numbers and the fractions separately, and then add their sums. Find the sums of the following fractions : 27. Add f , j% of j\ of 8 and 21. 28. Add 4f, ,»j- of ^ of 151. 29.Add3f, 4f andl6yV SO.AddSf, 4| and ^ of 16. 31. Add 6|, 13f, 181 and 1321. 32. Add 124, 201!-, and 40 I 8' 21. Add If, 31 and 1 of 7. 22.Add3ff,7f,iland2ii. 23. Add 2f , 41 and f of 5^\. 24. Add 12f , 9f, f of 61 25. Add j\ of 61 and f of 71. 26. Add 1 of 9f and | of 4f. 33. Bought a cord of wood for 2|- dollars ; a barrel of flour for $9^^ ; and some pork for $5^ : what was the entire cost ? 34. A person travelled in one day 351 miles; the next, 28^ miles ; and the next, 25^^^ miles : how many miles did he ti-avel in the three days ? 35. A grocer bought 4 firkin.s of butter, weighing re.'pectively 54|, 55f, 51 j'^^ and 50|4 pounds : what w.as their entire weight ? 36. I paid for groceries at one time j^ of a dollar; at ano- ther, 31 dollars ; at another, 7f dollars ; and at another, 5^ dollars : what was the whole amount paid ? 37. A merchant had three pieces of Irish linen ; the first piece contained 22^- yards ; the second 201 yards ; and tlie third 21^- yards : how many yards in the three pieces ? 38. A man sold 5 loads of hay ; the first weighed 18j^C'r^. ; the second 19^1c(6'A ; tlie third 19-^f;w/.; the fourth 21 J-ltvt'/. ; and the fifth 2{^\^cw(. : what was the weight of the whole ? CX)MMON FKACTIONS. 127 39. A farmer has three fields ; the first contains 17f acres ; the second 25^j acres; and the third 46 j^^ acres: how many- acres in the three fields ? 40. A man sold 112f bushels of wheat for 2504 dollars ; O/g bushels of corn for 62| dollars; 225^^ bushels of oats for 104^ dollars : how many bushels of grain did he sell, and how much did he receive for the whole ? CASE II. 129. When the fractions have different units. 1. What is the sum of ^Ib. and ^oz. ? Analysis. — In ^!b. there are operations. ^z. (Art. 41). Then, the units ^Ib. = f x IGoz. = ^^oz. of the fractions being the same, ^^ oz. + -^oz. = -^^oz. -\- ^oz. viz., \oz.. we reduce to a com- = -^-^oz. = IZ^oz mon denominator and add, and obtain IS^oz. Second Method. — Three- ^oz.=\x^Jh.=-^^lh. fourths of an ounce is equal to f''j- + ^V^-=l~2f^^-+F57'^-=lli' ^Ib. (Art. 41). Then, by add- ing, we iind the sum to be ^^Jb.= \2^'^oz.= \Zoz. %\dr . Third Method.— Find the {lb.=^xi&oz.=^oz. = Vloz.\2\dr. value of each fractional part ^oz. = \x\Gdr. — ^dr.=z 12 in terms of integers of the Sum - - - - 13 8^ lower denominations, and then add. Rule. — Reduce the given fractions to the same unit, and then add as in Case 1. Or: Reduce the fractions sejjaratehj to integers of lower de- nominations, and then add the denominate numbers. EXAMPLES. 1 . Add f of a yard to -| of an inch. 2. Add together ^ of a week, \ of a day, and i of an hour. 3. Add ^cwt., ^Ib., 13os'., ^cwt. and 6/i. together. 4. Add -g^ of a pound troy to i of an ounce. 129. How do you add fractions when they have different units 1 128 ADDITION OF FRACTIONS. 5. Add ^ of a ton to -j^^ of a hundred weight. 6. Add ^ of a chaldron to ^ of a busheL . 7. What is the sum of f of a tun, and f of a hogshead of wine ? 8. Add 1- of f of a common year, f of | of a day, and I of I of I- of 191 hours, together. 9. Add I" of an acre, f of 19 square feet, and |- of a square inch, together. 1 0. What is the sum of i of a yard, i of a foot, and \ of an inch ? 11. What is the sum of f of a £, and f of a shilling ? 12. What is the sum of i of a week, i of a day, i of an hour, and f of a minute ? 13. Add together |- of a mile, f of a yard, and ' of a foot. 14. What is the sum of f of a leap year, ^ of a week, and i of a day ? 15. Add -i of a ton to |- of a hundred weiofht. 16. Add ^Ib. troy, J02. and ^pivt. 17. Add together -^^ of a circle, 3|- signs, |^ of a degree, and ^ of 5i minutes. 18. What is the sum of ^ijcL, | of ^q?: and S^na. ? 19. Add j^g of a cord, f cubic feet, and |- of 1 of 24|- cubic feet. 20. What is the sum of f of i of 4 cords, ^^ of -^^ of 15 cord feet, and ^ of 31^ cubic feet ? 21. Add I of 3 ell English to j^^ o^ a yard.' 22. Add together A of 3.-J. IE. 20P., | of an acre, and | of 3E. 15P 23. What is the sum of ^^ of a ton, -^ of a cwt., and -^ of an ounce ? 24. Wliat is the sum of •?,- of ^ of a mile, ? of a furlon"-, -'*- of a rod and -^ of a foot ? 25. AVliaL is ilie sum of -^'^ of a common year, ^^ of a week, 3 of a day, and f of an hour ? 8UETRACT10N OF FKACTI0N3. 129 SUBTRACTION. 130. The diiference between two fractions is such a number as added to the less will give the greater. SuBTRA-CTiON of Common Fractions is the operation of finding the ditl'erence between two fractional numbers. Thei'e are two cases : 1. When the fractions have the same unit: 2d. When the fractio7is have different units. CASE I. 131. When the fractions have the same unit.. 1. What is the difference between ^ and \ ? 4 4 Analysis. — The unit of both fractions is the operation. same, being the abstract unit 1. The fractional f — ^ = f . luiit is also the same, being ^ in each ; hence, the diiference of tlie fractions is equal to the difference of the frac- 2. 4' tional units, which is 2. "What is the difference between ^Ib. and f of a pound ? Analysis. — The unit in both fractions is operation. lib. The fractional unit of the first is \1h. |— |=i|_l-^=^y6. and of the second ^Ib. Reducing to the Bame fractional unit, we have ^fZ6. and ^^/6., the difference of which is -fjlb. ; hence, Rule I. — If the fractional unit is the same in both, subtract the less numerator from the greater, and place the difference over the common denominator. II. When the fractional units are different., reduce to a common denominator : then subtract the less numerator from the greater, and place the difference over the common denominator. 130. What is the difference between two fractions 1 What is Subtrac- tion of Common Fractions 1 How many cases are there ! What are they ? 131. How do 3'ou make the subtraction when the fractions have the same unit 1 130 SUBTRACTION OF Note. — Reduce each fraction to a simple form and to its lowest terms before reducing to a common denominator. EXAMPLES. 1. From 1^ take 1. 2. From f f take {J-. 3. From if take if. 4. From ^^i take i^f 3 0a 305 5. From | take |-. 6. P>om ji take J-f 7. From || take ||. 8. From 37|i take \ of 5^. 9. From | take ^. 10. From | take j\. 11. From 25 take \}. 12. From ^"^ of 3 take 1 of |. 13. From i of f of 7 take ^. 14. From 3f take f of ^. 15. From f of 15 take | of 3. 16. From 7^ of 2 take -} of -|. 17. To ^vliat fraction must I add f that the sum may be -I ? 18. AVhat number added to 1 1 will make 5 ? 19. What number is that to which if 1^ be added the sum will be 17|-? 20. From the sum of 3f and 10| take the difference of 25i and 17^. 21. What number is that from which if you subtract i of j of a unit, and to the remainder add -| of -g- of a unit, the sum will be 9 ? 22. If I buy f of 1^ of a vessel, and sell ^ of ^ of my share, how much of the whole vessel have I left ? 23. A man bought a horse for i of 4 of j^ ^^ $500, and sold him again for | of I- of ^ of $1680 : what did he gain by the bargain ? 24. Bought wheat at 1|- dollars a bushel, and sold it ibr 2^ dollars a bushel : what did I gain on a bushel ? 25. From a barrel of cider containing 31^ gallons, 12f gal- lons were drawn : how much Avas there left ? 26. Bought 10| cords of wood at one time, and 24|- cords at another; after using IGJy cords, how much remained? 27. A merchant bought two firkins of butter, one containing ^^To pounds, and the other 56}^- pounds ; he sold 43|| poundd at one time, and 34^ pounds at another : how much had he left? COMMON FKACTIONS. ]31 28. A man having $501 expended $15^^^ for dry goods, and $12|- for groceries : liow much had he left ? 29. A boy having ^ of a dollar, gave -i of a dollar for an inkstand, and } of it for a slate : how much had he left ? 30. Bought two pieces of cloth, one containing 27f yards, the other 321- yards, from which I sold 4lO\^ yards : how much had I left ? 132. 1. ^yhat is the difference between i and i ? Analysis. — Reducing both fractions to operation. a coinmou denominator and subtracting, i — 1 = -^ — -j^^ = -^, we find the difference to be -^ ; that is, The difference behveen two fractions, each of ivhose numerators is 1, is -equal to the difference of the denominators divided by their product. 2. From i take ^. 3. From jL take -jL.. 4. From -jL take ^. 5. From Jy take Jg. 133. 1. What is the difterence between IQ>\ and 3i ? Analysis. — Since we cannot take -^-^ from ■j^. wc borrow 1 -.= \^ from the wliole nuin- operation. her of the minuend, wliich added to j^^-, gives 16^^= 16A- W : then -j^ from ^| leaves if. We must 3|- = 3y\ now carry 1 to the next figure of the subtra- 12W hend, and say 4 from 16 leaves 12. Hence, to subtract one mixed number from another, Subtract the fractional part from the fractional part, and the integral 'part from the integral part. 1. What is the diifei-ence between 144 and 12y^jy? 2 What is the difference between 115| and 391- ? 3. What is the difference between 78-i^ and A^ ? i h 3 2 4. What is the difference between 48y^j^ and 41l|- ? 5. What is the difference between 287^V and 104 -M^. 132. What is the difference between two fractions whose numerators are each 1 \ 133. How do you subtract one mixed number from another? 132 BUBTKACTION OF CASE II. 134. When the fractions have different iniits. 1. What is tlie difference between i of a £ and ^ of a shil- ling ? OPERATION. Analysis. — Reducing to the com- ■|£ = | x 205. = ^s. mon unit \s.^ we find the difference "^-^s. — ^s. = ^^s— ^s. = ^s. to be ^s. = 9s. 8d. = On. 8d. Second Method. — Reducing to the ^■^- — 3 ^ it^ ~ ^eV- common unit IjG, we find the differ- 2^~ eV-^ ~ %q^ ~ i^^- ence to be |f £ = 95. 8^. = |f £ = 95. 8d. Third Method. — Reduce the frac- ^£ = IO5. tions to integral units, and then sub- ^5. = Ad. tract as in denominate numbers. 95. 8c?. Rule. — Reduce the fractions to the same unit, and then sub- tract as in Case 1. Or : Find the value of each fraction in units of loiuer da- nominatiom, arid then suht7-act as in denominate numbers. EXAMPLES. 1. From f of a pound troy take ^ of an ounce. 2. From | of a ton take |- of | of a pound. 3. Fi'om |- of y of a hogshead of wine take ^ of | of a quart. 4. From >- of a lea2;ne take f of a mile. 5. What is the difference between Ifs. and f of l\d. ? G. What is the difference between ^1 of a degree and ~ of \ of a degree ? 7. From f|- of a squai-c mile take 3GJ acres. 8. From ^ of a ton take | of 12cwt. 9. From l^lb. troy take \ of an ounce. 10. From 2g- cords take f of a cord foot. 11. From -^ of a yard take | of an inch. 131. How do vou subtract w\ien the fractions have different units 1 COMMON FE ACTIONS. 133 12. From i of f of a pound take | of ^ of a dram, apothe- caries' weiglit. 13. A pound avoirdupois is equal to 14:0Z. Il2nvt. IGf/r. troy, what is the difference, in troy weight, between the ounce avoir- dupois and the ounce troy ? MULTIPLICATION OF FRACTIONS. 135. Multiplication of Fractions is the operation of taking one number as many times as there are units in another, when one or both are fractional. 1. If 1 pound of tea cost | of a dollar, what will f of a pound cost ? Analtsis. — The cost »,"ill be equal to operation. the price of unity taken as many times as $| X y = ^^^ := $3^' there are luiits in the quantity (Art. 75). One-seventh of a pound of tea will cost one-scvcnth as much as 1/6. Since lib. cost S|. \ of 1/6. will cost | of Sf^SgV (Art. 117). But 3 sevenths of 1/6. will cost 3 times as much as \\ that is, Sj^g X 3 = $|f (Art. 114). Hence, to multiply one fraction by another, Rule. — Multiply the numerators together for a new numera- tor^ and the denominators tor/ether for a new denominator. Notes. — 1. When the multiplier is less than 1, we do not take the whole of the multiplicand, but only such a part of it as the multi- plier is of 1. 2. When the multiplier is a proper fraction, multiplication does not imply increase., as in the multiplication of whole numbers. The product is the same part of the multiplicand which the multiplier is of 1. 135. What is multiplication of fractions ] How do you multiply ono fraction by another ? When the multiplier is less than 1, what part of the multiplicand is taken 1 If the fraction is proper, does multiplication imply increase ? What part is the product of the multiplicand 1 What do you do when either factor is a whole number 1 134: MULTIPLICATION OF 3. If either of the factors is a whole number. ^ATite 1 under it for a denominator. 4. ^Yhen either of the factors is a mixed number, it maybe reduced to an improper traction, or we may multiply the parts separately and take their sum. 1. Multiply I by 8. 2. Multiply fg by 12. 3. Multiply ll by 9. 4. Multiply 1^ by 15. 5. Multiply ^^1 by 12. 6. Multiply I of i- by 35. 7. Multiply 3i off by 14. 8. Multiply If of 2^ by 16. 9. ]\ruhii)ly 2i of f by 70. 10. Multiply 4| of 8 by 36. 11. Multiply 36 by 4i. Analysis. — The number 3(5 is to be taken 4 J times; that is, 4 times and i times. One- ninth of 36 is 4, which is wTitten in the units place : then. 4 times 36 is 144; and the sum 148 is the product. OPERATION. 36 4 144 148 Ans. 12. Multiply 67 by 9^^. 13. Multiply 842 by 71-. 14. Multiply 360 by 12f. 15. Multiply 460 by llf. 16. Multiply 620 by lOf. 17. Multiply 1340 by 8f. 1. Multiply ^ by 8. 2. Multiply 15 by f 3. Multiply 11 hyj%. 4. Multiply 7| by 8. 5. Multiply 9^ by 18f. 6. INIultiply 32- by 411. 7. Multiply Vr- by 9. 8. Multiply f by I-. 9. Multiply 1 by f . 10. Multiplyloff by ^. 11. Multiply -iV by /o of A- EXAJrrLES. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. Multiply i of 1 by A of T^. INIultiply I- by 16. iNIultiply 28 by -j^. :\rultiply ll- by 18. IMultiply 8^0 by 15. Multiply IMultiply Multi])ly 8421 by 7^. ISrultiply Multiply Multiply r. TT of 2- by ^J. 51 by A of 31. f\ bv ^-. 9 '•V 7 TTJ by 7^ TT* ^? by -J of ^g. COMMON FRACTIONS. ' 135 23. Multii)ly -j\, |f and || together. 24. Multiply if, ^^, -^j and f{i together. 25. What is the product of |^ by | of 17 ? 2G. What is the product of 6 by f of 5 ? 27. AVhat is the product of i of i of 3 by loj ? 28. Require the product of f of |- by f of 3|. 29. Require the product of 5, ^, | of |, and 41-. 30. Require the product of 14, f , ^ of 9, and 6f . 31. What A\ill 7 yards of cloth cost at $f a yard ? 32. Wliat will 12|- bushels of apples cost at $| a bushel ? 33. If one bushel of wheat cost $1^, what will f of a bushel cost ? 34. If one horse eat f of a ton of hay in one month, how much will 18 horses eat in the same time ? 35. If a man earn $i| in one day, how much can he earn in 24 days ? 36. What will 31 yards of cloth cost at |- of a dollar a yard ? 37. At $16 a ton, what will |i of a ton of hay cost ? 38. If one pound of tea cost $1\, what will 61 pounds cost? 39. What will 3| boxes of raisins cost at $2^ a box ? 40. At 75 cents a bushel, what will ii of a bushel of corn cost ? 41. If a lot of land be worth $75y^3-, what will ^x of it be worth ? 42. If a man earn $56 in one month, how much can he earn in y-j of a month ? 43. What will 171 yards of cambric cost at 21 shillings a yard ? 44. Bought 15|- barrels of sugar at $20| a barrel, what did the whole cost ? 45. If one bushel of corn is worth f of a dollar, what is f of a bushel worth ? 46. If I own -^j of a farm and sell -^^ of my share, what pai-t of the whole farm do I sell ? 47. Bought a book for -j^ of a dollar and a knife for j^ as much; how mucli did I pay for the knife ? 136 MDLTIPLICATION 48. At f of |4 of a dollar a pound, what will f of ||- of a pound of tea cost ? 40. If ha J is Avorth $9|- a ton wliat is ^ of Si ton worth. 50. If a man can dig a cellar in 22^ days, how many days will it take him to dig ^ of it ? 51. If a railroad train run 1 mile in -^L. of an hour, how long will it be in running 106j miles ? 52. What will be the cost of 20|- cords of wood at $3J a cord ? 53. If a man walk 3^ miles an hour, how far will he walk in Of hours ? 54. "What will 14| bushels of potatoes cost at 311 cents a bushel ? 55. What will 12J dozens of eggs bring at 18|- cents a dozen ? 56. At "I of a dollar a bushel, what will 1021 bushels of ry8 cost? 57. What will |- of a firkin of butter cost at $18Jg- a firkin ? 58. A man, at his death, left his wife $15000; she at her death left |- of her share to her daughter : what part of the father's estate did the daughter receive ? 59. A person owning ^ of a cotton factory sold f of his paii; to A, and the rest to B : what jiart of the whole did each buy? GO. A owTied I- of a farm and sold 4 of his share to B, who sold f of what he bought to C, who sold £ of what he bought to D : what part of the whole did D have ? 61. A owned | of 200 acres of land, and sold ^ of his sliare to B, who sold i of what he bought to C : how many acres had each? DIVISION OF FRACTIONS. 137 DIVISION. 136. Division of Fractioxs is tlie operation of finding a number wliicli multiplied by the divisor will produce the dividend, when one or both are fractional. 1. What is the quotient of |- divided by -J^*- ? Analysis. — How many lanes is ^^ con- operation. tallied in |-? If ^ be divided by 14, the l-^XA^l-^J^ quotient will be gx. . (Art. 117). Since ~ iVa' ~ 1^6 -^^'* the true divLsor is but ^ of 14, the divisor used is 5 times too large ; hence, the par- tial quotient r^^^ is 5 times too small. Multiplying this by 5, we have the true quotient, ,3_5^ = ■^\. 2 ^ ! The operation may be made by means X4 of the vertical line, by .simply placing the dividends on the right and the divisors on 16 | — -^^ A. the left. Since the same process is applicable to any two fractions, we have the following rule : I. Invert the terms of the divisor : II. Multiply the numerators together for the numerator of the quotient, and the denominators together for the denominator of the quotient. Notes. — 1. If either the dividend or divisor is a whole number. make it fractional, by writing 1 under it for a denominator. 2. If the vertical line is used, the denominator of the dividend and the numerator of the divisor fall on the left, and the other terms on the right. . 3. Cancel all common factors. 136. What is division of fractions ^ AMiat is the rule for the division effractions'! What do you do when cither the dividend or divisor is a whole number 1 Where do the parts fall when you use the vertical line '^ What do you do when either term of the fraction is a mixed number or a compound fraction 1 If the terms of the dividend are exactly divisible l)y the corresponding terms of the divisor, how do you find the quotient ? 7 L38 DIVISION OF 4. If the dividend and divisor have a common denominator, it will cancel, and the quotient of the numerators will he the answer. 5. When either term of the fraction is a mixed number, or a com- pound fraction, reduce to the form of a simple fraction before dividing. 6. If the numerator of the dividend is exactly divisible by the numerator of the divisor, and the denominator by the denominator, the division may be made without inverting the terras of the divisor. EXAMPLES. 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. lo. 16. 17. 18. 10. 20. 21. 22. 23. 24. 25. Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide H by 7. t\ by 6. If by 9. m by 40. M by 13. 5by tV- 27 by I ^byf fVby ^by off by f off. 5 TT* I off by. * of ^ I Of f by f off. 56 by 11. 1000 by T^. 725 by f f 4f by 5. 9^5^ by 12. of 16iby 41. by 1 of 7. ' ^ of 50" by 41. 300^'V by 61. 1 of"3ii by l>f 71 91 by 81. 1 h » OI yy by 6^. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. oo OO. 39. 40. 41. 42. 43. 44. 45. 46. 47. 48. 49. 50. Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide Divide by 4. _9 ro- il il by 5. ffby8. m by 48. tS's by 21. 36 by 420 by f 3 ¥• 7 15" byM- I- by if. foffbyfoff. lofioffbylofl 650 by J-^f . 1273 by li. 4324 by 2'o by 25 2 of 2 7. 3 "^ 5 by ] 28 475' 6f by 8. 121 by 42 r7 by 91. 100 by 43 44^ by lll-Vby by by I of U. by I of 191J- 5205} '8' 2 13 3'3 3* 33i. 1591. 90 COMMON FRACTIONS. 139 51. At J- of a dollar a pound, how much butter can be bought for I k of a dollar ? 52. At f of a dollar a yard, how muck cloth can be bought for |- of a dollar ? 5-), If a bushel of potatoes cost ^ of a doljar, how many can be bought for -^^ of a dollar ? 54. If ^ of a ton of hay will feed 1 horse one week, how many hoi^^es will -f^j of a ton feed, the same time ? 55. If ^^ of a bushel of apples cost | of a dollar, what will a bushel cost ? 5G. What will a barrel of flour cost, if j^^ of a barrel cost I of a dollar ? 4 57. If |- of a bushel of apples cost -| of a dollar, what will 1 bushel cost ? 58. How much molasses at f of a dollar a gallon, can be bought for ly dollars ? 59. A man sold |-|- of a mill, which was ^ of his share : what part of the mill did he own ? 60. Yf hat number multiplied by f, will give lof for the pro- duct ? 61. What number multiplied by 51, will give 146 for the pro- duct? 62. The dividend is 520^, and the quotient 36y% : what is the divisor? 63. What number is that which if multiplied bv I- of ^ of 151, will produce -I? 64. If lib. of sugar cost ^j of a dollar, what will 1 pound cost? 65. If lQ\Ih. of nails cost y of a dollar, what is the price per pound ? 66. If y of a yard of cloth cost $3, what is the cost of a yard ? 67. A fiuiiily consumes 165| pounds of butter in 8^ weeks: how much do they consume in 1 week ? 68. At $9-1 a barrel, how much flour can be bought for $138f ? 140 REDUCTION OF 69. If a man divides $3| equally among 8 beggars, how much will he give them apiece ? 70. If 8 pounds of tea cost 7f dollars, what is the price per pound ? 71. If I of a ton of hay sell for $10f, what should 1 ton sell for ? 72. If ^ of an acre of ground produce 84y^ bushels of pota- toes, how many bushels will 1 acre produce? 73. What quantity of cloth may be purchased for $5Jg-, at the rate of $6f a yard ? 74. How long would a person be in travelling 125^ miles, if he travelled oljj miles per day ? 75. How many bottles, each holding 1^ gallons, can be filled from a barrel of wine, containing 311 gallons ? 7G. How long will it take 11 men to do a piece of work that I man can do in 15| days ? 77. If |- of a barrel of flour cost G dollars, what is the price per barrel ? 78. Eighty-one is f of how many times 8 ? 79. Five-eighths of 48 is f of how many times 9 ? 80. How many times can a vessel, containing 3- of a gallon, be filled from i of a barrel of 311 gallons ? 81. If 5}Jb. of tea cost $41-, what is the price of 1 pound ? 82. If f of -^ of a ship is worth $2540, what is the whole vessel worth? 83. If |- of an acre of land cost S361, Avhat will be the value of an acre ? 84. If I of -J of a bai'rel of flour will last a family 1 week, how lonn; will 9fV barrels last them? COMPLKX FRACTIONS. 141 REDUCTION OF COMPLEX FRACTIONS. 137. A Complex Fraction is only another form of expres- Eion for the division of fractious: thus, -3, is the same as | "6 divided by f ; and may be written, i^^=is 5 o3 X "$ 7 138. To reduce a complex fraction to a simple fraction : 1. Reduce —y- to a simple fraction. Analysis. — Reducing the divisor operation. and dividend each to a simple frac- G|- = ^j) and 1| = f-. tion, we have %» and f . Then 2_o 20 _:. 8 ^ 2j) x 1 = 83 - 54 divided byf is equal to 5/ xX^Jj^a ^ "^ '' ' ^ ^' _3_5 _ t5 — 6 — "^a- Rule. — Divide the numerator g | 35 of the compilcx fraction hy its de- Ans. ^^- = 5|. nomi/iator. Or: Midtiply the numerator of the upper fraction into the de- nominator of the lower, for a new numerator ; arid the denominator of the upper fraction into the numerator of the lower, for a new denominator. ]v;oTES. — 1. When either of the terms of a complex fraction is a mixed number, or a compound fraction, it must first be reduced to the form of a simple fraction. 2. ^Yhen the vertical line is used, the numerator of the upper and Ihe denominator of the lower numbers fall on the right of the vertical line, and the other terms on the left. 137. What is a complex fraction 1 138. How do you reduce a complex fraction to a simi)le fraction ^ 142 APPLICATIONS m EXAMPLES. Reduce the following to simple fractions 1. Reduce f- 4 5 2. Reduce ^' T6 3. Reduce -^• 87i 4. Reduce -y^- 8 5. Reduce -^• 84 6. Reduce r^- 7. Reduce ~-^^' 8. Reduce 20 7 ^ of 7 3- 9. Reduce ^~J~^^- 26.8 10. Reduce '3 5 11. Reduce I of 17 554 H 12. Reduce f off^ of -| APPLICATIONS IX FRACTIONS. 1. What -will 51 cords of wood cost at L of | of | of $50 a cord ? 2. A farmer sold f of a ton of hay for $6| : what would be the price of a ton at the same rate ? 3. A person walks 77 1 miles in 10^ hours : at what rate is that per hour ? 4. From the product of ^ and llJ,take y^, and multiply the remainder by 20'. 5. How mucli greater is ^ of the sum of ^, ^, i and J , than the sum of -^, i and ^ ? 6. If •} of a ton of hay is worth $7i, what is 2| tons worth? 7. If - of a dollar will pay for |- of a yard of cloth, how piany yards can be bouglit for $ll-i?- ? 8. AVhat is the value of 3J- cords of wood at S-l| a cord ? 4 3- A 9. "What is the continued product of 144, -— , v, ^^^ ^? <■ '' oi' f 9 49''- 34?- 10. "Wiiat is the sum and (lidi'rencc of --3 and vr,rV ? 9/ 14"TT COMPLEX FRACTIONS. 143 11. At } of a dollar a peck, how many busliels of apples can be bought for $Gf ? 12. What is the difference between f of a league and -^ of a mile ? 13. Subtract 8|Z6. from |- of a cwf. 14. What is the sura of A^^ miles, ^ of a furlong, and f of 11 yards ? 15. At $lf per day, how many days labor can be obtained for$36f? 16. Sold 7i bushels of apples for $3| : what should I receive for 24f bushels ? 17. A has G34 sheep, which are 124 more than f of 21 times B's number : how many sheep had B ? 18. At 3^ of a dollar a yard, how many yards of ribbon can be bought for ^ of a dollar ? 19. Paid $56 1 for 94 yards of muslin : how much was that per yard ? 20. Bought 51 yards of cloth at $41 a yard, and paid for it in wheat at $11 a bushel : how many bushels were required ? 21. What number must be taken from 27|, and the remainder multiplied by 14f , that the product shall be 100 ? 22. Three persons. A, B, and C, purchase a piece of pro- perty for $6300; A pays f of it, B, land C the remainder: what is the value of each one's share ? 23. What number is that which being diminished by the dif- ference between f and | of itself leaves a remainder equal to 34 ? 24. Add together 1 of a week, 1 of a day, and 1 of an hour. 25. What is the sum of f of £15, £3f, i of f of | of £1, and f of f of a shilling ? 26. If 1 of John's marbles are equal to i of James', and to- gether they have 56 : how many has each ? 27. A person owning f of 2000 acres of land, sold f of his share : how many acres did he retain ? 28. A boy having 240 marbles, divided them in the following manner : he gave to^A, l, to B, j\, to C, 1, and to D, i, keeping the remainder himself : what number of marbles had each ? 144 DUODECIMALS. , 29. A man engaging in trade with $3740, found at the end of 3 years that he had gained $156^ more than ^ of his capital : what was his average annual gain ? 30. Two boys having bought a sled, one paying |- of a dollar, and the other |- of a dollar, sold it for y^g- of a dollar more than they gave for it : what did they sell it for, tind what was each one's share of the gain ? 31. A farmer having 126y bushels of wheat, sold -I of it for $21 a bushel, and the remainder for $1|- a bushel : how much did he receive for his wheat ? 32. A man having $19-1-, expended it for wheat and corn, of each an equal quantity ; for the wheat he paid $14 a bushel, and for the corn $|- a bushel : how much of each did he buy ? 33. Two persons engage in trade : A furnished -^^^ of the capital, and B, -^ ; if B had furnished $49 2|- more, their shares would have been equal : how much did each furnish ? 34. A man being asked how many sheep he had, said he had them in 3 fields : in the first he had G3, which was ^ of. what he had in the second, and that f of what he had in the second was just 4 times what he had in the third : how many sheep had he in all ? DUODECIMALS. 139. Duodecimals are a system of numbers which arise from dividing the unit 1 according to the uniform scale of 12 ; tlms, If the unit 1 foot be divided into 12 equal parts, each part is called an inch or prime, and marked \ If an inch be divi- ded into 12 equal parts, each part is called a second, and marked ". If a second be divided, in like manner, into 12 equal parts, each part is called a third, and marked '" ; and so on for divisions still smaller. 139. What arc duodecimals 1 If the unit 1 foot be divided into 12 equal parts, what is each part called? If 1 inch be divided into 12 equal parts, what is each part called ] If the second be divided in like manner, what is each part called 1 What are indices 1 DUODECIMALS. 145 This division of the foot gives 1' inch or prime — ^- of a foot. 1" second is Jj of jL - - - - = J-^ of a foot. V" third is tV of yV of t'2 - - = W^ of a foot. Note.— The marks ', ", '", &c., which denote the fractional units, are called indices. TABLE. 12'" make 1" second. 12" a r inch or prime. 12' (( 1 foot. Hence : Duodecimals are denominate fractions, in which the primary unit is 1 foot, and the scale uniform, the units of it, at every point, being 12. Note. — Duodecimals are chiefly used in measuring surfaces and solids. ADDITION AND SUBTRACTION. 140. The units of duodecimals are reduced, added, subtracted, and muhiplied like those of other denominate numbers. The units of the scale are 12, at every change of the unit. EXAMPLES. 1. In 86' how many feet? 2. In 750" how many feet? 3. In 37000'" how many ft. ? 4. In G7' how many feet? 5. In 470'" how many feet? 6. In 375" how manv feet ? 7. What is the sum of 8/?. 9' 7" and G/>. 7' 3" 4'"? 8. What is the difference between 32/?. 6' G" and 20ft. 7'"? 9. Add together 9/^. G' 4" 3"', 12//. 2' 9" 10"', 26ft. 0' 5", and 40/2. 1' 0" 3'". 10. Wliat is the sum of 126ft. 0' G", 45/?. 11' 0" 2'" and 12ft. G' ? 140. By what rules do you operate on duodecimal units I What are tha unils of the scale ! 1 4:0 DUODECIMALS. 11. What is the sum of 84//. 7', 96//. 0' 11", 42//. 6' 9'' 10"' and 5' 7" 11'"? 12. From 127//. 3' 6" 4'" 11"" take 40//. 0' 10" 7"' 5"". 13. What is the difference between 425/7. 9' 10" and 107//. 10' 9" 8'"? 14. What is the sum and difference of 325//. 7' 6" 2'" and 217/. 10' 9"? 15. What is the sum and difference of 1001//. 0' 0" 10'" and 720//. 10' 9" 1'" ? MULTIPLICATION. 141. Multiplication of duodecimals is the operation of finding the superficial contents, or the contents of volume, when the linear dimensions are known. To do this we begin with the highest unit of the multiplier and the loiuest of the multiplicand, and recollect, 1st. That 1 linear foot x 1 linear foot = 1 square foot, (Art. 411), or, that a part of a foot x a part of a foot = some part of a square foot. 2d. That a square foot X by a foot in length =: a cubic foot. Note. — Ob.serve that in the first muUiplication the unit is changed, from a linear to n superficial unit; in the second muUiplication, from a supevficial unit to a unit of volume. 1. Multiply 6//. 7' 8" by 2//. 9'. Analysis. — Since a prime is ^ of a foot, and a second y^, 2X8"= ^^ of a square foot ; which reduced to 12ths, is r and A"; that is, 1 twelfth, and 4 twelfths of twelfths of a square foot. 2 X 7' = 14 twelfths = 1ft. 2' - - - 2 X 6 = 12 square feet 2X6=12 9' X 8"= ylfg- of a square foot ---- 6" - 9'x 8"= 6" 9'x T = ^^ = 5' 3" 9'X 7' = 5' 3" 9 X G' =14 = 4 6' 9'X 6 = 4 6' Prod. 18 3' 1" OPERATION, ft- 6 7' 8" X 8" = o 9' 2 1' 4" 2 X 7' = 1 2' HI. Wliat is multiplication of duodecimals 1 DUODECIMALS. 147 Rule. — I. Write the midtijylier under the mtdtij^licand, so that units of the same order shall fall in the same column. II. Begin with the highest unit of the multiplier and the lowest of the multiplicand, and make the index of each product equal to the sum of the indices of the factors. III. Reduce each product of the first midtijylication to square feet and 12ths of a square foot, and when there ore three factors reduce the second products to units of volume, NoTK. — The index of the unit of any product is equal to the sum of the indices of the factors. EXAMPLES. 1. How many cubic feet in a stick of timber 12 feet 6 inches long, 1 foot 5 inches broad, and 2 feet 4 inches thick ? Analysis. — Beginning with the 1 foot, operation. we say 1 time 4' is 4' = ^^ of a square ft. foot : then, 1 time 2 is 2 square feet. 2 4' Next, 5 times 4' are 20" = 1' and 8" : 1 5^ then, 5 times 2 feet = 10', and the V to carry, makes 11' 8". Then multiplying by the length 12 feet 6', we find the contents to be 41 3' 10" cubic feet. 2 4' 11 8" 3 3' 8" 12 6' 39 8' 1 7' 10" 41 3' 10" 2. Multiply 9/7. 6' by 4/if. 7'. 3. Multiply 12/^. 5' by Qft. 8'. 4. MuUiply 35/^. 4' 6" by 9/?. 10'. 5. What is the product of 45//. 4' 3" by 12^ 2' 9" ? 6. What is the product of 140//. 0' 2" 4'" by 20//. 10' ? 7. What is the product of 279//. 10' 6" by 8' 4" ? 8. What are the contents of a board 14//. 6' 3" long and 2//. 9' wide ? 9. How many square feet in a floor 18//. 9' long, and 15/f. 10' wide ? 10. How many square yards in a ceiling 70//. 9' long, and 12//. 3' wide ? 148 DnasioN OF 11. What will be the cost of paving a yard 64/);. 6^ square, at 5 cents a square foot ? 12. What are the cubic contents of a block of marble, 6/?. 9' long, 4/'/. 8' wide, and 2//!. 10' thick ? 13. There is a room 97/7. 4' around it; it is 9//. G' high: what will it cost to paint the walls, at 18 cents a square yard ? 14. How many cubic feet of wood in a pile 36/^. 5' long, 6//. 8' high, and 3//. 6' wide ? 15. What will a pile of wood 26/if. 8' long, 6//'. 6' high, and Sft. 3' wide, cost, at $3,50 a cord ? 16. How many cubic yards of earth were dug from a cellar which measured 38/V. 10' long, 20ft. 6' wide, and 9/V. 4' deep? 17. At 16 cents a yard, what will it cost to plaster a room 22/;. 8' long, 18/^ 9' wide, and lift. 6' high? There are to be deducted 8 windows, Gft. 4' high and 2/7. 9' wide ; 2 doors, 1ft. 6' high and ^ft. 2' wide, and the base moulding, which is 1 foot wide. DIVISION OF DUODECIMALS. 142. Division of Duodecimals is the operation of finding from two duodecimal numbers a third, which multiplied by the first, will give the second. 1. A hall contains lOSsq.ft. 4' 5" 8'" 4^ and is Gft. IV S" wide : what is its length ? AnATA'SIS. The OPF.RATION. units of the dividend ft. s(]. ft. ft. are square feet and 6 11' 8") 103 4' 5" 8'" 4-(14 9' 11" fractions of a square foot. The units of the divisor arc linear feet and fractions of a linear foot. First, consider how often the first two parts of the divisor are contained in the first part of the dividend. The first two parts of the divisor arc nearly equa^ 97 7' 4" 5 9' 1" 8'" 5 2' 9" 0'" 6' 4" 8"' i' fi' 4" 8'" 4 142. What is Division of Duodecimals 1 How is it performed ] DIVISION OF DUODECIMALS. 149 to 7 feet, and this is contained in I02sg. ft. 14 times and something over. Multiplying the divisor by this term of the quotient and sub- tracting, we find the remainder 5ft. 9' 1", to which bring down 8"'. Next, consider how many times the first two parts of tlie divisor, (equal to 7 feet, nearly.) are contained in the first two parts of the remainder, reduced to the next lower unit ; that is, 5ft. 9' = 69'. Multiplying the divisor by the quotient figure 9', and making the subtraction, we have, 6' 4" 8", to which bring down 4'"'. Consider, again, how often, nearly 7 feet is contained in 6' 4"=76" Multiplying the divi-sor by the quotient 11", we find a product equal to the last remainder. Hence, the process of division is the same as that of other denominate numbers^ except in the manner of selecting the quotient figure. Notes. — 1. If the integral unit of the dividend and divisor is the same, the unit of the quotient unll he abstract. 2. If the unit of the dividend is a superficial unit, and the unit of the divisor a linear unit, the unit of the quotient will be linear. 3. If the unit of the dividend is a unit of volume, and the unit of the divisor linear, the unit of the quotient loill be superficial. 4. If the unit of the dividend is a unit of volume, and the unit of the divisor superficial, the unit of the quotient will be linear. EXAMPLES. 1. Divide 2^sq.fL 0' 4" by Qft. 4'. 2. Divide bOsq.ft. 0^ 10" 6'" by 9/;. 6'. 3. What is the length of a floor whose area is 1176sg'./i;. 1' 6", and breadth 24/;. 3'? 4. A load of wood, containing ll^cv.fL 2' 6" 8'", is Zft. 4' high, and 4ft. 2' wide : what is its length ? 5. In a granite pillar there are IQocu.ft.^ 1" 6'"; it is ?>ft. 9' wide, and 1ft. 3' thick : what is its length ? 6. There are 394sg./i!. 2'9"in the floor of a hall that is \^ft. 7' wide : what is its length ? 7. A board Ylft. 6' long, contains Tl sq.ft. 8' 6" : what is its width ? 8. From a cellar 42/V. 10' long, 12/. C wide, were thrown 158c2«. yds. lieu, ft 4' of earth : how deep was it? 150 DECIMAL FKACTIOrJS. DECIMAL FRACTIONS. 143. There are two kinds of Fractions : Common Fractions and Decimal Fractions. A Common Fraction is one in which the unit is divided into any number of equal parts. A Decimal Fraction is one in which the unit is divided according to the scale of tens, 144. If the unit 1 be divided into 10 equal parts, each part is called one-tenth. If the unit 1 be divided into one hundred equal parts, each part is called one-lmndrcdth. If the unit 1 be divided into one thousand equal parts, the parts are called thousandths, and we have like expressions for the parts, when the unit is further divided according to the scale of tens. These fractions may be written thus : Three-tenths, ------ ^. Seventh-tenths, ----- ^^. Sixty-five hundredths, - - - - _f^. 215 thousandths, - - . - - 1275 ten thousandths, - - - - 2 1 5 1000' 12-5 loooo- From which we see, that in each case the denominator indi- cates the fractional unit ; that is, determines whether the parts are tenths, hundredths, thousandths, &c. 143. How many kinds of fractions are tli-ere ? What are thoyi What is a common fractionl What is a flrcimal fraction 1 144. When the unit 1 is divided into 10 equal parts, what is each part called 1 What is each pari called when it is divided into 100 equal parts ? When into 1000 1 Into 10,000, cVc. 1 How are decimal fractions formed? What gives denomination to the fraction 1 DECIMAL FKACTIONS. 151 145. The denominators of decimal fractions are s(!ldom set down. The fractions are usually exj^ressed by means of a pei'iod, placed at the left of the numerator. Thus, y^ - • is written - - .3 Too - - - - .UO __2JL5_ .215 1000 \ .i--!^" 10000 .x-i^/ Tliis method of writing decimal fractions is a form of lan- guage, employed to avoid writing the denominatoi's. The denomi- nator, however, of every decimal fraction is always understood : It is the unit 1 with as many ciphers annexed as there are places of figures in the decimal. The place next to the decimal point, is called the place of tenths, and its unit is 1 tenth. The next place, at the right, is the place of hundredths, and its unit is 1 hundredth ; the next is the place of thousandths, and its unit is 1 thousandth ; and similarly for places still to the right. DECIMAL NUMERATION TABLE. w .^3 2 • tn S O "S '" ^ '^ ^ t^ _rf T^ ™ '^ • S •£ rg tn -^ ui o m i, g ^ iH C a c = o c - = c hKhhKSh .4 is read 4 tenths. .5 4 - - 54 hundredths. .0 6 4 - - 64 thousandths. .6754 - - 6754 ten thousandths. .01234 - - 1234 hundred thousandths. .007654 - - 7654 millionths. .0043604 - - 43604 ten millionths. Note. — Decimal fractions are numerated from left to right ; thus, tenths, hundredths, thousandths, &c. 152 DECIMAL FRACTIONS. 146. Write and numerate the following decimals : Six-tenths, - - - - .6 Six hundredths, - - - .0 G Six thousandths, - - - .0 6 Six ten thousandths, - - - .0006 Six hundred thousandths, - - .00006 Six miUionths, - - - - .000006 Six ten millionths, - - - .0000006 Here we see that the same figure denotes different decimal units, according to the place which it occupies ; therefore, The value of the unit, in the different places, in passing from the left to the right, diminishes according to the scale of tens. Hence, ten of the units in any place, are equal to one unit in the place next to the left ; that is, ten thousandths make one hundredth, ten hundredths make one-tenth, and ten-tenths make the unit 1. This scale of increase, from the right hand towards the left, is the same as that in whole numbers ; therefore, Whole numbers and decimal fractions may be united by placing the decimal point between them ; thus. Whole numbers. Decimals. to ■5 CO 5 w TS en 3 O w C .2 o ■B 3 aj C to .a a o o •5 "13 0) •5 ■.-> t/3 a o • •n c --a -a c 3 ^ ,J^ 't^ o CA o D O H (a 1^ wi a O j2 c *a .2 C c V3 H c c 3 3 O H "3 C 3 o a 3 u H 4 2 3 1 4 5 1 .2 4 3 7 8. 145. Arc the denominators of decimal fractions generally set down 1 How are Ihc fractions expressed \ Is the denominator understood ! M'hat is it ? What is the place ne.Yl the decimal point called ! What is its unit! What is the next place called ? What is its unitT What is the third place called ! What is its unit 1 Which way are decimals numerated ^ DECIMAL FRACTIONS. 153 A number composed pai-tly of a whole number, and partly of a decimal, is called a mixed number. RULE FOR WRITING DECIMALS. Write the decimal as if it were a ichole number, prefixing as many ciphers as are necessary to make it of the required denomi- nation. RULE FOR READING DECIMALS. Read the decimal as though it were a whole number^ adding the denomination indicated by the lowest decimal unit. EXAMPLES. Write the following numbers decimally : (1.) (2.) (3.) (4.) (5.) 6 11 5 _2_7_ i±_ Too 10 1000 100 Tooo* (6.) (7.) (8.) (9.) (10.) "loo 'Tooo *^ioo ■^'^loo -^''lO' "Write the following numbers in figures, and numerate them : 1. Twenty-seven, and four-tenths. 2. Thirty-six, and fifteen thousandths. 3. Ninety-nine, and twenty-seven ten thousandths. 4. Three hundred and twenty thousandths. 5. Two hundred, and three hundred and twenty millionths. 6. Three thousand six hundred ten thousandths. 7. Five, and three millionths. 8. Forty, and nine ten millionths. 146. On what does the unit of a figure depend 1 How does the value change from the left towards the right 1 What do ten units of any ono place make 1 How do the units of the places increase from the right to- wards the left ^ How may whole numbers be joined with decimals ! What is such a number called \ Give the rule for writing decimal fractions. Give the rule for reading decimal fractions. 154 DECIMAL FRACTIONS. 9. Forty-nine hundred ten thousandths. 10. Fifty-nine and sixty-seven ten thousandths. 11. Four hundred and sixty-nine ten thousandths. 12. Seventy-nine, and four hundred and fifteen millionths. 13. Sixty-seven, and two hundred and twenty-seven ten thousandths. 14. One hundred and five, and ninety-five ten millionths. UNITED STATES MONEY. 147. The denominations of United States Money correspond to the decimal division, if we regard 1 dollar as the unit. For, the dimes are tenths of the dollar, the cents are hun- dredths of the dollar, and the mills, being tenths of the cent, are thousandths of the dollar. EXAMPLES. 1. Express $37 and 26 cents and 5 mills, decimally. 2. Express $17 and 5 mills, decimally. 3. Express $215 and 8 cents, decimally. 4. Express $275 5 mills, decimally. 5. Express $9 8 mills, decimally. 6. Express $15 6 cents 9 mills, decimally. 7. Express $27 18 cents 2 mills, decimally. ANNEXING AND PREFIXING CIPHERS. 148. Annexing a cipher 15 placing it on the right of a number. If a cipher is annexed to a decimal it makes one 7nore decimal place, and, therefore, a cipher must also be added to the denomi- nator (Art. 145). The numerator and denominator will therefore have been multiplied by the same number, and consequently the value of the fraction will not be changed (Art. 118) : hence, 147. If the denominations of Federal Money he expressed decimally, ■what is the unit 1 What part of a dollar is 1 dime ? What part of a dime is a centl What part of a cent ia a milH What part of a dollar is I cent 1 1 mill 1 DECIMAL FRA.CTIOi!fS. 155 Annexing ciphers to a decimal fraction does not alter its value. We may take as an example, .5 = -f^. If we annex a cipher to the numerator, we must, at the same time, annex one to the denominator, which gives, .5 =: Y^ = .50 by annexing one cipher. .5 = tVoV — '^0*^ ^y annexing two ciphers, .5 = yo%%'V = .5000 by annexing three ciphers. Also, .■* _ y^j _ .t\J _ j-^Q _ .'iW — ^000* Also, .7 = .70 = .700 = .7000 = .70000. 149. Prefixing a cipher is placing it on the left of a number. If cij)hers are prefixed to the numerator of a decimal frac- tion, the same number of ciphers must be annexed to the de- nominator. Now, the numerator will remain unchanged while the denominator will be increased ten times for every cipher annexed ; and hence, the value of the fraction will be dimin- ished ten times for every cipher prefixed to the numerator (Art. 117). Prefixing ciphers to a decimal fraction diminishes its value ten times for every cipher prefixed. Take, for example, the fraction .3 = ^^. .3 becomes -^^ = .03 by prefixing one cipher. .3 becomes jWo = .003 by prefixing two ciphers. .3 becomes yHqq — .0003 by prefixing three ciphers: in which the fraction is diminished ten times for every cipher prefixed. 148. When is a cipher annexed to a number? Does the annexiinr of ciphers to a decimal alter its value 1 Why not ? What does five-tenths become by annexing a cipher 1 What by annexing two ciphers ! Three ciphers \ AVhat does 7 tenths become by annexing a cipher ? By annex- ing two ciphers 1 By annexing three ciphers 1 149. When is a cipher prefixed to a number 1 Whe» prefixed lo a decimal, does it increase the numerator \ Does it increase the denominator '\ What effect, then, has it on the value ef the fraction ? 156 ADDITION OF ADDITION OF DECIMALS. 150. Addition of Decimals is the operation of finding the sum of twe or more decimal numbers. It must be remembered, that only units of the same value can be added together. Therefore, in setting down decimal numbers for addition, figures expressmg the same unit must be placed in the same column. The addition of decimals is then made in the same manner as that of whole numbers. I. Find the sum of 87.06, 327.3 and .0567. OPERATION. Place the decimal points in the same column : 87.06 this brings units of the same value in the same 327.3 column : then add as in whole numbers j hence, .0567 414.4167 Rule. — I. Set doion the numbers to be added so that figures of the same unit value shall stand in the same column. II. Add as in simple numbers, and 2'>oint off in the sum, from the right hand, a number of places for decimals equal to the greatest number of places in any of the numbers added. Proof. — The same as in simple numbers. EXAMPLES. 1. Add 6.035, 763.196, 445.3741, and 91.5754 together. 2. Add 465.103113, .78012, 1.34976, .3549, and 61.11. 3. Add 57.406 + 97.004 + 4 + .6 + .06 + .3. 4. Add .0009 + 1.0436 + .4 + .05 + .047. ITjO. What is Atldition 1 ^Vhat parts of unity may be added together 1 How do you set down the numbers for addition ! How will the decimal points fain How do you then add! How many decimal places do j-ou point off in the sum 1 DECIMAL FEACTIONS. 157 5. Add .0049 + 49.0426 + 37.0410 + 360.0039. 6. Add 5.714, 3.456, .543, 17.4957 together. 7. Add 3.754, 47.5, .00857, 37.5 together. 8. Add 54.34, .375, 14.795, 1.5 together. 9. Add 71.25, 1.749, 1759.5, 3.1 together. 10. Add 375.94, 5.732, 14.375, 1.5 together. 11. Add .005, .0057, 31.008, .00594 together. 12. Required the sum of 9 tens, 19 hundredths, 18 thou- sandths, 211 hundred-thousandths, and 19 millionths. 13. Find the sum of two, and twenty-five thousandths, five, and twenty-seven ten-thousandths, forty-seven, and one hundred twenty six-millionths, one hundred fifty, and seventeen ten-mil- lionths. 14. Find the sum of three hundred twenty-seven thousandths, fifty-six ten-thousandths, four hundred, eighty-four milHonths, and one thousand five hundred sixty hundred-millionths. 15. What is the sum of 5 hundredths, 27 thousandths, 476 hundred-thousandths, 190 ten-thousandths, and 1279 ten-mil- lionths ? 16. "What is the sum of 25 dollars 12 cents 6 mills, 9 dollars 8 cents, 12 dollars 7 dimes 4 cents, 18 dollars 5 dimes 8 mills, and 20 dollars 9 mills ? 17. What is the sum of 126 dollars 9 dimes, 420 dollars 75 cents 6 mills, 317 dollars 6 cents 1 mill, and 200 dollars 4 dimes 7 cents 3 mills ? 18. A man bought 4 loads of hay, the first contained 1 ton 25 thousandths ; the second, 997 thousandths of a ton ; the third, 88 hundredths of a ton ; and the fourth, 9876 ten-thousandths of a ton : what was the entire weight of the four loads ? 19. Paid for a span of horses, $225,50 ; for a carriage? S127,055, and for harness and robes, $75,28 : what was the entire cost ? 20. Bou'o-ht a barrel of flour for $9,375 ; a cord of wood for $2,121 ; a barrel of apples for $1,621 ; and a quarter of beef for $6,09 : what was the amount of my bill ? 21. A farmer sold grain, as follows : wheat, for $296.75 ; 158 SDBTK ACTION OF corn, for $12G,12i; oats, for $97,371; rye, for $100,10 ; and barley, for §oO,G2i : what was the amount of his sale ? 22. A person made the following bill at a store ; 5 yards of cloth, for $16,408 ; 2 hats, for $4,87^ ; 4 pairs of shoes, for $6; 20 yards of calico, for $2, 378 ; and 12 skeins of silk, for $0,62^ : what was the amount of his bill ? SUBTRACTION OF DECIMALS. 151. Subtraction of Dechials is the operation of finding the difference between two decimal numbers. I. From 6.304 to take .0563. Note. — In this example a cipher is annexed to operation. the minuend to make the number of decimal places 6.3040 equal to the number in the subtrahend. This docs -05(33 not alter the value of the mmuend (Art. 148) : 6.2477 hence, KuLE. — 1. Write the less number under the greater, so that figures of the same unit value shall fall in the same column. II. Subtract as in simple numbers, and point off the decimal places in the remainder, as in addition. Proof. — Same as in simi^le numbers. EXAMPLES. 1. From 3278 take .0879. 2. From 291.10001 take 41.496. 3. From 10.00001 take .111111. 4. Required the difference between 57.49 and 5.768. 5. What is the difference between .3054 and 3.075 ? 6. Required the difference between 1745.3 and 173.45. 7. AVhat is the diflerence between seven-tenths and 54 ten- thousandths ? 151. Wliat is subtraction of decimal fractions ! How do you set down the numbers for subtraction 1 How do you then subtract ' How many Jcciinal placcfl do you point off \n the remainder 1 DECIMAL FRACTIONS. 159 8. What is the difference between .105 and 1.00075 ? 9. What is the difference between 150.43 and 754.355 ? 10. From 1754.754 take 375.49478. 