COMPILED BY MAJOR WALTON C. CLARK, C. A. ARTILLERY SCHOOL FORT MONROE, VIRGINIA HEAVY (COAST) ARTILLERY COAST ORIENTATION * .*--( - : --~~~ -…--~~~~ ~~~~ æ: §§§§§§§§§ $§šºſ #ffff;&~~~~--~~~~); ț¢&###~##### ::: ··. , : · · · · ·:· ■■■■ ■ ■*!*®.: §, №- ~~ ~ ~ ~~~~,~ ~~~~~ ~~~~(☆ ! TTTTTTTTTWA: E E. = E = E E E 3 E ſ = - \º sººrinº URiº. S- 3) . # . . . º ºf a * i BW W [...] > - : .-. ) • * #: º tºº)\!!Nºſſilſſſſſſſſſſſſſſſſſs ... . . . . ºrgsy Ǻ) ſcientº ... . OF THE UNIVER mºutlaw S 2-Tºsº, £ LIBRARYº: = Ne º ITITIT : ; ſ ; f ! & //#: Pºe - º: X- ººº |º º- : -- . , - - - , ſ —- . ** * * * * * > . . - º - - - ** mº-au-- ºrſº :AU ºy Jºãº --> w-wv-º-º: |%. , COLLEGE ºl i SX §: | OF º # f § ENGINEERING |º º ºil . . . sºs; º - ---------—— §§§ iſſiſſilſilliſ IIIHRHº: ź. IT - r At 3 Q. { º º-º-º-º-º-º-º- lºº ºl ** = ºr -º-º-º-º-º-º-º-º-º-º-º: (fºliºisºtºriºiºiſºnſ: |- d i : | . 22/7) , 4/4 /7/8. [] [] . D D [...] D HEAVY (COAST) ARTILLERY (REVISED) COMPILED BY MAJOR, WALTON C. CLARK, C, A. U.S. COAST ARTILLERY SCHOOL Sº . FORT MONROE, VIRGINIA [T]| [] [...] [T] [] [T]|| s N*.* s *-: COAST ARTILLERY SCHOOL FoRT MoMROE, WA. OCTOBER, 1918. This book, prepared under the immediate supervision of the Commandant, is published for use as a text in the Coast Artillery School and in the Universities giving preliminary military training. Care also has been taken to arrange in convenient form for field use the information necessary for making the topographical preparation for heavy artillery. Valuable assistance in the preparation of this text has been rendered by the staff of instructors on duty at the Coast Artillery School. The personal interest shown by these in: structors in contributing articles, in criticizing and correcting the work of the compiler has made it possible to publish this text in its present form. By order of Lt. Col. R. R. WELSHIMER, C. A.; C. L. KILBURN, Major-C. A. Secretary. == ºfºº gº ºf Tº ** rº ... “. .* _." -: F; 2”. *...* seed"-F *...* …ºf HIS BOOK may be purchased from the Jo URNAL OF THE UNITED STATES ARTILLERY, Fort Monroe, Virginia, at 75 cents per copy, postage prepaid. TABLE OF CONTENTS Page INTRODUCTION. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . YI & * CHAPTER I ELEMENTS OF Topography 1. Maps. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 2. Scales. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 3. Contours. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4. 4. Slope Scales. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 12 5. Profiles. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 14 6. Conventional Signs. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 16 CHAPTER II CARToGRAPHY of FRENCH MAPs 1. Map Projections. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 23 2. Coordinates and Quadrillage.... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 38 3. Geodetic Triangulation. . . . . . . . . . . . . . . . . . . . . . . . . . . tº dº tº e g º ºs e º ſº g g g º º º 46 4. Battle Maps. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 49 CHAPTER III ANGULAR MEASUREMENTS 1. Units of Angular Measure...... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 56 2. Direction of Lines . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 57 3. Instruments for Measuring Angles. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 58 * Verniers. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 70 5. Measuring Angles by Repitition. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 74 CHAPTER IV ADJUSTMENTS OF TRANSIT 1. Plate Levels. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 79 2. Crosswires. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 80 3. Line of Sight . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 81 4. Horizontal Axis. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 83 5. Telescope Level. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 83 6. Vertical Circle. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 86 CHAPTER V LINEAR MEASUREMENTS 1. Units of Linear Measure . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 88 ; Methods of Approximate Measurements . . . . . . . . . . . . . . . . . . . . . . . . . . . ; Stadia . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4. Steel Tape . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 97 5. Triangulation. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 101 VIII TABLE OF CONTENTS ii i i ; ; CHAPTER VI PLANE TABLE Page Materiel . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 105 Orientation....... . . . . . . * . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 108 Traverse. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 110 Intersection... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 112 Resection. . . . . . . . . . . . . . . . . . . . * c e s e e s a s a s e s e s e s s e s e a e s • e º e s e s s e s e 113 e W CHAPTER VII LEVELING Definitions. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 120 Map Leveling. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 121 Barometric Leveling. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 122 Trigonometric Leveling.... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 123 Spirit Leveling. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 126 TTOTS. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 129 CHAPTER VIII MERIDIAN DETERMINATION Mechanical Solutions.... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 131 Elements of Astronomy and Time. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 133 Observation on the Sun.... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 140 Observation on Polaris...... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 147 Observation on a Star at Equal Altitudes. . . . . . . . . . . . . . . . . . . . . . . . . . . 155 Observation on Known Terrestrial Points. . . . . . . . . . . . . . . . . . . . . . . . . . . 156 CHAPTER IX TRANSIT TRAVERSE t Methods of Running Traverses. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 161 Forms of Field Notes..... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 167 Computations. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 172 Adjustments of Coordinates and Altitudes. . . . . . . . . . ‘. . . . . . . . . . . . . . . . . 178 Plotting the Traverse. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 180 CHAPTER X INTERSECTION Reduction to Center and Swing..... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 182 U. S. Method of Intersection... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 185 French Method of Intersection... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 188 CHAPTER, XI RESECTION Trigonometric Solution. . . . . . . . . . . . . . . . . . . . . . . . . . . g tº tº º te º 'º º e º ſº º ſº gº tº º 194 U. S. Method. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 198 Relevement. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 202 N. TABLE OF CONTENTS IX i ; ii i CHAPTER XII Topographic RECONNAISSANCE Visible and Invisible Areas. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Determination of Defilade. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Maximum Range. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Minimum Range. ... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Dead Areas. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Charts Showing Possibilities of Fire. . . . . . . . . . . . . . . . . . . . . . . . . Summary. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . CHAPTER XIII THE FIRING BOARD Purpose. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Description. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Construction. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . CHAPTER XIV PANORAMIC SKETCHES Essential Features. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Annotations and Conventional Signs. . . . . . . . . . . . . . . . . . . . . . . . . Construction. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . CHAPTER, XV ORIENTATION FoR RAILWAY ARTILLERY Principles of Railroad Curves. . . . . . . . . . . . . . ". . . . . . . . . . . . . . . . . Types of Epis. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Surveys of Epis. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Graduation of a Curved Epi. . . . . . . . . . . . . . . . . . . . . . . . . . . . . g º º Resurvey of Old Tracks.... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . CHAPTER, XVI ERRORS IN MAPS AND FIELD WORK Tables. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . CHAPTER XVII DUTIES OF THE ORIENTATION OFFICER Survey Work. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Observation Service. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . INTRODUCTION During the early part of the war it was attempted to fire the heavy artillery by the more or less approximate methods that are used by the light field artillery in open warfare. The range and direction of the target were determined to a fair degree of accuracy, the effects of a few elements such as wind, drift and difference in altitude of gun and target were estimated, and the firing adjusted according to the fall of the shots. The system broke down. Ammunition was being wasted, much time lost, and targets were not destroyed. Extremely accurate methods of firing the heavy artillery had to be adopted, and now practically every condition that may appreciably affect the gun or powder charge or the projectile in its flight is accounted for in calculating the data for aiming and laying the gun. The heavy artillery batteries are always located several kilometers behind the first lines and frequently in defiladed positions. Rarely, if ever, is a target visible from the gun, and distances, directions and altitudes are determined by precise topographic methods before the ballistic data for laying the gun can be computed. The procedure of making the topographic determinations is now referred to as orientation. The methods of making these determinations are similar to those employed in making the initial surveys before mounting a heavy Seacoast battery of guns or mortars. The surveying instruments used are essentially the same and the only difference in methods is due to the unusual conditions brought about by the present type of warfare. In the use of heavy artillery in land warfare ranges and directions must be determined with precision. Maps play an important part in this work. When a battery is execut- ing map firing, its position and that of its target must be accurately known in order to calculate ranges and directions. The location of targets on the map is, in general, the duty of other branches of the service, but the location of the batteries, and their observation stations, is the duty of the artillery itself, as is also the computation of ranges and directions. Because of the high cost of ammunition and the rapid ero- XII INTRODUCTION & sion of the guns, an accurate execution of the preliminary topographic work is essential for the heavy artillery. It is not considered accurate until its errors are negligible com- pared to those which are unavoidable, i.e., the dispersion and the errors in the ballistic corrections, especially those due to indeterminate atmospheric conditions. Erroneous topo- graphic preparation may cause the shots to fall so far from the target that aerial and terrestrial observers fail to see them, thus making correct ranging and adjustment impossible. In any event, there has been a waste of time and ammunition. The question of time is very important, for unless the bat- tery’s object is attained quickly the enemy's fire is likely to drive back the aeroplane that is spotting the shots or to begin to take effect on the battery itself, causing casualties in the gun crews, driving them to their dugouts, and possibly destroying the guns. When the opposing trenches are close together erratic shots during adjustment may cause shells to fall among friendly troops, and though the casualties may be slight, nothing is more harmful to the infantry's morale than to be fired upon by their own artillery. If an attempt is made to improve an inaccurate topographic preparation by keeping in mind during future firings the cor- rections which had to be made during the first firing, it is possible that all the unavoidable errors made in the estimation of atmospheric conditions for the first firing and the position of the first target will creep in. To correct the topographic preparation by means of observation during the first firing will result, therefore, in errors for each succeeding firing. For a battery of several pieces the preparation for effective fire includes the formation of a sheaf of fire, which sheaf may be parallel, convergent or divergent. The different pieces of the same battery have peculiarities which are unfortunately difficult to determine with precision, such as the wear of the piece, causing irregularities, especially in the range, which are very important and which vary. The ballistic agreement of guns in the same battery is a very delicate thing which has never been perfectly solved. During the regulation of fire with several pieces, in addition to the adjustment of the group, there will always be small corrections which must be given to the different pieces for the purpose of bringing into coinci- dence their zones of dispersion. The positions of the dif- ferent guns in the battery with reference to their directing piece must therefore be determined with great accuracy, in INTRODUCTION XIII order to make it certain that any lack of agreement observed during fire does not result from a topographic error. Know- ing the topographic work to be accurate, any variations in the zones of dispersion will be correctly attributed to pecu- liarities of the piece, and corrections made accordingly. Besides having to guard against errors, the battery officer must always possess dependable checks which will eliminate the possibility of costly blunders. In general every result must be verified. All determinations must be made by two distinct and independent procedures which may have unequal precision, the less exact serving as an approximate control of the other. Each battalion of the heavy artillery has an “Orientation Officer,” sometimes called a “Survey Officer,” who is in charge of this topographic work. Under their usual civil meanings, the latter is the better title, but on the Western Front the meaning of “Orientation” has broadened, so that it now includes not only the determination of directions but, also all surveying work, and the study and use of the terrain. Therefore, “Orientation Officer” is the better title for the position, and will be used herein. - Normally the Orientation Officer performs certain fairly definite duties: He determines the locations and altitude of gun positions and observation stations, the directions (Y-azimuths) of aiming lines, and secures all orientation or topographic data related or incidental thereto. However, like the normal atmospheric conditions assumed in range tables, this normal condition rarely exists, and all battery officers—lieutenants as well as captains—must be prepared to perform any or all of this work. In a way, an orientation officer can be compared to a resident engineer in charge of construction work. He is an executive, who must plan, Supervise and check the work of locating the required points, lines, levels and directions, having various survey parties, computers and draftsmen to perform the detailed work. To train enlisted men to do this work properly, an Orientation officer must understand it even more clearly than would be necessary merely to perform the work himself. He must also understand maps, their projections, construction, tri- angulation systems, use, meaning and accuracy; Surveying instruments and methods; plotting, drafting and sketching; elementary astronomy and its uses and finally, their appli- cation to the problems of the heavy artillery. Suppose you are directed to emplace one gun on the lawn XIV INTRODUCTION in front of the Hotel Chamberlin and open fire on the Post Office in Newport News. Before you can make the ballistic calculations which are explained in “Gunnery for Heavy Artillery,” it is necessary for you to make certain topographic preparations for fire. What do you do? Briefly, you pro- ceed as follows: (1) Examine the map (Battle Map) and determine the coordinates of the Post Office and the approxi- mate distance to it. (2) Examine the range table and deter- mine the approximate angle of elevation necessary for a pro- jectile to hit the Post Office. (3) Select a position for the battery far enough from the Hotel so there will be no ques- tion, under any condition, but that a projectile will clear it. (4) Determine the coordinates of the gun position by topo- graphic methods. (5) Similarly determine the coordinates of the Fort Flag Pole, which you select as an aiming point. (6) From the coordinates of the gun and of the target, compute the distance and direction to the target. (7) From the coor- dinates of the gun and aiming point, compute the direction to the aiming point. (8) Determine the coordinates of one or more observing stations and the distances and directions from them to the Post Office. (9) If time permits, verify one of the directions so obtained by an astronomic observation. You now have not only the distance and accurate direction to the Post Office, but also the data for pointing the gun at it. These operations may at first be confusing and seem intan- gible. Therefore, it is the purpose of this book not only to explain them in detail, but also to give in a clear and con- cise form all the information necessary either for an orientation or a battery officer to solve the various problems of orienta- tion that may arise in connection with a battery of heavy artillery executing map firing. The use, care and adjustments of surveying instruments are explained in detail, together with the latest approved methods of making computations from field data. The con- struction and use of maps are discussed at length, with an explanation of the application of coordinates and quadrillage to heavy artillery problems. Typical examples are worked out in full, illustrating the different methods of computation, and every effort has been made to present the subject matter in a manner that will be intelligible to an officer who has had no training in civil engineering and whose knowledge of mathematics includes only algebra, geometry and plane trigonometry. INTRODUCTION XV IIST OF BOOKS CONSULTED “Topography, Map Reading and Reconnaissance.”—Spalding. “Plane Surveying.”—Tracy. “Engineers' Pocket Book.”—Trautwine. “Theory and Practice of Surveying.”—Johnson. “Topographical Surveying and Sketching.”—Rees. “Elements of Astronomy.”—Hosmer. “Military Topography.”—Sherrill. “Engineer Field Manual.”—Leach. “Lambert Conformal Conic Projection.”—Deetz. “Encyclopedia Britannica.” “Manual Artillery Orientation Officer.” Bulletins published by the Army Heavy Artillery School in France. Pamphlets published by the Army War College. CHAPTER I ELEMENTS OF TOPOGRAPHY MAPs SCALES CONTOURS SLOPE SCALES PROFILES CoNVENTIONAL SIGN's i 1. MAPs A map is a graphic representation of a portion of the earth’s surface. All maps are plans, showing on a reduced scale, but in their true locations, the principal plane features of the area covered, such as roads, railroads, towns, buildings, rivers and lakes. Many maps, especially military maps, are more than plans; they show also the topographic features, hills, valleys, ridges and plains, and their elevations; all objects being shown in their true relations in regard to elevation as well as location. Further, the word map, as normally used, conveys an impres- sion of accuracy and completeness. A sketch, on the other hand, is usually a rough map of an area, inaccurate, incom- plete, and rapidly made. Because a map is a plan, it must have a scale, that scale being the ratio between distances on the map and the corre- Sponding horizontal distances on the ground. As that ratio is constant for all parts of the map, it necessarily follows that any figure on the map, a triangle for example, is similar to the corresponding figure on the ground; therefore an angle between any two lines on the map is equal to the corresponding angle on the ground. In order to show topographic features as well, elevations must be indicated in some manner, usually by Čontours. In order to indicate the nature of the terrain (buildings, woods, roads, swamps and other local conditions) conventional signs are used, the appearance of the sign usually Suggesting the object it represents. This chapter deals with map scales, the methods of indi- cating topography, and conventional signs. Although it refers particularly to French Battle Maps on the Metric System, the Same principles apply to all maps, and once the student grasps 2 ORIENTATION FOR HEAVY (COAST) ARTILLERY them he will understand American as well as French maps. NOTE: For a description of the Metric System see the beginning of Chapter V. 2. SCALES Horizontal Distances.—In surveying, all distances are measured in two planes only, horizontal and vertical. Any distances not so measured are reduced to the corresponding horizontal and vertical distances. Therefore, in plotting points on a map or in Scaling distances therefrom, only hori- zontal distances, and in plotting contours or determining differences in elevations therefrom, only vertical distances need be considered. Map Scales.—If a map was made full size, i.e., if one meter on the map represented one meter on the ground, every detail on the ground could be shown on the map—every pebble on a beach and every brick in a pavement—but such a map would be worthless. Minute detail is of no value. Only important features need be shown, and to be of value a map must show a large area on a small sheet. Therefore maps are on a reduced scale. One meter on the map represents many meters on the ground. The scale of a map depends on the amount of detail that must be shown, and that in turn depends on the purpose of the map. A map of the United States cannot give the detail that a map of Virginia can. A map can show only the general features, and a map draftsman must clearly understand the purpose for which the map is to be used before he can properly select the data that should be shown. If too much detail is shown the map becomes “cluttered up,” hard to read, and loses much of its usefulness. On the French Battle Maps it was necessary to show considerable detail. Therefore, the scales are large. For infantry, interested in only a small area, a large amount of detail (trench traverses, machine gun em- placements, etc.) is necessary, while heavy artillery is only interested in the principal features of larger areas. Therefore, the battle maps are on several different scales. Representative Fraction.—The ratio of a distance on the map to the corresponding distance on the ground, which is the scale of the map, is usually expressed as a fraction, Map Distance . no Distance’ called the Representative Fraction (R.F.), It is a purely abstract quantity, no particular unit of meas- ELEMENTS OF TOPOGRAPHY 3 urement being implied, and the numerator is usually ex- pressed as unity. For example, if the R.F. is 1/10,000, it means that one unit on the map represents 10,000 similar units on the ground, regardless of what that unit may be. This same relation between Map Distance and Ground Dis- tance may also be expressed as a ratio, 1: 10,000. One inch on the map would represent 10,000 inches on the ground, or one meter on the map would represent 10,000 meters on the ground. For example, the Battle Maps used by French combatant troops have Representative Fractions of 1/5,000, 1/10,000, and 1/20,000, the first being used mostly by infantry and the last two mostly by artillery. The maps used by the Army staffs are, of course, smaller in scale and larger in area, their R.Fs. being 1/50,000, 1/80,000, 1/100,000, 1/200,000, and even smaller. The Representative Fraction of the Goast Artillery Plotting Board is 1/10,800, and those of most U. S. Geologica Survey maps are 1/62,500 and 1/125,000, which gives an idea of the scales of French Maps as compared with maps fre- quently used in this country. Use of the R.F.—By means of the Representative Fraction, which is given on the border of all French Battle Maps, the distance on the ground representated by any distance on the map, or vice versa, can be computed. For example: Given R.F. = 1/10,000. Required, the distance on the map that represents 1 km. on the ground. - 1/10,000 =Xm/1,000 m, X=0.1 meter = 10 cm. That is, 10 cm. on the map represents 1 km. on the ground. Given R.F. = 1/20,000 and a map distance of 5 cm. Required, the distance on the ground that this represents. 1/20,000 =5 cm./X cm., X=5x20,000 cm. = 1 km. That is, 5 cm. on the map represents 1 km. on the ground. Scaling distances off a map, with a ruler graduated in centimeters, is very simple if the ground distance represented by one centimeter on the map is known. This can be quickly found from the R.F., viz.: 1/ 5,000 = 1 cm./X cm. X = 5,000 cm., or 1 cm. = 50 m. 1/10,000 = 1 cm./X cm. X = 10,000 cm., or 1 cm. = 100 m. 1/20,000 = 1 cm./X cm. X=20,000 cm., or 1 cm. =200 m. Graphic Scales.—These relations are very simple, and by their use distances can be scaled from any battle map very quickly. If a ruler graduated in centimeters is used, the distance must be mentally multiplied by 50, 100, 200, etc., according to the scale of the map. It is simpler, however, to use a centimeter scale with the units marked according to the 4 ORIENTATION FOR HEAVY (COAST) ARTILLERY ground distances in meters that they represent. Fig. I shows Several centimeter scales marked in that manner. Such a scale is called a graphic scale. Technically it is a map reading graphic scale because it is used in reading maps. Map making graphic scales, graduated in meters, paces, strides, wheel revolutions of other units used in measuring ground distances are discussed on the chapter on “Plane Table.” — / 2 3 4 5 6 7 8 9 A4/V/AAZS OF AZZAAS Sco/e //0000. F- F |--|-- — |--|--|--|--|- 2 42 6 8 /O /2 /4 v /6 /9 ////VCAAZZS OF AZ7A/PS Scaſe /: 20000 ſ | | | | | | | | | | | | | i l | | 4 CŞ' /2 /6 20 24 28 J2 Jó A/VOAA/X5 OF AZA 74/75 Sco/e /:20000 Fig. I.-SCALES FOR FRENCH BATTLE MAPS Most American maps have graphic scales printed on their borders, but French maps often do not, probably because the relation between map distances and ground distances is so simple in the metric system. If a graphic scale is printed on the map, it should be used in preference to any other scale, because of possible shrinking or expansion of the map, which is apt to occur in printing or with climatic changes, and may amount to two per cent. For instance, a map distance which measured 10 cm. when the map was made may measure 10.1 cm. a year later in a dry, well-ventilated office, or 9.9 cm. in a damp, stuffy dugout. A scale printed on the map expands and contracts with the map, and its use avoids possible error. Furthermore, the use of a graphic scale avoids the trouble and possible error involved in computing ground distances by dividing map distances by the R.F. 3. CONTOURs. Elevations.—Thus far maps have been considered as plans only. But in addition to showing the relative locations of different points, many civil maps and all Military maps show also the relative elevations. ELEMENTS OF TOPOGRAPHY 5 Elevations are usually referred to mean sea level and if the elevation of a point is given as 75 m. it means 75 meters above sea level. In some places, however, for local convenience elevations are referred to a local datum plane. For instance, elevations in cities on the Great Lakes are usually referred to mean lake level. Common sense will usually show whether any given elevation refers to sea level or to a local datum plane. The elevations of certain important points, such as bench marks and hilltops, are usually printed on the map, but to print the elevations of a large number of points would result in a confused jumble of figures. Therefore, some other device is necessary. Methods of Indicating Topography. The topography or relief of an area must be shown. This can be done to scale in a relief map, such as the War Game Board, but ordinary maps are plane surfaces—sheets of paper— and the relief must be projected on to that plane surface. There are three common methods of indicating topography, viz.: 1. Color Shading. A wash in black or brown indicates elevations by the density of the coloring, higher points being lighter than lower. This method is often used on maps of countries or continents, but is seldom used on large scale land maps. It is also used on marine charts to indicate the depths of water in harbors and lakes, shallow water being colored a lighter blue than deep water. 2. Hachures.—In reality, hachures constitute a form of shading done with fine pen lines instead of washes. The lines or hachures run in the direction of the steepest slope (at right angles to contours). They are equally spaced but the hachures are heaviest where the slope is the steepest, being very fine lines where the slope is nearly level. They are seldom used because of the labor and expense involved, the difficulty in securing uniformity, the difficulty in determin- ing elevations from them, and the resulting subordination of all other details on the map. They are used on Battle - Maps in connection with contours to show cuts, fills or cliffs. They are used on some maps of Germany on a scale of 1/100,000. 3. Contours.-This is the accepted method for all modern maps and is undoubtedly the best system. A contour is an imaginary line on the Earth's surface all points of which are at the same elevation. They are the inter- Sections of a series of equally spaced imaginary horizontal 6 ORIENTATION FOR HEAVY (COAST) ARTILLERY planes with the surface of the Earth. More exactly, contours are the intersections of the surfaces of equally spaced concen- tric spheres with the surface of the Earth; but for small areas they can be considered as planes. These lines, projected downward onto the lowest plane (sea level) form a series of smooth closed curves, each contour being inside the one formed by the plane beneath it. This is illustrated in Fig. II, which Lºs L^ fe 23 : 2T i | ſ | ! | | | | | | ! | | | | | Fig. II.-CONTOUR PROJECTIONS shows a cone 25 meters high, with six planes spaced 5 meters apart cutting it, and a plane on which the intersections of the various planes with the cone have been projected. Ground forms are seldom as regular as this cone; therefore, contours are seldom regular curves. Except in a map of an island, the eleva- tions along the edges of a map are rarely constant; therefore only part of the contours close on the map, the others ending at the border line. The cone in Fig. II can be considered as an island, with all the contours closing on the map, but if the map covered only that part to the right of a line through the center, only part of the contours would close on the map. Ground contours are imaginary lines of constant elevation ELEMENTS OF TOPOGRAPHY 7 on the ground. Map contours are actual lines of constant elevation on the map, representing the corresponding lines on the ground. If a man walks along a contour line he neither goes up nor down hill, but always on a level. The surface of a quiet pond that has no outlet is practically level; therefore its shore line is a contour. If a man follows it in a clockwise direction he must turn to the left at every entering valley, walk up the valley until he heads the water line, cross the valley, turn to the right, and return on the other side of the valley, turning to the left again to pass around the spur that lies between that valley and the next. Thus his course will bend to the left at every inflowing drainage line, cross it and turn to the right to avoid leaving the level. If the water in that pond is at an elevation of 50 meters, the water line is the 50 meter contour. If the water level is raised 5 meters, the new water line will be the 55 meter contour. 2Ts / N / º \ / \ ſ o \ – > | N) L/ Fig. III.-RELATIONS BETWEEN SPACING OF CONTOURS AND GROUND FORMS Contour Interval.—The vertical distance between two adjacent contours (their difference in elevation) is called the contour interval. It is a whole number of meters—1, 5, 10 or 20—depending on the topography and the scale of the map, but it is constant on any one map. As Belgium is very flat, 1 meter contour can be shown on most 1/20,000 Belgian maps, 8 ORIENTATION FOR HEAVY (COAST) ARTILLERY but if 1 meter contours were shown on a 1/100,000 map, the map would be a confusing mass of contours; therefore on that map the contour interval is 10 meters. Most of the battle front in France is rolling country, and even on large scale maps the contour interval is rarely less than 5 meters. On a uniform slope the contours are equally spaced, and the contour spacing varies with the steepness of the slope; the steeper the slope, the closer the contours. Thus, the spacing of the contours is a measure of the steepness of the slope. This is illustrated in Fig. II. The slope of the cone is much steeper to the right of the vertex than it is to the left, and the contours are closer together on that side. Žºrž zºº * - ºzº º == - 22% ~ _^ º ſº §§ § § - …” ~2. …” z 2/7 2% .* 22 2. Tº º |l\\ º |\NS I -, * > 2 T-2 -2& - 22 °22 º aſſº - - / 222*2.22 mm& 2% W 22% º º z & § ޺. * t . § W WN \\ // % Minº |%\;\. \\ .44–4–4%º- º º Fig. IV.