Division of Agricultural Sciences UNIVERSITY OF CALIFORNIA i ■ > ■■*■■•■ * * - • -. - "■'■ CALIFORNIA AGRICULTURAL EXPERIMENT STATION BULLETIN 773 GROWERS and SHIPPERS interested in choosing new cooling facilities and modifying existing ones will find information in the first section of this bulletin on "Cooling i Methods/ 7 ,, ENGINEERS and others desiring to design coolers will find the second section on "Cooler Designs" especially useful. RESEARCH WORKERS \ will turn to the technical third section, "Analysis and Test Data," which contains the material on which the first two sections are based. CONTENTS Section I: Cooling Methods 3 Introduction 3 Ice or mechanical refrigeration?.... 3 Humidity control 4 Types of Coolers 5 Room cooling 5 Fast methods of air cooling 6 Hydrocooling 9 Vacuum cooling 10 Cooling Methods in Rail Cars 13 Car cooling by ordinary spacing .... 13 Car cooling by chimney suction 14 Forced-air cooling in rail cars 15 Costs of Cooling Methods 18 Section II: Cooler Design 21 Comparing and estimating cooling rates 21 Cooling rooms 21 Forced-air coolers 22 Mechanical refrigeration capacity . . 26 Ice bunker design 29 Spray humidification 32 Insulation and vapor barrier 36 Air passages 37 Fans 38 Section III: Analyses and Test Data 39 Cooling Calculations 39 Refrigerator Load 42 Ice Bunker Performance 43 Humidity Calculations 46 Optimum Insulation 48 Forced-Air Cooling Calculations .... 50 Half-Cooling Times 55 Units and Conversion Factors 63 References 64 Acknowledgments 66 Section I COOLING METHODS INTRODUCTION Cooling may greatly reduce deteriora- tion of fruits and vegetables between harvest and consumption. Although cool- ing effects on the product are important and should be carefully considered in planning an operation, this bulletin dis- cusses only the engineering aspects of cooling. Room cooling, a method used widely, relies on the heat being carried from the product to the ice or refrigerated surfaces chiefly by air which is circulated around the containers. Fast methods of air cooling, such as ceiling-jet cooling and forced-air cooling, use air that is made to flow through the containers. Hydrocooling depends on water being flowed about or through containers or through a bulk layer of the product, carrying heat from the product to ice or refrigerated surfaces. Vacuum cooling uses equipment in which heat is absorbed by evaporation of water from the product. "Body" icing relies on finely chopped ice, packed inside the container and mixed with the product, to absorb heat. Cooling may be carried on in spaces designed specifically for that purpose, in rooms used also for storage, or in loaded cars. The heat removed from the product is commonly absorbed either by melting ice or by mechanical refrigeration. Hu- midity is sometimes controlled in air coolers to prevent dehydration of the product. All five methods listed above, using ice or mechanical refrigeration, with or with- out humidity control, have their places and are in profitable commercial use in California. ICE OR MECHANICAL REFRIGERATION? The initial cost of an ice bunker is a small fraction of the cost of a mechanical system to do the same job. On the other hand, it is much cheaper to operate the mechanical system than to buy ice. Generally, the total annual cost for an operating season of a month or two is less for an ice-cooled unit, while for a season of four to six months or more, a mechanical system is cheaper. A well-planned ice bunker requires little maintenance and is very simple to operate. A mechanical system must be operated and cared for intelligently and will eventually require fairly expensive maintenance to insure against failure at a critical time. Supplies of ice and elec- tricity are local problems. An ice bunker maintains higher humidity in a cooler or storage than most mechanical systems do. However, humidity is undesirably low The Author: Rene Guillou is Associate Specialist in the Experiment Station, Department of Agricultural Engineering, Davis. JULY, 1960 [3] with any system when the product is warm and the containers are dry unless water sprays are provided; water sprays can produce satisfactory humidity in any system. Size and weight of a refrigeration source are important in the case of mobile equipment. The size and weight of a mechanical unit are usually only a fraction of the size and weight of a bunker and water-ice to do the same work. Dry ice compares favorably with mechanical refrigeration in weight and volume needed to absorb heat at a given rate, though the cost per heat unit ab- sorbed is about double the cost for water ice. HUMIDITY CONTROL Some products, such as grapes, de- teriorate seriously from loss of moisture during cooling and storage. Other things being equal, moisture loss is proportional to the difference in water-vapor pressure between the product and the surrounding air and the time over which this differ- ence exists. The time element may be reduced by cooling the product as rapidly as possible. Evaporation after a product is cooled may be reduced by use of the lowest air velocity that will prevent a rise in temperature, thus allowing evapora- tion from the product to raise the hu- midity of the air in its immediate vicinity. Probably most may be accomplished, however, by raising the general level of humidity of the air in a cooler or storage. The humidity in a cooler or storage is determined in part by the size and tem- perature of the cooling surfaces. Large cooling surfaces within a few degrees of air temperature ordinarily condense out less moisture than smaller surfaces that must be colder in order to give the same refrigerating effect. A little more mois- ture condenses in brine-spray cooling units than on ice or dry coils at the same cooling-surface temperature. Boxes and packing materials absorb moisture rapidly when they are first moved from dry outside air to a humid cooler. As they become damper, they absorb mois- ture more slowly, but it may take them weeks to come to equilibrium. Usually, the moisture to offset these losses is evaporated from the product, the air in the cooler remaining at a humidity at which the losses and gains balance. Use of larger cooling surfaces on which there is less condensation re- sults in higher air humidity and corre- spondingly less evaporation from the product. In a well-insulated storage con- taining cold fruit in damp containers and cooled by a large ice bunker, con- densation on the cooling surfaces and evaporation from the product may be insignificant. To attain this condition with mechanical refrigeration requires very large and expensive cooling units, and it is practically impossible to attain it with warm fruit even with ice as a coolant. Air humidity may be raised quite easily by means of fog sprays in a cooler or storage. In 1958 there were several such installations in California. In one case rooms cooled by brine spray and humidified with fog sprays were held at 91 per cent relative humidity and after several months the grapes stored in them were considered equal in condition to those in adjacent rooms cooled by ice. Substitution of fog spray for evapora- tion from the product makes it possible to have whatever humidity is desired while using relatively small cooling sur- faces. A spray system capable of supply- ing 10 or 15 gallons of water per ton-day of refrigeration or per ton of ice melted, plus whatever moisture is absorbed by boxes and packing material, can maintain 90 per cent relative humidity in the return air under almost any practical conditions. Condensation in a brine-spray cooler requires addition of salt to offset that lost in overflow from the brine tank. Moisture sprayed into a room cooled by dry coils, less what is absorbed by the boxes, must be removed from the coils [4] by defrosting. At very high humidities there may be trouble from collection of water on walls or floor or from wetting containers or product. These problems have been anticipated in existing installa- tions but so far they have not been troublesome. TYPES OF COOLERS ROOM COOLING Exposure of packed containers to cold air in a refrigerated space is one of the commonest methods of cooling. Ad- vantages of this method are: 1. The product may be cooled and subsequently stored in the same place without rehandling and with no special facilities for the cooling operation. 2. Design of the plant and its operation are simple. 3. Because of the relatively slow rate at which the produce is cooled, peak loads on the refrigeration system are less than with fast-cooling methods. Limitations and disadvantages are: 1. When produce is cooled in prepara- tion for immediate shipment, the time required for room cooling sometimes delays loading or results in produce be- ing loaded before it is adequately cooled. 2. Deterioration of the product in the s E <•- o o .08 .06 I 2 Half-cool (hours) 8 10 .2 .8 I 2 Half-cool (hours) 8 10 Fig. 15. Forced-air cooling grapes in lidded lugs, half-cooling of downstream boxes, based on constant temperature air supply. tests are available on the air flows or pressures used or on the effects on cool- ing rate. It can be estimated, however, that to double the cooling rate in a con- ventional room by this method would probably require an air velocity of 1,000 fpm in a channel 8 inches wide and 30 feet long beside each tier of boxes. A forced-air system using the same air flow and floor space would apparently cool the product in a fraction of the time. FORCED-AIR COOLERS The first consideration in planning a forced-air cooler is the relation of fan capacity to cooling time. Figures 15 to [22] z 6 r 4- o I ' £ 8 1-6 .1 .08 .06, .6 8 I 2 Half-cool (hours) 8 10 4 .6 .8 I 2 4 6 8 10 Ha If- cool (hours) Fig. 16. Forced-air cooling strawberries in open cartons, half-cooling of downstream cartons, based on constant temperature air supply. 24 show the air flows needed to cool various products half-way to air tem- perature in given times. Cooling three- fourths or seven-eights or fifteen-six- teenths of the way to air temperature takes twice, three times or four times as long. These curves are based on a constant temperature air blast. Estimation of slower cooling due to variation in air- blast temperature is described in the fol- lowing section on ice-bunker size. As a rough figure, half-cooling from product to ice temperature may be 50 per cent longer than the corresponding time based on air temperature. The air flow per [23] u 6 4 § $ .8 I 6 a » .1 .08 .06 2 6 4- 8 I 1 6 i 4 < .2 .08 .06, .8 I 2 Half-cool (hours) 8 10 4 .8 I 2 Half-cool (hours) 8 10 Fig. 17. Forced-air cooling peaches in paper cups in lidded lugs, half-cooling of downstream boxes, based on constant temperature air supply. pound of product to produce a given half-cooling time in the downstream pro- duce is not significantly affected by the thickness of the stack or layer of produce through which air passes. The static head to produce a given half-cooling time is, however, drastically affected by the thickness of the stack or [ layer, as shown by the upper curves in figures 15 to 24. The static head taken from one of these charts must be added to the static head needed to move the air through the ice bunker or cooling unit and through the openings, passages and turns in the system to get the head that must be developed by the fans. Air-flow 24] 6 8 1 2 Holf-cool (hours) Fig. 18. Forced-air cooling plums in open Sanger lugs, half-cooling of downstream box, based on constant temperature air supply. and static head in passages and ice bunk- ers and choice of fans are discussed in following sections. As explained there, savings in floor space and labor by use of stacks of four tiers or more should be weighed carefully against the added cost of fans and refrigeration entailed in op- erating at a high static pressure. The general arrangement of a pressure cooler and the method of handling and stacking the product should be coordi- nated with other packing and shipping activities. There are four general meth- ods of getting products into the cooler and out again : on pallets moved by fork trucks, in stacks moved by hand trucks, by moving containers on conveyors, or by stacking containers in the cooler by hand and removing them with hand trucks. Figure 25 illustrates movement of pal- lets by fork trucks. The flexible, hinged curtain has been very satisfactory. Pallets may be stacked two high with a saving in it 4-»-Tier* 06 2 Holf-cool ( lours) 6 4 2 1 « 8 . " 6 E " 3. 