11. Take 75.304 from 175.01. 12. Required the difference between 17.541 and 35.49. 13. Ecquired the difference between 7 tenths and 7 mil- lionths. 14. From 396 take 67 and 8 ten-thousandths. 15. From 1 take one-thousandth. 16. From 6374 take fifty-nine and one-tenth. 17. From 365.0075 take 5 millionths. 18. From 21.004 take 98 ten-thousandths. 19. From 260.3609 take 47 ten-millionths. 20. From 10.0302 take 19 millionths. 21. From 2.03 take 6 ten-thousandths. 22. From one thousand, take one-thousandth. 23. From twenty-five hundred, take twenty five hundredths. 24. From two hundred, and twenty seven thousandths, take ninety-seven, and one hundred twenty ten-thousandths. 25. A man owning a vessel, sold five thousand seven hundred sixty-eight ten thousandths of her : how much had he left ? 26. A farmer bought at one time 127.25 acres of land, at another, 84.125 acres, at another, 116.7 acres. He wishes to make his farm amount to 500 acres : how much more must he purchase ? 27. Bought a quantity of lumber for $617.37^, and sold it for $700 : how much did I gain by the sale ? 28. Having bought some cattle for §325.50 ; some sheep for $97.12^; and some hogs for $60.87i ; I sell the whole for $510.10 : what was my entire gain ? 29. A dealer in coal bought 225.025 tons of coal ; he sold to A, 1.05 tons, to B, 20.007 tons, to G, 40.1255 tons, and to D, 37.00056 tons : how much had he left ? 30. A man owes $2346.865, and has due him, from Ay $1240.06, and from B, $1867.981 : how much will he have left after paying his debts ? 160 MULTIPLICATION OF 31. Bought of eacli of two persons, 1284.0-'5 pounds of wool, from which I sell to three persons, each 262.125 pounds : how much will I still have on hand ? MULTIPLICATION OF DECIMAL FRACTIONS. 152. Multiplication of decimal fractions is the operation of taking one number as many times as there are units in ano- ther, when one of the factors contains a decimal, or when they both contain decimals. 1. Multiply 8.03 by G.102. OPERATION. Analysis. — If we change both factors to common fractions, the product of the mimerators will be the same as that of the decimal numbers, and the number of decimal places loill he equal to the number of ciphers in the two denominators ; hence, Rule. — Multiply as in simjyle man- 48.99906 hers, andiwint off in the product, from the right hand, as many firjures for decimals as there are decimal places in both factors ; and if there be not so many in the pro- duct, supply the deficiency by prefixing ci2}hc7-s. examples. 1. Muhiply 2.125 by 375 thousandths. 2. Muhiply .4712 by 5 and G tenths. 3. INIuhiply .0125 by 4 thousandths. 4. Muhiply G.002 by 25 hundredths. 5. Muhiply 473.54 by 57 thousandths. G. IMultiply 137.549 by 75 and 437 ^hou-sandths. 7. ]\Iultiply 3 and .7495 by 73487. 152. After multiplying, how many decimal places will you point oil' :n the product 1 When tlicrc are not so many in tlie product, whjit do you do 1 Give the rule for the multiplication of decimals. 803 100 = 8.03 6102 1000 = 6.102 1606 803 4818 DECIMAL FRACTIONS. 161 8. Multiply ,04375 by 4713 i liundi-ed thousandths. 9. Multiply .371343 by seventy-five thousand 493. 10. Multiply 49.0754 by 3 and 5714 ten thousandths. 11. Multiply .573005 by 754 millionths. 12. Multiply .375494 by 574 and 375 hundredths. 13. Multiply two hundred and ninety-four millionths, by ono millionth. 14. Multiply three hundred, and twenty-seven hundredths by G2. 15. Multiply 93.01401 by 10.03962. IG. Multiply 59G.04 by 0.000012. 17. Multiply 38049.079 by 0.000016. 18. Multiply 1192.08 by 0.000024. 19. Muhiply 7G098.158 by 0.000032. 20. Multiply thirty-six thousand, by thirty-six thousandths. 21. Multiply 125 thousand, by 25 ten thousandths. 22. What is the product of 50 thousand, by 75 ten millionths ? 23. What is the product of 48 hundredths, by 75 ten thou- sandths ? 24. What are the contents of a lot of land 16.25 i-ods long, and 9.125 rods wide ? 25. What are the contents of a board 12.07 feet long, and 1.005 feet wide? 26. What will 27.5 yai'ds of cloth cost, at .875 dollars per yard ? 27. At $25,125 an acre, what will 127.045 acres cost? 28. Bought 17.875 tons of hay, at $11.75 a ton: what was the cost of the whole ? 29. A gentleman purchased a farm of 420.25 acres, for $35.08 an acre ; he afterwards sold 196.175 acres to one man for $37.50 an acre, and the remainder to another person, for $36,125 an acre : what did he gain on the first cost ? 30. A merchant bought two pieces of cloth, one containing 87.5 yards, at $2.75 a yard, and the other, containing 27.35 yards, at $3,125 a yard ; he sold the whole at an average price of $2.94 a yard : did he gain or lose by the bargain, and how much ? 8 162 CONTKACTIOXS IN CONTRACTIONS IN MULTIPLICATION. 153. Contraction, in the multiplication of decimals, is a short method of finding the product of two decimal numbers in such a manner, that it shall contain but a given number of decimal places. 1. Let it be required to find the product of 2,38645 multi- plied by 38.2175, in such a manner that it shall contain but four decimal places. Analysis. — It is proposed, in this example, to operation. take the multiplicand 2.38645, 38 times, then 2.38645 2 tenths times, then 1 hundredth times, then 5712.83 7 thousandths times, then 5 ten-thousandths 715935 times, and the sum of these several products 190916 will be the product sought. 4773 Write the unit figure of the multiplier directly 239 under that place of the multiplicand which is 167 to be retained in the product, and the remaining 1 2 places of integer figures, if any, at the right, 91.2042 and then write the decimal places at the left in their order, tenths, hundredths, &c. When the numbers are so written, the product of any figure in the multiplier hij the figure of the multiplicand directly over it, will be of the same order of value as the last figure to be re- tained in the product. Therefore, the first figure of each product is always to be arranged directly under the last retained figure of the multlpli- cand. But it is the whole of the multiplicand which should be multiplied by each figure of the multiplier, and not a j^art of it only. Hence, to compensate for the part omitted, we begin 153. What is contraction in the multiplication of decimals ? What is proposed in the example ! liow arc the numbers written down for multi- (jlication 1 When the numbers are so written, what will be the oriicr of value of the product of any figure of the multiiilier by the figure directly over it 1 Where then is the first figure of each product to be written ! liow do you compciibutc for tlie j»art ouiiUvd ! \ MULTIPLICATION. 163 with tlie figure at tlie riglit of the one directly over any muUiplier, and carry one when the product is greater than 5 and less than 15, 2 when it falls between 15 and 25, 3 when it falls between 25 and 35, and so on for the higher numbers. For example, when we multiply by the 8, instead of saying 8 times 4 are 32, and writing down the 2, we say first, 8 times 5 are 40, and then carry 4 to the product 32, which gives 36. So, when Ave multiply by the last figure 5, we first say, 5 times 3 are 15, then 5 times 2 are 10 and 2 to carry make 12, which is written down EXAMPLES. 1. Multiply 36.74637 by 127.0463, retaining three decimal places in the product. Contraction. Oonunon ivay. 36.74637 36.74637 3640.721 127.0463 3674637 11023911 734927 22047822 257225 14698548 1470 25722459 220 7349274 11 3674637 4668.490 4668.490346931 2. Multiply 54.7494367 by 4.714753, reserving five places of decimals in the product. 3. Multiply 475.710564 by .3416494, retaining three decimal places in the product. 4. Multiply 3754.4078 by .734576, retaining five decimal places in the product. 5. Multiply 4745.679 by 751.4549, and reserve only whole numbers in the product. 16-i DIVISION OF 154. Note. — When a decimal num'ber is to be multiplied by 10, 100, 1000, kc, the multiplication may be made by removing the decimal point as many places to the right hand as there are ciphers in the multiplier ; and if there be not so many figures on the right of the decimal point, supply the deficiency by annexing ciphers. Thus, 4.27 multiplied by Also, 59G.027 multiplied by 10 42.7 100 427 > 1000 > = < 4270 10000 42700 100000 ^ 427000 10 ' ' 5960.27 100 59G02.7 > 1000 - = ^ 596027 10000 5960270 100000 59602700 I i DIVISIOxN OF DECIMAL FRACTIONS. 1.5.5. Division of Decim.^l Fractions i.s the operation of divi.sion when eitlier the divisor or dividend is a decimal, or when both are decimals. Analysis. — Since the dividend must be equal to the product of the divisor and quo- tient, it must contain as many decimal places as both of them (Art. 152) : there- fore. There must be as many decimal places in the quotient as the number of decimal places in the dividend exceeds thnt in the divisor : hence, OPERATION. 2.043). 71505(35 ^129 10215 10215 Ans. 0.35. Rule. — Divide as in simple numhers, and point off in the 154. How do you multiply a decimal number by 10, 100. 1000, &c. ? If there are not as many decimal figures as there are ciphers in the nnilti- pUer, what do you do ? 155. If one decimal fraction be multiplied by anothor, how many deci- mal places will there be in the product ' How docs the number of deci- mnl jilaces in the dividend compare with those in the divisor and quotient' How do you determine the number of decimal places in the quotient 1 Clivc the rule for the division of decimals. DECIMAL FE ACTIONS. 165 quotie7it,from the right hand, as mamj -places for decimals as the numhcr of decimal 'places in the dividend exceeds that in the divi- sor ; and if there are not so many, mpphj the deficiency hy pre- fixing ciphers. EXAMPLES. 1. Divide 4.6842 by 2.11. 2. Divide 12.825G1 by 1.505. 3. Divide 33.6G431 by 1.01. 4. Divide .010001 by .01. 5. Divide 24.8410 by .002. 6. Divide .0125 by 2.5. 7. Divide .051 by .012. 8. Divide .0G3 by 9. 9. Divide 1.05 by 14. 10. Divide 5.1435 by 4.05. 11. Divide .46575 by 31.05. 12. Divide 2.46616 by .145. 13. Wliat is the quotient of 75.15204, divided by 3 ? By .3 ? By .03 ? By .003 ? By .0003 ? 14. What is the quotient of 389.27688, divided by 8? By .08 ? By .008 ? By .0008 ? By .00008 ? 15. What is the quotient of 374.598, divided by 9 ? By .9 ? By .09 ? By .009 ? By .0009 ? By .00009 ? 16. What is the quotient of 1528.4086488, divided by 6? By .06 ? By .006 ? By .0006 ? By .00006 .? By .000006 ? 17. Divide 17.543275 by 125.7. 18. Divide 1437.5435 by .7493. 19. Divide .000177089 by .0374. 20. Divide 1674.35520 by 9.60?, 21. Divide 120463.2000 by 1728. 22. Divide 47.54936 by 34.75. 23. Divide 74.35716 by .00573. 24. Divide .37545987 by 75.714. 25. If 25 men remove 154,125 cubic yards of eartli in a day, how much does each man remove ? 26. If 167 dollars 8 dimes 7 cents and 5 mills be equally divided among 17 men, how much will each receive ? 27. Bought 45.22 yards of cloth for ^97.223 : how much was it a yard ? 28. If 375.25 bushels of salt cost $232,655, wliat is the price per bushel ? L66 DIVISION OF 29. At $0,125 per pound, how much sugar can be bought for $2.25 ? 30. How many suits of clothes can be made from 34 yards of cloth, allowing 4.25 yards for each suit ? 31. If a man travel 26.18 miles a day, how long will it take him to travel 366.52 miles? 32. A miller wishes to purchase an equal quantity of wheat, corn, and rye ; he pays for the wheat, $2,225 a bushel ; for the corn, $0,985 a bushel ; and for the rye, SI. 168 a bushel: how many bushels of each can he buy for S242.979 ? 33. A farmer purchased a farm containing 56 acres of wood- land, for which he paid $46,347 per acre ; 176 acres of meadow land, at the rate of $59,465 per acre ; besides which there was a swamj) on the farm that covered 37 acres, for which he was charged $13,836 per acre. What was the area of the land ; what its cost ; and what the average price per acre ? 34. A person dying has $8345 in cash, and 6 houses, valued at $4379.837 each ; he ordered his debts to be i)aid, amounting to §3976.480, and $120 to be expended at his funeral ; the residue was to be divided among his five sons in the following manner : the eldest was to have a fourth part, and each of the other sons to have equal shares. What was the share of each son ? ( PARTICULAR CASES. 156. Note. — 1 . When any decimal number is to be divided by 10, 100, 1000, &c., the division is made by removing the decimal point as many places to the left as tlieie are O's in the divisor : and if there be not so many figures on the left of the decimal point, the deficiency must be supplied by prefixing ciphers. l.'jG. How do you divide a decimal number by 10. 100, 1000, &c. 1 II thorn be not as many figures at tlie left of tlic deci.nal point as there cipher* in the divisor, what do you do ? DECIMAL FRACTIONS. 167 10 ] [4.987 100 .4'J87 1000 > = -^ .01987 10000 J .004987 10 1 r 32.756 100 3.2756 1000 y = [ .32756 10000 .032756 100000 .0032756 49.87 divided by 327.56 divided by 157. Note. — 2. When there are more decimal places in the divi- sor than in the dividend, annex as many ciphers to the dividend aa are necessary to make its decimal places equal to those of the dii^i sor; all the figures of the quotient will then he lohole numbers. Always bear in mind that the quotient is as many times greater than 1, as the dividend is times greater than the divisor. EXAMPLES. 1. Divide 4397.4 by 3.49. We annex one to the dividend. Had it contained no decimal place, we should have annexed two. OPERATION. 3.49)4397.40(1260 349 907 698 2094 2094 2. Divide 1097.01097 by .100001. Ans. 1260 3. Divide 9811.0047 by .1629735. 4. Divide .1 by one ten-thousandths. 5. Divide 10 by one-tenth. 6. Divide 6 by .6. By .06. By .006. By .2. By .3. By .003. By .5. By .005. By .000012. 158« Note. — 3. When it is necessary to continue the division farther than the figures of the dividend will allow, we may annex ciphers to it, and consider them as decimal places. 157. If there are more decimal places in the divisor than in the dividend, what do you do 1 AVhat will the figures of the quotient then be 1 158. How do you continue the division after you have brought down all the figures of the dividend ] When the division does not terminate, what sign do you place after the quotient 1 What does it show 1 1G8 CONTRACTIONS IN EXAMPLES. 1. Divide 4.25 by 1.25. In this example, after having exhausted the decimals of the dividend, we annex an 0, and then the decimal places vised in the dividend will exceed those in the divisor by 1. OPERATION. 1.25)4.25(3.4 3.75 500 500 Ans. 3.4 2. Divide .2 by .06. We see, in this example, that the division will never terminate. In such cases the di- vision should be carried to the third or fourth place, which will give the answer true enough for all practical purposes, and the sign + should then be written, to show that the division may still be continued. OPERATION. .06). 20(3. 333 + 18 18 20 18 20 Ans. 3.333 + 3. Divide 37.4 by 4.5. 4. Divide 58G.4 by 375. 5. Divide 94.0360 by 81.032. 6. Divide 36.2678 by 2 25. 159. Note. — 4. If we regard 1 dollar as the unit of United States Currency, all the lower denominations, dimes, cents, and mills, are decimals of tiie dollar. Hence, all the operations uponUiiitid States Money arc the same as the correspondins operations on decimal fractious. CONTR.ICTIONS IN DIVISION. 160. Contractions in division of decimals, are short methods of finding a quotient Avhich shall contain a given number of decimal places. 159. M'liat is tlie unit of the currnicy of the United States ? '^^'llat parts of lhi.s unit arc tlie inferior dcnoniinalions. dimes, cnits, and mills 1 IGO. "What are the contractions in division? E.\plaiii the process of making tho ilivision T DIVISION. EXAMPLES. 169 1. Divide 754.347385 by G1.34775, and find a quotient which shall contain three places of decimals. Common Method. 01.34775)754.34738500(12.296 Contracted Method. 75 61.34775)754.347385(12.290 988 61348 61347 14086 12260 1817 1226 ~590 552 "38 550 14086 438^ 12269 9550 1817 48350 12^1 12975 590 353750 ^ 361808650 38 37 1545100 1 In the operation, by the common method, the figures at the right of the vertical line, do not aflect the quotient figures : 1. Note the unit of the first quotient figure and then note the number of figures which the quotient is to contain. 2. Select as many figures of the divisor as you wish places of figures in the quotient, and midtiphj the figures so selected by the first quotient figure, observing to carry for the figures cast off as in the contraction of multiplication. 3. Use each remainder as a new dividend, and in each follow ing division omit one figure at the right of the divisor. ]S^OTE. — In the example above, the order of the first quotient figure M'ns obviously tens : hence there were two places of whole numbers ; and as there were three decimal places required in the quotient. /I'c fip:u)es of the divisor must be used. 2. Divide 59 by .74571345, and let the quotient contain four pl.'u't's of decimals. 160 What fifrures may be omitted in the contracted method'! ITO KEDUCTION OF 3. Divide 17493.407704962 by 495.783269, and let the quotient contain four places of decimals. 4. Divide 98.187437 by 8.4765G18, and let the quotient contain seven places of decimals. 0. Divide 47194.379457 by 14.73495, and let the quotient contain as many decimal places as there will be integers in it. REDUCTION OF COMMON AND DECIMAL FRACTIONS. 161. To change a common to a decimal fraction. The value of a fraction is the quotient of the numerator di vided by the denominator (Art. 105.) 1. Reduce |- to a decimal. Analysis. — If we place a decimal point after the 7, operation. and then write any number of O's, alter it, the value 8)7.000 of the numerator will not be changed (Art. 148). .875 If then, we divide by the denominator, the quo tient will be the decimal number : hence, Rule. — Annex decimal ciphers to the numerator and then divide by the denominator, pointing off as in divif^ion of decimal' EXAMPLES. Reduce the following common fractions to decimals : 1. Reduce \, l, and f. 9. Reduce j"^ and ^^. i 2. Reduce |^, ^, and -f^. 3. Reduce f and -^^. 4. Reduce j^-^ and y*j. 5. Reduce l and tttoTT' 6. Reduce -^^ and \^. 7. Express |i5^| decimally. 8. Express -^^^.j decimally. 10. Express 3^} ^5- deciraullj 11. Reduce y^j and 2^/j." 12. Reduce -^- of j of 6. 13. Reduce | of }\. 14. Reduce y\ of ||. 15. Reduce | of r!-- 16. Reduce ?°hind ^*\. 20 7 5 8 17. What is the decimal value off of |- multiplied by yg. 161, How do you cliaiigcaconimon toadccimal fraction'! SfZ. How ilo yoii rh.iiii;'^ a dcciiiial to llic loriii of a comiDoii fraction? COMMON FK ACTIONS. 171 18. What is the value, in decimals, of -} of f of I divided Djfoff? 19 A man owns |- of a ship ; he sells 2% of his share : what part is that of the whole, expressed in decimals ? 20. Bought 11 of 87fV bushels of wheat for ^^^ of 7 dollars a bushel : how much did it come to, expressed in decimals ? 21. If a man receives f of a dollar atone time, 71 at another, and 8|- at a third : how much in all, expressed in decimals ? 22. What mixed decimal is equal to f of 18, and /^ of 11 plus 74, added together ? 23. What decimal is equal to f of 31 taken from f of 8f ? 24. What decimal is equal to 4fj V^j h added together? 162. To change a decimal to the form of a common fraction. A decimal fraction may be changed to the form of a common fraction by simj^ly writing its denominator (Art. 145). EXAMPLES. Express the following decimals in vulgar fractions. 1. Reduce .25 and .75. 2. Reduce .125 and .625. 3. Reduce .105 and .0025. 4. Reduce .8015 and .6042. 5. Reduce .68375. 6. Reduce .01875. 7. Reduce .22575. 8. Reduce .265625. DENOMINATE DECIMALS. 163. A Denominate Decimal is one in which the unit of the fraction is a denominate number. Thus, .3 of a dollar, .7 of a shilling, .8 of a yard, &;c., are denominate decimals, in which the units are, 1 dollar, 1 shilling, 1 yard. CASE I. «• 164. To find the value of a denominate number in decimals of a liigher tmit. 163. What is a denominate {lecimaH 164. How do you find the value of a denominate number in decimals of a higher unit I OPEUATION. ■|f?. = .75d. ; hence, 9f(/. =9.75d. 12)9.75(7. .8125s., and 20)4.8125.5. 172 REDUCTION OF I. Reduce £1 4s. 9^d. to the decimal of a £. Analysis. — Wc first reduce 3 fartliings to the decimal of a penny, by dividing by 4. ^Ye then annex the quotient .756?. to the 9 pence. We next divide by 12, giving .81 25, which is the decimal of a shilling. This we annex to the shillings, and £.240625 : therefore, then divide by 20. ^1 4^ 93J. ='^^1.240625. Rule. — I. Divide the lowest denomination hy the units of the scale which connect it toith the next higher, annexing ciphers, if nccessa?y. II. Annex the quotient to the next higher dcnominntion and divide hy the units of the scale ; and proceed in the same manner through all the denominations, to the required unit. Note. — When any denomination, between the highest and the lowest is wanting, the number to be prefixed to the corresponding quotient, is 0. EXAMPLES. 1. Reduce 14 drams to the decimal of a Ih., Avoirdupois. 2. Reduce 78(f. to the decimal of a £. o. Reduce 03 pints to the decimal of a peck. 4. Reduce 9 hours to the decimal of a day. 5. Reduce 375G78 feet to the decimal of a mile. 6. Reduce 7oz. Iddict. of silver to the decimal of a pound, 7. Reduce Sctct. lib. 8oz. to the decimal of a ton. 8. Reduce 2.45 sliillings to the decimal of a £. , 9. Reduce 1.047 roods to the decimal of an acre. 10. Reduce 176.9 yards to the decimal of a mile. 11. Reduce 2qr. lilb. to the decimal of a C7rt. 12. Reduce IO02;. ISdivt. ^('■•gr. to the decimal of a lb. 13. Reduce oqr. 2na. to the decimal of a yard. 14. Reduce ^gal. to the decimal of a hog.-^head. 15. Reduce 17//. Gm. 43ser. to the decimal of a day. 16. Reduce 4ctct. '^^qr. to the decimal of a ton. 17. Reduce 19s. 5d. 2fa7\ to the decimal of a poiuid. DKNOMINATE DECIMALS. 173 18. Reduce 1^. ."7/'. to the decimal of an acre. 19. Reduce 2qr. ona. to the decimal of an Eng. Ell. 20. Reduce 2ijd. 2ft. G^««. to the decimal of a mile. 21. Reduce 15' 22^." to the decimal of a degree. 22. Reduce 290 cubic inches to the decimal of a ton of round timber. 23. Reduce obusJi. oph. to the decimal of a chaldron. 24. Reduce 17yc?. 1ft. Qin. to the decimal of a mile. 25. "What decimal part of a year is 9^ months ? 2G. What decimal part of a lb. is lOoz. 18dwt. 16gr.? 27. What decimal part of an acre is 1^. 14P. ? 28. AYhat decimal part of a chaldron is Aojyk. ? 29. What decimal part of a mile is 72 yards ? 30. What part of a ream of paper is 9 sheets ? 31. What part of a rod in length is 4.0125 inches? 32. Reduce IQwk. 2£?a. to the decimal of a leap year. 33. Reduce 4 5 13 19 lO^-r. to the decimal of a ife. 34. Reduce 3qt. 1.7 opt. to the decimal of a /ihd. 35. Reduce 24:sq. yd. l.^sq.ft. to the decimal of an acre. 36. Reduce 2qr. Ina. 0.3 6m. to the decimal of a yard. 37. Reduce 3ft. 4' 8" 3'" to feet and decimals of a foot. CASE II. 165. To find the value of a decimal in integers of less denomi- nations. 1. What is the value of .832296 of a £ ? Analysis. — Fu-st multiply the decimal operation. by 20, which brings it to the denomination .832296 of shillings, and after cutting off from the 20 right as many places lor decimals as there 16.645920 are in the given nunlber, we have 1 65. and 1 2 the decimal .645920 oter. This is re- 7.751040 duced to pence by multiplying by 12, and 4 then to farthings by multiplying by 4. 3.004160 Ans. 165. "id. 3far. 165. How do you find the value of a decimal in integers of less denomi nations 1 174r DKNOMINATE DECIMALS. Rule. — I. Mulliply (he decimal by the uiiis of the scaCe which connect it with the next less denomination, pointing off as in the multijjli cation of decimals. II. Mullijily the decimal part of the product as before, and tontinue so to do until the decimal is reduced to the required deno- minations. The integers cut off at the left form the ansuer. EXAMPLES. 1. "What is the value of .6725 of a hundred weight ? 2. What is the value of .61 of a pipe of wine ? 3. What is the value of .83229 of a £ ? 4. Required the value of .0625 of a barrel of beer. 5. Requii'ed the value of .42857 of a month. 6. Required the value of .05 of an acre. 7. Required the value of .3375 of a ton. 8. Required the value of .875 of a pipe of wine. 9. What is the value of .375 of a hogshead of beer ? 10. What is the value of .911111 of a pound troy? 11. What is the value of .675 of an English ell ? 12. What is the value of .001136 of a mile in length ? 13. What is tire value of .000242 of a square mile ? 14. Required the value of .4629 degrees. 15. Required the value of .875 of a yard. 16. Required the value of .3489 of a pound apothecaries. 17. Required the value of .759 of an acre. 18. Required the value of .01875 of a ream of paper. 19. Requii'ed the value of .0055 of a ton. 20. Required the value of .625 of a sliilling. 21. Required the value of .3375 of an acre. 22. Required the value of .785 of a year, of 3651 daya REPEATING DECIMALS. 175 CIRCULATING OR REPEATING DECIMALS. 166. In changing a common to a decimal fraction, there are two general cases : 1st. When the division terminates ; and 2d. When it does not terminate. In the first case, the quotient will contain a limited number of decimal places, and the value of the common fraction will be exactly expressed decimally. In the second case, the quotient will contain an infinite num- ber of decimal places, and the value of the common fraction can- not be exactly expressed decimally. CASE I. 167. When the division terminates : When a common fraction is reduced to its lowest terms (which we suppose to be done in all the cases that follow), there wuU be no factor common to its numerator and denominator (Art. 120). 1. Reduce ^ to its equivalent decimal. Analysis. — Annexing one decimal to the operation. numerator multiplies it by 10, or by 2 and 5; 50)17. 00(. 34 hence, 2 and 5 become prime factors of the nu- 15 merator every time that an is annexed. But 2 00 if the division be exact, these prime factors, and 2 GO none others, must also he found iii the denomi- nator (Art. 91). 166. How many cases are there in chanfring a vulgar to a decimal frac- tion 1 What are they ? . What distinguishes one of these cases from tho other 1 167. How do you determine when a vulgar fraction can be exactly ex- pressed decimally ^ How many decimal places will there be in the ciuotient ' 176 CIRCULATING OR OPERATION. 2. Reduce -^ to its equivalent decimal. 35) 50 (.1388 + Analysis. — 36 = 18x2 = 9X2x2= ?^ 3 X 3 X 2 X 2 : in which we see that the de- ^'^^ nominator contains other factors than 2 and o. ^^^ aud liencc, the fraction cannot be exactly ex- "^-^ pressed bij decimals (An. 91). Hence, to deter- ^^^ mine whether a common fraction can be exactly ^^^ expressed decimally : 288 I. Decompose the denominator into its prime factors; and if there are nn factors other than 2 and 5, (he exact division can be made : II. If there are other prime factors, the exact division cannot he made. Note.— Every decimal annexed to the numerator, introduces the two factors 2 and 5 ; and these factors must be introduced until we have as many of each as there are in the denominator after it shall have been decomposed into its prime factors 2 and 5. But the quo- tient will contain as many decimal places as there arc decimal O's in the dividend (Art. 155); hence, The number of decimal jylaces in the quotient will be equal to ike greatest number of equal factors 2 or 5, in the divisor. EXAJrPLES. 1. Can ^^3- be exactly expressed decimally ? opkration. how many jdaces ? 25) 70 (.28 50 25 = 5 X 5 ; hence, the fraction can be ex- 200 actly expressed decimally. 200 Find the decimals and number of places in the following: 1. Express ^?^ decimally. 5. Express ^Vo decimally. 2. Express ^-/^ decimally. G. Express -^^ decimally. 3. Express ^y^y decimally. 7. Express ^f^ decimally. 4. Express yi^^ decimally. J 8. Express /^j decimally. REPEATING DECIMALS. 177 CASE II. 168. When (he division does not terminate. 1. Let it be required to reduce i to its equivalent decimal. Analysis. — By annexing decimal ciphers to the numerator 1, and making the division, wc operation. find the equivalent decimal to be .3333 +, &c., 3)1 0000 giving 3's as far as avc choose to continue the .3333 + divifcion. The further the division is continued, the nearer the value of the decimal will approach to ^, the true vaZ;/eof the common fraction. We express this approach to equality of value, by saying, that if the division be continued without limit, that is, to infill ity, the value of the docimal will then become equal to that of the common fraction ; thu s, .33.33 +, continued to infinity 1 . 3 ' for, every annexation of a 3 brings the value nearer to ^. Also, .9999 +, continued to infinity = 1 ; for, every annexation of a 9 brings the value nearer to 1. 2. Find the decimal corresponding to the common fraction |^. Analysis. — Annexing decimal ciphers and operation. dividing, we find the decimal to be .2222 +, in 9)2.0000 which we see that the figure 2 is continually .2222 + repeated. 169. A Circulating Decijial is a decimal fraction in which a single figure, or a set of fiigures, is constantly repeated. 170. A Repetend is a single figure or a set of figures, which is constantly repeated. 168. Can one-third be exactly expressed decimally'! What is the foni) of the quotient 1 To what docs the value of this quotient approach ? When does it become equal to one-third 1 169. What is a circulatinjr decimall 170. What is a repetcnd 1 178 CIKCr LATINO OK 171. A Single Repetend is one in -which only a single figure is repeated ; as I = .2222+, or | = .3333 +. Such repetends are expressed by simply putting a mark over the first figure ; thus, .2222 +, is denoted by .% and .3333 + by .'3. 172. A Compound Repetend has the same set of figures circulating alternately ; thus. If = .57 57 +, and -|4|| = .5723 5723 +, are compound repetends, and are distinguished by marking the first and last figures of the circulating period. Thus, .57 57 + is written .'57', and .5723 5723 + is written .'5723'. 173. A Pure Repetend is one which begins with the first decimal figure ; as .'3, .'5, .'473', &c. 174. A Mixed Repetend is one which has significant figures or ciphers between the repetend and the decimal point ; or which has whole numbers at the left hand of the decimal point ; such figures are caWo.^ finite figures. Thus, .0733', .473', .3'573', G.'o, are all mixed repetends ; .0, .4, .3, and 6, are ih^ finite figures. 175. Similar Repetends are such as begin at equal dis- tances from the decimal points ; as .3'54', 2.7'534;.'. 176. Dissimilar Repetends are such as begin at different ^.'stances from the decimal point ; as .'253', .47'52'. 177» Conterminous Repetends are such as end af equal distances from the decimal points ; as .1'25', .'354'. 171. ^Vhat is a single repetend ? 372. What is a compound repetend T 173. What is a pure repetend 1 174. What is a mixed rcj)etcnd 1 175. What are similar repetends t 17(). What are dissimilar repctoudal REPEATING .DECIMALS. 179 178. Similar and Conterminous Repetends are sucli as bei^in and end at the same distances from the decimal point ; thus, 53.2753', 4.6'325', and .4^632', are similar and conter- minous repetends. REDUCTION OF REPETENDS TO COMMON FRACTIONS. CASE I. 179. To reduce apure repetendto its equivalent common fraction. Analysis, — This proposition is to be analyzed by examining the law of forming the repetends. 1st. .| =.llll+&c. = .M; and f =.4444 + &c. = .M : 2d. ^=.010101+&:c =>01'; and f|- =.2727+&c. = .'27' : 3d. ^1^=^.001001 +Scc. = .^001'; and fff = .324324 + &c. = .'324'. &c. &:c. &:c. &c. The above law for the formation of repetends does not depend on the multipliers 4, 27, and 324, but would be the same for any other figures; hence, The value of any jmre repetend is equal to the 7iiimher denot- ing the repetend, divided hy as many 9's as there are figures. EXAMPLES. 1. What is the equivalent common fraction of the repetend 0.3?^ Now, 9 = i = 0.33333 +.= 0.^3. 2. What is the equivalent common fraction of the repetend :i62' ? We have, gf I = t'tt -^"*' 3. What are the simplest equivalent common tractions of the repetends .^6,.^162', 0.769230', .^945', and .^09'? 4. AVhat are theleastequivalentcommonfractionsof the repe- tends .^594405', .^36', and .^142857' ? 177. What are conterminous repetends \ 178. What are similar and conterminous repetends 1 17'J. How do you find a common fraction equivalent to a puie repetend ! 180 CIRCULATING OR CASE II. 180. To reduce a mixed repelend to its cquivalen t common fraction. Analysis. — A mixed repetend is composed of the finite figures wliich precede, and of tlie repetend itself; hence, its value must be equal to such finite figures plus the repetend. When the repetend begins at the decimal point, the unit of the first figure is .1. But if the repetend begins at any place at the right of the decimal point, the unit value of the first figure will be diminished ten limes for each place at the right, and hence, O's must be annexed to the 9"s Avhich form the divisor ; therefore, To the finite figures, add the repetend divided hy as many 9'* as it contains places of figures, ivith as many O's annexed to them as there are places of decimal figures preceding the repe- tend ; the sum reduced to its simplest form icill be the equivalent fraction sought. EXAMPLES. 1. Required theleast equivalent common fractioQ of the mixed repetend, 2.4:'18'. Now, 2.4^18' = 2 + T-V +^18' = 2 + T^ + J4 = 2f 3. Ans. 2. Required theleast equivalent common fraction of the mixed repetend .o'925'. We have, .5^925' = -^ + ^^ = If- ^««- 3. What is the least equivalent common fraction of the repe- tend .008^497133'? Wo havf 008M971?!i' a i 4971 33 S3_, nCIKHt, .UUOiJ/IOO — Yoo^ i- 99-9999-000- — TTTaS' 4. Required the least equivalent common fractions of the mixed repetends .13^8, 7.5^43', .04'3o4', 37.5^4, .G7o', and .7^:i4347'. 5. Required the least equivalent common fractions of tlie mixed rcpetends 0.7^5, 0.4^38', .09^3, 4.7^543', .009'87^ and .4'o. 180. How do you find the value of a mixed repetend ' REPEATING DECIMALS.. 181 CASE III. 181. To find the finite figures and the repetend corresponding to Q,ny common fraction. 1. Find the finite figures and the repetend corresponding to the fraction ^^^q- Analysis. — 1st. Reduce the frac- tion to its lowest terms, and then OPKRATION. fi 3 560 280 3 280 2X2X2X5X7 280)3.000 +(.010^714285' find all the factors 2 and 5 of the denominator. 2d. Add decimal ciphers to the numerator and make the division. 3d. The number of finite decimals preceding the first figure of tho repetend will be equal to the greatest number of factors 2 or 5 (Art. 167). In this example it is 3. 4th. When a remainder is found which is the same as a previous dividend, the second repetend begins. 5th. The number of figures in any repetend will never exceed tha number, less l , of the units in that factor of tlie denominator which does not contain 2 or 5. Tn the example, that number is 7, and the number of figures of the repetend, is 6. Hence, Divide the numerator of the common fraction, reduced to its lowest terms, hj the denominator, and point off in the quotient the finite decimals, if any, and the repetend. EXAMPLES. 1. Required to find whether the decimal, equivalent to the common fraction 3-f ^-qt? is finite or c finite figures, if any, and the repetend Analysis. — We first reduce the fraction to its lowest terms, giving TtI It- ^^° ihen search for the fac- tors 2 and 5 in the denominator, and find that 2 is a factor 3 times ; hence, we know that there are three Q'^f;«")»'3 ofl + C on8''4Q7l 3*?' finite decimals preceding the repe- tend. We next divide the numerator 83 by the denominator 9768, and 181. How do you find the finite figures and the repetend corres]>ondi!ii» to any CDUuniMi fr;icli()ii ? jirculating : required the OPERATION. 249 83 29304 9768 83 83 9768 2X2X2X1221 182 PKOPERTIES OF THE note that the repeteiid begins at the fourth place. After the ninth 'livision, .we find the remainder 83 ; at this point the figures begin to 'epeat ; hence, the rcpetend has 6 places. 2. Find the finite decimals, if any, and the rcpetend, if any, )f the fraction fy^* 3. Find the finite decimals, if any, and the repetend, if any, tf the fraction ■. A„ -. 4. Find the finite decimals, if any, and the repetend, if any, of the fractions ^22^ _^^ _7_2_. PROPERTIES OF THE REPETENDS. 182. There ai-e some properties of the vepetends which it is important to remark. 1. Any finite decimal may be considered as a circulating decimal by making ciphers to recur ; thus, .35 = .35^0 = .35^00' = .35^000' := .35^0000', &c. 2. If any circulating decimal have a repetend of any number of figures, it may be changed to one having twice or thrice that number of figures, or any multiple of that number. Thus, a repetend 2.3^57' having two figures, may be changed to one having 4, 6, 8, or 10 places of figures. For, 2.3^57' = 2.3^5757' = 2.3^575757' = 2.3^57575757', &c.; so, the repetend 4.16^31G' may be written 4.16^316' = 4.1G^31G316' = 4.16^310316316', Sec. &c.; and the same may be shown of any other. Hence, two or more repetends, having a different number of places in each, may be reduced to repetends having the same number of places, in the following manner : 182. How may a finite decimal be made circulating 1 When a repetend has a given number of places, to what otlicr farm may it be reduced! How ! Into wiiat form may any circulating dociniai be transformed ? To wh.%1 fvnu may two or more icjielcnds be reduced 1 KEPETENDS. 183 Find the least comvion multiple of the number of places in each repetend, and reduce each repetendto such number of places. Ex. 1. Reduce .13^8, 7.5^43^ .04^354', to repetends having the same number of places. Since the number of places are now 1, 2, and 3, the least common multiple is 6, and hence each new repetend Avill con- tain 6 places ; that is, .13^8=. 13^888888'; 7.5^43'.zr 7.5^434343'; and 0.4^354' = 0.4^3o43o4'. Ex. 2. Reduce 2.4^8', .5^925', .008^497133', to repetends having the same number of places. 3. Any circulating decimal may be transformed into another having finite decimals and a repetend of the name number of figures as the first. Thus, .^57' = .575' =: .57\57' = .57575' = .5757^57'; and 3.4785' = 3.47^857' = 3.478^578' == 3.4785785'; and hence, any two repetends may be made similar. These properties may be proved by changing the repetends mto their equivalent common fractions. 4. Having made two or more repetends similar by the last article, they may be rendered conterminous by the pi-evious one ; thus, two or more repetends may alicays be made similar and contenninous. 1. Reduce the circulating decimals 165.'164', .'04', .037 to such as are similar and conterminous. 2. Reduce the circulating decimals .5'3, .475', and 1.'757', to such as are similar and conterminous. 5. If two or more circulating decimals, having several repe- tends of equal places, be added together, their sum will have a repetend of the same number of places ; for, every two sets of repetends toill give the same sum. 6. If any circulating decimal be multiplied by any number, the product will be a circulating decimal having the same number of places in the repetend ; for, each repetend will be taken the same number of times, and consequently must j^i'oduce the same product. 184 ADDITION OF ADDITION OF CIRCULATING DECIMALS. 183. To add circulating decimals : I. Make the reijetends, in each number to be added, similar and conterminous. II. Write the places of the same unit value in the same column, and 60 mani/ figures of the second repelend in each as shall indicate with certainty, how many are to he carried from one repdend to the other : then add as in whole numbers. Note — If all the figures of a repetend are 9's, omit them and add to the figure next at the left. EXAMPLES. 1. Add .1*2^5, 4.^163', r.7143', and 2.^54' together. Dissimilar. Similar. Similar and Conterminous. .12'5 — .12'5 = .12'555oo5555555' - - - 5555 4.'163' =4.16^316' = 4.16^310316316310' - - - 3103 1.7143' = 1.71^4371'= 1.71^437143714371' - - - 4371 2.'54' = 2.54^54' = 2.54^545454545454' - - - 5454 The true sum z= 8.54^854470131097' 1 to carry. 2. Add G7.3'45', 9.^051', .^25', 17.47, :5, together. 3. Add ;475', 3.75^43', 04.75', .^57', .1788', together. 4. Add :o, 4.37, 49.4\57', .4^954', .7345', together. 5. Add .^175', 42.^57', .3753', .4'954', 37^54', together. 6. Add 105, .\1W, 147.^04', 4.^95', 94.37, 4.712345' to- gether. SUBTRACTION OF CIRCULATING DECIMALS. 184. To subtract one circulating decimal from another. I. 3fuke the repetends similar and co7iterminous. ' II. Subtract as in finite decimals, observing that when the repetend of the lower line is the larger, 1 must be carried to the first rigid hand figure. 183. How do you add Circulating Decimals ? IS'l. How do you subtract Circulating Decimals ! CIRCULATING DECIMALS. 186 EXAMPLES. 1. From 11.475' take 3.45735'. Dissimilar. Similar. Similar and Conterminous. 11.^75' =: 11.47^57' == 11.47^575757' - - - ■ 3.45735' = 3.45735' = 3.45735735' - - - . The true difference = 8.01^840021' 1 to carry. 575 735 2. From 47.5^3 take 1.757'. 3. From 17.^573' take 14.57. 4. From 17.4^3 take 12.34^3. 5. From 1.12754' take. 47384'. G. From 4.75 take .37^5. 7. From 4794 take .1744'. 8. From 1.457 take .3654. 9. From 1.4^937' take .1475. MULTIPLICATION OF CIRCULATING DECIMALS. 185. To multiply one circulating decimal by another. Change the circulating decimals into their equivalent common fractions., and then multiply them together ; then, reduce the product to its equivalent circulating decimal. EXAMPLES. 1. Multiply 4.25^3 by .257. OPERATION. 4 95^3 — 4-l-_25_4. _3_ — 4 4. 225 I 3 900 2 2_R 3 S28 900 — 9T0~ 45 9.A1 225* Also, .257 =: -rsoo 5 lience, - 957 y _2_5J_ _ 2 45 9A9 _ 1 0931 OT) • 225 '^ 1000 — 225000 — x.v^UAVU, and since 225000 = 5x5x5x5x5x2x2x2x9; there will be five places of finite decimals, and one figure in the repetend (Art. 1G7). NoTK. — Much labor will be saved in this and the next rule by Icccpinp^ every fraction in its lowest terms ; and when two fractions are to be vndtipHcd together, cancel all the factors common to both terms be fore niakiyig the multiplicalion. ]Sr>. How do you mulliply Circulating Decimals 1 9 186 i)ivisio>r OF 2. Multiply .375'4 by 14.75. 3. Multiply .4'253' by 2.57. 4. Multiply .437 by 3.7^5. 5. Multiply 4.573 by .375'. 6. Multiply 3.45^ 6 by .42^5. 7. Multiply 1.^456' by 4.2^3. 8. Multiply 45.1^3 by .^245'. 9. Multiply .4705^3 by;.7^35'. DIVISION OF CIRCULATING DECIMALS. 186. To divide one circulating decimal by another. Change the decimals into their equivalent common fractions, and find the quotient of these fractions. Then change the quch tieni into its equivalent decimal. EXAMPLES. 1. Divide 5G.^6 by 137. OPERATION. 56.^6 Then, ] 7 3 56 4- 6- — SJLO _ no.. 137 = ip X t1_ = i7fi ^ /413G2530'. 4] 1 2. Divide 24.3^18' by 1.792. 3. Divide 8.59G8 by .2^45'. 4. Divide 2.295 by .^297'. 5. Divide 47.345 by 1.76'. 0. Divide 13.5UG9533 by 4.^297' 7. Divide .H5' by .^118881'. 8. Divide .^475' by .3753'. 9. Divide 3.753' by .^24'. CONTINUED FRACTIONS. 1. If -we take any irreducible fraction, as J-|, and divide both terms by the numerator, it will take the form 15 1 1 , ,. , ^. . . ml = V9 = T I ]4 > ^y malcmg the division. ZJ 1.. ^ "I 15 If now, we divide both terms of ^|^ by the numerator 14, we have 14 1 15 ~ 1 + tL ]8G. lluw f 11 ? SIMPLE PROPORTION— OR, SINGLE RULE OF THREE. 197. Simple Propoktion is an expression of equality between two simple ratios. Hence, a simple proportion con- sists of four single term,s, in which the ratio of the first to the second is equal to the ratio of the third to the fonrth. If three of these terms are known, the fourth can easily be found (Art. 193). 198, The Rule of Three explains the method of finding, from three given numbers, a fourth, to wliich the third shall bear the same ratio as exists between the first and second. 1. If 8 barrels of flour cost $5G, what will 9 barrels cost, at the same rate ? Note. — We shall denote the vequired terms of the proportion by the letter x. Analysis. — The condition, '' at the same rate,"' requires that the quantity. 8 barrels of flour, have the same ratio to the quan- tity, 9 barrels, as $.56; the cost of 8 barrels, to X dollars, the cost of 9 barrels: that is, quantity is to quantify, as cost to cost : and, Since the product of the two extremes is equal to the product of the two means (Art. 193) ; we have, 8 X 0? = 56 X 9 ; ST.\TEMENT. bar. bar. % 8 : 9 : : 56 OPERATION. $ X 9 X =^ $63, 197. What is Simple Proportion? How many terms are employed? How mnny terme must be Ivuown, before the rest can be found ? 198. What is the Kule of Three? 194 KATIO AND PROPORTION. and if 8 times x is equal to 56 x 49, x must be equal to this product divided by 8 : hence, The fourth term is equal to the product of tht second and third terms^ divided by the fust. 2. If 36 dollars will buy 9 yards of cloth, bow many yards, at the same rate, can be bought for $44 ? Analysis. — Thirty-six dollars, the cost of 9 yards of cloth, is to $44, the cost of the required cloth, as 9 yards to the re- quired number of yards; that is, cost is to cost J as quantity to quantity. The product of the two extremes being equal to the product of the two means, we place 36 and x on the left of the vertical line, and 44 and 9, on the right. STATEMENT. S $ : : yd. yd. 36 : 44 9 : X OPERATION. 4 t^ M 11 X — ilyd. 199. Hence, we have the following RULE. 1. Write the nvmher which is of the same kind toith the ansioer for the third term, the number named in connection with it for the first term, and the remaining number for the second term. II. Multiply the second and third terms together, and divide the product hy tlie first term: or, Multiply the third term by the ratio of the first and second. Notes. — 1. If the fir.st and second terms have diHeicnl units, ihoy must be reduced to the same unit. 2. If the third term is a compound denominate number, it must be reduced to its smallest unit. 109. How do you state a ([nestion l>y the Rule of Three? How do you find the foin-tli term? (live the entire rule. EXAMPLES. 195 3. The preparation of the terms, and writing them in their proper places, is called the statement. 4. When the vertical line is used, the unknown term is always WTitten at the left. EXAMPLES. 1. If 8 hats cost $24, what will 110 hats cost, at the same rate ? 2. If 2 barrels of flour cost $15, what will 12 barrels cost ? 3. If I walk 168 miles in 6 days, how far should I walk, at the same rate, in 18 da}'s ? 4. If 8^/;. of sugar cost $1,28, how much will 13/^. cost? 5. If 300 barrels of flour cost $2100, what will 125 barrels cost ? 6. If 120 sheep yield 330 pounds of wool, how many pounds will 3G sheep yield ? 7. If 80 yards of cloth cost $340, what will 650 yards cost ? 8. What is the value of 4:cwt. of sugar, at 5 cents a pound ? 9. If 6 gallons of molasses cost $1,95, what will 6 hogsheads cost? 10. If 16 men consume 560 pounds of bread in a month, how much would 40 men consume ? 11. If a man travels at the rate of 630 miles in 12 days how far will he travel in a leap year, Sundays excepted ? 12. If 2 yards of cloth cost $3,25, what will be the cost of 3 pieces, each containing 25 yards ? 13. If 3 yards of cloth cost 18s. New York currency, what will 36 yards cost ? 14. If it requires eight .shillings and four pence to buy eight ounces of laudanum, how many ounces can be purchased for 7s. 6(^. ? 15. If 5 A. IR. 16 P. of land, cost $150.5, what will 126A. '2R. 20P. cost ? 16. If Vdcwt. -Iqr. of sugar cost $129,93, what will be the cost of ^cwt. ? 17. The clothing of a regiment of 750 men cost £2834 os.: what will it cost to cloth a body of 10500 men ? 196 SIMPLE PROPORTION. 18. If dyd. 2qr. of cloth cost $15,75, how much will ^yd, oqr. of the same cloth cost ? 19. If .5 of a house cost $201.5, what would .95 cost ? 20. What will 26.25 bushels of wheat cost, if o.o bushels cost 48.40 ? 21. If the transportation of 2.5 tons of goods 2.8 miles costs $1,80, what is that per cwt.'^ 22. If f of a yard of cloth cost $2,1 6, what will I of a yard cost ? 23. If ^ of an ounce cost $11, what will l^oz. cost ? 24. What is the cost of lG|/&. of sugar, if 14p. cost $lf ? 25. If $19} will buy 14^ yards of cloth, how much will 39| yards cost ? 26. If |- of a barrel of cider cost -jj of a dollar, what will li of a barrel cost ? 27. If T^ of a ship cost $2880, what will i§ of her cost? 28. What will 116i yards of cloth cost, if 462 yards cost $150,66? 29. If 7-/j- barrels of fish cost $311 what will 32^ barrels cost ? 30. How much wheat can be bought for $9G|-, if ^hu. Ipk. cost $1,93 1 ? 31. If '^^ of a yard of cloth cost $1|, what will 71 yards cost? 32. What will be the cost of 37.05 square yards of pavement, if 47.5 yards cost $72.25 ? 33. If 3 paces or common steps be equal to 2 yards, how many yards will 160 paces make ? 34. If a person pays half a guinea a week for his board, how long can he board i'or £21 ? 35. If 12 dozen copies of a certain book cost $54.72, what will 297 copies cost at the same rate ? 36. If $3618 worth of provisions will subsist an armv of 9000 men for 90 days, if tiie army be increased by 4500 men, how much would last them the same time ? 37. A grocer bought a / ; 432 : AS XX : OPERATION. X 9 Ans. X = 9 days. 202 EXAMPLES. Write the elements of the cause containing the unknown ele- ment on the left of the vertical line for a divisor, and the elcmenti of the oilier cause on the right for a dividend. Notes. — 1. Since the effects are equal, they may each be denoted by 1 ; hence, the causes are to each other as 1 to 1 . 2. It is evident, that in this class of questions the elements of the causes are inversely proportional ; and hence, such questions have generally been arranged under the head of '• Rule of Three Inverse." EXAMPLES. 1. If 3| yards of cloth will make a coat and vest, -when the cloth is 1^ yards wide, how much cloth will be needed which is •I yards in width ? 2. If I have a piece of land 16f rods long and 3^ rods wide, what will be the length of another piece that is 7 rods wide and contains an equal area ? 3. How many yards of carpeting that is three-fourths of a yard wide, will carpet a room 36 feet long and 30 feet in breadth ? 4. If a man can perform a journey in 8 days, walking 9 hours a day, how many days will it require if he walks 10 hours a day ? 5. If a family of 15 persons have provisions for 8 months, by how many must the family be diminished that the provisions may last 2 years ? 6. A garrison of 4 GOO men have provision for G months : to what number must the garrison be diminished that the provi- sions may last 2 years and G months ? 