-CONTOUR SKETCH Following this idea a little further, on a dome shaped hill (one whose slopes are convex) the contours are closer together at the bottom than at the top, while on a peak (a hill whose ELEMENTS OF TOPOGRAPHY 9 slopes are concave) the contours are closer together at the top. (See Fig. III.) On a hill whose sides have a constant slope the spaces between the contours is uniform as shown in Fig. II. Thus the contours indicate not only elevations but also the shape or form of the ground. Critical Points.—The data for contours is usually obtained by plane table sketches and stadia, a rodman sometimes following a contour under the direction of the sketcher. Fre- quently, however, it is sufficient to locate the “breaks in grade,” i.e., find the elevation and locations of points where the slope of the ground changes. The contours can then be drawn in by interpolation. The breaks in grade determine the contours and are called “Critical Points.” For very accurate work, such as is required for calculation of quantities in a gravel pit, the area is gridironed by a system of lines 20 or 50 meters apart and elevations are taken at the intersections of these lines as well as at breaks in grade, the contours then being plotted by interpolation. Master Lines in Topography.—Practically all the ground forms existing on the earth today are the result of erosion, i.e., hills and valleys have been carved out by the action of running water. Because water courses have created the ground forms and the resulting contours, the drainage and ridge lines of an area form a system of masterlines, which once traced out and studied give a grasp of the main feature of topography that can be had in no other way. Moreover, if these master lines, and the critical points, are indicated on a sketch, the contours can be intelligently traced in with little error. \ Characteristics of Contours.—From the foregoing, several characteristics of contours that should be understood and remembered, can be summarized as follows: 1. All points on the same contour have the same elevations. 2. Contours follow the slopes of streams and valleys, forming a series of alternate Vs and Us, the Vs pointing up the valleys with their points at the stream crossings, and the Us outward around the hills between valleys. - 3. Between critical points slopes are nearly uniform and contours are equally spaced. 4. Every contour closes on itself, either within or beyond the limits of the map. 5. Every contour that closes on the map indicates either a summit or a depression. If there is no water in the depres- sion the contour is dotted. 10 ORIENTATION FOR HEAVY (COAST) ARTILLERY 6. Contours never cross each other except in the case of an overhanging cliff or cave, when there must be two distinct intersections. 7. On a uniform slope contours are equal distances apart. 8. On a plane surface contours are straight and parallel. 9. A contour is always at right angles to the steepest slope and crosses ridge lines at right angles. A X400 X 399 X 409 X423 447X 44.5 X, 3.03. 377 x4/3 423 × 423x Fig. V-STREAM LINES AND ELEVATIONS OF CRITICAL POINTS © NOTE.-On French Battle Maps occasional intermediate contours are shown in level areas at less than the ordinary contour or interval. Such intermediate contours are repre- sented by broken or dotted lines, and are often allowed to end without closing. Plotting Contours.-Contours can best be understood by actually plotting them on a sketch giving the drainage lines and critical points. Fig. V is such a sketch taken from a ELEMENTS OF TOPOGRAPHY 11. French 1/20,000 Battle Map. The area is about 2 km. square and the drainage lines and critical points are indicated. The contour interval is to be 5 meters. The first step is to interpolate between the critical points along the drainage and ridge lines, to locate the contours, remembering that along those lines the spacing should be equal, although near the sources of streams the spacing should be decreased because streams are usually steeper at their sources than elsewhere. 423 x ~ 423 × *e. N 4/3' * X Fig. VI.-PROBABLE SPACING OF CONTOURS INDICATED The next step is to draw in the contours between the points thus located, remembering that the contours should be smooth curves, forming a series of alternating Us and Ws, the Vs pointing up stream and outlining the valleys, the US pointing down stream and outlining the hills. Fig. VII shows the completed map, which was traced directly from a French Map. 12 ORIENTATION FOR HEAVY (COAST) ARTILLERY * A *...* * A 390 74 4.04 (e. - 430 X4/7 408X. xs .e. X *s 2.4% Fig. VII.-CoMPLETED MAP SHOWING 5M. CONTOURS 4. SLOPE SCALES Slopes.—As stated before, contours on a map express differences in elevation in the ground surfaces represented, and their horizontal spacing indicates the relative steepness of slopes. To artillery, slopes are very important because the slope of the ground in front of a battery may limit the angle of departure and the field of fire and protect the battery from hostile observation and hostile fire; and the slope of the ground in front of a target determines the value of its defilade or mask and may limit the angle of fall necessary to secure hits. There are three principal methods of expressing the slope of ground surfaces, viz.: 1. Degrees.—The degree of slope means the angle meas- ured in degrees between the plane of the slope and a horizontal plane. This method is seldom used in civil life, but is the standard method in armies. ELEMENTS OF TOPOGRAPHY 13 2. Gradient.—The gradient is the ratio between the vertical and horizontal distances, the former usually being given as unity. Thus a gradient of 1 on 8 means that the ground rises 1 meter vertically in each 8 meters of horizontal distance. This method is mostly used for the slopes of fills, cuts and steep banks. 3. Per Cent.—This is the number of units that the ground rises in a horizontal distance of 100 units, expressed as a per- centage. Thus in a 1.25 per cent. grade, the ground rises 1.25 meters in every 100 meters. This system is commonly used on roads and railroads. The following table compares these three methods for a few slopes; it is condensed from a table on page 16 of the “Engineer Field Manual.” Degree. . . . . . . . . . . . . . . 19 2° 3° 4° 5° 6° 70 Gradient. . . . . . . . . . . . . . . 1–57 || 1–29 || 1–19 || 1–14 || 1–11.4 || 1–9.5 || 1–8.1 Per Cent. . . . . . . . . . . . . . 1.74 || 3.49 || 5.24 || 6.99 || 8.75 | 10. 51 | 12.28 Slope Scales.—The distance between contours on a map is called the “Map Distance” (M.D.); the corresponding hori- zontal distance on the ground is called the “Horizontal Equiv- alent” (H.E.). The former is equal to the latter times the Representative Fraction, or M.D. = H.E.XR.F. The map distance varies inversely with the slope; the steeper the slope, the closer the contours and the less the map distance. A slope scale is a scale on which the map distance corresponding to various slopes have been laid off. With it the slope of the ground can readily be determined at any point. American military maps are provided with such scales, French maps are not. Construction of Slope Scales.—The gradient corresponding to a 1° slope is 1 on 57.3; because the natural cotangent of 1° is 57.3. In other words, a 1° slope rises 1 meter in 57.3 meters. For any vertical interval (V.I.) between contours, the horizontal equivalent on a 1° slope will be V.I. X57.3 and the corresponding map distance will be V.I. X57.3XR.F.; then M.D. (m.) =V.I. X57.3XR.F. M.D. (cm.) =V.I. X57.3×100XR.F. 1° slope = V.I. X5730 XR.F. For slopes up to 10 degrees it can be safely assumed that the gradient varies directly with the degree; i.e., if the degree * 14 ORIENTATION FOR HEAVY (COAST) ARTILLERY is doubled the gradient is doubled. Then the above formula, divided by the degree of slope, can be applied to any slope, viz.: M.D. (c V.I. X5730)× R.F. m.) = Degree of Slope As an illustration, compute the map distances for slopes up to 5° on a 1/20,000 Battle Map with 5 meter contours; then - 5730 X 5 × 1 M.D. (1°) == 1X20,000 = 1.43 CIOl. 2, 5730 × 5 × 1 M.D. (2 )=-jº--0.72 CII] . 1.43 M.D. (3° =-3--47 CII). 1.43 M.D. (4°) = -T = .36 cm. 1.43 M.D. (5°) = –E– = .28 cm. A map distance scale can now be made by laying out these distances successively on a straight line. (See Fig. VIII.) /o 2 ° 3 * 2° 5° ejº 7°.9 |Z / = -5/77 //op 5ca/e /i/3000 yo 3 o 5° zo /o 3 ° 3° zo V/-, 5/7 /v7.5 / 20,000 !//=/0/77 / 7.5/.40,000 Fig. VIII.—SLOPE SCALES Use of Slope Scales.—Such slope scales are of great use in determining quickly and roughly the slope of any road or hillside. The slope of a road may govern the battery’s ability to move over it, and the slope of a hill determines a target's defilade. It is important that artillery officers be able to construct and use these scales rapidly. The slope can be determined by shifting the slope scale over the contours until a space is found on the scale that equals the contour spacing on the map. The slope can then be read directly from th slope scale. . 5. PROFILEs. Another important use of contours and contoured maps is in the construction of profiles. For an exhaustive study of any sector with the view of picking battery positions, supply routes and observation stations it is necessary to construct profiles along the controlling lines of vision and fire, both from our positions and from known or suspected enemy positions and observation stations, for in this manner alone it is possible to ELEMENTS OF TOPOGRAPHY 15 determine the value of a battery defilade from all possible enemy positions, the effect of enemy defilades on our fire, the areas which it will be possible or impossible to reach from a tentative battery position and the value of possible observation stations. A profile may be explained thus: A vertical plane is passed into the Earth along the line of the desired profile. The irregular outline traced on this vertical plane by the surface of the Earth is the profile of this line. Knowing the scale of the map and the contour interval, such an outline can quickly be constructed on a sheet of cross section paper. The most convenient method is to use the same horizontal scale in plotting the profile that is used on the map. If the same scale were used in plotting vertical distances, however, the profile would probably be useless, because elevations are usually, so small compared to horizontal distances that most points would fall within the width of a pencil line. Further- more, there is no need of using the same scale for vertical as for horizontal distances, provided a single vertical scale is used for the entire length of any one profile. Hence, profiles are usually exaggerated vertically. This brings out the details of the ground much more clearly and facilitates the study of the terrain. Method of Construction.—Take a sheet of cross section paper or paper ruled with parallel horizontal lines. Choose a con- venient vertical scale. Suppose, for example, that each horizontal line on the paper is taken to represent a contour on the map. The vertical scale is then the ratio of the distance between the lines and the V.I. of the map. Mark each line with the elevation of the corresponding contour, from the lowest to the highest points which the profile is to include. ſºc w Lºs º: , ºr ..º §§§ #jºšSW/ Fig. IX.-CoNSTRUCTION OF A PROFILE FROM A CONTOURED MAP 16 ORIENTATION FOR HEAVY (COAST) ARTILLERY Place the edge of the paper along the line to be profiled on the map and make a mark on each line on the paper opposite each point where the corresponding contour crosses the line of the profile.(See Fig. IX.) Connect the points so marked in succession by a smooth curve. Note any features that might affect the shape of the curve, such as streams, roads, etc., or that might bear upon the purpose for which the profile is made. For example, if the problem is one of visibility, note trees and buildings that are situated along the lines of the profile. Limitations.—It is not necessary to draw a profile in order to determine visibility and similar questions. Simple mathe- matical principles are all that are required (see chapter on “Topographic Reconnaissance”), but a profile is often simpler and more convenient for any but very accurate work. How- ever, in working with profiles which are exaggerated vertically there is one limitation which must be remembered. Vertical angles, angles of slope, etc., cannot be measured on such a profile with a protractor, even if the angle so measured be divided by the number of times the vertical scale is exaggerated. In this case angles may be determined from their tangents. 6. ConVENTIONAL SIGNS In very large scale map (1 to 500 or 1 to 100), such as property maps in cities, it is possible to draw all objects to scale and indicate their character by printed notations, viz., “2- story frame house” or “brick pavement,” but on the scales used for Battle Maps such descriptions are not feasible and certain symbols called “Conventional Signs” are used. In general, these are nearly the same as the ones in common use on American maps, and their appearance usually indicates the objects they represent. The sheets of Conventional Signs attached hereto (Figs. X to XV) should be carefully studied and used as a reference when working with Battle Maps. In a general way the entire character of the terrain and the objects thereon are indicated by conventional signs, so that by merely studying the map it is possible to visualize the land- scape. Water is usually indicated in light black or blue; contours and elevations in light brown (burnt sienna); German military works in blue and French in red; details of troop dispositions in pencil marks, put on by the man using the map; woods, trees, fields, marshes, cultivated lands, etc., by char- ELEMENTS OF TOPOGRAPHY 17 acteristic symbols in black. It is not expected that the student memorize these symbols in detail, but after a few days’ use of the maps, should be able to read them rapidly. § l § s i Waſſo/A-007 H===== Co/75////c/ea/APO&/ H=== |Abor Aroad/ =============== |AW/7. Aroaza/ - - - - - - - - - - - - - - - C/ea/ea/A-7//? -------------- (77.7// --------------- |S/77/e 77.7-4. Cºs *::::: ZJoJ&/e 77.27CA. # =# 1572/07 — = mr- ./V2//o/Gaz/7e *H++++++++++++++ - &/o'7e 4% Aora/ Zarze Sºrea” t=}{=k= S/77.7//J/rea/77 ~39–35->e— A/7/7%/ø/A-o/7.75 (3) e= + ATP2/723, A&#ffl, J.T. , 4.ock Czz/7C/5 –JE Eh-r" r-r—r—r-r-r—r—r-r-ţ-r 52%. 2, We/ O 5/redºm A/277 °– /*700a24//a/70/ Zºo /&er *-*. -** *-* - -ms -*sº -* -> < re //7// _/TS-N /~l –L/N Aea/72 “O------O-----O-----O-----O-----O-----O-- l/00/797 A&M/7ce T-T-T + ---T-T-T----T T + ///e A-2/7ce — T---T – T – T – T – T A//a/7 CO7 Or m , A/77&z7A/77e/ %2 Wilſº Fig. X-CONVENTIONAL SIGNS PRINTED ON FRENCH BATTLE MAPS 18 ORIENTATION FOR HEAVY (COAST) ARTILLERY ; l ! *d s 7%z7%/7/07 *`s - | Z/25 tº ſº. AO/7/5 Wage - ... *sº | Sree/o/e O G) |Ways/ae + + Chape/ Ö Ö Cemerery. | W/767///// 26 & Wayer//// X'ſ Yºr 77/777/7/07 A/775 2^ Smokeszcks OC/?ee - Z/7/7s of Cº////Va/o/7 glūº l//765 - 6.72275 # Orcha/Osſºl 4 Aſr or A2/7e 777 - //002's :::::::: - AMºoresſed Areas É% _/so/ºrea/ 7/eas . . . . . . Ç.ź iii. * º, * - * , - Cor/ou/3 2.727A72pz7%/7 Zºozession Conrov cºs) * * * * Kºš . ..."--------- ğ. :::::::::::::::...s §: §iiişii; º &:. * * * * • * Jºnzºnes § ºš Jreeo S/606’s wºmmºn |A’ocky 5%pes $º ‘S LOUa/zy Fig. XI.-CONVENTIONAL SIGNS PRINTED ON FRENCH BATTLE MAPS ELEMENTS OF TOPOGRAPHY 19 /XAA/V5/VE WOAPAS. T ſ Aſom A^oſoziz/s ——ºf H+ Agozed. Wº Zoophoes “…”< ** | 3 a W///how? " __Tº_-T- § Commo/ſca/07–A/7C/oa/ ~~~ ES £/ -5°Cozzy --~~~ s, | Azom/ºporºs - ~~~~ § * A627.7076'a' ---------Tº-------" s § T/727 Aorozzo's ^ * º: š. §: ./727 Aſºooz's & § § &Am/.4/zoº/ 607 @ §| [comas H---- ////07/09003 ($ | /ø/2//s //0/A3 tºº § //24/7.77%.7727.5 XXXXXXXXXXX XXXX XXXX XXX § - A&//s eſc / She//º3 = E ETH § Observa/or Aasrs oob. Command/º3 =PC § */o/~///7e Cz7/2/3 o o O O 4. §§ //Z//72 &/75 A.M. Aſſy/767//owers & B. Lé's A'evo//77 &/727&CR 4.0%red/ºece a | $2 TAa/7ced///7e TTT Ž l § YS A/777-276/.25 ~/>- | S & 4 Cozz 77. A/7C/x/ =s_^^ § S 52C07&y 2^^_^ US LA/a/7&/7&7 7/270/725 / × --> Fig. XII.-ConventionAL SIGN's PRINTED ON FRENCH BATTLE MAPs 20 ORIENTATION FOR HEAVY (COAST) ARTILLERY *. Cross/a2 . k rtº sº f 772/7C/, /727.7// Sreas J//e/2/ D-3 Command'Aosys : AZ72/07 & Are/7e/ ſh 4/772a2 gº 42/3/07 º 24/7ZZZ (2025 º Aeſoarea/ Occa/yed - /7/277/ry Observ/77 Abşſs A A///€/y Observ///º3/3 Z\ A //ach/762 G./7 She/hers E-ſº zº’ 776/7ch/Morſø A/72%cemen/s (“‘ tºº 772//A2//e/y b-i- hºmºl 95/77./77 & t g, |/00mm à $ $3. § |/057/m. à i § /20/..ſ/ong) $ $ § |/334 à & $ /20C (5/70/7) É à — s (336 à à § 220/72/77 © © S § 270/7/7, \ |370mm 50eca/7Zºe’s (C&//7c,7) ife is A/777-A/C/a/7,57.7/.27 + Grø//7/27% [HTTH) Fig. XIII.-CONVENTIONAL SIGNS USED IN ALL INSCRIPTIONS PLACED BY HAND ON FRENCH BATTLE MAPS ELEMENTS OF TOPOGRAPHY 21 w Corſºye, § Grenadé's $ Jø/55/5/27ce 776/7c.h4/777&s § Wºſer 5%/es [5] 700&zz///7/27.7/* A72%//ſe/roºf ſco/pa/y tº Æð///07 Cyc/675 €º |Chasseurs: Com/oa/y Aa/7.7/o/7 *:Smaſ/Groupſ: Søon is Are?/near == TC.ompany * ** /24/ºx/o3%zoo. A Jecſons: 52.7ch/2% sº Army 72/ {Army 7%%2% of 27.7/ſhe º y 7%.7%h Zºzºmºroſ Army Coſos * 4%.e4.70%age sº * ſ320/oz AzzA ſºn 4077/77 Groº/o Azk Zond//72% fºr Czyże/Zoo, º %. Army %2. Azzy §-§..f. ; - i * Jºcſ%27 2.7% 'A37.7% //7/277//-y O5MI Æ/7772ers (8) T/S/Acheſon $ [s] SMA §|2nd/42/20, ($) § Æche/27 a.077/?oad/ y , (S), //opa//2 (8). /27.7% Jecſ/o/7 $5 P •9. |- AeavyArſ/2/2/k [ ] P Fig. XIV.-CONVENTIONAL SIGNS USED IN ALL INSCRIPTIONS PLACED BY HAND ON FRENCH BATTLE MAPS 22 ORIENTATION FOR HEAVY (COAST) ARTILLERY -*— •S § ſ/725///~af Ja/foº/ - §§ § {///2/2/ Aersonne/ El is CŞ •u A0/0/27% - #. ſAmbu/Znce + Z/ass/g,5%/07 PEFls § A632/ſa/Seaſon J//eſa/her Aſºzzy's ! § * A.Wacºon //05a EE Ævac //052 Jec. [= Ś |/reserve/ºrsoºne/ G) /ēserve/M&/e/2-Fºs |S LA/PS/2//on//o32 à 5.7%ry 7.77 *. - §: L.L AvX/a/y 777, A- IR § Ca///e/27//- //e/a/A&AEeſy rh- Command/og Genera/ . M Groºp of Arm/es - § 2nd Army |} § 5./Joy Serv/ce, 2nd/Army | ſpes * | *Armycozs VII X § 43rd//7/son (&f of Army Coas) ºn § 53/o/ Ød. ' ' ) . . ºn § 16.5% 5%aroſe /2/son Hº § |4% Cava/y/7/3/oz Es 25%//a/A/goog Fº 37& Cava/y&gade = Advanced/APase &eyond’AºA' T Aºmeof.../ 7/a/7 ſel- //cºmed//e/Wºoo; //eavyArſ/ºry D| Fig. XV.-CoNVENTIONAL SIGNS USED IN ALL INSCRIPTIONS PLACED BY HAND ON FRENCH BATTLE MAPſ; - - --- - |- º Carr *sovº … 0. º º, - *…* - - - º º +// º +4Flº –4–3o/ e - - - Boſſ, Nºſſ ºf º/ º,.\ |\ \ºl * - º - - º - º - - . - - - º - º -- fºll, / \\}|\, \º ºº:: º/a C º fe * ºSTT ---- \ - XX jº "A lºs º - - - º º - º - - - # | Wºr - : - º º - - ~ Vºz/ º º - - - º - - º º ºlºrseſ - 2 º F - |- - - on ſee AYºrbre º: - º - - - - - - - - 30 Rougeºisºnfº Łº £º - - - - - º - º/ º º 0ste/ ºrch --~~ º * - º - - . *Fºſº --- - __ - -- º - - - - - - - - | ---- - - - - - - boºk º - - ºf N º - |A| ſ/ - º 1832 - F- - - º A /95 196 - - - - Ž º ºne ºncase ſeas Zoº /9/7 - /98 – º – --> -- ºneº- execues /99 - - - Scale 1:20,000 - - Cº- ºte Les Cotes en Noir Sont celles du 80000- et nant n", ina. ... . . . . . . - - "N OF FRENCH BATTLE MAP Chemin des Dames Sector Aug. 17, 1917, G 1-32 196 G - *** Tº º 4-1-1 º: --- $55; - - 576 * \ . - sº On S32 - • º º *Chavig - º - Z ºš. - Sºe - - --- . à Malmaiso º ne I - eſ. - º: - wº º | - - ºf tº ºf - º ºr º: - - º - - * sº lº º º - - nth ſex % - - ſº Sans pair, Aſ. " -- - - % tegº - -- - - º:-3 - - -*. -- 2. 3 * Font Oger - . * 7%le Moulinet's, -º-º-º- ºr ºs -- -- - * * * - - - - - - - -º- -- - . - - - _ - - - --- - re- - - - -º- ſ º - - - - - - --- º -ºne-º - - *: Fº - º º -**** º - º º - Quadrillage kilométrique Système Lambert German Works in Blue 199 : sº- - - - tºº º - - -. - : - - … - º - - - - - * * * 76's - s --~~~ -- º -- - - -- - - - - - --- --- º - . - ----- -- {-\º ºi-º Tºsº *------- --- - - - - - . ------- º - º -- - -& - - º - --- º - - - n - - * Nº -- * - - -- M. - - * - ºs a º * - . . -- - - - - - ºv- - - - -B ºf º- ſº- º - - - a -- " - * - - - --- - -- - - | ?/. - - - - ** § º A 7. CHAPTER II CARTOGRAPHY OF FRENCH MAPS MAP PROJECTIONS COORDINATES AND QUADRILLAGE GEODETIC TRIANGULATION BATTLE MAPs : 1. MAP PROJECTIONS The use of heavy, long range artillery in trench warfare on the western front has required more detailed, accurate and larger scale maps than have heretofore been used by armies in the field. Artillery officers who may have to use them must have a clear understanding of maps, including the principles of map making and the accuracy to be expected from the various types. As the earth is a sphere (nearly) while a map is necessarily a plane surface, it is impossible to represent a portion (or all) of the Earth's surface correctly on a map. The various systems of attempting to do this are called “Map Pro- jections.” Those used in France are discussed herein. Form of the Earth.-The Earth is a slightly irregular oblate spheroid; i.e., itſis a figure formed by rotating an ellipse around its shorter axis. Because of its topography. (mountains, valleys, etc.) the surface of the Earth is slightly irregular, but for most practical purposes it can be considered a true oblate spheroid. The distance from the center of the Earth to the Equator is 6380 km.; to the Poles, 6359 km. The mean radius of the Earth is about 6371 km. Geographic Coordinates. English System.—For defining locations, the Earth's surface is gridironed by a system of Meridians of Longitude and Parallels of Latitude, the Longi- tude and Latitude of a point being called its Geographic Coordinates. Meridians of Longitude are imaginary lines on the Earth's surface cut by planes passing through its axis. In the English or sexagesimal system the initial Meridian or 0° Longitude passes through Greenwich Observatory, near London, and Longitude is measured from 0° to 180° both East and West according to the angle in the plane of the Equator between any meridian and the Greenwich Meridian. (See Fig. I.) 24 ORIENTATION FOR HEAVY (COAST) ARTIALERY The true or Geocentric Latitude of any point is the angle which a line from that point to the center of the Earth makes with the plane of the Equator. If that line is revolved around the axis of the Earth, maintaining a constant angle with the plane of the Equator, its path on the surface of the Earth forms (ºr©2/Vych) s Q Q 6 C29 - eff WN 90% H ------->|<------- 90%. <22e (20 O § ~záža ‘à, f Nº. 9 Pane of the Eguafor Aøne of any/ſer/a/a/7 “how/7/07/rude .5%an/g Zoffode. Fig. I.-GEOGRAPHIC COORDINATES, ENGLISH SYSTEM a Parallel of Latitude, which is parallel to the plane of the Equator. In the English system, true Latitude is considered and is measured from 0° at the Equator both North and South to 90° at each Pole. Each degree of Latitude and Longitude is divided into 60 minutes and each minute into 60 seconds. When finer measure- ments are desired each second is divided into tenths and hundredths. A nautical mile (Knot), 6080.7', is nearly equal to one minute of Latitude, or to one minute of Longitude at the Equator. As an illustration, the Geographic Coordinates of Fort Monroe are 37°–0' N. Lat. and 76°-18' W. Long. Because the Earth is not a true sphere, a line normal to its Surface passes through its center only at the Equator and the Poles. The angle which such a line makes with the plane of the Equator is called the “Geodetic Latitude.” It is always greater than true Latitude, the difference varying from 0 at the Equator and Poles to 11’–30" at 45°. (See Fig. II.) French System.—In France a slightly different system is used. The initial Meridian of Longitude (08) is the one through the Paris Observatory (2°–20–14" E), and Longitude is measured according to the centesimal system (the Quadrant CARTOC, RAPHY OF FIRENCH MAPS 25 (90°) being divided into 100 grades, each grade into 100 minutes and each minute into 100 seconds), from 08 to 2008, positively to the West, negatively to the East. Geodetic Latitude is used, being measured from 0° at the Equator to 100* at each Pole, positively to the North, negatively to the South. One kilometer is nearly equal to one centesimal minute of Latitude and to one minute of Longitude at the Equator. The exact value of a grade of Latitude is found from the formula, 27th/400. /VA’o/2 Geoce/77/7c Alaſ/77 Caſe A 2//a/or 2 Tſ Gcoºrd Alaſ/foae / - S.A’2/2 Fig. II.-GEODETIC AND GEOCENTRIC LATITUDES R is the radius of the Earth in kilometers. The value of one grade of Longitude at any Latitude is equal to its value at the Equator times the cosine of the Latitude. (See Fig. III.) w 27R Expressed as a formula it is, † X cos Lat. /*775 ///ºo/e 2: +/00% VSS . <2<> .9 '4%/2/or 07 —/007 MO Aze of 470.7%r 5/ow/y/on?” A272 of a/k/a/27 Show/27/0/0.7% Fig. III.-GEOGRAPHIC COORDINATES—FRENCH SYSTEM • 6 ORIENTATION FOR HEAVY (COAST) ARTILLERY Classes of Map Projections.—When a map is to be made of a portion of the Earth's surface, that curved surface (the Earth) must be represented on a plane surface (the map). There are many different methods of doing this, called “Map Projec- tions,” each of which has its own particular value for certain kinds of work. These can be divided into three general classes, VIZ. . I. Perspective Projections. II. Geometric Projections. III. Mathematical Projections. Perspective Projections.—In a perspective projection, points on the Earth's surface are projected on a plane by straight lines radiating from one point, the point of vision. That point may be infinity, at some stated distance outside the Earth, on the Earth's surface, or at its center. One type, the orthographic, with the point of vision at infinity, is simple to construct and gives a good general idea of a large area, but is very inaccurate. Maps of hemispheres are often made in this way. The sketches of the Earth in Figs. VI and VII are ortho- graphic projections. Another type, the stereographic, with the point of vision on the Earth's surface diametrically opposite the center of the area to be mapped, is accurate and conformal, but difficult to construct. A third type, the gnomic, with the point of vision at the Earth's center, represents all great circles as straight lines, but distorts distances and areas; it is much used for ocean charts. Geometric Projections.—In a geometric projection, points on the Earth's surface are projected on a plane, cone or cylinder, either tangent to or cutting the Earth (secant) according to some geometric law. These are simple to con- struct and for small areas are nearly correct. They are often used for maps of counties, states, and even countries. The polyconic projection, used for most parts of the U. S., and the polyhedral projection (described herein), used for many French maps, are of this class. Mathematical Projections.—In a mathematical projection points on the Earth's surface are plotted according to some mathematical equation, the projection being primarily based on a tangent plane, cone or cylinder. The Bonne and Lambert projections (described herein), used in France, and Mercator's projection, used for many navigation charts, are of this class. Choice of a System of Projection.—An area less than 10 miles square on the surface of the Earth is indistinguishable CARTOGRAPHY OF FRENCH MAPS 27 from a plane tangent at the center of the area; therefore, such an area can be considered as a plane surface; but for larger areas this assumption cannot be made. At the Equator the Meridians are parallel and a small area bounded by two Meridians and two Parallels is a rectangle; while at the Poles such an area is a triangle. Every system of Projection has an origin. That origin may be a point, a Parallel or a Meridian. At the origin the Projection will be true; leaving it, errors creep in. In any system of projection, angles, distances or areas, or all three, will be distorted away from the origin; only one can be preserved. Some systems are more accurate than others, but involve more labor and, consequently, more ex- pense. Therefore, the choice of a system of projection depends on the requirements of the map, and five factors must be con- sidered: - 1. The size of the area to be mapped. 2. Its location on the Earth. 3. Its shape, i.e., whether its greatest dimension is an E. and W. or N. and S. direction. 4. Whether angles, distances or areas should be preserved. 5. The accuracy desired. Theory of Projections.—In any system of projection it is sufficient to plot the Parallels and Meridians over the area involved until a fine network is constructed outlining sub-areas small enough to be considered as planes. With such a frame- work established, intervening topographic detail may be drawn as flat surfaces. Therefore, in describing any system of pro- jection only Meridians and Parallels need be considered. Lines tangent to Meridians and Parallels at the intersections are at right angles to each other. If angles are to be preserved this must also be true on the map, and further, any area on the map must be similar to the corresponding area on the ground. This is illustrated by Fig. IV: “A” represents a small area on the Earth between two Meridians and two Parallels; “B” represents the same area on a map, where angles between Meridians and Parallels have been preserved but where Par- allel distances have been distorted much more than Meridian distances. It is evident that angles between the dotted line and a Meridian in “B” are greater than those in “A”; thus all angles except those between Parallels and Meridians them- selves have been distorted. “C” represents the same area on a map such that Meridians and Parallels intersect at right angles and distances are distorted equally in all directions 28 ORIENTATION FOR HEAVY (COAST) ARTILLERY * N ſ A// SJ; A” (£ºva/Area) /D N ſ /// SS OC An’ - A Æ (527eº) (Conſa/B (Lamberſ;JTC A" réoreyer/5 a sma/ area Aeſheen 2 //e7775 & 2 Aara/e6 on he ground. A C/DA & / represe/ ſhe same area as Show, on various maps. A= /)3/ance abng Abra/e/3 on ground A. Some Zöf on Mø. //=/23//ze a 67.7//eſa/ans on 9/ot/d/M* same/Xsſ on M32 21-#-ZX%rſon / Aya/e6: Zſ-É? =/23/070, ſo Meridans. Comparkson of /Mao's (A, C/24 & / ) w/ſh Grovna (4) //e77 A. C A) Aſ O/7 Correcſ (2/2 _L/a/a/e/5 Correcſ Correcſ 24//5 f X/ 1 || 1% X/ of Z1 ſo A^ * A=A - > - Aeſh, Aya &/Mer: Correcſ | Correcy Ze. OC Corzecif Aa3/3 of Aºo/ec/fo/75 5/7//e 3 |Poſco/ Conſc Aro/ */7"º"A" refers fo aſsiance L Aaraſſeſs - > means "Greaſer//ia7+ K means "Zess fºam."— L means "Aerzena/colar fo" Fig. IV.--THEORY OF MAP PROJECTIONS (i.e., “C” is similar to “A”). Angles between the dotted lines and Meridians in “A” and “C” are equal; thus all angles have been preserved. If M and P are the Meridian and Parallel distances, respectively, on the Earth, M’ and P' the corresponding distances on the map, and A and A’ are the distortions in Parallel and Meridian distances, respectively, / / then: p = A and TVI ºf A' and comparing “A” and “C”:— P/ M7 P = M or A = A' Thus, if A = A' (i.e., if at any point the distortion is the same CARTOGRAPHY OF FRENCH MAPs 29 in all directions) small areas on the map are similar to the corresponding areas on the ground, and the map is “con- formal.” This condition can be exactly realized only for infinitely small areas, but because of the size of the Earth it can be practically realized for areas up to 10 miles Square, and the error is negligible for areas up to 100 miles square. That is the theory on which Lambert Projection, used for the new French Battle Maps, is based. - Referring again to Fig. IV, “D’’ represents the same area on a map such that Meridians and Parallels intersect at right angles, but distances along them are distorted inversely; i.e., one distance is increased in the same ratio that the other is * P’ M 1 decreased. Then comparing “A” and “D,” F= M, or A= W ‘. AXA' = 1 and PXM = P'XM'. Thus, if AXA' = 1, areas are preserved. This will be true even if Meridians and Parallels on the map do not intersect at right angles, providing that either the Parallels or the Meridians are parallel, and A and A’ are the distortions along, and at right angles to, the parallel sides of the trapezoid. (See “E” Fig. IV). This is the theory of Bonne Projection, used for the pre- war maps of France and Belgium and for many maps of countries in general use, and of the “Cylindrical Equal Area” projection, used for many maps of the World. The above is a brief summary of the theory of Map Pro- jection. We will now describe the three principal projections used on French maps, viz., the Polyhedral, Bonne and Lam- bert, discussing them in that order. Polyhedral Projection.—As stated before, a small area on the Earth's surface is nearly identical with the plane tangent at its center. This fact is the basis of the Polyhedral Pro- jection used by the French before the war for mapping areas around fortified towns. Meridians of Longitude and Parallels of Latitude divide the Earth into a series of curved isosceles trapezoids, because the Parallels are parallel to each other, the Meridian distance between two Parallels is the same at all Longitudes and at a given Latitude the convergence of all Meridians is the same. In the Polyhedral Projection each such small curved isosceles trapezoid on the Earth's surface is projected on to a plane tangent at its center. In effect this consists of assuming that the Earth is a polyhedron, instead of a spheroid (see Fig. V), and that its surface consists of a large number of facets, like a diamond. If these facets are small, 30 ORIENTATION FOR HEAVY (COAST) ARTILLERY Tº - Partial *Ea ulator \ W Development | The Earth Considered as a Polyhedron. *—S. Pole Fig. V.