4 - * o 5 2 08 : i 1 Ub 2 4 .6 8 1 2 4 6 8 10 Holf-cool (hours) Fig. 19. Forced-air cooling grapes in vented cartons, half-cooling downstream carton, based on constant temperature air supply. floor space but with more work for the fork truck. Pallets may also be stacked two-wide with the air passing through four or six tiers of boxes, though this re- quires either high static pressure or a slower cooling job as is shown in figures 15 to 24. Cooling of a multiple-tier stack is fastest and most uniform if the top of the stack is exposed to the air supply and if the tiers are spaced slightly apart, as explained in figure 26. Movement of boxes into a cooler by roller conveyor for hand stacking and later removal with hand trucks is shown in figure 27. Boxes may be stacked di- rectly in the cooler with no more labor than is needed to stack them on pallets, and movement by fork truck into the cooler is eliminated. This is a good ar- rangement if the cooler is close to the packing line and boxes are moved di- rectly to nearby cars or trucks (21). Figure 28 shows boxes being forced- aircooled in U-shaped stacks against the 25 s X £ 2 .08- oeL- '2 3 4~Tiers WW 4 6 .8 I 2 4 6 8 10 Half-cool (hours) 6- 4 - 06 2- 6 8 1 2 Holf-cool (hours) Fig. 20. Forced-air cooling plums in vented cartons, half-cooling downstream carton, based on constant temperature air supply. air returns in a combination room and pressure cooler. Cool grapes picked in the morning are stacked with ordinary spacing in the room area. The warm afternoon picking arrives in the early evening and is stacked for pressure cool- ing. With hand tongue-trucks and some practice, the handlers can place stacks tightly end-to-end for pressure cooling. It would be troublesome to do this with clamp trucks. By the next morning the fruit in the room area has been cooled for three six- hour half-cooling times and the warmer pressure-cooled fruit has been cooled for four or five two-hour half-cooling times. During the morning all the fruit is loaded out or moved for storage to another room where the air velocity is much lower. Running containers through a cooler on a conveyor, which is loaded and un- loaded outside of the cooler, makes it un- necessary to provide space inside for men to work. Such an operation is shown in figure 29. This type of cooler is very compact in relation to cooling capacity. There is a minimum of outside surface and air moves through short passages and a single tier of containers, giving a good cooling rate with low static head and low-power fans. These features com- bine to allow economical construction and excellent ice economy, especially in small units and during intermittent op- eration. The cooler shown in the photo- graph was designed and built by the owner for about $1,000 and cools one ton of cup-packed peaches per hour. In a similar unit, 75 to 80 per cent of the ice was melted by heat removed from the fruit while the cooler was operating, and 200 pounds of ice was melted per day in hot weather while the cooler was not in use. Plans for the unit in the photograph may be purchased at cost from Agri- cultural Publications, 207 University Hall, 2200 University Ave., Berkeley 4 (Plan No. 243, 'Fruit Cooler"). MECHANICAL REFRIGERATION CAPACITY General design of refrigeration sys- tems is beyond the scope of this publi- cation, but tables for determining refrig- eration capacity in relation to produce temperatures and cooling rate may be useful. Calculation of these tables is ex- plained on pages 39 to 41. Refrigeration capacity needed for a TABLE 2 Refrigeration for Continuous Cooling Fraction of refrigeration used to absorb heat from product Degrees F cooled .50 .65 .80 Tons refrigeration per ton of product cooled per hour 70 60 50 40 30 20 22 19 16 12 9 6 17 14 12 10 7 5 14 12 10 8 6 4 [26] .8 I 2 Half-cool (hours) Fig. 21. Forced-air cooling pears in vented cartons, half-cooling of downstream cartons, based on constant temperature air supply. continuous operation, such as hydro- cooling, is shown in table 2. The fraction of refrigeration used to absorb heat from the product is about .50 with light insulation or considerable air leakage, or .80 in a well-enclosed and insulated unit. Heat evolved by respira- tion of the product, in the short time ordinarily occupied by a continuous cool- ing operation, is usually not significant. In a batch operation, where the cool- ing rate is commonly proportional to the temperature difference between product and coolant, the refrigeration load is quite high when starting to cool a warm batch, as shown in table 3. [27 J Tiers— - 4 \ V X \ 6 4 - Holf-cool (hours) 2 a 8 € -6 E S 4 s - \ Lu w .2 < .1 08 .06 r * e- .8 1 2 4 6 8-10 Half- cool (hours) Fig. 22. Forced-air cooling artichokes in vented cartons, half-cooling downstream car- tons, based on constant temperature air supply. 6 - 4 - s 2 I I .8 J 6 E 4 .08 10 06 Large vents I sq in/4 lb melons Small vents I sq in/10 lb melons 4 6 8 1 2 4 6 Half-cool (hours) Half-cool (hours) Fig. 23. Forced-air cooling melons in cartons, half-cooling of downstream cartons, based on constant temperature air supply. Table 3 shows only the refrigeration needed to absorb heat from cooling the product. Additional capacity must be al- lowed for losses, and in some cases, for heat evolved by respiration. Conduction, infiltration and heat from fans may be estimated separately; or total losses with slow cooling, light insulation, or consid- erable air leakage from the outside may be estimated as roughly equal to heat TABLE 3 Refrigeration to Absorb Heat From the Cooling Product in a Batch Operation Half-cooling, product to coolant Remaining temp, difference between product and coolant 24 hr 12 hr 6hr 3hr 2hr lhr Tons refrigeration per ton of product in batch degrees F 80 60 40 .36 .27 .18 .13 .09 .07 .04 .02 .71 .54 .36 .27 .18 .13 .09 .04 1.4 1.1 .71 .54 .36 .27 .18 .09 2.9 2.1 1.4 1.1 .71 .54 .36 .18 4.3 3.2 2.1 1.6 1.1 .80 .54 .27 8.6 6.4 4.3 3.2 2.1 1.6 1.1 .54 30 20 15 10 5 [28] TABLE 4 Refrigeration Capacity to Absorb Heat of Respiration Product Apples Asparagus . . . Beans, snap. Broccoli .... Cantaloupes . Carrots Celery Cherries .... Corn, sweet . Grapes Oranges Peaches Pears Strawberries Tomatoes. . . Temperature (F) so' 70° 60° 50° 4(f Tons refrigeration per ton product 02 50 24 35 08 08 .24 .02 .04 .04 .04 .13 .04 .02 .39 .20 .26 .05 .05 .05 .05 .20 .02 .03 .03 .03 .09 .03 .01 .24 .13 .17 .03 .03 .03 .03 .13 .01 .02 .02 .02 .06 .02 .15 .08 .10 .02 ,02 .02 .02 .01 .01 .01 .04 .01 02 from the product when half-cooled; or total losses with fast cooling and a tight, well-insulated unit may be estimated as equal to heat from the product when three-fourths cooled. Table 4 shows the approximate tons of refrigeration capacity needed to ab- sorb heat evolved by respiration of vari- ous products at different temperatures. TABLE 5 Tons Ice Melted per Ton of Product Cooled Per cent of ice melted by heat from product Reduction in product temp. 50 65 80 Tons ice per ton of product Degrees F 60 .77 .60 .48 50 .64 .50 .40 40 .52 .40 .32 30 .39 .30 .24 20 .26 .20 .16 .8 I 2 Half-cool (hours) Fig. 24. Forced-air cooling of oranges in bulk, half-cooling of average fruit based on constant temperature air supply. (Data by R. L. Perry, University of California). This must be added to the amount from table 3, plus an allowance for losses, to estimate the capacity that should be in- stalled. Instead of installing the large refrig- erating capacity needed to maintain fast cooling when starting a warm batch, it may be more economical to install less refrigeration and accept slower initial cooling. The initial half-cooling period is lengthened by 45 per cent by provision of half the refrigeration that would be needed for a maximum initial cooling rate. This refrigeration capacity is ade- quate after the product is half cooled and cooling then proceeds at the rate de- termined by exposure of the product. Figure 30 illustrates this principle. ICE BUNKER DESIGN The weight of ice that will be melted in a cooling operation can be estimated from tables 5 and 6. A ton of ice in [29] TABLE 6 Ice Melted by Heat of Respiration in Cooling Various Products from 80°F to 35°F, in Air at 32°F, at Four Different Cooling Rates Product Asparagus . . Apples Beans, snap. Broccoli. . . . Cantaloupes . Carrots Celery Cherries. . . . Corn, sweet. Grapes Oranges Peaches .... Pears Strawberries Tomatoes. . . Half-cooling time 24 hr 12 hr 4 hr lhr Tons ice per ton of product .60 .30 .10 .02 .01 .32 .16 .05 .42 .21 .07 .08 .04 .01 .08 .04 .01 .08 .04 .01 .08 .04 .01 .32 .16 .05 .02 .01 .04 .02 .01 .40 .02 .01 .04 .02 .01 .16 .08 .03 .04 .02 .01 .02 .01 .02 .01 01 jumbled blocks occupies about 50 cubic feet; 60 cubic feet per ton will allow for upper corners of the bunker that are not filled. With slow cooling or light insulation, about 50 per cent of the ice is melted by heat from product; with fast cooling and heavy insulation, about 80 per cent of the ice is melted by heat from product. Some ice is melted also by heat evolved by respiration of the product (Wright, et al., 1954) . This is of small consequence with fruits, but with some vegetables and particularly if cooling is slow, heat of respiration is important. Table 6 shows the ice melted by heat of respiration while cooling various products from 80°F to 35 °F at four different rates in air at 32°F. The heat evolved by respiration while cooling to any particular tempera- ture is directly proportional to the time elapsed in reaching that temperature. The TABLE 7 Relation of Half-Cooling Times in Typi- cal Forced- Air Coolers and Room Coolers to Ice Depth in Bunker and Static Head in Bunker. Ice in 100-Pound Blocks, Air Flow 100 Cubic Feet per Minute per Square Foot Grate Area Static head (inches water) Relative half- cooling times Ice depth (feet) Forced- air cooler Room cooler 20 .75 .60 .45 .30 .20 .15 .12 1.0 1.0 1.1 1.3 1.5 1.8 2.2 5.0 16 12 8 5.0 5.1 5.3 5 5.5 4 3 5.8 6.0 reason for this is explained in the dis- cussion of refrigeration load, pages 42 and 43. Figures 31 and 32 are based on tests in a small bunker with 50-pound ice blocks and calculations for the larger sizes. For a given air flow, and cooling effect, 50-pound blocks as compared with 300-pound blocks require half the depth of ice but about the same static head, leaving a question as to how much break- ing of blocks is worth while. Doubling the air velocity in a bunker requires a 40 per cent greater depth of ice and over four times the static head for a given cooling effect. The recommended 100 cfm per square foot of grate area seems rea- sonable but 200 cfm per square foot is quite