7. A certain amount of provisions will subsist an army of 9000 men for 90 days : if the army be increased by 6000, how long will the same provisions subsist it ? 208. M'hat may we regard as causing or producing the contents of a room ? When two causes arc equal, how are the elements 1 Note. — It the cifects are equal, by what may they be denoted 1 EXAMPLES. 203 8. If G men and 3 boys can do a piece of work in 330 days, how long will it take 9 men and 4 boys to do the same work, under the supposition that each boy does half as much as a man ? 9. Four thousand soldiers were supplied with bread for 24 weeks, each man to receive liios. per day; but, by some acci- dent, 210 barrels containing 200/6. each were spoiled: what must each man receive in order that the remainder may last the same time ? 10. Suppose 4000 soldiers after losing 210 barrels of bread each containing 2001b., were to subsist on loos, each a day for 24 weeks ; had none been lost they would have received 14:0Z. a day : what was the weight of the whole, and how much did they receive ? 11. Let us now suppose 4000 soldiers to lose one-fourteenth of their bread, then to receive looz. each a day for 24 weeks : what was the whole weight of their bread including the lost, and how much would each have received per day had none been spoiled ? 12. If 4 men can do a piece of work in 80 days, how many days will 16 men require to do the same Avork? 13. If 21 pioneers make a trench in 18 days, how many days will 7 men require to make a similar trench ? 14. A certain piece of grass was to be mowed by 20 men in 6 days ; one-half the workmen being called away, it is required to find in what time the remainder will complete the work? 15. If a field of grain be cut by 10 men in 12 days, in how many days would it be cut by 20 men ? 16. If 90 barrels of flour will subsist 100 men for 120 days, how long will it subsist 75 ? 17. If a traveller perform a journey in 35.5 days, when the days are 13.566 hours long, in how many days of 11.9 hours would he perform the same journey ? 18. If 50 persons consume 600 bushels of wheat in a year, how long would it last 5 persons ? 19. A certain work can be done in 12 days, by working 4 20'i: INVEKSE PEOPOKTION. hours each day : how many days would it require to do the same work by working 9 hours a day ? 20. If 120 men can build ^ mile of wall in 15^ days, how many men would it require to build the same wall in 40| days ? 21. A garrison of oGOO men has just bread enough to allow 24:02. a day to each man for 34 days ; but a siege coming on, the garrison was reinforced to the number of 4800 men. How many ounces of bread a day must each man be allowed, to hold out 45 days against the enemy ? 22. If 3 horses or 5 colts eat a certain quantity of oats in 40 days, in what time will 7 horses and 3 colts consume the same quantity ? 23. If a person can perfoi'm a journey in 24 days of 10^ hours each, in what time can he perform the same journey, when the days are 12i hours long ? 24. A piece of land 40 rods long and 4 rods wide, is equiva- lent to an acre : what is the breadth of a piece 15 rods long that is equivalent to an acre ? 25. If a person travelling 1 2 hours a day finish one half of a journey- in 10 days, in what time will he finish the remaining half, travelling 9 hours a day ? 26. How many pounds weight can be carried 20 miles for the same money that 4-^ hundred weight can be carried 36 miles? 27. If 20 men can perform a piece of work in 12 days, working 9 hours a day, how many men will accomplish the same work in one half the time, working 10 hours a day? 28. If 72 horses eat a certain quantity of hay in 7^ weeks, how many horses will consume the same in 90 weeks ? 29. Bought 5000 planks, 15 feet long and 2^ inches thick; how many planks are they equivalent to, of 12^2- feet long and 1^- inches thick ? 30. If 12 pieces of cannon, eighteen pounders, can batter down a castle in 3 hours, in what time would nine twenty-four ])ounders batter down the same castle, both pieces of cannon being fired the same number of times, and their balls flying with the same velocity? COMPOUND PROPOKTION. 205 COMPOUND PROPORTION. 209. Compound Proportion is a comparison of compound ratios wlieii the terms are unequal. It embraces that class of questions in which the causes arc compound, or in which the effects are compound. In this class of questions, either a cause or a single element of a cause, may be required; or an effect, or a single element of an effect may be required. 1. If 8 men in 12 days can build 80 rods of wall, how much will 6 men do in 18 days? or STATEMENT. Cause : 2d Cause : : 1st Efl^ct : 2d Effect. 12; • is} - '0 : X 12x8 : 18x6 : : 80 : X Analysis. — In this example the second effeet is required, and the statement may bs read thus : If 8 men in 12 days can build 80 rods of wall, 6 men in 18 dajs will build how many (or x) rods of wall ? OPERATTON. t If. X 1$ $0 10 Ans. X =z 90 rods. 2. If a family of 12 persons, in 8 months, expend $864, hov/ many months will $900 serve a family of 20 persons ? or. STATEMENT. 1} ^ ^.r} ' '' ^^^^ $900. 12x8 : 20xx : : $864 : $900. 209. What is compound proportion 1 What questions docs it eml)race' Wliat i.9 ahvays required ^ 20G COMPOUND PROI'OKTIUN. Analysis. — In this example, an element of the second cause is required, viz.. the num- ber of months which the money will last 20 men. The question is thus stated : If 12 persons, in 8 months, expend $864, 20 persons in how many (or x) mouths will expend $900 ? OPER.iTION. t% X n $u $ 5 000 Alls. X := 5 months. o. If 24 men, in G days, working 7 hours a clay, can buiJd a wall 115 feet long 3 feet thick and 4 feet high, how long a wall can 36 men build in 12 days, working 14 hours a day, if the wall is 4 feet thick and 5 feet in height ? STATEMENT. 115 or, 24x6x7 : 36x12x14 115x3x4 : .rx4x5. Analysis. — In this example, an element of the second effect is required, viz.. the length of the wall ; and the question may be thus stated : If 24 men, in 6 days, working 7 hours a day, can build a wall 115 feet long, 3 feet thick, and 4 feet high, 36 men in 12 days, working 14 hours a day, will build a wall how many (or x) feet long, 4 feet thick and 5 feet high? OPERATION. u t X Ans. $6 n$ 2^ 3 .r = 450/V. 210. ITcncc, we have the following Rule. — I. Arrange the terms in the statement so that the causes shall comjiose one cotq^let, and the effects the other, jii^li^'"-!? X in the 2'>l'ice of the required element. 110. Give the rule for stating the question and finding the unknown part EXAMPLES. 207 II. If -s. fall in either extreme, make the product of the means a dividend, and the product of the extremes, omitting x, a dieisor ; if yi fill i. wide, and l^-in. thick, weigh Ablbs. how much will a bar of the same mcU\l wei/di that is Ifl. long, dill, wide, and 2i/». thick ? 19. If 5 compositors in 16 days, working 14 hours a day, can compose 20 sheets of 24 pages each, 50 lines in a page, and 40 letters in a line, in how many days, working 7 liou-s a day, can 10 compositors compose 40 sheets of 16 pages in a sheet, 60 lines in a page, and 50 letters in a line ? 20. Fifty thousand bricks are to be removed a given distance in 10 days. Twelve horses can remove 18000 in 6 ^%ys: how many horses can remove the remainder in 4 days? 21. If 3 men, working 10 hours a day, can plant }■ field 150 rods by 240 rods, in 5 days, how many men, working 12 hours a day, can plant a field measuring 192 rods by 30t> vod^^, in 4 days ? PAI^TNEUSITTP. 200 22. If 248 men, in 5 J, days of 11 hours each, dig a trench of 7 degrees of hardness, 232^- yards long, of wide, and 2^ deep, in how many days, of 9 hours long, will 24 men dig a trench of 4 degrees of hardness, 337-^ yards long, 5| wide, and 31 deep ? PARTNERSHIP. 211. Partxership is the joining together of two or more persons in trade, with an agreement to share the profits or losses. Partners are those who are joined together in carrying on business. Capital, is the amount of money employed. Dividend is the gain or profit : Loss is the opposite of jirofit. 212. The Capital or Stock is a cause of the entire profit : Each man's capital is the cause of his profit : Tlie entire profit or loss is the effect of the cause or capital : Each man's profit or loss is the effect of his capital : hence. Whole Stock : Each man's Stock : : Whole profit or loss : Each man's profit or loss. 1. Mr. Jones and Mr. Wilson are partners in trade: Mr. Jones puts in, as capital, $1250, and Mr. Wilson, $750 : at the end of a year there is a profit of $720 : what is the share of each? STATEIVIENT. OPERATION. 2000 : 1250 :: 720 : Jones' share. ^^^^^ X 2000 : 750 :: 720 : Wilson's share. ^ X — $450 Ans. 15 X liv- n^ X = 270. 211. What is a partnership? What are partners'? What is capital oi s^'centage is added to or sub- traded from the base. 1. Mr. .Jones buys 8 hogsheads of sugar, sells them at an advance of 15 per cent, and receives $470 : what did he pay for the sugar ? 218. How do you find the base when the percentage is subtracted from tljc base 1 218 PERCENTAGE. Analysis. — The amount received, $470 opekation. arises from adding the percentage to the 1.15) 470 ($400 base; that if>j it arises from multiplying the 470 base hy 1 + pbu; the rate per cent ; hence, to find the base, in such cases, Divide (he given number by 1 j>Zi<.? the roAe per cent, expressed decimally. 2. A cask of Avine, out of wliich 37 per cent had leaked, was found to contain 33.39 gallons : liow many gallons did the cask contain ? Analysis. — Thirty-seven per operation. cent denotes .37 of the capacity 1 —.37 per cent = .63 per cent, of the cask ; and hence, the part of the cask that is filled is de- .63) 33.39 (53 gallons, noted by 1 - .37 = .63. But 31 5 .63 of the cask contains 33.39 1 89 gallons : therefore, the entire 1 89 cask will contain as many gal- lons as .63 is contained times in 33.39. viz., 53 ; hence, to find the base, in such cases, Divide the given number by the difference between 1 und the rate p)£r cent, expressed decimally. EXA3IPI.es. 1. A farmer bought 40 sheep, and after keeping them for one year, sold them at an advance of 55 per cent, and received $248 : what did he pay for tlie sheep per head ? 2. A merchant bought a lot. of goods and marked ihcni at .in advance of 20 per cent : -vvhen sold, he found that they brought liini $6835,50 : what did the goods cost him ? 3. A son, who inherited a fortune, spent 371 per oent of it, when lie found tliat lie had only $31250 remaining: what was the amount of his fortune ? 4. A grocer purchased a lot of teas and sugar, on wiiicli he lost 16 i)(!r cent, by selling them for .^4200 : wliat did he pay fni- the goods ? INTEREST. 219 INTEREST. 219. Interest is a payment for the use of money. Principal or Base, is the money on which interest is paid. Amount is the sum of the Principal and Interest. For example : If I borrow $100 for 1 year, and pay 7 dol lars for the use of it ; then, 100 dollars is the Principal or Base, 7 dollars is the Interest, and 107 dollars is the Amount. Rate is the ratio of the principal to the interest, when the time is 1 year. Thus, .07 is tlie rate in the example, being the ratio of $100 to §7. This rate is read, 7 -per cent ; that is, $7 for every hundred : tlie term per cent, means by the hundred, and tlie term, per annum, by the year. Hence, there are four simple parts : 1st. Principal ; 2nd. Rate ; ord. Time ; 4th. Interest. CASE I. 220. To find the interest of any principal for one or more years. 1. What is the interest of $3920 for 2 years, at 7 per cent ? Analysis. — The rate of interest being operation. 7 per cent, is expressed decimally by .07 : S3920 hence, each dollar, in 1 year, ayIII pro- .07 rate. duce .07 of itself, and S3920 will pro- $274,40 int. for 1 year, duce .07 of S3920, or $274,40. There- ' 3 No. of years, fore, $274,40 is the interest for 1 year, $548,80 interest, and this interest multiplied by 2, gives the interest for 2 years : hence, the following — -^ _ « ■ 219. What is interest 1 What is principalT What is amount 1 What is Tate of interest 1 What does per annum mean 1 220. How do you find the interest of any principal for any number of years 1 Give the analysis. 220 INTEREST. RtjLE. — Multiphj the principal by the rate, expressed decimaUy and the product by the number of years. EXAMPLES. 1. Wliat is the interest of $675 for 1 year, at 6i per cent? OPERATION. $675 Analysis. — ^We first find the interest Qgi at \ per cent, and then the interest at ^Z" o ^ per cent 6 per cent; the sum is the interest at 4050 6 per cent. 6^ per cent. $43,875 fil per cent. 2. AYhat is the interest of $871,25, for 1 year, at 7 per cent ? 3. What is the interest of $535,50, for 7 years, at 6 per cent ? 4. What is the interest of $1125,885, for 4 years, at 8 per cent ? 5. What is the interest of -§789, 74, for 12 years, at 5 per cent ? 6. What is the intex-est of 6^2500, for 7 years, at 7i per cent ? 7. What is the interest of 83153,82, for 2 years, at A\ per cent? 8. What is the amount of $199,48, for 16 years, at 7 per cent ? 9. What is the amount of $897,50. for 3 years, at 8 per cent ? 10. What is the interest of $982,35, for 4 years, at 63- per cent? 11. What is the amount of ^1500, for 5 years, at 5\ per cent ? 12. What is the interest of $1914,10, for 6 years, at 3|- per cent ? 13. What is the interest of $350, for 21 years, at 10 per cent ? 14. What is the amount of 628,50, for 5 years, at 121 per cent ? 15. What is the amount of §75,50, for 10 years, at 6 per cent? 16. What is the amount of 85040, for 2 years, at 1\ per cent ? INTEREST. 221 Note. — When taerc are years and months, and the months are an aliquot part of a year, multiply the interest for 1 year by the years and the months reduced to the fraction of a year. EXAMPLES. 1. What is the interest of $119,48 for 2 years 6 months, at 7 per cent ? 2. What is the interest of $250,60 for 1 year 9 months, at 6 per cent ? 3. Yfhat is the interest of $956 for 5 years 4 months, at 9 per cent ? 4. Wliat is the amount of $1575,20 for 3 years 8 months, at 7 ])CY cent ? 5. What is the amount of $5000 for 2 years 3 months, at 5^ per cent ? 6. What is the interest of $1508,20 for 4 years 2 months, at 10 per cent ? 7. What is the interest of $75 for 6 years 10 months at 12^- per cent ? 8. Wliat is the amount of $125 for 5 years 6 months, at 4|- per cent ? CASE II. 221. To find the interest on a given principal for any rate and time. 1. What is the interest of $1752,96 at 6 per cent, for 2 years 4 months and 29 days ? Analysis. — The interest for 1 year is the product of the principal multiplied by the rate. If the interest for 1 year be divided by 12, the quotient will be the interest for 1 month : if the interest for 1 month be divided by 30, the quotient will be the interest for 1 day. The interest for 2 years is 2 times the interest for 1 year : the interest for 4 monlht-, 4 times the interest for 1 month ; and the nitere.st for 29 days, 29 times the interest for 1 day. 221. How do you find the interest for any time and rate "i How do you fiud the interest for years, months, and days by the second method T 222 PEKOENTAGK. $1752;96 OPERATION. .06 12)105,1776 int. for 1 2/r. Sl05,l776 X2 =$210,3552 2yr. 30)8.7 (i48 int. for Imo. 8,7648 X4 = 35,0592 4?no. ,29216 int. for Ida. 0,29216X29= 8.47264 29c/a Total interest, ©253,88704 Hence, we have the following EuLE. — I. Find the interest for 1 year : II. Divide t/iis interest by 12, and the quotient will be the interest for 1 month : III. Divide the interest for 1 month by 30, and the quotient will be the interest for 1 day. IV. Multiply the interest for 1 year by the number of years, the interest for 1 month by the number of months, and the inte- rest far 1 day by the number of days, and the sum of the products will be the required interest. Note. — This method of computing interest for day.s, is the one in general use. It supposes tlic month to contain 30 days, or the year 360 days; whereas, it actually contains 365 days. To find the exact interest for 1 day, we must regard the month as containing 3j;_5 days = 30-5- days; and this is the number by which the interest for one month should be divided, in order to find the exact interest for one day. As the divisor, commonly used, is too small, the interest found for 1 day, is a trifle too large. If entire accurac-- s required, the interest for the days must be diminished by its -g-^-j part = Tf 3- part. 2d method. 222. There is another rule resulting from the last analysis which is regarded as the best general method of computing intei'cst. Rule. — I. Find the interest for 1 year and divide it by 12: the quotient will be the interest for 1 month. II. Multijily the interest for 1 month by the time expressed in months and decimal parts of a month, and the product will be the required interest. Note. — Since a month is reckoned at 30 days, any number of days is rulutcd to decimals of a month by dividing the number uf days by 3. INTERESl 223 EXAMPLES. 1. What is the interest of $655, for 3 years 7 months and 13 days, at 7 per cent ? OPERATION. Syrs. = SGmos. $655 7vios. .07 13da. = A^mos. 12)45.85 int. for 1 year. Time — 43 Aminos. 3.82083 + int. for 1 month. 43.4^ time in months. 127361 1528332 1146249 1528332 165,951383 Ans. 2. What is the interest of $358,50, for 1 year 8 months and 6 days, at 7 per cent ? 3. What is tlie interest of $1461,75, for 4 years 9 months and 15 days, at 6 per cent ? 4. What is the interest of $1200, for 2 years 4 months and 12 days, at 7i per cent ? 5. What is the interest of $4500, for 9 months and 20 days, at 5 per cent ? 6. What is the interest of $156,25, for 10 months and 18 days, at 8 per cent ? 7. What is the interest of 6640, for 3 years 2 months and 9 days, at 6^ per cent ? 8. What is the interest of $276,50, for 11 months and 21 days, at 10 per cent ? 9. What is the amount of $378,42, for 1 year 5 months and 3 days, at 7 per cent ? 10. What is the amount of $1250, for 7 months and 21 days, a.t 101^ per cent ? 11. What is the interest of $6500, for 2 months and 10 days, at 9^ per cent ? 12. What is the interest of $70,50, for 10 years and 10 months, at 5^ per cent ? 22-i PEEOENTAGE. 13. What is the amount of $45, for 12 years and 27 days, at 6j per cent ? 14. What will $100 amount to in 15 years and 6 months, if put at interest at 4 jier cent ? 15. How much will $475,50 gain in 5 years 9 months and 24 days, at 8 per cent ? IG. What will be the interest of $45G0, for 14 months and 19 days, at 7 per cent ? 17. Wha^ will $128,371 amount to in 10 months and 27 days, at G per cent ? 18. What is the interest of $264,52, for 2 years 8 months and 14 days, at 6 per cent ? 19. What is the amount of $76,50, for 1 year 9 months and 12 days, at 6 per cent? 20. What Avill be the interest for 3 years 3 months and 15 days, of $241,60, at 7 per cent? 21. What is the interest of $5600, for 30 days, at 7 per cent? 22. What will $8450 amount to in GO days, at 10 per cent ? 23. What is the interest of $4000, for 1 month and 6 days, at 9 per cent ? 24. What will be the amount of $87,60, from Sept. 9th, 1852, to Oct. 10th, 1853, at 6i per cent? 25. What will be due on a note of $126,75, given July 8t;h, 1854, and payable April 25th, 1858, at 7 per cent ? 26. What is the interest of ^350, from Jan. 1st, 1856, to 15tli of Sept. next following, at 5-]- per cent ? 27. Gave a note of $560,40, March 14th, 1855, on interest, after 90 days : what interest was due Dec. 1st, 1856, at 10 per cent ? 28. Find the interest of $1256, for 11 months and 9 days, at 6 per cent. 29. What is the amount of $745,40 at 5 per cent interest, being reckoned from the 5lh day of the 10th month of 1850, to the 10th day of tlie 5th month of 1854 ? 30. Sept. 10th, James Trusty borrowed of Peter Credit $250, and IMarch 4th, 1853, he borrowed $500 more, agreeing rNTEKEST. 225 to pay 7 per cent interest on the whole ; what was the amount of his indebtedness Jan. 1st, 1854 ? 31. Ordered dry goods of A. T. Stewart & Co., at different times, to the following amounts, viz., Jan. 1st, 1854, $254 ; March 15th, 1854, $154,G0 ; April 20th, 1854, $424,25 ; and June 3d, 1854, $75,50. I bought on time at 6 per cent in- terest : what was the whole amount of my indebtedness on the tirst day of Sept. following ? 32. If I borrow $475,75 of a friend at 7 per cent, what will I owe him at the end of 8 months and a half? 33. In settling with a merchant, I gave my note for $127,28, due in 1 year 9 months, at 6 per cent : what must be paid when the note falls due ? 34. A person buying a piece of property for $4500, agreed to pay for it in thi'ee equal annual instalments, with interest at 6-^ per. cent : what was the entire amount of money he paid ? 35. A mechanic hired a journeyman for 9 months at $40 a mouth, to be paid monthly ; at the end of the time he had paid nothing; he then settled, allowed interest at 7 per cent, and gave his note, on interest, due in 1. year 4 months and 15 days : what will he pay when his note falls due ? 36. A person owning a part of a woollen factory, sold his share for $9000. The terms were, one-third cash, on delivery of the property, one-half of the remainder in 6 months, and the rest in 12 months, M'ith 7^ per cent interest: what was the whole amount paid ? NOTES. $382,50 Chicago, January, 1st, 1856. 1. For value received I promise to pay on the 10th day of June next, to C. Hanford or order, the sum of three hundred and eighty-two dollars and fifty cents, with interest fi'om date, at 7 per cent. $612 Baltimore, January 1st, 1856. 2. For value received I promise to pay on the 4th of July, 1858, to Wm. Johnson or order, six hundred and twelve dollars with interest at 6 per cent from the 1st of March, 1856. John Liberal. 226 PERCENTAGE. $3120 Charleston, July 3d, 1855. 3. Six months aftei* date, I promise to pay to C. Jones or order, three thousand one hundred and twenty dollars with interest from the 1st of January last, at 7 per cent. Joseph Sprinps. $786,50 New York, July 7th, 1851. 4. Twelve months after date, I promise to pay to Smith & Baker or order, seven hundi-ed and eighty-six -j^^ dollars for value received with interest from December 3d, 1851, at 8 per cent. "" Silas Day. $4560,72 Cincinnati, March 10th, 1856. 5. Nine months after date, for value received, I promise to pay to Redfield, Wright & Co. or order, four thousand five; hundred and sixty -J-^^ dollars with interest after 6 monthi?, at 7 per cent. Frederick Stillman. $1854,83 Boston, July 17th, 1856. 6. Eleven months after dale, for value received, we promise to pay to the order of Fondy, Burnap & Co., one thousand eight hundred and fifty-four y^q dollars with interest from May 13th, 1856, at 6 per cent. Palmer ence to the decimal of a pound (Art. 164). II. Then Jind the interest as though the sioii were dollars and cents ; after which reduce the decimal part of the answer to shil linys and pence (Art. 165). 223. How do you find tho interest when the principal is pounds, shil- lings and pence ' ESTTKUEST. . 227 EXAMPLES. 1. What is the interest, at 6 per cent, of £27 15s. 9d. for 2 years ? £27 15s. 9d. z= £27.7875. £27.7875 x .06 x 2 = £3.3345 interest. £3.3345 r= £3 6s: S\d. Ans. 2. "What is the interest on £203 18s. Gd., at 6 per cent, for 3 years 8 months 16 days ? S.^What is the interest of £215 13s. 8:/., at 6 per cent, for 3 years 6 months and 9 days ? 4. Wliat is the interest of £1543 10s. 6c/., for 2 years and a half, at 4 per cent ? 5. What is the amount of £1047 3s., for \p\ 4mo. 15da., at 6 per cent. ? 6. What is the interest on £511 Is. 4c/., at 6 per cent per annum, for 6yr. G))io. ? 7. What is the interest on £161 15s. Sd., at 6 per cent, for Smo. loda. ? PROBLEMS ]N INTEREST. 224, In every question of interest there are four parts : 1st. Principal ; 2d. Rate ; 3d. Time ; ^nd 4th. Interest. If any three of these parts are known, the 4th can be found. 1. At what rate per cent must $325 be put at interest for 1 year and 6 months, to produce an interest of $34,125 ? Analysis. — The principal, multiplied by opekation. the rate expressed decimally, multiplied by Principal, the time in years, is equal to the interest Rate, 12 (Art. 221) ; and when the time is expressed Time, Interest, in montlis and decimals of a month, the same in months, product is equal to ] 2 times the interest (Art. 221). Hence, 224. How many parts are there m every question of interest] How many of these must be known before the remainder can be found ! How do you find the interest when you know the Principal, Rate, and Time 1 How do you find the Principal when you know the interest, rate, and time 1 How do vo'i apply the formula to any ciuie ' 223 PEEOKNTAQE. I. When the time ts in months, the product of the principal rate and time will be equal (o 12 times the interest. II. When tioo of these parts and the interest are given, 12 times the interest divided hy the product of the given parts will he equal to the other part. Note — Let this formula be ^Yritten on the black board, or slate, and all the examples worked by it. To apply the rule to the above example, operation. place $325 for the principal, x for the rate, $325 18 (months) for the time, and $34,125 for ^. the interest. Cancelling and dividing, we ^^ 2 n $34,125 find a: = .07 : or, the rate is 7 per cent. o - i .-,- c 325x3 Ans. 7 per cent. EXAMPLES. 1. What principal, at G per cent, will in 9 months give an interest of $178,9552 ? 2. The interest for 2 years and 6 months, at 7 per cent, is $76,9G5: what is the principal? 3. What sum must be invested, at 6 per cent, for 10 months and 15 days, to produce an interest of §327,3249 ? 4. If my salary is §1500 a year, what sum invested at 5 per cent, will pay it ? ■ 5.. What sum put at interest for 4 years and 3 months, at 7 per cent, will gain $283,3914? 6. The interest of $2100 for 3 years 1 month and 18 days is $4G0,G0 : what is the rate per cent? 7. A man invests $5420 in Eailroad stock, and receives a semi-annual dividend of $244,17 : what is the rate per cent? 8. A person owning property valued at $2470,80, rents it for 1 year and 10 months for $452,98 : what per cent does it pay? 9. At what rate per cent must $3456 be loaned for 2 years 7 months and 24 days, to gain $503,712 ? 10. If I build a hotel at a cost of $5GO0O, and rent it for 67000 a year, what per cent do I receive for the investment ? INTKKEST. 229 11. The interest on $1119,48, at 7 per cent, is $195,900 : what is the time ? 12. A man received $47,25 for the use of 11750 ; the rate of interest being 9 per cent : what was the time ? 13. How long will it take ^7500 to amount to $7850, at 3J per cent per annum ? 14. How long will it take $500 to double itself, at 6 per cent, simple interest ? 15. Wishing to commence business, a friend loaned me $3720, at 6^ per cent, which I kept until it amounted to $5009,60 : how long did I retain it ? 16. I borrowed $700 of my neighbor for 1 year and 8 months, at 6 per cent ; at the end of the time he borrowed of me ^750 how long must lie keep it to cancel the amount of inte- rest I owed him? PARTIAL PAYMENTS. 225. We shall now give the rule established in New York (See Johnson's Chancery Reports, Vol. I., page 17,) for com- puting the interest on a bond or note, when partial payments have been made. The same rule is also adoiJted in Massachu- setts, and in most of the other states. Rule. — I, Compiite the interest on the principal to the time of tlic Jirst payment, and if the payment exceed this interest, add the interest to the principal, and from, the sum subtract the pay- ment : the remainder forms a new principal. 11. But if the payment is less than the interest, take no notice of it until other payments are 7nade, tvhich in all, shall exceed the interest computed to the time of the last payment : then add the interest, so computed, to the principal^ and from the sum subtract the sum of the payments : the remainder will form a new princip>al on which interest is to be computed as before. 225. What is the rule for partial payments 1 230 PERCENTAGE. EXAMPLES. $349,998 Richmond, Va., May 1st, 1846 1. For value received I promise to pay James Wilson or order, three hundred and forty-nine dollars ninety-nine cents and eight mills with interest, at 6 per cent. James Paywell On this note were endorsed the following payments : Dec. 25th, 1846, received $49,998 July 10th, 1847, " 4,998 Sept. Ist., 1848, " 15,008 June 14th, 1849, " 99,999 What was due April 15th, 1850 ? Principal on int. from May 1st, 1846, - - - - $349,998 Interest to Dec. 25th, 1846, time of first pay- ment, 7 months 24 days, 13,649 -f- Amount, - - - - $363,647 •-{- Payment Dec. 25th, exceeding interest then due § 49,998 Remainder for a new principal $313,649 Interest^of ^313,649 from Dec. 25th, 1846, to June 14th, 1849, 2 years 5 months 19 days §46,472 + Amount, - - - §360,121 Payment, July 10th, 1847, less~» than interest then due, - ) ' Payment, Sept. 1st, 1848, - - - 15,008_ T^^^^^""^' ". I "i^20,006" less than interest then due > Payment, June 14lh, 1849, - - 99,999 Their sum exceeds the interest then due - - $120,005 Remainder for a new principal, June 14th, 1849, 240,116 Interest of $210,116 from June 14lh, 1849, to April 15th, 1850, 10 months 1 day, $ 12.015 ToliU due, April 15th, 1850, - - - ¥252,T6r-f PARTIAL PAYMENTS. 281 $6478,84: New Haven, Feb. 6th, 1850. 2. Foi' value received I promise to pay William Jenks or order, six thousand four hundred and seventy-eight dollars and eighty-four cents with interest from date, at 6 per cent. John Stewart. On this note were endorsed the following payments : May 16th, 1853, received $545,76 May 16th, 1855, " 1276 Feb. 1st, 1856, " 2074,72. What remained due August 11th, 1857 ? 3. A's note of $7851,04 was dated Sept. 5th, 1851, on which were endorsed the following payments, viz. : — Nov. loth, 1853, $416,98; May 10th, 1854, $152: what was due March 1st, 1855, the interest being 6 per cent ? $8'J74,56 New York, Jan. 3d, 1854. 4. For value received I promise to pay to James Knowles or order, eight thousand nine hundred and seventy-four dollars and fifty-six cents, with interest from date at the rate of 7 per cent. Stephen Jones, On this note are endorsed the following payments : Feb. 16th, 1855, received $1875,40 Sept. 15th, 1856, " 3841,26 Nov. 11th, 1857, " 1809,10 June 9th, 1858, " 2421,04. What will be due July 1st, 1858 ? S345,50 Buffalo, Nov. 1st, 1852. 5. For value received I promise to pay C. B. Morse or order, three hundred and forty-five dollars and fifty cents with interest from date, at 7 per cent. Ja^in Dor. On this note are the following endorsements : 232 PEKCENTAGB. Juno 20tli, 1853, received $75 Jan. 12th, 1854, ii 10 March 3d, 1855, a 15,50 Dec. 13th, 1856, u 52,75 Oct. 14th, 1857, a 106,75 "What will there be due Feb. 4th, 1858 ? $450 Mobile, Oct. 19th, 1850. 6. For value received we jointly and severally promise to pay Jones, Mead & Co. or order, four hundred and fifty dollars on demand with interest, at 8 per cent. Manning c5 Bros. The following endorsements were made on this note : Sept. 25, 1851, received $85,60 ; July 10, 1852, received S20 ; June 6, 1853, received S150,45 ; Dec. 28, 1854, received §25,12J ; May 5, 1855, received $169 : what was due Oct. 18, 1857 ? LEGAL INTEREST. 226. Legal Interest is the interest which the law permits a person to receive for money which he loans, and the laws do not favor the taking of a higher rate. In most of the states the rate is fixed at 6 per cent ; in New York, South Carolina and Georgia, it is 7 ; and in some of the states the rate is fixed as high as 10 per cent. COMPOUND INTEREST. 227. Compound Interest is when the interest on a principal, computed to a given time, is added to the principal, and the interest then computed on this amount, as on a new principal. NoTK. — The laws do not favor the payment of compound interest. Ill most, of the states, an agreement to pay compound inlorc.-st, could uot be enforced. 226. What i.s legal interest 1 227. What is compound interest T How do you computo it ' EXAMPLES. 233 Rule. — Compute the interest to the time at which it becomes due ; then add it to the j^rincijxd and compute the interest on the amount as on a new j^^'incijKil : add the interest again to the jyrincipal and compute the interest as hefore ; do the same for all the times at which payments of interest become due ; from the last result subtract the 2^^'irici2}al, and the remainder will be the comp>ound interest. EXAMPLES. 1. What will be tlie compound interest of $3750 for 4 years, at 7 i^er cent ? $3750,000 principal for 1st year. $3750 X .07 = 2G2,500 interest for 1st year. 4012,500 principal for 2tl " 64012,50 X .07 = 280,875 interest for 2d « 42y3,'375 principal for 3d " $4293,375 x .07 = 300,536 + interest for 3d " 4593^911 + principal for 4th '* $4593,911 x .07 = 321,573 + interest for 4th « 4915,484 + amount at 4 years. 1st principal 3750,000 Amount of intei-est $1105,484 + 2. What will be the compound interest of 1175 for 2 years, at 7 per cent ? 3. What will be the amount of $240 at compound interest, for 4 years, at 5 per cent ? 4. What will be the compound interest of 8300, for three years, at 6 per cent ? 5. What will be the compound interest of $590,74, at 6 per cent, for 2 years ? 6. What will be the compound interest of $500, for 2 year, nt 8 per cent? 7. What will be the compound interest of $3758,50, for 3 years, at 7 per cent ? 8. What will be the compound interest of $95037,50, for 7 years, at per cent ? 11 234 COMPOUND INTEREST. Note. — The operation is rendered much shorter and easier, by taking the amount of 1 dollar for any time and rate given in the following table, and multiplying it by the given principal ; the pro- duct will be the required amount, from which subtract the given principal, and the result will be the compound interest. TABLE — Showing the amount of Si or £1, compound interest, from 1 year to 20 years, and at the rate of 3, 4, 5, 6, and 7 per cent. Years 3 per cent. 4 per cent. 5 per cent. per cent. 7 per cent Years. 1 1.03000 1.04000 1.05000 1.06000 1.07000 1 O 1.06090 1.18160 1.102.50 1.12360 1.14490 2 3 1.09272 1.12486 1.15762 1.19101 1.22.504 3 4 1.12.550 1.16985 1.215.50 1.26247 1.31079 4 5 1.15927 1.21665 1.27628 1.33822 1.40255 5 6 1.19405 1.26531 1.34009 1.41851 1.50073 6 7 1 22987 1.31593 1.40710 1.. 50363 1.60578 7 8 1.26677 1.36856 1.47745 1.59384 1.71818 8 9 1.30477 1.42331 1.55132 1.68947 1.83S45 9 10 1.34391 1.48028 1.62SS9 1.79081 1.96715 10 II 1.38423 1.53945 1.71033 1.89829 2.10485 11 12 1.42.576 1.60103 1.79585 2.01219 2.25219 12 13 146853 I 66507 1.88564 2 13292 2.40984 13 14 1.51258 1.73167 1.97993 2.20090 2.57853 14 15 1.5.5796 1.80094 2.07892 2.39055 2 75903 15 16 1.60470 1.87293 2.18287 2. ,54035 2.95216 16 17 1.65284 1.94790 2 29201 2.69277 3.1,5881 17 18 1.70243 2.02581 2.40061 2 85433 337993 18 19 1.75350 2.10684 2.52695 3.02.559 3.61652 19 20 1.80611 2.19112 2.65329 3 20713 3 86968 20 Note. — When there are months and days in the time, find tho amount for the ycarSj and on this amount cast the interest for tho months and days : this, added to the last amount, v.-ill be the re- quired amomit for the whole time. 9. What will be the compound interest of §75439,75, for 4 years? at 4^ per cent ? 10. What will SG50 amount to in 12 year.?, at 3 per cent, compound intercut ? 1 1. The slave population in the United States and territories in 1850, was 3204318; if the increase is 5 percent a year, what will be the entire slave population in 1870 ? 12. Wliat would be the compound interest of §540,50, at 6 per cent, for 3 years G months and 15 days? (Soe Note). DISCOUNT. 235 13. What will $75 amount to in 10 years 4 months and 21 days, at 7 j^er cent, compound intei'est ? 14. What will be the compound interest of $200, for 1 year 7 months and 9 days, at 5 per cent ? 15. A gives B a note of $375,40, April 20, 1854, payable Oct. 20, 185G : the interest is to be added at the end of every 6 months, and compounded at 7 per cent : what will be the amount of the payment when due ? DISCOUNT. 228. Discount is an allowance made for the payment of money before it is due. The Face of a note is the amount named in the note. 229. The PRESENT value of a note is sucli a sum as being put at interest until the note becomes due, would increase to an amount equal to the face of the note. 230. The DISCOUNT on a note is the difference between the face of the note and its present value. 1. I give Mr. Wilson my note for SlOG, payable in 1 year: what is the present value of the note, if the interest is 6 per cent ? what is the discount ? PROPORTION. 1 + its interest : $1 : : given sum : its present value. OPERATION. Analysis. — Since 1 dolJar in 1 year, SlOG -f- 1.06 = $100 at G per cent, will amount to 81,06. the pre.'^ent value will be as many dollars as proof. $LOG is contained times in the face of Int. SlOO lyr. = $ 6 the note; viz.. ?plOO; and the discount Principal = 100 will be SlOG — 100 = $6 : hence, Amount SlOG Discount 6 228. What is discount 1 What is the face of a note 1 229. What is present value 1 230. What is the discount ? 236 PERCENTAGE. Rule. — Divide the face of the note by 1 dollar plus the in. terest of 1 dollar for the given time, and the quotient will be the present value. Note. — When payments are to be made at different i\me,Sy find the present value of the sums separately, and their sum will be the present value of the note. EXAMPLES. Ul. What is the present value of a note of S615, due 1 year 4 months hence, at 7 per cent ? 2. "Wliat is the present value of $202,58, clue in 1 year 7 months and 18 days, at G per cent ? 3. How much should I deduct for the present payment of a note of $721, due in 7 months and 6 days, at 5 per cent? 4. If a note for $5160 is payable Feb. 4th, 1857, what is its value Sept. lOth, 185G, interest being reckoned at 8 per cent ? 5. "What sum of money will amount to $2500, in 2 years 7 months and 12 days, at 12 per cent ? G. "What is the present value and discount of $3000, paya- ble in 1 year 2 months and 20 days, at 7 per cent ? 7. Bouglit property to the amount of $5000, and agreed to pay for it in four equal installments ; the first in 3 months ; the second, in 6 months ; the third, in 9 montlis ; and the fourth, in 1 year : how much cash will discharge the debt ? Interest 6 per cent. ? ~ 8. If I loan a sum of money on interest at G]- per cent , for 7 months and 15 days, and at the end of the time receive $4987,50 for principal and interest, how nnicli did I loan ? ;>9. A held a note of 81400 against B, payable Aug. 1st, 185G ; B paid it May 15th, 1856 : what sum did he pay, the inlerest being 7 per cent. ? 10. A Hour merchant bought for cash 300 barrels of flour, for ^10,50 per barrel ; he sold it the same day for Si 2 a barrel, and took a note at 3 moijths : what was the cash value of tlie Bale, and wliat his gain il'the interest is reckoned at 7 per cent. ? 11. A man purcliased a house and lot for ^lOOOO, on tlio following terms : $5000 in cash, $2500 in 3 mouths, and (lie BANKING. 237 balance in G months : what was the cash value of the property, interest being reckoned at 6 per cent. ? 12. A provision dealer bought for cash 78 firkins of butter, of 8G pounds each, at 25 cents per pound. He sold it imme- diately at 25-^ cents per pound, and took a note for tlie amount at 4 months : did he gain or lose, and how much ; interest be- ing reckoned at 8 per cent. ? 13. Which is the more advantageous, to buy sugar at 7-i cents a pound, on 4 months, or at 8 cents a pound on G months, at 6 per cent, interest ? /114. Bought land at $10 an acre : what must I ask per acre if I abate 10 per ct., and still make 20 per ct on the purchase monc}- ? 15. A merchant owes three notes, viz., $1000 pa3able Aug. 1st, 1855 ; -S-oOO. payable Oct. lOtb. 1855. and SOOO payal)lc' Nov. 1st, 1855: what is-thecash value of the three notes, July 1st, 1855, reckoning interest at G per cent. ; and what is the difference between that value and their amounts at the times Avhen they fall due, if interest be reckoned from July 1st. BANKING. 231. Banks are corporations created by law for the purpose of receiving deposits, loaning money, and furnishing a paper ciiTulation I'epresented by specie. The notes made by a bank circulate as money, because they are payable in specie on presentation at the bank. They are called bank notes, or bank bills. The note of an individual, or as it is generally called, a promissoiy note, or note of hand, is a positive engagement, in writing, to pay a given sum, either on demand or at a specified time. FORMS OF NOTES. Negotiable Note. $25,50. Pi-ovidence, May 1, 185G. For value received I promise to pay on demand, to Abel Bond, or order, twenty-five dollars and fifty cents. Reuben Holmes. 233 PERCENTAGE. Note Payable to Bearer. No. 2. $875,39. St. Louis, May 1, 1855. For value received I promise to pay, six months after date, to John Johns, or bearer, eight hundred and seventy-five dollars and thirty-nine cents. Pierce Penny. Note by two Person fi. No. 3. $659,27 Bufialo, June 2, 1856. For value received we, jointly and severallj^, promise to pay to Richard Ricks, or order, on demand, six hundred and fifty-nine dollars and twenty-seven cents. Enos Allan. John Allan. Note Payable at a Bank. No. 4. $20,25. Chicago, May 7, 1856. Sixty days after date I promise to pay John Anderson, or order, at the Bank of Commerce in the city of New York, twenty dollars and twenty-five cents, for value received. Jesse Stokes. remarks relating to notes. 1. The person who si^nis a note, is called the drawer or malrr of the note; thus, Reuben Holmes is the drawer of note No. 1. 2. The person who has the rightful pos.scssion of a note, is called ihe holder of the note. 3. A note is said to be negotiable -when it is made payable to A B, or order, who is called the payee (see No. 1). Now, if Abel Bond, to whom this note is mndo payable, writes liis name on the back of it, he is said to endorse the note, and he is called the endorser; and when the note becomes due, the holder nnist first demand payment of till' maker, Reuben Holmes, and if lie declines paying it, tlio holder may then require payment of Abel Bond, the endorser. 231. Wliat arc Banks'! M'liy do (ho notes of l)nnks circulate at nioni'V ! W'li.il are tlicy called ' W h^t is a promissory note! BANKING. 239 4. If the note is made payable to A B, or bearer, then the drawer alone is responsible, and lie must pay to any person who holds the note. 5. The time at which a note is to be paid should always be named, but if no time is specified, the drawer must pay when re- quired to do so, and the note will draw interest after the payment is demanded. 6. AYhen a note, payable at a future day, becomes due, it will draw interest, though no mention is made of interest. 7. In each of the States there is a rate of interest established by law, which is called the legal interest, and when no rate is specified, the note will always draw legal interest. If a rate hi"-Ler than legal interest is named in the note, or agreed upon, the Crremium or discount. 1. What value of stock, at par, can be purchased by $3045,38 if the stock is at a premium of 10 per cent, and -^ per cent is charged for brokerage ? Analysis. — Since the stock is at a premium of 10 per cent, and the charge for brokerage is \ per cent, it will require $1,105 to pur- operation. chase $1 of stock, at par value; 1.105)3045.3S($2756 Ans. hence, $3045.38 will purchase as many dollars, at par, as $1,105 is contained times in $3045,38 ; viz., $2756. Rule. — Divide the given sum hy the cost of $1 of the stock, expressed decimally, and the quotient u'ill denote the par value of the stock p)urchased. EXAMPLES. 1. A person wishes to invest $3000 in bank stock, which ia at a discount of 15 per cent : what amount, at par value, can he purchase ? 242. How do you find the sum which will purchase a given amount of stock -at par value l 2-18 PERCENTAGE. 2. How many shares of Galena and Chicago Raih'oad Stock can be bought for $6384, at an advance of 14 per cent on tne par value of $100 a share ? S. When bank stock sells at a discount of 7\ per cent, Avhat amount of stock, at par value will §3700 buy ? 4. A person has $7000, which he wishes to invest : what v.ill it purchase in 5 per cent stocks, at a discount of 31 per cent, if he pays i per cent brokerage ? 5. How much 6 per cent stock, at par, can be purchased for $8700, at 81 per cent premium, i per cent being paid to the broker ? 6. A person owning $12000 in government funds, desires to purchase stock in the American Exchange Bank. The funds are at a discount of 3^ per cent, while the bank stock is at a premium of lOi per cent : what amount of stock, at par value, can he purchase, allowing the broker's charges for the pur- chase to be ^ per cent ? 243. 1st. To find the rate of interest on an investment, when the stock is above or below par. 2d. To find how much the stock must be above or belotv par to irroduce a given rate. 1. What is the rate of interest on an investment in G per cent stocks, when they are at a discount of 25 per cent ? Analysis. — The interest on the slock is computed on its par value, while the interest operation. on the investment is computed on the amount •' 5 paid : hence, 1 dollar multiplied by the iu- .06 terest. ou the stock will be equal to the cost x = .08 of ] dollar multiplied by the interest on the Ans. 8 per cent. investment. Rule. — I. Divide 1 dollar multiplied hj the interest on $1, by (lie price of $1 of the slock, and the quotient tvill be the rale. 243. How do you find the rate of interest on an investment when the stock is above or below par 1 How do you find the value of the stock whet the rite is given 1 STOCKS AND BROKERAGE. 2 1:9 II. Divide 1 dollar multiplied by the interest on the stock by the given rate, and the quotient will he the ijrice of $1 of the stock. EXAMPLES. 1. If I buy 7 pel :ent stock at 12-|- per cent discount, what is the i-ate per cent jn the investment ? 2. At what rate of discount must I invest in 8 per cent stock in order to yield me 10 per cent ? 3. The stock of the Erie Railroad is at G2^ per cent : if it pays semi-annual dividends of 2i per cent, what would be the rate of interest on an investment ? 4. The bonds of the Illinois Central Railroad Company, which bear interest of 7 per cent., are worth 87 per cent., and the charge for brokerage is -| per cent. : what would be the interest on an investment in these funds ? 5. If the par value of a stock is $100, and the interest 7 per cent., what is the discount when an investment yields 12 per ct. ? 6. The stock of the Hartford and New Haven Railroad is at a premium of 20 per cent : reckoning the interest on money at 6 per cent, what Avill be the interest on an investment in this stock ? 244. Which is the best investment? 1. I invest $1250 in State Stocks bearing an interest of 6 per cent, and a premium of 15 per cent. I invest the same amount in State fives at 12 per cent discount : which will yield the larger interest ? OPERATION. Analysis. — Find the rate of interest on 1.15 X n .06 the investment (Art. 243). ^_ q^^i + 244. How do you find which is the best investment ? 250 FKKCENTAGE. .88 Find the rate of interest on the second x $1 .05 investment (Art. 243). The comparison 2 =.0568 4- of these two rates will show which is the x = 5 ^-^ pr. ct. more profitable stock. 2. "Which is the best investment, to buy sixes at par, or sevens at 107 ? 3. Wliich will yield the larger profit, 8 per cent stock at a premium of 20 per cent, or 5 per cent stock at 80 per cent ? 4. If I invest $2000 in state stocks at 5 per cent, at par, and the same amount at G per cent, at 90, what will be the diifer- ence of the proceeds of the investments at the end of 5 years ? PROFIT AND LOSS. 245. Profit or Loss is a process by which merchants dis- cover the amount gained or lost in the purchase and sale of goods. It also instructs them how much to increase or diminish the price of their goods, so as to make or lose so much per cent. 1. Bought 325 bushels of wheat at $1,37 a bushel, and sold it at $1,45 a bushel : what was the profit ? OPERATION. Analysis. — We first find the $1,45 sold per bushel, profit on a single bnslicl, and 1,37 cost per bushel, then multiply by the number of ,08 profit on 1 bushel. bu.shcls, which is 325 : the pro- then, 325 x ,08 ^$26,00 profit, duct is the profit. 2. Bought a piece of broadcloth containing 36 yards, at $2,75 per yard ; it proving damaged, was sold at a loss of $18 : for what was it sold per yard ? 215. What is Profit or Loss ! How do you find the entire profit ol loss ? How do you find the profit or loss on unity \ ^ItOFIT AND LOSS. 251 Analysis. — Find the cost, which is operation. $99 ; then subtract the loss $18, and $2,75 x 3G = $99 then divide by the number of yards : Loss 1 8 the quotient \A-ill be the answer: hence, 36)81 ($2, 25 I. When the entire profit or loss is required : Find the iirojit or loss on unity and multiply it by the num- ber tvhich shares the profit or loss. II. When the profit or loss on unity is required : Find the entire profit or loss and divide it by the number ivhich shares the profit or loss. EXAMPLES. 1. Bought barrels of sugar, each weighing 250 pounds, at 7 cents a pound : how much profit would be made if it were sold at 8^ cents per pound ? 2. If in 3 hogsheads of molasses which cost $68,04, one-third leaked out, what must the remainder be sold for per gallon to realize a profit of $2,52 on the whole ? 3. A farmer bought a flock of 360 sheep ; their keeping for 1 year cost $0,75 a head ; their wool was worth 1 dollar and 25 cents a head, and one-fourth of them had laiTibs, each of which was worth one-half as much as a fleece : what was the profit of the purchase at the end of the year ? 246. Given the per cent of the yain or loss, and the amount of tJie sale, to find the cost. 1. A ffrocer sold a lot of susrars for $477,12, which was an advance of 12 per cent on the cost : what was the cost ? Analysis. — 1 dollar of the cost plus 12 per opkration. cent; will be what that wliich cost $1 sold for, 1.12)477.12 viz., $1,12 : hence, there will be as many dol- $42(3 Ans. lars of cost, as $1,12 is contained times in what the goods brought. 246. How do you find the cost when you know the per cent and the amount of sale 1 252 PERCENTAGE. 2. Mr. A. bought a lot of sugars, but finding them of an in- ferior quality, sold them at a loss of 15 per cent, and found that they brought $3-10 : what did they cost him ? Analysis. — 1 dollar of the co.^t less 15 per operation. cent, Avill be what that which cost 1 dollar sold .85)340 for, viz.. $0.85 : hence, there will be as many $400 dollars of cost, as .85 is contained times in what the goods brought. Rule. — Divide the amount received by 1 plus the per cent when, there is a gain, and by 1 minus the per cent when there is a loss, and the quotient loill be the cost. EXAMPLES. 