-POLYHEDRAL PROJECTION there is little distortion and a few adjacent maps can be used together without great error. However, for large areas, mapped as a whole or in Sections, the errors rapidly increase, and a different system must be used. For accurate Battle Maps of the large Zone of military operations in France a single unified system of projection, involving only minor errors, is necessary. In the U. S. most maps of cities and townships are really Polyhedral Projections. Bonne Projection.—A point at the center of the area to be mapped is taken as an origin. The slant height CD (see Fig. VI) of a cone tangent to the Earth at that Parallel is computed. It is CD = DW cot Lat., where DW is the length of a line normal to the surface of the 32 ORIENTATION FOR HEAVY (COAST) ARTILLERY Earth at that Parallel, from the surface to the Earth's axis (if the Earth were a sphere the line would pass through its center; as it is spheroid, the line intersects the axis below the center), and the Latitude is the Geodetic Latitude of the initial point. (In France the initial point is at 08 Long, and +50& Lat.) A straight line C'D' is drawn on the map to represent the initial Meridian. With C’ as a center and C/D' as a radius an arc is struck through D'. This represents the initial Parallel. On the initial Meridian distances are laid off equal to the true Meridian lengths between Parallels on the Earth’s surface (F'D', D'B', B'A', etc.) and through the points thus located arcs of concentric circles with centers at C’ are drawn. Those represent the successive Parallels of Latitude. On each of these concentric arcs true distances between Meridians on the Earth's surface at that Latitude are laid off, starting from the initial Meridian. Through the points thus located curves are drawn representing the Meridians. These converge at a point P’ which represents the North Pole. Thus distances are preserved intact along the initial Meridian and along all Parallels; also angles along the initial Meridian and initial Parallel, because along those two lines Meridians intersect Parallels at right angles and the distortion is the same in all directions (A = A' = 1). Further, areas are preserved, because at all points the radial distance between Parallels is correct. Therefore, AXA' = 1, and any area on the map is equal to the corresponding area on the Earth. For these reasons Bonne Projection is excellent for ordinary civil maps, where areas are of first importance, and for any map of a country having only a slight range in Longitude, such as Great Britain, Belgium, Japan or the northern parts of the present Western Front. The results obtained from the Poly- conic Projection, used for most maps of the U. S., are similar to those obtained from the Bonne Projection, but the methods of construction are radically different. One extreme of Bonne Projection is when a point on the Equator is taken as the origin, the tangent cone then becoming a cylinder tangent at the Equator, and the radius of the Par- allels becoming infinity. All Parallels then appear as parallel straight lines, their correct distances apart, the initial Meridian as a straight line at right angles thereto, and other Meridians as curves concave towards the initial Meridian, distances along all Parallels being correct. This is called the “Sinusoidal CARTOGRAPHY OF FRENCH MAPS 33 Projection” and is the basis of many maps of the Tropics in general use. The opposite extreme is when the Pole is taken as the origin, the tangent cone then becoming a plane tangent at the Pole, the Projection resembling the general case (Bonne) in appearance. This is one type of “Zenithal Equal Area Projection” and is the basis of many maps of the Arctics in general use. However, away from the initial Meridian or Parallel in the Bonne Projection, angles, and all distances except those along Parallels, are distorted, the distortion increasing with the distance from the initial Meridian. At the edges of the map of France, made on this Projection, the angular errors are 18' and the linear errors 1/379. These distortions are not negligible in artillery fire. Moreover, if these maps were extended into Western Germany, these errors would increase. Therefore, a large part of the Western Front has been re- mapped since the war began, using the Lambert Projection, which minimizes errors and permits accurate extension into Germany. Theory of Lambert Projection.—In this projection, as in the Bonne, a point at the center of the area to be mapped is taken as an origin, its Parallel and Meridian becoming the initial Parallel and initial Meridian of the Projection, and a cone with its vertex in the Earth's axis and tangent at the initial Parallel is the basis of the Projection. In a way points on the Earth are projected on a cone, but, according to a mathematical law rather than a geometric law. Meridians appear on the map as straight lines radiating from a common point (the vertex of the cone) and Parallels appear as arcs of circles concentric about the same point (imagine the cone to be “developed,” i.e., unrolled). Lambert Projection is conformal. As stated before, to attain this result, the distortion at any point must be the same in all directions. From this condition (that A = A') a formula is mathematically derived for the spacing of the Parallels. This formula is P= K (tan Z/2)h, where P is the radius of any Parallel on the map, Kan arbitrary constant, Z the co-Latitude 90°–Lat.) and h is the sine of the initial Latitude. Distances will be correct (1) along the initial Parallel, (2) along two Parallels or (3) they will not be correct along any Parallel, depending on the value given K. This can be vis- ualized as follows: In the first case the cone is tangent at the initial Parallel; in the second case the same cone has been 34 ORIENTATION FOR HEAVY (COAST) ARTILLERY pushed down, parallel to its original position until it cuts the Earth at two Parallels; and in the third case, it has been lifted up, parallel to its first position, until it does not touch the Earth at all. In the second case, if the value of K is so selected that one of the two Parallels is 9% of the map's range in Latitude below the Northern limit of the map, and the other 36 above the Southern limit, the linear distortion at the center of the map will equal that at the edges, distances at the center being less than the corresponding distances on the Earth and distances at the edges greater, the total linear distortion being minimized. The angle between Meridians on the map depends on the slope of the cone, or in other words, on the initial Parallel. It can readily be shown that the ratio of the angle between two Meridians on the map and their difference in Longitude is the sine of the initial Latitude (see Fig. VIII). This is the exponent “h” in the above formula. It can vary from zero to unity. At one limit (h+0) the cone becomes a cylinder tangent at the Equator and the Meridians and Parallels are straight lines at right angles to each other. This is Mercator Projection, one of the earliest devised and still invaluable for navigation. At the other limit (h = 1) the cone becomes a plane tangent at the Pole; the Meridians intersecting at angles equal to their differences in Longitude and the Parallels being complete concentric circles. This is one type of the Stereo- graphic Projection mentioned above. This formula, P= K (tan Z/2)*, can be converted into one that will give the distance of any Parallel from the initial Parallel, the new formula appearing as a series of terms, each term smaller than the previous one, the accuracy of the result depending on the number of terms considered. For the range of Latitude to be covered by the French maps only two terms 3 need be considered and the formula used is, B-B+; 2 where B is the Meridian distance from the initial Parallel to any other Parallel, B' the corresponding distance on the map, and R the mean radius of the Earth at the initial Parallel. French Maps on Lambert Projection.—For the new Battle Maps the origin was taken at a point whose Latitude is +55° and whose Longitude is —68. This is about midway North and South of the present battle front and about midway East and West between the present front and Central Germany. It is near Treves, Germany, which is on the Moselle just across the Luxemburg border. The value of h (h+sine of initial Latitude) CARTOGRAPHY OF FFENCEI MAPS - 35 is the sine 55* = 76. It was desired to have the maps extend in Latitude from +52 to +58 grades (+528 is in Central Switzer- land, +588 is in Northern Holland), therefore, the value 036 chosen for the factor K was 2037, which preserves distances along Parallels +538 and +57° one grade (1/6x64) above and below the Southern and Northern limits of the map, re- spectively. All distances used in constructing the framework of the map are multiplied by this factor, which amounts to 1 diminishing them by 2037. The slant height (CoDo) of a cone tangent at the initial Parallel is computed in the same manner as in the Bonne 1 Projection. (See Fig. VII.) This diminished by 2037 gives the slant height (CoDo) from the vertex to the initial Latitude of a second cone, parallel to the first, but cutting the Earth at the two selected Parallels. This is used as the radius of the initial Parallel on the map. A straight line, CoL)'o, equal to C'ol)'ois laid off on the map and with C'oas a center and Cºol)'o as a radius, an arc is drawn, representing the initial Parallel. Along this arc, distances between Meridians on the Earth's 1 surface at that Parallel, dimished by 2037, as explained above, are laid off, and through the points thus established radii are drawn representing the Meridians. Along the initial Meridian, distances between Parallels are laid off. These are computed 3 B by the formula B' = B+ dramentioned above, and are diminished 1 º by the factor 2037. Through the points thus established arcs of circles concentric at C/o are drawn, representing the Parallels. Angles.—All straight lines on the surface of the Earth are actually great circles (a great circle is the line made by the intersection of the Earth's surface with any plane through its center): all horizontal angles are measured between straight lines or great circles. To preserve angles, therefore, all great circles must appear in a projection as straight lines intersect- ing at their true angles. This result cannot be obtained, but in a conformal projection great circles appear as slight curves that for distances up to 100 km. can be regarded as straight lines with an angular error of less than a minute. 36 ORIENTATION FOR HEAVY (COAST) ARTILLERY Fig. VII.-LAMBERT PROJECTION CARTOGRAPHY OF FERENCH MAPS 37 Convergence of Meridians.—In the Lambert Projection the angle between any Meridian and the initial Meridian (Con- vergence of Meridians) is equal to the difference in Longitude times the sine of the initial Latitude and can be found by the formula (M–Mo) XsinLo, where M is the Meridian in ques- tion, Mo the initial Meridian (–68) and Lo the initial Lati- tude (+558). (See Fig. VIII.) Substituting constant values the formula becomes (M-H-68)X.76. Proof of Formula. ZACD = ZACB = Lo Z BAD = M — Mo Z BCD = cy AD = CDXSin Lo BD = ADX (M–Mo) (Circular Measure) = CDXSin Lox (M–Mo) (Circular Measure) BD = CDX.o. (Circular Measure) BD = CDX aſ a CDX (M–Mo) × Sin Lo o, = (M-Mo) XSin Lo– Convergence of Meridians iCº Fig. VIII.-CONVERGENCE OF MERIDIANS 38 ORIENTATION FOR HEAVY (COAST) ARTILLERY In the Bonne Projection the convergence of Meridians means the angle between the initial Meridian and a line tangent to the Meridian at the point in question. It is equal to the difference in Longitude times the sine of the Latitude of the point in question and can be expressed as (M–Mo) Xsin L. On Bonne Maps of France the initial Meridian is that of Paris (0%) and the formula becomes M sin L, where M is the Longitude and L the Latitude of the point in question. (See Fig. VI.) Results.-On Parallels +538 and +578 distances are correct; between them distances on the map are less than the corre- sponding distances on the Earth; and beyond them, greater, 1 . the maximum linear distortion being 2037. Thus for a belt 65 of Latitude in width (600 km.) the linear distortions are negligible (less than 0.05 per cent.); as the map is conformal, angular errors are inappreciable; areas are nearly correct; all the requirements for accuracy in artillery fire are met; and an excellent map is produced. - This projection can be extended indefinitely East and West without increasing the distortion, but if extended North or South, the errors in both distances and angles will be in- creased. The initial mathematics of a Lambert Projection (most of which has been omitted herein) is very complicated, which is probably the reason why it has been little used. The U. S. Coast and Geodetic Survey is now preparing a map on the Lambert Projection, extending from Duluth to Bagdad, and from Greenland to the West Indies. The whole Western Front is being mapped on the Lambert Projection as rapidly as possible. - - 2. COORDINATES AND QUADRILLAGE Rectangular Coordinates.—As stated before, Geographic Coordinates determine the location of points on the Earth's surface. From the Latitude and Longitude of two points (such as a battery and its target) the length and direction of a line joining them can be computed, but the computation is long and difficult. In a system of rectangular coordinates, however, CARTOGRAPHY OF FRENCH MAPS 39 if the abscissae (x) and ordinates (y) of two points are known, the determination of the length and direction of the line joining them requires only the solution of a right triangle. Therefore a system of rectangular coordinates has been placed on the Battle Maps. Coordinates.—The position of a point on a plane can be determined if the distances of the point from two intersecting reference lines are known. For simplicity the reference lines are drawn intersecting at right angles, the point of intersection being called the origin. The vertical reference line is known as the Y axis and the horizontal line as the X axis. The distances of a point from the two reference lines are known as the coordinates of the point. The X coordinate is always measured parallel to the X axis and the Y coordinate parallel to the Y axis. X coordinates are positive if measured to the right of the origin and negative if to the left. Y coordinates are positive if measured upwards above the X axis and negative if below the X axis. & The coordinates of A in Fig. IX are x and y, and the coor- dinates of B are x' and y'. If the coordinates of A had been given, the point could be plotted by measuring off a distance on the X axis from the origin equal to x, and at the point m erecting a perpendicular equal to y. The extremity of the perpendicular will be the point A. Example: Plot the point C, x coordinate = —8, y coordinate = —5. Since the x is minus it will be measured to the left and k will be located 8 units from the origin. Measure down on a perpendicular from k 5 units, since the y coordinate is —5, and C will be located at the extremity of this perpen- dicular. D is plotted with coordinates, x = —4 and y = +6; the coor- dinates of E are x = +2 and y = —8. If a coordinate is written without a sign it is understood to be plus. Points may also be plotted by measuring off the x coordinate on the X-axis and erecting a perpendicular at that point, and measuring off the y coordinate in the same manner and erecting a perpendicular; the intersection of the two perpendiculars will locate the point. Example: Plot the point D (x=A-4, y=6). Erect the perpendicular vL) 4 units to the left of the origin and the perpendicular wſ) 6 units above the origin. The perpen- diculars intersect at D, the point desired. Plotting a point when its distance and direction from given 40 ORIENTATION FOR HEAVY (COAST) ARTILLERY Y | •ºm sº ºme sºme sºme 42----|-l. ſ j" | |Sºf | & ºt | || | *- Hà* * *- * * *-* = <= <= *- a-mº sºm, sºme sm as sºme a- & | ſ ſ f | . X | { V/ W t 'O *—º | –– | l | | º | ! º C* * *E= * * * * * * *= ºms —H/, I_ Fig. IX.-RECTANGULAR COORDINATES point are known. Let A (x, y) be a given point and the length of the line AB and the angle 6 be given. Find the coordinates (x', y') of B. (See Fig. IX.) Bs and gn are perpendicular to the Y-axis and Br and fm are perpendicular to the X-axis. The angle 6 equals angle 6'. dx=Ag= AB sin 6 x = x +dx=x-HAB sin 9 dy = Af- AB cos 6 y' =y+ns =y+AB cos 6 If the coordinates of two points are known the length and direction of line connecting them can be determined. Let points A (x, y) and B (x', y') be given, find the length and direction of AB. Bf tan 0=Af Bf = rm =x' —x Af-ns =y'—y CARTOGRAPHY OF FRENCH MAPS - 41 x' —x therefore tan 6 = y’— From this formula 9 can be determined by looking up the / angle whose tangent is y’ —y in a trigonometric table of natural functions. The length of AB can be determined by the formulas: (1) AB = −. (Since ABcos 0-Af-y—y) COS 6 (2) AB = } — X (Since ABsin 6 = Bf = x'—x) Sln 6 (3) AB = V(x' –x)2+(y’—y)? Since AB is the hypothenuse of the right triangle ABf, AB = V(Bf)2+(Af)2, Bf-x'-x and Af-y’—y; therefore AB = V(x’—x)2+(y’—y)2. Kilometric Grid. Lambert Maps.-In order to locate points readily a system of rectangular coordinates has been placed on Battle Maps now in use on the Western Front. On the Lambert Maps the y-axis is the initial Meridian (–68), and the x-axis is a straight line perpendicular thereto at its inter- section with the initial Parallel (+55)*. (See Fig. X.) Thus the origin of the Projection is also the origin of the Quadrillage or Grid System, which simplifies the transformation of rec- tangular into Geographic Coordinates and vice versa. To avoid the use of negative coordinates the origin has been given certain arbitrary coordinates, viz.: x = 500,000 meters and y = 300,000 meters. If a and b are the distances of any point from the x and y axis respectively, its coordinates are x = 500,- 000 = a and y = 300,000 = b. Lines 1000 meters (1 km.) apart are ruled on the maps parallel to both axes. These form a “Rilometric Grid,” from which the coordinates of any point can readily be scaled on the maps, and vice versa, any point whose coordinates are known can be located on the maps. The coordinates of datum points (bench marks, towers, church spires, etc.) are found by triangulation to the nearest meter. Usually many of these datum points are indicated on each map, from which any other point can be accurately located. In some cases it is sufficiently accurate to locate places (towns) to the nearest kilometer; and in other cases it is sufficient to locate them to the nearest hectometer (100 meters). The large scale maps in common use do not extend over greater distances than 10 km. and the first two digits of 42 ORIENTATION FOR HEAVY (COAST) ARTILLERY Aong/foae -2 3 -4 , -5 -6? -7 , a -3, 70 !---L--- ; , | | | | | |_2: TT-4---H----|--|. ---J.------------f-269 i ; | ; - .# TT l º ſ º | I - ſ ; : ſº } | | | ! $ ; ; } | ; | ! }| ; TT1*------|-i- !-----L------4-57 500–1–Hºtte-H==#===4======4={------|--~~~~1 ; | ; | ! ! }}-T | | | | | i | | | | || § --- | ! ; ! : } . § 400++=#===#=======H---|--|-}===#====#29 Š J .# ! ; $ P : ſº S } r 0. | ſ B º | | Q ! ! § | ‘A | | ! . . ! | : Q) § 300+++----|--|3——|-|--|--|--|33 & - { - | - * § | | | | | | | | | | | | | S S * º | i yº ; : N. Nº. ſ | ſ | |} § { 3. YS ! } f ! ſº ! * II. º j § 200++---4----4-------------------|--|-54 & ; | | | | | t > | | [ f ; ; º ! ! * | & - ; | : | l, i | ſº ! § | {} 0. $ /06-#: - - t =; * * * I * --> h | --53 ; ; ; {T} } } $ | 1. , ſº r | : ſ $ ! ſ: | | ! | : ; ; ; ; ; ; ; ; ; ; ) * malf ºf . *- . #- ======== ===== == p-# —— ==5& A/lſ) 500 400 500 600 YQ0 A Codra/zoſºs in AZamefres Fig. X.-KILOMETRIC GRID FOR THE LAMBERT PROJECTION MAPS the hectometric coordinates can often be dropped when refer- ring to only one map. These various ways of expressing coordinates can best be illustrated by an example. Take point & 4 A” in Fig. X; - - Metric Kilometric Hectometric Hect. abbreviated x=234,117 234 2341 41 y =301,047 301 3010 10 The abbreviated Hectometric coordinates are usually written together, the first two digits being the x value and the last two the y value; i.e., in the above example, 4110. Lambert North (Grid North).-By Lambert North is meant the direction of a line parallel to the y-axis at any point. Thus, Lambert North is always parallel to the initial Meridian. The divergence of Lambert North from True North at any point is equal to the convergence of Meridians at that point and can be computed from the formula (M+68)X.76, mentioned above. At the initial Meridian (–64) Lambert North coin- CARTOGRAPHY OF FEENCH MAPS 43 cides with True North. West of the initial Meridian, Lam- bert North is West of True North. And East of the initial Meridian Lambert North is East of True North. On the Western Front the declination of the compass varies from about 8& West to about 15& West, which is greater than the divergence of Lambert North from True North. Therefore, Magnetic North is always West of both True North and Lambert North. The angle between Lambert North and any line is called the “Y-azimuth” of that line, and can readily be calculated from the coordinates of any two points on that line. The French measure it from Lambert North either clockwise or counter- clockwise, according to the instruments at hand. Americans will measure it from Lambert North clockwise only. Simi- larly, the azimuth of any line, as used in France, means the - angle between True North and that line (measured clockwise by the American forces). - Knowing the convergence of Meridians and the declination of the compass at any point, Y-azimuth can easily be calcu- lated from azimuth or magnetic bearings, and vice versa. Kilometric Grid on Bonne Maps of France.—This is similar to the grid on the Lambert maps, the origin of the grid being the origin of the projection (Long. 0s., Lat. --508) and the y-axis being the initial Meridian (08). In districts where both Bonne and Lambert maps are in use (i.e., at the edges of the area covered by the Lambert maps), the same point will have two different sets of coordinates, one set in each system, and confusion is apt to result unless great care is taken. Occa- sionally both grids are put on the same map. Use of Coordinates.—The locations of all points used by the artillery, gun emplacements, targets, aiming points, etc., are determined by their rectangular coordinates, from which the range and Y-azimuth of a target and the corresponding deflec- tion angles can be computed. As soon as a battery position or observing station has been selected its coordinates should be determined. The various methods used for this work are taken up in later chapters. In general only two problems arise for an artillery officer to Solve in using these coordinates, both of which require only the solution of a simple right triangle, viz.: First, from the coordinates of two points to find the length and direction of the line joining them; and second, vice versa, from the coor- dinates of one point and the length and direction of a line 44 ORIENTATION FOR HEAVY (COAST) ARTILLERY 72/k/e7° AX --ºf---|--|-- - * *m, sºme sº- - | -----|--- 220 N - | \ | \\ /Vo/-//7 | \ N TK. N- I \ § SA § | \ TS S. § | \ S. Q § | N. QN S. | \\ \ \ i 2/8 \ N. | \ | \\ | N N | N | \ AY \ | 2/6 \ I \ | \ | \ N | \ | \ | - N | \ | N N 2/4 N N i N | N V - Coo/a/ia7/es |X y ºf N &/reſy d/6650 2/2,600 N}; 7&ryer 6//500 220,750 S A 5550 7.550 N z 2/2 - NGVL’ Š § § § Fig. XI.-COMPUTATION OF RANGE AND Y-AZIMUTH joining it to an unknown point, to determine the coordinates of the unknown point. As stated before, the direction may be expressed in magnetic bearing, azimuth or Y-azimuth, which are interdependent at any one point, and it is essential that the relations between the three be clearly understood in order to change one into the other rapidly. (See chapter on “Angular Measurement.”) The two cases will be illustrated by examples. CARTOGRAPHY OF FERENCH MAPS 280 r— — — — — — — — — — — — — — — — — — —H - - -7arget | ! | | | 279 | | | | | ! | | | 276 : | | | | | | 274 | |--|< . * / Aoffery | - 85/650 7//€2/. 2 272 ºrrey : {\! N. WO § & § Fig. XII.-COMPUTATION OF COORDINATES OF TARGET 46 ORIENTATION FOR HEAVY (COAST) ARTILLERY First Ezample. (See Fig. XI.) Given:- x – Coordinate — y Battery 616,650 212,600 Target 611,300 220,150 - Difference 5,350 7,550 Required—Range and Y-azimuth of Target. 5350 Solution 35 - 7550 Tan v = 7550 Range = cos v. Log 5350=3.728354 Log 7550 =3.877947 Log 7550=3.877947 Log cos w =9.911644 Log tan v =9.850407 Log Range =3.966303 V = 35° 19' 20" Range =9254 m. Y-azimuth (v)=360°-v-360°–(35°19' 20")=324° 40'40". #5-? = —” + → = -FEB-1 + -===* Check:-Range AX Ay 5350 7550 Range = V28,622,500+57,002,500 =9254 m. Second Example. (See Fig. XII.) Given: Battery, x=851,650 y =272,350 Range =8682 m. Compass Bearing N 55.560 E Compass Declination = 222 Mils West Longitude = –138. Required: Coordinates and Y-azimuth of Target. - 222 Solution Declination=222 mils *T6 grades = 13.g.87 West, Convergence of Meridians = (M + § X.76 = (–135-H68)X.76 = 5.532 Angle between magnetic and Lambert North = 19.4:19 The point is east of Origin. Therefore, Lambert North is east of True North. The compass declination is west. Therefore, Magnetic North is west of True North. Magnetic North is also west of Lambert North: Therefore; Y-azimuth (V) =558.60–198.19 =368,41 = 32°46'8" Ax = Range Xsin W Ay = Range Xcos V Log Range =3.938620 Log Range =3.938620 Log sin W =9.733399–10 Log cos W =9.924724–10 Log Ax =3.672019 Log Ay =3.863344 Ax = 4699.15 Ay =7300.35 X y Battery 851,650 272,350 4,699 7,300 Target 856,349 279,650 v/Fº - Check: Range= Y4695+7306 = V/22,080,601 + 53,290,000 =8682 meters. 3. GEODETIC TRIANGULATION Geodetic Framework.-The system of projection having been determined upon and the Parallels and Meridians and Quad- rillage having been laid out, the next step in the construction of a map is to plot on this grid what is known as a Geodetic Framework. CARTOGRAPHY OF FRENCH MAPS 47 All maps of large areas are based on Some system of triangu- lation. Starting from one or more accurately measured base lines according to the size of the area, a network of triangles is laid out, whose sides vary from 10 to 200 kilometers in length. There are three different types of triangulation nets that are in standard use. (See Fig. XIII), viz.: (A) A series of approximately equilateral triangles. This is used when the survey is to extend over a long, narrow strip. (B) A series of central polygons, each with an interior station near its center. This is used for areas that are nearly Square. - (C) A series of quadrilaterals with both diagonals drawn in. This is used for wide areas and is the best system because it offers the greatest number of checks. - Triangulation Points.--Whatever system is adopted, a system of primary triangles is laid out so as to cover the entire area to be mapped. These are generally large, with sides from 15 to 200 kilometers in length. The angles at each vertex are measured with extreme accuracy—to decimals of a second— with accurate, large size transits, and the length of each side is calculated. Due to the curvature of the Earth such triangles usually have to be reduced to the equivalent plane triangles. Standard . Prºnoru Triangulation tiets. A €roup of Gºodrilaterals "Central Stations. with Diogonals. Fig. XIII,_TRIANGULATION NETs 48 ORIENTATION FOR HEAVY (COAST) ARTILLERY Each such vertex is called a “Primary Triangulation Point” and in France is located to within 0.3 meter. Its Geographic coordinates are found by astronomical observations. Based on these primary triangles a secondary system of smaller triangles is laid out (sides from 10 to 50 km. long) whose vertices are located by computations based on measure- ments of the angles and the computed lengths of sides in the primary triangles, with consequently less accuracy, but with a probable error of less than 0.5 meter. These are called “Secondary Triangulation Points.” On this secondary network of triangles is based a third system, the tertiary, whose sides vary from 5 to 30 kilometers in length and which are small enough to form a control for the Scolle in Kilometres C ) O 2C 5 o 4. O SO i:ſ Primary Net. —- — Secondloru Net. ... • * * * * * * Tertioru Net. Fig. XIV.-TYPICAL TRIANGULATION SYSTEM whole area. The vertices of the tertiary net are called “Ter- tiary Triangulation Points” and are located with a probable error of less than 1 meter. Fig. XIV shows a typical complete triangulation system. - Primary and Secondary Triangulation Points are usually marked with stone monuments on which the instruments can be set up and over which a flag signal can be placed. Some- CARTOGRAPHY OF FFENCH MAPS 49 times it is necessary to construct small towers over these points to secure the required range of vision, and for the longer sights heliographs replace flag signals. Sometimes tertiary points are also marked by monuments but more often they are distinct features of the landscape, such as church spires, chimneys, towers, and isolated trees. Frequently an instrument cannot be set up at such points and an “eccentric” point must be used for the transit. This does not affect the use of these points in resection, however. . Local Detail.—The metric coordinates in the Lambert System of all of these points are computed and used in plotting them on the maps. These coordinates are given in full in the lists of triangulation points that accompany each map. Trav- erses are usually run between tertiary points to locate roads, railroads, streams and benchmarks, while contours, buildings, cultivation and other detailed information is usually secured by plane table. As a result, the errors in the location of local detail may run as high as 10 meters, although, because of the scale of the map, such errors are negligible. For purposes of orientation in the field preference should be given first, to primary triangulation points; second, to secondary points; third, to tertiary points, and fourth, to local detail. Tertiary triangulation points are usually close together and there are several accessible or visible from nearly all points on the front. Local detail is often a valuable aid in rapidly finding a location on the map. 4. BATTLE MAPs Pre-war Maps.—At the beginning of the war the extensive use of large scale maps was not contemplated. There were several small scale maps of France, Belgium, and Western Germany, which were expected to be used by the French, British and Belgian armies as Staff maps in the direction of mobile operations. French General Staff Map.–Most important of these was the 1:80,000 French General Staff Map, which covered the whole of France and Alsace-Lorraine, though it had not been kept up to date in the latter provinces. It is based on the Bonne Projection with origin at +50s and the Paris Meridian. It was started early in the last century and required some 60 years for completion. Each sheet is 50 cm. X80 cm. in size, covering 40 km. X64 km. Geodetic points are fairly accurately 50 ORIENTATION FOR HEAVY (COAST) ARTILLERY located, but the error in other points may reach 100 meters. Elevations are shown by contours and hachures. This map is the basis of most of the pre-war maps of France, e.g., the 1:50,000 black and white and the 1:200,000 colored maps. Maps of Fortified Towns.—Another important series of French maps was the Battle Maps of the regions immediately about the French fortified towns. These are on scales of 1:10,000 and 1:20,000 and are fairly accurate. The Poly- hedral Projection is used. Contours show elevations. Maps of Belgium.—The basis of the pre-war military maps of Belgium was a set of 1:20,000 maps compiled from land-title (cadastral) plans, and verified and completed on the ground. Bonne Projection was used, the origin being +56° and the Brussels Meridian. Elevations are indicated by contours. From these were made up maps on the scales of 1:40,000 and 1:100,000. All these maps are only fairly accurate. Maps of Germany.—Most of Germany, including Alsace- Lorraine and the Rhine Provinces, was covered by a map on the scale of 1:100,000, made up from plane-table sheets of 1:25,000. The Polyhedral Projection is used. Relief is shown by contours and hachures. These maps are fairly accurate. Development of Battle Maps.--When the war assumed a more or less stationary character, it was found that accurate, large-scale maps were absolutely indispensable for the use of both infantry and artillery. Accordingly, as rapidly as possible there were prepared Battle Maps (French, “Plans Directeurs”) of the whole Western Front. The scales chosen by the French were 1:20,000, 1:10,000, and 1:5,000; by the English, 1:40,000, 1:20,000, and 1:10,000. These maps were based primarily on the small scale pre-war maps, but in order to get sufficient local detail and to increase the accuracy, every available source of material was used—maps and plans of roads, railroads, canals, private estates, tax assessors’ land- title maps (cadastral plans) of communes, etc. In addition, surveying parties were immediately put into the field, and countless aerial photographs were taken of the region near the front lines. - Revision of Battle Maps.