extravagant in use of fan power. Table 7 shows calculated effects on product cooling-times of effectiveness of air cooling in the ice bunker. These re- sults are in accord with the obvious prin- ciple that most of the temperature differ- ence and resistance to heat transfer in a room cooler is between the product and the air, and therefore conditions in the ice bunker have comparatively little ef- fect. In a forced-air cooler, on the other [ 30 } Fig. 25. Forced-air cooling, boxes on pallets. Air supply is through opening in ceiling, return is from space behind boxes, which will be enclosed by placing another pallet and closing the door. hand, the resistance between the product and the air is much less, and conditions in the ice bunker are relatively impor- tant. The basis of these estimates is dis- cussed on pages 43 to 46. Location of an ice bunker as close as possible to the product being cooled and on the same level reduces the space occu- pied by air passages, and the fan power needed to move the air. There is least outside surface exposed to heat leakage and requiring insulation if the bunker is located along the side of a rectangular cooling area, making the entire cooled structure approximately square; and also, if the bunker is on the same level as the cooling operation. It is usually cheaper to construct a bunker above ground, and this allows water from the melting ice to be drained by gravity. Hatches in the top of an elevated bunker, where they are not trucked over, can be simply constructed and are easily made air tight. These advantages must be offset against the convenience of other floor plans at a particular site, the possibility of using the top of a depressed bunker as a loading dock, and the necessity of pro- viding an elevator to ice an above-ground bunker. It is important that sump pumps, float switches and strainers in a depressed bunker be accessible for maintenance while ice is in the bunker. Failure of the drainage system soon floods the bunker and shuts the cooler down until repairs can be made. The conventional ice grate is made with heavy wood sills, notched or blocked to support 4" x 4" timbers on about 10- inch centers. The 4 x 4's are turned with corners upward and are capped with steel angles. Blocks of falling ice are split by the steel angles and impact forces are absorbed by the wooden framework. There is little information on air resist- ance and effectiveness of air cooling in ice bunkers. Air resistance and cooling [31] ♦ t r / / ♦- — — •- — ^ ,» — - ._ i Good U-^~~f4 i / — — »- _»- -*- — *- — »_ i ■ Bad Fig. 26. When several tiers are stacked for pressure cooling the top of the stack should be exposed to the air supply, so that the boxes which receive the least air also receive the coldest air. It is helpful to space the tiers W or %" apart, to allow cold air that passes be- tween the boxes to mix with warmer air that passes through them. effectiveness usually fall rapidly with in- itial melting after a bunker has been re- iced and then decline erratically as chan- nels form and collapse. Disappearance of ice from portions of the grate is accom- panied by a second rapid fall in air re- sistance and cooling effectiveness. Size of ice blocks and arrangements in which they fall result in different performance after successive re-icings. A common rule is to allow 1 square foot of grate area for each 100 cfm of air that passes through the bunker and to maintain the ice at least 5 feet deep in 100-pound blocks or 3 feet deep in 300-pound blocks. The temperature of air passing through such a bunker is reduced roughly half-way to ice temperature with a static head across the bunker of about .2 inch of water. SPRAY HUMIDIFICATION Calculated humidities resulting from net addition of different amounts of moisture in a cold room or cooler are shown in table 8. These figures agree well with the few available tests of existing installations and are believed to be a Fig. 27. Forced-air cooling. Boxes are moved from lidder to cooler on roller conveyor and stacked by hand, cooled fruit is removed with hand trucks. Air supply is through ceiling, return is from space behind boxes. [32] Fig. 28. Forced-air cooling. Boxes are placed by hand trucks in U-shaped stacks and covered with canvas. Air supply is from above, return is from behind the stacks. good basis for designing fog systems. The figures for moisture added are per ton of refrigeration. Under many condi- tions a given cooling effect is accompa- nied by about the same condensation, re- gardless of cooling surface temperature. The amounts of moisture shown in table 3 will condense on dry coils, on ice or in a brine spray. In case of dry coils above freezing, or ice, this condensation is easily drained away. Overflow of a brine spray system consumes salt and re- quires attention to the brine concentra- tion. Addition of 16 gallons of water per day per ton of refrigeration at tap temperature and its removal at brine tern- Fig. 29. Forced-air cooling. Boxes loaded and unloaded outside on roller conveyor which runs through the cooler. Canvas or light ply- wood will cover space between stacks, air supply is from above and between stacks and walls, return is through the floor from space between stacks, which is closed at the ends by the doors. perature adds about 1 per cent to the re- frigeration load. [33] Refrigeration capacity for maximum initial cooling rate •Refrigeration capacity for one-half maximum initial cooling rate Half-cooling Times Fig. 30. Effect of refrigeration capacity on cooling rate. Depth of Ice (feet) 12 16 Depth of Ice (feet) Depth of Ice (feet) Fig. 31 . Effect of air velocity in ice bunker, ice in 100-pound blocks. -.50 3 " Weight of ice blocks (lb)" ~^50 - ^too Remaining temp. _ diff. (per cent) ~^_ , " ^^■-iOO y^ 1 l j^, 4 8 2 16 20 24 Depth of Ice (feet) Fig. 32. Effect of ice-block size in ice bunker, air flow 100 cfm per sq. ft. grate area. [34 TABLE 8 Relative Humidities Resulting from Net Addition of Moisture in a Cooler or Cold Room and Corresponding Condensation on Cooling Surfaces Return air temp. Cooling surface temp. Net moisture added (gal. per day per ton refrigeration or per ton of ice melted) Kind of cooling surface 4 8 12 16 Degrees F. Return air relative humidity Unsalted ice or dry coils. . . . 35 32 88 91 94 98 100 25 64 72 82 95 100 18 46 60 76 95 100 10 30 50 75 95 100 Salted ice or brine spray. . . . 35 32 82 85 88 92 100 25 59 68 78 92 100 18 42 56 74 92 100 10 29 49 74 92 100 Unsalted ice or dry coils. . . . 50 32 50 58 69 81 99 25 36 47 61 81 99 18 26 40 58 81 99 10 17 35 58 81 99 Salted ice or brine spray. . . . 50 32 47 54 65 79 98 25 34 45 59 79 98 18 26 40 57 79 98 10 17 34 57 79 98 Condensation of 16 gallons of water per day per ton of refrigeration as ice on dry coils releases several times as much heat as does cooling the water, adding about 6 per cent to the refrig- eration load. Part of this loss is recovered by hot-gas defrosting or by defrosting with warm water from the condenser. Mechanics of defrosting on such a scale is a consideration, however. Introduction of this amount of moisture as steam rather than as water spray adds over 40 per cent to the refrigeration load. In order to maintain the above net ad- ditions of moisture, it is necessary to supply also the water absorbed by dry containers. Grape boxes held in 90 per cent relative humidity storage at Davis gained about % per cent of their dry weight per day initially, about % per cent per day after 20 days, about % per cent per day after 40 days, etc. Two types of air-and-water atomizing nozzles are available for spray humidifi- cation. In one type water is piped to the nozzle under pressure. The other type uses a tank in which the float-controlled level is a few inches below the nozzle and the water is sucked up by the air as it issues from the nozzle. The former type is the simplest to install and maintain, but slight variations in air or water pres- sure may make the spray too coarse or stop it entirely, requiring close adjust- ment of pressure regulators in the air and water lines. Suction feed from a float- tank automatically proportions the water to the air supply and a satisfactory spray is obtained over a wide range of air pres- sures. Electric soil-heating cable may be used to keep pipes and tanks from freez- ing. Spray-humidification is analyzed in more detail on pages 46 to 48. [35] INSULATION AND VAPOR BARRIER (1,8) Inadequate insulation may double the refrigeration used in a cooler, adding as much as $2 per ton of product to cost of a cooling operation, and may in addition seriously slow the cooling by raising the temperature of the air or water used. Effectiveness of the materials commonly used to insulate walls and ceilings — fibre- glass, mineral wool, other fibrous ma- terials, plastic foams, or multiple layers of aluminum foil and paper — is not very different, inch for inch of thickness. These insulations should be chosen on a basis of cost and deterioration under expected conditions of service. Wooden studding which contacts both faces of a wall will conduct four or five times as much heat as the same area of insulation between the studs. Staggered studs, each contacting only one face of the wall, are worth while for a cooler operating a long season. Steel fastenings or pipes have 1,000 times, and aluminum ones 6,000 times, the heat conductivity of insulation. Metal passing through heat insulation has been likened to a leak in the bottom of a boat. It is a common prac- tice to use 4 inches of insulation in walls and 6 inches in ceilings or roofs. This may be calculated to be the thickness for least combined cost of insulation and re- frigeration under the conditions below. Cost of 4-inch insulation, installed 12j£ per sq. ft. Cost of 6-inch insulation, installed 18jzf per sq. ft. Insulation to pay for itself in five years, plus 10 per cent annually of its average value during that time for in- terest, insurance and taxes Cost of ice or equivalent mechanical refrigeration $6 per ton Time of annual operation 20 days Average temperature difference between inside and outside of insulation in walls 30°F Average temperature difference between inside and outside of insulation in roof 60°F Heat conduction through insulation 03 Btu/ft 2 hrF/f t Differences in any of the above figures that save 20 per cent in annual insulation cost, or that add 20 per cent to the an- nual refrigeration cost, justify adding 10 per cent to the insulation thickness. It is evident that 4-inch and 6-inch thicknesses are a minimum and that 6-inch and 8- inch insulation will pay for itself in many cases. Ordinary concrete walls need as much insulation as wooden ones. Twelve inches of ordinary concrete have about the same insulating value as % inch of wood. Special aggregates can improve the insulating value of concrete consid- erably. Manufacturers of these products can supply information on their effective- ness. Concrete and styrofoam sandwiches, cast flat and then tipped up into place, have been used successfully for ice bunkers. Floors and walls against dry soil do not introduce much heat after the first yard or so of soil is cooled, which may take several days, however. It can be calculated that ice or other refrigeration used in cooling the soil is worth perhaps four cents per square foot of surface each time the cooler is started up. Insulation is seldom provided, though apparently it should pay for itself. Heat can enter easily through exposed edges of floors or through surface soil against walls. Wall insulation should