R PA P P A 777 MATHEMATICS ?,!5 PAPER LOCATION OF A RAILROAD J, C. L. FISH MATHEMATICS OF THE PAPER LOCATION OF A RAILROAD J. C. L. FISH Assoc. M. Am. 8oc. C. E. Associate Professor of Civil Engineering Leland Stanford, Jr., University, Palo Alto, Cal. NEW YOKK M. C. OLAEK 13-21 PARK Row 1905 Copyright, 1905, by M. C. Clark The object of this article is to present the mathematical steps involved in preparing, from the paper location of a railroad, a set of mathe- matically consistent alinement notes by which to run the corresponding field location; and to sug- gest an orderly arrangement for the necessary computations. Mr. W. B. Storey, Jr., in discussing a paper by Michael L. Lynch on Railroad Location, says:* On the Southern Pacific System the location ia trans- ferred from the paper to the ground, not by scaling, but by calculation. Each tangent is fixed, and the connect- ing curves are all calculated in the office by carrying the line from one fixed tangent around through the prelim- inary to the next tangent. These calculated notes are then given to a machine known as the locating party and put on, the ground by it. The writer does not remember having seen else- where any reference to the calculation of field notes; but in various articles on railroad location he has noted direct or implied reference to scal- ing. To make clear what is meant by scaling and by calculating, and to show the advantage of calcu- lating over scaling, let us find, by the two methods, the station and "plus" via the prelimi- nary and via the location for the check point A, Fig. 1, the first crossing of the location and pre- liminary w;hich have a common starting point, Pi. BY SCALING. The angle at Pi, between pre- liminary and location, is scaled in the course of preparing the notes for field location. Simply for the purpose of getting a check on the location at Trans. Am. Soc. C. E., Vol. XXXI., p. 92. (Reprinted from Engineering News, March 16, 1905.) 381115 5000 FT. 4000 (1500,4000) R 1000 Pape (3000, 4200) fg i = 100 (109 370/6 = 100 (109.62) / 6 = 1,827. 8 Length of curve No. 2 is L s 100 Aa/D a 100 (124 34') / 8 = 1OO (124.57) / 8 1,557. We now step off the curve lengths on the map to obtain a rough check on the computed values. 7. COMPUTE LENGTHS OF CENTER-LINE TANGENTS. The length of the first tangent, as the map shows, is PiPCi = PiVi Ti = 3,627 1,355 = 2,272. The second tangent is PTi PC 2 = ViVs (Ti + T 2 ) = 2,921 (1,355 + 1,364) = 202; And the third tangent is PTa PCs = Va PCs T 2 = 2,428 1,364 = 1,064. The rough check by scaling is now employed. 8. COMPUTE STATION AND PLUS FOR CURVE AND TANGENT POINTS. The station and plus for Pi is + 00. The station and plus for PCi Is PiPCi = (22 + 72). The station and plus for PTi is (22 + 72) + La. = (22 + 72) + 1,827 = (40 + 99). The station and plus for PCs is (40 + 99) + PTi PCs = (40 + 99) + 202 = (43 + 01). The station and plus for PTa is (43 + 01) + L = (43 + 01) + 1,557 = (58 + 58). The station and plus for PCs is (58 + 58) + PT PCs = (58 + 58) + 1,064 = (69 + 22). Now we prick off the stations on the map, thus checking roughly these values. 9. COMPUTE ELEMENTS FOR CHECK POINTS. On our map the location crosses the preliminary at the point A, which we use as a check point. There is no corresponding point at the other end of the line, and, in order to obtain a check, we draw the line PCsP? and compute its bearing and length, to be run in the field as an auxiliary line to check on point PT. CHECK POINT A. We first write the equa- tions for lines, P 2 Ps and PiVi. The general equa- tion for a straight line is y = ax + b, where a = (y n y^ / (x n x k ) and b = y k ax k . (The subscripts k and n refer to the initial and final points respectively of any line.) 9 For line P g P 3 a = (y 3 y 2 ) / (x 3 x 2 ) (1,700 600) (2,600 1,600) = 1,100/1,000 = 1.1; and b = y, ax 2 = 600 1.1 (1,600) = 1,160. Equation of line P a P 8 is therefore, y=l.l x + (1,160) or y - 1.1 x 1,160. For line PiVi i, 6W0 _ 04.954 3,250-0 and making the equation of PiVj y = 0.4954 x. We now compute the co-ordinates of the point A of intersection of PaP2 and PiVi. If the equation of the first line be written y = ax + b and the equation of the second be written y = a' x + b' then the co-ordinates of this common point are : and a check is had in the equation y ~a!x> +V Substituting numerical values of a, b, a', b', for rou point A, we get : (- J.160J - 951 We scale the map to get a rough check on the computations. It remains to find for A the station and plus via each line. The distance log 319 = 2.50379 log sin 42 16' = 9.82775 log 474.8 = 2.67604 The logarithmic computation makes P 2 A 474.3. 