-No sooner were the Battle Maps prepared than some change in the battle lines or in the detail of the terrain, due to artillery fire or mining operations, ren- dered them out of date. The accuracy of points and the number of trigonometrically located points must also be CAERTOGRAPHY OF FERENCH MAPS 51 constantly increased. This necessitates continual topographic work in the region of the front lines. So important and exten- sive has this work become that special units, called “Topo- graphical Sections,” have been organized in connection with each army and corps, whose chief duty is the preparation, revision, distribution and destruction of Battle Maps. Description of French Battle Maps.-The French Battle Maps are based upon the Lambert Projection, with origin near Treves, and have a kilometric Grid System, or Quadrillage, with the same origin, as described above. Relief is shown by contours with a Vertical Interval of (usually) 5 meters. Each map is dated to show the time to which it has been revised. For a description of the conventional signs, see Chapter I. In general, points of planimetric detail are accurate within 10 meters, though in regions taken directly from the General Staff Map, or in case of blunder, errors may be as large a 100 meters. Often there is a marginal plan on a map showing the sources of its various parts, as an aid in determining the accuracy of points within them. Areas, Detail and Typical Uses.—Most of the French Battle Maps on all three scales are issued on sheets of the same size—50 cm. by 80 cm. Therefore, the dimensions of the area covered vary inversely with the scale. - The detail shown also varies with the scale. The 1:20,000 maps usually cover an area 10 km. by 16 km., and show the German works, but none of the French, except sometimes the outline of the advanced line of trenches. The 1:10,000 cover 5 km. by 8 km. and show German works and the outline of the advanced line of French trenches. The 1:5,000 cover 2.5 km. by 4 km. and show German works and the first line French trenches. Oceasionally special maps are made up of different size and showing different detail. While there are many uses for each scale of Battle Map, it may be stated in general that the typical use of the 1:5,000 is for infantry attack, of the 1:10,000 for the light artillery, and of the 1:20,000 for heavy artillery. Lists of Points of the General Control.—Of equal importance with Battle Maps to heavy artillery officers are lists, also issued by the Topographical Sections, of the trigonometrically located points within each area. These lists, which are being con- tinually enlarged, give the metric rectangular coordinates and the altitude of all points whose locations have been determined with an accuracy comparable to that of geodetic triangulation 52 ORIENTATION FOR HEAVY (COAST) ARTILLERY points. Such points will usually appear on the latest Battle Maps, but their exact coordinates and elevations can be obtained only from these lists. As will appear later, accurate data concerning trigonometric points is absolutely essential to the correct determination of positions and altitudes and to the determination of direction by the method known as “Terrestrial Y-azimuth,” or “Wo.” (See Chapter VIII.) As these are the two most important topographical problems confronting a battery officer, the value of these lists can be readily seen. Other uses of them are the following: - 1. To increase the density of points of reference in the regions occupied by our batteries; as the original points of reference shown on the maps (steeples, windmills, isolated houses) are generally destroyed. Even the planimetric details of the map are not always sufficiently close together to serve as a basis for surveys which must be both simple and rapid. Furthermore, in the region of the first positions these plani- metric details may have disappeared more or less completely. 2. To serve as a basis in preparing an accurate system of reference points in the region of the enemy’s first line for use in firing on auxiliary targets, etc., and also to facilitate the organization of the fire of our artillery after its first rush forward following an attack—an extremely important matter. 3. To permit the checking of the map in certain parts where it might be in error because of changes that have occurred since the latest revision (outlines of woods, roads, etc.). Lists of Y-azimuths.—The Topographical Sections can also furnish lists of observed Y-azimuths and oriented “tours d’hor- izon,” which are used to orient the plane table of a traverse. British Maps.-In the maps of Northern France and Bel- gium used by the British those on a scale of 1:40,000 are the basis of a Grid System in yards. These maps are issued on sheets of the same size (50 cm. by 80 cm.) as the French Battle Maps and therefore cover an area 32 km. (east and west) by 20 km. (north and south). Each sheet is designated by a number. The metric coordination of each of the four corners are given on the map. Thus, “57,240 m.n.” means “57,240 meters north of origin.” The divergence of Lambert North from True North and the compass declination at the center of the map are also give on each sheet. (See Fig. XV.) These 1:40,000 maps are divided into quarters called N.E., N.W., S.W. and S.E., which are mapped separately on the CARTOGRAPHY OF FRENCH MAPS 53 57240/M/V, Sºğ /60,00/M 27] Š sº * ! S Š / | | 2 § §§ | ! S$ Š|S wº | QO S— — — — — — - - yy— — — — — — — — — — T- — — — — — — — — —WE---------- 3. | | 4. § ! | §k—-—-—--—-—23 —- —--—-—- ! ‘Vls | | | S / 2 | / | 2 SS c) | | | <-----—sº----------------sºsº asse sºme sº assº sºme sº-sº smº, sº | i | | 3. | 4. 3. | 4. | 1 | 57240/M/V Fig. XV.-BRITISH BATTLE MAPS WITH ORIGIN AT BRUSSELS scale of 1:20,000. Each of these in turn is divided into quar- ters, numbered 1, 2, 3 and 4, each of which is mapped sepa- rately on a scale of 1:10,000. Thus, all these sets of maps are the same size. In a way this system resembles the method of subdividing sections of land in the United States. British Grid in Yards.--To facilitate the determination of range in yards, the British superimposed a “Yard Grid” on their maps. It consists primarily of a system of rectangles 6000 yards square, centered on the center lines of the 1:40,000 maps (see Fig. XVI), on which there are 24 such rectangles, lettered from A to X. As the dimensions of the map in meters do not coincide with any even distances in yards, there is a slight overlap. On the East and West edges the overlap is negligible (6/.5), but the East and West tiers of rectangles are not full width, being only 5500 yards wide. On the North and South edges the overlap is greater (192'.4) and the upper and lower rows of rectangles are only 5000 yards long. Thus, only the 8 center rectangles (H, I, J, K, N, O, P and Q) are full size. Each of these large lettered rectangles is divided into 1000 yard squares, numbered from 1 to 36, as indicated in Fig. XVI. The upper and lower rows of lettered rectangles have only 30 such squares, and the East and West tiers of small squares are only 500 yards wide. Each 1000 yard square is divided into quarters, each 500 54 ORIENTATION FOR HEAVY (COAST) ARTILLERY Órla System —-—/% O//ne -------00/mes of 34*//yos Zoºgeſ/effered/Tecſon%25 øre 6000% $70,72 S/772//(W//776e/ed') Af * /OOO / A Fig. XVI.-BRITISH GRID on A 1:40,000 MAP -—-/772 007/725 — 67.75).376/77 ----500 Yarz$70,725 º s 300% - 42% Aecºg/25 (Cºoſa//eſ/+4–f—- /0 –=A /TV Fig. II.--THEORY OF STADIA MEASUREMENTS (HORIZONTAL) D+f-Hc. f--c is practically a constant and is usually taken as .3m with an ordinary transit telescope. To measure a LINEAR MEASUREMENTS 93 distance using a stadia rod and transit determine the intercept on the rod between the wires, multiply this by 100, and to the result add 1 foot, or 3 m. This rule applies only when the rod and the transit are on the same level. If the line of sight is inclined and the rod is held vertically a correction will have to be made to reduce the reading to the horizontal. amºm, ºsm, sº sºme sm- *-* *-* - S.23 zºrs" Fig. III.--THEORY OF STADIA MEASUREMENTS (INCLINED) In Fig. III let the line of sight be inclined at an angle, X. If the rod were held perpendicular to the line of sight the stadia reading mn would give the distance OE and this added to the constant c-H f would give the total distance from the center of the instrument to the rod. This could be reduced to the horizontal distance RS by multiplying RE, the total distance, by cos X, but it is not practical to incline the rod until it is perpendicular to the line of sight, the general practice being to hold it vertical. This introduces another error since it makes the reading AB longer than the true reading mn. The angle AEm= X and AmE is approximately a right angle, hence AB cos X=mn (very nearly). In other words, the distance actually read must be multiplied by cos X to obtain mn. RE=f-H c-H 100 mn=f-H c-H 100 (ABcos X) RS = RE COS X ..". RS=[f-H c-H 100 (ABcosX)] cos X. RS = (f-H c) (cos X)+100 AB cos^X, let f-H c = 1 Horizontal Distance = R.S. = COSX-H 100ABCOS*X. 94 ORIENTATION FOR HEAVY (COAST) ARTILLERY) 09 | 82° 8'İ , 90° 86 | 0Ī, Zſ IQ ( 86 || 0† - 0 I Ț6, 86 || 89° 8 †Z ° 66 | 96, 9 Igº 66 | 8Z , Q 82 ° 66 | 6ț¢ £ 33' 66 | # / ' I 16' 66 | 09 89 || $1, $I 80, 86 | #0. 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By referring to the figure it will be seen that the height of the instrument above the ground does not change the com- putations of the height H, between the two points on the ground. - Obviously, it would be laborious to perform the computa- tions indicated by the above formulae for each observation. Tables known as “Stadia Reduction Tables” are given below which greatly facilitate stadia computations. Their use is illustrated by an example. To Measure the Vertical Angle, X, proceed as follows: (a) Set up the transit and level it. Bring bubble in level tube underneath telescope to the center. (b) Mark the height of the center of the telescope, HI, above the station on the stadia rod by means of a rubber band. (c) With the rod on the point whose elevation is desired sight the telescope with the middle horizontal wire on the height of instrument, HI, marked by the rubber band. (d) Read the angle on the vertical limb. Use of the Reduction Table.—To the rod intercept add the equivalent of c (in metric units 0.3 m. is equivalent to 0.003 m. on the rod). Select the tabular quantities for the observed vertical angle, interpolating for odd minutes. Then the horizontal distance will be the horizontal tabular number mul- tiplied by the adjusted rod intercept; and the vertical distance will be the vertical tabular number multiplied by the adjusted rod intercept. By putting c into the rod intercept a slight error is introduced but since this error is exceedingly small it may be entirely neglected. The following example will illustrate the use of the Table: Rod Intercept 1.275 m. Adjusted rod intercept Vertical Angle 8° 25' 1.275–H0.003 = 1.278 For 8° 25' the Tabular Numbers are Hor. 97.86 Vert. 14.48 therefore Horizontal Distance = 97.86 × 1.278 = 125.1 Vertical Distance = 14.48X1.278 = 18.51 Horizontal distances are usually computed to the nearest decimeter and vertical distances to centimeters. LINEAR MEASUREMENTS 97 Practical Suggestions for Reading Stadia.—1. Examine the graduations on the stadia rod carefully before attempting to read intercepts with the telescope. Rods are usually graduated in feet or meters and these units subdivided into tenths and hundredths. - 2. With horizontal wire near the HI on the rod bring the lower stadia wire on a main division and read the upper wire. Multiply the difference in the readings by 100 and add the constant. The result gives the distance to the rod in the units used, when the transit and rod are approximately on the same level. 3. Do not take sights longer than 100 to 140 meters if they can be avoided. With the average telescope errors at this distance should be less than .50 m. With high grade instruments and favorable atmospheric conditions sights up to 250 m. may be taken with an average error of about 0.18 m. or 1/1400, but as a rule it is better to divide the distance and make two readings. 4. To avoid errors due to refraction do not make readings near the bottom of the rod and avoid working during the midday hours except on dull, overcast days. - 5. Read and record the vertical angle before reading the stadia intercept. When proficiency is attained time may be saved by reversing the process, reading the vertical angle after the rodman has moved to the next station. The stadia is primarily intended to secure rapidity rather than accuracy; nevertheless, with proper care to eliminate the chief sources of error a high degree of accuracy may be obtained. 4. STEEL TAPE The steel tape furnishes a convenient, rapid, and economical means of measuring any distance for any desired degree of accuracy up to about 1 in 300,000. For topographical sur- veying a length of 30m is usually most convenient. For base- line measurement the length should be from 100 to 200m and its cross section about twenty one-thousandths of a square centimeter. - The length of a topographical base will depend first on the size of the triangulation net to be based on it, and second on the stretch of level or evenly sloping ground available. Such bases have varied in length from 3/3 km to 6 or 8 km. It is nore important to be able to eactend the base by well proportioned 98 ORIENTATION FOR HEAVY (COAST) ARTILLERY triangles than to measure a long base. The ideal site is on level, even ground, from which good views of the surrounding coun- try can be obtained. - Measurement of Base.—A topographical base should always be measured with a steel tape. This should be carefully com- pared with a standardized steel tape before and after using. A standardized steel tape is one whose exact length when sup- ported throughout its length for a given temperature and pull, as well as its coefficient of expansion, has been determined by the National Bureau of Standards at Washington, D. C. For an accuracy of 1 in 5,000 the tape may be used in all kinds of weather, held and stretched by hand, the horizontal position and amount of pull being estimated by the tapeman. The temperature may be estimated or read from a ther- mometer carried for the purpose. On uneven ground the end marks are given by a plumb bob, which is held at some grad- uation on the tape. These various distances are then added together in order to find the total distance between the two points A and B. (See Fig. IV.) Fig. IV.-TAPING OVER ROUGH TERRAIN For an Accuracy of 1 in 10,000 to 1 in 50,000.-The line of the base should first be cleared of trees, bushes, or high grass; Small mounds, etc., should be removed. Each terminal point of the base should, if time allows, be marked by burying a bottle 1 meter under ground; accurately centered over this should be built a small masonry pillar, sur- face flush with the ground. A fine mark should be made in a metal plug sunk into the surface of the pillar. Having marked the terminal points, set a transit over one of them and direct it on the other, over which a pole should have been fixed; with the transit align stakes at intervals of about 300 meters. By means of this alignment hammer into the ground square-headed stakes, accurately in the line of the base LINEAR MEASUREMENTS 99 and at tape lengths from each other, starting from one end of the base. The tops of the stakes should be just flush with the ground; on these stakes nail strips of zinc. The trace of the line of sight of the transit should be marked on the zinc cap and the edge of the tape should lie along this line when marking measurements. In measuring the base, stretch the tape from terminal point to first stake and from stake to stake; the tension should be taken on a spring balance and should be that given for the standardized tape. The end of the tape should be marked by a fine pencil line or knife cut on the zinc strip nailed on top of each stake. The temperature of the tape should be taken at frequent intervals by letting the bulb of the thermometer come in contact with the underside of the tape. At the other terminal the small space between the last graduation and the end of the base should be measured with a pair of dividers. Now measure the inclination to horizontal from peg to peg with a level or transit. Minor undulations crossed by the tape are to be disregarded. The base should be measured at least once in each direction, On a still, dull day, if possible, or in early morning or late after- IlOOIl. Precautions to Insure Accuracy.— 1. Find exact points which mark the ends of the gradua- tions on the tape. 2. Find by what method the tape is graduated and note how it must be read. 3. See that the tape is straight and exert a steady standard pull while measuring. 4. Keep tape horizontal and use short lengths on steep slopes. 5. Keep the right count of tape lengths. 6. The rear tapeman should line in the head tapeman with the forward point. Causes of Errors.-The following table shows the conditions that will cause an error of 3mm in a distance of 30m (1 in 10,000), using a 30m tape. 1. Length of tape differing from a standard by 3mm. 2. Tape not horizontal, one end .043m higher than the other end. . . . . . 3. Tape not stretched tight. Center of tape 0.21m out of line. 100 ORIENTATION FOR HEAVY (COAST) ARTILLERY 4. For every 15° F. or 8.3° C. change in temperature. 5. Alignment—one end of tape in line, the other 0.43m out of line. 6. Sag—the middle of the tape .19m below the ends. 7. For every 15 pounds pull. 8. Marking tape-lengths. Error of 3mm in marking or plumbing. Base Line Calculations.—The measured length of a base line is subject to five corrections: For standard. For temperature. For inclination or slope. For sag. For height above sea level. : The following example will illustrate the method of applying these various corrections: A base line, measured length 1615.818 meters, has been measured as above described. Two 30 meter tapes were supplied with the equipment, one being reserved for a “reference tape” and not used in the field; the other was used exclusively as the “field tape.” The reference tape, when standardized, was found to be 0.015 meters short at 18° C. The field tape (supposed to be 30 meters long) when compared with the reference tape was found to be 0.006 meters longer than reference tape at 22°C. The temperature of the tape during measurement of the base line was 28°C. Height of base line above sea level, 1380 meters. The base line was measured on a slope of 1° 15' for a distance of 700 meters, the remainder was measured on the level. 1. Standard: Reference tape was 0.015 m. short at 18° C. Steel expands 0.00001125 of its length for 1° C. Therefore, at 22° reference tape was *****-000iml 10,000,000 = 0.001m Onger. Therefore the reference tape was 0.015–0.001 = 0.014 m. shorter than standard at 22° C. Tape used was 0.006 m. long on reference tape at 22°C. 2 ºld tape was therefore 0.014–0.006 = 0.008m shorter than standard at 2° C. 2. Temperature: Temperature of field tape during measurement. . . . . . . . . . . . . . . . . . . . . 28° C. Temperature of tape when compared with reference tape. . . . . . . . . . . . 22° C. - Difference 6° C. Increase in length: 6 × 30 × 112.5 iOOOOOOO− =0.002 m. The actual total variation in length of field tape is therefore: For Standard 0.008m short . For Temperature 0.002m long . . * * Total, 0.006m short º The total caráction for standard and temperature to be applied to the meas- ured length of the base line is therefore: 1616 0.006 × T30T = 0.323m LINEAR MEASUREMENTS 101 3. Inclination or Slope: For 700 meters the base line has a slope of 1° 15'. The correction is, therefore 700 (1 —cos 1° 15') = 0.168 meters. 4. Sag: In the measurement of a base it is desirable that the whole length of the tape should as far as possible be supported by the ground, so that no correction is necessary for the sag of the tape. Where the ground is uneven, it is customary to support the tape at intervals by stakes, but it may happen in the measure- ment of a base that a ravine has to be crossed. In such a case the sag, i.e., the difference between the length when suspended and when laid on a plane surface, must be determined and corrected for. If s = the correction for sag in meters. l=the length of the tape suspended between two supports in meters. w = the weight of the tape in pounds. t=the tension applied in pounds. s =lw?/24t2. 5. Height above Sea Level: If the base line is measured at a mean height (h) above the sea level, it will require a correction of h -R × length of base. Where R = the radius of the earth, which may be taken as 6,370,000 meters. In this case h = 1380 m. The correction is therefore 1380 6,370,000 X 1616 = 0.350m. Corrections 1 and 2 may be either positive or negative; 3 and 4 must always be negative and 5 will usually be negative. Combining all corrections Meters 1. Standard and Temperature. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . — 0.323 3. Inclination. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . —0.168 4. Sag.:...:. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . — 0.000 5. Height above Sea Level. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . –0.350 Total correction... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . — 0.841 Measured length. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1615.818 Corrected length of base line. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1614,977 5. THIANGULATION A triangulation system is determined by first locating and accurately measuring a base line as has just been described. From this base line, triangles are extended by measuring angles and computing the lengths of the sides trigonometri- cally. The general method of extending a triangulation system is discussed in Chapter II. It is obvious that an error in the length of the base line will be carried throughout the entire framework, and will be multiplied in magnitude in the location of distant points of the framework. In like manner errors in the measurement of angles will cause errors in the coordinates of the points based on the calculations. It is therefore necessary to keep both errors within the allowable errors for the work being done. 102 ORIENTATION FOR HEAVY (COAST) ARTILLERY Computation of Sides.—In extending a series of triangles on a given base line, the base line is the only side of the series of triangles that is measured, the others being determined by computation. 7. A/o//zonfa/A22/7e N fºrough 77a.m.5// / | smº mºst - - ---a -- ~~s ess axº~ *-* = * * * * Fig. V.--TRIANGULATION In Fig. V let c be the base line and T a tower whose dis- tances from the ends of the base line are desired. The angles are measured with the transit and their values adjusted. In case the point C is inaccessible the angle y may be obtained by the formula y = 180°– (o-H 6); this, however, leaves no check on the accuracy in measuring the angles o and 8. The length of the sides a and b are to be found from the law of sines. sin o. a c sin o. e — — 8, 5 g SIn y C ; SIn Y sin 3 b - c sin 8 sin YT c; - sin Y Applying logs, log a = log c-Hlog sin o-H colog sin Y log b = log c-Hlog sin 3+colog sin Y Altitude.—Fig. V illustrates the method of obtaining alti- tude or vertical distance in a triangulation system. The angles q and 6 are measured when the transit is set up at the stations A and B. The difference in altitude of stations A and B must e determined by some available means. The LINEAR MEASUREMENTS 103 horizontal distances a and b are determined by computation in the triangle ABC. The height TC' is then computed by using the formulas:– TC' = a tanó TC' = b tan q log TC' = log a-H log tanó log TC' = log b-Hlog tan (b The two values of TC’ obtained are the altitudes of T above horizontal planes through the transit at A and at B and should differ by the difference in altitude of A and B if these points are not of the same level. To obtain the altitude of T above the ground plane it will be necessary to add to the height TC' the height of the transit. CHAPTER VI PLANE TABLE MATERIAL ORIENTATION TRAVERSE INTERSECTION RESECTION i The plane table is a surveying instrument consisting of a drawing board supported on a tripod, and a ruler to which a pair of sights or a telescope is attached. It is used in the field for projecting the lines and points of a survey directly upon the drawing, thus eliminating the measuring of hori- Zontal angles and the use of the protractor. On the western front the plane table is being extensively used for such work as: - - 1. Running a traverse from a triangulation point to deter- mine the coordinates of a gun position and the Y-azimuth of an aiming line. 2. Facilitating the reconnaissance of aiming points and the prevention of errors in their identification. 3. Verifying the fact that the operation which is to be undertaken with a transit is geometrically correct (for ex- ample, in locating an unknown point care must be taken that it is not on the circle with the visible known points and that all intersections are made at large angles). 4. Checking topographical work and computations by furnishing approximate data. 5. Sketching a battery position to show details and main plan. 6. Locating points by intersection and resection. Filling in details on large maps. In a warfare of movement where time becomes a very im- portant factor the plane table is frequently used to determine topographical data for tractor artillery. However, for railway artillery the determinations are not sufficiently accurate and more precise surveying instruments must be used. PLANE TABLE 105 1. MATERIAL Plane Table.—The table itself consists simply of a draw- ing board mounted on a tripod equipped with leveling screws similar to those on a transit. It is connected to the tripod by means of a spindle allowing the board to be revolved in a horizontal plane. A winged nut under the tripod head makes it possible to clamp the board in any position desired. A sheet of drawing paper is attached to the plane table by means of thumb tacks or clamps at the corners. Some boards are constructed with a magnetic needle pivoted in a trough in the edge of the board, others are supplied with a simple box compass. Both are used to give the board a certain position with respect to the North line. A-Table. BaAlidade. C-Telescope. D-Wert, circle, E-Vernier. F- Level. Fig. I.-PLANE TABLE Alidade.—The alidade consists of a ruler with sight vanes or a telescope. There are four types in common use and a brief description of each will be given. (a) The telescopic alidade is used for accurate work and has a ruler 6 cm. to 7 cm. wide to provide a firm base for the telescope. Level tubes are frequently mounted on the ruler or on the box compass to assist in leveling the table. A brass column firmly fixed to the ruler carries a telescope which is similar to the one on the transit having stadia wires, vertical limb, and level tube. 106 ORIENTATION FOR HEAVY (COAST) ARTILLERY (b) A triangular wooden ruler can be used as an alidade with fairly good results. The top edge is used for sighting and the other two edges for ruling. (c) The metal ruler with folding sight vanes is a common form of alidade. One vane is simply a vertical slit and the other has a fine wire stretched vertically across a narrow opening. - (d) Leveling alidade.—This instrument consists of a ruler graduated in millimeters with a level mounted at its middle. Two small cams, one at each end of the ruler, are used for leveling it. Folding sight vanes are used and by means of a scale on the forward vane that is graduated in units equal to one one hundredth of the distance between the vanes the slope between two stations can be read direct. Clinometer.—In rough work vertical angles are some- times measured by a small instrument known as a clinometer. It consists of a circular scale of degrees pivoted at the center with a weight attached to a point on the circle. When the case in which the scale is mounted is held vertically the weight swings to the bottom causing the circle to revolve. The distant point is sighted through peepholes in the case and the graduations on the circle are read at the same time. When the line of sight is horizontal the scale reads zero; when it is inclined upwards, the black figures on the scale come oppo- site the index and when it is inclined downwards the red figures appear. This method of reading vertical angles is likely to be at least 1° in error and if accurate measurements are desired a telescope with a vertical limb should be used. Scales.—In making a plane table survey distances are usually measured by stadia or pacing. Before beginning the work in the field the scale of the drawing or survey must be decided upon, and a working scale constructed accordingly. It is usually best to use a scale that will make the map large enough to fill the sheet of drawing paper on the board conven- iently. When using stadia rods reading in meters the follow- ing formula can be used to find the map distance. (Map distance is distance measured on the map that represents a given horizontal distance on the ground.) Scale of Map X 100×100 = Map Distance in centimeters per 100 meters. The scale of the map will be expressed as a fraction, *10,000 meaning 10,000 units on the ground are represented by one unit on the map. PLANE TABLE * 107 - 1 º - Example: Scale of map to be T0.005. Find the map distance in centi- meters of 100 meters. 1 10,000 X 100 × 100 = 1 cm. If distances are to be measured by pacing, first determine the average length of your pace by walking over a measured course several times keeping an accurate count of your paces. Divide the total distance in centimeters by the total number of paces. This gives the length of your pace in centimeters. The map distance in centimeters for 100 paces is found by using the formula: Scale of Map XLength of PaceX 100 = Map Distance in centimeters of 100 paces. - Scale of map to be expressed fractionally and length of pace in centimeters. 1 - Example: Scale of map is TOOOT. Length of pace is 80 cm. Find map distance in centimeters of 100 paces. 1. : 1000 X 80 × 100 = 8 cm. If one prefers to count strides instead of paces the above formula may be used by putting the length of a stride in place of the length of a pace and the result will be the map distance of 100 strides. - Having determined the map distances for 100 meters or paces a working scale should be constructed using a stiff strip of paper about 3 cm. wide and 30 cm. long cut with straight edges. Take a number of map distances that will give a length of 24 to 26 cm. of the scale and divide this length graph- ically into the number of distances used. Mark these points in hundreds on the scale, beginning at the second mark from the left with the zero. The space to the left of the zero sub- divide into tenths or twentieths. If the map distance should be a whole number of centimeters the scale can be laid off with a scale of centimeters without having to make the divi- sions graphically. Example: Map distance in centimeters for 100 paces was found to be 2.12 cm. Multiply 2.12 by some number that will give a length of about 24 to 26 cm. as 12. The result is 25.44 cm. Lay off on a line AB (see Fig. II) a length equal to this distance. Draw AC making any convenient angle with AB. On AC mark off with the compass from A 12 equal spaces of about one centimeter. Connect D with B and draw lines from the divisions of AC parallel to DB cut- 108 ORIENTATION FOR HEAVY (COAST) ARTILLERY ting AB. AB will then be divided into 12 equal parts. Mark the scale by these divisions as shown in the figure. C. Scaſe ſºn Fig. II.-CONSTRUCTION OF A WORKING SCALE 2. ORIENTATION In making a survey with a plane table it is necessary after occupying the first station to set up the board at each succeed- ing station so that all lines on the drawing will be parallel to the lines corresponding on the ground. This adjustment of the table is known as orientation and is usually done by means of a compass, or by backsighting. To Orient the Board by Compass.-Set up the tripod with board loosely screwed to it and level the board carefully by means of the bubble tubes on the alidade. Free the needle by turning the cam and turn the board slowly around until the needle Swings from side to side in the trough. Let the needle settle, turning the board as necessary so that the needle when settled lies directly along the north and south line (the median line of the trough). Without changing the position of the board reach under and tighten up the screw of the tripod. Care must always be taken not to turn the tripod Screw too tight, as the threads are likely to be stripped by rough treatment. The board is now oriented. Draw a line parallel to the needle on the paper and mark the north end with a half arrow. Above this write M. M. or N. (mag- netic meridian or north). PLANE TABLE 109 If a box compass is used on the board instead of the needle pivoted in the trough the plane table is turned into such a position at the first station that the survey will lie entirely on the drawing. The box compass is then placed on the board near the edge and turned until the needle points to the North mark on the needle circle. Draw a light line at the edge of the compass box parallel to the needle and mark this as before described with an arrow and the letter “N.” The compass can now be removed while drawing rays with the alidade. (Any line drawn with the alidade on the map is called a ray.) At the next station after leveling the table the compass is placed against the North line and the board turned until the needle lies along the north and south line of needle circle. The board is now oriented. To Orient the Board by Backsighting.