be carried two feet or more below the floor or below the outside grade, whichever is higher. Inadequate insulation may seriously 36 impair the cooling effect of an ice AIR PASbAGta [i) bunker. Air may emerge at 35°F from The cost of air passages and their ef- the ice in a bunker and on its way to the fects on the operation should be minor product be warmed to 40°F by contact factors in a well-designed fruit or vege- with poorly insulated surfaces. The cover table cooler, though unfortunately this of a poured concrete bunker is sometimes is not always the case. Ice bunkers or not insulated at all. On a hot day its top cooling units should be located as close surface may be too hot to touch while its as possible to the fruit that is being under surface is being swept by the cold cooled, and so arranged that openings air supply — conditions for serious heat through which the air passes may be of leakage at a point where it does most to ample size. Passages may sometimes be impair the effectiveness of the cooler, entirely eliminated, as by mounting fans Forced-air coolers should not be designed in a wall between a cooling room and with sheet metal or extensive, thin ply- an ice bunker, or by placing a cooling wood surfaces separating the return and unit in a room or separated from it only supply air. The return air in a forced- by a wall. Where passages are necessary air cooler may sometimes be 20°F or they should be of ample size, their walls more warmer than the supply. Heat leak- should be smooth and free from obstruc- age from the return to the supply does tions, and there should be as few turns not waste refrigeration but it slows cool- as possible, ing of the produce. Under these conditions, a few simple The inner part of the insulation is rules are sufficient to estimate the static usually cold enough to condense mois- pressure that will be contributed by the ture from any outside air that reaches air passages to the total head against it. To prevent this there should be a which the fans must work. It is first neces- vapor-proof barrier on the outside of the sary to estimate the air velocity, which insulation. The insulation is then warmer is the air flow in cubic feet per minute than the inside air which reaches it and divided by the area of the opening or remains reasonably dry. Blanket insula- the section of the passage in square feet, tion with a layer of metal foil on one For velocities of 500 feet per minute or side may be used. If there is foil on both less, the pressure loss is negligible in sides, the perforated side should be in- produce cooler operation and this is an ward. Polyethylene sheeting is an excel- ideal condition if openings can be made lent vapor barrier. lar g e enough. Although opinion differs in this re- A pressure of about .02-inch is needed spect, it is probably best to omit any to move air throu g h an opening or into vapor barrier in a concrete floor that is a P assa S e or around a s q uar e corner if laid on the ground. Such a floor, whether the velocit > r 1S 550 fe f P er minute ' This insulated or not, eventually becomes con- ^XL^ UP W highei velocities siderably colder than the soil beneath it, with the result that vapor from the soil 7nn *,. ^ • , rvo • i. , , i . -i * ' 00 * eet P er minute 03 inch condenses on the underside ol any vapor -, nrkA £ . n „ . , i . ., . . -j j /\ • . * i 1,000 feet per minute 06 inch barrier that is provided. Omission of the -. . ™ r , . „ rt . , i 11 .u • 1,400 feet per minute 12 inch vapor barrier allows the moisture to n ' ~ - J . „. . , ii i.i . 4 j 2,000 feet per minute 24 inch come through the concrete into the room, which does no harm in a produce cooler Pressure is needed to overcome friction and is even of some help in regard to i n a long passage, as well as to move air cooling the floor and to raising the into it. For a wood or concrete passage humidity. with no projections from its walls, each [37] length equal to 30 times the least lateral dimension is about equivalent to another opening or to a square corner. Friction may be doubled by small offsets or pro- jections, or reduced by one-half in a smooth metal duct. For example, the static pressure to produce an air flow of 5,000 cubic feet per minute in a smooth wood passage l'x 5' and 60' long, with one square turn, is estimated as follows: ^OOrfm = 1000 fpm air yeIocity 1 X o Pressure to move air into entrance 06 inch Pressure to move air around turn 06 inch Pressure to move air through 60' passage 30 X 1' x .06 inch .12 inch Total pressure 24 inch If such a passage as that in the example above was between the stacked containers and the wall in a forced-air cooler, there would be a difference of .24 inch in the pressures at the two ends of the stack. This would result in some of the boxes getting considerably less air than others, or even perhaps in some boxes getting no air at all. Due to eddies in the pas- sages, this effect can be very erratic and troublesome. It is recommended that air passages beside the boxes in a forced-air cooler should be large enough to keep the velocity under 500 feet per minute when the total pressure on the boxes is % inch, and under 1,000 feet per minute when the total pressure on the boxes is 2 inches. FANS (8) Fans for use in fruit or vegetable cool- ers should be chosen on a basis of ratings certified to conform to test methods of one of the fan manufacturers' associa- tions. These ratings are usually given in catalogs or should be furnished by deal- ers on request. To insure comparable results, these tests are made under ideal conditions, with straight, clear passages 10 fan diameters upstream and down- stream. Turns or obstructions have un- predictable effects on the true static head against which a fan works. Discharge in commercial installations is seldom more than 90 per cent of that based on static head in the rest of the system, and turns or large obstructions near the fans may reduce this figure to 75 or even 50 per cent. Ratings are usually for air delivered in cubic feet per minute and for static pres- sure against which the fan is working in inches of water. Static pressure in a cooler is the sum of the pressures needed to move the air through openings, pas- sages and turns; through the ice bunker or cooling system; and in a forced-air cooler, through the product. Inexpensive, sheet-metal fans may be used for pressures up to % or % inch. More expensive high-speed propeller fans are available for pressures up to 1% or 2 inches, above which it is necessary to use still more expensive centrifugal fans or special types of axial-flow fans. Fan power to circulate a given flow of air is in direct proportion to the static pres- sure. Power supplied to fans is converted to heat by churning of the air, requiring ad- ditional ice or refrigeration. A ton of mechanical refrigeration, or melting of a ton of ice a day, is required to offset the heat introduced by 3% horsepower of fans with the motors in the cooled space or 4 horsepower of fans with the motors outside. Coolers should be designed to operate at high static pressures only after considering the costs for fans and refrig- eration that are involved. [38 Section III ANALYSES AND TEST DATA COOLING CALCULATIONS (10,29) An object placed in surroundings at a constant lower temperature, if resistance to heat transfer from the object to the surroundings is constant, cools according to Newton's law. The process is conveni- ently analyzed as follows: Let d t h = time in the new surroundings. = temperature of the object at time 6. = initial temperature of the ob- ject. = temperature of the surround- ings. F = = remaining fraction of initial temperature differ- ence between the object and the surroundings. C = the rate of cooling divided by the temperature difference between the object and the surroundings, called the "cooling coefficient." Z = time to reduce the initial tem- perature difference between the object and its surround- ings by one-half, called the "half-cooling time." Then dt/dO = C(t - k >) 1, I- 6 -c^u- - U - *0 ' C 7 ln| 6 hiF (1) In a (2) From equation (1), C may be calcu- lated from observations of time and tem- perature, or when C is known it may be used to calculate the time to reach a given temperature or the temperature that will be reached in a given time. Graphically, C is the slope of a plot of InF against 0, which is easily constructed on semi-log paper, and which may be used to deter- mine either 6, F or C when any two of these quantities are known. Equation (2) and the half-cooling time Z are in some ways more convenient. This equation may be solved for Z, 0, or F, when any two of these quantities are given, by a single setting of a log-log slide rule; or either natural or common logarithms may be taken from tables. Z may be estimated by inspecting observa- tions for the time at which the initial temperature difference is reduced by one- half. The time needed to cool a product to l/o, % or Ys of the initial temperature above its surroundings is Z, 2Z or 3Z. [39} In the commercial cooling of fruits and vegetables, the conditions for Newton's law are seldom strictly satisfied. There is often a considerable temperature gra- dient within a container, or within indi- vidual fruits or vegetables when these are exposed, and resistance to heat transfer to the surroundings may vary. Most im- portant, the temperature of the immedi- ate surroundings, such as the air among stacked containers or even the tempera- ture of the main air stream, may fall considerably as cooling progresses. In most cases, however, there is a final heat sink at reasonably constant temperature, such as a thermostatically controlled space or the ice in a bunker. It has been our experience that Newton's law applies quite well if t is taken as the average temperature of the product at time 6, and t as the temperature of the final heat sink. This application would be exact if the conductance from the thermal center of the product to a fixed-temperature heat sink were constant, and apparently, the departures from such an ideal condition are small. For cooling in variable-temperature surroundings, the cooling coefficient may be considered as the decrease in object temperature in degrees per hour divided by the average temperature difference between the object and its surroundings. This may be written as: C = (ti - t)/e {t ~~ ^o)av (3) It is convenient to calculate (t— £ )av as the numerical average of equally timed observations. The resulting value of C is a measure of the exposure of the object in relation to its heat capacity, though it is obviously not possible to predict the cooling of an object from this coefficient without having also some means of pre- dicting the surroundings temperature. Equation (3) may also be used when the surroundings temperature is constant. In this case determining (£-£ ) av fr° m equally timed observations is the same as calculating it as the log mean of initial and final observations. For a given ob- ject exposed in a given way, C is evi- dently the same whether it is determined in constant temperature surroundings or in variable temperature surroundings, and a half-cooling time Z may be calcu- lated from it, though Z will have a physi- cal meaning only when the surroundings temperature is constant. C will obviously not be the same, how- ever, for different portions of the heat circuit; for example, from product to adjacent air, from product to main air stream, or from product to ice bunker. Cooling coefficients or half-cooling times as given in references may have been