1. I sold a parcel of goods for $195,50, on which I made 15 per cent : what did they cost me ? 2. Sold 78cwt. dqr. 14//;. of sugar, at 8 cents a pound, and gained 15 per cent : how much did the whole cost ? 3. A merchant having a lot of flour, asked 33^ per cent more than it cost him, but was obliged to sell it 12^ per cent less than his asking price ; he received for the flour, §7.015 a barrel : what did it cost him ? 4. A dealer sold two horses for $472,50 each, and gained on one 35 per cent, but lost 10 per cent on the other : what was the cost of each, and what was his gain ? 2-17. To find the selling price of an article so os to gain or lose a certain per cent. 1. A grocer bought 12 barrels of sugar, for which he paid §18,50 a barrel : what must he sell it for to yield him a profit of 15 per cent ? Analysis. — Since the amomit f »r which operation. the sugar is to be sold exceeds its cost by $18,50 X 12 = $222 15 per cent., that amount added to the 15 per cent 33. .'JO cost will give what it mu&t be sold for. Ans. $255.30 When tliere i.s a loss, subtract. PKOFIT AND LOSS. 255 Rule. — Add the iwrcentage to the cost, token there is a gain, and subtract it ivhen there is a loss. EXAMPLES. 1. A farmer sells 375 bushels of corn for 75 cents a bushel ; the purchaser sells it at an advance of 20 per cent : how much a busliel did he receive for the corn ? 2. A merchant buj's a pipe of wine, for which he pays $322,5G, and he wishes to sell it at an advance of 25 per cent : what must he sell it for per gallon ? 3. A man bought 3275 bushels of wheat, for which he paid S3493,33l, but finding it damaged, is willing to lose 10 per cent. : what must he sell it for per bushel ? 4. If a merchant in selling cloth at $4,70 a yard, loses G per cent, on its cost, for how much must he sell it to gain 14 per cent. ? 5. If I purchase two lots of land for $150,25 each, and sell one for 40 per cent, more than it cost, and the other for 28 per cent, less, Avhat is my gain on the two lots ? 6. Bought a cask of molasses containing 144 gallons, at 45 cents a gallon, 36 gallons of which leaked out : at what price per gallon must I sell the remainder to gain 10 per cent, on the cost ? 7. A person in Chicago bought 3500 bushels of wheat, at ^^ 1.20 a bushel : allowing 5 per cent on the cost, for risk in transportation, 3 percent for freight, and 2 per cent commission for selling, what must it sell for per bushel in New York that he may realize 40 per cent net profit on the purchase ? 248. Given the gain or loss to find the iier cent. 1. Bought a quantity of goods for $200, and sold them for $170 : what per cent did I lose on the purchase ? 247. How do you find the selling price of an article so as to gain or loso a certain per cent 1 248. How do you find the percentage when you know the gain or loss ' 12 254 PEKCENTAGK, Analysis. — The gain or loss will opekation. be equal to the dilierence between S200-S170 === S30 the cost and the amount received $30 -^ $200 = .15. from the sale. If this difierence be Ans. 15 percent, divided by the cost, the quotient will denote the per cent on the cost • if it be divided by the amount of the sale, the quotient will denote the per cent on the sale. Rule. — Divide the gain or loss by the number on ivhich the 2)er cent is reckoned. EXAMPLES. 1. Bought ,1 quantity of goods for $348,50, and sold tho same for $425 : what per cent did I make on the amount I'eceived ? 2. Bought a piece of cotton goods for G cents a yard, and sold it for 71 cents a yard : what was my gain per cent ? 3. If I buy rye for 90 cents a bushel, and sell it for $1,20, and wheat for $1,12-^ a bushel, and sell it for $1,50 a bushel, upon which do I make the most per cent ? 4. If paper that cost $2 a ream, be sold for 18 cents a quire, what is gained per cent ? 5. How much per cent would be made upon a hogshead of sugar weighing Vdciut. 3qr. 14/6., that cost $8 per cwl, if sold at 10 cents per pound ? 6. A hardware merchant bought 45 T'. IGcwt. 25lb. of iron, at $75 per ton, and sold it for $78,50 per ton : what was his whole gain, and how much per cent did he make ? 7. If 25 per cent be gained on flour when sold at $10 a barrel, Avhat per cent would be gained when sold at $11, GO a barrel ? NoTK. — In this class of examples, first find the cost, as in Art. 240 : then find the gain, or loss, and then divide by the number on which the per cent is reckoned. 8. A lumber dealer sold 25G50 feet of lumber at $19,20 a thousand, and gained 20 per cent : how much would he have gained or lost had he sold it at $15 a thousand .'' INSURANCE. 255 9 A man sold his form for $3881,25, by which he gained 12^ per cent on its cost : what was its cost, and what would he have gained or lost per cent if he had sold it for $3277,50 ? 10. If a merchant sell tea at 66 cents a pound, and gain 20 per cent, how much would he gain per cent if he sold it at 77 cents a pound ? 11. Sold 5520 bushels of corn at 50 cents a bushel, and lost 8 per cent : how much per cent would have been gained had it been sold at 60 cents a bushel ? 12. A grocer bought 3 hogsheads of sugar, each weighing 14121 pounds ; he sold it at 11 cents a pound, and gained 37^ per cent : what was its cost, and for how much must he sell it to gain 50 per cent on the cost ? INSURANCE. 249. Insurance is an agreement, generally in writing, by which individuals or companies bind themselves to exempt the owners of certain property, such as ships, goods, houses, &;c., from loss or hazard. The Policy is the written agreement made by the parties. 250. The Base of insurance is the value of the property in- sured. 251. Premiuji is the amount paid by him who owns the property to those who insure it, as a compensation for their risk. The premium is generally so much jjer cent on the pro- perty insured. 252. There are four cases which may arise in questions of Insurance. The principles on which these cases depend have already been considered, and reference is made to the articles. 249. What is insurance 1 What is a policy 1 250. What is the base of insurance 1 251. What is a premium 1 352. How many cases are there which arise in insurance 1 What are tliey 1 256 I'EKCKNTAGE. 1. To find the Premium (Art. 216). 2. To find the Rate (Art. 217). 3. To find the ba.se, or sum insured (Art. 218). 4. To insure on both the base and premium. 253. To find the 2^'remiurii : 1. What would be the premium on a cargo of goods, valued at $39854, the insurance being made at 41- per cent? OPERATION. Analysis. — This is simply a case of finding 39854 the percentage when the base and rate are given .045 (Art. 216). $1793,430 EXAMPLES. 1. What would be the premium for insuring a ship and cargo, valued at $147674, at 31 per cent ? 2. What would be the insurance on a ship, valued at S47520 at ^ per cent ? At i per cent ? ' 3. What would be the insurance on a house, valued at Si 6800, at 1^ per cent ? At |- per cent ? 4. A merchant owns |- of f of a ship, valued at $24000, and in- sures Iiis interest at 2^ per cent : what does he pay for his policy ? 5. WJiat will it cost to insure a store worth $5640, at ^ per cent, and the stock Avorth $7560, at -| per cent? 6. A carriage maker shipped 15 carriages worth $425 each : what must he pay to obtain an insurance upon them at 75 cents on a hundred dollars ? 7. A merchant imported liJOIihd. of molasses, at 35 cents a gallon : he gets it insured for 31 per cent on the selling price of 50 cents a gallon : if the whole should be destroyed, and he get the amount of insurance, how much would he gain ? 8. If I get my house and furniture, valued at $3640, insured at 4^ per cent, what would be my actual loss if they were de- stroyed ? 253. How (3o you find the premium 1 LIFE INSUliAK(!K. 257 9. The ship Astoria is vahied at $20450, and her cargo at $25 GOO ; being bound on a voyage from New York to Canton, insured $12000 on the vessel, at the St. Nicholas Office, at 2|- per cent, and $18500 on the cargo, at the Howard Office, at 3^ per cent : if the vessel founder at sea, what will be the loss to the owner ? 10. Sliipped from New York to the Crimea 5000 barrels of flour worth $10,50 a barrel. The premium paid was $2887,50 : what was the rate per cent, of the insurance ? 11. Paid $120 for insurance on my dwelling, valued at $7500 : what was the rate per cent. ? 12. A merchant imported 225 pieces of broadcloth, each piece containing 40 yards, at $3,50 a yard : he paid $1323 for insurance : what was the rate per cent. ? 13. A merchant paid $1320 insurance on his vessel and cargo, which was 51 per cent on the amount insured : how much did he insure ? 14. A man pays $51 a year for insurance on his storehouse, at IJ- per cent, and $126,45 on the contents, at 2i per cent: what amount of property does he get insured ? 15. A person shipped 15 pianos, valued at $275 each. He insures them at 3 per cent, and also insures the premium at tho same rate : what insurance must he pay ? 16. A store and its contents are valued at $16750. The owner insures them at If per cent., and then insures the premium at the same rate : what amount of insurance must he pay ? LIFE INSURANCE. 254. Insurance for a term of years, or for the entire con- tinuance of life, is a contract on the part of an authorized asso- ciation to pay a certain sum, specified in the policy of insurance, on the happening of an e^ent named therein, and for which the association receives a certain premium, generally in the form of an annual payment. '2CA. What is a life insurance '■ VA 258 PEKCENTAGB. 255t To enable the company to fix their premiums at such rates as shall be both fair to the insured and safe to the asso- ciation, they must know the average duration of life from any given time to its probable close. This average is called the " Expectation of Life," and is determined by collecting from many sources the most authentic information in regard to the averwje duration of life from any period named. If we take 100 infants, some will die in infancy, some in childhood, and some in old age. It has been found, from care- ful observation, that if the sum of their ages, after the last shall have died, be divided by 100, the quotient will be 38.72 very nearly : hence 38.72 is said to be the " Expectation of Life" at infancy. The Carlisle Tables, which are used in this country and England, show the " Expectation of Life" from 1 to 100 years. At 10 years old it is found to be 48.82 ; at 20, 41. 4G; at 30, it is 34.34; at 40, 27.G1; at 50, it is 21.11; at GO, 14 years; at 70, 9.19; at 80, O.ol ; at 90, 3.28, and at 100, it is 2.28 years. 2.56. From the above facts, and the value of money (winch is shown by the rate of interest), a comjiany can calculate with great exactness the amount Avhich they should receive annually, for an insurance on a life for any number of years, or during its entire continuance. Among the principal life insurance companies in the United States, are the New York Life Lisurance and Trust Company, the Girard Life Lisurance, Annuity and Trust Company of Philadelphia, and the Massachusetts Hospital Life Insui-ance and Trust Company of Boston. The rates of insurance, iu these companies, differ but little. The PKEMiUM for life insurance is generally at so much per annum on $100 ; and is always paid in advance. 2.5.'). What is ncccsKary to enable a company to fix their preiniiun.s \ How is tlie expectation determined ! What do you understand by tha ex|)cctation of life 1 !J.OG What may be calculated from the necessary facts 1 LIFE INSURANCE. 259 EXAMPLES. 1. A person, 20 years of age, finds that tlie premium, pei afiiuim, is $1.36 on $100 : what must he pay to insure his lift for 1 year for $8950 ? 2. A man, aged 40 years, wishes to insure his life for 5 years, and finds that the annual rate is $1.8G for $100 : how much premium must he pay per annum on -£^12500 ? 3. A person, 38 years of age, obtains an insurance on lii.- life for 5 years, at the rate of ^1,75 per annum on %100 : how mucli is the annual premium on $15000? 4 A. person going to Europe, expecting to return in 2 years, effects an insurance on liis life at ^ of 4 per cent, premium on $100 ; he insures for $5000 : what is the annual premium ? 5. What will be the annual premium for insuring a person's life, who is 60 years of age, for ^2000, at the rate of •'i;4,91 on $100 ? 6. A person, at the age of 50 years, obtained an insurance at 4| per cent, per annum on each $100 ; he insured for $1500, and died at the age of 70. How mucli more was the insurance than tlie payments, without reckoning interest ? 7. A gentleman, 47 years of age, going to China as ambassa- dor, obtains an insurance on his life for $10000, by paying a premium of $2.71 })er annum on every $100, and dies at the middle of the third year : reckoning simple interest on his pay- ments at 7 per cent, wliat is gained by the insurance ? ENDOWMENTS. 257. An Exdoavmext is a certain sum to be paid at the ex])iration of a given time, in case the person on whose life it is taken shall live till the expiration of the time named. » 2.57. What is an endowment 1 What does the table of endowments show ] What maj- be found from the table ". 200 PEIICKNTAOE. The following table shows the value of an endowment pur- chased for $100, at the several periods mentioned in the column of ages, the endowment to be paid if the person attains the age of 21 years. TABLE OF ENDOWMENTS. . „_ Sums to be paid '^"''- afil, if alive. Age. Sura to be paid at 21, if alive. Age. Sum to be paid at 21, if alivo. Birth, - - 3376,84 5 years, - $210,53 13 years, - S144.12 3 months, - 344,28 6 " 198,83 14' '' 137.86 6 " - 331,46 7 " - 188,83 15 " 131,83 9 «' - 318,90 8 " 179,97 16 " - 125,97 1 year, - - 300,58 9 " 171,91 17 " - 120,31 2. " - - 271,03 10 " 164.46 18 " - 114,89 3 " - - 243,69 11 " 157,43 19 " 109,70 4 " - - 225,42 12 " - 150,64 20 " - 104,74 This table shows that if 8100 be paid at the birth of a child, he M'ill be entitled to receive 8376,84, if he lives to attain the age of 21 years. If 8100 be paid when he is ten years old, he will be entitled to receive 8164,46, if he lives to attain the a^-e of 21 years. And similarly for other ages. We can easily find by proportion IsL How much must be paid, at any age under 21, to pur- chase a given endowment at 21 ; and 2c?. What endowment a sum paid at any age under 21, will purchase ? EXAMPLES. 1. What endowment, at 21, can be purchased for $250, paid at the age of 10 years ? 2. What endowment, at 21, can be purchased for 8360, paid at tlie age of 5 years ? 3. If my child is 7 years old. and I purchase an endowment for 8650, what will he receive if he attains the age of 21 years? 4. If, at the birth of a daugliter, I purchase an endowment for 8350, what will she receive if she attaiii* the ago of 2] years *? ANNUITIES. 261 ANNUITIES. 258. An Annuity is a fixed sum of money to be paid at T'^gular periods, either for a limited time, or forever, in con- rjderalion of a given sum paid in hand. The Present Value of an annuity is that sum which being put at compound interest would produce the sums necessary to l);iy the annuity. The j)urchaser of an annuity should jiay more than tlie com- pound interest ; for the seller cannot aiford to take the money' of the purchaser, invest it, re-invest the interest, and pay over the entire proceeds. Knowing the rate of interest on money, and the present value of an annuity, a close estimate may be made of the price it ought to sell for. TABLE Shoiving the peesent value of an annuity of %l, from 1 to 30 years, at different rates of iriterct!. Years. 5 per cent. G per cent. Vear.s. 5 per cent. G per cent. -1 0.95-2381 0.943396 16 10.837770 10.105895 1.859410 1.833393 17 11.274066 10.477260 3 2.723X148 2.673012 18 11.689587 10.827603 i 4 3.545950 3.465106 19 12085321 11.1.58116 5 4.329477 4,212364 20 12.462216 11.469921 6 5 075G92 4.917324 21 12,821153 11.764077 7 5.786373 5.582381 22 13.163003 12-041582 8 6.463213 6.209794 23 13488574 12.303379 9 7.107823 6.801692 24 13.798642 12.550.358 10 7.721735 7.360087 25 14.093945 12 783356 11 8.306414 7.886875 26 14.375185 13.003166 12 8.86.3252 8. .388844 27 14 643034 13.210.5.34 13 9393573 8.852683 28 14.898127 13 406164 14 9 898641 9.2949S4 29 15.141074 13.590721 15 10.3796,58 9.712249 30 15 372451 13.764831 To find the present value of an annuity for any rate, and for any time, we simply multiply the present value of an annuity 2.58. What is an annuity! What is the present value of an annuity ! How do you find the present value of an annuity for a given rate and time 1 How do you find what annuity a given sum will produce, at a given rate and for a given time ? 262 PKRCENTAGE. of SI for the same rate and time, bj the annuity, and the pro- duct will be its present value. Thus, the present value of an annuity of $600 for 8 years, at G per cent, is $6.209794 X 600 = 83725.8764 ; that is, pres. val. of $1 X annuity = pres. vaL, hence, pres. val. ,, n annuity = ^ ; ; therefore, pres. val. of §1 I. To find what sum will produce a certain annuity at a given rate, and for a given time. Multiply the present value of an annuity of %1, at the given rate and for the given time, hy the given annuity ; the product will he that sum. II. To find what annuity a given sum will produce at a given rate and for a given time. Divide the given sum, or present value hy the present value of $1, for the given rate and time, and the quotient ivill be the annuity. EXAMPLES. 1. What is the present value of an annuity of $550, at 5 per cent, for 21 years? 2. What would be the value of an annuity that should yield eight hundred and thirty-five dollars a year for sixteen years, the interest being compound, and at the rate of 5 per cent, per annum ? 3. What is the present value of an annuity of $1500 a year, for 30 years, the compound interest being reckoned at 5 per cent. ? 4. For what sum could Mr. Jones purchase an annuity for twenty-eiglit years, of twelve hundred and twenty dollars, the compound interest being reckoned at 6 per cent.? 5. What annuity, for twenty-four years, could be purchased for tlie sum of twenty-seven thousand iivc luiiulred and sixty dollars, the compound i-nt crest being reckoned at 6 per cent. ? ASSESSING TAXES. 263 6. Mr. Jones having a small fortune of S25000, and calcula- ting tli;it he will live about 20 years, purchases an annuity at six per cent., with nn agi-eement that he would pay 1)20 a year to an invalid sister : what was his annual income from the investment, after making that payment? ASSESSING TAXES. 259. A Tax is a certain sum required to be paid by the in- habitants of a town, county, or state, for the support of govern- ment. It is generally collected from each individual, in propor- tion to the amount of his property. In some states, however, every white male citizen over the age of twenty-one years, is required to pay a certain tax. This tax is called a poll-tax ; and each person so taxed is called a poll. 2G0. In assessing taxes, the first thing to be done is to make a complete inventory of all the property in the town, on which the tax is to be laid. If there is a poll-tax, make a full list of the polls and multiply the number by the tax on each poll, and subtract the product from the whole tax to be raised by the town ; the remainder will be the amount to be raised on the properry. Having done this, divide the %ohoh tax to he raised by the amount of taxable jjroperty, and the quotient will be the tax on $1. Then multiply this quotient by the inventory of each individual, and the product will be the tax on his property. EXAMPLES. 1. A certain town is to be taxed $4280 ; the property on which the tax is to be levied is valued at $1000000. Now there are 200 polls, each taxed $1,40. The property of A is Valued at $2800, and he pays 4 polls, 259. What is tax ] How is it generally collected 1 What is a poll-tax ? 2G0. What is the first thing to be done in assessing a tax 1 If there is a poll-tax, how do you find the amount 1 How then do you find the per cent of tax to be levied on a dollar I How do you find the tax to be raised on each individual I 264 PERCENTAGE. B's at $2400, pays 4 polls, C's at $2530, pays 2 D's at $2250, pays 6 u E's at $7242, pays 4 polls, F's at $1651, pays 6 " G's at $1600,80, pays 4 « What will be the tax on one dollar, and what will be A's tax, and also, that of each on the list ? First, $1,40 X 200 = $280, amount of poll-tax. $4280 — $280 = $4000, amount to be levied on property. Then, $4000 -^ $1000000 = 4 mills on $1. Now, to find the tax of each, as A's, for example, A's inventory, $2800 ,004 11,20 5,60 4 polls, at $1,40 each, - A's whole tax, _ - - $16,80 In the same manner, the tax of each person in the township may be found. ASSESSMENT TABLE. 261. Having found the per cent, or the amount to be raised on each dollar, form a table showing the amount which certain sums Mould produce at the same rate per cent. Thus, after having found, as in the last example, that four mills are to be raised on every dollar, we can, by multiplying in succession by the numbers 1, 2, 3, 4, 5, 6, 7, 8, &c., form the following TABLE. $ $ $ $ $ « 1 gives 0,004 20 gives 0,080 300 gives 1,200 | 2 •• O.OOS 30 " 0,120 400 ' 1 .600 3 • 0,012 40 " 0,100 500 ' 2,000 4 •' 0.016 50 " 0,200 600 ' 2,t()() 5 " O.O'^O 60 " 0.210 700 ' 2,800 6 " 0.024 70 " 0,280 800 ' 3.200 7 " 0.028 80 " 0,320 900 ' 3,600 9 " 0.0:12 90 " 0,3()0 1000 ' 4.000 <) " 0,():!0 100 " 0,400 20110 • 8.000 10 " 0.040 200 " O.MOO 3000 ' 12,000 2G1. How do you form tlio Assessment table 1 ASSESSING TAXES. 265 This table shows the amount to be raised on each sum in the cohimns under $'s. Note. — If you wish ilie tax on a sum not named in the Table, as $25, it is equal to the sum of the taxes on $20 and So : and similarly for other numbers. 1. To find the amount of B's tax from this table. B's tax on $2000, is - - $8,000 B's lax on 400, is - - 1,000 B's tax on 4 polls, at $1,40, - 5, GOO B's total tax is - - $15,200 2. To find the amount of C's tax from the table. C's tax on $2000, is - - $8,000 C's tax on 500, is - - 2,000 C's tax on 30, is - - 120 C's tax on 2 polls, is - - 2,800 C's total tax is - - $12,920 In a similar manner, Ave might find the taxes to be paid by D, E, &c. EXAMPLES. 1. In a county embracing 350 polls, the amount of property on the tax list is $318200 ; the amount to be raised is as fol- lows : for state purposes, $14G5,50 ; for county purposes, $350,25; and for town purposes, $200,25. By a vote of the county, a tax is levied on each poll of ^1,50 : hovi^ much per cent will be laid upon the property ? 2. In a county embracing a population of 98415 persons, a tax is levied for town, county, and state purposes, amounting to S100406. Of this sum, a part is to be raised by a tax of 25 cents on eacli poll, and the remainder by a tax of two mills on the dollar : what was the amount of property on the tax list ? 3. In a county embracing a popuhuion of 5G450 persons, a tax is levied for town, county, and state purposes, amounting to 887467 : the pergonal and real estate is valued at S4890300. Each poll is taxed 25 cents : what per cent is the tax, and how 266 PEKOENTAGE. much will a man's tax be, who pays foi- 5 polls, and whose px-o- perty is valued at. $5400 ? Yy''hat is B's lux, who was assessed for 2 polls, and whose j)rpperty was valued at ^3760,50 ? 4. A banking corporation, consisting of 40 persons, was taxed $957.p0 ; their property was valued at §125000, and each poll was assessed 50 cents each : what per cent was their tax, and what was a man's tax, who paid for 1 poll, and whose share was assessed for $2000 ? 5. What sum must be assessed to raise a net amount of $5674,50, allowing 2^ per cent commission on the money col- lected (Art. 218) ? 6. Allowing 4 per cent, for collection, what sum must be assessed to raise $21346,75 net ? 7. In a certain township, it becomes necessary to levy a tax of 14423,2475, to build a public hall. The taxable property is valued at $916210. and the town contains 150 polls, which are each assessed 50 cents. "What amount of tax must be raised to build the hall, and pay 5 per cent, for collection, and what is the tax on a dollar ? What is a person's tax who pays for 3 polls, and whose per- sonal property is valued at $2100, and his real estate at $3000 ? What is G s tax, who is assessed for 1 poll, and $1275,50 ? What is li's tax, who is assessed for 1 i)oll, and $2456 ? 8. The people of a school district wish to build a new schoo. house, which shall co-^^t ^2850. The taxable ])roperty of tin- district is valued at $190000 : Avhat will be the tax on a dollar, and what will be a man's tax, whose property is valued at $7500 ? How much is IMr. Merchant's tax, whose personal and real estate are assessed for $1200 ? 9. In a school district, a school is supported by a rate-bill. A teacher is employed for 6 months, at $60 a month ; the fuel and other contingoucies amount to $66. They drew $41,60 public money, and the whole number of days attendance was 7688: what was D's tax, who sent 148 days? AVhat was F's tax, wlio sent 184.V days? CUSTOM HOUSE BUSINESS. 2G7 CUSTOM HOUSE BUSINESS. 259. Persons who bring goods, or merchandise, into the United States, from foreign countries, are required to land them at particular places or ports, called Ports of Entry, and to pay a certain amount on their value, called a Duty. This duty is imposed by the General Government, and must be the game on the same articles of merchandise, in every part of the United States. Besides the duties on merchandise, vessels employed in com- merce are required, by law, to pay certain sums for the privilege of entering the ports. These sums are large or small, in pro- portion to the size or tonnage of vessels. The moneys arising from duties and tonnage, are called revenues. 260. The revenues of the country are under the general direction of the Secretary of the Treasury, and to secure tlieir faithful collection, the government has appointed various othcera at each port of entry or place where goods may be landed. 261. The office established by the government at any port of entry, is called a Custom House, and the officers attached to it are called Custom House Officers. 262. All duties levied by law on goods imported into the United States, are collected at the various custom houses, and are of two kin,ds — Specific and Ad valorem. Specific Duty is a certain sum on a particular kind of goods named ; as so much per square yard on cotton or woollen cloths, so much per ton weight on iron, or so much per gallon on molasses. 259. What is a port of entry ? What is a duty ? By wliom are duties imposed ? What charges are vessels required to pay ! What arc the moneys arising from duties and tonnage called 1 260. Under whose direction are the revenues of the country 1 261. What is a custom house \ What are the officers attached to it called 1 262. Where are the duties collected ! How many kinds are there, and what are they called 1 What is a specific dutyl An ad valorem dutyl 268 PERCENTAGE. Ad valorem Duty is such a per cent on the actual cost of the goods in the country from which they are imported. Thus, an ad valoi-em duty of 15 per cent on Enghsh cloths, is a duty of 15 per cent on the cost of cloths imported from England. 263. The laws of Congress provide, that the cargoes of all TC-ssels freighted with foreign goods or merchandise, shall be weighed or gauged by the custom house officers at the port to ■vs'hich they are consigned. As duties are only to be paid on the articles, and not on the boxes, casks, and bags which contain them, certain deductions are made from the weights and mea- sures, called Allowances. Gross Weight is the whole weight of the goods, together with that of the hogshead, barrel, box, bag, &c., wliich contains them. Net Weight is what remains after all deductions are made. Draft is an allowance from the gross weight on account of waste, where thei'e is not actual tare. lb. lb. On 112 it is 1, From 112 to 224 " 2, " 224 to 336 " 3, « 33G to 1120 " 4, « 1120 to 2016 '' 7, Above 2016 any weight " 9, consequently, 9//;. is the greatest draft generally allowed. Tare is an allowance made for the weight of the boxes, bar- rels, or bags containing the commodity, and is of three kinds, 1st. Legal tare, or such as is established by law; 2d. Cus- tomary tare, or such as is established by the custom among merchants ; and 3d. Actual tare, or such as is found by re- 203. Wliat do tlie laws of Coniiress direct in relation to forciirn rroods 1 Why arc deductions made from their weight ? Wiiat are these dcductioiia called? Wiiat is gross \vci;i;ht ? What is net weight ! "\\'hat is draft ' What is the greatest draft allowed ! What is tare? What arc the dill'er eiit kinds of tare 1 AVUat allowances are made on lic^uors 1 CUSTOM HOUSE BUSINESS. 269 moving the goods and actually wcigliing the boxes or casks in which they are contained. On liquors in casks, customary tare is sometimes allowed on the supposition that the cask is not full, or what is called its actual ivants ; and then an allowance of 5 per cent for leakage. A tare of 10 per cent is allowed on porter, ale, and beer, in bottles, on account of breakage, and 5 per cent on all other liquors in bottles. At the custom house, bottles of the common size are estimated to contain 2|- gallons the dozen. For tables of Tare and Duty, see Ogden on the Tarift'of 1842. EXAMPLES. 1. What is the net weight of 25 hogsheads of sugar, the gross weight being 66c«'i. ^qr. lUb. ; tare lllb. per hogshead? civt, qr. lb. 66 3 14 gross. 25 X 11 = 275/6. - - 2 3 tare. Ans.M 14 net. 2. If the tare be Alb. per hundred, what will be the tare en QT. 2cwt. 3qr. Ulb. ? Tare for QT. or UOcwf. = ASOlb. 2cwt. z= 8 Sqr. = 3 Ulb. = 0^ Tare - - jM^Ib. 3. What will be the cost of 3 hogsheads of tobacco at $9,47 per cwt. net, the'gross weight and tare being of ctvt. qr. lb. lb. No. 1 - - 9 3 24 - - tare 146 « 2 - - 10 2 12 - - " 150 " 3 - - 11 1 24 - - « 158 4. At 21 cents per lb., what will be the cost of 5hkd. of coffee, the tare and gross weight being as follows : 570 1'! 1 i£Ci ■;]SiTAGK. cwl. qr. /<;-. lb. No. 1 ■ ■ - 6 2 14 - - tare 94 « 2 - ■ - 9 1 20 - - " 100 " 3 ■ ■ - G 2 22 - - " 88 " > ■ • - 7 2 24 - - " 89 " *5 - • - 8 13 - " 100 5. What is the net weight of IShhcL of tobacco, each weigh- ing gross Sctvf. dqr. 1Mb.', tare 16/6. to the cwt."? G. In 47'. Zciol. Zqr. gross, tare 20/i. to the cwt., Avhat is the net weight ? 7. What is the net weight and value of 80 kegs of figs, gross weight IT. Wcict. 3q}:, tax*e 12/6. per cwt., at $2,31 per civi. 8. A merchant bought Idcwt. Iqr. 24/6. gross of tobacco in leaf, at $24,28 per cwl.; and 12ca'L 3qr. 19/6. gross in rolls, at $28,56 per cwt. ; the tare of the former Avas 149/6., and of the latter 49/6. : what did the tobacco cost him net ? 9. A grocer bought 17^^h/id. of sugar, each lOart. Iqr. 14/6., draft 7/6. per civ/., tare 4/6. per cwt. What is the value at $7,50 per art. net? 10. In 29 parcels, each weighing Sctvt. oqr. 14/6. gross, draft 8/6. per cwt., tare 4:'6. per cwt. how much net weiglit, and what is the value at $7,50 per cwt. net ? 11. A merchant bought 7 hogsheads of molasses, each Aveigh- ing 4rwf. 'dqr. HI/), gross, draft 7/6. per cwt., tare 8/6. per hogshead, and damage in the whole 99|-/6. : what is the value at $8,45 per cwt. net ? 12. Tlie net value of a hogshead of Barbadoos sugar was $22,50; the custom and fees $12,49, freight $5,11, factorage $1,31 ; the gross weight was llcwf. Iqr. 15/6., tare ll]-/6. per cirf. : what was the sugar rated at per cwt. net, in the bill of parcels ? 13. In 7h/id. of .sugar, each weighing 3cwt. 2qr. 14/6. gross, tare 21/6. per cwt., what is the value at $6,25 per ca-t. ? CUST'>^odiicts, and multiply it by the inter- est for 1 day : the result will be the interest balance, which is to he added to the side having the greater sum. III. Then find the cash balance. Notes. — 1 . If the cash balance had been required on any day after the 25th of April, the mode of proceeding would have been exactly the same. 2. In the examples the rate of interest will be taken at 7 per cent, and 360 days in the year. 3. After the balance of interest is found, the cash balance is ob- tained, by adding the two sides of the account, taking the difference of the sums and placing it on the s/naller side of the account. 4. If the cash balance is settled by a note, interest shoukl run ci the note from the date of the cash balance to the time of payment. 5. Let the pupil find the interest and cash balance in each of th" following examples. 278' EQUATION' OF PAYMENTS. 2. What is the balance of interest and what the cash balance on the following account on Marcli 20th ? Dr. S. JOHXSON. Or. 856. Jan. 1, To merch. $500 ' Jan. 5, By cash, $350 ■• 16, '' cash, 450 •' 19, " merch. 780 Feb. 5, " merch. 680 " 25, '• " 250 >• 24, " " 300 Feb. 15, " cash, 600 Mar. 1, " cash, 150 cash balance, 700,65 " 16, •'•' merch. 600 $2680,65 Interest balance, ,65 12680,65 Note. — 1. When the items have the same or different times of credit allowed, find when, the items are payable and then proceed as before. 2. If the cash balance is required on a day previous to the latest date of the items, find the ca.sh balance for this latest date : then find the present value for the given date : this will be the cash balance. 3. Allowing a credit of six months on each item, what is the interest and cash balance Feb. 1st, 1856 ? R. Sherman. Cr. Feb'y 6, By merch. $800 i\Iar. 7, " " 900 interest bal. 45,48 $2150 cash bal. 404,52 2150.00 4. Allowing a credit of 3 months on each of the items of the following account, what would be the interest and cash balance on October 31st, 1856. Dr. R. Rivers. ' Or. Dr. 1855. July 1st, To merch., $750 " 17th, " " 600 " 25lh, " " 800 1856. May 1, To merch. $500 " 20, " 675 Jun. 6, To cash, 350 July 9; merch. 175 cash balance, 620 ,70 $232o7n) May 6th, By cash, $400 25th. mer. 620 900 July 20th, '■'■ mer. 400 interest balance, .70 June 16th, " cash, c ALLIGATION. 275 ALLIGATION. 265. Alligation is that branch of Arithmetic which treats of all questions relating to the mixing or compounding of two or more ingredients of different values. It is divided into two parts : Alligation Medial and Alligation Alternate. ALLIGATION MEDIAL. 266. Alligation Medial teaches the method of findins; the price or quality of a mixture of several simple ingredients whose prices or qualities are known. 1. A grocer would mix 200 pounds of lump sugar, Avorth 13 cents a pound, 400 pounds of Havana, worth 10 cents a pound, and GOO New Orleans, worth 7 cents a pound ; what should be the price of the mixture ? OPERATION. Analysis. — The quantity, 200/6., 200 x 13 = 26.00 at 13 cents a pound, cost.s $26 ; 400 400 x 10 = 40.00 pounds, at 10 cents a pound, costs 600 x 7 = 42.00 $40 ; and 600/6. at 7 cents a pound, 1200 ) 108,00(9 cts. costs $42 : hence, the entire mix- ture, consisting of 1200/6., costs $108. Now, the price of the mixture will be as many cents as 1200 is contained times in 10800 cents : viz., 9 times. Hence, to find the price of the mixture. Rule. — Multipli/ the inice or quality of a unit of each simple hy the number of such units : take the sum of their products and divide it by the ivhole number of units : the quotient will be the price or quality of a miit of the mixture. EXAMPLES. 1. If 1 gallon of molasses, at 75 cents, and 3 gallons, at 50 cents, be mixed with 2 gallons, at 37|^, what is the mixture worth a gallon ? 265. What is Alligation 1 Into how many parts is it divided 1 What are they 1 266 What is Alligation Medial \ IIow do you find the prict- of the mixture 1 276 ALLIGATION. 2. If teas at 371, 50, 62i, 80, and 100 cents per pound, be mixed together, what ay ill be the value of a pound of the mixture ? 3. If 5 gallons of alcohol, worth GO cents a gallon, and 3 gallons worth 96 cents a gallon, be diluted by 4 gallons of water, what will be the price of one gallon of the mixture ? 4. A farmer sold 50 bushels of wheat at $2 a bushel ; GO bushels of rye, at 90 cents; 36 bushels of corn, at G2i cents; and 50 bushels of oats, at 39 cents a bushel : what was the average price per bushel of the whole ? 5. During the seven days of the week, the thermometer stood as follows : 70°, 73°, 731°, 77°, 70°, 801°, and 81° : what was the average temperature for the w^eek ? 6. If gold 18, 21, 17, 19, and 20 carats fine, be melted to- gether, what will be the fineness of the compound ? 7. A grocer bought 3Alb. of sugar at 5 cents a pound, 1021b. at 8 cents, lS6lb. at 10 cents a pound, and 34/6. at 12 cents a pound. He mixed it together, and sold the mixture so as to make 50 per cent on the cost: what did he sell it for per pound ? 8. A merchant sold 8//;. of tea, 11^5. of coifee, and 25lb. of sugar, at an average of 15 cents a pound. The tea was worth 30 cents a pound ; the coffee, 25 cents a pound ; and the sugar, 7 cents a pound : did he gain or lose, and how much ? ALLIGATION ALTERNATE. 267. Alligation Alternate teaches the method of finding wliat proportion of several simples, whose prices or qualities are known, must be taken to form a mixture of any required price or quality. It is the reverse of Alligation Medial, and may be proved by it. 267. What is Alligation Alternate 1 How may Alligation Alternate b« proved ! 2G8. How do you find the proportional parts 1 ALTERNATE. 277 CASE I. 268. To find the 2'n'02'>ortional 2^0 fts. 1. A miller Avould mix wheat, worth 12 shillings a bushel; corn, worth 8 shillings ; and oats, worth 5 shillings, so as to make a mixture worth 7 shillings a bushel : what are the propor- tional parts of each ? OPERATION. oats, 75. 5 s.-. 8,s'.J corn, wheat, 12s, A. B. c. D. 2^ i 5 1 2 J r, 2 E. 6 or 2 " 9 a Analysis. — On every bushel put into the mixture, whose price is less than the mean price, there will be a gain; on every bushel whose price is greater than the mean price, there will be a loss ; and since there is to be neither gain nor loss by the mixture, the gains and losses must balance each other. A bushel of oats, when put into the mixture, will bring 7 shillings, giving a gain of 2 shillings; and to gain 1 shilling, we mast take half as much, or |- a bushel, which we write in column A. On 1 bushel of wheat there will be a loss of 5 shillings ; and to make a loss of 1 shilling, W"c must take -^ of a bushel, which we write in column A : \ and -J- are called proportional numbers. Again : comparing the oats and corn, there is a gain of 2 shillings on every bushel of oats, and a loss of 1 shilling on every bushel of corn : to gain 1 shilling on the oats, and lose 1 shilling on the corn, we must take \ a bushel of the oats, and 1 bushel of the corn : these numbers are written in column B. Two simples, thus compared, are called a couplet : in one. the price of unity is less than the mean price, and in the other it is greater. If, every time we take i a bushel of oats we take -g- of a bushel of W'heat, the gain and loss will balance ; and if every time we take i a bushel of oats we take 1 bushel of corn, the gain and loss will balance : hence, if the proportional numbers of a couplet be multiplied bv any number^ the gain and loss denoted by the products xcill balance. When the proportional numbers, in any column, are fractional (as in columns A and B), multiply them by the least common mul- tiple of their denominators, and write the products in new cohimns C and D. Then, add the numbers in columns C and D, standing opposite each simple, and if their sums have a common factor, reject it: the last result will be the jiro; urtional luunbers. l:{ 278 ALLIGATION. Note. — The answers to the last, and to all similar questions, will be infinite in number, for t-\TO reasons : 1st. If the proportional numbers in column E be multiplied by any number, integral or fraetional, the products will denote propor- tional parts of the simples. 2d. If the proportional numbers of aiiy covplct be multiplied by any number, the gain and loss in that couplet will still balance, and the proportional numbers in the final result will be clianged. Rule. — I. Write the prices or qualities of the simples in a column, beginning ivith the loivest, and the mean p>r ice or qualitij at the left. II. Opposite the first sim2)le write the part ichich must be taken to gain 1 i'oportional number. II. Multiply the given simple by the ratio tvhich its propor- tional number bears to each of the others, and the products will denote the quantitits to be taken of each. Note. — If we multiply the numbers in either or both of the columns C or D by any number, the proportion of the numbers in column E will be changed. Thus, if we multiply column D by 12, we shall have 60 and 12, and the numbers in column E become 66, 12 and 1, numbers which will fulfil the conditions of the question. EXAMPLES. 1. What quantity of teas at 12*-. \Qs. and Gv. must be mixed with 20 pounds, at 4s. a pound, to make the mixture worth Ss. a pound ? 2. How many pounds of sugar, at 7 cents and 11 cents a pound, must be mixed with 75 pounds, at 12 cents a pound, so that the mixture may be worth 10 cents a pound ? 269. How do you find the proportional parts when the quantity of one simple is ijivcii ! 280 ALLIGATION. 3. How many gcallons of oil, at 7s., 7s. Qd. and 9s. a gallon, mu>t be mixed v.itli 24 gallons of oil, at 9^-. Gd. a gallon, so as to form a mixture worth 8s. a gallon ? 4. Bought 10 knives at $2 each : how many must be bought at §1 each, that the average price of the whole shall be m? 0. A grocer mixed 50/^. of sugar worth 10 cents a pound, with sugars worth 9i cents, 7-i cents, 7 cents, and 5 cents a pound, and found the mixture to be worth 8 cents a pound : how much did he take of each kind ? CASE III. 270. When the quantity of the mixture is given. 1. A silversmith has four sorts of gold, viz., of 24 carats fine, of 22 carats fine, of 20 carats fine, and of 15 carats fine : he would make a mixture of 42 ounces of 17 carats fine : how much must he take of each sort ? OPERATION. 17 ^ A. B. C. D. E. F. G. H. "I'^nO 1 2 I 2 7 5 o 15 30 20J 1 2 2 4 22 ) 1 5 3 2 2 4 24— _y ] 7 2 2 4 Proportional Parts : 15 + 2 + 2 + 2 = 21; 42 -+21 = 2. Rule. — I. Find the proportional parts as in Case I. II. Divide the quantity of the mixture by the sum of the pro- portional jmrts, and the quotient will denote hoio many times each part is to be talceii. Multiply this quotient by the parts separately, and each 2>yoduct tvill denote the quantity of the cor- resjiondiiig simple. 270. How do you liiul ilir proportional i)arls wlieii llic iiiiaiitity of llif mixUirc is j^'ivcii 1 ALLIGATION. 281 Note. — We may, as in the other cases, multiply each couplet by any number we please, which will merely change the relation of the proportional parts, and consequently uivc diirerent proportions of the ingredients. Hence, there is an infinite number of answers^ if we employ fractions, and often many answers to similar questions, in whole numbers.* EXAMPLES. 1. A grocer has teas at 5s., Os., 8?., and Os. a pound, and wislies to make a compound of 88/i. worth 7^. a pound : how much of each sort must be taken ? 2. A liquor dealer wishes to fill a hogshead with water, and two kinds of brandy, at $2,50 and $3,00 per gallon, so that the mixture may be worth $2,25 a gallon : in what proportions must he mix them ? 3. A person sold a number of sheep, calves, and lambs, 40 in all, for $48 : how many did he sell of each, if he received for each calf $lf, each sheep 111, and each lamb If? 4. A merchant sold 20 stoves for 8180 ; for the largest size he received $19 each, for the middle size, $7, and for the small size %Q: how many did he sell of each kind ? 5. A vintner has wines at 45., 65., 8s., and IO5. per gallon > he wishes to make a mixture of 120 gallons, Avorth os. per gal- lon : what quantity must he take of each ? 6. A tailor has 24 garments, worth |;144. He has coats, pantaloons and vests, worth $12, $5 and $2 each, respectively : how many has he of each ? 7. A jeweler melted together four sorts of gold, of 24, 22, 20 and 15 carats fine, so as to produce a compound of 42o2'. of 17 carats fine : how much did he take of each sort ? 8. A man paid $70 to 3 men for 35 days labor : to the first lie paid |5 a day, to the second, $1 a day, and to the third, $^ a day : how many days did each labor ? * See an admirable article on Alhgation, published by Professor D, Wood, in the June number of the New ifork Teacher for 1855. B\' his permission, I have used such parts of it as seemed appropriate to a Text Book. 1:! 282 COIN'S AND CUEEEXCIES. COINS AND CURRENCIES. 271. Coins ai-e pieces of metal, of gold, silver, or copper, of fixed values, and impressed with a public stamp prescribed by the country where they are made. These are called specie, and are generally declared to be a legal tender in payment of debts. The Constitution of the United States provides, that gold and silver only, shall be a legal tender. The coins of a country, and those of foreign countries having a fixed value established by law, together with bank notes redeemable in specie, make up what is called the Currency. 272. A Foreign coin may be said to have four values : 1st. The intrinsic value, which is determined by the amount of pure metal which it contains : 2d. The Custom House or legal value, which is fixed by law : 3d. The mercantile value, which is the amount it will sell for in open market : 4th. The Exchange value, which is the value assigned to it in buying and selling bills of exchange between one country and another. Let us take, as an example, the English pound sterling, which is represented by the gold sovereign. Its intrinsic value, as determined at the Mint in Philadelphia, compared with our gold eagle, is $4,861. Its legal or custom house value is $4,84. Its commercial value, that is, what it will bring in Wall-street, New York, varies from $4,83 to $4,80, seldom reaching either the lowest or highest limit. The excliange value of the Eng- lish pound, is $4,44|-, and was the legal value before the change in our standard. This change raised the legal value of the pound to $4,84, but merchants and dealers in exchange pre- ferred to retain the old value, which became nominal, and to add the difference in the form of a iiremium on excInnujCy which is cx]ilained in Art. •287. For the values of the various coins, see Table, page 3'Jl. 271. Wliat are loce divi- ded by its equivalent at the third, and so on to the last place. EXAMPLES. 1. A merchant wishes to remit $4888,40 from New York to London, and the exchange is at a premium of 10 per cent. He finds that he can remit to Paris at 5 francs 15 centimes to the dollar, and to Hamburg at 35 cents per marc banco. Now, the exchange between Paris and London is 25 francs 80 centimes for £1 sterling, and between Hamburg and London 13|- marcs banco for £1 sterling. How had he better remit ? 1st. To London direct. The amount to be remitted is $4888,40, The exchange value of £1 is $4,444, and since the exchange is at a premium of 10 per cent, the value of £1 is $4,444 + ,4444 r= $4,8884 : hence, $4888,40 X T.sVsT = ^1000 : hence, if he remits direct he will obtain a bill for £1000. 2d. Exchange through Paris. 1.03 4888,40 X ^ X j^ ^ £975,7852 = £975 15s. 8}d. 5.16 Analysis. — Since 5.15 francs are equal to 1 dollar, the first mul- tiplier will be this amount divided by $1 ; and since £l is equal to 25.80 francs, the second multiplier will be £^1 divided by this amount. Then, by dividing by 5 and multiplying, we find that the amount remitted by the second method would be worth, at London, £^975 t5s. S^^. 3d. Exchange through Hamburg. $4888,40 X .3J3 X 13^.^5 =^1015.771 = £1015 15s. 5d. Analysis. — Since 1 marc banco is equal to 35 cents, it is 35 hun- dredths of a dollar : hence, the first multiplier is 1 marc banco 294 ARBITRATION OF EXCHANGE. divided by .35, and the second, 1 divided by 13.75. By tlii.s course of exchange the remittance at London would be worth £1015 1 5s. 5d. Hence, the best way to remit is through Hamburg, then direct, and the least advantageous, through Paris. 2. A merchant in London has sold goods in Amsterdam to the amount of 824 pounds Flemish, which could be remitted to London at the rate of 34s. 4rf. Flemish per pound sterling. He orders it to be remitted circuitously at the following rates, viz. : to France at the rate of 48(/. Flemi.sh per crown ; thence to Vienna at 100 crowns for 60 ducats ; thence to Hamburg at lOOd. Flemish per ducat ; thence to Lisbon at 50c/. Flemish per crusado of 400 reas ; and lastly, from Lisbon to England at 5.y. 8'J. per milrea : does he gain or lose by the circular exchange ? 48(/. Flemish = 1 crown, 100 crowns = GO ducats, 1 ducat =: 100(7. Flemish, 50d. Flemish = 400 reas, 1 milrea or 1000 reas = G8d. sterlinjr. o~- *o- a:0 $ 17 1 00 100 00 ^$ 824x17 14008 ^$ i00 1 00 1000 ~ 25 ~ 25 $ m 25 = £560 6s. 4frf. The direct exchange would give, 82i X ^-i j:^. — = 824 X If"- = £480 sterhng. 34s. 4c?. Flemish '^ ** ° Hence, the amount gained by circuitous exchange wouliJ b" £80 6s. |rf. GENERAL AVEKAGE. 295 GENERAL AVERAGE. 295. Average is a term of commerce and navigation, to signify a contribution by individuals, wliere tlie goods of a par- ticular merchant are thrown overboard in a storm, to save the ship from sinking, or wliere the masts, cables, anchors, or other furniture of the ship are cut away or destroyed for the preser- vation of the whole. In these and like cases, where any sacri- fices are deliberately made, or any expenses voluntarily incurred, to prevent a total loss, such sacrifice or expense is the proper subject of a general contribution, and ought to be ratably borne by the owners of the ship, the freiglit, and the cargo, so that the loss may fall proportionably on all. The amount sacri- ficed is called the jeidsoji. 296. Average is either general or particular ; that is, it is either chargeable to all the interests, viz., the ship, the freight, and the cargo, or only to some of them. As when losses occur from ordinary wear and tear, or from the perils incident to the voyage, without being voluntarily incurred ; or when any par- ticular sacrifice is made for the sake of the ship only or the cargo only, these losses must be borne by the parties imme- diately interested, and are consequently defrayed by a -particular average. There are also some small charges called pjetty or accustomed averages, one-third of which is usually charged ta the ship, and two-thirds to the cargo. No general average ever takes place, except it can be shown that tlte danger was imminent, and that the sacrifice was made indiqoensahle, or sup)-posed to be so by the captain and officers, fur the safety of the ship. 297. In different countries different modes are adopted of valuing the articles which are to constitute a general average. 