—Having plotted (located and drawn in) a station and arrived at a point far- ther on to which you have sighted and drawn a ray, set up the tripod and board, measure off with the scale the distance between the two points on your ray and stick a pin in the point found. This is your present position. Place the ali- dade against the pin and along the ray between the two points and turn the board until the station you have just come from is sighted. Tighten up the clamp screw without moving the board and it will be oriented. Verify this by reading the needle. 3. TRAVERSE The term traverse is applied to the route followed by a surveyor in making a map of a number of points on the ground. Being at a point A it is desired to make a map of the points ABCD on the ground (see Fig. III). First set up the plane table over the station A. In setting up a plane table over a station it is necessary to: 1. Place the table so that the point on the map is verti- cally over the station on the ground it represents. 2. Level accurately by the same method as used with a transit. 3. Orient carefully by compass or backsight. The point “a” on the map is located so that the complete survey will be well spaced on the paper. With the table properly set over “A,” stick a pin in the 110 ORIENTATION FOR HEAVY (COAST) ARTILLERY |S. 2. As N > º \ / -- / SS JA) / / º, º (7 / & –7. / 2*-- / A T --~ . / T - ~ 6 /W ~ ºf a/ A) Fig. III.--—TRAVERSE point “a” on the map. (Capitals are used to represent points on the ground and small letters points on the map.) Lay the alidade against the pin and pivot it until the point B is sighted. Draw a ray toward B. Read the stadia inter- cept, if measuring distances by stadia, and also the vertical angle. Move to B and upon arrival set up the board approx- imately over the station. With the working scale measure off the distance (corrected to the horizontal) from “a.” Now set up the table carefully over B as described above, using particular care to orient accurately. As the needle may be affected by local attraction the orientation should be checked by back sighting. With the alidade pivoted at “b” draw a ray toward C, read the stadia intercept and vertical angle. Move to C and repeat the steps taken at B. Each station on the traverse is occupied in the same manner and if the work is done accurately the last ray drawn from “d” toward A will pass through “a.” Very likely there will be a small closing error which may be adjusted by changing the direction and length of the last ray or by distributing the error proportion- ately over the entire traverse. Adjustment of Traverse.—Figure IV shows method of graphical adjustment for a traverse run between two points, the positions of which are already plotted on the record sheet. Proceed as follows: PLANE TABLE 111 Figs. IV and V.-ADJUSTMENT OF TRAVERSES Plot the traverse, as actually measured in the field. In plane table work this is already done. Draw a line AB from the starting point to the ending point of the plot. Now from the record sheet measure the straight line distance between the record positions of A and B. Measure off this distance from A on line AB. Call the end of the distance b. Take any convenient point O and draw OA and OB. Now from b draw a line parallel to OA. Where this line crosses OB is the new position (B') for B. From B' draw a line parallel to AB. Where this line intersects AO is the new position of A. 112 ORIENTATION FOR HEAVY (COAST) ARTILLERY To find the new position of station 1, draw a line from A' parallel to A1 and where it intersects O1 is the new position 1' of 1. From 1 draw a line parallel to 1–2, etc. The traverse A', 1’, 2’-B' is now adjusted and can be traced off on to record sheet. Fig. V shows a method when a traverse is run from a known point back to the same point. Plot the traverse as measured in the field. The point A’ should be at A, but due to errors, does not so plot. On a long straight line OA lay off from O, in succession, the lengths of courses (A–1, 1–2, 2–3, etc.). From the end of this line lay off in any convenient direction the line AB equal to the error in closure A'A. Connect the outer end of this offset line to O. Now from each succeeding station point on the long line, draw a line parallel to the offset line AB. *. Returning to the plot of the traverse, draw through each plotted station a line parallel to the final closing line A/A and in the direction of the closing station. On each line lay off its respective offset length, giving new positions for each sta- tion. Connect these new stations and the traverse is adjusted. In locating a position by a traverse the closing error should be less than 1 per cent. of the total distance traversed; however, in making a rough sketch of a battery position a three per cent. error may be allowed. The importance of the work will determine the permissible error. In case a traverse is to be made between a known and unknown point it should be made to close by returning to the known point by a different route, or continued beyond the unknown point until another known point is reached. An angular traverse has for its object the determination of the direction of an unknown line by referring it to a line of known direction. In this case only angles are measured, the lengths of the sights not being determined. Careful orientation is particularly essential and short sights are to be avoided. 4. INTERSECTION In making a traverse, points visible from the stations may be located on the map without measuring the distances to them. This is done by drawing rays to the points from two or more stations of the traverse when the table is oriented. This method of locating points is called intersection. When the station A was occupied suppose rays were \ PLANE TABLE 113 drawn toward the points E and F (see Fig. VI). After mov- ing to B and orienting the table draw the ray E from “b.” The intersection of the two rays drawn toward E locates the point “e” on the map. The second ray to F was drawn from the station C and its intersection with the first ray determined the point “f.” Rays to locate points off the traverse should always be drawn from stations selected so that the inter- sections will be at large angles. In very accurate work three or more rays are drawn to locate a point by intersection. They should meet in a point but frequently a small triangle of error is formed and the true point is taken to be about the center of this triangle. 5. RESECTION This method of locating points on the map is a modifica- tion of the method of intersection. Its chief characteristic is that the point determined by the intersecting rays is the station occupied by the plane table. This means that a plane table can be set up anywhere and the corresponding point on the map can be found by resection provided three points already plotted are visible from the unknown station. e_Kö \ - ~ / \ _ - T a)(ſ is \ __ - T 24 f N £-~ / / Af `ss \ / \ / / `SS \ / / SS \ / / >w \ / / YS& / A 62 \ / A WZ \ / | 27 S > | — — — — — Tø \ / 2 Ø —|------ ~ % \ / £7 /c / \ || Tº / / C/ Tº -- * = / / A / / `s ×/T 4 : Fig. VI.-LOCATION OF POINTS BY INTERSECTION 114 ORIENTATION FOR HEAVY (COAST) ARTILLERY Solution. With Oriented Board.—Having previously plotted the position of points “a,” “b,” “c,” and “d” it is desired to locate the station G on the map from which the stations B and C can be seen (see Fig. VI). Set up the table over the station G and orient it carefully with the compass. With a pin at “b” pivot the alidade and with it sighted on B draw a ray past the approximate position of “g.” Repeat the operation using “c” as a pivot. The intersection of the two rays locates the point “g.” If other stations are visible from G other rays may be drawn as a check on the accuracy of the work. If the rays form a small triangle instead of intersect- ing at one point the center of the triangle may be taken as the true point. Solution when the board is not oriented. This is known as The Three-Point Problem and is the most important prob- lem that can be solved by using the plane table. It permits the location on the plane table of any unknown point at which the plane table may be set up having plotted the positions of three or more visible known points. There are three distinct methods of solving the problem and several different solu- tions under each method. However, only the most impor- tant solutions will be given. With tracing paper. 1. Field Method 3 Triangle of error. Italian Method. 2. Graphical—Construction of “segments capable.” 3. Mathematical { U. S. Method. Relevement. The first method is customarily used in plane table work. The second can be used either on a plane table or in connection with transit measurements of the angles between lines from the unknown point to the known points. The third method requires the use of a transit and trigonometry. The first two methods will be discussed in this Chapter and the third in Chapter XI. Field Method with Tracing Paper.—This method can be used with any number of visible points that are plotted on the map. The table is set up over the unknown station and leveled but not oriented. Fasten a piece of tracing paper over the map with thumb tacks and stick a pin into the board at Some convenient point to represent the unknown station. With the alidade pivoted at this point draw rays to the visible stations and mark them. Next loosen the tracing paper on PLANE TABLE 115 the board and shift it over the map until each ray passes through the point on the sketch representing the station to which the ray was drawn. With the sheet in this position prick the map at the intersection of the rays. This gives the location on the map of the station occupied. Triangle of Error.—Orient the table as accurately as pos- sible by estimation. Clamp and draw rays toward your position from “a,” “b,” and “c” by pivoting the alidade on these points and sighting on A, B, and C respectively. If the table has been oriented correctly these three rays will intersect in a point which will be the point sought. Most likely, however, a small triangle of error will be formed. (See Fig. VII.) By certain rules that will be given later the true Fig. VII.-LOCATION OF POINTS BY RESECTION position of the point can be closely approximated. Place the alidade with one edge against this approximate position of the point and also pivoted against “a,” “b,” or “c.” Now turn the board until the alidade is sighted on the station represented by the point where it is pivoted. With this new orientation draw the three rays as before. The rays will possibly form a very much smaller triangle than was made on the first trial. (See Fig. VIII.) The small triangle to the right of the triangle KLM was formed by the rays drawn 116 ORIENTATION FOR HEAVY (COAST) ARTILLERY A-A2/27. Sooyºr T ~ – —— A-A/32/277/2/2/2// Fig. VIII.-TRIANGLES OF ERROR when the board had been given the new orientation. Con- tinue the process until the triangle disappears and the rays intersect in a point. Rules for Reducing the Triangle of Error.—The term “point sought” will be understood to mean the true position on the map of the station where the plane table is set up. The sur- veyor is assumed to be facing the signals or stations and the directions right and left are given accordingly. Rule I.-The point sought is always distant from each of the three rays in proportion to the length of the rays. Rule II.—It will always be on the right or left of all three rays, never to the left of one and to the right of others or vice versa. - Rule III.-The “great triangle” is the one formed by the three points a, b, and c on the map and the “great circle” refers to the circle through these same points. When the point sought is within the great triangle it is within the tri- angle of error. (See Fig. VII, Station E.) - Rule IV.-When the point sought is without the grea triangle but within the great circle the ray drawn from the middle station lies between the point sought and the inter- section of the other two rays. (See Fig. VII, Station D.) Rule W.--When the point is without the great circle it is PLANE TABLE 117 always on the same side of the ray from the most distant point as the intersection of the other two rays. (See Fig. VII, Station F.) Rule VI.—After forming the first triangle of error deter- mine on which side of the triangle the point sought lies. (This rules does not apply if the point sought is within the triangle of error.) - Rule VII.-Turn the table slightly and draw new rays from the visible stations. These rays will form another triangle of error similar to the first. (See Fig. VIII.) It is advantageous to turn the table in such a direction that it will pass through the position of true orientation. The triangle obtained in this case will be similar to the first but inverted. The intersection of the lines joining the corresponding vertices of these two similar triangles will be near the point sought, being always between it and the great triangle. Rule VIII.—If the point sought lies on the great circle it Fig. IX.-ITALIAN METHOD 118 ORIENTATION FOR HEAVY (COAST) ARTILLERY cannot be located graphically or by any other known method. To locate its position it will be necessary to use another com- bination of three points that are not on a circle through the point sought. Usually one new point together with two of those first selected will give the desired combination. Italian Method.—Let a, b and c be the three known points and P the unknown point. (See Fig. IX.) Draw the base ab. Place the edge of the alidade along it with the objective toward B. Without disturbing the alidade turn the plane table so as to sight on the point B. With the plane table in this position turn the alidade about a and sight on C. Draw a line along the edge of the alidade. This will be the line am. Next place the edge of the alidade along ba with the objective toward A and turn the plane table so as to sight on the point A. Turning the alidade about b, sight on C and draw the line, which will be bn. The intersection of am and bm, deter- mines the point y. The plane table is now oriented by plac- ing the edge of the alidade on the line ye and sight on C. The plane table being oriented, it is only necessary to sight on A and B and draw the two lines which should intersect at P. The proof of this method involves only simple geometrical theorems and can readily be understood by drawing a circle through the points a, b and y. f b S Fig. X-CONSTRUCTION OF “SEGMENTS CAPABLE” PLANE TABLE 119 Graphic Solution.—With the table set up at the unknown station P (See Fig. X) place a sheet of paper over the map and pin it down with thumb tacks. Stick a pin in the board at any convenient point and with this as a pivot draw rays to A, B, and C, exactly as described when using a sheet of trac- ing paper. Remove the sheet, which will have on it the angles subtended by the lines ab and be. At “a” on the map construct an angle equal to the angle subtended by ab and at “c” construct an angle equal to the angle subtended by be. (See Fig. X.) (This will require a pair of compasses in addition to the regular plane table equipment.) At “a” draw a perpendicular, x, to the line AR; draw y perpendic- ular to cs. Draw m, the perpendicular bisector of ab; and n, the perpendicular bisector of bc. With the intersection of m and x as a center draw the circle through a and b; similarly draw the circle through b and c using the intersection of n and y as a center. The intersection of these two circles locates the position of the unknown station on the map. This is a rapid solution of the three point problem and can be made very accurate if care is used in handling the dividers, laying off the angles and keeping a fine point on the pencil. The most accurate determinations are made by this method when the rays from “a,” “b,” and “c” intersect at large angles and the unknown point is some distance from the great circle. The errors in the determination of a point by this method can be made extremely small by observing the above precautions and using a large scale map. If three known points, visible from an unknown point, are plotted on a map the angles between the lines to the known points can be measured by a transit and the location of the known point on the map determined graphically as described above without the use of the plane table. The common practice is to use coordinate paper on the plane table and plot the known stations from their coordinates as given in the “Lists of Triangulation Points.” In locating a point by resection or intersection the coordinates can then be read directly from the plot. In running a traverse the start- ing point (usually a triangulation point) is plotted and the board carefully oriented from a line of Y-azimuth. The coordinates of every station on the traverse can now be read direct and in this way the position of a gun can be determined within 10 to 20 m. very quickly. CHAPTER VII LEVELING DEFINITIONS MAP LEVELING BAROMETRIC LEVELING TRIGONOMETRIC LEVELING SPIRIT LEVELING ERRORS i The principles governing linear measurements have been discussed with particular reference to horizontal distances. It is now proposed to discuss the measurement of vertical distances, or what is the same thing, the measurement of differences in altitude or elevation. The heavy artillery officer is concerned with the difference in altitude between his battery and the target and between the different guns in the battery. It is therefore necessary that he understand the means of obtaining this difference in altitude. 1. DEFINITIONS Leveling.—In this discussion “leveling” will be taken to mean the determination of difference in altitude between given points or stations. - Datum.—An imaginary level surface all points of which are assumed to have an elevation of zero, and to which all eleva- tions in a given survey are referred. Mean Sea Level affords the most convenient datum, although an arbitrary datum may be assumed. The distinction between a horizontal surface and a level surface should be kept in mind. It is readily seen that due to the curvature of the earth, the level surface of mean sea level is in reality a curved surface. Datum, datum line, and datum plane are synonymous terms. Elevation or Altitude.—The distance of a given point or station above or below the datum. The term “altitude” will be used exclusively in this discussion. Plane of Sight.—The line of sight of a telescope instrument used as a level will always lie in a horizontal plane of sight no matter in what direction the telescope may be pointed, pro- vided the instrument is in adjustment and properly leveled. LEVELING 121 Bench Mark (B.M.).-A fixed point of reference whose altitude with respect to some assumed datum is known. It is used either as a starting or closing point for leveling. Stations (Sta.).-Points whose altitudes are to be ascer- tained or points that are to be established at a given altitude. It is where the level rod is held and not where the instrument is set up as is the case in a transit traverse. n Height of Instrument (H.I.).-The altitude of the plane of sight with respect to the assumed datum. Backsight (B.S. or +Sight). —A sight taken on a rod held at a point of known altitude to determine the H.I. Foresight (F.S. or -Sight).-A sight taken on a rod held at a point whose altitude it is desired to ascertain. Turning Point (T.P.).-A more or less temporary point of known altitude used to hold the altitude while the instrument is being moved from one set-up to another. * 2. MAP LEVELING Use.—One of the first things a Battery Commander must do when he occupies a battery position is to determine the altitude of the directing gun. As a general rule, this is taken directly from the Battle Map (or Plan Directeur). The Battle Map, as has been shown, is constructed with great care and shows by means of contours the elevations of all points on the terrain. The position of the station whose altitude is desired is plotted on the map. It is then possible by reading the altitude of the nearest contour line, to determine the altitude of the sta- tion within one contour interval. By interpolating between bracketing contour lines the altitude may be more accurately obtained. In determining altitudes in this manner the limits of accuracy of the map must be borne in mind. If the contour lines are close together, indicating steep slopes, it is obvious that a slight error in plotting the position of the station on the map may result in an error in reading its altitude from the map. Moreover, the errors inherent in printing contours on a map may cause an appreciable error in their use in this connection. Accuracy.—The usual contour interval employed on the 1:20,000 Battle Map is 5 meters. In rough country this may be increased to 10 or even 20 meters. The altitude of the directing gun must be known to within 5 meters. It is therefore obvious that the artillery officer must exercise due judgment in reading 122 ORIENTATION FOR HEAVY (COAST) ARTILLERY an altitude from the map. If there is likelihood that map leveling may give errors in altitude which are inadmissible in the firing data, it is necessary to use a more accurate method. 3. BAROMETRIC LEVELING Atmospheric Pressure.—At 0° C. the weight, at sea level, of a column of dry air one inch square is equal to a column of mercury 29.92 inches (760 mm.) high. As we ascend, the weight of the air column decreases so that the height of the equivalent mercury column decreases at the approximate rate of 0.1 inch for every 90 feet ascent above sea level. In the metric system this rate is 9 mm. for an increase in altitude of 100 meters. Aneroid Barometer.—If, then, we have an instrument which will measure the difference in atmospheric pressure between two points we have a means of leveling. Such an instrument is the aneroid barometer. However, the problem is not as simple as it may at first appear. Atmospheric pressure varies not only with altitude above sea level, but also with temper- ature, hygrometric state (humidity) and latitude. In Baro- metric Leveling the effects of these other causes of variation must be eliminated as far as possible. The Aneroid Barometer usually employed in America is a watch-shaped instrument with a dial face about 2% inches in diameter, provided with a pointer which is connected to an airtight metallic coil or vessel in the case of the instrument which is sensitive to changes in atmospheric pressure. The dial is graduated with a scale of altitudes from zero to 3000 feet with a least reading of 10 feet, and also a scale of heights of a mercury column. Means are usually provided for setting the zero of the scale of elevations at any barometric height, and also for adjusting the scale of height of the mercury col- umn. Change in pressure causes a change in the shape of the coil, which movement is communicated to the pointer, causing it to move over the dial, thus enabling the observer to read the amount of change in pressure in terms of difference in altitude. The best method of barometric leveling requires the use of two aneroids. Simultaneous readings are then taken at each station. If the stations are not far apart all causes of variation will be substantially the same at each and therefore eliminated, except temperature, which with considerable difference of altitude will always be less at the upper than at the lower LEVELING 123 station. When simultaneous observations cannot be made, the stations should be occupied with as little interval of time as possible. Better results will be obtained if the time of observation can be so chosen as to take advantage of calm, bright, dry weather. The difference in temperature at the two stations is of no consequence if aneroid barometers are used. These instruments are usually compensated for tem- perature and are, moreover usually kept at the temperature of the body. If mercurial barometers are used it is necessary to apply a temperature correction. Accuracy.—Barometric leveling should be employed only in case exact methods are impracticable or great accuracy is not required. It will be seen from a consideration of the causes of variation in the weight of the atmosphere and the fact that a slight variation in weight corresponds to a relatively large change in altitude, that it is impossible to obtain results of even moderate accuracy except under ideal conditions, which will rarely exist. If possible a mean of several observations made under apparently similar conditions should be taken. General Rules.—(1) Keep the barometer at a temperature as nearly constant as is practicable. This is best done by keeping it in an inner pocket, where it will have nearly the temperature of the body. Remove it from the pocket only for the purpose of reading and return it as soon as possible. (2) Always hold the barometer with its dial horizontal when reading it and tap it gently two or three times with the finger or pencil before reading. (3) In clear, settled weather it will be found that the pressure variation due to change of temperature follows a regular law. Beginning at about 9 A.M. the elevation scale will show a rise of about 10 feet per hour for about 4 hours. It will then remain stationary until about 4 P.M., and will then fall regularly until about 7 P.M. when the same reading as at 9 A.M. will be reached. A knowledge of this change will enable proper corrections to be made. (4) In unsettled weather, before or after a storm, note, if possible, the movement of the needle for an hour before starting work to ascertain its direction and rate of change, and thus be enabled to make proper corrections. 4. TRIGONOMETRIC LEVELING Method.—Trigonometric Leveling consists in the deter- mination of the difference in altitude between two points by 124 ORIENTATION FOR HEAVY (COAST) ARTILLERY means of the angle measured at one of them between the horizontal or level line, and the other; or by measuring the zenith distance of the other. This method will be of frequent application in the topographical operations pertaining to the artillery. The shorter the sights, the more accurate will be the results obtained. This form of leveling has been discussed briefly under the Chapter on Linear Measurement. By Stadia.—In the discussion of Stadia measurements it was shown that the vertical distance from the instrument to the point sighted on can be obtained if the rod intercept and the vertical angle to the point are known. The vertical distance is computed by means of tables. If the rod be in- clined so as to be perpendicular to the inclined line of sight, then it is possible to obtain the inclined or slope distance directly without referring to tables. Let the slope distance be m, the vertical angle be q, and the vertical distance be h. Then, h = m sin q It is necessary to take into consideration the height of the instrument above the ground when the altitude of an object on the ground is to be determined. If the object is situated at about the same distance above the ground as the instrument, this correction need not be made. For long distances it is also necessary to make certain corrections for atmospheric refraction and for curvature of the earth. Correction for Apparent Level.—This correction, which is negligible for sights shorter than two or three kilometers, takes into consideration the refraction of the atmosphere and the curvature of the earth. The curvature of the earth makes a point appear lower than it really is, and refraction makes it appear higher. The effect of curvature is the greater. If NA = the combined correction for the refraction and curvature and D = the distance in kilometers, the following table may be used: D (in kilometers). . . . . . . . . . . . . . . ... || 2 || 3 || 4 || 5 || 6 || 7 || 8 || 9 || 10 || 11 | 12 N A (in meters). . . . . . . . . . . . . . . . . . 0.3|0.61.1|1.72.43.34.35.56.88.29.7 2 C = Refraction Correction. K= Curvature Correction. When the altitude H of the ground at the station A is known and the altitude H’ of the sighted point B is unknown, LEVELING 125 let o = the slope measured, positive for an ascending slope and negative for a descending slope, ~~ // 7- --~~ Line O fa/ * ! - • f O/7 - -" - 7 * % observer's ſº * T.All 3. º: Wºź. - --- S. tº WZº & w 2 -* - º W/2S$ *=1|||} - º exW/ºW/* Z /, ſº _zamº - *- –– 23s.55% - - * Wºź 7% 2 A/ AV / Aſ A/ Fig. I.-TRIGONOMETRIC LEVELING D = the horizontal distance AB, h = the height of instrument at A above the ground, and h' = the height of the sighted point B above the ground. Then the formula becomes, with due regard for the sign of “a,” H’=H+D tan a-i-NA--(h—h') in which NA is the correction for apparent level applied only for long sights. The quantity h-h' becomes zero if the sighted point is exactly the same height above the ground as the sighting instrument. & When the altitude H' of the sighted point is known, and the altitude H of the ground at the station is unknown, we can find the altitude of the instrument station by using the same formula with the signs changed. Thus, H = H'—D tan a –NA— (h—h') Example: Assume that it is desired to obtain the altitude of a distant station, B, from station A. Elevation of A is given as 693.7 meters and from the coor- dinates of the stations the distance, AB, has been computed to be 67.95 meters. We set up at A and find that we cannot see station B, because of trees, but we can see the lower limb of a tree alongside it, which we afterward measure and find to be 3.3 meters above B. Sighting on the lower limb of this tree we find the vertical angle to be 4° 36'. The telescope is 1.4 m. above A. Our computations are then as follows: D tan o' NA from Table log 6795 = 3.832.189 NA for 7 km. =3.3 m. +log tan 4° 36' =8.905570 NA for 6 km. =2.4 m. log D tan o' = 2.737759 - Diff. for 1 km. = 0.9 m. 126 ORIENTATION FOR HEAVY (COAST) ARTILLERY , 795 D tan or =546.7 =T. 1000 × 0.9 = 0.7 m. NA for 6.795 km. = 2.4 + 0.7 = 3.1 m. (h—h’) h = 1.4 h’= 3.3. h—h’= –1.9 Substituting in the f H = 693.7 - 546.7 -H rmula, we have 1 + (−1.9) = 1241.6 meters = Altitude of “B.” : 3. 5. SPIRIT LEVELING Instruments.-Spirit leveling is so called because it makes use of a spirit level attached to a telescope, or other device for defining a line of sight, to make the line of sight level. The term “differential leveling” is applied to the operation of obtaining the difference in altitude between two stations by means of a spirit level. The instruments in general use for spirit leveling are: 1. Engineer's Complete Transit or Theodolite. 2. The Wye Level. 3. The Dumpy Level. 4. The Hand Level. Since the Engineer's Complete Transit is the instrument almost exclusively used by the Battery Commander in the field work connected with his problems, the discussion will be con- sidered to apply to it alone, although the Theory of Spirit Leveling applies equally well to the otherinstruments mentioned. Theory.—There are two steps in leveling for any single set-up: (1) To find how far the plane of sight is above a point of known altitude. This is the backsight rod reading. (2) To find how far a given station is below the plane of sight. This is the foresight reading. The repeated applications of these two steps constitute a “level circuit” or “line of levels.” Consider the case shown in Fig. II. * Aroa/ e - -——-4—- tº - -—“ | | –Z) - AES N * * 㺠AS &S - AEacks/g/ºr * §3. §ºes Jya Aº AS-AOresº/ºr *Ses== º Q - z-S éSè Fig. II.-SPIRIT LEVELING LEVELING 127 (1) The instrument is set up and carefully leveled as has been previously described. Care must be taken to see that the line of sight, when level, will strike on the rod held on the B.M. In case of doubt this should be verified by directing the telescope toward the B.M. and centering the telescope bubble before centering the plate bubbles. A sight through the tel- escope will then indicate whether the instrument is too high or too low. This simple precaution frequently saves much time and annoyance. (2) Sight on the level rod held on the B.M. Carefully center the telescope bubble and read the rod. (3) Verify the centering of the bubble. If it has moved, repeat the reading of the rod. (4) Record the rod reading and compute the H.I. The rodman now goes ahead to the next point, either a station or a T.P. If it is a T.P., he must be directed where to Set it so that the instrument man can read the rod. (5) Proceed as before with the telescope sighted on the rod at the forward point. (6) Record the rod reading and compute the altitude. This completes the two steps. The level circuit is con- tinued by a repetition of the foregoing. From the foregoing discussion it is seen that it is not neces- sary to have the altitude of the starting point referred to sea level datum unless the altitude of the station is desired with respect to the same datum. For purpose of obtaining dif- ference in altitude only, any datum may be assumed for the starting point. - Notes.—In order to avoid confusion it is necessary to adopt Some suitable system of recording the notes. The system may vary for different cases but a satisfactory method is shown below, which represents the field notes of the level circuit shown in Fig. III. These notes show the method of recording a rod reading on an intermediate station as “A.” In some level circuits, as for pro- file leveling or cross sectioning, the intermediate readings may be more numerous than the readings on B.Ms. or T.Ps. But ordinarily in different leveling there are very few intermediate readings and these are taken to establish altitudes for possible future reference. Such intermediate stations, if they are permanent, then become B.Ms. It is a good plan to draw a ring around the most important altitudes for convenience in picking them out and to distinguish them from altitudes of 128 ORIENTATION FOR HEAVY (COAST) ARTILLERY a à 7/5 |72 Ž37 tº .4% Z 0.56_ --7, A | ºx/ | & 4. /O/5 |897. gº %Ş. Š%$2 º z Af ſy ºs º--—3%| -4% as à § § S2 4. & 2. % % º Š% § -T N Ž Zº-- NZ sº § Š sº *Ç $ % Zeff//and/A27e Aºghr Hand/ºage tº a - ".