determined in any one of these ways, and it is important to note which. A figure based on a constant-temperature heat sink is the only one that can be used to predict cooling behavior. For this reason as well as for purposes of comparison, it is useful to estimate a conversion from one base to another. Using primed sym- bols to indicate the shorter portion of the heat circuit, we may write for any time : C = (h - t)/e it — to) av and C" = (<1 t)/6 (t - $. Hence: g_ = (t - < ') av C (t — to)av For air cooling systems the heat ca- pacity of the coolant is usually small and at any time the heat flowing through the circuit is that being lost by the prod- uct. Under these circumstances t - t' and t - t are proportional to the heat re- sistances over which they are measured. The heat resistances between different elements of a cooling system ordinarily depend on the physical setup and do not change as cooling progresses. Conse- quently (t - 1' ) / (t - 1 ) , is the same at whatever stage of cooling it is measured and we may write simply: [40 C t - to C " t- to 7 M z ~ C Z' c t - Z " C ' " t - -to - to Since C 2T C_ t - to (4) Commonly, V Q is the temperature of an air supply or a water supply and t is the temperature of ice, or of refrigerant in an evaporator. From measurement or former experience with similar situa- tions (t - Iq) / (t - 1 ) may be estimated at some fraction, usually between % and % . The product will then be cooled half-way to ice or refrigerant tempera- ture in a reciprocal fraction, usually be- tween % or x %, of the time required to cool it half-way to a constant surround- ing air or water temperature, with the same exposure. Calculations of Z and Z' to allow for effectiveness of air cooling in an ice bunker or evaporator are more involved. Continuing the above nomenclature and also letting: t r R v = temperature product. of air leaving t - t r t- t' ratio of air to prod- uct temperature differences, down- stream/upstream. R c = V - t, ratio of air to cold- sink temperature differences, down- stream/upstream. From equation (4) above Z^ z t - to (t - to) - (to - U) t - to t - t. ^ = 1 - £p — tp t - u (a) From definitions: (t - to) - (t r - to) = R p [(t - to) - (to - to)] I . tp — tp t r to — D Combining (b) and (c) and simplifying: = R P [(t - to) - (to - to)] (t - to) - U ~ R c to — to R c — RcRi t — £o 1 — R c Rp (b) (c) (d) Combining (a) and (d) : Z 1 R c — R c Rp 1 — Rc Z 1 — R C R P 1 — R c Rp (5) Z/Z' is plotted against R c for representative values of R p in figure 33, on which table 7 is based. [41] 4.0 r 3.5 Typical forced air cooler- Typical room cooler 3.0 2.5 2.0 Fig. 33. Effect of ice-bunker conditions on cooling. Z/Z / is product-to-ice half-cooling time divided by product-to-air half-cooling time. R c is ratio of air-to-ice temperature differences downstream and upstream. R is ratio of air-to-product temperature differences downstream and upstream. REFRIGERATION LOAD (31) Specific heat of plant material is usually estimated by assuming that the average specific heat of the dry matter is .2 and the specific heat of the water con- tent is 1.0. On this basis the specific heats of most fruits and vegetables involved in cooling operations range from .85 to .95, with an average value of about .9. Con- tainers and packing materials may be estimated to weigh y i0 as much as the product and to have a specific heat of .3. A specific heat of .93, based on the net weight of product, takes into account the heat capacity of the containers also. This is well within the accuracy to which prac- tical cooler performance may be pre dieted and is used for calculations in this publication. Complete tabulations of spe cine heats, on which corrections may be based if desired, are available in refer- ences (3, 31). Refrigeration load from cooling of the product in a batch operation may be calculated from the cooling equations de- veloped in the preceding section: dt/dO = C(t - to) where lni (t - to) dt/dd — cooling rate F/hr C = cooling coefficient, F/hrF t — to = temperature of product minus temperature of heat sink, F In y 2 = .69 Z = half-cooling time, hr Refrigeration load from cooling of the product in a continuous operation is the rate at which the product is passing through the cooler, times the temperature reduction accomplished, times the spe- cific heat of the product. < [42 The total heat evolved by respiration in a given cooling operation may be cal- culated by integrating the respiration rate, or it may be estimated graphically by plotting respiration rates against tem- peratures at successive half -cooling times as in figure 34. Any desired scale of time in hours may be substituted for the scale of half-cooling times. The total heats evolved by respiration, in refrigeration ton-hours, are then represented by the areas under the curves. Table 4 was pro- duced in this way. The scale of areas to refrigeration ton- hours is evidently directly proportional to the scale of Y-axis distances to hours. From this it follows that the heat evolved by respiration while cooling to any par- ticular temperature is directly propor- tional to the time elapsed in reaching that temperature. W. V. Hukill has demon- strated this analytically (31). Losses by heat conduction into a cooler through the walls and ceiling may be estimated with fair accuracy from tabu- lated conductances of the construction materials. Heat introduced by the fans can be calculated from electrical input at the rate of 3,413 Btu per kwh. Heat pickup from a concrete floor-slab is more uncertain. Infiltration of warm air from the outside can only be guessed from ex- perience and is usually important be- cause of appreciable static pressure and suction in a cooler. At least for small coolers it is probably as safe to make a single estimate of losses based on an assumed efficiency; ranging from 50 per cent for slow cooling, meagre insulation or considerable infiltration ; up to 80 per cent for fast cooling and tight, well- insulated construction. PERFORMANCE u o 1 2 3 4 •Half-cooling Times 5 6 80 56 44 38 35 Product Temperature (°F) 34 33 Fig. 34. Refrigeration to absorb heat of respiration, initial product temperature 80°F / coolant temperature 32°F. D h ICE BUNKER (6, 11, 14) Nomenclature A = surface area of ice per unit of F volume occupied. a = surface area of ice block of effec- tive mean size. [43], 'o = U = = linear dimension of ice block of effective mean size. = heat conductance from fluid to ice per unit surface area. = heat conductance from fluid to ice per unit of volume occu- pied. = distance in direction of fluid flow. = number of ice blocks. = fluid head per unit distance in direction of flow. = fluid head in distance X. = temperature of fluid after flow- ing distance L. initial temperature of fluid, temperature of ice. t' - U remaining fraction of initial temperature difference between fluid and ice. V = fluid velocity in gross section of flow path. W = weight of ice block of effective mean size. X = distance in direction of flow in which temperature difference between fluid and ice is re- duced by one-half. Subscripts 1 and 2 represent two con- ditions being compared. Other things remaining equal, heat transfer to broken ice in a bunker from air or water being forced through it varies directly with the temperature dif- ference between the ice and the air or water. The relation of temperature dif- ference to distance traveled is therefore logarithmic, corresponding to the rela- tion of temperature difference to time in the case of a cooling body as discussed previously. The distance in which the temperature difference is reduced by one- half is convenient for estimating the tem- perature reached in a given distance or the distance to reach a given temperature. This might be called the "half-cooling distance," corresponding to the half- cooling time for a cooling body. A par- allel analysis leads to the relation L/X — InF/ln %, which may be used for calcu- lations. Effect of size of ice blocks. The "half-cooling distance" is evidently in- versely proportional to the heat conduc- tance per unit volume: X,/X 2 = tijh[ Heat conductance per unit volume is in turn directly proportional to heat con- ductance per unit surface times surface per unit volume: From geometry, for blocks of similar shape : a 2 /ai = OD2/A) 2 , n 2 /wi = (D 1 /D 2 y , {Dx/DtY = WJW 2 Combining: Xr/X* = (Wt/Wt) to (6) Hence, the distance in which a given change in fluid temperature is accom- plished should vary with something be- tween the square-root and the cube-root of the effective weight of the ice blocks. From fluid dynamics, friction from flow among solids is inversely propor- tional to approximately the 1.5 power of the effective dimension of the solids, giving: P1/P2 = (iV^i) 1 - 5 , where (Z> 2 /Z>i) 3 = W 2 /W 1 Combining: Pi/Pt = Wz/Wt (7) In words, static head for flow through a given distance is inversely proportional to the square-root of the effective ice- block weight, other things being equal. Equations (6) and (7) may be com- bined to find the effect of ice-block weight on the static head needed to half- cool the fluid, velocity remaining un- changed : P1/P2 = { V i/V2){X l /X 2 ) = (W 2 /W 1 ) - 5 (W 1 /W 2 ) - 33 to (W2/WO - 5 (W 1 /W 2 ) - 5 = (W 2 /W 1 ) - 17 to (lf#i)° KlK = {h2/h l ){a 2 /a l )(n 2 /n l ) Apparently the static head to accomplish a given change in fluid temperature should be practically independent of the From heat transfer data, depending on weight of the ice blocks. conditions: Effect of fluid velocity among ice blocks of a fixed size. The "half-cooling hi/ hi = {Di/D 2 ) Q to (Di/D 2 )- 5 distance" with varying flow is evidently [44] .I75r .150 Inches water = 1.25x10 (fpm) .125 .100 • Bunker 4'x 24'x7'deep ©Bunker 3' x 4'x 4' deep Ice in 50 lb blocks .075 .050 .025 75 100 125 Velocity in Gross Section (fpm) Fig. 35. Airflow through ice bunkers, static head related to air velocity. 200 directly proportional to velocity and in- versely proportional to heat conductance per unit volume: Xi/Ti = (Vi/V i )(h' 2 /h' 1 ) In this case the surface per unit volume is fixed, so that heat conductance per unit volume is directly proportional to heat conductance per unit of surface, and from heat transfer principles for turbulent flow, approximately: h' 2 /h[ Combining: AtAi = (V2/VO Xi/x t = (F,/y 2 ) (8) Consequently, the distance to accomplish a given change in fluid temperature should vary directly with the .4 power of the fluid velocity. From fluid dynamics, friction from turbulent flow through a bed of solids is about proportional to the 1.8 power of the velocity: P1/P2 = (pi/p 2 )(x 1 /x 2 ; = (Fi/V*)" (9) (10) For flow through a given distance, the static head should vary directly with the 1.8 power of the fluid velocity, and for a given change in fluid temperature the static head should vary directly with the 2.2 power of the fluid velocity. Equations (6) through (10) should apply to cooling of either air or water in ice bunkers. They have been used to extrapolate the inadequate available data in figures 31 and 32. Figures 35 and 36 show tests with air flow through small bunkers, illustrating [45] Q. 4 Q .3 Depth (ft) = 0.64 (fpm) • Bunker 4 , x24'x7'deep ©Bunker 3'x4'x4'deep Ice in 501b blocks 25 50 150 175 75 100 125 Velocity in Gross Section (fpm) Fig. 36. Air flow through ice bunkers, half-cooling depth related to air velocity. 