295. \Miat does the term average signify 1 296. How many kinds of average are there ! What are the small charges called 1 Under what circumstances will a general average take place 296 GENERAT> AVERAGE. In general, hoTvever, the value of" the freightage is held to be the clear sura which the ship has earned after seamen's wages, pilotage, and all such other charges as came under the name of petty charges, are deducted ; one-third, and in some cases one-half, being deducted for the wages of the crew. The goods lost, as well as those saved, are valued at the price they Avoukl have brought in ready money at tlie j^loce of delivery, on the ship's arriving there, freight, duties, and all other charges being deducted : indeed, they bear their proportions, the same as the goods saved. The ship is valued at the price she would bring on her arrival at the port of delivery. But when the loss of masts, cables, and other furniture of the ship is compensated by general average, it is usual, as the new articles will be of greater value than the old, to deduct one-third, leaving two- thirds only to be charged to the amount to be contributed. EXAMPLES. 1. The vessel Good Intent, bound from New York to New Orleans, Avas lost on the Jersey beach the day after sailing. She cut away her cables and masts, and cast overboard a part of her cargo, by which another part was injured. The ship was finally got off, and brought back to New York. AMOUNT OF LOSS. Goods of A cast overboard, . - . $500 Damage of the goods of B by the jettison, - 200 Freight of the goods cast overboard, - - 100 Cable, anchors, mast, &;c., worth - $300 ) gOQ Deduct one-third, . - - 100 ) Expenses of getting the ship off the sands, 56 Pilotage and port duties going in and out | jqq of the harbor, commissions, &c., - ) Expenses in port, ----- 25 Adjusting the average, - - - - 4 Postage, - - - - - - - 1^ Total loss, $1186 GENERAL AVERAGE. 297 ARTICLES TO CONTRIBUTE. Goods of A cast overboard, - - - - -$500 Value of B's goods at N. O., deducting freight, &c., 1000 " of C's " « « « 500 " of D's « « « « 2000 " of E's « « • « « 5000 Value of the ship, 2000 Freight, after deducting one-third, - - - - 800 S1L800 Then, total value : total loss : : 100 : per cent of loss. $11800 : 1180 :: 100 : 10; hence, each loses 10 per cent on the value of his interest in the cargo, ship, or freight. Therefore, A loses 850 ; B, $100 ; C, $50 ; D, $200 ; E, $500 ; the owners of the ship, $280— in all $1180. Upon this calculation the owners are to lose $280; but they aix3 to receive their disbursements from the contribu- tion, viz., freight on goods thrown overboard, $100 ; damages to ship, $200 ; various disbursements in expenses, $180 ; total, $480 ; and deducting the amount of contribution, they wiU actually receive $200. Hence, the account will stand : The owners are to receive . - - _ _ $200 A loses 8500, and is to contribute $50 ; hence, he he-) y 450 receives - - - - - "- " ) B loses $200, and is to contribute $100 ; hence, he "> ' y 100 receives ------- t Total to be received, . - - $750 C $ 50 C, D, and E, have lost nothing, and are to pay -l D 200 E 500 Total actually paid, - - - - $750 ; 297. How is the freight valued 1 How much is charged on account o( the seamen's wages 1 How is the cargo valued 1 Does the part lost beaj its part of the loss 1 How is the ship valued 1 When parts of the ship are lost, how arc they compensated for 1 How do you explain the example ' 5 298 TONNAGE OF VESSELS. 60 that the total to be paid is just equal to the total loss, as it should be, and A and B get their remaining and injured goods, and the three others get theirs in a perfect state, after paying their ratable proportion of the loss. TONNAGE OF VESSELS. 298. There are certain custom house charges on vessels, which are made according to their tonnasre. The tonage of a vessel is the number oi, tons weight she will carry, and this is determined by measurement. [From the " Digest," by Andrew A. Jones, of the N. Y. Custom House]. Custom house charges on all ships or vessels entering from any foreign port or place. Ships or vessels of the United States, having three-fourths of the crew and all the officers American citizens, per ton, SO, 06 Ships or vessels of nations entitled by treaty to enter at the same rate as American vessels, . . - . . ^06 Ships or vessels of the United States not having three-fourths the crew as above, - - - - - - - -,50 On foreign ships or vessels other than those entitled by treaty, .50 Additional tonnage on foreign vessels, denominated light money, ..-. ,50 Licensed coasters are also liable once in each year to a duty of 50 cents per ton, being engaged in a trade from a port in one slate to a port in another state, other than an adjoining state, unless the officers and three-fourths of the crew are American citizens : to ascertain •which, the crew's are always liable to an examination by an officer. A foreign vessel is not permitted to carry on the coasting trade ; but having arrived from a foreign port with a cargo consigned tc more than one port of the United States, she may proceed coastwise with a certified manifest until her voyage is completed. 298. What is the tonnage of a vessel ] What are the custom house charges on the dilTercnt classes of vessels trading with foreign countries f To what charges arc coasters subject 1 TONNAGE OF VESSELS. 299 299. The government estimate the tonnage according to one rule, while the ship carpenter wlio builds the vessel uses another. Government Rule. — I. Measure, in feet, above the vpper deck the length of the vessel, from the fore part of the main stem to the after part of the stern-post. Then measure tlte breadth taken at the ividest part above the main ivale on the outside, and the depth from the under side of the deck-plank to the ceiling in the hold. 11. From tlte length take three-fifths of the breadth and mul- tiply the remainder by the breadth a?id depth, and the product divided by 95 will give the tonnage of a single decker ; and the same for a double decker, by merely making the depth equal to half tlte breadth. Carpenters' Rule. — Multiply together the length of the keel, the breadth of the main beam, and the depth of the hold, and the product divided by do will be the carpenters^ tonnage for a single decker ; and for a double decker, deduct from the depth of the hold half the distance betiveen decks. EXAMPLES. 1. What is the government tonnage of a single decker, whose length is 75 feet, breadth 20 feet, and depth 17 feet ? 2. What is the carpenters' tonnage of a single decker, the length of whose keel is 90 feet, breadth 22 feet 7 inches, and depth 20 feet 6 inches ? 3. What is the carpenters' tonnage of a steamship, double decker, length 154 feet, breadth 30 feet 8 inches, and depth, after deducting half between decks, 14 feet 8 inches ? 4. What is the government tonnage of a double decker, the length being 103 feet, breadth 25 feet 6 inches ? 5. What is the carpenters' tonnage of a double decker, its length 125 feet, breadth 25 feet 6 inches, depth of hold 34 feet, and distance between decks 8 feet ? 299. What is the government rule for finding the tonnage 1 What the fchipbuilders' rule 1 800 INVOLUTION. INVOLUTION. 300. A POWER is the product of two or more equal factors. Either of the equal factors is called the root of the power. The root, in Algebra, is Q.dl\eAi\\Q first poiver. The second lyower is the j^roduct of the root by itself: The third power is the product when the root is taken 3 times as a factor : The fourth poioer, when it is taken 4 times : The fifth power, when it is taken 5 times, &;c. 301. The number denoting how many times the root is taken as a factor, is called the exponent of the power. It is written a little at the right and over the root : thus, if the equal factor or root is 3, 3 = 3 the root or base. 3- = 3 X 3 = 9 the 2d power of 3. 33 = 3 x3x3i^ 27 the 3d power of 3. 3* = 3x3 x3x3= 81 the 4th power of 3. 35 = 3 X 3 x 3 X 3 X 3 = 243 the 5th power of 3. Involution t's /^e operation of finding the powers of numhers. Note. — 1. There are three things connected with every power : 1st, The root; 2d, The exponent : and 3d, The .power or result of Iho multiplication. 2. In finding any power, one multipliccation gives the 2nd power: hence, iha number of multiplications is 1 less than the exponent. Rule. — Multiply the mimber i?tto itself as many times less 1 as there are units in the exponent, and the last 'product will be the power. 300. What is a power 1 What is the root of a power 1 What is the first power ! Wliat is the second power ] The third power ? 301. What is the exponent of the power ? How is it written 1 What is Involution ; How many things are connected with every power \ How do you find the power of a number ? EVOLUTION. '601 EXAMPLES. Find the power of the following numbers : 1. The square of 4? 2. The square of 15? 3. Tlie square of 26 ? 4. The square of 142 ? 5. The square of 4G3 ? G. Tlie square of 1340? 7. The square of 24. G ? 8. The square of .526 ? 9. The square of 3.125 ? 10. The square of .0524 ? 11. The square of 246.25 ? 12. The square of -I ? 13. The square of |^? 14. The square of -g-? 15. Tlie square of }|-? 16. The square of -| j ? 17. The square of yjy ? 18. The square of 24 ? 19. The square of 7|- ? 20. The square of 15-j\ ? 21. The square of 225^%? 22. The cube of 6 ? 23. The cube of 24 ? 24. The cube of 72 ? 25. The cube of 125 ? 26. The cube of 136? 27. The 4th power of 12 ? 28. The 5th power of 9 ? 29. The value of (4.25)^? 30. The value of (1.8)'? 31. The value of (32.4)3? 32. The valu« of (.45)5 p 33. The value of (If)^? 34. The cube of (|) ? 35. The 4th power of | ? 36. The cube of 14f? 37. The value of (21)^? 38. The value of (|f)^? 39. The value of (24|)3 ? 40. The value of (.25)6 ? 41. The value of (142.5)3? 42. The value of (3.205)- ? EVOLUTION. 302. Evolution is the operation of finding the root when know the power. The Square Root of a number is the factor which multi- plied by itself 07ice will produce the number. The Cube Eoot of a number is the factor which multiplied by itself taice will produce the number. 302. What is Evolution! What is the square root of a number 7 \^'hat IS the cube root of a number 1 How do you denote the square root of a number ! How the cube rooti 14 302 EXTRACTION OF THE SQUARE ROOT. Thus, 8 is the square root of 64, because 8 X 8 = 64 ; and 3 is the cube root of 27, because 3 X 3 x 3 = 27. The sign J is called the radical sign. "When placed before a number it denotes that its square root is to be extracted. Thus, yST = 6. "VVe denote the cube root by the same sign with 3 written over it : thus, ^/^, denotes the cube root of 27, which is equal to 3. The small figure 3, placed over the radical, is called the index of the root. EXTRACTION OF THE SQUARE ROOT. 303. The square ro t of a number is one of the two equal factors of that number. To extract the square root is to find this factor. The first ten numbers and their squares are 1, 2, 3, 4, 5, G, 7, 8, 9, 10. 1, 4, 9, 16, 25, 36, 49, 64, 81, 100. The numbers in the first line are tlie square roots of those in the second. The numbers 1, 4, 9, 16, 25, 36, &c., having two exact equnl factors, are called perfect squares. A perfect square is a number which has two exact equal factors. A perfect square is a number which has two exact factors. Note. — The square root of a number less than 100 will be less than 10, while Ihc square root of a number greater than 100 i\ill be greater than 10. 304, To find the square root of a nunxber. 1. "What is the square of 36 = 3 tens + 6 units ? Analysis. — The square of 36 is found by- taking 3fi thirty-six times; and this is done by first taking it (5 units times and then 3 tens times, and adding the products. 3G taken 6 units times, gives 3 x G + 6^ : and taken 3 tens times gives 3= + 3 X 6. and their sum 3" + 2(3 X fi) + G" is 3* + 2 (3 X G) + 6" : that is, 303. What is the square root of a number \ What is a perfect square'? How many perfect squares arc there between 1 and 100 ] How do the roots of numbers less than 100 compare with 10 ! ;J0'1. Into wliat parts may every inmibcT be decomposed ! Wlicn so J-ffiMiiiiuscd what is its square equal to ! OPERATION. 3 + 6 3 + 6 3 X 6 + 6= 3^+3 X 6 EXTRACTION OF THE SQUAKE ROUT. 303 F 30 I 30 6 6 6 TT 180 3G 30 E O o n 80 30 900 C8 30 6 180 D K M A 30 B T/ie square of a nicmher is equal to the square of the tens, vlus twice the 'product of the tens hy the units, jjIus the square of ''.'C units. The same may be shown by a diagram : Let the line AB re- present the 3 tens or 30, and BC the six units. Let AD be a square on AC, and AE a square on the ten's line AB. Then ED will be a square on the unit line 6, and tlie rectangle EF ■will be the product of HE, which is equal to the ten's line, by IE, which is equal to the unit line. Also, the rectangle BK will be the product of EB. which is equal to the ten's line, by the unit line, BC. But the whole square on AC is made up of the .'^quare AE, the two rectangles FE and EC and the square ED . hence, it is equal to The square of the tens plus t/rice the product of the tens hy the units, plus the square of the units. 1. Let it nov/ be required to extract the square root of 2025. Analysis. — Since the number contains more than two places of figures, its root will contain tens and units. But as the square of one ten is one hundred, it follows that the square of the tens of the required root must be found in the two figures on the left of 25. Hence, beginning at the right, we point off the number into periods of two figures eacli. We next find the greatest square contained in 20 tens, which is 4 tens or 40. We then square 4 tens which gives 16 hundred, and then place 16 under the second period, and subtract ; this takes away the square of the tens, and leaves 425, which is twice the product of the tens by the units plus the square of the units. OPERATION. 20 2'c (85 16 8 5)42 5 42 5 o04 EXTRACTION OF THE SQUARE ROOT. If now, we double the tens and then divide the remainder exclu- sive of the right hand figure, (since that figure cannot enter into the product of the tens by the units) by it, the quotient will be the units figure of the root. If we annex this figure to the augmented divisor, and then multiply the whole divisor tiius increased by it. the pro- duct will be twice the tens by the units plus the square of the units : and hence, we have found both figures of the root. This process may also be illustrated by the diagram. Suppose AC = 45. Then, subtracting the square of the tens is taking away the square AE, and leaves the two rectangles FE and BK, together with the square ED on the unit line. The two rectangles FE and BK representing the product of units by tens, can be expressed by no figures less than tens. If then, "we divide the number 42, at the left of 5. by twice the tens, that is, by twice AB or BE, the quotient will be BC or EK, the unit of the root. Then, placing BC or 5, in the root, and also annexing it to the divisor doubled, and then multiplying the whole divisor 85 by 5. wc obtain the two rectangles FE and CE, together with the square ED 305. Hence, for the extraction of the square root, we nave the following lluLE. — I. Separate tlie given number into periods of tico figures each, hy setting a dot over the pfoce of units, a second over the place of hundreds, and so on for each cdternate figure to the left. II. Note the greatest square contained in the j^eriod on the left, and place its root on the rigid after the manner of a quotient in division. Subtract the squai-e of this root from the first period, and to the remainder bring down the second period for a divi- dcnd. III. Double the root thus found for a trial divisor and place ii on the left of the dividend. Firid hoiv 7nang times the trial divisor is contained in the dividenJ, exclusive' of the right-hand 305. What is the first step in extracting the square root of numliors \ Wlr.t is tlic second 1 What is the third 1 Wliat the fourth ? \Vlial tho iW'ili \ (Ilvo tiic entire rule] EXTKACTION OF Tnii SQUARE BOOT. 305 figure, and place the quotient in the root and also annex it to the divisor. IV. Midtiply the divisor thus increased, hi/ the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Boxdjle the whole root thus found, for a new trial divisor, and contimie the operation as before, until all the periods are brought down. EXAMPLES. 1. What is the square root of 425104? Analysis. — We first place a dot over the operation. 4, making the right-hand period 04. We 42 51 04(652 then put a dot over the 1. and also over the 36 2, making three periods. 125)651 The greatest perfect square in 42 is 36, 625 the root of which is 6. Placing 6 in the 1302)2604 root, subtracting its square from 42, and 2604 bringing down the next pcriod"51. we have 651 for a dividend, and by doubling the root we have 12 for a trial divisor. Now, 12 is contained in Go., 5 times. Place 5 both in the root and in the divisor; then multiply 125 by 5 ; subtract the pro- duct and bring down the next period. We must now double the whole root 65 for a new trial divisor; or we may take the first divisor after having doubled the last figure 5; then dividing, we obtain 2. the third figure of the root. Notes. — 1. Tlie left-hand period may contain but one figure ; each of the others will contain two. 2 If any trial divis^or is greater than its dividend, the correspond- ing quotient figure will be a cipher. 3. If the product of the divisor by any figure of the root exceeds the corresponding dividend, the quotient figure is too large and must be diminished. 4. There will be as many figures in the root as there are periods in the given number. 5. If the given number is not a perfect square there will be a remainder after all the periods are brought down. In this casoj periods of ciphers may be annexed, forming new periods, each of which will give one decimal place in the root. 14 306 EXTEACTION OF THE SQUARE KOOT. 2. What is the square root of 758692 ? OPERATION. 75 86 92(871.029 +. 64 Note. — After using all the periods of the given number, we annex periods of decimal ciphers, each of which gives one decimal place in the quo- tient. 167)11 11 86 69 1741)17 92 17 41 174202)510000 348404 1742049)16159600 15678441 481159 Rem, 306. To extract the square root of a fraction 1. "What is the square root of .6 ? Note. — We first annex one cipher to make even decimal places; for. one decimal multi- plied by itself will give two places in the product. We then extract the root of the first period, and to the remainder annex a decimal period, and so on, till we have found a sufficient number of decimal places. 2. What is the square root of if ? Note. — The square root of a fraction is equal to the square root of the nume- rator divided by the square root of the denominator. 3. What is the square root of |^ ? NoTK. — When the terms are not per- fect square.", reduce the common fraction to a decimal, and then extract the square root of the decimal. OPERATION. .60(.774 + 49 147)1100 1029 1544)7100 6176 924 rem. OPERATION. fxS. Vl 6 _ 4 2^ -V2^-** OPERATION. f = .75 ; yf'= y/^ = .8545 •+• SOf). How do you extract the square root of a decimal number \ How of a coiiirnon fraction \ EXTKACTION OF THE SQUARE KOOT. 307 Rule. — I. If ike fraction is a decimal, point off the periods from the decimal point to the rir/lU, annexing cipliers if neces- sary, so that each period shall contain two places, and then ex- tract the root as in integral numbers. 11. If the fraction is a common fraction, and its terms perfect squares, extract the square root of the numerator and denomina- tor separately ; if they are not perfect squares, reduce the frac- tion to a decimal, and then extract the square root of the result. EXAMPLES. What are the square roots of the following numbers ? 1. Square root of 49 ? 2. Square root of 144 ? 3. Square root of 225 ? 4. Square root of 2304 ? 5. Square root of ff ? 6. Square root of o^^^ ? 7. Square root of .0196? 8. Square root of 6.25 .'' 9. Square root of 278.89? 10. Square root of 6275025 ? 11. Square root of 7994 ? 12. Square root of .205209 ? 13. Square root of | ? 14. Square root of ^|? 15. Square root of Jg- ? 16. Square root of .60794 ? 17. Value of ^-022201 ? 18. Value of -^^25.1001 ? 19. Value of -v/196.425 ? 20. Value of VTS ? 21. Value of VffH ? 22. Value of ^ ? 23. Value of 25 • 24. Value of yT35 ? 25. Value of -^19000 ? 26. Value of yT784? 27. Square root of 5647.5225 ? 28. Square root of 160048.003 6! APPLICATIONS IN SQUARE ROOT. 307. A triangle is a plain figure Avhich has three sides and three angles. If a straifjht line meets another straio;ht line, C5 7 making the adjacent angles equal, each is called a right angle ; and the lines arc said to be per- pendicular to each other. '.507. Wliat is a triangle ? What is a iglit angle 308 EXTKACTION OF THE SQUAKE KOOT. 308. A right angled triangle is one which has one right angle. In the right angled tri- angle ABC, the side AC opposite the right angle B, is called the hypotheniise ; the side AB the base ; and the side BC the perpen- dicular. 309. In a right angled triangle the square described on the hypothenuse is equal to the sum of the squares described on the other two sides. Thus, if ACB be a right angled triangle, right an- gled at C, then will the large square, D, described in the hypothenuse AB, be equal to the sum of the squares F and E described on the sides AC and CB. This is called the carpen- ter's theorem. By count- ing the small squares in the large square D, you will find their number equal to that contained in the small squares F and E. In this triangle the hypothenuse AB = 5, AC — 4, and CB = 3. Any numbers having the same ratio, as 5, 4 and 3, such as 10, 8 and 6 ; 20, 16 and 12, &c., will represent the sides of a right angled triangle. 310. When the base and perpendicular are known, to find the hrjuotlienusc. D — 308. What is a ri^ht angled triangle ? Which side is the hypothenuse] 309. In a right angled triangle, what is the square on the hyjjolhenuso fq\ial to 1 310. How do you find the hypothenuse when you know the bise and perpendicular 1 EXTRACTION OF THE SQUARE KOOT. 309 1. "Wishing to know the distance from A to the top of 11 tower, I measured the lieight of the tower and found it to be 40 feet ; also the distance from A to B, and found it 30 feet : Avhat was the distance from A to C ? AB = 30 ; AB- = 30^ = 900 BC = 40 ; BC2 = 402 ^ iGOO AC- = AB2 + BC2 = 900 +1600 AC = y'2500 =: 50 feet. Rule. — Square the base and square the 2Jei-pendicular, add the results, ami then extract the square root of their su)7i. 311. To Jiiid one side ivhen we know the hypothenuse and the other side. 1. The length of a hidder which will reach from the middle of a street 80 feet wide to the eaves of a house, is 50 feet : ■what is the height of the house ? Analysis. — Since the square of the length of the ladder is equal to the sum of the squares of half the width of the s-trect and the height of the house, the square of the length of the ladder diminished by the square of half the width of the street will be equal to the square of the heighl of the house : hence, EuLE. — S'juare the hypothenuse and the hnoion side, and take the difference ; the square root of the difference will be the other side. EXAMPLES. 1. A general having an army of 117649 men, Avished to form them into a square : how many should he place on each front ? 2. In a square piece of pavement there are 48841 stones, of equal size, one foot square : what is the length of one side of the pavement ? 3. In the centre of a square garden, there is an artificial circular pond covering an area of 810 square feet, which is y^ 311. When j'ou know the hypothenuse and one side, how do you find lh(.- other i;ide ! 310 EXTK ACTION OF THE SQUARE EOOT. of the whole garden : how many rods- of fence will enclose tho garden ? 4. Let it be required to lay out 67 J. 2R. of land in the form of a rectangle, the longer side of which is to be three times as great as the less : what is its length and width ? 5. A farmer wishes to set out an orchard of 3200 dwarf pear trees. He has a field which is twice as long as it is wide which he appropriates to this purpose, setting the trees 12 feet apart- each way : how many trees will there be in a row, each way, and how much land will they occupy ? G. There is a wall 45 feet- high built upon the bank of a stream GO feet wide : how long must a ladder be that will reach from the outside of the stream to the top of the wall ? 7. A boy having lodged his kite in the top of a tree, finds that by letting out the whole length of his line, which he knows to be 225 feet, it will reach the ground 180 feet from the loot of the tree : what is the height of the tree ? 8. There are two buildings standing on opposite sides of the street, one 39 feet, and the other 49 feet from the ground to the eaves. The foot of a ladder Q)b feet long rests upon the ground at a point between them, from which it will touch the eaves of either building : what is the width of the street ? 9. A tree 120 feet higli was broken off in a storm, the top striking 40 feet from the roots, and the broken end resting upon the stump : allowing the ground to be a horizontal plane, what was the height of tlie part standing ? 10. What will be the distance from corner to corner, tln-ough the centre of a cube, whose dimensions are 5 feet on a side ? 1 1 . Two vessels start from the same point, one sails due north at the rate of 10 miles an liour, the other due west at the rate of 14 miles an hour: how far apart will they be at the end of 2 days, supposing the surface of the earth to be a plane? 12. How much more will it cost to fence 10 acres of land, in the form of a rectangle, the length of which is four times its breadth, llian if it were in the form of a square, the cost of thu fence being $2.50 a rod ? CUBE KOOT. 311 13. "^Yhat is the diameter of a cylindrical resei'voir contain- ins: 9 limes as much water as one 25 feet in diameter, the heiijhts beino; the same ?* 14. If a cylindrical cistern 8 feet in diameter will hold 120 barrels, what must be the diameter of a cistern of the same depth to hold 1500 barrels? 15. If a pipe 3 inches in diameter will discharge 400 gallons in 3 minutes, what must be the diameter of a pipe that will discharo-e IGOO gallons in the same time? IG. "What length of rope must be attached to a halter 4 feet long that a horse may feed over 21 acres of ground ? 17. Three men bou2;ht a si-rindstone, Avhich was four feet in diameter : how much must each grind off to use up his share of the stone ? CUBE ROOT. 312. The Cube Root of a number is one of three equal factors of the number. To extract the cube root of a number is to find a factor whicli multiplied into itself twice, will produce the given number. Thus, 2 is the cube root of 8 ; for, 2 X 2 X 2 =: 8 : and 3 b the cube root of 27 ; for, 3 x 3 x 3 = 27. 1, 2, 3, 4, 5, 6, 7, 8, 9, 1 8 27 64 125 216 343 512 729 The numbers in the first line are the cube roots of the cor- responding numbers of the second. The numbers of the second line are called perfect cubes. A number is a iX'rfccl cube when 313. What is the cube root of a number \ "When is a number a perfect cube 1 How many perfect cubes are there between 1 and 1000 ] * Note — If two volumes have the same altitude, their contents will be to each other in the same proportion as their bases ; and if the bases are similar figures (that is, of like form,) they will be to each other as the squares of iheir diameters, or other like dimensions. 312 CUBE ROOT, it has three exact equal factors. By examining the numbers in the two lines we see, 1st. That the cube of units cannot give a liigher order than hundreds. 2d. That since the cube of one ten (10) is 1000 and the cube of 9 tens (*J0), 729000, tJie cube of tens ivill not give a lower denomination than thousands, nor a higher denomination than hundreds of thousands. Hence, if a number contains more than three figures, its cube root will contain more than one ; if it contains more than sis, its I'oot Avill contain more than two, and so on ; every additional three figures giving one additional figure in the root, and the figures Avhich remain at the left hand, although less than three, will also give a figure in the root. This law explains the reason for pointing off into periods of three figures each. 313. Let us now see how the cube of any number, as 10, is formed. Sixteen is composed of 1 ten and 6 units, and may be ■written, 10 + 0. To find the cube of 10 = 10 + 6, we must multiply the number by itself twice. To do this we place the number thus, product by the units, _ - - product by the tens, - - . Square of 16 Multiply again by 16, product by the units, - - - 600+ 720 + 216 product by the tens, - - - 1000 + 1200 + 300 Cube of 16 - - - - 1000 + 1800 + 1080 + 216 1. By examining the parts of this number, it is seen that the first part 1000 is the chIjc of the tens ; that is, 10 X 10 X 10 = 1000. 16 = 10 + 10 + 60 + 100 + 60 6 6 3G 100 + 120 + 10 + 36 6 yi3. Of how many parts is the cube of a number composed 1 \Vhal arc I hey ! CUBE ROOT. 313 2. The second part 1800 is three times the square of the tens multiplied by the units ; that is, 3 X (10)2 x6 = 3xl00xG = 1800. 3. The thii-d part 1080 is three times the square of the units multiplied by the tens ; that is, 3 X 62 X 10 = 3 X 36 X 10 = 1080. 4. The fourth part is the cube of the units ; that is, 63 = 6x6x6 = 216. 1. "What is the cube root of the number 4096 ? Analysis. — Since the number contains more than three figures, we know that the root will contain at least units and tens. operation. Separating the three right-hand ' 4 096(16 figures from the 4, we know that 1 the cube of the tens will be found 1* X 3 = 3)3~0 (9-8-7-6 in the 4 ; and 1 is the greatest cube 16' = 4 096. in 4. Hence, we place the root 1 on the right, and this is the tens of the required root. We then cube 1 and subtract the result from 4, and to the remainder we bring down the first figure of the next period. We have seen that the second part of the cube of 16, viz., 1800, is three times the square of the tens multiplied by the units; and hence, it can have no significant figure of a less denomination than hundreds. It must, therefore, make up a part of the 30 hundreds above. But this 30 hundreds also contains all the hundreds which come from the 3d and 4th parts of the cube of 16. If it Mere not so, the 30 hundreds, divided by three times the square of the tens, would give the unit figure exactly. Forming a divisor of three times the square of the tens, we find the quotient to be ten ; but this we know to be too large. ^Placing 9 in the root and cubing 19, we find the result to be 6859. Then trying 8 we find the cube of 18 still too large; but when we take G we find the exact number. Hence, the cube root of 4096 is 16. 314, Hence, to find the cube root of a number: Rule. — T. Separate the given number into pteriods of three fiyures each, by placing a dot over the place of units, a second 81-i OUBK KOOT. over the ])lace of thovsa7ids, and so on over each third figure ta the left: the left hand period will often contain less than three places of figures. II. JV^ote the greatest perfect cube in the first period, and set its root on the right, after the manner of a quotient in division. Subtract the cube of this number fro )n the first period, and to the remainder bring down the first figure of the next jieriod for a dividend. III. Take three times the square of the root just found for a trial divisor, and see how often it is contained in the dividend, and place the quotient for a second figure of the root. Then cube the figures of the root thus found, and if their cube be greater than the first tzvo j^eriods of the given nujuber, diminish the last figure, but if it be less, subtract it from the first two periods, and to the remainder bring dotvn the first figure of the next period for a new dividend. IV. — Tahe three times the square of the whole root for a second trial divisor, and find a third figure of the root as before. Cube the whole root thus found and subtract the result from the first three jyeriods of the given numhir when it is less than that number, but if it is greater, diminish the last figure of the root, proceed in a similar way for all the periods. EXAMPLES. 1 What is the cube root of 2070 G875 ? OPERATION. 20 796 875(275 2'= 8 2' X 3 = 12)127 First two periods, ... 20 796 (27)' = 27 X 27 X 27 = 19 6S3 3 X (27)' = 2217)1 i 138 Tirst three periods, - - - 20 796 875 (275)' = 275 X 275 X 275 = 20 796 875 314. WTiat is the rule for oxtracting the cube root of a number? CUBE KOOT. 313 Find the cube roots of the followinnr numbers : 1. Cube root of 1728? 2. Cube root of 117649? 3. Cube root of 46G56? 4. Cube root of 15069223 ? 5. Cube root of 5735339 ? 6. Cube root of 48228544 ? 7. Cube root of 84604519 ? 8. Cube root of 28991029248? 315. To extract the cube root of a decimal fraction : Annex ciphers to the decimal, if necessary, so /hat it shall con- sist q/ 3, 6, 9, ^c, decimal places . Then put the first point over the 'place of tlioiisaudths, the second over the place of milliontlts, and so on over every third place to the rigid ; after which extract the root as in whole numhers. Notes. — 1. There will be as many decimal places in the root as there are periods in the given number. 2. Tlie same rule applies when the given number is composed of a "whole number and a decimal. 3. If in extracting the root of a number there is a remainder after all the periods have been brought down, periods of ciphers may be annexed by considering them as decimals. EXAMPLES. Find the cube roots of the following numbers : 5. Cube root of .387420489 ? 6. Cube root of .000003375 ? 1. Cube root of 8.343 ? 2. Cube root of 1728.729? 3. Cube root of .0125 ? 4. Cube root of 19683.46656? 7. Cube root of .0066592? 8. Value of y8Tr7"29? 316. To extract the cube root of a common fraction, I. Reduce compound fractions to simple ones, mixed numhers to improper fractions, and then reduce the fraction to its lowest terms. 314. What is the rule for extracting the cube root of a number 1 315. How do you extract the cube root of a decimal fraction '^ How many decimal places will there be in the root \ W"\\\ the same rule apply when there is a whole num!)er and a decimal I If in extracting the root of any number you find a decimal, how do you proceed T 816 CUBE ROOT. II. Extract the cube root of the numerator and denominator separately, if they have exact roots ; but if either of them has not an exact root, reduce (he fraction to a decimal, and extract the. root as in the last case. EXAMPLES. Find the cube roots of the following fractions : 1. Cube root of y"^ ? 2. Cube root of III? 3. Cube root of SIJ^? 4. Cube root of 911? 5. Cube root of 141? 6. Cube root of yf^ ? 7. Cube root of oVVrir ? 8. Cube root of If ^f^? 9. Cube root of 7f ? 10. Cube root of 56f ? APPLICATIONS. 1. What must be the dimensions of a cubical bin, that its A'ohime or capacity may be 19683 feet? 2. If a cubical body contains 6859 cubic feet, what is the length of one side : what the area of its surface ? 3. The volume of a globe is 46656 cubic inches : w'hat would be the side of a cube of equal solidity ? 4. A person wished to make a cubical cistern, which should hold 150 barrels of water ; what must be its depth ? 5. A farmer constructed a bin that would contain 1500 bush- els of grain ; its length and breadth were equal, and each half the height ; what were its dimensions ? 6. AVhaL is the difference betAveen half a cubic yard, and a rube whose edge is half a yard ? 7. 7l merchant paid $911,25 for some pieces of muslin. He paid as many cents a yard as there were yards in each piece, and there were as many pieces as there were yards in one piece : how many yards were there, and how much did he pay a yard ? Notes. — 1. Bodies are said to be similar when they have the same form and have their like parts proportional. 2. It is proved in Geometry, that the volumes or weights of similar bodies are to each other ns the cubes of their like dimensions. 3. Those bodies which arc named in the same example arc sup posed to bo similar. ARITHMETICAL PROGRESSION. 317 8. If a sphere 3 feet in diameter contains 14.1372 cubic feet, what are the contents of a sphere 6 feet in diameter ? 33 : 63 :: 14.1372 : 113.0976. Ans. 9. If a ball 2^ inches in diameter weighs 8 pounds, how much will one of the same kind weigh, that is 5 inches in diameter ? 10. What must be the size of a cubical bin, that will contain 8 times as much as one that is 4 feet on a side ? 11. How many globes, 6 inches in diameter, will it require to make one 12 inches in diameter? 12. If a ball of silver, 1 unit in diameter, be worth $8, what will be the value of one 51 units in diameter ? 13. If a plate of silver, 6 inches long, 3 inches wide, and i inch thick, be worth $100, what will be the dimensions of a similar plate of the same metal worth $800 ? 14. If one man can dig a cellar 12 feet long, 10 feet wide, and 41 feet deep, in 3 days, what will be the dimensions of a similar cellar that requires him 24 days to 3ig it, working at the same rate, and the ground being of the same degree of hardness ? 15. If I put 2 tons of hay in a stack 10 feet high, how high must a similar stack be to contain 16 tons ? 16. Four women bought a ball of yarn 6 inches in diameter, and agreed that each should take her share sejiarately from the surface of the ball : how much of the diameter must each wind off? ARITHMETICAL PROGRESSION. 317. If we take any number, as 2, we can, by the continued addition of any other number, as 3, form a series of numbers : thus, 2, 5, 8, 11, 14, 17, 20, 23, Sec, in which each number is formed by the addition of 3 to the preceding number. ,S17. What is an arithmetical progression 1 What is the number added or subtracted called ? 515 AKmrMETICAL PROGRESSION. This series of numbers may also be formed by subtracting 3 continually from a larger number : thus, 23, 20, 17, 14, 11, 8, 5, 2. An Arithmetical Progression is a series of numbers in which each is derived from the preceding by the addition or subtraction of the same number. The number which is added or subtracted is called the com- mon difference. 318. When the series is formed by the continued addition of the common difference, it is called an increasing series ; and when it is formed by the subtraction of the common diflference, it is called a decreasing series : thus, 2, 5, 8, 11, 14, 17, 20, 23, is an increasing series. 23, 20, 17, 14, 11, 8, 5, 2, is a decreasing series. The several numbers are called terms of the progression the first and last terms are called the extremes, and the interme- diate terms are called the tncaas. 319. In every arithmetical progression there are five parts, any three of wliich being given or known, the remaining two can be determined. They are, 1st : The first term ; 2d : The last term ; 3d : The common difference ; 4tli : Tlie number of terms ; 5th : The sum of all the terms. 318. When the common difference is added, what is the series called 1 What is it called when the common difl'crencc is subtracted 1 What are the several numbers called 1 What are the first and last called 1 What arc the intermediate ones called ! 319. How many parts are there in every arithmetical progression ^ What are they! How many parts must be given before the remaining ones can be found 1 AKITIIMETICAL PROGRESSION. 319 CASE I. 320. Hating given the first term, the common difference, and the nuinher of terms, iojind the lust term. 1. The first term of an increasing progression is 4, the com- mon difference 3, and the number of terms 10 : what is the last term ? Analysis. — By considering the manner in which the increasing progression is formed, we see that the 2d term is obtained by adding the operation. common difference to the 1st term ; 9 no. less 1 the 3d, by adding the common differ- 3 com. diff. ence to the 2d ; the 4th, by adding the 27 common difference to the 3d, and so 4 1st term, on; the number of additions^ in every 31 last term, case^ being 1 less than the ymmber of terms found. Instead of making the additions, we may multiply the common difference by the number of additions, that is, by 1 less than tlie number of terms, and add the first term to the product. Rule. — Multiply the common difference by 1 less than the mimber of tei-ms : if the 2^^'ogression is increasing, add the pro- duct to the first term, and the sum 'will be the last term ; if it is decreasing, subtract the product from the first term and the dif- ference will be the last term. EXAMPLES. 1. What is the 18th term of an arithmetical progression, of which the fii'st term is 4, and the common difference 5 ? 2. A man is to receive a certain sum of money in 12 pay- ments : the first payment is $300, and each succeeding pay- ment is less than the previous one by $20 : what will be the last payment ? 3. What will $200 amount to in 15 years, at 7 per cent simple interest : the first year it increases $14, the second, $28, and so on ? 320. When you know the first term, the common difference and the iiuiuber of terms, how do you find the last term 1 820 ARITHMETICAL PROGRESSION. 4. A man bus a piece of land 35 rods in length, which tapers to a point, and is found to increase ^ rod in width,, for every rod in length : what is the width of the wide end ? 5. James and John have 100 marbles. It is agreed between them that John shall have them all, if he Avill place them in a straight line half a foot apart, and so that he shall be obliged to travel 300 feet to get and bring back the farthest marble ; and also, if he will tell, without measuring, how far he must travel to bring back the nearest. CASE II. 321. Knoiving the two extremes of an arithmetical 'progreS' sion and the number of terms, to find the common difference. 1. The two extremes of a progression are 4 and 68, and the number of terms 17 : what is the common difference ? Analysis. — Since the common difference multiplied by 1 less than the number of terms gives a product equal to the difference of the extremes, if we operation. divide the difference of the extremes by 1 68 less than the number of terins^ the quo- 4 Xieni vf\\\ he WiQ common difference : hence, 17 — 1 = 16)64(4 Rule. — Subtract the less extreme from the greater, and divide the remainder by 1 less than the number of terms : the quotient will be the common difference. EXAMPLES. 1. A man started from Chicago and travelled 15 days ; each day's journey was increased by the distance which he travelled the first day : what was his daily increase if he travelled 75 miles the last day ? 2. A merchant sold 14 yards of cloth, in pieces of 1 j-ard each ; for the first yard ,he received $1, and for the last $2G^ . what was the diflference in the price per yard ? 321. ^Vllrn you know the extremes and number of terms, how do you find tile oonniion dLfTercujio 1 2 5 8 .23 20 17 11 14 14 11 17 8 20 5 23 2 25 25 25 25 25 15 25 25 ARITHMETICAL PROGRESSION. 321 3. A board is 17 feet long: it is 2-^ inches wide at one end, and 144 at the other : what is the average increase in width per foot in length ? CASE III. 322. To find the sum of the terms of an arithmetical prO' gression. 1. What is the sum of the series whose first term is 2, com- mon difference 3, and number of terms 15 ? Given series, Same, order inverted. Sum of both series. Analysis. — The two series are the same ; hence, their sum is equal to twice the given series. But their sum is equal to the sum of the two extremes, 2 and 23. taken as many times as there are terms J and the given series is equal to half this sum, or to the sura of the extremes multiplied by half the number of terms. Rule. — Add the extremes together and multi2'>Iy their sum by half the number of terms ; the product will he the sum of all the t4rms. EXAMPLES. 1. What debt could be discharged in a year, by weekly pay- ments in arithmetical progression, the first payment being $5, and the last $100 ? 2. A person agreed to build 56 rods of fence ; for the first rod he was to receive 6 cents, for the second, 10 cents, and so on : what did he receive for the last rod, and how much for the whole ? 3. If a person travel 30 miles the first day, and a quarter of a mile less each succeeding day, how far will he travel in 30 days ? 4. If 120 stones be laid in a straight line, each at a distance of a yard and a quarter from the one next to it, how far must a person travel who picks them up singly and places them iu a a23. How do you find the sum of the series 1 822 ARITHMETICAL PEOGEESSION. heap, at the distance of 6 yards from the end of the line and in its continuation ? CASE IV. 323. Having given the first and last terms, and the common difference, to find the number of terms. 1. The first term of an arithmetical progression is 5, the com- mon difference 4, and the last term 41 : what is the number of terms ? Analysis. — Since the last term is equal operation. to the first term added to the product of the 41 — 5 = 36 common dilTerence, by 1 less than the num- 4)36( = 9 ber of terms (Art. 320), it follows that, if 9 + 1 = 10 No. terms, the first term be taken from the last term, the difference will be equal to the product of the common difference by 1 less than the number of terms : if this be divided by the com- mon difference, the quotient will be 1 less than the number of terms.' Rule. — Divide the difference of the tico extremes hy the com- mon difference, and add 1 to the quotient : the sum will be the number of terms. EXABIPLES. 1. A farmer sold a number of bushels of wheat ; it was agreed that for the first bushel he should receive 50 cents, and an increase of 9 cents for each succeeding bushel, and for the last he received $500 : how many bushels did he sell ? 2. A person proposes to make a journey, and to travel 15 miles the first day, and 33 miles the last, with a dally increase of 11 miles : in how many days did he make the journey, and what was the Avhole distance travelled ? 3. I owe a debt of $2325, and wish to pay it in equal install- ments, the first payment to be $575, the second $500, and decreasing by a common diflcrencc, until the last payment which is $200 : what will be the number of installments ? 323. Having given the first and last terms and the common difference, Low do \ou find the number of terms ! GEOMETRICAL PKOaKESSIOJ^. 328 GEOMETRICAL PROGRESSION. 324. A Geometrical Progression is a series of terms, each of which is derived from the preceding one, by muUiply- ing it by a constant number. The constant multiplier is called the ratio of the progression. 32.5. If the ratio is greater than 1, each term is greater than the preceding one, and the series is said to be increasing. If the ratio is less than 1, each term is less than the preced- ing one, and the series is said to be decreasing ; thus, 1, 2, 4, 8, 16, 32, &c. — ratio 2 — increasing series : 32, 16, 8, 4, 2 1, &c. — ratio \ — decreasing series. The several numbers resulting from the multiplication arc called terms of the progression. The first and last are called the extremes, and the intermediate terms are called means. 326. In every Geometrical, as well as in every Arithmetical Progression, there are five parts : 1st : The first term ; 2d : The last term ; 3d : The common ratio ; 4th : The number of terms ; 5th : The sum of all the terms. If any three of these parts are known, or given, the remain- ing ones' can be determined. 324. What is a geometrical progression 1 What is the constant multi- plier called 1 325. If the ratio is greater than 1, how do the terms compare with each other 1 What is the series then called ! If the ratio is less than 1, how do they compare T What is the series then called ? What are the several numbers called ? What are the first and last terms called 1 What are tho intermediate ones called l 326. How many parts are there in every geometrical progression \ What are they "! How many must be known before 'lie others can be found \ 324 GEOMETKICAL PROGRESSION. CASE I. 327. Having given the first term, tJie ratio, and the number of terms, to find the last term. 1. The first term is 4, and the common ratio 3 : what is the 5th term? Analysis. — The second term is formed by operation. multiplying the first term by the ratio; the 3 X 3 X 3 x 3 = 81 third term by multiplying the second term 4 by the ratio, and so on ; the number of mul- Ans. 324 tiplications icing 1 less than the number of terms : thus, ■ 4 = 4, 1st term, 3x4= 12, 2d term, 3x3x4== 36, 3d term, 3x3x3x4= 108, 4th term, 3x3x3x3x4= 324, 5th term. Therefore, the last term is equal to the first term multiplied ly the ratio raisvd to a jioioer whose cxpomnt is 1 less than the number of terins. Rule. — Raise the ratio to a poicer tchose exponent is 1 less than the number of terms, and then midtiphj this power by the first term, EXAMPLES. 1. The first term of a decreasing progression is 2187 ; the ratio is l, and the number of terms 8 : what is the last term ? Note, — The 7lh power of -J- i.s -rrx^y; this operation. multiplied by the first term, 2187, gives 1, (-J-)' = •jxVt the last term. (ttVt x 2187 = 1. 2. The first term of an increasing geometrical series is 8, the ratio 5 : wliat is the 9th term ? 3. The first term of a decreasing geometrical series is 729, the ratio i : what is the 10th term ? M'Zl. Knowing the first term, the ratio, and the number of tenns, how Jo you find the last term ? OKOMETRICAL PROGRESSION. 325 4. If a farmer should sell 15 bushels of wheat, at 1 mill for the first bushel, 1 cent for the second, 1 dime for the third, and 60 on ; what would he receive for the last bushel ? 5. A man dying left 5 sons, and bequeathed his estate in the following manner ; to his executors $100 ; his youngest son was to have twice as much as the executors, and each son to have double the amount of the next younger brother : what was the eldest son's portion ? 6. A merchant engaging in business, trebled his capital once in 4 years ; if he commenced with $2000, what will his capital amount to at the end of the 12th year ? 7. A farmer wishing to buy 16 oxen of a drover, finally agreed to give him for the whole the cost of the last ox only. He was to pay 1 cent for the first, 2 cents for the second, and doubling on each one to the last : how much would they cost him ? CASE 11. 328. Knowing the two extremes and the ratio, to Jind the sum of the terms. 1. What is the sum of the terms of the progression 2, C, 18, 54,162? OPERATION. 6 + 18 + 54 + 162 + 486 = 3 times. 2 + 6 + 18 + 54 + 162 =z 1 tim e. 486 - 2 = 2 times. 