…-, * May 9./9/8 A&ve/s fo Obfa/7/4///ſvaº of 5/a//o/7 A Cºr/Poe Z/20//*/Ooe Sfa APS /// | A.S. Aſſev APeº/772/7%5. AP/7 0.56 |/7269 Zeze 2/ve co//efe descr/offon of . 7/2 /0/3 |/6956 (A/Mg/w/n7AU/hor/ſy for/ðA/evaſad 7\ | /25 /708/ ;4” 407 7/2 (29/ A 397 |/7.587 %3" 9/5 $% § &2 (77.273) Oescribe Zescº//ve —a– : —s –T Fig. III.-DIAGRAM OF LINE OF LEVELS |EXTRACT FROM FIELD NOTE BOOK T.Ps. All Bench Marks and important stations should be so carefully described that they can be found at any time without difficulty. This is an important point, frequently neglected. Level Rods.-There are two types of leveling rods. (1) Target rods, having a sliding target which is set by the rodman on signals from the levelman, and (2) self-reading or direct reading rods, read directly by the levelman. The self-reading rod is probably the most popular. However, the target rod presents less chance for mistake and in a circuit of very accurate levels the target is always used. Most direct reading rods are also provided with a target. Error of Closure.—As in the case of a transit traverse a circuit or running of levels should always be checked either on the starting point or on some other point whose altitude is known. Errors are to be expected. The error of closure of a level circuit run with a transit in good adjustment, with careful methods and sights ranging about 75 m. should not exceed E=.006 VS, where E = error of closure in meters. S = number of instrument set-ups. - f LEVELING 129 6. ERRORS 1. Instrumental Errors.-These are practically confined to errors of adjustments. They may be entirely eliminated by making the lengths of backsights and foresights equal. 2. Mistakes in Manipulation.— (a) The bubble may be incorrectly centered. (b) If the observer rests his hands on the tripod he may CallSé all eIſI’OI’. - (c) The leveling rod must be held plumb or perpendicular to the line of sight. When “short rod” is used, the rodman can easily balance the rod on the station and hold it steady. When “long rod” is used, or for readings over 2 m. it is usually advisable to “wave the rod.” The rodman stands directly behind the rod, facing the instrument, he leans the rod, first toward the instrument, then away from it, the top describing an arc about .6 m. long. The instrument man selects the lowest reading on the rod. (d) Dirt or any accumulation, as of snow or ice on the foot of the rod, introduces an error. 3. Mistakes in Reading the Leveling Rod.—Reading 8 for 9 or vice versa, transposing figures, etc. Each observer must learn his own peculiarities in this respect. 4. Errors in Sighting.—Coarseness of the crosswire, grad- uations of the rod or form of the target and the eyesight of the levelman all have to do with such an error. In using the transit as a level instrument it is a common mistake to use one of the stadia wires for the horizontal wire. Long sights should be avoided. 75 m. is long enough with the average instrument. 5. Errors due to Change in Position of Instrument or Rod.— These may be avoided by setting up on firm ground and taking the foresight immediately after taking the backsight. Small wooden stakes driven diagonally into the ground and using the high corner make satisfactory turning points. Loose stones should not be used. Turning points should be carefully selected with regard to the next set-up. Be careful in walking around the instrument not to jar or disturb it. 6. Errors Due to Natural Sources.—Unequal expansion of different parts of the instrument, change of length of level rod, curvature of the earth and refraction of the atmosphere are included under this head. They are usually inappreciable and are ignored in ordinary work, but are taken into account in precise leveling. 130 ORIENTATION FOR HEAVY (COAST) ARTILLERY 7. Mistakes in Recording and Computing.—Transposing figures, recording foresight as backsight or omitting a fore or backsight entirely are among the common mistakes. A con- venient check on the computing is obtained by the following rule: Add all backsights together; add all turning point fore- sights, including the foresight on the closing point, together; the difference between these sums should equal the difference between the altitudes of the starting and closing stations. 8. Personal Errors.-These are not serious in ordinary work, but must be considered in precise leveling. CHAPTER VIII MERIDIAN DETERMINATION MECHANICAL SOLUTIONS ELEMENTS OF ASTRONOMY AND TIME OBSERVATION ON THE SUN OBSERVATION ON Polaris OBSERVATION ON A STAR AT EQUAL ALTITUDEs OBSERVATION ON RNOWN TERRESTRIAL POINTs i In the preparation for artillery fire on the Western Front it is essential that battery positions be accurately known. After a battery position has been selected the coordinates of the di- recting gun, and usually of all guns, and the Y-azimuth of each aiming line must be found. In some cases these can be obtained by solving the three point problem, either mechani- cally with a plane table or mathematically with a transit, or by running a traverse from a known point on a known line. In Some cases, however, there may be but one datum point avail- able and a survey must be run from that point to the battery position, and the survey oriented or “tied in” by an astro- nomical observation to determine the True North. Further, such an observation may be necessary as a check on other work. The line in which the plane of the Meridian intersects the plane of the horizon is called the “North and South Line” or the “True Meridian.” 1. MECHANICAL SOLUTIONS There are four simple and rapid approximate methods of Meridian determination in general use which, for want of a better name, are called “Mechanical Solutions.” By their use general directions can be found quickly, which is often valuable in a strange country, or True North can be found within a degree, which is sufficiently accurate for some pur- poses, such as in making rough sketches. (a) If the declination of the compass is known True North can quickly be determined from Magnetic North, with an accuracy of one or two degrees, or even closer, depending on the accuracy of the compass. This was covered fully in Chapter III. 132 ORINETATION FOR HEAVY (COAST) ARTILLERY (b) If the hour hand of a watch is pointed at the sun, a line bisecting the angle between that hour hand and 12 o'clock points South. (See Fig. I.) If the sun is shining general directions can thus be found very quickly. *2. Fig. I.-DIRECTIONS FROM SUN AND HOUR HAND OF WATCH (c) Another method is to fasten a sheet of cardboard at the upper end of a vertical board attached to the south edge of a table, exposed to the sun's direct rays. (See Fig. II.) Prick a small hole in the cardboard, through which a Sunbeam can fall on the table. For half an hour before and after noon, put a pencil mark on the table every five minutes at the center of this Sunbeam. These successive marks will form a curve concave northwards. With a point on the table directly beneath the hole in the cardboard as a center, and any con- venient radius strike an arc that will intersect the path of the Sunbeam twice. A line perpendicular to the chord connecting these two intersections is a True North and South line. By this method True North can be determined to within one degree. (d) At night directions can be found quickly by looking for the North Star (Polaris), which is always within two MERIDIAN DETERMINATION 133 &Q ! G. | J. ! I I | | º ! N • ‘. <> º | l I • 1– N US ~~~ | Fig. II.-APPROXIMATE NORTH FROM PATH OF SUNBEAM AT NOON degrees of the plane of the Meridian; the relative positions of the fixed stars is always the same, although they apparently revolve around the Earth from East to West, and a knowledge thereof is valuable, especially in case Polaris is obscured by clouds. 2. ELEMENTS OF ASTRONOMY AND TIME The Great Dipper (Ursa Major) is the most important of the constellations and is easy to find. The “pointers” of and 8 point to Polaris at all times as the Dipper circles the Pole, the bowl of the Dipper being towards Polaris (see Fig. III). About the same distance on the other side of Polaris is Cassi- opeia, a group of five stars forming an irregular letter W, its upper part being toward Polaris. As the Latitude of any place is equal to the altitude of the Pole, when the Dipper and Cassiopeia are on either side of Polaris (East and West) the altitude of Polaris will give a reasonably correct figure for the latitude of the place of observation. When they are above or below Polaris, a compass reading on Polaris will give the decli- nation of the compass to within its least reading. There are many other constellations which should be known, but which have to be omitted here. These are given in the “Training Manual in Topography, Map Reading and Reconnaissance,” by Major George R. Spalding, published by the Govern- ment Printing Office, and in various textbooks on practical astronomy. - However, in the preparation of artillery fire True North must be known to within one minute and sometimes even 134 ORIENTATION FOR HEAVY (COAST) ARTILLERY Grea/ Cooer (6/rºso Mayor/ >. + +T \,-g- ** # f roomsº / l / / / / | | | | | | | | I #4 A." / / Š * / S &T, ‘’s V. § *> \ zººs Sk —% *> Fig. III.-CONSTELLATIONS NEAR POLARIS closer. That accuracy can be obtained by astronomical observations with a transit or theodolite. A knowledge of the elementary principles of astronomy is essential to a clear understanding of astronomical observations. Therefore, con- sider briefly the Motions of the Earth, the resulting apparent motions of the stars as seen from the Earth, and time. Motions of the Earth.-The Earth has two motions, both of which are counter-clockwise motions of revolution: It re- volves around its own polar axis and it moves around the Sun in an elliptical orbit. (Fig. IV.) The Earth's axis is not per- pendicular to the plane of its orbit, but is inclined at an angle of about 66% thereto; for our purposes its positions at all points in its orbit can be considered as parallel. Therefore, when the Earth is in one-half of its orbit, the Sun is below the plane of the Equator and when in the other half of its orbit, above the Equator. This causes the different seasons of the year. The angular distange of the Sun above or below the Equator, measured from the Earth, and called the Sun's declination, is used in solar observations. Sidereal Time.—The length of time it takes the Earth to MERIDIAN DETERMINATION 135 *( & ) - * * s º º - * * * z* f \ \ W * N. a f t \ Sº, Fig. IV.-MOTIONS OF THE EARTH make one complete revolution (360°) around its own axis is constant and is called a “Sidereal Day.” This is 23 hr. 56 min. 4 Sec. of standard time (the time our watches keep). The rotation of the Earth around its own axis is the most uniform motion in nature. The Earth makes one complete circuit of its orbit in a year, during which it makes 366.2422 revolutions around its own axis. Thus, there are 366.2422 sidereal days in a year. As both motions of the Earth are counter-clockwise, one revolution is apparently lost in a year, and the sun crosses a Meridian one time less than the number of revolutions of the Earth. In Fig. IV: Arc ABCA =360° = 1 rotation around Axis = 1 Sidereal Day, - =23 hr. 56 min. 4 sec. Standard Time. Arc ABCAB =361°= = 1 Apparent Solar Day. Arc MNOPM = 1 Year=366.242 Sidereal Days, =365.2422 Mean Solar Days. Apparent Time.—The length of time between two successive transits of the sun across a Meridian is called an “apparent solar day.” As the motion of the Earth around its orbit is not uniform, but varies inversely as the distance to the Sun, the length of time between successive transits of the Sun will depend on the position of the Earth in its orbit. This will 136 ORIENTATION FOR HEAVY (COAST) ARTILLERY be better understood by examining Fig. V, the shaded areas being equal and representing equal lengths of time. The average “apparent solar day,” or the average time between successive transits of the Sun, is called the “mean solar day.” Four times a year apparent solar time is the same as mean solar time; during two of the intervening periods it is slower, and during the two alternate periods it is faster. Standard time, kept by our watches, is based on mean solar time. The Earth's Or \bºt !ſ Suva *: zzzzzzzzzzzzzzzz ZZZZZZZZZZZZZZZZ Fig. V.-VARIATIONS IN EARTH's ORBITAL VELOCITY American Ephemeris gives for each day in the year an “equa- tion of time,” which added to or subtracted from mean solar time as the case may be, gives the corresponding apparent solar time at any instant. All calculations are based on mean solar time. When observations are made on the Sun, Sun time (apparent solar or true time), computed by the equation of time from mean time, is used. The Year.—A year contains 365.2422 mean solar days, or 365 days, 5 hrs., 48 min. and 46 sec. of mean time. In order to take up the extra 5 hrs., 48 min., 46 sec., an extra day, Feb. 29, is inserted in the calendar every fourth year (Leap Year) and omitted every hundred years. The Solar System.—The solar system consists of several planets (the Earth, Mercury, Venus, Saturn, etc.) which revolve around the Sun, and the various satellites, such as the Moon, which revolve around the planets. The position of the MERIDIAN DETERMINATION 137 planets and the Moon at any time, as seen from the Earth, depends on the combination of their motions and the Earth's motions, necessitating awkward calculations in case obser- vations are made on them. The position of the Sun, however, as seen from the Earth, depends only on the Earth's motions, and by observations of the Sun, Latitude, Longitude, azimuth and correct time can be computed with comparative ease. Fiaced Stars.-Similarly the positions of the “fixed stars” (practically all the stars except the planets and comets) depends solely on the Earth's motions, because they are at such infinite distances that their own motions are imperceptible, and by observations on them the same data can be obtained as from Solar observations. Because of the great distance to these stars, the Earth's motion around its orbit has little effect on their positions and can often be disregarded and a sidereal day can be defined as the interval of time between successive transits of a star across a Meridian. As there is one more sidereal day than there are mean solar days in a year, a sidereal 1 day is 3 min., 56 sec. shorter than a mean solar day, 365,2422 X24 hrs. Therefore, a star crosses the Meridian 3 min., 56 sec. earlier each day, and in stellar observations this time difference must be considered. Time and Longitude.—Time depends on longitude. When it is 12 o'clock noon at Greenwich (0° longitude) it is 6 P.M. at 90° E., midnight at 180° and 6 A.M. at 90° W. longitude. The following table gives the relation between mean Solar time and longitude: Mean Solar Time Longitude Mean Solar Time Longitude Interval Interval Interval Interval 24 hours 360° 1 minute 15' 1 hour 15° 4 seconds 1’ 4 minutes 1° 1 second 15" Standard Time.—Thus, each point on the Earth's surface has its own mean local time, depending on its longitude, all points on the same meridian having the same mean local time. With the growth of railroad travel these small time differences became very inconvenient, and the United States was divided into four somewhat irregular “Time Belts.” Standard time 138 ORIENTATION FOR HEAVY (COAST) ARTILLERY is the same for all points in each belt and is the mean local time of a central Meridian in that belt. Standard time in adjacent belts differs by just one hour. Under the recent “daylight saving” Act of Congress Stand- ard time is advanced one hour during the Summer months (April to September, inclusive), Standard time then being one hour faster than the mean local time of the Standard Meridians. In England and France Standard time is Greenwich mean time (Greenwich is near London) with a similar daylight saving plan in Summer. The following table gives Standard time data: - STANDARD TIME Longitude Meº cal Summer Winter Greenwich. . . . . . . . . . . 0° Noon 1 P.M. Noon Eastern. . . . . . . . . . . . . . 75° W. 7 A.M. 8 A.M. 7 A.M. Central. . . . . . . . . . . . . . 90° W. 6 A.M. 7 A.M. 6 A.M. Mountain. . . . . . . . . . . . 105° W. 5 A.M. 6 A.M. 5 A.M. Pacific....... . . . . . . . . 120° W. 4 A.M. 5 A.M. 4 A.M. Celestial Sphere.—To an observer, the Earth seems station- ary and the Sun and stars appear to revolve around it from East to West, which is the reverse of what actually happens. The Earth seems to be the center of a hollow sphere, the Sun and stars being on the inner surface. This imaginary sphere, called the “Celestial Sphere,” is a very useful conception and is the basis of most astronomical observations. (See Fig. VI.) Its axis is the Earth's axis produced; its equator is the Earth's Equator produced. The zenith is a point on the Celestial Sphere directly above the observer. The Horizon is the inter- section of the horizontal plane through the observer with the Celestial Sphere. In this Celestial Sphere everything is measured as an angle, either between imaginary lines, or be- tween imaginary planes. The distance between the Equator and the zenith, and the altitude of the Celestial Pole both equal the observer's Latitude. The altitude of the Sun or a star above the horizon depends on the time of day. The declination of the Sun or a star—its angular distance North or South of the Equator—depends on the time of year (the posi- tion of the Earth in its orbit). Astronomical Triangle.—The spherical triangle between the Pole, the zenith, “Z,” and a star (or the Sun, “S”) is called MERIDIAN DETERMINATION 139 452----- Q2--T --~~ N. N N `s Nº Sl S __\* 3 § -’ S. § 2^- ~ S}/ 2' $2. © S// Sº S. / - J’ (VH * * - - - * - - - amº ºf A -- * * * *-* - sº º /D/ $ /V - * // 2. \\ /Xec//72//o/, Y) i Fig. VI.-CELESTIAL SPHERE the “Astronomical Triangle” or the “PZS Triangle.” (See Fig. VI.) The curve UQBZPN is a Meridian, NREAUWH the Horizon, EDQW the Equator, and RSBH the Sun's path. The observer is at the point “O.” The side NP = Z NOP = Latitude, “Q.” The side AS = ZAOS = Sun's altitude, “H.” The side SD = Z DOS=Sun's Declination, “D.” One side, PZ, is the Co-Latitude (90°–Latitude); another, PS, is the polar distance, “P” (90°–Declination), of that particular star (or the Sun); the third side, SZ, is the co-altitude (90°–alti- tude) at the instant of observation. These sides are measured as angles between imaginary lines from the observer to the vertices of the triangle. The angle at the zenith (PZS) is the azimuth of the star (or Sun); the angle at the Pole (ZPS) is called the hour angle; from it sidereal time, in the case of a star, or apparent solar time, in the case of the Sun, can be deter- mined. The angle at the zenith is the same as the angle in the plane of the horizon between the Meridian and a plane through the observer, the star and the zenith. The hour angle is the same as the angle in the plane of the Equator between the plane of the Meridian and a plane through the observer, the Pole and the star. The PZS triangle has six parts—three angles and three sides—all measured as angles. If any three 140 ORIENTATION FOR HEAVY (COAST) ARTILLERY parts are known, the triangle is determined and any of the unknown parts can be computed. In Meridian observations on the Sun and some stars, the three sides of the PZS triangle are found, and in Meridian observations on Polaris two sides (PZ and PS) and the hour angle are found; from either set of observations the angle at the zenith, the azimuth of the Sun or star, can be computed. 3. OBSERVATIONS ON THE SUN If all three sides of the PZS triangle are known, the angle at the zenith can be found by means of a formula, which is the method used in Solar Observations. The data necessary is the Latitude and the Sun's altitude and declination at the instant of observation. The altitude is measured with a transit and the exact time recorded; the corresponding declination is found in an Ephemeris, and assuming that the Latitude is known, all necessary data is at hand. The transit must have a smoked glass eyepiece or else the image must be clearly focused on a sheet of paper held back of the eyepiece. Detailed Procedure.—In order to determine the azimuth of a line by means of an observation on the Sun, the instrument should be set up over one of the points marking the line, and carefully leveled. If the vernier of the vertical circle is not adjustable, the amount and sign (+ or –) of the index error should be recorded. Clamp the upper plate at zero, then bring the vertical crosswire on the reference stake, and clamp the lower plate. The colored shade glass, if one is used, is then screwed on to the eyepiece. The upper clamp is then loosened and the telescope turned toward the Sun. The Sun's disc should be sharply focused before beginning the operations. In making the pointings on the Sun great care should be taken not to mistake one of the stadia wires for the middle wire. The Sun's image is then brought consecutively in the upper º gº) FIG. VII POSITION OF SUN IN PLACING WIRES FOUR QUADRANTS TANGENT TO SUN 2. 2) MERIDIAN DETERMINATION 141 left, lower right, upper right, and lower left quadrants formed by the horizontal and vertical crosswires. (See Fig. VII.) As the Sun's diameter is about 32', the crosswires cannot be placed at its exact center, but they can be placed tangent to two edges of the Sun at once. Thus, by taking four observa- tions, one with the Sun in each quadrant of the crosswires, the result is the same as if one observation had been made on the Sun's center. By keeping one crosswire tangent, to the Sun, and letting the Sun creep up until it is tangent to the other crosswire also, exact readings can be taken. In each case clamp both horizontal and vertical motions, and with the slow motion screws bring both crosswires tan- gent to the two sides of the Sun. At the moment of contact record the time, the vertical and the horizontal circle readings. Point again at the mark and read both verniers as a check. Then reverse the telescope and repeat the operation. The mean of the horizontal angles will be the angle between the reference mark and the mean position of the center of the Sun. The mean of the vertical angles will be the angular altitude of the center of the Sun. The observations should be made as rapidly as possible (as is consistent with accuracy) with the time intervals between the pointings approximately equal. Refraction.—On account of refraction astronomical bodies appear to be higher than they really are. Hence, all vertical angles found by astronomical observation should be reduced by subtracting the correction for refraction. Below about 20°, the correction for refraction is very uncertain and hence any observation depending principally on altitudes should be taken only after the Sun or star is from 20° to 30° above the horizon. The correction for refraction varies with the temperature, height of barometer, etc. The following mean values for a temperature of 50° F. and barometer reading of 29.9 inches are taken from “Hayford's Geodetic Astronomy.” MEAN REFRACTION CORRECTIONS Altitude Correction | Altitude Correction Altitude Correction 0° 34' 08" 16° 3' 20" 40° 1’ 09" 5° 9' 52" 17° 3' 08" 45° 0' 58" 10° 5' 19” 18° 2. 57*. 50° O' 49" 11° 4' 51" 19° 2' 48" 55° 0' 40" 12° 4, 27” 20° 2' 39" 60° 0' 34" 13° 4' 07” 25° 2' 04" 70° 0' 21" 14° 3'49" 30° 1'41" 80° O’ 10” 15° 3' 34" 35° 1'23" 90° 0' 00" 142 ORIENTATION FOR HEAVY (COAST) ARTILLERY If observations are taken too near noon the altitude of the Sun is changing too slowly and the astronomical triangle is poorly proportioned for definite results. Hence, the best time for observations is from 8:00 to 10:00 A.M. or from 2:00 to 4:00 P.M.; they should never be taken within an hour of noon. In the computations an Ephemeris of the Sun is needed, and in using the tables great care should be taken not to confuse “mean” and “apparent” times. In the following example the computations have been made with the United States Land Office Ephemeris. The tables on pages 2–13 give the declina- tions of the Sun for Greenwich apparent (or true) noon, and equations of time to be applied to apparent to get mean time. If the observer's watch time of observation has been corrected to Greenwich mean time, this equation is applied to that time to get apparent (or true) time of observation; and the decli- nation given for Greenwich apparent noon is then interpolated for apparent time of observation. If the American Nautical Almanac had been used, the tables would have given the declinations for Greenwich mean, noon. Consequently, no equation of time would be applied but the declination would have been at once interpolated for watch time of observation corrected to Greenwich mean time. Formula.—The formula for azimuth is taken from Hay- ford's Geodetic Astronomy and no proof is here given. Let D = Declination of Sun. H = Altitude, corrected for refraction. Q = Latitude. 0. P = Polar distance of Sun = 90°–Declination. A = Azimuth of Sun from North, measured clockwise in the morning, and counter-clockwise in the afternoon. § s-ºn tº /sin (S–H) sin (S-Q) Then tan 9/3A = v cos S cos (S-P) Computations.—The calculations may be summarized in nine steps as follows: 1. Correct average watch (Standard) time of observation to Greenwich mean time. (First, correct for watch error, if any; second, correct for difference in watch time between station and Greenwich. If Standard time is used, the Greenwich mean time is found by adding the Longitude, in hours, of the Standard Meridian to MERIDIAN DETERMINATION 143 which it refers if West of Greenwich, subtracting if East.) 2. Find Greenwich apparent time of observation (after Greenwich noon) by applying equation of time from the Ephemeris. Note.—If the Ephemeris gives the Sun's declination at Greenwich mean noon the equation of time must not be used. The correction for the number of hours since noon, i.e., the change in declination since noon will be determined from the time elapsed at the moment of observation since mean noon instead of that since apparent noon. 4 3. Find declination of the Sun at nearest Greenwich apparent noon from the Ephemeris. 4. Correct this declination (3) to declination at instant of Zo/77&ey? /Vor//, & 77//e * l 2-j-43400" 5Uſ! ~~ Nº & § Fig. VIII,-SKETCH SHowING POSITIONS OF SUN, MARK, TRUE AND LAMBERT NORTH 144 ORIENTATION FOR HEAVY (COAST) ARTILLERY observation, by applying the difference for 1 hour from Ephemeris multiplied by the number of hours intervening (2). 5. Find polar distance of Sun. This is 90-declination (4). (It is important to fix in mind the algebraic signs corresponding to North and South declinations, viz.: North = +; South = —.) 6. Correct observed altitude for refraction. This is always subtractive. (From table of mean refraction corrections.) 7. With the corrected altitude = H; Latitude = Q; and Polar distance = P, substitute in the formula:— /sin (S–H) sin (S-Q) Tan 3%A = V/ cos S cos (S-P) Angle A = angle from North to Sun, clockwise in the morn- ing, and counter-clockwise in the afternoon. 8. Find angle from North to mark. (By applying angle between Sun and mark to angle “A” found in (7).) 9. Find Y-azimuth of line from station to mark. (By correcting (8) for convergence.) FIELD NOTES. HoRIzoNTAL - Point Telescope ANGLES - Mean Angle | Altitude #º Wernier AWernierB & sº tº a.º. tº lº & Mark | Normal 0°0' | 180°0' . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 9|- | Normal 46°37' 226°37' 46°37' 46°37' 23°23' 4— 4–00 ||8 Normal 46°18' 226°18' | 46°18' | 46°18' 22°36' 4— 5–20 - Normal 46°30' 226°30' | 46°30' | 46°30' 22°55’ 4— 6–30 Oſ- Normal 47°26' 227°26' | 47°26' | 27°26' 22°1' 4— 8–30 Mark | Normal 0°0' | 180°00' | . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Means = | 46°42'45"| 22°43'45"| 4– 6– 5 Mark | Inverted | 180°00' | 0-0 |.........l.........l.........l......... 0|_ Inverted 228°10' | 48°9' 228°9'30"| 48°9'30" | 21°52' 4–12–20 TÉ Inverted 227°53' || 47°53' | 227°53' || 47°53' 21°04' 4–14–00 -- Inverted 228°07 || 48°07' 228°07' | 48°07” 21°22' 4–15–10 n- || Inverted 229°00' 49°00' 229°00' | 49°00' 20°28' 4–17–00 Mark | Inverted | 180°00' 0°0' l. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Means = | 48°17'23"| 21°11'30" 4–14–38 = 47°30'04"| 21°57'38"| 4–10–21 4 h. 10 m. 21 S. = average watch (Standard) time of observation. º 1 m. 30 S. = watch error. 4 h. 11 m. 51 s. = corrected Standard time of observation. +5 h. 0 m. 0 s. = difference in Standard time between Ft. Monroe and Greenwich. MERIDIAN DETERMINATION 145 1. 9 h. 11 m. 51 S. =Greenwich mean time of observation. – 10 m. 17.9 s. =equation of time to be applied on Mar. 11th (from Ephemeris). 2. 9 h. 1 m. 33.1 s. = Greenwich apparent time of observation, after Green- wich apparent noon. 3° 55' 0.5" = Declination of Sun at Greenwich apparent noon Mar. 11th. (Declination is South and decreasing; from Ephemeris.) º 8' 51.1" = correction for number of hours since Greenwich appar- ent noon. (From Ephemeris, difference for 1 hr. Mar. 11th = 58.84". 9 h. 1 m. 33.1 S. = 9,026 hrs. 9.026×58.84" =8' 51.1".) 3. 4, 3° 46' 9.4" = Declination at time of observation. . 90° 00' 00" As declination is South, its algebraic sign is – ; hence + 3° 46' 9.4" 90°–(a negative declination) =90°,+that declin- - ation. 5. 93° 46' 9.4" = Polar distance of Sun. 21° 57' 38" = observed mean altitude. - - – 2' 26" = correction for refraction and is always subtractive. (Found from table of mean refraction correction.) 6. 21° 55' 12" = altitude of Sun, corrected for refraction. Corrected altitude = H = 21° 55' 12" Latitude =Q=37°00' 02" Polar distance = P = 93° 46' 09" 2|152° 41' 23" S = 76° 20' 41" S–H = 54° 25' 29" S— Q=39° 20' 39" Formula: sin (S.–H) sin (S.–Q) / S– P = 17° 25' 28” - Tan 3% A = V/ cos S cos (S-P) 9.910279 = log sin (S–H) 9.802074 = log sin (S-Q) 0.626941 = colog cos S 0.020400 = colog cos (S-P) 2 : 0.359694 .179847 = log tan 3% A 56° 32' 18" = % A * 113° 4' 36" = angle A=angle from North to Sun, counter-clockwise because observed in the afternoon. + 47° 30' 04" =mean angle between Sun and mark. 7 8. 160° 34' 40" = angle from North to mark, contra-clockwise. – 48' 00" = correction for deviation to West from Lambert North. (MI — Mo) ×sin Lat. = 1.3×sin 38°=.8=48'. (Origin of Lambert grid on Ft. M map, Long. 75°, Lat. 38°.) 159° 46' 40" = angle from Lambert North to mark, counter-clockwise. 360° 00’00” — 159° 46' 40" = 200° 13' 20". 9. 200° 13' 20" =Y-azimuth of line to mark, clockwise. 200° 13' 20" =200.22° or =222.4699. (See Fig. VIII.) Example (French Method of Computation).--The French Ephemeris gives they declination of the Sun for Greenwich mean noon each day, giving it to the nearest tenth of a minute, 146 ORIENTATION FOR HEAVY (COAST) ARTILLERY and the correction to be applied thereto for time (or Longitude) intervals. Therefore in using these tables no correction is necessary for apparent time, and the Sun's declination at the instant of observation can be found directly by adding the cor- rection for the elapsed time to the declination at Greenwich mean noon. In another table is given the refraction correc- tions to be applied to the observed altitude. The following example is based on observations made in France and is computed using the French Ephemeris. The computations are quite similar to those when the American Ephemeris is used. Observed data: 10–16–17 Lat., 48° 40'. Long., 4° 13' E” Sun to right of mark. Watch, 2 m. 00 s. slow' Mean deflection angle 144° 04' 25" Mean observed altitude 16° 37' 00" Mean time of observations 2 h. 55 m. 30 s. P.M. Computations: 2 h. 55 m. 30 s. = mean watch time of observations. + 2 m. 00 s. = watch correction. 2 h. 57 m. 30 s. =Standard time (Greenwich) of observations. 8° 46'.7 =South declination of the Sun at Greenwich mean noon, Oct. 16, 1917. (From French Ephemeris.) - + 2'.8 = correction for elapsed time. (From French Ephemeris.) 8° 49'.5 =South declination of Sun at instant of observation. 16° 37'.00 = observed altitude. e — 3’.22 =refraction correction. (From French Ephemeris.) 16° 33’.78 = corrected altitude (H). 48° 40'.00 = corrected Latitude (Q). 98° 49'.50 = Polar distance (P). 2|164° 03'.3 82° 01'.6 = S colog cos S = 0.857:885 S–H = 65° 27'.8 log sin (S–H) = 9.958892 S– Q = 33° 21'.6 log sin (S.–Q) = 9.740272 S— P = 16° 47'.9 colog cos (S-P) = 0.018939 2.575.988 % A = 62° 44'.4 Log tan 3% A = .287994 e A=125°28'.8 = Angle from North to Sun, counter-clockwise, because in the afternoon. 360° 00'.0 234° 31'.2 = Azimuth of Sun. —144° 04'.4 = (Sun to right of mark.) 90° 26'.8 = Azimuth of Line. + 2° 40'.8 = Deviation to West from Lambert North. 92° 07'.6 = Y-azimuth of Mark. MERIDIAN DETERMINATION 147 4. OBSERVATION ON POLARIS Orbit of Polaris.