200 the erratic effects of recurrent melting and collapse of the ice structure. These results are consistent with conventional full-scale construction. A sufficient num- ber of observations at regular time inter- vals might show a statistical distribution on which more satisfactory design pro- cedures could be based. Published data on water-flow through broken ice seem to be entirely lacking and time has not permitted such measurements at Davis. HUMIDITY CALCULATIONS (28) Refrigeration texts commonly discuss the graphical representation on a psy- chrometric chart of changes in air tem- perature, moisture content and enthalpy. Such a representation of the history of a pound of dry air as it circulates in a closed system must evidently be a closed figure. This is a very convenient and useful way of analyzing events in produce coolers and storages. Figure 37 shows possible cycles in a cooler or storage where a pound of circulating air picks up 2 Btu in the cooling or storage room and loses 2 Btu in a cooling unit where the by-pass factor is 40 per cent and the cooling surfaces are at 32°F. If no moisture is gained or lost any- where in the circuit, the dewpoint of the air may be at the temperature of the cooling surfaces and a pound of dry air may be alternately heated and cooled along line A" F" . Entering air is about 37°F, 80RH; return air is 45.5°F, 59RH. If produce is being cooled without spray humidification, conditions may be like those in the next circuit above, with history of a pound of dry air as follows : [46] 13 Btu per pound dry air 14 15 16 32 34 36 38 40 42 44 46 48 Dry Bulb(°F) Fig. 37. Effect of humidification on air conditions in a produce cooler. 50' A' A'B f B'D' = Enters from cooling surfaces at 36°F, 90RH. = Gains 1.8 Btu from warm pro- duce and heat leakage from outside. = Gains 3.0 grains moisture by evaporation from produce. D'E' = Gains .2 Btu and .4 grain mois- ture by mixture with .02 lb air from outside, by leakage. = Loses 1.0 grain moisture by absorption in boxes. = Returns to cooling surfaces at 43°F, 75RH. = Loses 2.0 Btu and 2.4 grains moisture to cooling surfaces. The shape and position of this figure evidently depend on the order and magnitude of these events. However, it is only by virtue of net loss of moisture from the packed product or gain of moisture from outside air that the abso- lute humidity is anywhere above line A" F". Spraying water into the entering air may virtually stop evaporation from the product and double moisture absorption by the containers, as represented in the upper diagram; history of a pound of dry air being as follows: E'F' F' F'A' AC CD DE = Enters from cooling surfaces at 35.5°F, 96RH. = Gains 5.8 grains moisture from spray, of which .6 grain evap- orates and 5.2 grains remain as a fog. = Gains 1.8 Btu from warm pro- duce and heat leakage from outside. = Gains .2 Btu and .4 grain mois- ture by mixture with .02 lb from outside, by leakage. 47] EF = Loses 2.0 grains moisture by absorption in boxes. F = Returns to cooling surfaces at 41°F, 90RH. FA = Loses 2.0 Btu and 4.2 grains moisture to cooling surfaces. Conditions without and with water spray are summarized in table 9. Air circulation, cooling surface temperature, by-pass in the cooling units, and heat added and removed are assumed to be fixed. In this example, 5.2 grains of moisture per pound of entering air re- mains in suspension until the air is warmed and dried by contact with the produce and containers. For comparison, a thick natural fog contains two grains of suspended moisture per pound of air, and up to 18 grains per pound has been measured in dense clouds. In practice the gains and losses of moisture and heat in a cooling room occur more or less in parallel, rather than in series as shown in the diagrams. The level of humidity that may be attained by use of a spray system without trouble from water col- lecting on floors or on produce is some- thing that must apparently be determined by experience. It should be noted that the relation of moisture condensed to heat given up at the cooling surfaces depends only on return air and cooling surface conditions and is independent of the by-pass factor. Figures 38 to 41 are constructed from a psychrometric chart for a range of return air and cooling-surface conditions. In some cases line AF in figure 37 inter- sects the saturation line at a temperature above that of the cooling surfaces. This indicates condensation from mixing as air passes through the cooling unit. This condensation or fog may impinge on surfaces in the cooling unit and be re- tained, or it may pass out with the air blast and evaporate as mixing is com- pleted. These alternatives are indicated in figures 38 to 41. OPTIMUM INSULATION (28) Produce coolers are sometimes used for shorter seasons than other insulated structures but at wide differences of temperature between inside and outside, raising questions as to how much insula- tion should be provided. The following analysis assumes that temperature dif- ference between outside and inside of insulation is independent of insulation thickness, that cost of refrigeration per heat unit absorbed is fixed and that annual insulation cost is directly pro- portional to insulation thickness. TABLE 9 Effect of Water Spray on Temperatures and Humidities in a Cooler Refrigerated with Unsalted Ice Air conditions Entering air Return air Moisture added or removed Spray Evaporation from produce Gain from air leakage Condensation in boxes Condensation on cooling surfaces Without spray With spray 36F, 90RH 43F, 75RH 35.5F, 96RH 41F, 90RH Gal per day per ton of refrigeration per ton of ice melted vTone 14.5 7.5 None 1.0 1.0 2.5 5.0 6.0 10.5 [48] IOOi- 10 18 25 32 Cooling surface temperature (°F) Dotted lines fog forms in cooling unit and evaporates Dashed line fog forms in cooling unit and is retained 2 4 6 8 10 12 14 16 Moisture (gallons per day per ton of refrigeration) Fig. 38. Moisture added in a room and condensed on ice or coils, return air 35°F. Nomenclature (any consistent units) : Ci = annual cost of insulation per unit area and thickness, cost of refrigeration per heat unit absorbed. = annual operating season. = heat conductance of insulation. = temperature difference outside to inside of insulation. = insulation thickness. C r = Then: Annual cost of insulation per unit area — c* %x» Annual cost of refrigeration to offset heat leakage through a unit area of insulation = C r kLta/x Taking the derivative of total cost with respect to x and equating to zero: d - CrkLt d /x 2 = x = (C r kLt d /Ci)i In words, the optimum insulation thick- ness is the square root of the annual cost of refrigeration to offset heat leakage through a unit area of unit thickness, divided by the annual cost of insulation of unit area and thickness. Consider for example a metal hydrocooler under these conditions: Insulation cost installed S^/sq ft 1" thick, annual fixed charges 33% per cent, annual cost 1^/ft 2 in [49] 10 25 32 I00r 90- 80- 2. X 70 60 50 40- 30 20. # # / § ^f ^^^ -^^J? - J& jf 18 / y / J°~^ Brine temperature (°F) y Dotted lines fog forms in cooling unit and evaporates ,i., Dashed line fog forms in cooling unit and is retained . I 1 I 1 1 i 2 4 6 8 10 12 Moisture (gallons per day per ton of refrigeration) 14 16 Fig. 39. Moisture added in a room and condensed in brine spray, return air 35°F, relative humidity at brine surface 93 per cent. Refrigeration cost $6/ton for ice, .002^/Btu Annual operating season 30 days, 720 hours Heat conductance of insulation .36 Btu/ft 2 hr(F/in) Temperature difference outside to in- side, average, 30°F Annual cost of refrigeration to offset heat leakage through 1 sq ft of insula- tion 1 inch thick: (.002jzf/Btu)(.36 Btu/ft 2 hr F/in) • (720hr)(30°F) = 15.5*! in/ft 2 Optimum thickness : [(15.5^m/ft 2 )/(l^/ft 2 in)P = 4 in FORCED-AIR COOLING CALCULATIONS (5,27) Calculation of forced-air cooling times and temperatures from principles of heat transfer requires constants which have not been directly determined. Calcu- lations from assumed constants are use- ful, however, in evaluating and applying existing test data. Heating or cooling of a bed of solids, by a fluid passing through, establishes temperature gradi- ents from entrance to exit in both the fluid and the solid. Calculation of the initial fluid temperatures from entrance to exit, and of the solid temperatures at the entrance from start to finish, are not [50] 10 18 25 32 i /// Dotted lines fog forms in cooling unit and evaporates Dashed line fog forms in cooling unit and is retained '0 2 4 6 8 10 12 14 16 Moisture (gallons per day per ton of refrigeration) Fig. 40. Moisture added in a room and condensed on ice or coils, return air 50°F. difficult, but fluid and solid temperatures in the interior as time passes are some- thing of a problem. Figure 42 shows a graphical solution published by C. C. Furnas, for air flow parallel to the axis of a prismatic ar- rangement of solids, with solids initially at a uniform temperature and air entering at a constant temperature and rate (5, 27). Nomenclature is as follows: c a = Specific heat of air, Btu/lb F c s = Specific heat of product and con- tainers, Btu/lb F hA = Heat conductance from product to air, Btu/ft 3 hr F w a = Air rate in gross section, lb/hr ft 2 w s x e t h te to z D T 1] Density of product and con- tainers as stacked, lb/ft 3 Distance from air entrance, ft Distance from air entrance to air exit, ft Time, hr Temperature of product at x and 6, F Initial temperature of product, F Temperature of product at exit at time 0, F Initial temperature of air, F Time to reduce (t — t ) by one- half hAx/caWa "Distance parameter' ' hA6/c s w s "Time parameter" Dotted lines fog forms in cooling unit and evaporates Dashed line fog forms in cooling unit and is retained 2 4 6 8 10 12 14 Moisture (gallons per day per ton of refrigeration) Fig. 41. Moisture added in a room and condensed in brine spray, return air 50°F, relative humidity at brine surface 93 per cent. T.5,T. us Time parameters for (t — t ) /(h - t ) = .5 and .125 re- spectively Tables 10 to 12 show calculated cool- ing rates for downstream fruit, related to heat conductance, air rate and product density. It is interesting that arranging a given lot of fruit in a single tier or in several tiers, while the air flow in cfm/lb of fruit is held constant, increases both x e and w a in proportion and so has no direct effect on the cooling rate of the down- stream fruit. The increase in w a no doubt results in some increase in hA, which should in turn produce faster down- stream cooling in a multiple-tier arrange- ment. Note however that air flow among the fruits is probably partly laminar, that hA depends in part on resistance to heat flow inside the fruits, which is not af- fected by w a , and that table 10 shows that cooling rate varies only with some fractional power of hA. It is not surpris- ing for tests to show that cooling of the downstream fruit is not significantly af- fected by single or multiple tier arrange- ments so long as the air flow in cfm/lb of fruit is not changed. Table 11 shows that the cooling rate of the downstream fruit should vary with about the square-root of the air rate, which is in accord with test results. Table 12 shows the considerable effect of prod- [52] 3 4 T= hA0/c s w 8 Fig. 42. Graphical solution for heat transfer between a moving fluid and a bed of solids. (Furnas, 1930; Schumann, 1929). uct density, so evident in the fast cooling of such light products as strawberries in trays. These tables show the approximations involved in considering that cooling is logarithmic — in particular that a half- cooling time calculated from one stage in a cooling operation may be used to predict conditions at some other