10 The station and plus of A on the preliminary Is PI P 2 -f ?2 A. = 1,709 + 474.3 - 21 + 83.3. The distance as computed by logarithms here : log 1,919 = 3.28299 log sin 63 39' = 9.95236 log 2,141 = 3.330Q3 The station and plus for A on the location is, then, 21 + 41. Scale the map to roughly check these values. It is evident that station 21 + 41 on the location survey should coincide with station 21 + 83.3 on the preliminary. In cases in practice a check point may be con- veniently obtained by producing a location tan- gent to intersect the preliminary, and making the computation in the foregoing manner. CHECK LINE PCaF?. When a crossing of the location with the preliminary is not near at hand for a. desired check on the field work, a check line, or tie line, is drawn between a chosen point of the location and a chosen point of the pre- liminary; and the bearing and length of the check line are computed. As an example, draw the check line PCsP?, and find the bearing by the equation: Vr, -ypc 3 4,500-4,120 and find the length log 470 2.67210 log 470 2.67210 log 380 = 2.57978 log sin 51 03' = 9.89081 log tan 51o 03' = 0.09232 log 604.4 = 2.78129 We find the bearing and length of PCaP? to be N 51 03' E, 604.4 ft. The location having been carried in the field to the point PCs, the transit- man deflects to the left at this point the angle ^PCs - ^PCsPr = 78 36 ' ~ 51 3 ' ---- 27 33/ ' and the chainmen lay off 604.4 on this course, and 11 should by so doing- arrive precisely at PT on the preliminary. 10. COMPUTE CURVE DEFLECTIONS. PCi is 22 + 72 making- the first sub-chord on the 6-degree curve, 28 ft. The corresponding deflection is .28 x 3 = .28 x 180' == 50', i. e., the tangent deflection for station 23 is 50 minutes. The deflection for sub-chord at .PCa is .99 x 240' = 238' = 3 58'. The deflection for sub-chord at PTi is .99 x 180' = 178' = 2 58'. The deflection for sub-chord at PT 8 is .58 x 24tf = 139' = 2 19'. ALGORITHMS. To facilitate explanation the foregoing computations have been put down in a Red- Fig. 2. Design for Rulings on Computing Paper. rambling manner which makes the computed quantities hard to find when wanted. For a lon- ger location than this, economy of time and effort requires that the routine computations be syste- matically arranged, that like operations as well as like quantities may be brought together. By this means entering the data and making the computa- tions in a short time become largely mechanical processes, and at the end the computed quantities stand in tabular order and may be quickly found when wanted. For the computations of this ar- tide the following computation forms, or algo- rithms, are suggested. While these may not pre- sent the best arrangement, they will at least show the advantage of order over disorder. The reader may be interested in the fact that the writer's stu- dents buy for their computing, letter-size sheets of paper ruled on one side with the special design shown in Fig. 2. By the use of this paper any algorithm may be followed without drawing lines, and columns of digits are kept vertical automat- ically. Algorithm 1 is for computing the bearing and length of lines which are terminated by points of known co-ordinates. Column A contains the num- bers of the horizontal lines of the algorithm. Col- umn B contains the symbols. Xk, yk designate the co-ordinates of the initial point of any line; x n , y n designate the co-ordinates of the final point of the line; )3kn is the bearing, and dk n is the length of the line. The lower half of this algorithm has to do with the check equation: hypot. = (base 2 + altitude 2 ) 1 / 2 . Notice that the values on line 21 check those on line 12. Of course this check will not detect errors made in entering values of co-ordinates on lines 1, 2, 3, 4. When a table of squares is at hand it may well be used in place of logarithms for the computation of checks. Columns C, D, E, F give for the line Pi Vi, Vi Va, Va PCs, and PCsP? respectively, the numerical quantities corresponding to the symbols of Column B. It is suggested that the order of steps in computing be: (1) Enter the co-ordinates for all the lines concerned; (2) Set down on lines 5 and 6 the differences; (3) Enter all the logs on line 7; (4) Enter all the logs on line 8, and so on; every operation in Column C being immediately repeated for the succeeding columns. Algorithm 2: Column A contains the numbers which have been used to designate the curves. In B will be found the degree of each curve. Each degree of curve is repeated in parenthesis, with the minutes expressed in decimal of a degree. In C are entered the central angles, each of which has been computed from two values of taken from Algorithm 1. For example: C2 (i. e., the 13 ICC*'* CO COO _, ^ibw^wS ^ ^ CO T-J iM iH CO kO l> ko kOko koc* 2s: OoOo rHOkOr-iCO.SlOCS CO CO> H-^OS-^iMCD'H k(5 iHkOiM CO COC^