-Polaris, the “North Star,” is very near the Pole, its polar distance being about 1° 07', and it is there- fore frequently used for the determination of True North. To an observer on the Earth it apparently revolves around the Pole counter-clockwise in a slightly elliptical orbit. (See Fig. IX.) When it is directly above the Pole, it is said to be at Upper Culmination; when it is directly below, at Lower Culmination; when it is directly west of the Pole, at Western Elongation, and when directly East at Eastern Elongation. It makes one complete revolution about the Pole every Sidereal Day, or every 23 hrs. 56 min. 4 Sec. of mean time. Its position in its orbit is expressed by the smaller angle between it and Upper Culmination, that angle being measured in hours instead of degrees. That is called the “Hour Angle” and means the elapsed time since the last Upper Culmination, if Polaris is West of the Pole, or the time that must elapse before the next Upper Culmination, if Polaris is East of the Pole. This hour angle can never be over 11 hrs. 58 min. (half the time of revolution). The “American Ephemeris,” published by the General Land Office in Washington, gives for each day in the year the 4/20er &/22/72//o/7 § § § § S S SN SS S. S S | S S. S § § § § Š [[] 4-42/72-S/3/27s Alower &/77/naffo/7 Fig. IX.-APPARENT ORBIT OF POLARIS 148 ORIENTATION FOR HEAVY (COAST) ARTILLERY time of Upper Culmination of Polaris at Greenwich and the corresponding Declination, which varies by about 50" during the year, also in another table, the azimuths of Polaris at certain hour angles, declinations and latitudes. Observations at Culmination.—If an observation is made on Polaris at the exact instant it is at either culmination, and the transit is then depressed and a point marked on the ground, that point is directly North of the instrument. This observa- tion is simple and no calculations are necessary, but a slight error in the time of observation will cause an appreciable error in the line, because Polaris is moving rapidly East or West at culmination. Moreover, clouds may hide the star at that time, or culmination may come at an inconvenient hour (2 A.M.) Therefore such observations are seldom made. Observations at Elongation.—When Polaris is at Elongation its motion is practically vertical for about 20 minutes—down- ward at Western Elongation and upward at Eastern—and a small error in time has no appreciable effect on the results. Several different readings of the angle between the star and a given line can be taken during this 20 minutes and accurate results obtained. Then by looking up the azimuth of Polaris at Elongation, in an Ephemeris, the true azimuth of the line can be computed. Observations of Polaris at elongation are frequently made, but the same objections of inconvenient time and possible invisibility hold true as at culmination. Observations at any Time; Hour Angle Method.—Observa- tions at either culmination or elongation are special cases; the general case is to make the observation at any time, and then compute the hour angle at that instant and the corresponding azimuth of Polaris. If the general case is understood either of the special cases can readily be used if desired. The Hour Angle Method consists in measuring the angle between any given line, whose Y-azimuth, computed from the observations, and Polaris at any instant (or depressing the telescope and setting a stake in line with Polaris) and then finding (from an Ephemeris) the hour angle and declination of Polaris at that instant. Knowing them and the Latitude, two sides (PZ and SP) and the included (hour) angle of the PZS triangle are known and the azimuth of Polaris at that instant can be computed. (See Fig. X.) MERIDIAN DETERMINATION 149 Fig. X.-ORBIT OF POLARIS ZPNO = Plane of Meridian. Z = Zenith. P = Celestial Pole. S = Polaris. O = Observer. SHB = Orbit of Polaris. Z.P = 90°– Lat. SP=Polar Distance. ZZPS = Hour Angle. ZPZS = Z NOM = Azimuth. Small errors in the Latitude have almost no effect on the azimuth, and it can usually be estimated with sufficient accu- racy from a map, because one minute of Latitude subtends a distance of about a knot (6080.7") on the Earth's surface, and the location is usually known much closer than that. In observations on Polaris it is not necessary to solve the triangle, however, because that has been done for a large number of cases and the results tabulated in the Ephemeris, so that it is only necessary to interpolate for the proper values. Observations.—Set your watch accurately—to the second— at Standard time before the observation, and as soon as possible afterwards compare it with Standard time, and estimate its probable error, if any, at the instant of observation. Set your transit on the line whose azimuth is desired, sight on some other point on that line, lock the lower plate and read both verniers. (If the verniers are first set at 0° this is simplified.) Loosen the upper plate and point the telescope at Polaris. To facilitate this, first set off your Latitude on the vertical arc, and then point the telescope at Polaris by sighting over it. (See Fig. X.) A slight movement of the tangent screw will then bring Polaris into the field of vision and on to the vertical crosswire, which must be illuminated by a lantern or flash- light. When Polaris is on the crosswire record the exact time and the vernier readings. Plunge and reverse the instrument and sight on Polaris, again recording the time. Then sight on 150 ORIENTATION FOR HEAVY (COAST) ARTILLERY the line and record vernier readings. Compute the mean of the two deflection angles. If great accuracy is desired, repeat two or three times, but work up each set of observations separately. Computations.—The computations necessary to determine the azimuth of Polaris at the instant of observation can be divided into seven steps, viz.: 1. From an Ephemeris or Nautical Almanac, find the time of the nearest Upper Culmination of Polaris and its corre- sponding Declination. 2. Correct (1) for the Longitude of the place of observa- tion; the correction is .16 min. for each 15° Longitude 15 (#x3 min. 56 sec. = .16 min) if West of Greenwich, the correction is subtracted, because the time of Upper Culmina- tion is earlier there than at Greenwich; if East of Greenwich it is added. This gives the time of Upper Culmination at point of observation in local mean time. 3. Correct the time of observation (Standard time) to local mean time, first correcting for any watch error. 4. Find the hour angle (the time interval between (2) and (3). 5. With this hour angle, declination and Latitude, find in an Ephemeris the corresponding azimuth of Polaris. 6. Compute the correct azimuth of the line. 7. Compute the Y-azimuth of the line. Eacample Date, March 11, 1918. Observation at Fort Monroe, Va. Latitude, 37° N. Longitude, 76° 18' W. Mark was West of Star Watch, Correct Standard time. FIELD NOTES Deflection Point Vernier A | Vernier B Mean Angle Time Mark. . . . . . . . . . O°0' | 180°0' 0°0' . . . . . . . . . . . . . . . . Star. . . . . . . . . . . 120°39' 300°39' 120°39' 120°39' 7–31–40 P.M. Star. . . . . . . . . . . 300°40' 120°40' 120°40' 120°40' 7–37–20 Mark. . . . . . . . . . 180°0' 0°0' 0°0' | . . . . . . . . . . . . . . . . . Means 120°39'30" 7–34–30 Mark. . . . . . . . . . 0°0' 180°0' 0°0' . . . . . . . . . . . . . . . . . . Star. . . . . . . . . . . 120°38' 300°38' 120°38' 120°38' 7–44–56 Star. . . . . . . . . . . 300°38' 120°38' 120°38' 120°38' 7–47–30 Mark. . . . . . . . . . . 180°0' 0°0' 0°0' | . . . . . . . . . . . . . . . . . Means 120°38' 7–46–13 MERIDIAN DETERMINATION 151 Computations of the First Set of Readings 1. 2 h. 16.4 m. P.M. = nearest Upper Culmination (Mar. 11) from Ephemeris, page 4. (Note—Declination 88° 52'22.4".) — .8 m. = correction for difference in Longitude from Greenwich (.16m, for each 15° Longitude;+if East; —if West.) 2 h. 15.6 m. = Upper Culmination at point of observation in local mean time. 2, 7 h. 34 m. 30 s. = average watch time of observation. — 5 m. 12 s. = correction to local mean time. Longitude of observa- tion=76°18' =76°.3. 76.3—75 (Standard Meridian) = 1.3. 4 m. X1.3 = 5.2 m. = 5 m. 12 s. 3. 7 h. 29 m. 18 s. =local mean time of observation. –2 h. 15 m. 36 s. = local mean time of Upper Culmination at point of observation. 5 h. 13 m. 42 s. = mean time hour angle. =5 h. 13.7m. As stated before, the azimuths of Polaris have been com- puted for a large number of hour angles, declinations and latitudes and the results tabulated in the Ephemeris, pub- lished by the U. S. General Land Office, the tabulation appear- ing on pages 14 and 15. The back azimuth (360°– azimuth) when Polaris is West of the Pole is the same as its azimuth at the same hour angle when it is East of the Pole. Therefore the table only gives the azimuth. This is a complete and con- venient table from which the azimuth corresponding to any hour angle, declination and Latitude can quickly be found by interpolation, but at first glance it looks complicated. As soon as it is understood, however, the necessary interpolations are simple. At a given Latitude the azimuth varies with the declination and hour angle, but the same azimuth will hold for several different combinations of declination and hour angle, Similarly for the same declinations and hour angles at another Latitude, another azimuth will hold true. The variations in the azimuth caused by variations in Latitude or Declination are small, while the variations caused by changes in the hour angle are large. Therefore the table was compiled so as to give certain azimuths for each 2° of Latitude, the azimuths vary- ing by about 2 minutes, and opposite them the corresponding hour angles for each 10 Seconds of declination. In using this table it is necessary to interpolate three times: First, for the hour angle corresponding to the proper declination; second, for the azimuth corresponding to the proper Latitude; and third, for the azimuth corresponding to the proper hour angle. In this example the declination was 88° 52'22.4", the Latitude 37° and the hour angle 5 hr. 13.7 min. A portion of the table in which these values lie, separated so as to permit easy inter- polation below. 152 ORIENTATION FOR HEAVY (COAST) ARTILLERY Declination Latitude Tissº-527-20Tssº-527-22. Tssº-307|36. Tº as TT # 5 — 2.6 5 – 3.2 A 5- 5.1 || 81.4 82.5 B | 83.6 L : 5 — 13.7 83.33’ C # É| 5–15.0 5–15.8 A 5-13.4 || sº sº. 5 B sag 3 The table gives certain hour angles for declination of 88° 52'20" and 88° 52' 30", and the corresponding azimuths for Latitudes 36° and 38°. The first interpol- ation, A, is between the two pairs of hour angles for the hour angles corresponding to the given declination. The second interpolation, B, is between the two Lati- tudes for the azimuth at the given Latitude; the new azimuths are correct for any of the three combinations of hour angles and declinations on their respective lines. The third interploation, C, is between these two azimuths found in B, to find the azimuth corresponding to the given hour angle with reference to the hour angles found in A. The result, 83.33, is the azimuth of Polaris at an hour angle of 5–13.7, a declination of 88° 52'22.4" and at Latitude 37°, i.e., at the instant and place of observation. In an Ephemeris of the Sun and Polaris used by the A. E. F. in France the Azimuths of Polaris have been computed for a constant declination of 88° 52' 20" between Latitudes of 478 and 60s and for every 10 m. of hour angle. The inter- polation to obtain the azimuth of Polaris is somewhat simpler than that required in the Land Office Tables, but a small correction must be made when the declin- ation differs from 88° 52'20". These corrections are placed in a condensed table following the table of azimuths. The following problem illustrates how the tables are used: Date of observation = Aug. 25, 1918. Declination = 88° 52' 05". Latitude = 54.59. Hour Angle =4h 23m. INTERPOLATION LATITUDES Hour ANGLE * 54.0° 54.5g 55.08 4h. 20m. . . . . . . . . . . . . . . . . . . . 1° 33’.7 1° 34'.6 1° 35'.5 -- 4h. 22m. . . . . . . . . . . . . . . . . . . . . . . . . . . . 1° 34'.9 | . . . . . . . # 4h. 30m. . . . . . . . . . . . . . . . . . . . 1° 35'.4 1° 36'.4 1° 37'2 |: The azimuth, 1° 34'.9 corresponds to a hour angle of 4h. 22m. and a declin- ation of 88° 52' 20" but the true declination is 88° 52'05". In the table of cor- rections under azimuth of 1° 34'.9 and opposite 88° 52' 05" is found + 0.4' ap- plying this to the azimuth, 1° 34'.9, the corrected value is 1° 35'.3. 5. Azimuth =83,33' = 1°23'20" equals azimuth of Polaris at Latitude of ob- - serving station. (Star was West of North because observation was after nearest upper culmination.) 6. 1°23'20" = azimuth of Polaris. 120° 39' 30" = mean deflection angle, mark to star. (Mark was West of star.) MERIDIAN DETERMINATION 153 122° 2'50" = angle from North to mark (counter-clockwise). 48' 00" = correction for deviation to West for Lambert North. (M-Mo.) ×sin Lat. e. (76.3–75) ×sin 38° =.8°=48' 00". ©iºn ; * grid on Ft. Monroe map Long. =75° at. - 38°. 121° 14' 50" = angle from Lambert North to mark (counter-clockwise). 7, 360° 00' 00" — 121° 14' 50" 238° 45' 10" =Y-azimuth of line to mark, clockwise. = 265,2818. (See Fig. XI.) Without listing the computations for the second set of readings the result obtained is 265.3819. Taking a mean of the two we have 265.377& Y-azimuth, from Lambert North to mark, measured clockwise. Zamber/ /Vo/7/? 77°C/e e /Vor//? Aºo/a/75 | 2d-/*23'20" /*TS 49%.00" \\ A9 0.4% 38 231 a. Fig XI.--SKETCH SHOWING POSITIONS OF MARK, T.N., L.N., AND POLARIS \ 154 ORIENTATION FOR HEAVY (COAST) ARTILLERY Eacample, (French Method of Computation).-The French “Tables Extraites. de la Connaissance des Temps” give in one table the hour angle of Polaris in sidereal time at Greenwich mean noon each day (“Polarie avance sur le Soleil moven”). It must be corrected for the difference in Longitude (16 min. for 15°) to get the hour angle at local mean noon. In the fol- lowing example this correction is so small that it can be neg- lected. This hour angle of Polaris at local mean noon, plus the elapsed sidereal time (which is the elapsed mean time plus a correction), gives the hour angle of Polaris at the instant and place of observation; measured clockwise from upper culmi- nation, from 0 hr. to 24 hrs. Another table gives the azimuth of Polaris corresponding to each even degree of Latitude, and each 10 min. of hour angle. The former varies from 10° to 65° and the latter from 0 hr. to 24 hrs. The azimuths in this table are computed for a mean declination and no corrections are given for a variation therein. Consequently, the results may be 30" in error. However, this may be neglected for most practical purposes. The following example is based on observations made in France and is com- puted using the French Ephemeris: - Observed data: Date, October 11, 1917. Lat. 48° 40' N. Long. 4° 13' E. Mean deflection angle, 88° 50' 37". Mean time, 4.33.21 P.M. Mark was East of star. Watch, 1 m. 30 s. slow. Computations: 4. h. 33 m. 21.s. Mean watch time of observation. + 1 m. 30 s. Watch correction. 4 h. 34 m. 51 S. Standard (Greenwich) time of observation. + 16 m. 50 s. Longitude correction (−4° 13' = 16 m. 50 s. variation). 4 h. 51 m. 41 s. } Local mean time of observation, or elapsed mean time since 4 h. 51.7 m. local mean noon. - + 0.8 m. Cºº for sidereal time. 4 h. 51.7 m. (*# *x8.98 m. = 0.8 m. ) 4 h. 52.5 m. Elapsed sidereal time since local mean noon. 11 h. 46.3 m. Hour angle of Polaris at Greenwich mean noon, Oct. 11, 1917, from French Ephemeris. 4.21 0.0 m. Longitude côrrection (# X.16 = 0.04 m) 11 h. 46.3 m. Hour angle of Polaris at local mean noon, Oct. 11. +4 h. 52.5 m. Elapsed sidereal time since local mean noon. º 16 h. 38.8 m. Hour angle of Polaris at instant and place of observation. The following table contains the proper data on the azimuth of Polaris, taken from the French Ephemeris and arranged for easy interpolation: MERIDIAN DETERMINATION 155 Hour ANGLE LATITUDE - 16h. 40m. 16h. 38.8m. 16h. 30m. 48° 1° 35'.1 | . . . . . . . . . . . 1° 33’.4 48° 40' 1° 36'.3(A) 1° 36'.1 (B) 1° 34'.6(A) 49° 1° 36'.9 | . . . . . . . . . . . 1° 35'.3 The first interpolations (A) are for the azimuths corresponding to the bracket- ing Latitudes, at the bracketing hour angles; the second interpolation (B) is between the two values thus formed to determine the azimuth at the proper hour angle. It should be noted that for hour angles less than 12 hrs., Polaris is West of North, and for hour angles over 12 hrs., it is East of North. 88° 50' 37" = Mean deflection angle. Mark, was East of Star. 1° 36' 06" = Azimuth of Polaris (Star was East of North). 90° 27' = Azimuth of mark, measured clockwise from the True North, to nearest minute, which is as close as it can be computed reliably unless a correction is made for the proper declination of Polaris 2° 41' = Deviation to the West for True North. 93° 08' =Y-azimuth of line. 5. OBSERVATIONS ON A STAR AT EQUAL ALTITUDES True North can also be readily obtained by the method of “Equal Altitudes.” A star that is above the horizon all the time is called a “Circumpolar Star,” and if observations are made on it when it is at the same altitude on both sides of its orbit, True North is halfway between the two readings. The Fig XII.-OBSERVATIONS OF STAR AT EQUAL ALTITUDES ABE = Orbit of the Star. P = Pole. Z BOD = Z AOC = Altitude. O = Observer. ZDON = Z CON = Azimuth. Z = Zenith. 156 ORIENTATION FOR HEAVY (COAST) ARTILLERY observations cover a period of Several hours but neither an Ephemeris nor exact time is necessary. For convenience it is best to take the observations when the star is below the Celes- tial Pole. If an observation is taken on a star in the lower left hand quadrant of its orbit, reading both the horizontal angle to a given line and the vertical angle, and a few hours later a second observation is taken when the star is at the same alti- tude in its lower right hand quadrant, the azimuth of the line is the mean of the horizontal angles. (See Fig. XII.) Greater accuracy can be obtained by making several pairs of observa- tions and computing the mean result. 6. OBSERVATION ON RNOWN TERRESTRAIL POINTS On the Western Front a transit is usually set up with its zero on some prominent landmark. The Y-azimuth of this arbitrary line (zero reading of the transit) is called V.,. If the coordinates of both the transit point and the W. point are known the Y-azimuth, V., can be quickly computed, but unless the line is very long (say 20 kilometers or more) the probable errors in the coordinates, which are known only to the hearest meter, will cause a slight probable error in the Y-azimuth. Arithmetic Mean.—With this arbitrary setting of the transit the angles to several visible known points can be measured. This is called making the “Round of the Horizon.” From the coordinates of the transit point and each such point its Y-azi- muth (V) can be computed, and from each value of V and the corresponding transit reading, an independent value of V, can be computed. These values will vary slightly, because of errors in the coordinates. It is impossible to tell which individual result is the more accurate, but it is evident that their mean value is more reliable than any single value, its accuracy increasing with the number of points considered, because the errors in the coordinates of a number of points, each known to the nearest meter, tend to balance. This is the same principle that is used in computing the center of impact in gunnery; a single shot may be anywhere in the 100 per cent. zone; from three shots a fair value for the center of impact can be found; and from five shots a closer value. In computing the mean value of V., from a set of readings on several known points, any result which differs widely from the others should be discarded, because it is evidently in error. MERIDIAN DETERMINATION 157 For instance, suppose that the following five values for Vo were obtained from angles to five known points, viz.: A–17° 31' 30" B–17° 31' 45" C–17° 31' 25" D–17° 34' 15" - : E–17° 31' 20" The extreme variation in the five values is 2' 55" (between D and E), but if D is omitted, the extreme variation is 25" (between B and E). It is evident that there is a material error in the D value and it should be discarded. The mean of A, B, C and E is 17° 31' 30", which can be considered as an accurate determination of We, correct to within 5". Weighted Mean.-The mean value found above is called the arithmetic mean. If the distances from the transit point to the various known points are nearly equal, the probable error in each value of V, is the same and the airthmetic mean can be used. However, if the distances vary, particularly if one distance is several times as great as another, the probable error in the longer distances is less than in the shorter distances, and this should be considered in computing the mean value of Wo. The simplest way is to assign each value a weight in proportion to its length, multiply each value by its weight, find the sum of the products, and divide by the total weight. The result is the “weighted mean.” Usually only seconds need be considered. The following is an example of this method: Line Length Weight. Vo Product A 3384 3 * 17°–31’ – 30" 907 B 4550 4 17°–31’—45" 180" C 2537 2 17°–31’—25" 50” D 4838 omit 17°–34’ — 15" • e E 2114 1 17°–31’ – 20” 20" 10 340 Weighted Mean = 17°–31’–34" Arithmetic Mean = 17°–31’ –30" The difference between the arithmetic mean and the weighted mean is small (in this example only 4"), but the weighted mean is the more accurate. By the method of least squares a mean value can be estimated that is even closer than a weighted' mean, but the method is long and its use is only justified when extreme accuracy is desired and there is plenty of time. Either 158 ORIENTATION FOR HEAVY (COAST) ARTILLERY an arithmetic or a weighted mean value for V., determined as above, is usually sufficiently accurate. In the following example a transit, graduated clockwise, is at a known point, P, and the angles from the V. line are read to three other known points, A, B and C. (See Fig. XIII.) In the following table v represents the angle found by using the formula given under Quadrillage: tan v = Ax/Ay or log tan v =log Ax-log Ay. Fig. XIII.-DETERMINATION OF MEAN VALUE OF Vo | To find the Y-azimuth, V, of a line to a station after determin- ing the angle, V, it is necessary to plot the line and the angle, v, and by inspection determine the relation between v and V. The following formulae cover the possible relations: W = v; W = 180° ==v or W =360°–v. MERIDIAN DETERMINATION 159 Eacample: Given— Point X—Co-ordinate—Y Transit Readings A. . . . . . . . . . . . . . . . . . . . . . . . 381,121 191,618 12°–30’–00" B. . . . . . . . . . . . . . . . . . . . . . . . 384,045 193,392 85°–51’ –00" C. . . . . . . . . . . . . . . . . . . . . . . . 383,115 192,110 59°–33’ –30" P. . . . . . . . . . . . . . . . . . . . . . . . 383,676 190,486 Find Vo Ǻ TABULATED CoMPUTATIONS Quantity A B C 383,676 383,676 383,676 381,121 384,045 383,115 AX 2,555 369 561 190,486 190,486 190,486 191,618 193,392 192,110 Ay 1,132 2,906 1,624 Log Ay. . . . . . . . . . . . 3.407391 2. 567026 2.748963 Log Ay. . . . . . . . . . . . 3.053846 3.463296 3.210586 Log tan v. . . . . . . . . . 9.753.545 9. 103730 9. 538377 V. . . . . . . . . . . . . . . 66°–06’—15" 7°–147 – 12" 190°–03’—26" V computed. . . . . . . . 293°–53’—45" 367°–14' – 12" . 34°–56’—34" Reading. . . . . . . . . . . 12°–30’—00" 85°–51’–00" 59°–33" —30" Vo. . . . . . . . . . . . . . . . 281°–23'-45" | 281°–23'-12" | 281°–23'-40" Vo =Vcom. – Reading. Line Length Weight Vo Product, PA. . . . . . . . . . . . . 2750 3.5 28.1°–23’—45" 158 PB. . . . . . . . . . . . . 2950 4.0 28.1°–23’ — 12" 48 PC. . . . . . . . . . . . . 1700 2.5 281°–23’ –04" 10 Total. . . . . . . . . . . . . . . . . . . . . . . 10. 0 844°– 10’ —01" 216 Arithmetic Mean . . . . . . . . . . . . . . . . . . . . . . . . 281°–23’ —20" 22 Weighted Mean. |. . . . . . . . . . . . . . . . . . . . . . . . 28.1°–23’ — 22" s s a Rnowing the Y-azimuth W., of this arbitrary line, Lambert North or True North can easily be found, and the correct value of the Y-azimuth of any line radiating from that station, based on the mean value of V., can be computed. A mean value of V, based on several observations to distant points is very reliable. CHAPTER IX TRANSIT TRAVERSE METHODS OF RUNNING TRAVERSES FORMS FOR FIELD NOTES COMPUTATIONS ADJUSTMENT OF COORDINATES AND ALTITUDE PLOTTING THE TRAVERSE : The transit may be used in making a traverse instead of a plane table, the essential difference being that the obser- vations taken with the transit are more precise and are re- corded in a note book together with rough sketches as a guide, the computation and plotting being done at any time and place convenient. Transit traverses can easily be made with a precision of less than 1 per cent. error and are invar- iably used in preference to the plane table traverse when very precise locations are desired. Having triangulation stations already established, the position of any point in the area covered by the triangulation system can be located by run- ning transit traverses which should begin and end at a trian- gulation station. If only one triangulation station is near, the traverse should be run to the unknown point and made to close by returning to the same station by a different route. The transit is used to measure the horizontal angles at the intersection of adjacent courses; the vertical angle, or slope, of each course; to lay down and prolong the straight lines forming the several courses; and to measure each course if stadia measurements are used. Having this data, the remainder of the work—which may be done at any time and place convenient—consists of (1) computing and adjusting the error in the horizontal angles, (2) giving the corrected Y-azimuth of each course and aiming line, and adjusting the error of closure, (3) reducing the actual length of each course to its horizontal projection; (4) computing, from this corrected data, the coor- dinate components of each course; and (5) plotting or tabu- lating the results of these computations. These computations cannot be made unless the field notes show (1) the length of each course, (2) the angle at all the intersections of adjacent TRANSIT TRAVERSE 16.1 courses, (3) the angle from some one course to a line of known direction, and (4) the coordinates of some point on the traverse. Lacking any one of these, the notes are incomplete and of little value. To this extent notes should be made complete before the field work is completed. Additional field data for checks is always desirable and often extremely valuable. The several methods of running a traverse, as indicated in the following discussion, are usually named from the manner in which the angles are read. In this connection it should be borne in mind that each course must also be measured, usually by one of the three following methods: (a) stadia, (b) tape, or (c) computed trigonometrically. Stadia measure- ments are quickly and easily made, but with a probable error of one in 400, under ordinary conditions. When time and the terrain permit, tape measurements are much better than the stadia, being much less liable to gross errors as well as more precise than stadia measurements under all ordinary conditions. Computed courses are most precise, but require the use of a triangulation system on a small scale, which would be advisable only in case of very rough country, ob- struction, or the need of a very precise survey. It should also be observed that in all this work pertaining to the computation of firing data, the angular measurement is much more precise than the accompanying linear measure- ment. The explanation is that an error of one or two meters in the location of a gun position is of no importance as com- pared with a small error in direction for a 10 kilometer range. 1. METHODS OF RUNNING TRAVERSES Direct Angle Traverse.—This method consists simply in measuring the angle at each station directly from a back- sight on the preceding station to the station ahead. If de- sired the angle may be doubled, tripled or repeated any num- ber of times. If the limb on the transit is graduated clock- wise the stations of the traverse should be occupied in counter- clockwise order, to simplify the reading of limb and vernier. Care must be taken not to read the exterior angle at a re- entrant angle, as Sta. C, in Fig. I. In Fig. I let A represent a triangulation station and D a directing gun whose position is to be determined. The tran- sit is set up at A, the angle to AB from some reference line of known Y-azimuth is read, and the distance to station B is determined by reading a stadia rod or by tape measurement. ! 162 ORIENTATION FOR HEAVY (COAST) ARTILLERY O Gwri Pºsſfor " º A A 77-ſarau/zhon Staffor Fig. I.-DIRECT ANGLE TRAVERSE The transit is taken to B and the interior angle between the courses AB and BC is measured and the distance to C is determined. C is occupied in a similar manner. To check the work the traverse is made to close by returning to A by another route which in this case includes one additional station, E. Method of procedure at each station. (1) Set up and level transit over stake marking the station. (2) Using the upper motion, clamp vernier A at 0°. Wernier A is under the eyepiece end when the telescope is in the normal position. Vernier B is used only as a check. (3) Direct telescope on preceding station with lower motion and clamp. (This is called backsighting.) At the first station read the direct angle between the line to the for- ward station and a line whose Y-azimuth is known in order to have the data for computing the Y-azimuth of the courses of the traverse. - (4) If using stadia measurement read and record the intercept on the rod and the corresponding vertical angle. (5) Loosen upper motion and direct telescope on forward station with upper slow motion and clamp. (Foresighting.) (6) Read and record vernier A. In very accurate work the angle should be measured by repetition, that is, the angle should be added on the limb several times and the mean of the readings used. TRANSIT TRAVERSE 163 (7) Read and record stadia intercept and vertical angle to the forward station. Deflection Angle Traverse.—This method is being used almost exclusively for artillery work in France at the present time and particular emphasis will be placed on it in this Chapter. By taking certain precautions it can be made very precise. Instead of measuring the interior angles, as in the direct angle method, the angle between any course extended and the next course is determined. The same courses shown in Fig. 1 will be used for an illustration of this method and also for the two methods which follow. When using this method the stations should be occupied in the same order, clockwise or counter-clockwise, as the numbering of the graduations of the 0°–360° circle on the limb of the tran- sit. This simplifies reading the angle on the limb. Read always on the 0°–360° circle, never on those graduated by quadrants. In the field notes record always and only the figures actually read, indicating whether the angle is Right or Left. All reductions and computations should be made later and not as a part of the field notes, which should never be erased or changed in any way after leaving the station at which they were taken. • Deflection angles may be read either by the simple or double reverse method. Simple deflection angles are read but once with the instrument, being quickly read but liable to error both from mistakes in reading and poor adjustment of transit. Double reverse reading tends to prevent personal errors, compensates for poor instrument adjustment, and gives a more precise value because of the repetition of measure- ment. The latter is the standard method for precise traverse. Simple deflection angles—Procedure at each station: (1) Set up and level transit over station. (2) Using upper motion, clamp vernier A at 0°. (3) With telescope normal, using lower motion, clamp the transit with the line of sight on the preceding station. At the first station read the deflection angle between the forward station and the orientation line. (4) Loosen the upper motion, plunge the telescope, direct it toward the station ahead using upper motion only, read and record vernier A. This completes the angle read- ing; loosen the lower motion, leaving the upper motion clamped. (5) If using stadia measurement, with telescope normal, read rod intercept and the vertical angle and record. 164 ORIENTATION FOR HEAVY (COAST) ARTILLERY Orlantoſh Y, rtantof ion • * i.' rú Fig. II.-DEFLECTION ANGLE TRAVERSE Double Reverse deflection angles—Procedure at each station: (1) Set up and level transit over station. (2) Using upper motion, clamp vernier A at 0°. (3) With telescope normal, using lower motion, clamp the transit with the line of sight on the preceding station. At the first station read the deflection angle between the forward station and the orientation line. (4) Loosen the upper motion, plunge the telescope, direct it toward the forward station, using upper motion only, read and record vernier A. (5) Leaving upper motion clamped, loosen lower motion, and direct telescope (still inverted) toward the preceding station, using lower motion only, and clamp. (6) Loosen the upper motion, plunge telescope (back to normal) and direct it toward the forward station, using upper motion only, read and record vernier A. - This completes the angle reading, giving two values, which should check closely. Any even number of repeti- tions, as four, six, etc., may be obtained by repeating the above cycle of operations. Length and slope of courses are then measured as described for the Simple Deflection Angle Traverse. Azimuth Traverse.