stage. Z 5 and Z. 125 represent half-cooling times calculated for reduction of the initial temperature difference to one-half and one-eighth of its initial value, respec- tively. For small values of D, correspond- ing in general to thin stacks and high air velocities, Z 5 and Z 125 agree very well. For the largest value of D, in table 11, Z 5 is 75 per cent greater than Z 125 , indicating that for thick stacks and low air velocities half-cooling times provide only a rough prediction of cooling be- havior. [53 TABLE 10 Forced Air Cooling with Varying Product-to-air Heat Conductances c a = .24 Btu/lb F, c s = .9 Btu/lb F, w s = 30 lb/ft 3 , air rate 1 cfm/lb product = 144 lb/hr ft 3 , c s ws = 27 Btu/ft 3 F, x e / CaWa = .029 ft 3 F/Btu. hA (Btu/ft» hr F) hAxe/CaWa = D (no dimension) T.5 from chart (no dimension) T.125 from chart (no dimension) T.sCW./hA = Z.5 (hr) T.uiCsW,/UA = Z.l2b (hr) ^average (hr) 10 20 40 80 .29 .58 1.16 2.32 4.64 .9 1.2 1.8 2.8 5.2 2.8 3.4 4.4 6.1 9.0 2.5 1.6 1.2 1.0 .9 2.5 1.5 1.0 .7 .5 2.5 1.6 1.1 .8 160 .7 TABLE 11 Forced Air Cooling with Varying Air-rate hA = 40 Btu/ft 3 hr F, c c Btu/ft 3 F. .24 Btu/lb F, c a = .9 Btu/lb F, w s = 30 lb/ft 3 , c s w s 27 Air rate (cfm/lb product) hAXe/CaWa = D (no dimension) from chart (no dimension) T.us from chart (no dimension) T.bCsWs/hA = z. b (hr) T .i2bC e w,/3hA = Z.12S (hr) ^average (hr) .25 .5 4.64 2.32 1.16 .58 .29 5.2 2.8 1.7 1.2 .9 9.0 6.1 4.4 3.4 2.8 3.5 1.9 1.2 .8 .6 2.0 1.4 1.0 .8 .6 2.8 1 6 1.0 1 l 2.0 8 4.0 .6 TABLE 12 Forced Air Cooling with Varying Product Density hA = 40 Btu/ft 3 hr F, c a = .24 Btu/lb F, c s = .9 Btu/lb F, air rate 1 cfm/lb product. (lb/ft*) CsW» (Btu/ft»F) air rate (lb/ft« hr) hAXe/CaWa = D (no dimension) from chart (no dimension) T.125 from chart (no dimension) T.iCsWs/hA (hr) T.i2oC s w s /MA = Z.125 (hr) ^average (hr) 15.... 30.... 50... 13.5 27 45 72 144 240 2.32 1.16 .70 2.85 1.75 1.30 6.1 4.4 3.5 1.0 1.2 1.4 .7 1.0 1.3 .8 1.1 1.4 [54] HALF-COOLING TIMES Room cooling, Half-cooling times based on constant air temperature, data from tests at Davis, except as noted. Half-cooling time Artichokes packed in paper-lined apple boxes, loaded on end with sides in contact with adjacent boxes, tops and bottoms exposed to air in random motion, average of 10 thermocouples in centers of artichokes 9 hr Grapes in standard wooden lugs with sides and ends exposed to air in random motion, average of two thermocouples in grapes in one box 10 hr Same, 400 fpm air velocity parallel to long dimension of lug, sides and ends exposed, average of five thermocouples in grapes in each of two boxes 8 hr 20 min Grapes in 12 2-lb consumer cartons in master cartons, stacked with sides and ends exposed to air in random motion, average of two thermocouples in grapes in each of two boxes 23 hr Pears, standard wrapped pack in wooden boxes, ends and bulged top exposed to air in random motion, thermocouples in corner, side and center pears, average of three tests : Corner pear 6 hr Average pear 16 hr Center pear 24 hr Pears naked in wirebound box, about 35 lb net, sides and ends ex- posed to air in random motion Of four thermocouples in pears: Coolest 9 hr Average 12 hr Warmest 13 hr Pears naked in telescope carton with hand holes in ends, about 40 lb net, sides and ends exposed to room air Of four themocouples in pears : Coolest 9 hr Average 18 hr Warmest 21 hr Same, but pears wrapped and carton ends only exposed Of four themocouples in pears : Coolest 15 hr Average 25 hr Warmest 28 hr [55] Pears naked in telescope carton with no vents, 36 lb net, sides and ends exposed to room air, thermocouples in corner, side and center , pears, average of three tests Haif-cooiing time Corner pear ^ nr Average pear 11 hr Center pear 17 hr Pears in 2-lb consumer carton packed 20 in cubical master carton, four sides exposed to room air, average of two tests Of four thermocouples in pears: Coolest. 8 hr I Average 14 hr Warmest • 18 hr $ Pears naked in field lug, sides and ends exposed, other lugs beneath and on top Of four thermocouples in pears : Coolest 7 hr Average 8 hr ^ j Warmest ., ...'. .,;:." 9 hr Half-cooling time Pear, Single, 2%" dia., 260 grams Surface Center Exposed to room air 52 min 1.3 hr 20 mph air blast 8 min 30 min 4 Pear, single, 2" dia., 100 grams Exposed to room air 28 min 36 min 20 mph air blast 6 min 18 min Pears in 36-lb cartons stacked on pallet, top and bottom vents in line with vent in pallet, no lateral spacing, thermocouples in centers of nine cartons, tests in Lake County Haif-cooiing time 1 Coolest carton (corner bottom) 12 hr Average of nine cartons 24 hr Warmest carton (center top) 48 hr Pears in 36-lb cartons cross-stacked on pallet, with lateral spacing, thermocouples in centers of cartons, tests in Haif-cooiing time T olro r^rvnr-i + ir Six cartons Six cartons i^aKe bouncy with vents wit h ut vents Coolest carton 8 hr 17 hr Average carton . 14 hr 18 hr Warmest carton 21 hr 21 hr [56] Plums in 12^" X 12}^" X 7" (inside) corrugated fibreboard box, top layer in fibreboard tray, 25 lb net, average of two thermo- couples in plums in each box With polyethylene liner: Haif-cooiing time Two sides exposed in room air 24 hr Two sides exposed in 10 mph air 12 hr No liner, two hand holes: Two sides exposed in room air 16 hr Two sides exposed in 10 mph air 4 hr Same, but folded telescope box, sides five layers of corrugated board, Two sides exposed to room air, no vents 26 hr Four exposed vents each Y%" X 2}^" 15 hr Six exposed vents each %" X3" 11 hr Same, box with projecting lids, sides two layers of corrugated board, Two sides exposed to room air, four exposed vents each 1" X 3" 9hr Plums in 12^" X 12^" X 7" (inside) laminated kraft-veneer box with wooden frame, top layer in fibreboard tray, 25 lb net, average of two thermocouples in plums, two sides exposed to room air ... . 9 hr Plums in 12^" X 12^ ,/ X 7" (inside) corrugated fibreboard box, top layer in fibreboard tray, 25 lb net, two sides exposed, average of two thermocouples in plums in each box Projecting lid, room air 11 hr Projecting lid, air velocity 720 fpm 8 hr Telescope box : 8 W X 2" horizontal vents, room air 10 hr 8 K" X 2" horizontal vents, 630 fpm 8 hr 8 Y2' X 2" vertical vents, room air 1 1 hr 8 y 2 " X 2" vertical vents, 520 fpm 9 hr 4 34" X 2" horizontal vents, room air 1] hr 4 l /i" X 2" horizontal vents, 630 fpm 10 hr No vents, room air 18 hr Plums in four-basket crate, two sides exposed, average of two ther- mocouples, room air 9 hr Same, 630 fpm 2 hr Plums, single fruits on table : Room air 30 min Air blast 1750 fpm 8 min [57] Potatoes in special boxes to test effect of vents; 11 3^" X 17 %" X 8%" high; tops, bottoms and ends insulated; sides two layers corrugated fibreboard exposed to air movement and with vents as indicated, average of four thermocouples in potatoes in each box Per cent of side area vented Half-cooling time Room air 200 f pm No vents . . hr 15.3 14.8 14.0 11.8 10.0 8.6 5.9 5.0 hr 14 1.3 14.1 2.6 10 3 5.2 10 9 10.4 5 7 24 5 7 52 4 100 2 7 - (1 per cent of side vented reduces cooling time about 5 per cent) Potatoes in experimental plastic lugs 15" X 24" X 9" outside, 64 lb TT . . ' Half-cooling net, 7.4 lb tare, stacked three high m room air, average of five time thermocouples in potatoes in center lug, tight bottoms 9 hr Same, but wood lugs 12%" X 22" X 9", 50 lb net, 9 lb tare. ... 6 hr Strawberries in corrugated fibreboard tray containing 12 12-ounce baskets, six stacks of 12 trays each on single pallet, all sides ex- posed in large cold-storage room Of four thermocouples in berries : Average 2.2 hr Warmest 3 nr Forced-air cooling Half-cooling times based on constant air temperature, data from tests at Davis, except as noted. Artichokes packed in plum cartons 123^" X l2 l / 2 " X 6J^" high inside, three layers of 16 artichokes each, net wt 32.9 lb, 2 %," X 3" vents in each of opposite faces of cartons, axes of artichokes normal to air-flow, static air head across carton J/g" water, air- flow 1.5 cfm/lb product 1.2 hr Grapes, stack of five standard lidded lugs, average net wt 28 lb each, average of five thermocouples in each of two boxes, static head across lugs .09", air flow 1.5 cfm/lb product 41 min Same, static .005", air flow .2 cfm/lb product 3.7 hr Same, static ("water). .07 .05 .03 .02 .01 .008 air-flow (cfm/lb) . . . 1.2 1.0 .74 .58 .36 .26 [58] Grapes in 123^" X 12^" X 7" plum carton, 3 %" X 3" vents in each of opposite faces, 23.8 lb net, average of 10 thermocouples in car- ton: Static head, inches 2.1 .75 .25 .10 Air flow cfm/lb fruit 4.5 2.5 1.5 .84 Half-cooling time 10 min 15 min 22 min 34 min Grapes in 12 2-lb consumer cartons in master carton, 6 Y%' X 1%" vents in each of opposite faces of master with 34" X 13^" vents in 2-lb cartons to match, average of four thermocouples in up- stream 2-lb cartons and four in downstream, static on master carton .2", air-flow 1.1 cfm/lb fruit, average fruit 48 min Same, downstream fruit 80 min Grapes in 12 2-lb consumer cartons in master cartons, 134" X 7" vents in tops and bottoms of masters by shying flaps, 5 Y2' holes in top and bottom of each end of 2-lb cartons, stack of five master cartons with vents lined up, slatted floor, static top to bottom .15", air flow .13 cfm/lb fruit, simulating solid load in rail car, horizontal baffle in center of master carton to force air to sides, average of two thermocouples in grapes in bottom master carton Same, but no baffle Same, but no holes in 2-lb cartons Melons in cartons 14J4" X 2334" X 9M" high outside, net weight 58 lb, stacked four high on slatted floor rack, }/$" static head on top of stack, simulating rail car loaded solid : 5hr 5hr 9hr Vent area Air flow Half-cooling time Top Bottom Matching floor slots Top carton Second carton Third carton Bottom carton (in*) 20 11 18 (in*) 15 11 18 (in*) 1.0 1.0 1.2 (cfm) 25 28 29 hr 2.2 2.6 2.5 hr 4.8 3.8 3.6 hr 6.6 6.1 5.9 hr 7.5 7.7 6.1 Peaches in paper cups, two layers in standard wooden box, 22 lb net, horizontal air flow, average of 8 thermocouples near pits of peaches Thin pads, static head .08": Haif-cooUng time 5.0 cfm/lb fruit 50 min 4.8 cfm/lb fruit 50 min Thick pads, static head .10": 1.3 cfm/lb fruit 51 min [59] Peaches in naked pack, two layers in standard wooden box, 22 lb net, horizontal air flow, average of eight thermocouples near pits Of peaches Half-cooling time Thick pads, static head .07", 5.2 cfm/lb fruit 46 min Thick pads, static head .005", 1.3 cfm/lb fruit 1.3 hr Peaches in 12^" X 123^" X 7" (inside) plum boxes with 3 %" X 3" vents in each of opposite faces, 48 peaches net weight 19 lb, horizontal air flow Half -cooling time 25 min 29 min 34 min 46 min 1.2 hr Static head inches Air flow cfm/lb fruit 2.1 7 1.2 5 .8 4 .16 2 .04 1 Pears naked in 12" X 18" X 10" cartons with side vents, 36 lb net, air flow horizontal, average of 8 thermocouples in fruit Static head inches Air flow cfm/lb fruit .50 2.4 .30 1.8 .13 1.4 .08 .86 Half -cooling time 39 min 46 min 50 min 1.1 hr Pears naked in 12" X 18" X 9^" cartons, 36 lb net, stack of four cartons with top and bottom vents in line, 1 thermocouple in center of pear in center of each carton, static head on stack .1" Air flow cfm/lb fruit Half -cooling time Arrangement Carton Top 2nd 3rd Bottom Bottom carton with vents exposed. . .40 .30 hr 1.7 2.5 hr 4.5 5.5 hr 7.5 7.5 hr 8 2 Bottom carton in floor rack with Y^" slots on 4" centers 9 Plums in Sanger lugs, 22 lb net, horizontal air flow, average of eight thermocouples in plums in 1 lug Haif-cooiing time Static head .10", air-flow 2.3 cfm/lb fruit 29 min Static head .008", air-flow .6 cfm/lb fruit 78 min Same, but vertical air-flow Static head .09", air-flow 2.3 cfm/lb fruit 27 min Static head .01", air-flow .7 cfm/lb fruit 59 min [60] Plums in 12}^" X 12^" X 7" cartons with 3 %" X 3" vents in each of opposite faces, 24 lb net, horizontal air flow, average of 10 thermocouples in plums in one carton Static head Airflow inches cfm/lb fruit Half-cooling time 1.4 4.0 20 min .8 3.0 23 min .3 1.6 32 min .05 .6 53 min Potatoes in 12" X 18" X 9J^" pear cartons stacked 4 high with top and bottom vents in line, 40 lb net per box, static head .12" on top of stack, air flow .56 cfm/lb product, two thermocouples in potatoes in each box Location of box Half-cooling time Top Bottom Average Top hr .6 2.1 3.3 4.8 hr 2.1 3.2 4.7 5.8 hr 1.4 2nd 2.6 3rd Bottom 4.0 5.3 Strawberries in corrugated fibreboard trays containing 12 12-ounce baskets, six stacks of 12 trays each on single pallet against air- return from large cold-storage room, static head on three tiers of trays .5", air-flow estimated 3.0 cfm/lb berries, test at Watson- ville Of six thermocouples in berries: Haif-cooiing time Average 16 min Warmest 23 min Strawberries in above pack but three trays in one stack in labora- tory cooler, average of nine thermocouples in berries Static head inches .05 .002 air flow cfm/lb berries 3.0 .8 . 