486 - 2 484 2 = 242 sum. Analysis. — If we multiply the terms of the progression by the ratio 3. we have a second progression, 6, 18, 54, 162, 486, which is 3 times as great as the first. If from this we subtract the first, the remainder. 486 — 2, will be 2 times as great as the first; and if this remainder be divided by 2. the quotient Avill be the sum of the terms of the first progression. 328. Knowing the two extremes and the ratio, how do you find the cum of the terms ! IS g26 GEOMETlilCAL PKOGKESSION. But 48P is the product of the last term of the given progression multiplied by the ratio, 2 is the first term, and the divisor 2, 1 less than the ratio : hence, Rule. — Multiply the last term by the ratio ; take the differ- ence between this 2}roduct and the first term and divide the remairir- der by the difference between 1 and the ratio. Note. — When the progression is increasing, the first term is sub- tracted from the product of the last term by the ratio, and the di\'isor is found by subtracting 1 from the ratio. When the progression is decreasing, the product of the last term by the ratio is subtracted from the first term, and the ratio is subtracted from 1 . EXAMPLES. 1. The first term of a progression is 4, the ratio 3, and the last term 78722 : what is the sum of the terms ? 2. The first term of a progression is 1024, the ratio i, and the last term 4 : wliat is the sum of the series ? 3. What debt can be discliarged in one year by monthly payments, the first being $2, the second S8, and so on to the end of the year, and what will be the last payment ? 4. A gentleman being importuned to sell a fine horse, said that he would sell him on the condition of receiving 1 cent for the first nail in his shoes, 2 cents for the second, and so on, doubling the price of every nail : the number of nails in each shoe being 8, how much would he receive for his liorse ? 5. A laborer agreed to thresh 64 days for a farmer on the condition that he should give him 1 grain of wheat for the first day's labor, 2 grains for the second, and double each succeeding day : what number of bushels would lie receive, supposing a pint to contain 7G80 grains, and wliat number of ships, each carrying 1000 tons burden, might be loaded, allowing 40 bushels to a ton ? ( ANALYSIS. 327 ANALYSIS. J. If 12 yards of cloth cost S48,36, what will 7 yards cost? Analysis. — One yard of clolh will cost -^ as much as 12 yards : •ince 12 yards cost S48,36, one yard will cost Jg- of $48,36 = $4,03 7 yards will cost 7 times as much as 1 yard, or 7 times -^ of $48, 3G = 828.21 ; therefore, if 12 yards of cloth cost -148,36, 7 yards will cost $28,21. OPERATION. 4,03 4,03 i$,$$ 1 7 ^„^^, 1^ ^S^^i $28,21 ; or MM 7 I $28,21 Ans. 3. If 27 pounds of butter will buy 45 pounds of sugar, how much butter will buy 36 pounds of sugar ? Analysis. — One pound of sugar will buy -^ as much butter as 45 pounds, or -^-^ of 27lbs. of batter; 3fc pounds of sugar will buy 36 times as much butter as 1 pound of sugar, or 36 times -^ of 27/65., which is ^^Ibs. = 21|/65. OPERATION. ^:^ 1 36 3. "What will 6| cords of wood cost, if 2^ cords cost $7^ ? Analysis. — Since 2| cords = ^ cords of wood costs S7|- ~. S-^ one cord will cost as many dollars as -l^ is contained times in 'y or $3 : C-| cords = ?j? cords, will cost ^-^ times as much as 1 Qmd that is. $3 X 3J = $8ji ::= $20.25. 0PER.4TI0N. 108 5 27 . =2ims.; or 108 21^/55- a ■ ^ ii) ^ 4 ~ 4 $201; or, $ 4 $ 27 4 81,00 $20,25 Ans. 12 3 $ ^ n $ 5 7 180,00 328 ANALYSIS. Note. — The fractional pirt of a dollar may always be reduced to cent.s by annexing two ciphers, and to mills by annexing three, and then dividing by the denominator. 4. A farmer sold a number of cows, and had 12 left, which was i of the number sold ; if the number sold be divided by I of 91, the quotient will be 1 the number of dollars he received per head : how much did he receive per head for his cows ? Analysis. — 12 is ^ of 3 times 12 = 36, the number of cows sold ; 36 divided by | of 9J=7, the quotient, 8^, is | of 5 times ^=-i-fA = S25f OPERATION. 12 3 4x3 5 180 ^^,^ „ T^1^3^28^i=-T==^2^^'^^^; $25,71|- Ans: 5. What will 20 bushels of barley cost, in dollars and cents, at 7 shillings a bushel, New York currency ? Notes. — 1. Although United States money is expressed in dollars, cents, and mills, still in most of the States the dollar (always valued at 100 cents) is sometimes reckoned in pounds shillings and pence; thus. 2. In the New England States, in Indiana, Illinois, Missouri, Virginia, Kentucky, Tennesce, Mississippi, and Texas, the dollar is reckoned at 6 shillings ; in New York, Ohio, and Michigan, at 8 shil- lings ; in New Jersey, Pennsylvania, Delaware, and Maryland, at • 75. Gd.; in South ^Carolina and Georgia, at 45. 8fZ. ; in Canada and Nova Scotia, at shillings. 3. It often occurs that the retail price is given in shillings and pence, and the result or cost is required in dollars and cents. Analysis. — Since 1 bu.shel of barley costs 7 shillings, 20 busliela will cost 20 times 7 shillings, or 140 shillings; and as 8 shillings make 1 dollar, New York currency, there will be as many dollars ub }< i.^ contained times 140 = $17 50. ANALYSIS. 829 OPERATION. 20 X 7 -i- 8 = $171 ; or n 35,00 "$17,50 Ans. 6. What will be the cost of 72 bushels of potatoes, at 35. M. per bushel, New York currency ? 4 13 Ans. OPERATION. Or, ^0^ 3 n 39 4 117,00 4 117,00 $29,75 $29,75 Ans Note. — When the pence is an aliquot part of a shilling, the price may be reduced to an improper fraction, which will be the multiplier m the denomination of shillings ; thus, 35. 3c?. = 'i\s. = ^^^5. : or, the shillings and pence maybe reduced to pence; thus, 3s. 3rf. = 39rf., tn which case the product will be pence, and must be divided by 96, the number of pence in $1. 7. What will 121 pounds of tea cost at 65. Sc?. a pound, Pennsylvania currency ? OPERATION. 3 ^ 20 9 100 $111 Ans. Or, 00 9 25 4 100,00 $11,11j \ns Note. — In the last example the multiplier is 65. 8J. = 6>5. — \ or %Qd. The divisor is 75. Gc/. = 7^.s. = ^s.^ or 90d Hence, to fiii fjie cost of articles in dollars and cents, when the price is in shillings and pence, Muliiplij the commodity hy the price, and divide the product by the value of a dollar, ex2')resscd in the unit of the price. 330 ANALYSIS. 8. How many daj^s work at 10s. 6c/. a day, must be given for 18 bushels of corn at os. lOd. a bushel? 1$ 2 OPERATION. Or, m 10 days Ans. 10 10 days Ans. Note. — The same rule applies in this as in the preceding examples, except that the divisor is the price of the articles received in pay- ment, reduced to the same unit as the price of the article bought. 9. What will 5cwt. of coffee cost, at I5. 4c?. per pound, New York currency? OPERATION, > 25 4 t Or, n 250 25 250,000 883,3331 Ans. $83,3331 Ans. Note. — Reduce the cwts. to Ihs. by multiplying by 4, and then by 25, after which proceed as in the preceding examples. 10. A merchant bought a number of bales of cloth, each containg 1331 yards, at the rate of 12 yards for $11, and sold it at the rate of 8 yards for $7, by which he lost $100 in the trade : how many bales were there ? Analysis. — Since he paid Su for 12 yards, for 1 yard he paid -A of $11, or W of %\ \ and since he received $7 for 8 yard.«. for 1 yard he received \ of $7, or \ of $1, He lost on 1 yard the difference between \\ and |- — -jjtj. of a dollar. Since his whole loss was Si 00, he had as many yards as ^ is contained times in 100 = 2400 yards; and 1 here were as many bales as 133J (the number of yards in ] bale) is contained times in the whole number of yards = 18 bales. OPERATION. _1_ '2 4 (100 - ^v) - 133'^ = 18 ^«5. ^''' m_ 100 6 3 18 bales Ano. ANALYSIS. 831 11. A can mow an acre of grass in 7^ hours ; B, in 5 hours ; C, in 5| hours ; how many days working 6|- hours, would they requix'e to mow lo| acres ? Analysis. — Since A can mow an acre of grass in 7^ hours, B, in 5 hours, and C in 5|, A can mow ^, B, \, and C. -^-^ of an acre, in 1 iiour. Together, they can mow t'5+i+4^^=-4l "' "•' acre in 1 hour: and to mow 1 a^.TC, they will require as many Imurs- as |-| is contained times in 1 = -ff hours: to mow 13-|- acres, they will require 13-| times -1^ = 27 hours, and working 6|- hours each day. will require 4 days. OPKRATION. 15 5 45 4o fit Or ^ 00 4 , , ^'' n X -— X n $ — = 4 days 4 4 days Ans. 12. A person employed three men, A, B, and C, to do a piece of work for $132,66. A can do the work alone in 23^ days, working 12 hours a day; B can do it in 25 days, working 8 hours a day; and C can do it in 16 days, working IIJ hours a day. In what time can the three do it, working to- gether, 10 hours a day, and what share of the money should each receive ? Analysis. — Since A can do the work in 23^ days, working 12 hours each day: B, in 25 days, working 8 hours each day; and C, in 16 days, working lli hours each day, A can do the same v/ork in 280 days. B, in 200 days, and C. in 180 days, working 1 hour each day : then A, B, and C, can do -^h + nh + li o = Trifo ^^ ^^^^ work in 1 day, working 1 hour : by working 10 hours, they will do 10 times as much ; or, the work done by each in 1 day of 10 hours, will be denoted by -^q. -^^q, and ,^^ : and the whole work done in 1 day by tt^tt^ ; hence, the number of days will be denoted bv the number of times which 1 contains ■jWiT^'We'^ "'''"g^ days. If the part which each does in 1 day be multiplied by the number of days, viz., 7^, the product will be the part done by each ; viz., Aj 5^0 x'^W^iV^; B> ^x ' sV^tVs ■■ '^"d C, J^o_.x7^=^% ; there- fore, A must have ^-^, B, ^-^ and C J^ of S132,GG. 332 ANALYSIS. OPERATION. First: l-^Y^=.W7f=V^days. Ans. Second: 8132,66 XTV8 = ^33,53f|=A's share. $132,66 xf-^=S46,95fi=B's share. 8132,76 X ^^ =$52,16 |^=:C's share. Total paid 3132 66" 13. If 336 men, in 5 days, working 10 hours each day, can dig a trench of 5 degrees of hardness, 70 yards long, 3 yards wide, and 2 yards deep ; how many days of 12 hours each, will 240 men require to dig a trench 36 yards long, 5 yards wide, and 3 yards deep, of 6 degrees of hardness ? Analysis. — Since 336 men require 5 days of 10 hours each, to dig a trench, it will take 1 man 336 times 5 days of 10 hours each, and 10 times (336 X 5) days of 1 hour each^ to dig the same trench. To dig a trench 1 yard loug. will require -^ as much time as to dig one 70 yards long ; to dig one 1 yard wide, ^ as much as 3 yards wide; to dig one 1 yard deep, -^ as much as 2 yards deep ; and to dig one of 1 degree of hardness \ as much as to dig one of 5 degrees of hardness. 240 men can dig a trench 1 yard long, 1 yard wide. 1 yard deep, and of 1 degree of hardness in ^^ of the time that 1 man can dig the same, and in -jlj as many days of 12 hours each, as of 1 hour each; but to dig one 36 yards long, will require 36 times as much time as to dig one 1 yard long ; to dig one 5 yards wide, 5 times as much as 1 yard wide ; to dig one 3 yards deep, 3 times as much as 1 yard deep; and to dig one of 6 degrees of hardness will require 6 times as much time as to dig one of 1 degree of hardness. OPERATION. «Ji^5xi0^1xixlxlx-Lxlx?^x*x?x?=9*,. 1 Tt0 1i fi $ t0 1^2 1 1 1 1 Or, U0 m X $ n 10 q n % $ % H $ 0^ da; ANALYSIS. 083 Note. — The principle of the above analysis is this : 1st. Find how many hours it will take 1 man to dig 1 cubic yard of trench ; this ia done in the first part of the analysis. 2d. Find how long it will take 240 men. working 12 hours a day, to dig the required trench, working at the same rate ; this is done in the second part of the analysis. 14. If 20 cords of wood are equal in value to 6 tons of hay, and 5 tons of luiy to 36 bushels of wheat, and 12 bushels of wheat to 25 bushels of com, and 14 bushels of corn to 5Q pounds of butter, and 72 pounds of butter to 8 days of labor ; how many cords of wood will be equal to IG days of labor? Analysis. — Since 20 cords of wood arc equal to 6 tons of hay, 1 Ion of hay is equal to ^ of 20 cords of wood, or ^- cords ; 5 tons are equal to 5 times ^^ or ^^ cords ; since 5 tons of hay. or ^^ of a cord of AA"ood are equal to 36 bushel.s of wheat, 1 bushel of wheat is equal to ^-^ of ^^ = -|f cords, and 12 bushels of wheat are equal to 12 limes |^ = ^J cords ; and since 12 bushels of wheat, or ^^ cords of wood are equal to 25 bushels of corn, 1 bushel of corn is equal to ^V ^^ y = t of a cord of wood, and 14 bushels of corn are equal to 14 times f ~ 2_8 cords ; and since 14 bushels of corn, or 2_8 cords of wood are equal to 56 pounds of butter, 1 pound of butter is equal Jg. of 2J = ^ig^ of a cord, and 72 pounds of butter are equal to 72 times ^Ig = 4 cords of wood ; and since 72 pounds of butter or 4 cords of wood are equal to 8 days' labor, 1 day's labor is equal to -I- of A =:z ^ cord of wood, and 16 daj's labor are equal to 16 times -^ of a cord, or 8 cords of wood. 20 1 1 6 5 1 1 36 .| Xf>XiXor?Xi X4)--Xt X 12 T 1^ 25 OPERATION. 14 2 1 ^"56"^ 1 X^X8XY=8cord3;or, i0 ^ $0 $ t$ n $$ u n^ 10 8 cords. Ans. Note. — This and similar examples fall under what is called the Chain Rule. In analyzing, then, always commence with the ternj which is of the same name ur kind as the required answer. 334 ANALYSIS. 15. A, B, and C, put in trade $5626 : A's stock was in 5 months, B's, 7 months, and C's, 9 months. They gained $1260, wliich was so divided that A i-eceived $4 as often as B had $5; and as often as C had $3. After receiving 82164,50, B ab- sconded. What was each one's stock in trade, and how much did A and C gain or lose by B's withdrawal ? Analysis. — Since A received S4 as often as B had So, and as often aS C had $3, if the whole gain were divided into 12 equal parls, A would have ^. B, ^j. and C. y%, of $1260, or A would have S420, B, $525. and C. $315. Now. if their respective gains be divided by the luimber of months each one's stock continued in trade, the quo- tients will represent their monthly gains, viz., A's will be $420 -r 5 = S84 ; B's, $525 -r 7 = $75 ; and C's. $315 -r 9 = $35, which gives $194 as their whole gain for 1 month. But since each one's share of the gain for a given time will be to the whole gain for the same time, as each one's stock to the whole stock: it follows that, A will have ^^r-. B, J^. nnd C, y^^. of the whole stock, or A will have $2436, B, $2175, and C, $1015. When B ran away he was entitled to his original stock $21 75. and his share of the gain for 7 months, that is, to $2175 + $525 = $2700; but as he took away only $2164,50, A and C gained $535.50 by his with- drawal, which must be divided between Hicm in tlic ratio of their ' If investments, or as 4 to 3 ; therefore. A will have 4-. and C -f of B's unclaimed portion, or A will have $306, and C $229.50. OPERATION. 4 + 5 + 3 = 12. A's whole gain = j\ of SI 2 60 = $420 B's " " = y\ « « _ $525 C's " " = j% " " = $315 A's monthly gain = $420 -j- 5 =: $84 B's " " = $525 -f 7 = $75 C's " " = $315 — 9 = $35 $194 A's stock = /^ of $5626 = $2436 B's " = yVi " " =^2175 C's ** = T-Vr " " = $1015 ANALYSIS. So5 $2175 + $525 - $2164,50 = $535,50, what B left, i- of $535,50 = $306 A's share of it. 3. " « = $229,50 B's share of it. 16. Mr. Johnson bought goods to the amount of $2400, 1 to be paid in 3 months, i in 4 months, | in 6 montlis, and the remainder in 8 months : what is the equated time for the pay- ment of the whole ? Analysis.— SSOO to be paid in 3 months, is the same as $1^ to bo paid in 2400 months ; SGOO, in 4 months, the same as Si in 2400 months; $600, in 6 mouths; the same as $1, in 3600 months; and $400 in 8 mouths, the same as $1, in 3200 months. Then $1, payable in 2400 + 2400 + 3600 + 3200 = 11600 months, is the same as $2400 in 2^0^ of 11600 months, wliich is 4| months — 4 months 26 days, the equated time of payment. OPERATION. 800 X 3 = 2400 GOO X 4 = 2400 600.x 6 = 3600 400 X 8 = 3200 2400 11600 11600 -^ 2400 = 4|wo. = ioio. 25da. Ans. 17. What will be the interest on $60,48 for 1 year 3 months, at 7 per cent ? Analysis. — Since the interest on $1 for 1 year is 7 cents, or seven hundredths of SI. the interest on $60,48 for 1 year, will be $60,48 X .07 = $4.2336. The interest for 1 month wnll be ■^\ as much as for 1 year or ^ of $4.2236 = ^0.3528, and for \yr. 3mo. = 15 months, it will be 15 times as much as for 1 month, or $0,3528 x 15 = $5,292. OPERATION. ($60,48 X. 07 -f 12) X 15 = $5,292 yl?is. Or, i^ 5,04 ()0,4^ • 7 15 I $5,292 Ans. 18. What will be the interest on $88,92, for 8mo. 20Ja., at 7 per cent? 836 ANALYSia. Analysis. — Since the interest on ^1 is 7 cents for 1 year, the in- terest on $^88.92 for 1 year will be $88.92 x .07 = S6.224 ; the in- terest for 1 month will be ^-^ of $6,224 = $0,5187 ; and since the number of days divided by 30 will give the value of those days ia decimals of a month (Art. 222) 20c/a. = .6f months. The interesi for Pmo. 20cZa. = 8.6| months, will be 8.6|- times as much as for 1 mouth = 0.5187 X 8.6| = $4.4954. OPERATION. ($88,92 X .07-M2)x8.6f=$4,4954 A?is. n 2 47 .07 Or, .It 26 ^^ $0 '^"^ 26 I $4.4954 I S4.4954 An>s. 19. A liquor mercliant mixed together 25 gallons of brandy at $],60 a gallon, 25 gallons at $1,80, 10 gallons at $2,50, and 20 gallons of water ; wliat was the value of 1 gallon of the mixture, and what was the gain on a gallon if he sold it at the average price of the liquor ? Analysis. — The value of 20 gallons of water would be ; of 25 gallons of brandy at $1,60 a gallon would be $1,60 x 25 = $40; of 25 gallons at $1.80, would be $1.80 X 2a = $45 ; of 10 gallons at $2,50, would be $2.50 X 10 = $25. 25 + 25 + 10 gallons of brandy + 18 gallons of water = 80 gallons, the amount of the mixture; and $40 + $45 + 25 = $110, the value of the mixture; hence, if 80 gallons are wortli $110, one gallon is worth -^ of $110 = $1,371. But 25 + 25+10 = 60 gallons of brandy, arc worth $110, and $110 -- 60 = $1.83^, the average price per gallon of the brandy; therefore $1,83-J- — $1,37^ = 45|- cents, the gain oa 1 gallon. OPERATION. 20 X r^ 00 25 X l.GO = 40 25 X 1.80 -^ 45 10 X 2.50 = 25 80 no 8110-^80 = $l,37.V value: ^1 10 -f- G0=r$1.83i averagre price, 81,83^ - $1,371 = e0,45;;. ANALYSIS. 337 10. A merchant has three kinds of cloth, worth $lf, $2 J, fi^^a. yard : what is the least number of whole yards he can sell, to receive an average price of $2}, a yard ? Analysis. — If he sells 1 yard worth Sl|-, for $2 J, he will gain j of a dollar; to gain 1 dollar he must sell as many yards as | is contained times in 1, or -| yards. But since he is neither to gain or lose by the operation, if he gains on one kind, he must lose an equal 'mm on some other ; hence, he must sell some that is worth more ihan the average price. If he sell 1 yard worth $3|- for $2^^, he will lose -I of a dollar; and to lose $1, he must sell -|- of a yard. There- fore, to make the loss equal to the gain, he must sell ^ of a yard at $3|- a yard, as often as he sells I- of a yard at Slf a yard. If he sells 1 yard Avorth $2^, for $2i, ho gains -^ of a dollar, and to gain Si he must sell 4 yards ; hence, to keep the average price, he must lose as much on some other, and as he can only lose on that at $3-| a yard, he must sell enough of that to lose $1, which would be |- of a yard ; therefore, as often as he sells -| yards at Slf a yard, he must sell I yards at $3-| a yard; and as often as he sells 4 yards at $2^ a yard, he must sell -| yards at $3|- a yard. But since it is desirable to have the proportional parts expressed in the least whole numbers, we may multiply the numbers by the least common multiple of their denominators, and divide the products by their greatest common factor; this being done, we obtain in the above example, 3 yards at Sl| a yard. 10 yards at $2^ a yard, and 4 yards at $3| a yard. OPERATION. 3 10 4 21. The hour and minute hands of a clock are together at 12 o'clock : when are they next together ? Analysis. — Since the minute hand passes over 60 minute spaces while the hour-hand passes over 5. the minute-hand passes over 12 minute spaces while the hour-hand passes over 1, gaining 11 minute spaces on the hour-hand in 12 minutes of time ; the minme- hand requiring one minute of time to pass over 1 minute of space. Hence, in 1 minute of time, the minute-hand gains on the hour hand. \-^ of a minute space. n ' .5 6 6 ^ 4 20 20 4 5 4 5 4 4 8 OoS ANALYSIS. When the minntc-hand returns to 12, the hour-hand will be at 1, and M"ill require the niinute-hand to gain 5 minute spaces. As the minute-hand passes over -^^ the space gained, to gain 5 minute spaces it must pass over -i^ of 5 = ^^ = 5^j minute spaces, requirin"! 5^ minutes of time = 5ini. 27-^jSCC.^ which added to 1 o'clock, gives ihr. 5ini. 27-^^.sec. Second Analysis. — In 12 hours the minute-hand passes the hour- hand 11 times, consequently, if both are at 12, the minute-hand will pass the hour-hand the first time in ^ of 12 hours, or ihr. 5mi. 27^jscc. It will pass it the second time in -^ of 12 hours, and so on. OPERATION. 5 X -^-f = yy = h-^m'i. —. omi. 27-^scc., which added to Ihr. =r l//r. omi. 27^sec. Ans. 21. An apple boy bouglit a certain number of apples at the rate of 3 for 1 cent, and as many more at 4 for 1 cent, and selling them again at 2 for 1 cent, he found that he had gained 15 cents : how many apples had he ? Analysis. — Since he bought a number of apples at 3 for a cent, and as many more at 4 for a cent, he paid ^ of a cent apiece for the first, and ^ of a cent apiece for the second Jot : then, ^ + \ = ^ o( a cent, what he paid for one of each, and -^-t- 2 = -^ of a ceni, the average price for all he bought. Since he sold at 2 for a cent, or -J- a cent a piece, he must have gained on each apple the difference be- tween -^ and -^j = ^ of a cent ; hence, to gain 1 cent he must sell as many apples as -^ is contained times in 1 = 4-| apples, and to gain 15 cents he must sell 15 times as many, or 4-| x 15 ^ 72 apples. operation. Ill 7 7_L.9 7 1 7 5 3^4— T2' T^ ■ ^ ■ — TT' 2 2T — 2T' 1 -f ^\- = 4|, 4|- X 15 = 72 apples. .In*'. 22. A gentleman left to his three sons, whose ages were 13, 15 and 17 years, $15000, to be divided in such a maimer, that each share being put at interest, at 7 per cent, should give to each son the same amount when he attained the age of 21 years : wliat Avas the share of each ? ANALYSIS. 839 ANJi LYSIS. — By the question their respective shares would be at interest 8, 6 and 4 years. Find the present worth of $1 for 8, 6 and 4 years, respectively: They are S0.G41025G +, $0,7042253 + , and $0,78125. These s'nns teing put at interest at 7 per cent, will each amount to $1 at tho expiration of their respective times ; and the sum of these numbers, $0,6410256 + $0,7042253+^0,78125 = $2,1265009+ is the amount, which being so distributed among them, will produce $1 to each. If each number be divided by the sum, $2,1265009, the quotients will denote the parts of $1, which according to the conditions of the question, each person should receive, and which put at interest will produce equal amounts at the end of their respective times ; there- fore, each person will receive for his entire share 15000 like parts of one dollar. OPERATION. $1 -^ 1.56 = $0,6410256 + present worth of $1 for 8 years. $1 -^ 1.42 = $0,7042253 + " " " 6 " $1 -f- 1.28 = $0.78125 " « " 4 « $2,1265009 S0,6410256 -f 2.1265 x 15000 - $4521,694 $0,7042253 + 2.1265 x 15000 = $4967,494 $0,78125 -^ 2.1265 x 15000 = $5510,815 23. A, B, C, and D, agree to do a piece of work for $312. A, B, and C, can do it in 10 days ; B, C, and D, in 7-i- days ; C, D, and A, in 8 days ; and D, A, and B, in 8y days. In how many days can all do it, working together ; in how many days can each do it working alone ; and what part of the pay ought each to receive ? Analysis. — Since A, B, C, can do the work in 10 days, they can do -^-g = -^^ of it in 1 day : since B, C, D. can do it in 7-^ days, they can do ^^ = -^^ of it in 1 day; since C, D, A, can do it in 8 day.s, they can do ^ = ^^^ of it hi 1 day; and since D, A, B. can do it in 8^ days, they can do -^q = -^^ of it in 1 day ; hence. A, B, C, and D, by working 3 days each, will do ^2_ + ^^ + ^i^^ + ^i^ = -^^^ of the work, and in 1 day they will do } of ^^^ = J^. It will then tiike them as many days to do the whole as -^-^^ is contained times in 1 - 6^ days. 310 ANALYSIS AND By subtracting, in succession, what the three can do in 1 day, when tliey work together, from what the four can do in 1 day, we shall have what each one will do in 1 day ; viz., J^ — -^^ = -jl^, what D will do in 1 day; ^^ — I'^o — tIo'j what A can do in 1 day; ^ia-tio^ ihy ^^"li^t B can do in 1 day ; J=^ - t^o = Th: ^'^^^^ C can do in 1 day. It will take each as many days to do the whole work as the part which he can do in 1 day is contained times in 1 ; viz., 1 -I- y4o = 40 days. A's time to do it; 1 -|- j^ = 30 days, B's; 1 -- ^ = 24 days, C's ; 1 -;- j^ = 17-^ days. D"s. Now. each should receive such a part of the whole amount paid, viz., $312, as he did of the whole work. This part will be denoted by what he did in 1 day multiplied by the number of days he worked: viz., A. ^X6^%=^-^: B, j^^x6^^=^-^; 0,^1^x0^ = 19- '''•1^0'^"l9 19- OPERATION. ■j^ = i\fo5 ^'l^at A, B, C, does in 1 day. _2_ _ .UL "BCD " " 8 — 120' ^' -^J -^J _7_ _ 1 4_ " 71 A R " « fiO — 120' -^> -^5 ^> t¥o + -i^'o + T^ + i'^ = t¥u' ^v^at A, B, C, and D, can do in 3 days. yYo -7- 3 r= jL^y, what A, B, C, and D, can do in 1 day. y'^^o — y"^ = jfo^ what A can do in 1 day ; 1 -i- yf ^ — AOda. T2 120 — 120 -^J ■*■ • TTo — ^^""* JL9- _ JIJ_ _ _5_ « n u li 1 _i_ ,5_ _ 94 7 T20 l-'O — 120 ^» ■*■ • 120 — •2: what sum, on the first day of April, 1853, will o*UH',':l the bond ? APPLICATIONS OF AllITHMETIC. MENSURATION. 329. Mensukation embraces all the methods of determining the contents of geometrical figuies. It is divided into two parts, the raeniiiration of surfaces and the mensuration of Volumes. 1 foot. o MENSURATION OP SURFACES. 330. Surfaces have length and breadth. They are measured by means of a square, which is called the unit of surface. A square is the space included between four equal lines, drawn perpendicular to each other. Each line is called a side of the square. If each side be one foot, the figure is called a square foot. If the sides of a square be each four feet, the square will contain sixteen square feet. For, in the large square there are sixteen small squares, the sides of which are each one foot. Thei'efore, the square whose side is four feet, contains sixteen square feet. The number of small squares that is con- tained in any large square is always equal to the product of two of the sides of the large square. As in the figure, 3x3 = 9 square feet. The number of square inches contained in a square foot is equal lo 12 x 12 = 144. 329. What is mensuration 1 330. What is a surface i What is a square 1 ^Miat is tlic luiiuber ol small fciiuart's coutained ia a large square equal to 1 MElvrSUKATION 331. A triangle is a figure bounded by three straight lines. Thus, ACB is a triangle. The lines BA, AC, BC, are called sides ; and the corners, B, A and C, are called angles. The side AB is the base. When a line like CD is drawn, making the angle CDA equal to the angle CDB, then CD is said to be perpendicular to AB, and CD is called the altitude of the triangle. Each triangle CAD or CDB is called a right-angled triangle. The side BC, or the side AC, opposite the right angle, is called the hypothenuse. The area or contents of a triangle is equal to half the product of its base by its altitude (Bk. IV., Prop. VI).* OPERATION. 50 30 2)1500 Ans. 1 bO square yards. EXAMPLES. 1. The base, AB, of a triangle is 50 yards, and the perpendicular, CD, 80 yards : what is the area ? Analysis. — We first multiply the base by the altitude, and the product is square yards, which "vve divide by 2 for the area. 2. In a triangular field the base is GO chains, and the pei*- pendicular 12 chains : how much does it contain ? 3. There is a triangular field, of wliich the base is 45 rods, and tlic perpendicular 38 rods : what are its contents ? 4. Wliat are the contents of a triangle whos.e base is 75 chains, and perpendicular 36 chains ? 332. A rectangle is a four-sided figure like a squai'e, in which the sides are perpendicular to each other, but the adjacent sides are not ?qual. * All the references are to Davies' Letrendrc. 331. What is a triangle ? What is the base of a triangle'! What the I'lliliulo? What is a rirjht-angled triangle 1 Which side is the hypo- tlicniise 1 What is the aica of a triangle equal to \ ■M'i. Wluit i^ a rectangle ? \ or suKFACKs. 353 333. A parallelogram is a foux*-sided figure which has its opposite sides equal and parallel, but its angles not right- angles. The line DE, perpendicular to - p the base, is called the altitude. 334. To find the area of a square, rectangle, or parallelogram. Multiply the hase by the 2^cfpendicular height, and the -product will he the area (Bk. IV., Prop. Y.) EXAMPLES. 1. What is the area of a square field, of which the sides are each 6G.16 chains ? 2. What is the area of a square piece of land, of which the sides are 54 chains ? 3. What is the area of a square piece of land, of which the sides are 75 rods each ? ' 4. What are the contents of a rectangular field, the leno;th of which is 80 rods, and the breadth 40 rods ? 5. What are the contents of a field 80 rods square ? 6. What are the contents of a rectangular field, 30 chains long and 5 chains broad ? 7. What are the contents of a field, 54 chains long and 18 rods broad ? 8. The base of a parallelogram is 542 yards, and the per- pendicular height 720 feet : Avhat is the area ? 335. A trapezoid is a four-sided figure d E ABCD, having two of its sides, AB, DC, parallel. The perpendicular EF is call- -^d the altitude. A F B 336. To find the area of a trapezoid. Multiply the sicni of the two parallel sides hy the altitude, 333. What is a parallelogram T 834. How do you find the area of a square, rectangle, or parallelogram 1 335. ^^'hat is a trapezoid 1 330. How do you find the area of a trapezoid ? If) 854: MENSURATION OPERATION. 643.02 + 428.48 = 1071.50 = sum of parallel sides. Then, 1071.50x342.32 = 366795.88; and S^&l^&JSA ^ 183397.94 = the area. divide the p7-oduct hj 2, and the quotient will he the area (Bk. IV. Prop. VII). EXAMPLES. 1. Required the area or contents of the trapezoid ABCD, hav- ing given AB=G43.02 feet, DC = 428.48 feet, and EF = 342.32 feet. Analysis. — We tirst find the sum of the sides, and then multiply it by the perpendicular height, after which we divide the product by 2. for the area. 2. What is the area of a trapezoid, the parallel sides of which are 24.82 and 16.44 chains, and the perpendicular distance between them 10.30 chains? 3. Required the area of a trapezoid, whose parallel sides are 51 feet and 37 feet 6 inches, and the perpendicular distance between them 20 feet and 10 inches. 4. Required the area of a trapezoid, whose parallel sides are 41 and 24.5, and the perpendicular distance between them 21.5 yards. 5. What is the area of a trapezoid, whose parallel sides are 15 chains, and 24.5 chains, and the perpendicular height 30.80 chains ? 6. What are the contents of a trapezoid, when the parallel sides are 40 and 64 chains, and the perpendicular distance between them 52 chains ? 337. A circle is a portion of a plane bounded by a curved line, every point of which is equally dis- tant from a certain point within, called the centre. The curved line AEBD is called the circumference; the point C the centre ; the line AB passing through the centre Ti, did meter ; and C'li n radius. TIic circiiniierence AEBD is 3.1416 times as great as the diiuneter AB- OF SUKFACES, 855 Hence, if the diameter is 1, the circumference Avill be 3.1416. Therefore, if tlie diameter is known, the circumference is found hy multiplying 3.1416 by the diameter (Bk. V. Prop. XIV). EXA3IPLES. ' 1. The diameter of a circle is 8 : what is the circumference ? OPERATION. Analysis. — The circumference is found 3.1416 by simply multiplying 3.1416 by the di- 8 ameter. » Ans. 25.1328 2. The diameter of a circle is 186 : what is the circum- ference ? 3. The diameter of a circle is 40 : what is the circum- ference ? 4. What is the circumference of a circle whose diameter is ? 338. Since the circumference of a circle is 3.1416 times as great as the diameter, it follows, that if the circumference is known, we may find the diameter by dividing it by 3.1416. EXABIPLES. 1. What is the diameter of a circle whose circumference is 157.08? OPERATION. Analysis. — We divide the circumference 3.1416)157.080(50 by 3.1416, the quotient 50 is the diameter. 157.080 2. Wliat is the diameter of a circle whose circumference i3 23304.3888 ? 3. What is the diameter of a circle whose circumference is 13700 ? 337. What ir- a circle 1 What is the centre ? What is the circumfer- ence ': What is the diameter 1 What the radius 1 How many times greater is tliC circumference th.m the diameter 1 How do you find the circumference when tlie diameter is known ? 33S. How do you find the diameter when the circumference is knuwu 1 356 MEKSdRATION 339. To find the area or contents of a circle. Multlphj the square of the diameter by the decimal .7854 (Bk. V. Prop. XII. Cor. 2). EXA3IPLES. 1. What is the area of a circle whose diameter is 12 ? Analysis.— We first square the diam- operation. 2 eter, giving 144, which we then multi- 12 = 144 ply by the decimal .7854 : the product 144 x .7854 = 113.0976 is the area of the circle. Ans. 113.0976 2. What is the area of a circle whose diameter is 5 ? 3. What is the area of a circle whose diameter is 14 ? 4. How many square yards in a circle whose diameter is d^ feet? 340. A sphere is a portion of space bounded by a curved surface, all the points of which are equally distant from a certain point within, called the centre. The line AD, passing through its centi-e C, is called the diameter of the sphere, and AC its radius. A 341. To find the surface of a sphere, Multiply the square of the diameter by 3.1416 (Bk. VHL Prop. X. Cor.) EXAMPLES. 1. What is the surface of a sphere whose diameter is 6 ? OPERATION. Analysis. — We simply multiply the number 3,1416 3.1416 by the .square of the diameter : the pro- 6'= 36 duct is the surface. Ans. 1 13.076 339. How do you find the area of a circle ? 340. What is a sphrre ? \\'hat is a iliameterl What is a radius^ 341. How do you find the surface of a gpherc ? OF VOLUME. 357 3 feet = 1 yard. 2. What is the surface of a sphere whose diameter is 1 4 ? 3. Required the number of square inches in the surface of a sphere whose diameter is 3 feet or 36 inches. 4. Required the area of the surface of the earth, its mean diameter being 7918.7 miles. MENSURATION OF VOLUMES. 342. A SOLID or VOLUME is a portion of space h-iving tliree dimensions : length, breadth, and thickness. It is measured bj a cule called the cuhic unit, or unit of vohime. A CUBE is a volume having six equal faces, which are squares. If the sides of the cube lie each one foot long, the figure is called a cubic foot. But when the sides of the cube are. one yard, as in the figure, it is called a cubic yard. The base of the cube, which is the face on which it stands, contains 3x3 = 9 square feet. Therefore, 9 cubes, of one foot each, can be placed on the base. If the figure were one foot high it would contain 9 cubic feet ; if it were 2 feet high it would contain two tiers of cubes, or 18 cubic feet ; and if it were 3 feet high, it would contain three tiers, or 27 cubic feet. Hence, the contents of stick a f (jure arc equal to the "product of its lengthy breadth, and height. 343. To find the contents of a sphere, Multiply the surface by the diameter, and divide the product by 6, the quotient will be the contents (Bk. VIII. Prop. XIV. Sch. 3). EXAMPLES. 1. What are the contents of a sphere whose diameter is 12 ? 342. What i.s a volume ] AVhat is a cube 1 W!i«t is a cubic foot ? What is a cubic yard 1 How many cubic feet in a cubic yard ■! What are the contents of a figure of three dimensions equal to 1 :i'iri. Hov.' di> you ihid the contetit.s of a sphered 858 MENSUKATION Analysis. — We first find the surface by multiplying the square of the diam- eter by 3.1416. We then multiply the surface by the diameter, and divide the product by 6. OPi RATION, 12"= 144 mulliply by 3.1416 surface 452.3904 diameter ] 2 solidity 904.7808 2. What are the contents of a, sphere whose diameter is 8 ? 3. What are the contents of a sphere whose diameter is 16 inches ? 4. What are the contents of the earth, its mean diameter being 7918.7 miles? 5. What are the contents of a sphere whose diameter is 12 feet? 344. A prism is a volume whose ends or bases are equal plane figures and whose faces are par- allelograms. The sum of the sides which bound the base is called the perimeter of the base, and the sum of the pai'allelograms which bound the prism is called the convex surface. 34.5. To find the convex surface of a ri"'ht prism. Multiply the perimeter of the base hi/ the perpendicular height, and the product will he the convex surface (Bk. VII. Prop. I). EXAMPLES. 1. What is the convex surface of a prism whose base is bounded by five equal sides, each of which is 35 feet, the alti- tude being 52 feet ? 2. AVhat is the convex surface when there are eight equal sides, each 15 feet in length, and tlie altitude is 12 feet? 344. What is a prism 1 What is the perimeter of the base 1 What ia the convex surface ] 345. How do you find tlic convex surface of a prism ? 34G. How do you find Iho contPiit:! of a prinui 1 OF VOLUM]':. ;J59 346. To find the contents of a prism, Multiply the area of the base by the altitude, and the product will be the contents (Bk. VII. Prop. XIV). EXAMPLES. 1. What are the contents of a square prism, each side of the square -which forms the base being IG, and the ahitude of the prism 30 feet ? OPERATION. Analysis. — We first tind the area of the square 16^— 256 which forms the base, and then multiply by the 30 altitude. Ans. 7 680 2. What are the contents of a cube, each side of Avliich is 48 inches ? 3. How many cubic feet in a block of marble, of which the length is 3 feet 2 inches, breadth 2 feet 8 inches, and height, or thickness 5 feet ? 4. How many gallons of water will a cistern contain, whose dimensions are the same as in the last example ? 5. Required the solidity of a triangular prism, whose height is 20 feet, and area of the base G91. 347. A Cylinder is a volume generated by the revolution of a rectangle AF about EF. The line EF is called the axis or alti- tude — the circular surface, the convex surface of the cylinder, and tlie circular ends, the bases. 348. To find the convex surface of a cylinder, Multiply the circumference of the base by the altitude, and the product will be the convex surface (Bk. VIII. Prop. I). 347. What is a cylinder 1 What is the axis or altitude T What is tho convex surface 1 348. How do you find the convex surface ! 3 GO MENSTIRA.TION EXASIPLES. 1. "What is the convex surface of a cylinder, the diameter of whose base is 20 and the altitude 40 ? OPKRATION. AxALVSis. — We first multiply 3.1416 by 3.1416 the diameter, which gives the circumfer- 20 ence of the base. Then, multiplying by 62.8320 the altitude, we obtam the convex sur- 40 face. Ans. 2513.2800 2. "What is the convex surface of a cylinder whose altitude is 28 feet and the circumference of its base 8 feet 4 inches ? 3. What is the convex surface of a cylinder, the diameter of whose base is 15 inches and altitude 5 feet ? 4. What is the convex surface of a cylinder, the diameter of whose base is 40 and altitude 50 feet ? 349. To find the volume of a cylinder, 3Ii(ltiph/ the area of the base by the altitude : the product will he the contents or volume (Bk. VIII. Prop. II), EXAMPLES. 1. Required the contents of a cylinder of which the altitude is 11 feet, and the diameter of the base 16 feet. Analysis. — We first find the area of the operation. base, and then multiply by the altitude: 16^ = 256 the product is the solidity. .7854 2. What are the contents of a cylin- ^"^^^ ^^'®' 201-0624 der, the diameter of whose base is 40, ' , . , „^^ 2211.6864 and the altitude 29 ? 3. ^Vliat are the contents of a cylinder, the diameter of whose base is 24, and the altitude 30 ? 4. "V\''hat are the contents of a cylinder, the diameter of whose base is 32, and altitude 12 ? 5. "What are the contents of a cylinder, the diameter of whose base is 25 feet, and altitude 15 ? U4'J IIow do you find the contents of a cyliudcr 1 OF VOLTTME. 861 350. A Pyramid is a volume bounded by several triangular planes united at the same point S, and by a plane figure or base ABODE, in which they terminate. The altiude of the pyramid is the line SO, drawn perpendicular to the base. 351. To find the contents of a pyramid. 3fultipli/ the area of the base by the altitude, and divide thd product by 3 (Bk. VII., Prop. XVII). EXAMPLES. 1. Required the contents of a pyramid, the area of whose base is 86, and the altitude 24. OPERATION. 86 24 3);i0tJ4 Analysis. — We simply multiply the area of the base 86, by the altitude 24. and then divide the Ans. 688 product by 3. 2. What are the contents of a pyramid, the area of whose baso is 3G5, and the altitude 36 ? 3. What are the contents of a pyramid, the area of whose base is 207, and altitude 36 ? 4. What are the contents ef a pyramid, the area of whose base i.s oG2, and altitude 30 ? 5. What are the contents of a pyramid, the area of whose base is 540, and altitude 32 ? 6. A pyramid has a rectangular base, the sides of which are 50 and 24; the altitude of the pyramid is 36: what are its contents ? 7. A pyramid with a square base, of which each side is 15, has an ahitude of 24: what are its contents ? 350. What is a pyramid 1 What is the altitude of a pyramid ] 351. How do you find the contents of a pyramid 1 GAUGING. 352. A Cone is a volume generated by the revolution of a ri^'bt ani^led trianerle ABC, about the side CB. The point C is tli(! vertex, and the line CB is called the axis or altitude. 353. To find the contents of a cone. Multiply the area of the base hj the altitude, and divide the product by 3 ; or, midtiply the area of the base by one-third of the altitude (Bk. VIII., Prop. V.) EXAMPLES. 1. Required the contents of a cone, the diameter of whose base is 6, and the altitude 11. OPERATION. 6^ = 36 .7854 = 28.2744 n 3)311.0184 Ans. 103.(j728 Analysls. — We fir.st square the diame- ter, and multiply it by .7854, which gives 36 x the area of the base. We next multiply by the altitude, and then divide the pro- duct by 3. 2. What are the contents of a cone, the diameter of whose base is 36, and the altitude 27 ? 3. What are the contents of a cone, the diameter of whose base is 35, and the altitude 27 ? 4. What are the contents of a cone, whose altitude is 27 feet, and the diameter of the base 20 feet ? GAUGING. 354. Cask-Guaging is the method of finding the number of gallons which a cask contains, by measuring the external dimensions of the cask. 352. Wh&t is a cone \ What is the vertex ? What is the axis I 3.')3. How do you find llio contents of a cone ? 364. What is cask-gauging \ GAUGING. S63 355. Casks are divided into four varieties, according to the curvature of their sides. To wliicli of the varieties any cask belongs, must be judged of by inspection. 1st Variety — least curvature. 2d Variety. 3d Variety. 4th Variety — greatest curvature. 356. The first thing to be done is to find the mean diameter. To do this. Divide the head diameter hy the hung diameter, and find the quotient in the first column of the following table, marked Qu. Then if the hung diameter he midtiplied hy the number on the same line with it, and in the column answering to the proper variety, the product will he the true mean diameter, or the diame tcr of a cylinder having the same altitude and the same con tents with the cask projMsed. oCi5. Into how many varieties are casks divided ! ^56. How do you liiid tlic mean diameter 1 3(54 GAUGING. Qu. 50 mVai. •2dVar. 3dVar. 4thVar. Qu. 1st Var. 2d Var. 3d Var. 4th Var. 8660 8465 7905 7637 76 9270 9227 8881 8827 51 8680 8493 7937 7681 77 9296 9258 8944 8874 52 8700 8520 7970 7725 78 9324 9290 8967 8922 53 8720 8548 8002 7769 79 9352 9320 9011 8970 54 8740 8576 8036 7813 80 9380 9352 9055 9018 55 8760 8605 8070 7858 81 9409 9383 9100 9066 56 8781 8633 8104 7902 82 9438 9415 9144 9114 57 8802 8662 8140 7947 83 9467 9446 9189 9163 58 8824 8690 8174 7992 84 9496 9478 9234 9211 59 8846 8720 8210 8037 85 9526 9510 9280 9260 60 8869 8748 8246 8082 86 9556 9542 9326 9308 61 8892 8777 8282 8128 87 9586 9574 9372 9357 62 8915 8806 8320 8173 88 9616 9606 9419 9406 63 8938 8835 8357 8220 89 9647 9638 9466 9455 64 8962 8865 8395 8265 90 9678 9671 9513 9504 65 8986 8894 8433 8311 91 9710 9703 9560 9553 66 9010 8924 8472 8357 92 9740 9736 9608 9602 67 9034 8954 8511 8404 93 9772 9768 9656 9652 68 9060 8983 8551 8450 94 9804 9801 9704 9701 69 9084 9013 8590 8497 95 9836 9834 9753 9751 70 9110 9044 8631 8544 96 9868 9867 9802 9800 71 9136 9074 8672 8590 97 9901 9900 9851 9850 72 9162 9104 8713 8637 98 9933 9933 9900 9900 73 91 88 9135 8754 8685 99 9966 9966 9950 9950 74 9215 9166 8796 8732 100 10000 10000 10000 10000 75 9242 9196 8838 8780 EXAMPLES. 1. Supposing the diameters to be 32 and 24, it is required to find the mean diameter for each variety. Dividing 24 by 32, we obtain .75 ; which being foimd in the column of quotients, opposite thereto stand the numbers. .9242 .919G .8838 .8780 which being each mul- >. tiplied by 82, produce respectively, 20.5744 29.4272 28.2816 28.09G0 for the correspond- \. ing menn diameters required. 2. The head diameter of a cask is 2G inches, and the bung diameter 3 feet 2 inches : what is the mean diameter, the cask being of the thii'd variety ? 3. The head diameter is 22 inches, the. bung diameter 34 inches •• what is the mean diameter of a cask of the fourth variety? GAUGING. SG5 357. Having found the mean diameter, we multiply the square of the mean diameter by the decimal .7854, and the product by the length ; this -will give the contents in cubic inches. Then, if we divide by 231, we have the contents in wine gallons (see Art. 414), or if we divide by 282, we have the contents in beer gallons (Art. 415). Analysis. — For wine measure, we mul- operation. tiply the length by the square of the mean I X d^ x tj^^* = diameter, then by the decimal .7854, and I X d^ X .0034. divide by 231. If then, we divide the decimal .7854 by 231, the quotient carried to four places of decimals is .003 1, and this decimal multiplied by the square of the mean diameter and by the length of the cask, will give the contents in wine gallons. For similar reasons, the content is found operation. in beer gallons by multiplying together the I X d- X 'l^^ = length; the square of the mean diameter, I X d'- X .0028. and the decimal .0028. Hence, for gauging or measuring casks, 31ultiply the length by the square of the mean diameter ; then midt'ply by 34 for wine, and by 28 for beer measure, and point off in the product four decimal places. The product will then express gallons and the decimals of a gallon. 1. How many wine gallons in a cask, whose bung diameter is 36 inches, head diameter 30 inches, and length 50 inches; the cask being of the first variety ? 2. What is the number of beer gallons in the last example ? 3. How many wine, and how many beer gallons in a cask whose length is 36 inches, bung diameter 35 inches, und head diameter 30 inches, it being of the first variety ? 4. How many wine gallons in a cask of which the head diameter is 24 inches, bung diameter 36 inches, and length 3 feet 6 inches, the cask being of the second variety ? t357. How do you find the contents in cubic inches 1 How do you find the contents in wine gallons 1 lu beer gallons 1 S6(J MECHANICAL P0WEK3. OF THE MECHANICAL POWERS. 358. There are six simple machines, which are called Mechanical 2)0wers. They are, the Lever, the Pulley, the Wheel and Axle, the Inclined Plane, the Wedge, and the Screw. 359. To understand the nature of a machine, four things must be considered. 1st. The power or force which acts. This consists in the efforts of men or horses, of weights, springs, steam, &;c. 2d. The resistance which is to be overcome by the power. This generally is a weight to be moved. 3d. We are to consider the centre of motion, or fidcrum, which means a prop. The prop or fulcrum is the point about which all the parts of the machine move. 4th. We are to consider the respective velocities of the power and resistance. 360. A machine is said to be in equilibrium when the resist- ance exactly balances the power, in which case all the parts of the machine are at rest, or in uniform motion. We shall first examine the lever. 361. The Lever, is a bar of wood or metal, which moves around a fixed point, called the fulcrum. There are three kinds of levers. 1st. When the fulcrum is between the weight and the power. 358. How many simple machines are there ^ What are they called 1 359. What things must be considered, in order to understand the power of a machine 1 300. When is a machine said to be in equilibrium? 361. What is a lever 1 How many kinds of levers are there ? Describe the first kind \ Where is the weight placed in the second kind \ Where ia the power placed in the third kind ] MECIIANIUAL POWERS. 367 2d. "When the weight is be- tween the power and the ful- crum. 3d. When the power is be- tween the fulcrum and the weight. The perpendicular distance from the fulcrum to the direc- tions of the weight and power, are called the ar/ra< of the lever. 362. An equilibrium is produced in all the levers, when the weight multiplied by its distance from the fulcrum is equal to tlie power multiplied bj its distance from the fulcrum. That is, The iveight is to the power, as the distance froin the poxoer to the fulcrum, is to the distance from the weight to the fulcrum. EXAMPLES. 1. In a lever of the first kind, the fulcrum is placed at the middle point : what power will be necessary to balance a weight of 40 pounds ? 2. In a lever of the second kind, the weight is placed at the middle point : what power will be necessary to sustain a weight of bOlhs. ? 3. In a lever of the third kind, the power is placed at the middle point : what power will be necessary to sustain a weight of imhs. ? 4. A lever of the first kind is 8 feet long, and a weight of QOlbs. is at a distance of 2 feet from the fulcrum : what power will be necessary to balance it ? 362. When is an equilibrium produced in all the levers ! What is then the proportion between the weight and power 1 BG3 MECHANICAL POWERS. 5. In a lever of the first kind, that is 6 feet long, a weiglit of 200/is. is placed at 1 foot from the fulcrum : what power will balance it ? 