25 min 1 hr [61] 2 min Hydrocooling (data from tests at Davis except as noted) Half-cooling time Asparagus in bunches (data by R. L. Perry, 17), five bunches, total weight 15.2 lb, immersed in trough with water flow 3 gpm, aver- age of 10 thermocouples Cantaloupes in commercial hydrocooler (data by Lipton and Stew- art, 13), thermocouples % inch beneath surface, half-cool to water temperature 20 min Peaches in half-bushel baskets (data by Harris and Spigner, 9). Fruit dia 2Jjj$", in different positions in baskets, water flow 8 gal/min sq ft, temperatures at pit. Concentration Calculated half-cooling time wetting agent (ppm) Top Middle Bottom Average min min min min 8 22 12 12 250 9 13 10 10 500 8 11 10 10 750 9 11 9 10 1,000 8 9 10 9 Fruit dia 23^", in centers of baskets, temperatures at pit. Water-flow (gal/min sq ft) Calculated half-cooling time With wetting agent Without wetting agent 24 min 9 14 24 min 8 18 16 8 22 3 31 1.8 Fruit dia 2J^", water flow 3.6 gal/min sq ft, no wetting agent: Depth Surface «" l Half-cooling time 1 min ie" 8 min 2 22 mm p it 28 min Water flow 3.6 gal/min sq ft, with wetting agent, temperatures at pit: Fruit diameter inches Half-cooling time 2 34 13 min 25 A 16 min [62] Peaches in special test box 1 ft cube inside, 114 peaches, 34 lb net, four thermo- couples at pits, water sprayed on top, drains adjusted to keep box empty or full of water, tests at Davis: Water level in box Water flow through box Half-cooling time Average Warmest min min 22 38 14 15 15 18 18 22 21 24 Box empty Box full . . . (gpm) 5.0 5.7 2.8 2.0 1.5 Peaches in commercial hydrocoolers (Toussaint et al, 1954), half- Haif-cooiing time cooling at pits based on 32°F ice, tests at 1 1 hydrocoolers, range . . 8 to 14 min Average 11 min Pears in open lug (150 size Anjou), water spray about 4 gal/min sq ft, three thermocouples near cores, Top layer 11 min Center layer . Bottom layer. Pear, single fruit immersed in still water. Core Plum, single fruit immersed in still water, at pit , 17 min 13 min 6 min 20 min 4 min UNITS AND CONVERSION FACTORS One ton of refrigeration equals: 288,000 Btu/da, 12,000 Btu/hr, 200 Btu/min Heat absorbed by melting water ice at rate of: 1 ton/da, 83 lb/hr, 1.4 lb/min Heat absorbed by vaporizing dry ice at the rate of: 0.52 ton/da, 44 lb/hr, .73 lb/min Melting 1 lb water ice absorbs 144 Btu. Vaporizing 1 lb dry ice absorbs 274 Btu. One kilowatt-hour converted to heat equals 3,413 Btu/hr = .28 tons of re- frigeration. One horsepower converted to heat equals 2,540 Btu/hr = .21 tons of refrigera- tion. Specific heats: fruits and vegetables .85 to .95, average .90 used in this bul- letin; wood and paper .30, air at 35°F .24. Specific volume of air at 35°F 12.5 ft 3 /lb. 1 lb = 7,000 grains. 1 grain moisture per Btu = 5 gal w T ater per ton-da of refrigeration. Approximate compressor horsepower per ton of refrigeration (2) Evaporator Temp. (°F) Condenser Temp. (°F) 95 115 135 30 20 1.1 1.3 1.5 1.7 1.5 1.8 2.1 2.3 2.0 2 4 10 2 7 3 2 [63 REFERENCES 1. American Society of Heating and Air-Conditioning Engineers. Heating, ventilating, air- conditioning guide. 35th edition. American Society of Heating and Air Conditioning Engineers. 1957. 2. American Society of Refrigerating Engineers. Air conditioning-refrigerating data book, 10th edition, design. American Society of Refrigerating Engineers. 1957-58. 3. American Society of Refrigerating Engineers. Air conditioning-refrigerating data book, vol. 1, refrigeration applications. American Society of Refrigerating Engineers. 1959. 4. Friedmann, B. A., and W. A. Radspinner. Vacuum cooling fresh vegetables and fruits. AMS- 107. USDA Agricultural Marketing Service. April, 1956. 5. Furnas, C. C. Heat transfer from a gas stream to a bed of broken solids. Industrial and Engineering Chemistry. 22(7) : 721-31. July, 1930. 6. Giedt, Warren H. Principles of engineering heat transfer. Van Nostrand. 1957. 7. Harvey, E. M., E. P. Atrops, H. W. Hrusehka and H. R. Barber. Shipping and cooling-in-car tests with oranges in fibreboard cartons in different load patterns, 1953. AMS-2. USDA Agricultural Marketing Service. November, 1954. 8. Henderson, S. M. and R. L. Perry. Agricultural process engineering. John Wiley & Sons. 1955. 9. Harris, Hubert, and R. L. Spigner. Hydrocooling peaches. Mimeograph. Alabama Polytechnic Institute Agr. Exp. Sta. No date. 10. Hicks, E. W. Precooling of fruits and vegetables, some theoretical considerations. Paper No. 2593 (0.11) Proceedings of Ninth International Refrigeration Congress. International Insti- tute of Refrigeration, Paris. 1955. 11. Hickson, Arthur W. and Sidney J. Baum. Heat and mass transfer coefficients in liquid-solid systems. Industrial and Engineering Chemistry. 33(11) : 1433-39. November, 1941. 12. Isenberg, F. M. and John Hartman. Vacuum cooling vegetables. Cornell Extension Bulletin 1012. New York State College of Agriculture. June, 1958. 13. Lipton, Werner J. and Joseph K. Stewart. Commercial hydrocooling of cantaloupes tested. Western Grower and Shipper. 30(6) June, 1959. 14. McAdams, William H. Heat transmission. McGraw-Hill. 1942. 15. Mitchell, F. Gordon and H. B. Richardson. What we're learning about Tokay quality. Blue Anchor. 33(3) August, 1956. 16. Parsons, Philip S. and Ralph Rush. Unpublished report. University of California, Davis. December, 1957. 17. Pentzer, W. T., R. L. Perry, G. C. Hanna, J. S. Wiant and C. E. Asbury. Precooling and shipping California asparagus. Bulletin 600 University of California Agr. Exp. Sta. April, 1936. 18. Pentzer, W. T., James S. Wiant and John H. MacGillivray. Market quality and condition of California cantaloupes as influenced by maturity, handling and precooling. Technical Bulletin No. 730. USDA July, 1940. 19. Pentzer, W. T., C. E. Asbury and W. R. Barger. Precooling California grapes and their refrigeration in transit. Technical Bulletin 899. USDA October, 1945. 20. Pentzer, W. T. and W. R. Barger. Precooling grapes in tunnel coolers. H. T. and S. Office Report 198. USDA Bureau of Plant Industry, Soils and Agricultural Engineering, 1948. 21. Redit, W. H., M. A. Smith and P. L. Benfield. Tests on hydrocooling and refrigeration of peaches in transit from Georgia and South Carolina, 1954. AMS-62. USDA Agricultural Marketing Service. July, 1955. 22. Ryall, A. Lloyd, James R. Clements, W. A. Radspinner, F. W. Allen and R. W. Harris. A comparison of transit protective services for Bartlett pears during the early part of the shipping season. H. T. and S. Office Report No. 232. USDA Bureau of Plant Industry, Soils and Agricultural Engineering. October 15, 1950. 23. Ryall, A. Lloyd. A study of packaging materials. Ice and Refrigeration. August, 1952. 24. Ryall, A. Lloyd. Condensed data on rate of cooling experimental plum cartons. Mimeograph. U. S. Horticultural Field Station, Fresno. May, 1953. 25. Sainsbury, G. F. Improved fruit cooling methods. Refrigerating Engineering, 59(5) May, 1951. [64] 26. Sainsbury, G. F. and H. A. Schomer. Influence of carton stacking patterns on pear cooling rates. Marketing Research Report No. 171. USDA Agricultural Marketing Service. April, 1957. 27. Schumann, T. E. W. Heat transfer: A liquid flowing through a porous prism. Journal of the Franklin Institute. 208 (3) September, 1929. 28. Stoecker, W. F. Refrigeration and air conditioning. McGraw-Hill. 1958. 29. Thevenot, R. Precooling. Paper No. 2592 (0.10) Proceedings of Ninth International Re- frigeration Congress, International Institute of Refrigeration, Paris. 1955. 30. Toussaint, W. D., T. T. Hatlow and George Abshier. Hydrocooling peaches in the North Carolina sandhills, 1954. A. E. Information Series No. 39. North Carolina Agricultural Experiment Station. February, 1955. 31. Wright, R. C, Dean H. Rose and T. M. Whiteman. The commercial storage of fruits, vegetables and florist and nursery stocks. Agricultural Handbook No. 66. USDA September, 1954. [65 ACKNOWLEDGMENTS This publication presents the engineering conclusions of cooperative studies by the Departments of Agricultural Economics, Agricultural Engineering, Pomology, Vegetable Crops and Viticulture and of the Extension Division of the University of California. Particular appreciation is due to George Giannini, Ralph Parks and Russell Perry of the University of California, to Diven Meredith for his contributions to forced-air cooler design, to Richard Bagdasarian, Harry Carian, Randolph Frink and Glen Moody who demonstrated their confidence in University findings by con- structing the first commercial forced-air coolers, and to Vincent Gessel for test data on his installations of spray humidification and cooling by air jets directed down- ward from the ceiling. 10m-7,'60(A7954)JF i' fcmw nmm 21 ji> *m. \M. . . This is probably the world's largest plow — it was built about 1910. It plowed an acre in four and one-quarter minutes. A swath 60 feet wide was turned under by 55 bottoms, pulled by three oil-burning tractors. The monster plow was built in sections and assembled for several test runs in the midwest. Impractical? ... no! This "stunt" yielded new knowledge about hitches . . . knowledge that agri- cultural engineers have used in designing many of today's farm implements. For more than 40 years agricultural engineering has offered opportunity to young men of mechanical bent with an interest in agriculture. And as mechanization increases on farms, opportunities in agricultural engineering expand . . . with the GOOD JOBS going to those who are WELL TRAINED. Many leaders in the field were trained at the University of California at Davis. The staff at Davis is recognized nationally and internationally for its accomplishments in teaching and in research. The Department of Agri- cultural Engineering is accredited ... a graduate is eligible for examina- tion for a Professional Engineer's license, or he may continue study toward a master's or doctor's degree. The growing College of Letters and Science on the same campus broadens the student's educational and social back- grounds. For further information . . . about courses and careers in agricultural engineering, write Mr. Roy Bainer, Chairman, Department of Agricultural Engineering, University of California, Davis. Or . . . See the College Entrance Advisor in the office of your local Farm Advisor.