6. In a lever of the first kind, like the common steelyard, the distance from the weight to the fulcrum is one inch : at what distance from the fulcrum must the poise of lib. be placed, to balance a weight of 1Z6.? A^\eightof^lbs.? 0{2lbs.?Of4:lbs.? 7. In a lever of the third kiqd, the distance from the fulcrum to the power is 5 feet, and from the fulcrum to the weight 8 feet : what power is necessary to sustain a weight of AOlbs. ? 8. In a lever of the third kind, the distance from the fulcrum to the weight is 12 feet, and to the power 8 feet : what power will be necessary to sustain a weight of lOOlbs. ? 363. Rejiarks. — In determining the equilibrium of the lever, •we have not considered its weight. In levers of the first kind, the weight of the lever generally adds to the power, but in the second and third kinds, the weight goes to diminish the effect of the power. In the previous examples, we have stated the circumstances under which the power will exactly sustain the weight. In order that the power may overcome the resistance, it must of course be somewhat increased. The lever is a very important mechanical power, being much used, and entering, indeed, into most other machines. OF THE PULLET. 364. The pulley is a wheel, having a groove cut in its circumference, for the pur- pose of receiving a cord which jiasses over it. When motion is imparted to the cord, the pulley turns around its axis, which is generally supported by being attached to a beam above. 363. Has the wciiiht been consiilercd in detprmining the eoiiilihrijm of the levers 1 In a lever of the first kind, will the weight increase oj dimii*- iih the power? How will it be in the two other kiuds 1 a(i4. What is a imllcy ! MICCUANIOAL POWEKS. 8G9 365. Pulleys are divided into two kinds, fixed pulleys and movable pulleys. "When the pulley is fixed, it does -not in- crease the power which is applied to raise the weight, but merely changes the direction in which it acts. 3G6. A movable pulley gives a mechan- ical advantage. Thus, in the movable pulley, the hand which sustains the cask actually supports but one-half the weight of it ; the other half is supported by the hook to which the other end of the cord is attached. 367. If we have several movable pul- leys, the advantage gained is still greater, and a very heavy weight may be raised by a small power. A longer time, however, will be required, than with the single pulley. It is, indeed, a general principle in machines, that lohat is gained in 2J0wer, is lost in time ; and this is true for all machines. There is also an actual loss of power, viz., the resist- ance of the machine to motion, arising from the rubbing of the parts against each other, which is called the friction of the machine. This varies in the diiferent machines, but must always be allowed for, in calculating the power necessary to do a given w^ork. It would be wrong, however, to suppose that 365. How many kinds of pulleys are there ? Does a fixed pulley givo any increase of power"! ::!6';. Does a movable pulley give an}' mechanical advantage \ In a eingle movable pulley, how much less is the power than the weight? 'Ml . Will an advantiige l>s gained \iy several niovalile ptilleya 1 Statu r \ VI 370 MECUANICAL POWEKS. the loss was equivalent to the gain, and that no advantage is derived from the mechanical powers. We are unable to aug- ment our strength, but, by the aid of science we so divide the resistance, that by a continued exertion of power, we accom- plish that which it would be impossible to effect by a single effort. If in attaining this result, we sacrifice time, we cannot but see that it is most advantageously exchanged for powei". 368. It is plain, that in the movable pulley, all the parts of the cord will be equally stretched, and hence, each cord running from pulley to pulley, will bear an equal part of the weight ; consequently. The power will always be equal to the weight divided hy the 7iumber of cords which reach from pidley to pidley. EXAMPLES. 1. In a single immovable pulley, what power will support a weight of QOlbs. ? 2. In a single movable pulley, what power will support a weight of SOlbs. ? 3. In two movable pulleys with 4 cords, (see last fig.,) what power will support a weight of lOOlbs.? WINCH, OK "WHEEL AND AXLE. 369. This machine is com- posed of a wheel or crank — firmly attached to a cylindri- cal axle. The axle is sup- ported at its ends by two pivots, which are of less diameter than the axle around wliich the rope is coileil, and which turn freely about the points of support. In order to balance the weight, we must have. MECHANICAL POWERS. 371 Tlie power to the weight, as the radius of the axle, to the length of the crank, or radius of the wheel. EXAMPLES. 1. What must be the length of a crank or radius of a -wheel, in order that a power of 40/^5. may balance a weight of QOOlbs. suspended from an axle of 6 inches radius ? 2, "What must be the diameter of an axle, that a power of lOOlbs. applied at the circumference of a wheel of 6 feet diame- ter may balance 400/fo. ? INCLINED PLANE. 380. The inclined plane is nothing more than a slope or declivity, which is used for the purpose of raising weights. It is not difficult to see that a weight can be forced up an inclined plane, more easily than it can be raised in a vertical line. But in this, as in the other machines, the advantage is obtained by a partial loss of power. Thus, if a Aveight W, be supported on the in- clined plane ABC, by a cord passing over a pul- ley at F, and the cord from the pulley to the weight be parallel to the length of the plane AB, the power P will balance the weight W, when P : W :: height EC : length AB. the general principle in machines. What does the actual loss of power arise from 1 What is this rubbing called 1 Does this vary in different machines I 36S. In the movable pulley, what proportion exists between the cord and the weight 1 369. Of what is the machine called the wheel and axle, composed? How is the axle supported I Give the proportion between the power and tho weight. 370. What is an inclined plane ? What proportion exists between the power and weight when they are in equilibrium 1 372 MECHANICAL POWEliS. It is evident, that the power ought to be less than the weight, since a part of the weight is supported by the plane : hence, The power is to the loeight as the height of the plane is to its length. exa:^iples. 1. The length of a plane is 30 feet, and its height 6 feet: what power will be necessary to balance a weight of 2Q0lhs. ? 2. The height of a plane is 10 feet, and the length 20 feet : what weight will a power of bOlhs. support ? 3. The height of a plane is 15 feet, and length 45 feet : what power Avill sustahi a weight of l^Olbs. ? THE WEDGE. 381. The wedge is composed of two inclined planes, united together along their bases, and forming a solid ACB. It is used to cleave masses of wood or stone. The resistance Avhich it over- comes is the attraction of cohesion of the body which it is employed to sepa- rate. The wedge acts principally by being struck with a ham- mer, or mallet, on its head, and very little effect can be produc- ed with it, by mere pressure. All cutting instruments are constructed on the principle of the inclined plane or wedge. Such as have but one sloi)ing edge, like the chisel, may be referred to the inclined plane, axid such as ha\-e two, like the axe and the knife, to the wedge. Half the thickness of the head of the wedge is to the length of one of its sides, as the power which acts against its head to the effect produced at its side, EXAMPLES. 1. If the head of a wedge is 4 inches thick, and the length 371 \^'liat is the wedge 1 What is it used for 7 "What resistance is it used to overcome ! MECHANICAL POWERS. 873 of one of its sides 12 inches, what will measure the effect of a force denoted by 96 pounds ? 2. If the head of a wedge is 6 inches thick, the length of the side 27 inches, and the force applied measure by 250 pounds, what will be the measure of the effect ? THE SCREW. 381. The screw is composed of two parts — the screw S, and the nut N. The screw S, is a cylinder with a spiral projection winding around it. The nut N is per- forated to admit the screw, and within it is a groove into which the thread of the screw fits closely. The handle D, which projects from the nut, is a lever which woj'ks the nut upon the screw. The power of the screw depends on the distance between the threads. The closer the threads of the screw, the greater will be the power ; but then the number of revolutions made by the handle D, will also be proportiona- bly increased ; so that we return to the general principle — what is gained in power is lost in time. The power of the screw may also be increased by lengthening the lever attached to the nut. The screw is used for compression, and to raise heavy w^eights. It is used in cider and wine-presses, in coining, and for a variety of other purposes. As the distance between the threads of a screw is to the circum- ference of the circle described hy the power, so is the power em- ployed to the weight raised. 381. Of how many parts is the screw composed ? Describe the screw. What is the thread \ What is the nut ? What is the handle used fori To what uses is the screw appUed '' What is the power of tlic screw ? Oli QUESTIONS IN PHILOSOPHT. EXAMPLES. 1. If the distance between the thi-eads of a screw is half an inch, and the circumference described by the handle 15 feet, what weight can be raised bj a power denoted by 720 pounds ? 2. If the threads of a screw are one-third of an inch apart, and the handle is 12 feet long, what power must be applied to sustain 2 tons ? 3. "What force applied to the handle of a screw 10 feet long, >vith threads 1 inch apart, working on a wedge whose head is 5 inches, and length of side 30 inches, will produce an effect measured by lOOOOlbs. ? 4. If a^ower of 300 pounds applied at the end of a lever 15 feet long will sustain a weight of 282744/^5., what is the distance between the threads of the screw ? QUESTIONS IN NATURAL PHILOSOPHY. UNIFORM MOTION. 382. If a moving body passes over equal spaces in equal successive small portions of time, it is said to move with uni- form motion, or uniformly. 383. The velocity of a moving body is measured by the space passed over in a second of time. 384. The space passed over in any time is equal to the pro- duct of the velocity multiplied by the number of seconds in the time. If we denote the velocity by V, the space passed over by S, and the time by T, we have S = V X T. 382. What is a unilorm motion 1 383. Wliat is the velocity of a moving body 1 384. To wliat is tl)C space passed over in a unit of time equal 1 What lb the span; passed over equal to, in uniform motion ' QUESTIONS IN PHILOSOPHY. 375 EXAMPLES. 1. A steamboat moves with a velocity of 23 feet: what space does it pass over in 1\ hours ? 2. A locomotive is moving with a velocity of 32 feet : what distance will it travel in 3 minutes ? 3. A horse travels uniformly a distance of 12 miles with a velocity of 6 feet : what time does he require to perform the journey ? 4. A carriage performs a journey of 15 miles in 2|- hours : with what velocity does it move ? 5. The hammer of a pile-driver is moved upwai'd a distance of *35 feet with a velocity of 1-^ feet : what time is required to raise it ? 6. A ton of coal is raided from a mine 1000 feet deep in 3^ minutes : with what velocity does it move ? 7. A vessel containing a criminal, after leaving a port, sailed with a daily speed of 170 miles ; four days after, a clipper was dispatched in pursuit, and sailed at a daily rate of 275 miles : in what time did the clipper overtake the vessel ? 8. A bird flew a distance of 100 miles in 11 hours: with what velocity did it travel ? 9. Sound moves with a velocity of 1127 feet. If the report of a gun was heard 31.3 seconds after the flash was seen, what distance was the gun from the observer ? 10. A hurricane moves with a velocity of 95 feet : what time does it take to move through 3 degrees of latitude, the degree being estimated at G91 miles ? 11. The velocity of light has been found, by astronomical observations, and by experiments made in France, to be 191,300 miles : what time will it occupy to traverse the mean distance of the earth from the sun, or 95000000 of miles ? 12. If a message sent by electro-magnetic telegraph 2300 miles requires 14 seconds for its transmission, what is the velocity of the magnetic current in this telegraph line .'' 376 QUESTIONS IN PHILOSOPHY. LATVS OF FALLING BODIES. 385. A body fulling vertically downward iu a vacuum, falls tlirough 16^2^;'. during the first second after leaving its place of rest, 481//. during the second second, SOj^^ft. the third second, and so on : the spaces forming an arithmetical pro- gression of which the common difference is 32^fL, or double the space fallen through during the first second. This number is called the measure of the force of gravity, and is denoted oyop)ortional to the pjresmre. EXAMPLES. 1. A vase contains 4.3 quarts of air, the pressure being 10 pounds : what will be the volume of the air when the pressure is 12.3 pounds, the temperature remaining the same? 2. Under a pressure of 15 pounds to the square inch, a cer- tain quantity of gas occupies a volume of 20 quarts : what pressure must be applied to reduce the volume to 8 quarts ? 3. A quart of air weighs 2.6 grains under a pressure of 15 pounds : what will be the weight of a quart if the pressure be reduced to 14.2 pounds ? 4. The jjressure upon the steam contained in a cylinder is increased from 25 pounds upon the square inch to 47 pounds : what part of the original volume will be occupied ? 5. How will the density of the steam in the last example, at the second pressure, compare with that at the first ? 6. Eight quarts of hydrogen gas are contained in a vessel and submitted to a pressure of 22 pounds : how many quarts of ga? will there be if the pressure is changed 9i pounds .'' APPENDIX. DIFFERENT KINDS OF UNITS. 391. There are eight kinds of units : 1st. Abstract Units ; 2d. Units of Currency or Coin ; 3d. Linear Units, or Units of Length ; 4th. Units of Surface, or Superficial Units ; 5th. Units of Volume, including Cubic Units and Gallons ; Gth. Units of "Weight ; 7th. Units of Time ; and 8th. Units of Circular or Angular Measure. ABSTRACT UNITS. 392. The abstract unit 1 is the base of all numbers, and is called a unit of the first order. The unit 1 ten is a unit of the second order ; the unit 1 hundred is a unit of the third order ; and so for units of the higher orders. These are abstract num- bers formed from the unit 1, according to the scale of tens. All abstract integral numbers are collections of these units. UNITS OF CURRENCY. 393. In all civilized and commercial countries, great care is taken to fix a standard value for money, which standard is called the Unit of Currency. In the United States, the unit of currency is 1 dollar ; in Great Britain it is 1 pound sterling, equal to S4,84 ; in France it is 1 franc, equal to 18j cents. All sums of money are expressed in the unit of currency or in units derived from the unit of currency, and having fixed proportions to it. 391. How many kinds of units are there in Arithmetic 1 Name them. 393. What is said of the abstract unit 1 1 AVhat is a unit of the 2J order I What of the 3d \ 4th 1 5th ! &c. How are these numbers ("ormed from 1 ! 884: APPEjroiX. UNITS OF LENGTH. 394. One of the most important units of measure is that fof distances, or for the measurement of length. A practical want has ever been felt of some fixed and invariable standard with which all distances may be compared : such fixed standard ha3 been sought for in nature. There are two natural standards, either of which affords this desired natural element. Upon one of them, the English have founded their system of measures, from which ours is taken, and upon the other, the French have based their system. Tliese two systems, being the only ones of importance, will be alone considered. 395. First. — The English system of measures, to which ours conforms, is based upon the law of nature, that the force of gravitij is constant at the same jJoint of the carlh\s sur- face, and consequently, that the length of a pendulum which oscillates a certain number of times, in a given period, is also constant. Had this unit been known brfore the adoption and use of a system of measures, it would liave formed the natural unit for division, and been the natural base of the system of linear measure. But the foot and inch had long been used as units of linear measure ; and hence, the length of tlie pen- dulum, the new and invariable standard, was expressed in terms of the known units, and found to be equal to 39.1393 inches. The new unit was therefore declared invariable — to contain 39.1393 equal parts, each of which was called an inch ; 12 of these parts were declared by act of Parliament to be a standard foot, and 36 of them, an Imperial yard. The Imperial yard and the standard foot are marked ujwn a brass bar, at tlie tem- perature of 62^-°, and these are the linear measures from which 393. "What is a unit of ciiiTcncy 1 "What is the unit of currency in tho Unitcii St;itos? Wliat in (iroat Britain ! "What in Fiance 1 394. For what is an invaiialile stanilanl of lenglli used ! 395. What is the standard unit of length in the EngUsh system 1 What in ours ■> UNITS OF SURFAOK. 8 85 ours are taken. The comparison has been made by means of a brass scale 82 inches long, manufactured by Troughton in London, and now in the possession of the Treasury Depart- ment. 396. Second. — The French system of measures is founded upon the principle of the invariability of the length of an arc of the same meridian between two fixed points. By a very minute survey of the length of an arc of the meridian from Dunkirk to Barcelona, the length of a quadrant of the meri- dian was computed, and it has been decreed by the French law that the ten-millionth part of this length shall be regarded as a standard French metre, and from this, by multiplication and division, the entire system of linear measures has been estab Ilshed. On comparing two scales, vei'y accurately, it has been found that the French metre is equal to 39.37079 English inches — differing somewhat from the English yard. This relation enables us to convert all measures in either system into the corresponding measures of the other. UNITS OF SURFACE. 397. The linear unit having been established, the most con- venient UNIT OF SURFACE is the area of a square, one of whose sides is the unit of length. Thus, the units of surface in com- mon use, are A square inch = a square on 1 inch. A square foot =144 square inches. A square yard = 9 square feet. A square rod = 30^ square yards. &c. &c. 396. What is the standard unit of length in the French system 1 IIow was it found 1 How docs the French metre compare with the Imperial yard 1 397. What is the most convenient unit of surfaced What are those in common use I 386 Al'PENDIX. UNITS OF VOLUME. 398. The Unit of Volume, for the measurement of solids, h taken equal to the volume of a cube one of whose edges is equal to the linear unit. The units of volume in common use are A cubic inch = a cube whose edge is 1 inch ; A cubic foot = a cube whose e ige is 1 foot = 1728 cubic in, A cubic yard=: a cube whose edge is 1 yard = 27 cubic feet. A perch of stone = 24f cubic feet ; or a block of stone 1 rood long, 1 foot thick, and lA feet wide. The standai-d unit of volume for the measurement of liquids i3 the wine gallon, which contains 231 cubic inches. The standard i( nit of dry measure is the Winchester bushel, which contains 2150.4 cubic inches, nearly. UNITS OF WEIGHT. 399. Having fixed an invariable unit of length, we passed easily to an invariable unit of surface, and then, to an invariable unit of volume. We wish now to define an invariable unit of weight. It has been found that distilled rain water is the most inva- riable substance ; hence, this, at a given temperature, has been adopted as the standard. We have two units of weight, the avoirdupois pound, and the pound troy. The standard avoirdupois pound is the weight of 27.701554. cubic inches of distilled water. The standard Troy -pound is the weight of 22.794422 cubic 398. What is thp unit of volume for the measurement of solids \ AVhat are tiiose in common use \ ^\'h,^t is the standard unit for the iiic;i.suro« ment of liquids ! What for dry measure ! 399. What is used as a standard in fixing the iinits of weight? How many units of weight have we 1 How is the .standard avoirdupois iKumd determined ? How tlie Troy pound ! Wliich is represented by a standard at the mint 1 UNITS OF TIME. 387 inches of distilled rain water. This standard is at present kept in the United States Mint at Philadelphia, and is the standard unit of weight. UNITS OF TIME. 400. Time can only be measured by motion. The diurnal revolution of the earth affords the only invariable motion ; hence, the time in which it revolves once on its axis, is the natural unit, aud is called a day. From the day, by multi- plication, we form the weeks, mouths and years ; and by divi- sion, the hours, minutes and seconds. UNITS OF CIRCULAR OR ANGULAR MEASURE. 401. This measure is used for the measurement of an •* " In S. Carolina and Ga. 45. M. - £1 = $4f , and $1 = £ J5. I Canad Scotia, In Canada & Nova I ^^^ . £1 = $4, and $1 = £ 1. ENGLISH MONEY. 406. The units or denominations of English money are guineas, pounds, shillings, pence, and farthings. Notes. — 1. What is the degree of purity of the gold coins? Of the silver coins ? Of the copper 1 2. How much pure gold in the eagle 1 How much pure silver in tho dollar \ 3. What is a carat ? How are metals mixed by carats T 4. In what denominations is money sometimes reckoned in the different ptates ? IOC. What are the denominations of English money? ENGLISH MONEY. 391 TABLE. 4 farthings, marked far., make 1 penny 12 pence - - - - 20 shillings - 1 pound, c 21 shillings - 1 guinea. far. d. 5. 4 = 1 48 = 12 = 1 960 = 240 = 20 marked d, 1 shilling, - «, £. = 1 TABLE OF FOREIGN COINS WHOSE VALUES ARE FIXED BY LAW. Franc of Franco and Belgian, Florin of the Netherlands, Guilder of do. . Livre Tournois of France, Milrea of Portugal, . Milrea of Madeira, Milrea of the Azores, Marc Banco of Hamburg, Pound Sterling of Great Britain, Pagoda of India, Pteal Vellon of Spain, Real Plate of do. Rupee Company, Rupee of Biiiish India, . liix Dollar of Denmark, . Rix Dollar of Prussia, . Rix dollar of Bremen, Ptoublc. silver, of Russia, Tale of China, . Dollar of Sweden and Norway, Specie Dollar of Denmark, Dollar of Prussia and Northern States of Germany, Florin of Southern States of Germany, Florin of Austria and city of Augsburg, . Lira of the Lombardo Venetian Kingdom, . Lira of Tuscany, ...... Lira of Sardinia, Ducat of Naples, ...... Ounce of Sicily, ...... Pound of Nova Scotia, New Brunswick, Newfound laud, and Canada, ..... 4 1 cts. 40 40 12 00 83J 35 84 84 05 10 44^ 44^ 00 68^ 78f 75 48 06 05 69 40 48^ 16 16 SO 40 04 392 APPENDIX. TABLE OF FOREIGN COIXS "WHOSE VALUES ARE FIXED BY USAGE. Berlin Rix Dollar, Current Marc, Crown of Tuscany, Elberfeldt Rix Dollar. Florin of Saxony, Bohemia, Elberfeldt, Prussia, . Trieste, Nuremljurg Frankfort, Basil, St. Gaul, (( u u li li u u (( Creveld, Florence Livre, . Genoa do., Geneva do., . Jamaica Pound, Leghorn Dollar, Leghorn Livre ((Ji to Livre of Catalonia, Neufchatel Livre, . Pezza of Leghorn. Rhenish Rix Dollar, Swiss Livre, Scud a of Malta, Turkish Piastre, the dollar), ds. GH 28 05 69| 48 48 40 22f 48 40 40 41 40 15 18| 21 00 90 o3| 2(1^ 90 60f 27 40 05 [The above Tables are taken from a work on the Tariff, by E. D. Ogden, Esq., of the New York Custom House]. Notes. — 1. The primary unit in EnglLsh money is 1 farthing. The units of the scale, in passing from farthings to pence, are 4; ih passing from pence to shillings, the units of the scale are 12 ; in pass- ing from shillings to pounds, they are 20. 2. Farthings are generally expressed in fractions of a penny. Thus, 1/ar. = \d. ; 2far. = ^l. ; Zfur. --^ \d. 3. The standard of the gold coin is 22 parts of pure gold and 2 parts of copper. Note. — 1. What are the primary units of the English currency 1 Name the units of the scale. UNITED STATES MONEY. 893 The standard of silver coin is 37 parts of pure silver, and 3 parts of copper. A pound of gold is worth 14.2878 times as much as a pound of silver. In the copper coin 24 pence make 1 pound avoirdupois. By reading the second table from right to left, we can see the value of any unit expressed in each of the lower denominations. Thus, Id. = Afar.; Is. = 12tZ. = 48/ar.; £l = 205. = 240rf. = 960/ar. LINEAR MEASURE. 407. This measure is used to measure distances, lengths, breadths, heights and depths. TABLE. 12 inches make 1 foot, marked ft. 3 feet - 1 yard, - - yd. 51 yards or IG^ feet - - 1 rod, - - - rd. 40 rods _ - - - 1 furlong, - - fur. 8 furlongs or 320 rods - 1 mile, - - mi. 3 miles _ - - - 1 league, - - L. 69i statute miles, or 60 geographical miles, - -] 1 degree on the ) , ° V deg. or . equator, - > 360 degrees a circumference of the earth. in. ft. yd. rd. fur. mi. 12 =. 1 36 z= 3 = 1 198 = 16L = 5* = 1 7920 = 6G0 = 220 = 40 =1 63360 = 5280 =: 1700 = 320 =8 =1 Notes. — 1. A fathom is a length of six feet, and is generally used to measure the depth of water. 2. A hand is 4 inches, and is used to measure the height of horses, 3. The units of the scale, in passing from inches to feet, are 12 j in passing from feet to yards, 3 ; from yards to rods, 5-J; from rods to furlongs, 40 ; and from furlongs to miles, 8. 407. For what is linear measure used 1 What are its denominations? Repeat the table 1 - What is a fathom \ What is a hand ? What are- the I'jiits of the scale in linear measure 1 894 APPESTDIX. FOREIGN MEASURES OF LENGTH. 408. The Imperial jard of Great Britain is the one from ■which ours is taken. Hence, the units of measure are identical. " * FRENCH SYSTEM. 409. The base of the new French system of measures is the measure of the meridian of the earth, a quadrant of which is 10,000,000 metres, measured at the temperature of 32° Fahr. The muhiples and divisions of it are decimals, viz. : 1 metre =z 10 decimetres = 100 centimetres r= 1000 millimetres = 8.280899 United States feet, or 39.37079 inches. This relation enables us to convert all measures in either system into the corresponding measures of the other. Austrian, 1 foot — 12.448 U. S. inches = 1.03737 foot. Prussia!}, J „, . , , I 1 foot = 12.3G1 " « = 1.0300 Kluneland. Swedish, 1 foot = 11.G90 « " =0.974145" ^ 1 foot — 11.034 " " = 0.9195 " Spanish, Y league (royal) = 25000 Span. ft. = 4^ miles "i >> ) " (common) = 19800 « = ^ '' \ \ CLOTH MEASURE 410. Cloth measure is used for measuring all kinds of cloth, ribbons, and other things sold by the yard. TABLE. 2\ inches, in. make 1 nail, marked na. 4 nails - - 1 quarter of a yai'd, qr. 3 quarters - - 1 Ell Flemish, E. Fl. 4 quarters - - 1 yard, - - yd. 5 quarters - - 1 Ell English, - E. E. 408. How docs the Imperial yard compare with the standard in tlic United States \ 409. What is the unit of tlie French system of measures ? How doci the metre compare wilii our standard yard 1 410. For what is cloth measure used ! What arc its denominations 1 Repeat the table. What arc the units of the ucalcc ? SQUAKE MEASUKE, 395 m. na. qr. ^. i^'l. yd. 2i = 1 9 = 4 = 1 27 = 12 = 3 = 1 36 = 16 = 4 -1^ = 1 45 = 20 = 5 = lf = U KK == 1 Note. — Tho units of the scale, iu this measure, are 2^, 4, 3, J, and -J. SQUARE MEASURE. 411. Square measure is used in measuring land, or anything in which length and breadth are both considered. A square is a figure bounded by four equal lines at right angles to each other. Each line is called a side of the square. If each side be one foot, the figure is called a square foot. 1 Foot. o o I— < 1 yard = 3 feet. CO 1 II 1— t If the sides of the square be each one yard, the square is called a square yard. In the large square there are nine small squares, the sides of which are each one foot. Therefore, the square yard con- tains 9 square feet. The number of small squares that is contained in any large square is always equal to the product of two of the sides of the large square. As in the figure, 3x3 = 9 square feet. The number of square inches contained in a square foot is equal to 12 X 12 = 144. 411. For what is square measure used ^ What is a square'? If each side be one foot, what is it called 1 If each side be a yard, what is it called 1 How many square feet does the square j^ard contain ? How is the number of small squares contained in a large square found 1 Rc()cat the table. What are the units of the scale 1 39G APPENDIX. TABLE. 144 square inches, sg. in. make 1 square foot, Sq.ft. 9 square feet - - 1 square yard, Sq. yd. 30^ square yards - - 1 square rod or perch, P, 40 square rods or perches 1 rood, - - - K. 4 roods - - - 1 acre, - - - A. M. A. 640 acres - 1 square mile. Sq. in. Sq. ft. Sq. yd. P. P. 144 = 1 1296 = 9 = 1 39204 = 272i = 30J =1 15G8160 = 10890 =z 1210 =40 = 1 6272G40 = 43560 = 4840 =160 =4 = 1. Note. — The units of the scale in this measure are 144, 9, 30^. 40, and 4. SURVEYORS' MEASURE. 412. The Surveyor's or Gunter's chain is generally used in surveying land. It is 4 poles or 66 feet in length, and is divided into 100 links. TABLE. 7^^ inches make 1 link, marked - - I. 4 rods =66//;, = 100 links 1 chain, - - - c. 80 chains - - - 1 mile, - _ - mi. 1 square chain - - 16 square rods or perches, P. 10 square chains - 1 acre, - - - A. Notes. — 1. Land is generally estimated in square miles, acres, roods, and square rods or perches, 2. The units of the scale, in this measure, arc 7^^^, 4. 80, 1, and 10. CUBIC MEASURE. 413. Cubic measure is used for measuring stone, tlmbei, eartli, and sucli otlier things as have the three dimensions, length, breadth, and thickness. 412. What chain is used in land surveying '> What is its length 1 How is it divided 1 Repeat the table 1 In wliat is land generally estimated 1 Wiiat are the units of the scale f CUBIC MKASURK. 897 TABLE. 1728 cubic inches, Cu. in. , make 1 cubic foot, - Cu.ft. 27 cubic feet - - 1 cubic yard, - Cu.yd. 40 feet of round or 50 feet of hewn timber, } 1 ton. - T, 42 solid feet - - 1 ton of shipping, T. 8 cord feet, or ) 128 cubic feet 1 - 1 cord. - C. 241 cubic feet of stone - 1 perch, - - P. C3 CO Notes. — 1. A cord of -wood is a pile 4 feet wide, 4 feet hish, and 8 feet long, 2. A cord foot is 1 foot in length of the pile which makes a cord. 3. A CUBE is a figure bounded by six equal squares, called faces ; the sides of the squares are called edges. 4. A cubic foot is a cube, each of whose faces is a square foot ; its edges are each 1 foot. 5. A cubic yard is a cube, each of whose edges is 1 yard. 6. The base of a cube is the face on which it stands. If the edge of the cube is one yard, it will contain 3X3=9 square feet* therefore, 9 cubic feet can be placed on the base, and hence, if the solid were 1 foot thick, it would contain 9 cubic feet ; if it were 2 feet thick it would contain 2 tiers of cubes, or 18 cubic feetj if it were 3 feet thick, it would contain 27 cubic feet ; hence, The contents of such a figure are found by multiplying the length, breadth, and thickness together. 7. A ton of round timber, when square, is supposed to produce 40 cubic feet : hence, one-fifthjs lost by squaring. 3 feet = 1 yard. 413. For what is cubic measure used! What are its denominations? What is a conl of wood 1 AVhat is a cord foot ? What is a cube' What is !i cubic foot 1 What is a cubic yard ? How many cubic feet in a cubic yard 1 What are the contents of a volume equal to ? Repeat the table. What are tlic units of the scale 1 18 898 APPEISTPIX. WINE MEASURE. 414. "Wine measure is used for measuring all li [quids except ale, beer and milk. TABLE. 4 gills, gi. make 1 pint, marked pt. 2 pints - 1 quart, qt. 4 quarts - - 1 gallon, gal. 31 1 gallons - - 1 barrel. bar. or hbl 42 gallons - - 1 tierce. tier. 63 gallons - - 1 hogshead, hhd. 2 hogsheads - 1 pipe, 2n. 2 pipes or 4 hogsheads 1 tun. tun. gi. pL qt. gal. bar. tier. hhd. . pi. tun. 4 =1 8 =2 = 1 32 =8 = 4 = 1 1008 = 252 = 126 : = 311 ^1 1344 = 336 = 168 : = 42 =1 2016 ^ 504 = 252 : = 63 = 11 = 1 4032 = 1008 =.504 : = 126 =3 =2 = 1 8064 z^ 2016 zzz 1008 : = 252 =6=4 = 2=1. Notes.— 1. The standard unit, or gallon of wine measure, in the United States, contains 2.31 cubic inches, and hence, is equal to the weight, avoirdupois, of 8.339 cubic inches of distilled water, very nearly. 2. The English Imperial wine gallon contains 277.274 cubic inches, and hence, is equal to 1.2 times the wine gallon of the United States. BEER MEASURE. 415. Beer measure is used for measuring ale, beer, and milk. 414. What is measured by wine measure 1 AVliat arc its dcrominations 1 Rcpcr.t the table. What are the units of the scale 1 What is a standard wine gallon 1 415. For what is beer measure used? What are its denominations 1 Repeat the taiilc What arc the units of the scale 1 DKY MEASUKE. 399 TABLE. 2 pints, pt. make 1 quart, marked qt. 4 quarts - 1 gallon, - gal. 36 gallons - 1 barrel, - bar. 54 gallons - 1 hogshead. hhd. pt. qt. gal. bar. hhd. 2 =1 8 =4 = 1 288 = 144 = 36 =1 432 = 216 = 54 =11 = 1. Notes. — 1. The standard gallon, heer measure, contains 282 cubic inches, and hence, is equal to the weight of 10.1799 cubic inches of distilled rain water. 2. Milk in many places is sold by wine measure. DRY MEASURE. 416. Diy measure is used in measuring all dry articles, such as grain, fruit, salt, coal, &;c. TABLE. 2 pints, pt. make 1 quart, marked qi. 8 quarts - - 1 peck, - - pk. 4 pecks - - 1 bushel, - - biu 36 bushels - 1 chaldron, - ch. pt. qt. pk, hu. ch. 2 =1 16 =8 =1 64 =32 =4 =1 2304 = 1152 = 144 =36 =1. Notes. — 1. The standard bushel of the United States is the Win" chester bushel of England. It is a circular measure 18-J inches in diameter and 8 inches deep, and contains 2150.4 cubic inches, nearly. It contains 77.627413 pounds avoirdupois of distilled water. 2. A gallon, dry measure, contains 268.8 cubic inches. 416. What articles are measured by dry measure 1 What are its de- nominations 1 Repeat the table. What are the units of the scale 1 What ir the standard bushel ! What are the contents of a ffallon '' 400 APPENDIX. 3. Wine measure, Beer measure, and Dry measure, and all mea- sures of volume, differ from the cubic measure only in the unit which is used as a standard. AVOIRDUPOIS WEIGHT. 417. By this weight all coarse articles are weighed, such as bay, grain, chandlers' wares, and all metals except gold and silver. TABLE. 16 di'ams, dr. make 1 ounce, marked oz. 16 ounces - - 1 pound, - - Ih. 25 pounds - 1 quarter, - - qr. 4 quarters - 1 hundred weight, cwt. 20 hundred weight 1 ton, - - T. dr. oz. lb. qr, cwt. T. 16 = 1 256 nr 16 = 1 6400 r=: 400 =25 =1 25600 = 1600 =100 =4 =1 512000 = 32000 = 2000 =80 =20 =1. Notes. — 1. The standard avoirdupois pound is the weight of 27.701 5 cubic inches of distilled water; and hence, 1 cubic foot weighs 1000 ounces, very nearly. 2. By the old method of weighing, adopted from the English sys- tem, 112 pounds were reckoned for a hundred weight. But now, the laws of most of the States, as well as general usage, fix the hundred weight at 100 pounds. 3. The units of the scale, in passing from drams to ounces^ are 16 ; from ounces to pounds, 16, from pounds to quarters, 25 j from quar- ters to hundreds, 4 ; and from liundreds to tons, 20. 417. For what is avoirdupois weight used 1 How is the table to be read ^ How can you determine, from the second table, the value of any unit in units of the lower denominations 1 NoTF.s. — 1. What is tlie standard avoirdupois pound 1 2. What is a hundred weigiit by the English method ] What is a hun- dred weight by the United States method 1 3. Name the units of the scale in passing from one denominatijii to another. TROY WEIGHT. 401 TROY WEIGHT. 418. Gold, silver, jewels, and liquors, are weighed by Troy wciglit. TABLE. 24 grains, gr. make : 1 pennyweight. marked pu 20 pennyweig hts - 1 ounce, oz. 12 ounces - 1 pound. lb. gr. pwt. oz. lb. 24 = 1 480 = 20 = 1 57G0 = 240 = 12 = 1. Notes. — 1. The standard Troy pound is the weight of 22.794377 cubic inches of distilled "water. Hence, it is less tlian the pound avoirdupois 2. 7000 troy grains = 1 pound avoirdupois. 175 troy pounds = 144 pounds " 175 troy ounces = 192 ounces " 437-^ troy grains = 1 ounce " 3. The Troy pound being the one deposited in the mint at Phila- delphia, is generally regarded as the standard of weight. 4. The units of the scale are 24, 20, and 12. APOTHECARIES' WEIGHT. 419. This weight is used by apothecaries and physicians in mixing their medicines. But medicines are generally sold, in the quantity, by avoirdupois weight. TABLE. 20 grains, gr. make 1 scruple, marked 9 . 3 scruples . - 1 dram, - - 3 . 8 drams - - 1 ounce, - - 5 . 12 ounces - -^ - 1 pound, - - Ife-. 418. What articles are weighed by Troy weight"! What are its denomi- nations 1 Repeat the table. What is the standard Troy pound ? What are the units of the scale, in passing from one unit to another 1 419. What is the use of Apothecaries' weight 1 What are its denomi- nations 1 Repeat the table. What are the values of the pound and ounce 1 What are the units of the scale, in passing from one unit to another 1 18 402 APPENDIX gr- 9 3 20 = 1 60 = 3 r= 1 480 = 24 = 8 ft = 1 5760 =288 =96 =12 =1 Notes. — 1. The pound and ounce are the same as the pound and ounce in Troy weight. 2. The units of the scale, in passing from grains to scruples, are 20 ; in passing from scruples to drams, 3 : from drams to ounces, 8 ; and from ounces to pounds, 12. NEW FRENCH SYSTEM. 420. The basis of this system of weights is the weight in vacuo of a cubic decimetre of distilled water. This weight is called a kilogramme, and is the unit of the French system. It is equal to 2.204737 pounds avoirdupois. The other denomi- nations are as follows : 100 kilogrammes = 1 quintal ; 10 quintals = 1 ton sea water; 1 gi-amme = 10 hectogrammes ; 1 hectogramme = 10 deco- grammes ; 1 decogramme = 10 grammes ; 1 gramme = 10 de- cigrammes ; 1 decigramme = 10 centigrammes ; 1 centigramme = 10 milligrammes. COMPARISON OP WEIGHTS. English^ 1 pound = 1.000936 pounds avoirdupois. French, 1 kilogramme = 2.204737 " " Spafiish, 1 pound = 1.0152 " " Swedish, 1 pound = 0.9376 " « Austrian, 1 pound = 1.2351 " " Prussian, 1 pound = 1.0333 « « MEASURE OF TIME. 421. Time is a part of duration. The time in which the earth revolves on its axis is called a daij. The time in which it goes round the sun is called a solar year. Time is divided into parts according to the following DA xr.s. 40y TABLE. 60 seconds, sec. make 1 minute, marked m. 60 minutes 1 hour, - - hr. 24 hours 1 day, - - da. 7 davs 1 week, - - wk. 4 weeks 1 month, nearly, - mo. 12 calendar m'ths = 365(/rt. 1 Julian or civil year, yr. 866 days 1 leap year. 100 years 1 century, - - cent. see. VI. hr. da. xok. yr. 60 =1 3600 =60 = 1 &6400 =1440 = 24 =1 604800 =100S0" =168 =7 =1 31536000 =525600 ^8760 =365 =521 =1. The year is divided into 12 calendar months : No. No. days. No. No. days. 1st. January, - - 31 7th. July, - - - - 31 2d. February, - - 28 8th. August, - - - 31 3d. March, - - - 31 9th. September, - - 30 4th. April, - - - 30 10th. October, - - - 31 5th. May, - - - 31 11th. November,- - - 30 6th. June, - - - 30 12th. December, - - 31 The number of days in each month may be remembered by the following : Thirty days hath September, April, June, and November ; All the rest have thirty-one. Excepting February, twenty-eight alone. 421. What are the denominations of time 1 How long is a year 1 How many days in a common year 1 How many days in a Leap year ] How many calendar months in a year '\ Name each, and its number, and the number of days in each. How many days has February in the leap year \ How do you remember which of the months have 30 days, and which 31 1 jVoTE. — 1 How are the centuries numbered 1 How are the years nuin eared 1 The days 1 The hours 1 404 APPENDIX. Notes. — 1. Days are numbered in each month fiom the first day of the month. 2. Montlis are numbered from January to December. 3. The centuries are numbered from the beginning of the Christian Era. The year 30, for example, at its commencement, was called the 30th year of the first century, though neither the century nor the year had elapsed. Thus, June 2d, 1856, was the 6th month of the 56th year of the 19lh century. 4. The civil day begins and ends at 12 o'clock at night. In the civil day, the hours are reckoned from that time. DATES. 1. The length of the solar year is 365da. 5hr. 48m. 4S.tcc.. very nearly. It is desirable to have the periods and dates of the civil year correspond to those of the solar year ; else, the summer months of the one would in time become the winter months of the other, thereby producing great confusion in dates and history. 2. The common civil year is reckoned at 365^/a., and the solar year at 365da. 6hr. The 6 hours accumulate for 4 years before they are counted, when they amount to 1 day, and are added to February and the year is called a bissextile or leap year. 3. The odd 6 hours have been so added that the leap years occur in those numbers which are divisible by 4. Thus, 1856, 1860, 1864, &c., ar3 leap years; and when any number is not divisible by 4, the remainder denotes how many years have passed since a leap year. 4. This method of disposing of the fractional part of the year would be without error if the solar year were exactly 365da. 6hr. in length ; but it is not; it is only 365(la. 5hr. 48m. 48scc. long : hence, tt;C leap year is reckoned at too much^ and to correct this error, every centennial year is reckoned as a common year. But this makes an error again, on the other side, and every fourth centennial year the day is retained. Thus, 1800 was not, and 1900 will not be. reckoned a leap year : the error will then be on the other side, and 2000 will be a leap year. This disposition of the fractional part of the year cau,scs the civil and solar years to correspond very nearly, and indi- cates the following rule for finding the leap years : Every year ivhick is divisible by 4 is a leap year, unless it is a centennial year, and then it is not a leap year tmless the num' her of the century is also divisible by 4. 5. Tlie registration of the days, by reckoning the civil year at jnSCKIXANKOUS TABLES. 405 365da., was established by the Roman Emperor, Julius Ca5sar, and hence Ihis period is sometimes called the Julian year. The error, arising from the fractional part, continued to increase until 15S2. when it amounted to 10 days; that is, as the year had been reckoned too long the number of days had been too feu\ and the count, in the civil year, was behind the count in the solar year. In this year, (1582), Pope Gregory decreed the 4th day of October to be called the 14th, and this brought the civil and the solar years to^ether. The new calendar is sometimes called the Gregorian Calendar. 6. The method of dating by the old count, is called Qld Style ; and by the new, New Style. The difference is now 12 days. la Russia, they still use the old style; hence, their dates are 12 days behind ours. Their 4th of January is our 16th. CIRCULAR MEASURE. 422. Circular measure is used in estimating latitude and longitude, in measuring the motions of the heavenly bodies, and also in measuring angles. The circumference of every circle is supposed to be divided into 360 equal parts, called degrees. Each degree is divided into 60 minutes, and each minute into 60 seconds. TABLE. 60 seconds " make 1 minute. marked • 60 minutes 1 degree. - O • 30 degrees 1 sign, - - s. 12 signs or 360° 1 circle, - - c. // 1 o s. c. 60 = 1 3600 = 60 = 1 lOSOOO r= 1800 = 30 = 1 1296000 = 21600 = 360 = 12 = 1. 422. For what is circular measure used ! How is every circle supposed lu be divided 1 Repeat the table. 406 APPKNDIX, MISCELLANEOUS TABLE 12 units, or things make 12 dozen - - _ . 12 gross, or 144 dozen 20 things - - . . 100 pounds - - _ 196 pounds - _ _ 200 pounds 18 inches - - - - 22 inches, nearly 14 pounds of iron or lead - 21^ stones - - - _ 8 pigs - . - . 1 dozen. 1 gross. 1 great gross. 1 score. 1 quintal of fish. 1 barrel of flour. 1 barrel of pork. 1 cubit. 1 sacred cubit. 1 stone. 1 fother. BOOKS AND PAPER. The terras, folio, quarto, octavo, duodecimo, Sec, indicate the number of leaves into which a sheet of paper is folded. A sheet folded A sheet folded A sheet folded A sheet folded A sheet folded A sheet folded A sheet folded A sheet folded n 2 leaves is called a folio. .1 4 leaves " a quarto, or 4to. n 8 leaves n 12 leaves n 16 leaves in 18 leaves n 24 leaves n 32 leaves a ii ii a a 24 sheets of paper 20 quires - 2 reams - 5 bundles make an octavo, or 8vo. a 12mo. a 16mo. an 18mo. a 24mo. a 32mo. 1 quire. 1 ream. 1 bundle. 1 bale. ANSWERS. r. EX. 1 ANS. EX. "8 A^S. 1 EX. 15 ANS. 16. XVI. DCCLI. DCCCCLVII. 16. 2 XIV. 9 MLX. 16 MCCVI. IG. O XVIII. 01 MMXCI. 17 CCCCXCV. 16. 4 LXIX. 11 DLXIX. 18 DCCLV. 16. 5 LXXVIII. 12 DCCXLV 19 MDCCCXLVII. 16. 6 CXV. 13 DCCCCLXI 20 MMDXX. 16. 7 CCCCIX. 14 DCXCIX. 19. 1 7 3 9000 11 5 1 961 6 7408 19. 2 80 4 93 - 20. 7 897.021 20. 8 86.029,430 20. 9 4,328,021,063 20. 10 967,040,932 20. 11 30,430,208,123 20. 12 360,030,702,010 20. 13 5,800,006,000,812 14 15 16 17 18 19 20 75,605,070,905,008 904,000.800,200,720 6,000.900,704,098,020 80,510,006,040,900,040,900 6,050,900,001 987,654,321.012,345,678 208,104,111,001,111,111 23. 23. 23. 23. 23^ 24. 24. 24. 24. 24. 24. 24. 2 o O 4 5 621 6 5.702 7 8,001 8 10,406 9 65,029 10 40,000,241 59,000,310 12,111 300,001,006 69,003,000,211 11 12 13 14 15 16 17 47.000,069,000,465,207 800. 000,'000,000,429, 006,009 95,000,000,000,000,089,089,306 6,000,000,451,065,047,104 999,065,841,411 470,040,000.000,000,000,000,000,004,006,204 65.000,800,000.750,751,975,310 3L 33. 33. 34. 34. 34. 34. 34. 2; 7 1 \ 42600 ; (426000 36b60 ^8,75 10|8996 ll|i;i 125. &c^. Ifar. 12 13 14 15 16 4 5445/5. IT. lAc'ct. \qr. 20/6. 262155-r5. \22lb. 2oz. ISpwt. 9gr. 29:]ii2gr. 17 mib. 4 § 3 5 2 9 7gr. I8\2i9i?i. 1600rJ. SSOOyds. 26400/?. 316800m 20 r/oi/d. 2ft. 6in. ,9 403 ANSWERS. P. EX 21 ANS. EX. 30 ANS. 34. 6sq. t/d. 2v7. ft. 78 E.E. \qr. 34. 22 2 A. OH. 35P. 31 1008^^. 34. 23 ^5A. Q)sq. Oh. 32 1 Z)hhd. I 34. 21 56SP. 33 •i02\pt. 34. 25 967 GSOcu. in. 34 \29har. 34. 26 o968cu.ft.. 35 1984;)^. 34. 27 iiOcords. 36 Oc/i. o2hu. o'ph. Iqt. 34. 28 25 \ 2 )ta. 37 6311385C )sec. 34. 29 lUj/d.. 38 Smo. 2ick. 38. 1 182630 --J 1 395873 13 32921 38. 2 87539 8 30534 14 185876 38. 110526 9 74716 15 93684 38. 4 79165 10 29909 16 34289 38. 5 73285 11 74022 17 243972 38. r 41-18907 12 833516 J 39. 18 39. 19 39. 20 39. 21 39. 22 39. 23 39. 24 39. 25 39. j26 §991,546. •^85,465. 4770,560, ^525.892. f;9638.495. £223 2s. 5d. If. 1295/6. lOoz. 2jnct. 4531b 9 ! 3 3 2ciol.ogr.8lb.8oz. 5d>: 27j 2s: 29 3o: 31 32 .. .■> oo 34 43 T. 2cict. Qqr. lib. 312i/d. Qqr. 2da. 2d\ E. E. \qr. 3na. 143jL. 2)7ii. 6 fur. 4 fur. -ird. Oi/d. \ft. i22A. \R. IP. 2224 T. Ohlid. 5gal. oqt. Tin. 19 gal. 40. 40. 40. 40. 40. 35 36 37 38 39 2o0chal. 2bbu. opk. Aqt. 823 ?/r. I0??i0. 9Q4da. \8hr. Imi. 2 2\lAcivt.lqr.2Qlb. l5oz. ,23592550. 40 41 42 43 44 -S137915910. 68056. 12 Imi. 4fiir. 8rd. 5ft. 519190. 1124749. 41. i 15 $22,009. 1 50 ; 29026. 41. 46 $27,740. 51 8209.75. 41. 47 2tMn. 2hhd. 29gal. 2qt. Ojn. 52 26326421. 41. 48 §20308675. 53 29714. 41. 49 30569S53. 54 50110025. 42. 55 5980^512 60 Alb. ooz. (jjnct. 42. 56 2T. Acict. 2qr. lib. 61 1053420 42. 57 205 acre a. 62 1089507 42. OH S75002,295 63 32341 42. 59 $7425 — ANSWERS. 409 P. EX. ANS. e:c. ANS. 43. 43. 43. 43. 43. 64 65 CG 67 68 $27131,23 $28,105 39//f/. }qr. $180,825 $35068,807 69 70 71 72 481125 66585383 $1019,10 $33800 44. 44. 73 74 380 bu. \2^k. $458,342 75 76 £57 lis. 2d. ofar. 58G0 47. 47. 47. 47. 1 2 o O 4 363296 56579 733071 17 11 0O7 5 6 7 8 41923288 rods. $7838180 106026 vtills. 4-^01 /)/v.. 9 10 11 62786/;^. 198621115m. 3591 75765 b;>. 48. 48. 4S. 48. 48. 48. 48. 48. 48. 48. 48. 48. 48. 48. 12 13 14 15 16 17 18 19 120 21 2-2 23 ;25 4199675 cords. S87877S. $3-143.641 $806,384 $4853673,758 £14 18s. 3^/. l//r. 3 T. 8cioL 2qr. 7 lb. i\7 yds. 2qr. \na. odL. \mi. ofar. 28rd. 8t,un Ihhd. bogal. 2>qt. 89 A 2R. 37 P. 976bu. Ipk. 6qt. 124 cords 5Sft.. 522in. 26 27 28 29 30 31 36 37 3.8 25 E. E. \cjr. 3;i«. 79fe 10 ! 6 3 12 3 4 5 2 9 124 £. E. 3qr. 3}ia. 9GE. F. Iqr. Ina. 12 T. newt. 3qr. 2cwL 2/r. 22/6. G9qr. 2lb. lioz. l34//>. l4oz. \odr. 10 A 2R. 18P. 37 A. 2R. 34P ] 47 da. 2\hr. 5(Jmi. o2kr. 50)11. 54isec. 49.1 39 49.! 40 49.! 41 49.1 42 49.! 43 49. 4^ 49. 45 $8759,625 183666662 (■>?/;•. 9mo. 3ick. Wda. 8b fe ! 6 3 $8,20 $39,808 $10,626 46 47 48 19 50 51 52 £121 175, 6///. Qmo. 6353870 5747 $6020 25712808,91 $36190 Od. \far. Owk. Gda. 9hr. 2tni odJ 50.1 50.1 50.' 5,). 5^ 51. 51 Ob 54 ■55 56 57 GS3021 107445034 6274 4 T. 3civL 2qr. £19 19.y. 2d. 23lb. ydr. 58\2299mi. 2far. 4.rd. 59 60 61 62 63 64 >; 19 9,625 lost. S175,875 $3,25 19987563 2899248 i;73675 ' 65 66 22815 $198,625 67 68 80///-. 87710. Oda. 3hr. 30m. $655,125 410 ANSWERS. p-i EX. ANS. EX. AXS. 51. G9 249?//-. Imo. Wda. 73 §7398 51. 70 17877 74 -$23G0 5!. 71 S731U756 75 526 51. 72 $62727794 76 6274 77 78 79 80 81 82 $356.35 gained. 3J.. 2ii. 39P. 41 cords 5 cord feet. $3280,105 $44161,987 $14352,50 83 84 85 86 87 2?/A 8?reo. I9(^a. iOgal. 2qt. Ipi. 50062 15550 12° 23' 53'' 88 $161,175 gained. ,, 90 89 2271707 i: 91 32y(^. O^-;-. 2«a. £950 2s. 8d. 1 2 »"> o 4 5 6 7 8 9 10 11 12 6776368 68653214 3422454 1952883 4354224 1028.540646 24668698404 $70,84 $12517,764 >;96 1662,960 201638228149 4281770760 174809600 141301144560000 15|610071000 16 14783518400 17 £81 6s. 8d. 1 8 24 T. TcivL oqr. W\UQyd. \fl. 2>in. 20ill4° 26' 15" 2\\5i6hhd. Igal. 2qt. 22 [598 E. F. 23 1 865 T. 11 cm;^. Syr. 20/5. 24]320y?-. 2mo. Oiv/c. Ida. lohr. I2f)u 2514896 Opt. 26 27 26 29 30 31 32 34 35 36 37 38^ 234048 4482566 314986464 320021195962 556321146761 1747125213301 23246S4880333 71109696192112 90012355857332 549600 670460; 6704600 570 1900; 57049000 j 498U496000 ; 1 49804960000 ,59 40 41 42 43 44 45 46 47 48 49 50 51 52 9072040000 ; 907204000000 74040900; 740409000 67493600; 67493600000 129359360000 13729103000000 664763206000000 879923S229600000 25264260 17908695000000 10936893 68 145U8437S777040 16714410677359581583737 $61975 3240WU. §2097 \33t/d. 3qr. 2na, ANSWKKS. 411 p. EX. ANS. EX. 54 ANS. 62. Do £3 1 95. 4d. 2far. 11031,68 62. 55 62. i 56 62.1 57 62. 58 62.1 59 62.' 60j $15 $506,88 $6336 $5545 $16763832 496mi. \fur. 24:rd. 61' 62 63 64 65 66 63. i 67 63. 68 63. 69 63. 70 63. 71 63. 72 63. '^O 63. JO 146484 yards. 427816 barrels. $84,26 $16875,60 2T. \8cw(. Iqr. 2\lb. $971,04 461 barrels left. $1315 cost. 74 75 76 77 78 O 57i$4.75 58,'$ JO 59,757 ISByLS, 60$1,625 61 )65r/a. 62S00008 63J47 ririffs. 64\lT. Ucu't. 2qr. 65 45c-. /■/. 9954c. in. 66b0liff/on.s-.' 67 44242f^-oZ5. 74. 2 74. 3 74. 4 74. 5 7175 4600 168525 76850 2725 387321 4413840 15423 2674584 280082 75. 75. 75. 1 4800 1 4| 2 5950 1 3 185000 2 83S0225 559750661 493574661 3558504001 148072400 7408000 I 2 219917G000 3 242601500 4 17573500 76. 76. 76. 76. 2 o O 254 26251-2-0- 291147 5 211488i6J^ 6 978 7 852 8 954 9 140848 13 10 2025 14 11 39252 15 12 475542 16 242172 2250 48126 16215 77. j 77. 1 o 387 1548 532 804 5 6 15911 1935 7 8 1809 3216 78. 78. 78. 79. 79. 80, 80. 2 3 1322^ 1740| 218^ 1 j 2| /I 2 9 -J fi ^4200 146 75 1 5 26 9£ ■S 4 00 4 5 83253f^V 2459|f| 6 7 4n7"l-6-A2_ '^'^^ '7560 o 4 Ql 27 1 606 ^^80)400 Joo/o4:-y2o-ooi 5 6 ''"■-' 1 4 6000 99.175 a:; 9 H ^ '63 000 3117^i o 4 6109611- ''i'409 5 6 9095f^| 69921|| 8i4079-A^ 81. 1 1 §142 1 2|§;17 ||3 !$14 |4|,t35!|6 $l72||7j$120i;8jC-;90 82. 1 1 $121,615 ] 2 $67,50 | 3 | $118,9145 83.| 1 1 $3,024 II 2 $12,8915 3 | $9,198 || 4| $18,22765 85. 1 3 5° 13' difT in long. 2 lA?-. 2//^ 8i-cc. P.M. 86. 3 86. 4 13° 23' 4w. 36.SYC. 5 6 8/^r. 1 2m. A. M. 10° 34' ANSWERS. 413 p. EX. 7 ANS. I 1 ANS. 86. 35° 11' $128 86. 8 P5° 48' West, 2 2bu. \pk. 86. \ 10 /.r. 17m. 4Ssfc.P M. 3 , $53.28 86. 9 120° 4 32 barrels. 86. 10 1/ir. 2m. 2G.'?«c. Fast. 5 463684 87. 6 1 41GG6|f/rt//o«s. 15 $812.25 87. 7 57979fl| 16 $147,9375 87. 8 5552-1 17 £14 145. 87. 9 Imo. \ivk. A^da. 18 £166 2s. Qd. 87. 10 12 years. 19 6d. 87. 11 ^mo. Ow. 5d. 14/i. 40m. 20 $6,95175 87. 12 765 barrels. 21 $8,64 87. 13 $72 22 $93. 87.1 14 $0- 88. 23 if ?7,875 2 8 SI 9 33 7680 88. 24 1 8 cents. 2 9G780C. ft 34 1/6. 7oz. 12pwt. Ugr 88. 25 :: 6 3 $773, 39£ ) -io SIO 88. 2G';1 olb. 6or. lipivf. 3 1 $4.2408 36 2/>M. \pk. Iqt. 88. 27'$50 3 2 $16,702^ ) 37 $0,75 89. 38 104 sheep. 44 $59b2Sl 89. 39 12 days 45 31680 times. 89. 40 16 caunisters. 46 130 farms. 89. 41 52gal. Iqt. 47 n9/4¥3Ta«i-^s. 89. 12 1424 48 S44397293 89. 43 96 acres. 49 11/tr. Ami. 32.SW., A.M. 90. 601 127° '30 57 5''ll-/fl?.l fur.oArd.2yd. 90. 51 1 J 67° 35' jVs Long. \ 9hr. I9in. P. M., B's time. 58 1000000>. 90. 59 \o82Arods. 90. 52 lOcords, ^ cord ft. \^c.Jt. GO 36100 90. 53 \cwt.. '3qr. 9lb. lOoz. 61 291111. ofur. 2rd. 16/?. 90. 54 $164,475 62 1 Oacres. 90. 55 282?/r. 6mo. 8da 63 c.'oyards. 90.'56 6i:al. 2(jt. Gpt. 2r/i. 91. G4[. 3//c/. Iqr. oiia. 69 2o}ir. 6mo. IGc/a. 'Jhr. 91. 6oi 33 of each. 70 $10591021,60 91. r,6 13209 + 71 ) $2478 widow's share ) $1239 each child's " 91. 67 $11,88 91. 1 G 8 ' 1 ?/ ;•. 2 5^/a . 1 Ih r. 1 5 m. 72 $9 92. 73 130C8 shuigies. 1 . J 107° 47' diti: iu long. ) Ihf 1 i «j. ftsvr (lifT. in timfi. 92. 1 ! ( ■ " 414: ANSWEK5. P. EX. 75 ANS. KX. 78 AXS. 92. 1/i;-. 11?«. 8sec.,P. M. $2 92. 7G j Ahr. 5(J7n., P. M. 79 4333|- schoolhouses. 92. \ 2^° from N. York. SO AQ^lbs. 92. 77 48 hours. 81 14 days. 93. 82 28bar. 6gaL I 4S2A«. \pk. -I'jis. — l:,t. 93. S3 24:bar. ]9gals. 90 ] U\{)hu.opk.Qqt. \^j)t. — 2A. 93. 84 $85,33i I o2lbu. 2pk. \qL ^pt. =zod. 93. 85 1 1 2. rolls. 91 I 40° 50' East. 93. 86 lini. 6/ur. 20rd. I 35^ days. 93. 87 8750 pounds. f $2400 = Captain's share. 93. 88 $18,025 (-^ j $2000 = 2 Lieut:s " •^"^ ] $3600 = 6 Midship. " 93. 89 2500 barrels. 93. [$ 200 :nr each sailor s " 94. 93 87° 30' 98 514 eagles. 94. 94 9hr. 33m. 146rc., A. M . 99 2011 bushels. 94. 95 lOhr. 54.m. IGsec. A. J n 100 $7410 94. 96 19° 101 Ij/r. 338da. 22hr. 94. 97 4800//f^s. — 96. 1 3x3; 2x5; 2x2x3; 2x7; 2x2x2x2; 96. 3x3x2; 2x2x2x3; 3x3x3; 2x2x7. 96. 2 2x3x5; 2x11; 2x2x2x2x2; 3x3x2x2; 96. 2x19; 2x2x2x5; 3x3x5; 7x7; 96. 3 2x5x5; 2x2x2x7; 2x29; 2x2x3x5- 96. 2x2x2x2x2x2; 2x3x11; 2x2x17; 96. 2x5x7; 2x2x2x3x3. 96. 4 2x2x19; 2x3x13; 2x2x2x2x5; 2x41; 96. 2x2x3x7; 2x43; 2x2x2X11; 2x3x3x5. 97. 6 2x2x23; 2x47; 2x2x2x2x2x3; 2x7x7; 97. 3x3x11; 2x2x5x5; 2x3x17; 2x2x2x13. 97. 6 3x5x7; 2x53; 2x2x3x3x3; 2x5x11; 97. 5x23; 2x2x29; 2x2x2x3x5; 5x5x5. 97. 7 2x151; 5x01 ; 2x2x151; 5x5x5x7; 97. 3x5x5x13 ; 5x131. 97. 8 5 X 3 X 2. 97. 9 2 X 3 X 7. 97. 10 3x5x7. 97. 11 2x3x7. 97. 12 2 97. 13 2x3x5x7. lUO .11 2 1 18 3 12 1 4 1 5 11 5 6 6 j 10 7 ] 28 | 8 j 14 ANSWEKS. 415 P. EX. 101. 1 101. 2 101. o O 101. 4 101. 5 ANS. 16 7 22 124 62 EX. 6 7 8 9 10 ANS. 81 45 bushels. 25 acres. 12 feet. 3 bushels. EX. 11 ANS. $22 jyer head. 13, A bought. 21, B " 29, a " 103. 1 1260 5 10500 9 103. 2 7200 6 lOfcOO 10 103. 3 12G0 7 540 11 103. 4 1008 8 420 12 336 1176 1 AArods, $1680 12 112 men at $15 105 " $16 80 " $21 70 " $24 104. r 210 b ushel 1 60 days. 104. bags 105 times. A, 3 times. 104.' 13 ^ barrels 70 " 14 ■< B, 4 " 104. boxes 30 " C, 5 " 104.! hhds. 14 " L X*, 6 " 106.' 1 32 6 4t 11 9 dozen. lOf). 2 33 7 8 12 36 pounds. 106. 3 14 8 -/t 13 46 bushels. 106. 4 48 9 61^ 14 4 firkins. 106. 5 8f 10 27 1 107. 15 107. 16 107. 17 16|- t/a?/5. 8 pieces. 471^ bushels. IS 19 20 15 barrels, 6210 bushels. 6|- bushels. 21 17-^ bushels. 1 1 i rfc/ys. boxes. 41 111. 111. i_5 . 3J7^ 1 9 ' 4 9 • 27 . 9 5. . 1_0_6 40 ' 40 ' 4 £1- 4 . 4 ' 4 ^■! 45 . 5.6 , ^_h_ . 9_i . 3X 68' 68' 68' 68' 68" ^ J>_ • 8_7 . TLA • 6A • 8_5 . 9 a . \Vi_Q '-^190' 90' 90' 90' 90' 90' 90 ' 114. 1 18. 21 8 1 8 2 H • 41 • 9 1 > ^45 -^ 8 • 114. 2 "4 . 77 3 . 9 . 3 . 9 . 9 4 ' 8 ' 2 ' 4 ' 3 • 114. o 124. 129 ^3 1' ^31' 4 7 . 7 . 7 . 7 . 5 ' 6" ' 3 ' 2 ' 114. 4 ^ 9 . •:i2 3 5 17. 17. 17. J 7 . 1 7 . 17 . 17. 24'16'12' 8' R'4'^' ¥• 114. 5 9|; 12tV 6 6 . 6.6.6.6 20' 10' 8' 4' 2' 114. 6 5/9 ; m 7 7 . 7 .5 ' 7- 114. 7 8H; i6ff. 8 6.6.6. 6 . 6 ¥ » T' "6 ' 14' 21* 114. 8 213 . 10-7- 2^ 9 ' 2 9' 9 19.19. 19. 19 . 19 . 19 18" ' 1 2 ' 9 ' ■e ' 4 ' » • 114. 1 11-91 115. 1 8 . 4 , 2_ . _ T9 ' T9 ' 19' 1 V- i 4 12.10. 6 . 4 . 3 26 ' 26 ' 26 ' 26 ' 2 6" 115. 2 7.2.1 Tl ' 11' IT I 1 5 9 . 6 . 3 , 2 TT ' 19' 19' 19- 115. 3 10. 4 . 5 . 19' 19' 1 P ' T \- \ c 8 . 4 . 3 . 2 2 5 ' T5 ' "55 ' ^5- 416 ANSWERS. P. EX. 115. 7 115. 8 115. 1 115. 2 115. 3 ANS. 116. 116. 116. 116. 116. 116. 1 2 o O 4 o 1 119. 119. 119. 119. 119. 119. 119. 1I9.I 120^ 120. 120. 1 2 3 4 5 G 7 8 29 ' 9 _3 . 29 ' 6 59 ' 59 ' 3 . 24 ' _4_ . 45 ' Ji . 5 1 ' 3 , 28 ' __4 . 3fi ' 1 4 , 68 ' JL 29* 2 fo > 32- _4_ a 1- 2 4* 59' EX. 4 5 G 7 8 ANS. 3:1 4 0- 12 . 99 ' 121- 2.8 . ±2 3 2 > 4 3 4.0 . 6 i 5 5' 88 112 1 3 3 7 . X±2 . 84 . 168 TT5 ' 232' 174' 348 i-C. . 19 . _9_2_ . 115 50 ' 75 ' 100 ' T2^5- 2 . J 4 ' 2* 3 0_ . _3 0_ . 3 YS-^ ' 376' 51 y* _l_5_ . 1 5 . J 5 X I 9 ' 8 5' 5 I • J_4 . . J 1. . 14 18 9' 216' 1 W2' 2 5. , _2_5_ . _2_5 57' 133' 209- J JL . J i . _1 1_ 120' 6 ' 15 0' T.2.._ 5400 ~TT~ U 7 72 12416 10 11 1 4 801 "89 2 4 375 ~"73"- ANSWKKS, 417 p. 121" 121, 121. 121, EX. 9 126. 136. 126. ANS. T2 7 S'O _9_ 1 4' 5 1 "8 EK. 6 7 8 ANS. 1 fi r>4 35| EX. y 10 11 ANS. 147 4 16 EX. \2 13 AN- 3080 1 i-i. 122.1 1 63 • 448 . 72 84 ' 34 ' 84 1 9 . T2 ' 7 . 1 2 ' 6 . J_0 12' T^ 122. 2 126. 140. 30 . 2 10' ii ' 2 1 ' 525 iJlO 2 J.8 . 21 ' 8 . 21 ' M 122. 3 5 7 0. 260. 1 6 .5 , 60 ' 6 ' 6 0' 48 60 o O 84 . 2 ' 1 8 . ¥0 ' Vo^ 122. 4 16. 21. 20 . 12 24 ' 24 ' y* ' y-i . 54 ' 24 4 1 90 1 8 ;H . 132 ' Ts" 122. 5 4725. 540. 280 630" ' 630 ' 630 . 37 8 ' 630 5 T_8 6 30 . 25 ' 30 . 220 ' 30 122. 6 220 . 399 -4 2"! "T2" 6 32 . 40 ' 3 5 . 40 ' 5 80. ISO 4 0' 40 122. 7 5 . 9 ^"8' 28 7 42 . 72 ' 64 . 72 ' 204 . 99 T2 > 72 122. 8 88. 42. 99. lOf T¥ ' l¥ ' 1 8 ' 18 8 36 . 42 ' 7 . T 2 ' 32 . 28 4 2' 42 122. 9 1 .■■. 6 . 3 6. LP 5 . 30 ' 30 ' 30 ' ] 10 30 9 36 . 44 ' 33 . 44 ' 38 . 22 4 4' 44 122. 10 672. 264. 833 16 8' 168' 168 10 150 60 . 3 10. 54. 265 ' 6 0" ' 60 ' ISO 122. 11 266 . 9 . 129. "y T ' 2 T ' 2 1 ' ' /t 123. 1 6 3. 96. 70 168' T6S ' 168 4 1 29 24 .106. 7 ' 24"' 24 123. 2 1 .'5 . 1_ 8 . 3 2 4 2' 42' 42 5 254 3 . 12 ' 30 . 7 ' 30 123. 3 88 . 10. 9 3 2' 32' T2 6 642 66 . 9 ' 66 . ] ' 6 6 124. 7 1 05 42 136. 3 -42^' 4-J 12 20 . 174. 49 ' 20 ' 20 124. 8 1 4 48 5 6. 18 48 ' 48 . 27 > 48 13 354.405. 4 66 ' 66 ' 66 124. 9 96 1 08 20 . 21 10 8' 108 14 36 6 8 . 142. 73 » S8 ' 68 124. 10 3 4 8 78 555 . 10 7 8 ' 7 a 15 416.452.14. I 72 ' 72 ' 72 » 77 124. 11 1 24 3 6 226 . 37 "76" ' 36 125. 1 6| 7 1 1 1 ^20 12 92 1 ■^64 125. 2 2f 8 92J '-30 13 1187 -^1008 125. 3 2tV 9 9)7. -56 14 m 125. 4 4tV 10 9133 ~204 15 4tf 125. 5 6f 11 C> 97 "^144 16 2 4 5 1 '^2^040 125. G 03 "4 IS 19 20 5 . JL 6 ' 1 _2_2_. JLL. 12 0' 240 16.19 6 3' 90 1 5 . 54 ' ±3 40 21 22 23 q25 ^28" 1 ^337 ^"600 ' ^ 20 24 25 26 26^ 41S ANSWERS. r. EX. 27 28 29 30 ANS, "l 10 64 3 944 8 9 iqi 1 3 EX. 31 32 ANS. 17 80 $1 89 ^168 JU_ 1 26 °24 EX. AIsS. 60 36 37 38 2\2^^ pounds. 6o^^2\) pounds. 39 40 1 891-?- acres. 4 o f 347]4 bushels. H-fL- inches. 2 o O 4 2i/t/. HJ/t/-. Icdi'i. 2'7?'. 2lb. VZoz. 2oz. lOjjwt. l2(/r. 6 G 7 8 9 10 12 13 14 15 dcwt. Iqj: bib. 8^02. 20bu. \pk. 5^qt. Shhd. '61(jaLoqt.Qpt.\igi. ooda. 2hr. Aim. ohsec. 2R.20F.llsq.fi.5S^sq.{n. 1 inches. 13s. lOff/. 2da. 2hr. 30 to. 45,sec. 7/wr. 2//. ^in. 222da. Ihr. 2Am. \2cwt. \qr. llb.ooz. O-i-^f/r. 7 02. l/Jiot. 2ogrs. 5 signs IG" 16' 40^^". 16 17 \S\\yd. Oqr. 2f «a, 19: 20' 21 99 .24 25 1 coro?//. llc.//.466fc.m. 2 rorrf.v, 4 cord ft. 2c. ft. '3gd. 2qr, ■3A. 2R. \\cwt.2,qr.2\lb.nozAldr ofwr. Orel. 2ft. Gin. 2wk. Ada. Ilir. 49m. 33>P. 1 2 o O 4 5 6 7 8 9 2. 7 _3_ 1 9 _4_ 25 JJpO 305 _2_ 35 _5_ 48 2 195 •^"9 7 3K 10 11 12 13 14 15 16 17 18 43 7 -2 ^^] 5 ■^1 3.1 \ 8 '24 40 •">2 19 20 21 22 23 24 25 26 27 914 •^1 5 62J "40 8i ^8 I sold ;\i left. §72 I8IJ- gallo7is. 18-}|- cords. 33i,''jj pounds. 28 29 $22JL 30j 18|yan^s. 1| 934 6^^ "3 8 1 82-?-^ 1 2 3 4 5 G 9oz. Ipu't. \2firs. Icwt. \qr. 2Alb. 80; 29^a/. 3|-7^ \vii. \fur. \Q>rd. Is. ?>d. 38' 34f ". 7 8 9 10 11 563.4. OR. 35|P. lOc;t'A \qr. 22lh 9\\oz. Mb. 80Z. \6pu'(. IGgr. 2 cords, 2 cord ft. Ac. ft 5} in. ANSWEK3, 419 p. EX. ANS. EX. ANS. 133. 12 4 5 3 3 2 9 4^r 13 Ijjwt. I8^f/r. l3lT 1 3f. 15 5i05. . 11 1 24' 134. 2 iiiV 16 6975. 12 3 134. 3 n- 17 11725. 13 14. 134. 4 HtV 1 3 •'5 14 18. 134. 5 n- 2 12f 15 15 2V 134. 6 IG. o O 5^3 16 130-1. 134. 7 32f. 4 63. 17 ^3- 134. 8 70. 5 1781 18 14. 134. 9 44. 6 ^ ^231 • 19 63161 134. 10 1584. 7 19|. 20 ^h 134. 11 608 jV 8 9 20- 21 m- 134. 13 5987f. 9 21 40" 22 A- 134 14 4536. 10 .5 9 fi- — X W X. — 135. 23 4 T 31 $5i. 39 «8tV 135. 24 I 1 5* 32 $14f 40 55 cenfs. 135. 25 02 33 $f. 41 $34i. 135.' 26 20. 34 lli/OrtS. 42 $36. 135. 27 53 5 6- 35 $221. 43 43|- shillings. 135. 28 23 84* 36 $3tV 44 $325. 135.i 29 9 8 i 37 $14f. 45 $f. 135. 30 1 540. ; 38 $7|1. 46 3 lo- 136.! 47 $-g- 50 22 8i cents. 136. 48 $}.}. 56 SC)32f. 136. 49 $2Uf. 57 $ioi^ 136. 50 1 2}j days. 58 $12000. 136. 51 5^ hourfi. 59 /., yl'.; ^%,B's. 136. 52 $66f. 60 h -^■■^•• 136. 53 34 miles. 61 1 ^ 120 acres, A's; 80 ac?rs, i?'s; 136. 54 456Jc/s. i 20 «c?-e.?, (7's. 138. 1 \' 7 36. 13 2 5- 19 ^SH- 138. 2 3 28- 8 7 14 61tV. 20 OT 3 '^21- 138. 1 3 1 35' 9 2f. 15 16621 21 9tV 138. 4 3 31 9- 10 1 23 ■^40' 16 1363. 22 ^^^h' 138. 5 23 11 1 1 2 TJ5- 17 7 8"- 23 40 133- 138. 6 7f 12 1 7 M 2S- 18 26 33 1 24 1 37 ■^2 1) • 420 ANSWERS. P. EX. 1 138. 25 138.' 26 138. 27 138.' 28 138.! 29 138.' 30 138.* 31 138.' 32 138. OO ANS. 1 21" 3 IT* 4 ■JT- 1 To- _9 52 1* T23'* 40. 1120. EX. 34 35 36 37 38 39 40 41 42 ANS. EX. H- 43 243 5 0' 44 1 ] 2 1 So- 45 il 2 135- 46 u. 47 825J. 48 4193-5?-. 49 16046/2. 50 7 9- ANS. 2 7- 1 3- O0 6 "^781" 3i. H- 9-5- 7 O 53 "-180* 139. 51 139. 52 139. 53 139. 54 139. 65 139. 56 51/^5. i^ybs. 4^ hours. $3J-. 57 58 59 60 61 62 $1^. 6 ff a lions. ■| of the whole. 21. 973. ~' 8- 14-*- ^ 4 T 63 64 65 66 67 68 _5JL 3 fi3- 19|fZ6s. 14A6ffr. $ 140.' 69 140.1 70 140.' 71 140.' 72 140.1 73 140.1 74 $13i. 10S^\5Ms/i. 4 c/ay5. — 75 2|i io/^/e.s-.! SO 76 If rf(/y5. 81 77 SI 01 82 78 ^■ S3 79 6. 84 1 tunes. $^096. S43i. 1'^tV 142 142 142. 142 142 142 142 142. 1 l2'4- 9 2 ]B- 10 3 962 '^8 1- n 4 100. 12 5 1 6 8T- 1 6 5 7* 2 ' 7 H- 3 ' 8 — 350 549- O 68 •^1 19- 53|. 4 5 6 9 6 4- $15. 7 8 $171 9 n>' lies. 10 1 — jy47_9 ^~7 2- _4J_ 84 0" $26,1^. 1 5 yai %\^ m- 4 7 5 62429 ds. 3 sum i^^lJ?! (///f *"'"i 6 242920 "i'* 93 20 143 143 143 143 143 143 143. M3 111 12 13 14 15 161 \1. 18i ^ Lush. 1ml. 2fitr. \&rd. 2:Mh. Ifur. Iqr Ann. $20{ 272 sheep. 13 yards. 4oz. IS-j-j-i lOrd.'dyd dr. 0|T- 3 a A |19 20 21 09 24 ^5- 14 bushels. 20 {i $27 00, yfs share. $2800, 7i'.v $ 800, O's " 40 ?(A/. 14///-. 30ni. ANSWKRS. 421 p. EX. 25 1 ANJ. 1 EX. ANS. 143. £7 176'. od. O^far. 27 285i c/f/Y.'?. 143. ^P \ 24 marbles to JoJoii. ] 32 " to Jame-<. 28 . J, SO;/?, 24; (7,30; 143. D, 40 ; 66 remain. 144. 29 $467f. 3- I ' 7g Imshtls. 144. 1 $2^^, luhat it sold for. „^ j $1724i A's. \ $-,'\f^ = first one's gain. ^"^ \ $123 If, B's. 144. 30 144. ( $2^9^ rzr s-eco/2c/ " 34 166shiep. 144. O 1 «■>:-. 7. 1<)_ 145. 1 1 1ft. 2'. 6 2/. 7' 3". 145. 2 Gft 2' 6". 7 15//. 4' 10" 4"'. 14.5. 3 21//. 4' 11" 4'". 8 : /?. 6' 5" 5'". 145. 4 5ft. 7'. 9 ^ 57/lf. Kr 7" 4"'. 145. 5 n/ or' o'/r 10 ] 183//. 5' 6" 2'". 146. 11 223/?. 8' 4" 9'". 1 1 107/?. 8' 9" 2'". 146. 12 87/7. 2' 7" 9'" 6"". . - j 1721/?. 10' 9" 11'" sum 146. 13 '317/^. ir 0" 'V". \" -' I 280,/?. 1' 3" 9'" c/i'/: 147. 2 ioft. 6' 6". 7 19 4/?. 4' 3"' 6"'. 147. 3 82/?. 9' 4'^ 8 39 /?. 11' 2' 3"'. 147. 4 347/i;. 10' 3'^. 9 29 6/?. 10' 6". 147. 5 oo4/?. 7' 8" 8'" 3"". 10 96 sq. yd. 2sq.ft. 8' 3" 147. 6 2917/?. 0' 0" 7'" 4""-. - 148. 11 S;2Uts,Uli. 14 819/?. «' b". 16 2lD^r..yds. 148.! 12 89//. 3'. 15 $15,403 + . 17 $19.bOf. 148. 13 ^18,49J. 149. 1 4/. /'. 3 46ft. 6'. 5 li /?. (i'. 7 !/■/. 7'. 149. 2 5/;'.4ai"j6 4 8/?. 7'. 6 37 ft. 3'. S 8//. 153. 1 .06 7 7.008 3 9! )0027 153.! 2 1.7 8 9.05 4 .3 20 . 153.! 1 -3 .005 9 11.50 5 21 )0.000320 153.^ 4 .27 10 44.7 6 .3 610 153.i 5 .047 1 27.4 7 5 000003 153. 6 6.41 2 36.015 8 4( 3.0000009 154. 9 .4900 14 ] 05.00001)95 4 $275,005 154. 10 59.00G7 1 $37,205 5 $9.0U8 154. 11 1 .04 09 2 $17,005 6 $15,069 154. 12 79.000415 o O $215.03 7 $27,182 154. 13 67.0227 — 156. 1 1306.1805 4 1.5415 6 27.2Ub7 156. 2 528.697893 5 446.0924 7 88.76257 156. 3 159 37 19 4:22 ANSWERS. P. EX. ANS. EX. 13 AXS. EX. ANS. 157. 8 71.01 204.0278277 18 3.8896 ions. 1.57. 9 1835.599 14 400.33269960 19 $427,835 157. 10 397.547 15 .1008879 20 $19,215 157. 11 31.02464 16 $85,463 21 $670,975 157. 12 1.110129 17 $1065.19 158. 22 $30,286 3 9.888899 6 1571.85 158. 1 3277.9121 4 51.722 7 .6946 1.58. 2 249.60401 5 2.7696 159 J 8 .89575 16 6314.9 24 103.0150 159. 9 603.925 17 365.007495 25 .4232 159.1 10 1379.25922 18 20.9942 26 171.925 acres. 159.' 11 99.706 19 260.3608953 27 $82,625 159. 12 17.94 9 20 10.030181 28 $26.60 159. 13 .099993 j 21 2.0294 29j 126.84194 tons. 159.! 14 328.9992 22 999.999 30 $761.18 159.! 15 .999 23 2499.75 31 1181.725 pounds. 160. 1 .796875 4 1.50050 5 10376 2*3913 160. 2 .263872 5 26.99178 7 275539.5065 160. 3 .0000500 - — - 161. 8 .0206211250 16 .00715248 24 148.28125 ac.-w. 161. 9 28033.797099 17 .608785264 25 12.13035/i^. 161. 10 175.26788356 18 .02860992 26 -^24.0625 161. 11 .000432015770 19 2.435141056 27 $3192.005625 161. 12 216.91165850 20 1296 28 *210. 03125 161. 13 .000000000294 21 312.5 29x708.901875 161. 14 18616.74 22 .375 30 82.06525 (/ained. 161. 15 933.8253150761 2 23 .0036 16.3.1 \2 258.13007 |3 162.526 4 2757.89786 5 3566163. 165. 1 2.22 r 25.05068 r 41.622 165. 2 8.522 250.5008 416.22 165. 3 33.331 13 <^ 2505.068 . - 25050.68 4162.2 165. 4 1.0001 1 41622. 16.5. 5 12420.5 250506.8 416220. 165. 6 .005 4162200. 165, 7 4.25 r 48.65961 ( 254.7347748 16.5. 8 .007 4865.961 25473.47748 165. 9 .075 14 ■{ 48659.01 ^ 486596.1 254734.7748 165. 10 1.27 ] 2547347.748 165. 11 .015 4865961. 25473477.48 165. 12 17.008 1 254734774.8 ANSWERS. 423 p. EX. 165. 17 165. 18 165. 19 165. ;^o ANS. .13956463 + 1918.515 + .U0473O 174.412+ KX. 21 90 24 ANS. 69.7125 1.36S32 + 12976.81 + .004958 + EX. 25 26 27 28 ANS. 6.165c. yd. $9,875 $2.15 $0.62 166. 166. i6G. 166. 167. 167. 167. 29 30 31 32 18 2)oujids. 8 suits. 14 days. 55.5 bush. 269 acres. $13573.204 cost. $50,458 + , average jvice per acre. $7631.8855, elder s share. $5723.914125, each of others. 10970 G0200 1000 100 10 ; 100; 1000 ; 30; 20; 2000; 12; 1200; 500000. 168. 170. 170. 170. 170. 170. 170. 170. ,375 8.311+ II 4 1.563 + 4 5 6 7 8 9 1.1604+ I 6 16.119 + 79.1188 35.2843 11.5834036 ;5i3202.8S69 .25 ; .5 ; .75 .8; .875; .3125 015625; .2666 + 125; .003 2571+ ; .4411 + 23903 + 07157 + 4375; .078125 00448 11 12 13 14 15 10 17 ,536; .372 .9 ,7333 + ,48375 ,5128 ,5375;. 0056 + ,1666-f 171. 18 171. 19 171. 20 171. 21 171. 22 1.000 + .15909 + $100.80 $17.R5 30.011 + 24 1 2 o O 2.9166 + 2.8412 JL. 3 4 ' 4 8 ' 8 2 1. 1 4 5 6 7 8 16 03 2 0"0 .= 4 7 800 3 1 fiO 903 4000 200 ' 400 R4 jiOJl 5000 172. 172. 172. 172. 172. 172. .0546875/6. £.325. .olQda. 71.1511 + wz, .6625/6. / 8 9 10 11 12 .15375 ions. £.1225 .26175^. .100511+ m?, .&Acivt. .91111+ lb. 1 '^ 14 15 16 17 .875yd. .01587+ hhd. .7129975c/a .2325 ions. £.9729 + 173.' 18 173. 19 173. 20 173.; 21 173. 22 173.: 23 173 24 .48125.4. .5'oE.E. .0016177 w^^. .25625^ .0041956 7: .10416 cAa/. .00994318m/, 25 26 27 28 29 30 31 .791666 yr. .9111/6. .3375 .3125 chal. .0409»ii. .01875 ream. .02026rd 00 34 35 36 .19672y?-. .3489 fe .01537 + /iArf. .005A .ol25yd. 3.390625/i!. 174. 174. 1 J 2qr. nib. 4oz. 2 I Ih/id. V2,gal. oAAqt. o 4 16.s\ Id. 2.99/ar, 2gal. \qt. 424: ANSWERS. P. EX. 5 ANS. EX. ANS. 174. ( Iwk.Ada. 2ohr. 59m \ 56.0SCC. 14 ( o2mi. \fiu: Urd. I Uft. 9.4 0S/«. 174. 174. 6 b.F. 15 2/1. 1.5in. 174. 7 6cirL 3qr. 16 4 5 13 19 9.(Sgr. 174. 8 l/jhd. Algal. \qt. 17 '6R. \P. \3.3 \sq.1jd. 174. 9 20!/al. 1<7('.+ 18 9 sheets. 174. 10 lOos. ]8pwt.l5.99gr. 19 nibs. 174. 11 oqr. I. Qua. 20 Id. 2/ur. 174. 12 5/1. 11.9 4- ill. 21 IE. UP. 174. 13 j 24:F. 23i!q.yd. 5sq.ft. 22 286da. nhr. 18' 36''' 174. \ 82.4832sg. in. 176. 1 .06 5 .029729 + 176. 2 .09285 + 6 .034 176. o O .034370 7 .028 176. 4 .013281 + 8 .043055 + 179.1 2. . _fi_ -■} ' 3 7 1 . 15. • 1_ 3 7' 11 4 143 _4_ • 1 1 1 ' 7 180. 180. 4 5 J}. • 3fi ' 34 . 269 29 _v. .^. ..« . •'^74 ' 4" 9 "5 ' "BTTe ' "^ ' 9 2 1 7 . 1_ . A 1 2A6 I 45' 495' 75' 16fi5 9 . 223 . 7 54 31 0' 330' 99 9 99* . ] 6 3 . 4J. ' 1 fi 5 ' 9 182.11 2 |.]875'.||3|.0'0344827 + ||4P09756' ; .'592';. 5^3 2.4M8181S' .5M)25025' .008^497133' 165. urn 61 U/ .0P0I0 104' .03"777777' ;; ' • > Q o .1 o .-> ^ .0 00 O.J 00 .4'757o75' J.7'577o77' 9o.2'829647' 09.74^203112' 55.6^209780437503' 6 47.3'763']90' 216.2^542870' 185. 2 457^757' 6 185. 3 2.9^957' 7 185. 4 5.09 8 185. 5 .6o'370016280907' 9 186.1 2 186.! 3 186. 4 186. 5 186. 6 186. 7 186. 8 186. 9 5.53780^5 , 1.093^)86' 1.6411^7 1.7183\39' 1.1710^037' G.rOSG' ll.V)(;8735102' .81G54U68350' 4.37^4 4.619^525' 1.0923^7 1.3! 62' 937' o 4 5 6 7 8 9 13.570413'96103S' 35.024 7.719'54' 26.7837M28571' 3.r45' 3.'82a5294 117647058 1.2' 6 15.43'423' ANSWERS. 425 loi. 193. 193. 193.1 193.1 38 2 56 12 4 40 96 o 4 6 7 8 i 6 2 3 1 3 9 •10 11 5 ■A- 9 TT 195. 195 195. ]95. 195. 195. 195. 19.5. 195. 1 2 3 4 5 6 7 8 9 $330 $90 504 miles. $2,08 $875 99 pminds. $2762,50 $20 $122,85 10 *> 11 12 13 14 15 16 17 18 1400 pounds. 16485 miles. $121,871. 216 shillings. $3533,936-}" $86.62 £39679.105. $39,371 19 20 21 22 23 24 25 26 bo §382 S63 $0,036 $2,52 $1,925 $2,10 $52,50 198. 196. 196. 196. 27 28 29 30 $7200 137,909 + $132,589 + 31 32 $18,66f 35 $56,355* 36 106|- yards. 37 40 weeks. J $112,86 $5427 2l^a^. wafer. 197. 38 197. 39 197. 40 197. 41 197. 42 A, $2142; $0,62|. G|- bottles. 1261-1 shilli 168 povnds. B, $1125, ngs. 43 44 45 46 47 9o 55 $1 6/i 14 |- gallons. 2 miles. 7444. o 0// '6Zm. A^^jsec, 19 i26 ANSWERS. P. 197. 197. 198.i 198.1 198J 202.1 202.i 202.1 EX. 48 49 ANS. A, 155 miles; B, 124 miles. 14. days. EX. 50 ANS. 22^ days. 51 52 53 As, $88,40 ; £"s, $77.35. 10/i?-. 40m. 36^yec. 48??i. l^sec. 54 55 $24,66^ 3* 16^ times. 1 2 o O 9 yards. 8-| roc/^f. ] CO yards. 4 5 7-1- (iays. 10 6 7 920 54 days. 203. 203. 203. 203. 8 225 f%5. 9 13 ounces. • j 588000/6. I 546000Z/^. 10 1] 12 13 { 588000Z6. 14 ounces. 20 f/ays. 54 f/ays. 14 12 days. 15' 6 " le'ieo " 17:40.47. 18 120 mn. 19 51 da;/s. 204. 204. 204. 204. 20 21 22 23 45 7nejt. 13f ounces. 13 jY (^ia!/^- 201 days. 24 11 Of rods. 25 ho'^days. 26 8j-L cioi. 27 136 me?z. 28 29 30 6 horses. 857 1|^ plan/cs. 3 hours. 207. 207. 207.' 20J^ 208. 208. 208 210. 210. 210. 210. 210. 210. 210. 210. 210. 1 2 o O 4 161 dai/s. 5 7200 men. 6 \%l^mihs. 7 72 acres. 8 10 daus. d2\ days. $36. 292.5 ^aZ. 9 10 u 1 156 tailors. 19600 men. 50 wie;*?.. 12 13 14 $471,04. ■3\^da. 180. 15j600. 16 14f fZa. 17|7i-oz. 18 19 20 971/6. 32 days. 32 horses. 215 vien. 22|132 days. $1000, A's. $1200, i;'5. $ 800, C's. $1714,28A ^V $285,7 If, B's. £4030, ^'s. £3980, //.v. £3980, C's. £4010, i>'s. , ' f=5000 As. §2500 i?V <^ .$33331 CV §2500", D's. $6666f,^'*'. 100, As. 140. B's. 200, (7'5. OClOO-.r,Jl .S. $3000, B's. $3000. C"5. $26G6f , Z)'s. $1500,soM'.'?s/t. $3000,?//o'.9s/i. $12961,50 .fs. $1 5737,25 ^'s. $10802,25 (7'5. ^l^ooj/sgiiin 211. 211. 9 211. 211. 211. 10 211. 211. 211. 11 $450. $600. $750. As, $4242,50 s 7i'.v, 15939,50 C".s§.6788 $237,75, As. $181.0025, B's tack : $;1697 gain. " §2375,80 " " $2715,20 " 11 12 13 ($125.4375 6' I $70, .D's. $12720. f $87,831 +.4 $65.06 -f- B. $18.795+C $68,313 + Z) ANSWERS. 427 p. 1 EX. ANS. 211.! (Sl015,33i the first. 211. 14 ■} $1523,00 " second. 211. '■ (S2030,66f, " third. 212. i §16,38, A's. r> ($6577.23A±3^^'5. 212. 1 { $35,10, £'s. |$1S22,76L46^^'5, 212. 1 SI 8,72, C's. ( $288, A's. 212. 2 S7. 4 \ $270, B's. 212. — I $2-10, C's. 213. 5 J $280, D's. } $163, C's. r $84, A's. 213. 8 $90, B's. 213. ($1309,43^;^^, oj/i :ers. ] $82,50, C's. 213. 6 ■\ $2946,22f|f, midshipmen. $90, D's. 213. ( $10504,33^1^, sailors. ($2, \ St grade. 213. 1 $2648,86-i-\. A's. 9 ■^ $ 1, 2d " 213. 7 n2901,13-rV, ^'5. ( $0,50, M " 213. ( $1850, CVv. 10 \ $800, 5'a' stock. 213. \ 1 5 Hio.9. C's time. 214. 1 .095; . 0575. 3 2.08, 3.75 ; .95. 214. 2 .125 ; .09875. 4 .666f. 215. 2 $3,14 9 16.74 nid.es. 16 $4344,35 215. 3 $4,7825 10 47.725 sheep. 17l2625/;ar. 215. 4 ■i. 562 5r/ds. 11 27.54 tons. 18'$5144.625 215. 5 2.S3937 ociot. 12 $300,365. 19 $12500 215. 6 \.002lbs. 13 15,75 coius. 20 $3867.01875 215. 7 126?/. 14 1 60 bales. 2l'$15000 215. 8 $90. 15 478.1 25yi?. 22 $65 216. 23 742,85 gallons. 26 $6093,75. 216. 24 205 boxes. 27 $196,59375. 216. 25 .421; $10625. " i 217. 1 .20 5 .25 9 .01375 13 .05 217. 2 .125 6 .875 10 .33^ 14 .035 217. 3 .075 7 .625 11 .375 15 .72 217. 4 .136 8 .0075 12 .125 218. 1 1 %'i per head. \ 2 $5425 |3 $50000 4 $5000 220. 2 $60.9875 7 $283,8438 12 $373,2495 220. 3 $221,91 8 $422,8976 13 $735 220. 4 $360,2832 9 $1112,90 14 $1016,075 220. 5 $473,844 10 $265,2345 15 $120.80 220. 6 $1312,5 D 1 1 $1893,75 10 $5796 423 ANSWERS. 221 221, 221 EX. 2 3 ANS. $20,9U9 $26,313 $458,88 EX. 4 5 6 ANS. $1979,5013 $5618,75 $628,4162- EX. 7 8 ANS. $64,0625 $157,65625 o 4 5 $42,2432 + $420,2531-1- $213 $181,25 $11,0415 $132,7707-1- $26,95864- $416,16734- 10 11 12 1334,21874- $120,0694- $40,0908 13 14 15 16 17 18 *"> 1 ol 33 2 o O 11 12 2 3 2 o O 4 $81,67784- $162 $221,266 $389,24 66 $135,3714 $42,94044- $933,1574- $499,3394- $140,6444- 19,$84,6855 20855,66854- 2l|$32,6664- 22:$8590,8324- 23l$36 24!$93,78434- 25 i $160,44084- 26 27 28 29 30 $12,9644- $82,0364- $70,964 $879,467 $801,769 34 35 36 $5085 $403,858 $9337,50 1 2 $394.325-f $697,986 226. 226. 3 4 $3339,613 $823,9024- 5 6 $4640,5324- $1976,634- 227. 227. 227. 2 o O 4 £45 8s. l^d. £45 12.S. 4 It/. £154 7s. Od. 2 far. 5 6 1 7 £1133 106'. 9}d.+ £199 6s. 3^d. £6 16s. 5cl. $3976,7824- $439,80 $6234,76-h $30000 5 6 7 $952,576-(- .07 .09 8 9 10 .10 .05} .121 2yr. 67710. omo. 18da. 13 14 lyr. Amo. i6yr. 8mo. 15 16 Syr. 4??io. lyr. 6mo. 20fl?. $5359,3664- $8925.544 4- 4 5 ^1127,041 S190,758 G I $156,204- $25,3575 5j291,7215 $57,3048 5 6 $73,015 $83,20 7 8 $845,837 $48165,936 234. 234. 9 10 $14523,555 $926,744 11 12 $8501984,90622" $124,1624 235. 13 $151,5811 14 $16,3875 | 15 $445,857 236. 1 $562.50 2 1 $184,499 4- I 3 $21 \ ANSWERS. 42\^ p. EX. 4 ANS. EX. 10 ANS. 236. $5000 ($3538, 083 CMA'Ava/. ($388,083 gain. 236.1 5 $1902,557 + 236.i 6 ($2763,703 2^r. vol; \ $236,297 disc'L 11 $9890,239 238. 12 $10,890 loss. 236. 7 $4820,537 13 .00414, a^ic/s. 236. 8 $4800 14 236. 9 $1379,6123 + 15 ($2369,2617c«sAmi ($61,9883 diff. 236. — 240. 1 ^6,15 5 84,374 240. 2 $7,65 6 882,591+ gain. 240. o j 2'i,2'^\^ discount. \ $476,708^ pres. val. 7 $11,785 difference. 240. O 8 $15,4044 diferejice. 240. 4 81 225,3555 ^9/-e6\ val. 9 8981,21 cash value. 241. 2 $296,50 1 3 $697,20 4 $474,375 242. 5 $3522,092 243.; 3 $34,8375 H $25420,195 243. 4 $164,53125 9 86835,283 243. 5 $96,33 $5831,67 10 8935 243.! 6 ( $163,80 commission. \ $4340,70 whole cost. 11 \ 863,625 cotn'n. 243.! I 4544.642+ 6 wi-Ae/s. 243.' 7 8115,39 + 244. 12 $255»,16 15 15 tons. 244. 13 (158 barrels. \ $2412.66 16 870 244. 17 20 shares. 244. 14 $420,922 18 $55743,289 216. 1 85320 1 3 859110 216. 2 $666 4 821375 247. 5 $7999,6875 7 $300 247. 6 $213500 1 $3529,41 + 248. 2 56 shares. 5 $6000 248. 3 $4000 6 $10432,432 + 248. 4 $7235,142 + 249. 1 1 .08 o .08 5 .4166 + '249. i 2 .20 4 .03 6 .05 250. 250. 2 o 7 per cent, the best. a i 41,^ h^r.t 4 $166,66| o 1 o pvr i;cnc. lug (yco(. }j 251.11 1 1 $33,75 2 1 $0,56 3 I $236,25 430 ANSWEKS. P. EX. ANS. EX. ANS. EX. 4 AXS. 252. 252. 1 2 $170 548,80 $6,0053 $70 gain. 253. 253. 253. 1 2 3 $0,90 ) $3,20 $0,96 4 5 6 $5,70 ■ii; 18,03 $0,66 7 $1,80 254. 254. 254. 254. 254. 2 o O 4 5 .18 .25 the same- .80 .25 7 8 $160,34375 wliole gain. ] .046+ 2->e?* cent. .45 $25,65 lost. 263. 265. 265. 265. 1 o 255. 255. 9 10 .U5 ^;er cent loss. .40 11 12 $508,50 256. 256. 256. 1 2 o O §50 168,59 S158,40; 8237,60 $126; $252 4 5 6 $300 $89,55 $47,8125 7 8 $1252,125 $163,80 257. 257. 257. 9 10 11 $16481,25 loss. .051 .Olf 12 13 14 .04i $2i'ooo $9020 15 16 $127,4625 $298,2546 259. 259. 259. 1 2 o O $121,72 $232,50 $262,50 4 5 6 $20 $98,20 $120 7 $9101,635 260. 260. 1 2 $411,15 $757,908 O 4 $1227,395 $1318,94 262. 262. 262. 1 2 3 $7051.63415 $9049,53795 $23058,6765 4 5 $16355,52 $2160,90 $2159,6134- 'g^per cent. $37901125 1^ per cent. $82,25 $56,9075 266. 4 ^perct; $15,50 (.015 on $1 \ $112,50 ($18 266. 5 $5820 8 266. 6 $22236,197 266. ( $4656,05 whole tax. 9 ($7,40 ■[$9,225 286. 7 \ .005 on $1 ; $27 266. ( $6,8775 6^'s;$12,78ir'.v. 269.11 3 I $260,9932 4 I $713,37 ANSWEKS. 431 1-. EX. ANS. 9 ANS. 270. 5 iVr. l^rwt.lqr. 16.G8/6. $1190,343 + 270.! 6 3 T. Inot. 10 $744,546 270.i 7 \ GT.]3cwt.2gr. Alb. 11 $250,835 270.; \ $308,4774 12 $4,09 + 270.' 8 $792,612 13 $125,S0| 271 271, 271, 271, 271 271. 272. 14 -S39S.il 99 + 20 $1512 15 .$'166,273 21 $423,36 . 16 $1101,24; $0,14 22 1251,453 + 17 $7936,50 23 $1457,75 . 18 $820,4625 24 ( 22.605cdi';. tare. ($68,5856 duty. . 19 §16,206 + 12 months. 273. 273. 273. 273. 2 3 4 5 9 mo. B^mo. 1 mo. oda. 64-mo. 4 6 7 8 21+ daj/s. 6mo. Gda. 2(j^da., or on July 23 274. 274. 9,^1 io!s S^'^Jjda. or on Sept. 19 ISl^da. or Dec. 30th 11 12 7Sfy(/., or Oct. 19 59.(57da., or June 28. 275.1! li*0,50^ 276. 276, 276, 2 o O 4 80,66 $0,49 $1,00 o 6 7 75" 19 carats. $0,13i 80,30 278. 278. 278. 1 2 {1 lb. at Sets. 1 lb. at Qcts. 3 lb, at lActs. Mb. each. 1 calf", 2 cows, 1 ox, 1 colt. 3 gallons of water. 279.11 I I 20 pounds of each. 2 I 75 pounds of each. 280. 280. 280. oG(/al. at 7s., 24/7a/. at 7*'. 6c/. and at 9s. 6c/., I2gal. at 9s. 10 at $2, 15 at"'Sf. 2olb. at 5 and 7, 100 at 7Jc;s., 37^ at 9^, and 50 at \Qcts. 281.! 1 22 pound of each. 281.1 2 9gal. of water, 40^ at $2,50, 13^ at $3. 281. 3 12 calves, 12 sheep, 16 lambs. 281. 4 8 at $6, 8 at $7, 4 at 819. 281. 5 ^Qfjal. at 4s. and \Qgal. each at 6?. 8s. and 10s. 281. 6 6 vests, 12 pants, 6 coats. 281. 7 30 at 15 carats, and 4 each of 20c., 22c., 24c. 281. 8 10 at 81, 15 at 81, 10 at 85. 288. 1 88591,975. 432 ANSWERS. P. EX. AN 3. EX. ANS. 289. 2 $8637,168 + 2 $176204,4729 289. o S9777,636 £14014 17s. 7J.+ 290. 4 $6005,368 2 .07 'p<:r cent al/ovepar. 290. 5 $807,874 + 291. 3^^12286,06 (§1250,52 291. 4184097 f'7tcs66 centimes. ( .03 ijer cent nearly, below par. 291.':li$0657,G93 - 299. 1 1 22Dj\ ions. 3|729^V5^««^'- 5 1006,57 7. OQO i o 43841 ^^"*'- 4 300.14 r. i ^yy. 1 ^ 301. 116 15 iH 1 29,76,765625 301. 2225 16 1225 7056 30! 10,4 976 301. 3:676 17 1 " fi 2 h TT 1 f ) 9 3134012,224 331. 4 20164 18 7,84 32.0184528125 301. 5 214369 19 58,140625 '^'^14 09 6 301. 6 1795600 20 250AV 34iM 301. 7 605,16 21 51030,81 3 ^ 8 1 301. 8 .276676 22 216 36 3l54|f 301. 9 9,765625 23 13R24 -^^ ^^'10 2 4" 301. 10 .00274576 24 373248 3R 390H2 5 "^153 1 44 I 301. 11 60639,0625 25 1953125 39 i48a6,936 301. 12 9 26 2515456 40 ,( )002441 40625 301. 1 • > 3 6 27 20736 41 2 893640,625 301. 1449 28 59049 12 1 0,272025 307. 1 7 8 2 .5 15 .1581 + 22 3 7 307. 2 12 9 1 6,7 16 .779 + 23 .2828 + 307. 3 15 102 505 17 .149 24 11.618 + 307. 4 48 118 9,409 + 18 5,01 25 137,84 307. 5 6 9 12.^ 153 19 14,015 26 .885 + 307. 6 15 4 13.5 33 + 20 1,2247 + 27 75.15 307. 7 .1 4 14.i )68 24 21 53 28 400.06 309. 1 30//. 2 221 stones. 309.1 1 343 3 21y9j- rods. 310. 4 ( GOrds. wide. I \SOrds. lonq. 8 94,708/7. 310. 9 53.331/1!. 310. 5 10J.0/^.29P.168f^5'.//. 10 8,660 //!.+ 310.! 6 15 ft. 11 825,8 mikfi. 310.! 7 1 35/V. 12 $100 ANSWERS. 433 r. EX. AiNS. EX. ANS, 311. 311. 311. 311. 13 14 15 16 loft. 28.28 +/<. 6i/(. 11.041rf/5. 17 ( 4.405 + i/i., 1st man's share. -' 5.739 + ni., 2d " ( 13.856+?;;., 3d " 315. 1 12 5 179 1 2,028 + 5 .729 + 315. 2 49 6 364 2 12,0016 + 6 .0]5 315. o 36 7 439 O .232 + 7 .188 + 315. 4 247 8 3072 4 27,0002 + 8 4,339 + 316. 1 316. 2 316. 3 316. 4 316. 316. 6 316. 7 316. 8 316. 9 316. 10 5 9 4-1- 7. B 9 2.S 2 7 f>4 35 1.987 + 3.83 + 1 2 3 4 5 6 7 { 27/V. 19//;., length of each side. 2l66s5'./(f., area 36/?., length of each side* 8.57+//. 9.77 />., length and breadth. 19.54 +/;;., height. 10.125 c?i. /it. 45 cents per yard. 2025 whole number of yards. 317. 9 317. 10 317. 11 317. 12 317. 13 317. 14 317. 15 317. 1 317. 16 317- 319. 64/65. 8//., length of each side. 8 jrlobes. $1331 12m. long, 6m. wide, \m. thick. 24/. long, 20/. wide, 9//. deep. 20 feet. .54 + Mi., 1st woman's share. .69 + ^;., 2d " .99 in., 3d " " 4th, 3.77m. '89 \ 2 1 $80 II 3 I §396 320. 320. 321. 321, 321, 4 5 1 2 174i'(/A-. 20 !/., to bring back the nearest. 1 2 5 miles. $2 fftw. ij;2730 §64,96 79l-l-m2. I0??z«., 7/Mr., 27rds., \\yd. 322. i 1 5551^*2/. 1 2 1 13rfff.; 'M2ini. | 3 | 6 324. i 2 3125000 o 4^ 325. 325. 4 5 100000000000000 .$3200 6 7 $54000 $327,68 434 AKSWEK3. P. EX. ANS. EX. 4 5 ANS. 326.1 326.' 326. 1 3 118081 2044 811184810 $4294 9672,95 93S249922+ ships. 34i.';2i $4166,40 28 2i|- hours. 32 117/A. 36 $5600 341. ;2o 9f days. 29 OO S693 37 $0,071 341. 26 36 feet. 30 $100 1 '34 1 1 cents. 38 $126 341. 27 §1770 31 5i yards. j35 9;56 39 $44,10 342. -10 $43 r 60 the first. 342. 41 $240,75 gain. 47 100 " second. 342. 42 5//.r. 21 mi. l&^jscc. 1 140 " third. 342. \o 40 yards. ISO " fourth. 342. 14 10 hours. 48 16-i inches. 342. 45 36 days. 49 2y^;j months. 342. IC 11^ days. 50 ( 35J- yards baize. 342. I $2,20 per yard. 343. 51 $12 1 r-^^2317,15.4's. 443. 52 $1,20 ' '\<-. $1853,725'.?. 443. oo 'S7 S. 652 + discount. OO i 1 $2317,15 6"6\ 343. 54 8129,60 827S0,58Z>'s. 343. ..- \ $19,375 most advan- f $95,10.1'5. 343. 343. 56 ] tajTL'ous for cash. 1292^.823 gain. 59 $95,l0i>"6-. ' $133,1 4 (?'s 34:}. (SI 22,7 O^'^'. \ Si 63,60 Z^'s. (§1 96,32 6"6-. $l52,16/;'6'. 343. 57 60 71 ounces. 343. G] 8f days. 343. — 1 1 ;62 17 times. 344. 63 41| days. II ( 8172,78+ more advanta- 314. 64 5 months 24 day-s. 167 < geous in bond and inort- 344. 65 68 days. i ( gaae. 344. 66 126":allons. 68 $3312,417 + 344. 70 1 69 §42,60 1 345. 4 yards high. • [ 77 836000 345. 71 20 hours ; 140 miles. 78 41,183+ bushels. 345. 72 f S2 the lirst. 79 137.942+ feet. 345. ( $6 the second. The second. 10 dava 345. 73 100 thousand leet. ailer the od ; thv.' 345. 74 91 39 ~ ' 5 80 < first, 8 days after 315. 75 $3825 the second, or I"' 345. 76 i>144, better to pay casli. days after tlic .'i 1. ANSWERS. 435 p. 346. 346. 346. 346. 346. 346. 346. 346. 346. EX. ANS. EX. ANS. 81 §6890 86 12ibs. soap. 82 ( $13 16, whole cost. 87 5 o'clock 20m. P.M. ( -^7, cost per acre. 88 $f = $0.66f. 83 32 days, or Mar. 1 6. 89 j 24 chickens. 84 (512 slabs; (36 turkies. "[ $302,222., cost. 1 $350 A'&; $297,50 B's; 85 \ $210 C's; $175 D's ; f $122,50 E's. 347. 90 347. \ 347. 91 347. i 347. 347. 92 347. 347. 347. 93 8 days. $1707,50 first, $2157 second, $2516,50 third. $960 stock; $180 gain, first. $640 stock; $120 gain, 2d. 49.945+ leet. 94 95 90 97 98 99 8 llri/i;- ( $5331+ A's. oi' a week. 1341 miles. \ $8&8f + B's. ( $177,H C's. 36^ days 84485,006 feet. $200,06 in favor of" 1st invest. 348. 100: ^3599680 cubic yards. 102 $4004,338+ 5th. 348. 101=! ^4646,363 1032160 men. 348. 348. 348. 102 '$1555,017+ 1st. $1354,717+ 2J. ' $4304,663+ 3d- 104 105 j $57,142 A's. I $42,857 B's. $31 348. 1 ^$5781,263+ 4th. 106 8 hours. ( $30 com. diff i $2160 whole cost. '$144,03 A's $ 90,12 B's $ 63,45 C's $168,35 D's .06397 $14467,505 111 112 113 114 971 pounds. |- of a cent cost ; I of a cent sold for; -^^ gain on each ; 80 eggs sold. 84 years. 942.'48+ cubic feet. 155.4. -.iR. 38.72P. A, 25 days, B, 30 days, C, 37-^ days. $365,837 nearly 118 119 120 121 (j-fjf hours. lOSy"^^ planks. 5 inches. ■^4006,54 + 3o2. 2 .■> o 36 acres. ! 5 A IR. 15P. ! 4 I ] 35 acres. 43G ANSWERS. P- 1 EX. ANS. EX. 5 G 7 8 ANS. 353.! 353.! 353.' 353. 1 2 3 4 437 A 2R. 3lP-i- 291^. 2/i. IGP. 35^. Oil. 2oP. 20 A 40^. \bA. 2\A, ]R. 8 P. 26 A. 3Ii. 20 P. 0,/d. 354. 354. 354. o 4 21 A OR. 39.824P. 921.875.V.7./5. 704.12o.v^. V^. 6 60 A SR. 12. 8 P. 270 A IR. 24 P. 355.1 2 355. i 3 356. o»4.33/G 125.664 4 2 17 9.U712 7418 4360.8354- 19.635+ I 3 I 153 9384 || 4 | 1.069 +.S7. yc?. 357.1 357.1 358. 358. 358. 359. 359. 615.7536 4071.5136 19699657 1.7221046^. mi 2 »■> o 4 268.0832 2144.6656 c. in. 2599927920826.6374908 1 2 904.7808 c./(5. giOOsy./^. ]440.s^y./i;. 2 3 110592 c. f/z. 42|c.//. 4 5 315f^ gallons. 13820 eft. 360. 2 360. 360. 4 360. 2 361. 361. 233.334- ^ sq.ft. 2827.44 sy. zn. 6283.2s(7./;;. 36442.56 4 5 13571 712 9650.9952 7363.125 2 o O 4380 2484 5620 5760 6 7 14400 1800 362. i 2 9160.9056 8659.035 4 1 2827.44 364.1 2 32.4938i/z. |l 3 28.2574i;z. 365. 365. 365. 1 2 197.459-1- gal. wine. 162.613+ gal. beer. 3 4 ( 136.9209+ wine gal. (112.7583+ beer gal. 148.3772+ wine gal. 3 67.11 1 I 40ZA. 36S.I 5 368.! 6 25/6. 50/*. II 4 I 2U/A. AOlb. l/ji., lirin., 2m., Ain. 7 8 64//;. 150/6. 370.11 1 I 60//?. 2 I 40/6. II 3 I 25/6. 371.11 1 1 Ufi. li 2 1 U//. 372.11 1 1 40/6. 11 2 1 100/6. || 3 j 60/6. II 1 576/6. 373.11 2 1 2250/6. — 374.11 1 1 259200/6.11 2 |1.47 + /6.1l 3 I 1.1 + /6.II 4 1 1.2/??. ANSWEKS. 437 p. KX. ANS. EX. ANS. 375. 1 23»z/. 2760/^. 7 Gda. iWu: 375. 2 57 GO/"/-. 8 131 A 875. 3 21ir. 56 m. 9 Gini. 050 5. ^ ft. 375. 4 8fi. 10 Shr. \2>n. 12||.5ec. 375. 5 2'3^sec. HA 11 8m. IG.Gsrc. 375. 6 12 1 G4.285?m. 377. 1 377. 377. o 377. ^.< 377. o o 377. 4 oG9]Ui. 23 1 G?/. 3Gl8f/if. 4821 /■/. 223^ 21.V.C. < ft. nearly. 6 7 { IGOSl//. 321 g- velocity. 2mi. 49S4j^s ft. 164.G9 ft. 100.52/1. 375. 10 678. 11 378. 12 1447.5//. C1.24SPC. 13 14 15 14.2S+ " 15U5011|/i;. 23 1 6//. 380. 380. 380. 380. 380. 380. ] 2 3 4 5 G 8.857 -m^c.ft. .9S0 2ft. 11.383m. idoT. lom. 2.75 7 8 9 10 U — 7.234 .78G .875 177//;. 5oz. 1.103 381. 381. 381. 12 13 4.23/«. (3.172 \ .504 14 15 4.57202. 1418/i. 3.38410S. 382. 382. 382. 1 2 3 3.497/5. 37.5/6. 2.4Go-r. 4 5 6 ..^319 1 wa 4 S. BARNES & COMPANy's PUBLICATIONS. Page's Thtory and Practice of Teaching. THEORY AND PRACTICE OF TEACHING? MOTIVES OF GOOD SCHOOL-KEEPING. BY DAVID PAGE, A.M., LATB PRINCIPAL Or THE STATE NORMAL SCHOOL, SKW YORK. •I received a few days since your 'Tlioory and Practice, &c.,' and a capital (A«*r» Bud capital /iractir.e it is. I liMve i\-:u\ it with iiiiiiuiiv'lfcl ilclii;lit. Ev}- keepiii? carried ul in every school-room : and as nearly as possil)liN in llie style ia wh':3h Mr. Pa^e illustrates them in his own practice, as the devoted and acconiplifhud Principal of your t^tate Normal School."— //c;n-y Barnard^ SupcnnUndciil vf Comnuv Sthooii for the atate uf Rhode Island. "The 'Theory and Practice of Teachins,' by D. P. Page, is one of Ihe best ()ookB oJ the kind 1 have ever met with. In it the tlieory and practice of the teacher's duties ere clearly explained and happilv combined. The style is easy and fainihar, and the BUgKcstious it contains are plain, jiraclical, and to the point. To leachers especial!? d wUl furnish very imporUmt aid in dischiu-sing the diitie«,of Jieir hc;h and respuasiiila profeMion."— /eoger 6'. Howard^ Siuieriiitendent of Ck'mnion SchuoU, Uratss I'o.y t'U A. 8. BARNES AND COMPANV's PUBLICATIONS. No rthend' s Teacher and P arenl, A NEW VOLUME FOR THE TEACHEr's LTBRAET. THE TEACHER AND THE PARENT: A. Treatise upon Common-Scliool Education, containing Practical Sug- gestions to Teachers and Parents. By Charles Northend, A. M, late, and for many years, Principal of the Epes Scliool, Salens. Now Su'Derintendent of Public Schools, Danvers, Mass. ■■•"Wfi may anticipate for tbis work a -wide circulation, among teachers and friends of education. The extensive and liigb reputation of its autlior, indeed, will bespeak for it more than pen of ours can do. It is a work of about three hundred and twenty pages, in good size tj'pe, and presents a very plea.'^ant appearance to the eyc^ BS well as the work noticed on the preceding page, both of which, for their neat appearance, do great credit to the enterprising publishers. Mr. Northend's book will prove interesting to all, and of great benefit to teach- ers, especially as a chart for those just commencing to engage in the profession. As a r.aOe mecum, it will prove a very ple.asant companion, lor its pagi-s are tilled with the results of a large experience presented in a very pleasing form. We are glad to find that the author, in furnishing to teachers so useful a work, has not neglected the svaviter in modo, and has here and there thrown in a pleasant anec- dote, which will enliven its character, and make it all the more acceptable. Wo shall have frequent occasion to refer to it hereafter. In closing this short notice, we would assure our readers that a perusal of the work will more than realize to them the truth of all we have attempted to say in its favor. Appended to tho volume will be found a catalogue of educational works suitable for tho teachers library." — Massachusetts Teacher. "We wish that this interesting and read.ablo volume may find a place in every family, and we are certain that it ought to be on the shelf of every school library in the land."— 5aZem Gazette. "It presents a multitude of practical hints, which cannot fail to do good service In enlightening all laborers in the tield of education." — £ostvn Transcript. "We unhesitatingly commend this volume of sound, practical, common sense snj- pestions. Every seboid teacher should carefully examine its paces, and ho will not fail— he cannot help receiving — invaluable aid therefrom." — Boxton Atlas. "We h.ivo examined this work with care, and cheerfully commend it t? parenti Md teachers. It abounds in judicious advice and sound reasoning, and cannot fail to Impart ideas in the education of children which may be acted upon with the most beneficial results." — Boston Mercantile Journal. ""Kiis is an Intelligible, practical, and most excellent treatise. The book is •nlivened with numerous anecdotes which serve to clinch the sood advice given, m well as to keeji awake iho attention of the advised." — Boston Traveller. "Tub la a sterling work of groat value. It should be In every fimlljr. A!^ t««oh ITS need just «uch a work." — Boston Olive Branch. A. 8. BARNES A COMPANY'S PUBI.ICATT0N8. Mansfield on American E du ea tion. /MERICAN education; ITS PRINCIPLES AND ELEIIENTS. DEDICATED TO THE TEACHERS OF THE UNITED ST/'l'I.i BY EDWARD D. MANSFIELD, Author of ^'•I'olitical G-rammar,'''' etc. This work is suggestive of principles, and not intended to point o;-* r, eourse of studies. Its aim is to excite attention to what sliould be tii« elements of an American education ; or, in other words, what are thfl ideas connected with a republican and Christian education in this period of rapid development. "The author could not have applied his pen to the production of a book upon a subject of more importance th:m the one he has chosen. We have had occasion to notice one or two new works on education recently, whi^h indicate tliat the attention of authors is beini; directed toward that suljject. We trust that those who occupy tho proud position of teachers of American yoiUli will find much in these worlis, wliich are a sort of inlerchanc;e of opinion, to assist them in tlie discharge of their responsibie d'.ities, "The author of the work lietbre us does not point out any particular course of sliulies to be pursued, but conliues hirasell to the consideration of the principles which should govern teachers. His views upon the elements of an American education, and ila bearings upon our institutions, are sound, and worthy the attention of those to whom they are paiticularly addressed. We commend the work to teachers." — Jiuohester Daily Advertiser, "We have examined it with some care, and are delighted with it. It discusses the whole subject of American education, and presents views at once enlarged and compr& hensive ; it, in fact, covers the whole ground. It is high-toned in its moral ana religious bearing, and points out to the student the way in which to be a man. It ehoidd be in every public and private library in the country." — Jackson Patrwt. " It is an elevated, dignified work of a philosopher, who has written a book on tho Bubject of education, which is an acquisition of great value to all classes of our Countrymen. It can be read with, interest and profit, by the old and young, the educaled and unlearned. We hail it in this era of superficial and ephemeral litera- ture, iLM the precursor of a better future. It discusses a momentous subject; bringing to bear, in its examination, the deep and labored thought of a comprehensive mind. We hope its sentiments may be diffused as freely and as widely throughout our land 88 the air we breathe." — Kalamazoo Oazctte, " Important and comprehensive as is the title of this work, we assure our readers 11 [fi no misnomer. A wide gap in the bulwark of lliis age and this country is greatly lossenetl by this excellent book. In the first place, the views of the author on educa- tion, irrespective of time and place, are of the highest order, contrasting strongly with too groveling, time-seeking views so plausible and so popular at the present day. A leading purpose of the author is, as he says in the preface, ' to turn the thoughts ol those engaged in the direction of youth to the fact, thai it is the entire soul, in all ita fgiculties, which needs education.' '•The views of the author are eminently philosophical, and he does not pretend to enter into the details of teaching: but his is a practical philosophy. Iiaviug to do with Ufine, abiding truths, and does not sneer at utility, though it demands a utility thai takes hold of the spiritual part of man, and reaches into bis immortality." — Uolden'i A. S, BARNES k COMPANY'S PUBLICATICN8. J) e Tocquevill c' s American Ins t itutione. AMERICAN INSTITUTIONS AND THEIR INFLUENCE. BY ALEXIS DE TOCQUEVILLE. WITH NOTES, BY HON. JOHN C. SPENCER. 1 vol. 8vo. This book is the first part of De Tocqueville's larger work, on the Repiblio ot America, and is one of llie most valuable treatises on American poiiiics that has eTM t>i»n issued, and should be in every library in the land. The views of a Hbarai- miaded and enlightened European statesman upon the working of our coiuitry's socia) said political establishments, are worthy of attentive perusal at all times; those of a raa» lite Ue Tucqueville have a higher iuti'insic value, from the fact of his residence among the people he describes, and his after position as a part of the republican government of France. Tlie work is enriched likewise with a preface, and carefully prepared notes, by a well-known American statesman and late Secretary of the Navy. The book is on« of great weight and inleresi, and is admirably adapted for the district and school library as well as that of the private student. It traces the origin of the -Anglo-American* treats of their social condition, its essential democracy and [lolitical consequences, tb# •overeignty of the people, etc. It also embraces the author's views on the .Ameriaii system of townships, counties, &c. ; federal and state powers; the judiciary ; llie cod Blitution ; parties; the press ; American sociely ; jjower of the mijority, its tyrann\ and the causes which mitigate it ; trial by jury; religion; the three races; the arista cratic party ; causes of American commercial prosperity, etc., etc. The work is ai epitome uf the entire political and social condition of the United Slates. "M. De Tocqueville was the first foreign author who comprehended the genius c» our institutions, and who made intelligible to Europeans the complicated ra.ichliierj- wheel within wheel, of the stale and federal governments. His ' Democracv ic America' is ackiiowled'-'ed to be the most profound and philosophical work iipor rnodern reiiublieanlsm that has yet appeared. It is characterized by a rare uniiiii o discenimenl, rellecliiin, and candor; and though occasionally tinged with the aiilhor'f pecuiiarilies of education and faith, it may he accepted as In the main a just and iu> partial criticism upon the social and political feiitures ol the United Slates. The pui> lishers have now sought to adapt it as a te.\t-book for higher seminaries of learninji Fi'r this purpose they have published the lirsl volume as an independent work, ihut avoiding the auihur's speinilalions ujiDn our social habits and reli'-rioiis cnmlitinii. Thi» volume, however, is unmiililaled — I he author ia left throu^'hout to speak for himself; bill where at any pnjnl he had misappiehended our sjstem. the detect is sujiplied by iiule! or para:,'raphs in brackets from the pen of one inosi thoroughly versed in the hislnri the legislalioii, the adininislration, and the jurisprudence of our counlry. This woi^k will supply a felt deliciency in the educational apparatus of our higher schools. Kveri man wlio pretends lo a good, and much more to a liberal ediic;ition, should ma.-;i i th'f 5)rinciples ami philosophy of the inslitutionsorbis coiintiy. In the hands of ajuu.ciou* teacher, Hits volume will be an adniir.ible te\t-bi)ok." — The huUjicndcnl. '■' Having had the honor of a personal acqiiaiiitance with .M. De Tocqueville while h# was in this country ; having discussed with him many of the topics treated of in Ibb bo pelled him In his Uisk, and having formed a hi;;h admiration of his chaia-uer and rf this production, the editor felt under some obligation lo aid in procuring' for one whoix he ventures to call his friend, a hearini; from Ihose who were Ihe olijecl-s of his ob' »ervalions.' The notes of Mr. Spencer will be found to elucidate occasional niiacc* ceplions of the transl.iior. It is a most judicious text-book, and ought lo be reivC wrefully by all who wish to know this country, and to trace its power, position, an^ nllimate deslit/y from the true source of philosophic governmi'iii, Ivejuiblicanism — th« people. De Tocrecialiun a general actjiiainlance with the leading iiictbods ami routine of niatliemalical invesiiijation. 'I'o tho e who have a natural fondness lor this (iiirsuit and enjoy the leisure for a retrospect of their fivorite studies, the pre.sent \olunie wil possess a charm, not surpassed by tiie (asciiiations of a romance, it is an efiliorale and Iticid exposition of the principles which lie at the foundation of pure malliematicu with a hit;hly inuenions application of their results to the development of the essen- tial idea id' .Arilhnietic. (Jeinoelry, Al'.'i'bra, .-Xnalytic (Jeometry, and the DuiiTi-ntial and Inteural Calculus. The work 'is preceded by a ;,'eneral view of the subject of Lo;;ic, mainly drawn from the writinj:s of Arclibisbop Whately and Mr. Mill, and closes «ith an essiiy on the utility of mathematics. Some occasional e.xa^'geralions, in presenting the clai'ms of the science to which his life has been devoted, UiUst here be pardoned to the professional enthusiasm of the author. In general, the work is wriitea with s'.ngnlar circuniS(jection ; the views of the best thinkers on the subject have been thorouuhly digcaled, and are presented in an orij.'inal form; every thin<; bears the im- press of llie intellect of the writer ; his style is for the most part chaste, simple, trans- parent, and in admirable harmony with the dif;nity of the subject, and his condensed generalizations are often profound ai.d always suj^gestive."— i/ar//er's A'cic jUu«£Aij Maj;aiinc. "This work is not merely a mathematical treatise to be used as a te.\t book, but a complete and philosophical unfolding of the principles and truths of luathematical science. " ll is not only designed for professional teachers, professional men, and students ol mathematics and philosophy, but for the general reader who desires mental improve- meni. and would learn to search out the miport of language, and ac(iuire a habit of notiiit; of conni'xion between ideas and their signs; also, of the relation of ideas to each other. — The Student. " Students of the Science will find this volume full of useful and deeply interesting matter." — .Itbany Evening Juuruixl. " Seldom have we opened a book so attractive .is this in its typography and style ol eiccution ; and there is besides, on the margui opposite each section, an index of the subject (d" whicli it treats— a great convenience to the student. I!ut the mutter is no less to be commended than the manner. And we are very much mi-taken if ibis wurk sliall not prove mnre popular and more useful than any which the distinguished author has given to tlie public."' — Lutheran Observer. " We have been much interested both in the plan and in the execution of the work. Iinil would recommend the study of it to ilie tlieologian as a discipline in close ami Kcurate tliinking. aMi in logical nielhod ar.d reasoning. It will be useful, al-o, to thf general scholar and to tlie practical muchanic. We w(Uild s|iecially rcconiiiiend it M those who would have nothing tauglit in our Free .Acailemy and other liiglier inslitu Uons but what is directly 'practical'; nowhere have wa seen a finer iiluslraliun o< the eoiuieetion between the ab.straetly scieiitific and tlie praclic.-il. "The work is divided into three books; llie first of wliich treats of Logic, mainly ipon tlie liasis of Whately; the second, of Matlieuiatical Science; aud Iho third, r f the Dtility of },liilhemixtic3."—Incl^2^endent. "Tlie authoi's style is perspicuous and concise, and he exliibits a in.istery of the ibstni.se topics which he attempts to .simplify. For the inatbeiiiatical student, ^^■!l^ desires an analytical kiunvled^'e of the science, and who would begin at the beginning. we .should suppose the work would have a special utility. I'rof. Davies" matbemati- cal works, we liolieve, have become quite popular with educators, and this di.selo.soj qidte .IS much reasearch aud practical scliolarship a.s any we havp seen from Ids p^u ' •A>i(i- Yi }'k EvangelUst Qf\l03 /85f r T