—In this method the transit is oriented at each station and the angles made by the transit lines with true TRANSIT TRAVERSE 165 north are measured. A traverse can be run by measuring Y-azimuth, the only difference being that the angles are meas- ured from Lambert north instead of true north. The angles are not measured with the same precision and certainty as when using the double reverse method, but the field work is more quickly and easily done, and can be roughly checked at any time by means of the compass. The method is mainly used on short traverses where time is a greater consideration than precision. The first and closing stations may have refer- ence points of known Y-azimuth, or orientation may be obtained from solar or Polaris observations. Procedure at each station: (1) Set up and level transit over station. (2) Lower motion should be loose; upper motion clamped with vernier A reading the same as when looking forward from the preceding station. Fig. III.-AZIMUTH TRAVERSE (3) With telescope inverted, direct it to preceding sta- tion, using lower motion. This orients the limb; that is, with telescope normal, vernier A gives azimuth for any point- 166 ORIENTATION FOR HEAVY (COAST) ARTILLERY ing of the telescope. The instrument may be oriented at the first station of a traverse by setting on vernier A the Y-azimuth of any line from the first station to a given point and with the lower motion direct the inverted telescope on the given point, then clamp the lower motion. (4) Loosen upper motion, plunge telescope back to nor- mal, direct it to forward station using upper motion and read and record vernier A. This reading is the azimuth of the course, looking forward. Read always and only on 0°–360° circle on the limb. - COMPARISON OF METHODS OF ANGLE MEASUREMENT ADVANTAGES DISADVANTAGES DIRECT | 1. Stations may be occupied in 1. Liability of error in reading ANGLES any order. exterior instead of interior 2. Error in one angle measure- angle at a reentrant angle. ment does not affect others. |2. Angle as read cannot be used 3. Must be used when telescope directly in computing Y-azi- cannot be plunged. muth of course. 4. Probably the most simple 3. Lack of adjustment of transit method for those not well ac-l causes errors. quainted with transit. SIMPLE | 1 and 2. Same as preceding. 1. Cannot be used on telescopes DEFLECTION 3. Computation of Y-azimuth too long to be plunged. ANGLES more simple than with direct|2. Practically all errors of ad- angles, as the angle read justment affect results. actually measures the change in direction. 4. By reading on 0–360° circle, | R. and L. designations are unnecessary. DOUBLE | 1, 2, 3 and 4. Same as preceding. 1. Cannot be used on telescopes REVERSE |5. Eliminates practically all the too long to be plunged. DEFLECTION errors due to lack of adjust- 2. Manipulation somewhat con- ANGLES ment of transit. . fusing to those not familiar 6. Repetition gives both a check with transit. and added precision. - AZIMUTH | 1. Reading gives azimuth, direct.|1. Stations must be occupied in ANGLEs 2. Notes and computations much order. simplified. - 2. Angles cannot easily be read 3. Compass reading may be used by repetition. to check azimuth of line. 3. Setting of plates must be checked before reading any angle. 4. Errors in one angle affects all work which follows. 5. Errors of adjustment of transit affect results. BEARINGs | 1. Field work quickly and easily 1. Results liable to have great done under adverse conditions. 2. May usually be done with disabled transit. errors, being neither consistent nor dependable. –ºf– TRANSIT TRAVERSE 167 Before running a traverse give careful consideration to the necessary precision of the results required, study the terrain and select the method best suited. Give due con- sideration to both time and precision, which will usually be the controlling factors in selection. What is gained in accu- racy will be lost in time and vice versa. The terrain will usually determine whether the distances will be measured by tape or stadia. If time is available and the ground is not particularly rough the tape should be used, but if speed is essential or the terrain is very hilly the stadia is preferable. 2. FoEMs FoR FIELD NOTES It is a universally accepted principle that field work is usually of no value unless all the various readings and other data are carefully and systematically recorded according to some suitable form, exactly as they are read from the instru- ments. The question of the particular form is of much less importance than the keeping of it. Those forms here given are considered suitable for the work under discussion, but when the method is changed the recorder should give con- siderable thought to devising suitable changes to fit the new conditions. A sketch showing the approximate length and di- rection of each course, and their relations to any reference points and lines, will be found helpful in clearing up any uncertainty in the notes or in the manner in which readings were taken. “Full and complete descriptions of all road crossings or intersections, kilometer posts, boundary stones or other permanent monuments should be made in the notes as the line progresses; in fact one should endeavor to place his tra- verse so that each line run may constitute a permanent record not only in the notes but upon the ground as well. To this end all stations wherever possible should be on hubs securely placed, marks on stones or nails in roots of trees. Any por- tion of a line run may be very useful in some future work and save valuable time in retracing, as well as avoid a multiplicity of astronomic observations which are generally more or less tedious on account of atmospheric conditions. “Above all, keep notes and descriptions in a legible and con- cise manner so that they may be readily interpreted by any other field party, and, what is equally important, so that the computer will not be at sea in seeing at a glance what has really been done. A neat sketch, supplemented by a word picture is the best possible medium for conveying information of this type.” FIELD NOTES-DIRECT ANGLE TRAVERSE e Horizontal STADIA Rod READINGS 100 Times Sta. Line Angle Vertical Intercept REMARKS (Vernier “A”) Angle - +0.30 m. Upper Middle Lower - A A—AT O° To A sta. T. A A—B 81° 10' — 19 15’ 3.31 1.91 0. 50 281.3 |281.55 =tape measure Mean — 19 15' 281.6 m. B B-A 0° +1° 15' 2.916 1. 52 0.10 281.9 B B–C 83° 51’ +3° 0' 2.02 1.26 0. 50 152.3 Sta. B =stake-Hinail at S. end of bridge Mean +3° 1' 152. 4 m. C C—B 0° –3° 2' 2. 522 1.77 1.00 152.5 Sta. C =stake-Hinail at lone oak, near C C–D 209° 19' +0° 46' 1.905 1.08 0.25 165.8 creek Sta. =stake, point or location over which transit is placed. Line =line along which telescope is directed. Horizontal Angle =reading of vernier “A.” Vertical Angle =reading on the vertical circle when middle horizontal crosswire of telescope cuts stadia \rod at same reading as height of telescope above top of station stake. Stadia Rod Readings=readings of horizontal crosswire intersection on stadia rod held on station indicated. # w 100 ×iº. +0.30 m. = total rod intercept, checked by middle wire, multiplied by 100, and instrument constant added, giving slope length OI (3OUli SE. Remarks=any pertinent data not noted elsewhere. ź FIELD NOTES-SIMPLE DEFLECTION ANGLE TRAVERSE Def V I STADIA ROD READINGS º Times - & ~ : Avº ( ; A 27 eflection ertica ntercept REMARKS Sta. Line Vernier “A Angle Angle +0.30 m. e Upper | Middle | Lower A A—AT 0° 0' To A Sta. T A A—B 335° 49' 24° 11'L — 19 15' 3.31 1.91 0. 50 281.3 281.55 = tape measure Mean — 19 15' 281.6 m. B B—A 0° 0' +1 15' 2.916 || 1 , 52 (). 10 281.9 B B–C 26.3° 51’ 96° 09/L +3° 0' 2.02 1.26 0. 50 152.3 sº ºstake-ºnal at S. end of }ridge Mean +3° 1' 152.4 m. C C–B 0° 0' –3° 2' 2. 522 | 1.77 1.00 152.5 |Sta. C =stake-Hinail at lone oak, near creek C C–D 29° 19' 29° 19'R. +0° 46' 1.905 1.08 0.25 165.8 Vernier A =reading of “A” vernier on 0°–360° graduations, horizontal limb. Deflection Angle=angle from preceding course produced, to the forward course. Value and direction both deduced from Vernier “A” readin gs, knowing direction of graduation of horizontal limb and remembering that deflection angle is always less than 180°. an essential part of field notes, but included here to show how it is obtained from vernier “A” readings. Other columns are same as form for Direct Angle Traverse. Not Ž FIELD NOTES-DOUBLE REVERSE DEFLECTION ANGLE TRAVERSE © Mean STADIA Rod READINGs 100 Times Sta. Line Vernier “A”. Differences | Deflection | Vertical Tape Intercept REMARKS Angle Angle Measure +0.30 m. Upper | Middle | Lower A A–AT | 247° 14' s To A Sta. T A A—B 223° 03' 24° 11’ — 19 15' | 281.55 m. 3.31 1.91 0. 50 | 281.3 281.55 =tape meas. A | A–B | 198° 52' 24° 11’ | 24° 11’L | – 19 15' - 281.6 m. B B-A 113° 41' +1° 15' 2.916 1. 52 0, 10 || 281.9 - Sta. B = stake-Hnail B B–C 17° 33’ 96° 08' +3° 0' | 152.00 m. 2.02 1.26 || 0 , 50 | 152.3 at S. end of bridge B B–C | 28.1° 23' | 96° 10' | 96° 09'L | +3° 1' 152.4 m. C C–B 312° 04' –3° 2' 2. 522 1.77 1.00 152.5 Sta. C=stake-Hrail at lone oak, near C C–D 341 ° 24′ 29° 20' +0° 46' | 165.75 m. 1.905 1.08 0.25 | 165.8 creek C C–D 10° 42’ 29° 18' 29° 19'R. Vernier “A” =readings of “A” vernier on 0°–360° graduations, horizontal limb. The initial setting for the backsight is not 0°, but the upper motion is clamped at any position, the telescope directed at the backsight using lower motion, and vernier “A” read and recorded. Measuring the angle then proceeds as previously described. Differences = difference between successive readings of vernier “A.” Each difference gives one value of the deflection angle, and its direc- tion; and they should check closely, which guards against errors of reading, etc. Limb of transit assumed to be graduated clockwise. Mean Deflection Angle=the mean of the Differences column, giving a more precise value than any one difference and compensating for the usual errors of transit adjustment. The repetition may be carried along to four or six times for greater precision, if desired. NoTE.—If the accuracy desired requires that the angles be measured by the double reverse method all distances should be taped to maintain the same degree of precision between the lengths and directions of the courses. § FIELD NOTES-AZIMUTH TRAVERSE STADIA Rod READINGs 100 Times Sta Line Azimuth Vertical Intercept REMARKS e (Vernier “A”) Angle +0.30 m. Upper Middle Lower A AT—A 316° 47' Azimuth from A sta. T = 316° 47' A A—B 292° 36' — 19 15' 3.31 1.91 0. 50 281.3 281.55 =tape measure Mean — 19 15’ 281.6 m. B B—A +1° 15' 2.916 1.52 0.10 281.9 B B–C 196° 27' +3° 0' 2.02 1.26 0. 50 152.3 Sta. B =stake-Hnail at S. end of bridge Mean +3° 1' 152.4 m. C C–B +3° 2' 2. 522 1.77 1.00 152.5 Sta. C=stake-Hnail at lone oak, near C C–D 225° 46' +0° 46' 1.905 1.08 0.25 165.8 creek Mean Azimuth = angle from true north, measured clockwise, to each course in its forward direction. Azimuth of line from sta. T to sta. A would have been previously determined as 316° 47'. 'Vernier “A” is set to this reading, telescope plunged and set on sta. T, orienting the transit. Other columns same as preceding forms. Sighting to B, telescope normal, then gives azimuth of line A-B. s 172 ORIENTATION FOR HEAVY (COAST) ARTILLERY 3. CoMPUTATIONS Having the complete field notes and field sketch of a transit traverse, the desired information—usually consisting of the coordinates of the gun position and Y-azimuth of a reference line from it—may be computed at any time. Unlike the field work, which would never be done twice exactly alike, the computation should give identical results by all computers, using the same field notes. Field work is then a matter of precision while computations are either accurate or inaccurate, the latter being of no value. It is desirable to keep this dis- tinction in mind, because no computation may be used until checked, and checking is impossible unless each computer is accurate. For this reason all computations are made with logarithms of not less than five places, and care in the work will usually give checked results more quickly than any attempt at speed. The successive steps in the computation of a traverse, of which the previously given field notes are a part, will be shown in detail in the remainder of this chapter. The computations are given on Fig. V, which represents a typical computation form suitable for this work. The detailed explanation of this form is given in the subhead, “computation of coordinates.” Adjustment of Angular Error.—The sum of all the interior angles of any irregular closed figure, as a closed traverse, is found by multiplying the number of sides, less two, by two right angles (180°). This method is used to check the angles of a closed, Direct Angle Traverse. For example, Fig. I shows a closed traverse of five sides. The sum of the interior angles should be (5–2) times 180° = 540°. If the sum is approximately 540° the field work is probably free from angular errors, the difference between the actual sum and 540° being a measure of the precision of the angle measurements. This difference should usually be apportioned to each angle equally. Thus, if the sum actually were 540° 10', each angle should be reduced by 2'. The reason for this is not that each angle was probably read 2' too small, but that some one angle may be 10' in error, or two angles may each be 5' in error, and in the absence of any definite knowledge of the error the best adjustment will be to apply the same correction to each angle. Occasionally, Some particular angle may be known to be liable to error, justifying the placing of all or a large part of the adjustment at this angle; but usually the TRANSIT TRAVERSE 173 uniform adjustment is preferable. If the adjustment is more than 2' per angle additional field work to reduce the error is necessary. For precise traverses the adjustment should be well within 1' per angle. Note that no adjustment is made of any angle measured from a line of known Y-azimuth, and which is not one of those angles whose sum is checked against the theoretical value. The sum of the deflection angles of a closed deflection angle traverse should be 360° since the transit makes one complete revolution in a closed circuit. If the stations are occupied in clockwise order, deflection angles to the right will be plus, while those to the left will be negative, the signs being considered in computing the sum. The divergence of thus sum from 360° is the total angular error. This is appor- tioned equally to each angle. If the sum for a 5 course tra- verse were 359° 50', the error would be 10'. The adjustment would be 2' per angle, and it would be added to plus angles but subtracted from negative angles. - A traverse may not close on itself, but at a point of known coordinates on a line of known Y-azimuth, starting from some similar location. The algebraic sum of its deflection angles should equal the difference of Y-azimuth of the two known lines. The error is apportioned equally among the angles, as for a closed deflection angle traverse. For example, Fig. IV L.M. § N N A Tº §l  | \ friargv/affon & - § ſº §§ D 3% who/, *N !—s §§§ 2\! § § Z § & ~! § &// : § G GUAW sº Posſrow | *š. º / 3. º- fior sºsºs" 3. Fig. IV.-ANGULAR TRAVERSE shows a traverse of four courses, running from Station A on line AX to the gun position, G, and closing at Station B on line BY. Lines AX and BY and Stations A and B might belong to a triangulation system previously established. 174 ORIENTATION FOR HEAVY (COAST) ARTILLERY Sum of deflection angles is:– + 48° 10' – 97° 18' Y-azimuth of Line BY = 201° 08/ + 54° 16' — 27° 50' Y-azimuth of Line AX = 160° 20' + 63° 40' — 125° 08' Difference of Y-azimuth = 40° 48' + 166° 06' Sum = +166° 06’—125° 08' = +40° 58'. Errors in traverse angles equals difference of 40° 48' and 40° 58', or 10'. The correction, or adjustment, will be 2' per angle, subtracted from plus angles and added to negative angles. The corrected angles are indicated in parentheses on Fig. IV, and are those accepted and used for the computa- tion of Y-azimuth and coordinates. Computation of Y-azimuth.-In order to determine the coordinates of an unknown station by running a traverse to it from a station whose coordinates are known, it is necessary that the Y-azimuth of courses be accurately determined. This can be done if the Y-azimuth of any one of the courses is known. If the traverse starts from a triangulation station it is very likely that the Y-azimuth of some line through the sta- tion has previously been determined by one of the three accu- rate methods given in the Chapter on Meridian Determination. If this is the case it is only necessary to read the angle between the line of known Y-azimuth and the first course in order to be able to orient the traverse. If there are no lines at the initial station of the traverse whose Y-azimuth are known the Y-azi- muth of the first course will have to be determined by a solar or Polaris observation or by computing a Terrestrial Y-azimuth, otherwise the traverse will be worthless. Having the adjusted angles of a traverse and the Y-azimuth of any one course, the Y-azimuth of each course may be readily computed. While a line may have two Y-azimuths, differing by 180°, a traverse course is always assumed to point in the direction the traverse was run. In Fig. IV, the Y-azimuth of AX is assumed to have been previously established as 160° 20'. The Y-azimuth of each course would be computed as follows: Sta. A, Y-azimuth of course AX = 160° 20' Sta. A, direct angle right +48° 08' Sta. A, Y-azimuth of course AC = 208°28' Sta. C, deflection angle right = +54° 14' TRANSIT TRAVERSE 175 Sta. C, Y-azimuth of course CG = 262°42' Sta. G, deflection angle right = +63° 38' Sta. G, Y-azimuth of course GD = 326°20' Sta. D, deflection angle left = – 97° 20' Sta. D, Y-azimuth of course DB = 229°00' Sta. B, deflection angle left = — 27° 52' Sta. B, Y-azimuth of course BY = 201° 08' The final computed Y-azimuth of any series should check with its previously determined value, thus checking each of the intermediate computed values. Reduction to Horizontal.—Tape measurements are usually made so as actually to measure the horizontal projection of the slope distance covered. Trigonometrically computed dis- tances are always horizontal. Stadia measurements give slope distances, from which the horizontal and vertical projections are computed or obtained directly from stadia reduction tables. These reductions must be made, as illustrated by an example in connection with the explanation of these stadia reduction tables in the Chapter on Linear Measurements, be- fore the traverse can be plotted or computed. The horizontal projection is then used to compute the coordinates while the vertical projection is the increment of altitude of each course Computation of Coordinates.—Computations are made on a ruled form, illustrated by Fig. V, after the field measure- ments have been adjusted and entered in their proper col- umns, each column being explained as follows: Sta.-Indicates the position of the transit during all the measurements shown in the same horizontal space. Line.—Indicates the pointing of the telescope for all measurements on the same horizontal line on the field form or computation sheet. Deflection Angle.—In this column are placed the adjusted deflection angles. The angles shown are the same as given in the field notes, but they will not be the same if a correction is to be applied as explained in Adjustment of Angular Error. Y-azimuth, V.—This is the Y-azimuth of each course, in the forward direction, computed by applying the deflection angles in the preceding column to the Y-azimuth of the preceding course, explained in Computation of Y-azimuth, and Fig. IV. Vertical Angle.—In this column is entered the mean of the two values of the vertical angle along each course, copied from the field notes direct. 176 ORIENTATION FOR HEAVY (COAST) ARTILLERY asſig.AVAL JO NOILVLſmā WOO—’A ’6%, I (~~~~ ~ ~ Lopatº-ſoºglºſſ A0g/32 ff. --|./0£3,724}^0/ZZ}^{2222 _6ſ2 –_F./0/.../3„VO Z/3| = /2 *//Q//ºË 92 Z/£ +ș.Z9°/2ºa^/922- -- - - - ---- çZ 6/g-| 92Z/2+Z9/2;&-| gº????+/923-|6|233}| 20 ºſº//$ļķļºJ.ļ__ –-- - - - - ---- 4,9€ž62 | 709,86|| 67-y| | / Ģēõā| ±±goºgāÞ922/+|_8/£9 90/2| 29′24. */cº/c/c72 cº.22/3/gº * | ſºzzz 682292” –,fº?Z268€2wo- |999 tº | Zºtz |,99,2 +| .9ă,/g |79,69|| !/-7|| 7 zy //oo/A2a/º 3yº/sº º 7'^XSYØ/'6022 + | OGZO /£66082 g/+| 76924/46,9972/+(@) «/002, WyoŽMAÇ/*24%89247-609.6 99Z /92'&63+| ÇZg6 69Þ2 || 2ę 9/-* •«gggggºgº,99'+Þ292 92672Zºſ-fºg 98.8/ſº2 | 90°-62006 | 2704|,99€-|///e/Ø ¡¿|3;&/g, „gºſpºſº. ‘¿/sąyłaeº-C7º45'ſ º£89–37289 282680362+|_/º29 1666, „1499/-(75)Aſſºckſzº26/1#%ſ*$' 82°9'//--2/O/ £902 %76’ſ?//--(924fº/026/24- 'yº,2/2 vººd/ 'yoo99 "+69047 6/22Z/" -690976/??go- || ZZ39/| 899/|,9ť,0+ |,9ť,922 |/462 | 67-2| 2 •«øy ſo zozzzzzzz 9yaſs-2 zºsſ º9.97/-±969. gº8667/ ’9//--26/2 çç869&4,&222+ ©__ .……. #f7ſ/0&09 g9/'2O2− ºſz- ÉGZ8 ÉÉ9/662 + ºſo,? ſo pue£ €' +047/8 /ß/ž9/--0 Ç/6? /º/?20 - || 66/47 | fººg/ | /„£ + 1,2ă,96/|760,96 || 9–47|| 9 sºye závº, áyoffs-groſs | ZZºº/-O6#9 /866Źr(Oºg ſv-2090 29°6. „/O?+•→---- •aźńZZ '90/+ | 9/90 zºg O? 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If the course is measured with tape the horizontal projection has usually been measured and in which case the value may be entered directly in the following column. Horizontal Distance, D.—This is the horizontal projection of the slope length of each course, computed from the stadia measurement as explained in Reducation to Horizontal. It is helpful to note in the preceding column the amount deducted from the slope distance. This horizontal distance D is the distance used in all coordinate computations, or for plotting the traverse. Altitude Increments.--This is the vertical projection of the slope length of each course. When stadia measurements are used this Altitude Increment is obtained directly from reduction tables, as explained in Reduction to Horizontal. If tape measurements are used, the altitude increment = dis- tance D, multiplied by the tangent of the vertical angle of the course. The sign of the value obtained will be plus for an ascending course, and negative for a descending course. Care should be observed that the value obtained is placed in the column of the proper sign. This sign will be the same as the sign of the vertical angle. - Coordinate Computations.—Having the horizontal length, D, and the Y-azimuth, V, of each course, the difference of the X and Y coordinates of the beginning and end of each course is computed. The difference of X coordinates is called dx, and difference of Y coordinates is called dY. These differ- ences, called increments, are computed from the following relations: - dX=D sin W; dY = D cos V dX is the projection of the course on the X axis and dY is the projection on the Y axis, as shown in Fig. VI. V is the Y-azimuth; but the sine and cosine of Y-azimuths greater than 90° must be taken with the proper sign, and the angle actually looked up in the tables is in every case the smaller angle between the Y axis and the course in the forward direc- tion, as shown in Fig. VI. For example, for a course of Y- azimuth between 0° and 90° the Y-azimuth itself is used; if the Y-azimuth were 100°, the angle used in computing dx and dY would be 80°; if the Y-azimuth were 225°, 45° would be used, and if 320°, 40° would be used. 178 ORIENTATION FOR HEAVY (COAST) ARTILLERY L. N. * _- > 2. 2’ N / -d X | +d). +d Y | +dy 270. 90 X . \ — dx +d){ / – d Y | – d’Y / -d dy, ^ `-- _2^ ^ | 6 ião $53- > 9. Fig. VI.--COORDINATE INCREMENTS AND Fig. VII.-SIGNS OF INCREMENTS ANGLES OF COURSES WITH Y AXIS IN FOUR QUADRANTS The signs of the resulting values of dx and dY must be carefully observed. If d X extends toward the right it is positive, while to the left is negative. If d Y extends upward its sign is positive, while downward is negative. Another quick method of determining the signs is by the use of Fig. VII. For Y-azimuths between 0° and 90° both increments have plus signs; for Y-azimuths between 90° and 180° dx wil be + while d'Y is —, and so on. The method of making these computations is shown on Fig. V which shows that at Station A, course AB has a Y-azimuth of 292° 36' and a horizontal distance of 281.46 meters. In the first column under “X Coordinate Compu- tations” is placed the logs of the quantities. First is the log sin of the angle used, which is the smaller angle from 292° 36' to the Y axis. This is 67° 24′ which, for the quick reference, may be noted in small figures as shown. To the log sin 67° 24' is added the log D, which is 2.4494167. The sum of these logs is the log d) for the course. In the tables the corresponding distance d x is found to be 259.85, and its sign as determined by any of the rules just given is negative. 259.85 is therefore entered in the dx column headed —. The value of d'Y is similarly obtained, using log cos in place of log sin, the same angle, 67°24', being used. 4. ADJUSTMENT OF COORDINATES AND ALTITUDE Computations of the dx and dY increment of each course having been made and entered in their proper columns of the computation form illustrated by Fig. IV, the algebraic sum TRANSIT TRAVERSE 179 of the dx values of the courses between any two stations gives the difference of X coordinates of those stations. Simi- larly for the Y coordinates. Therefore, with a closed trav- erse, the initial and closing station being the same, the algebraic sum of the dN increments should be zero, and the same for the d'Y increments. That is, the sum of the + d x values should equal the sum of the – d.X values. Assuming the computations to be accurate, the difference of these totals, called the error of closure, is a measure of the precision of the field work. - Before using a traverse having errors of closure, some attempt must be made to correct or adjust the several meas- urements so as to eliminate these errors in field work. If the error of closure is large, the field notes and computations should be checked carefully for some misinterpretation of the notes, or mistake in computation, to make certain that the error is due to the field work. If the error proves to be in the field work, and is large, the only satisfactory procedure is to check the field work. If the error of closure is small it is compensated for by adjusting the computed value, so as to eliminate the error. Occasionally this adjustment may be applied to only one, or a few of the field measurements which are known to be faulty. Usually the more reasonable and satisfactory method is to assume the field work to have been done with uniform precision and adjust all the measurements. A standard and accepted method consists in apportioning to the d\, d\ and altitude increment of each course its part of the total error, in the proportion of the length of course to the total length of traverse. - This adjustment is more easily understood by referring to the computation on Fig. V. To find the correction that must be applied to each course multiply the total error of clo- sure by the length of the course and divide by the total length of all the courses. The error of closure of d x increments is indicated as +1.21 (linear unit is meter). To adjust the 2 course A — B, apply, 1145.07% 1.21 = 0.30 to the dN increment of the course. The sum of the +d), increments being the larger, all – d.X increments are to be increased, while +d)K values are decreased. To the – d.X increment of course A–B, which is 259.85, is added 0.30, making the adjusted increment 260.15. If each d x value is adjusted in this manner, the sum of the adjusted --d Y values will equal the sum of the adjusted 180 ORIENTATION FOR HEAVY (COAST) ARTILLERY —d X values. The d'Y increments are adjusted in the same manner. The method of distributing the error in the sum of the plus and minus increments of altitude is similar to that used in balancing the coordinate increments. The correction that must be applied to each increment is found by multiply- ing the total error by the length of the course and dividing by the total length of all the courses. If the traverse is not a closed circuit, but runs from one triangulation point to another the dN, dY and altitude incre- ments are adjusted by exactly the same method, so as to make the algebraic sums of the increments indicate the same dif- ference of coordinates and altitude between the initial and closing stations as are known actually to exist. As a traverse always starts from a triangulation station whose coordinates are known, the coordinates of any station on the traverse can be determined by adding algebraicly to the coordinates of the first station the dxs and dYs to the station whose coordinates are wanted. Example, in Fig. W the coordinates of the gun position are: X = 4000–260.15 – 43.20 – 118.95 = 3577.70 Y = 6000+ 108.77–145.44 – 115.28 =5848.05 The altitude of the gun position is found in a similar manner: Altitude = 500—6.18—H·7.99-H2.19 = 504.00 5. PLOTTING THE TRAVERSE The traverse may be plotted by several different methods, at various times during the course of the work, with varying degrees of precision, depending upon the use to which the plot will be put. - A rough and approximate sketch should be made at the time the field work is done, for the purpose of adding clearness to the notes and indicating the general direction and extent of the traverse. A plot to a small scale of the completed field notes should be made before computing the traverse, as an aid in making these computations and applying the adjustments. When the computations are adjusted and com- pleted, the final and official plot of the traverse is made, with care consistent with the results required. It may be made on the battle map direct, on the firing board, or on any other map used for location purposes. Occasionally, with a short traverse the plot may be made with scale and protractor, laying off the adjusted angles or Y-azimuths and horizontal distance, TRANSIT TRAVERSE 181 D, of each course. A more precise and preferable method is to plot each station by its coordinates as computed from the adjusted increments of the computation sheet. This requires the grid system to be drawn before plotting begins. Fig. VIII shows a plot of the computations on Fig. V. The coordinates of the initial station being known the coordi- nates of any other station are computed by applying to the coordinates of the initial station the algebraic sum of the increments of each course between the stations. Thus in the plot shown Station B is 260.15 m. to the left and 108.77 m. above Station A. Applying these values to the coordinates of Station A gives the coordinates of Station B, and similarly for the other stations. —w 6200. SS § § § ~\\ * * * * * *dź-269.5-l----------- ...& *A *> - N 6100 $ `s < g * s. Pé L T N GUN POSITION: T- § T- Aiº *— ...I.I.I.I.I.I.III+284T&I.I.FE- asºe r= - 5700 5OO 3500 3700 3000 3900 4OOO Fig. VIII.-PLOT OF TRAVERSE It is desirable to give the coordinates of each station on the plot. While it may also be convenient to indicate the Y-azimuth and length of each course, these figures should be enclosed in parentheses, or encircled, as they are slightly in error due to the adjustment corrections applied to the incre- ments in adjusting the traverse. - CHAPTER X INTERSECTION 1. REDUCTION TO CENTER AND SWING 2. U. S. METHOD OF INTERSECTION 3. FRENCH METHOD OF INTERSECTION 1. REDUCTION TO CENTER The method of determining the coordinates and distance to an unknown point has been explained under triangulation. It will be remembered that it was necessary to set up a transit at each end of a base line of known length and read the hori- Zontal angles to the unknown point. In France there are many points located over the entire battle area whose coordinates are known. The distance between any two of these known points can be determined and used as a base line. Setting up a transit at each end of the base line and measuring angles to an unknown point gives the necessary data for determining the coordinates of the unknown point. In many instances, how- ever, points whose coordinates are known are towers, trees, etc., and cannot be occupied. In such cases the transit is set up near the known point which cannot be occupied and angles measured to the unknown point and also to known points. Each angle read must now be reduced so that it will be the same as if the transit had been set up over the known station. For this reduction it is necessary to know: a. The angle measured at the instrument between the center of the signal and the first distant station to the right of it as viewed from the instrument. - b. The distance in meters from the instrument to the cen- ter of signal. c. The approximate distance from the signal occupied to the various signals sighted. As these distances are very large in comparison with the distance from the instrument to the signal they may be computed from the uncorrected angles, or measured from an accurate map where stations can be located closely. INTERSECTION 183 The formula for computing the Swing, in seconds, for any line may be put in the following simple form: Si a sin Y a sin Y In or = − Or o = −. d d sin 1" (sin o. = o sin 1" for very small angles) o: = angle of Swing. a = distance from off center station to signal. d = distance from signal to distant station. ºy = angle between signal and distant station. Fig. I.-REDUCTION OF CENTER 184 ORIENTATION FOR HEAVY (COAST) ARTILLERY Example: At a station S, four other stations, A, B, C and D, were sighted. (See Fig. I.) A round of the horizon was made, including a sight on the signal; the angles as noted below are from the field notes. Stations sighted Angles Reduction to Angles Reduced to Center Center Station A to B 45° 36' 30.00" + 4.91 45° 36' 34.91" Station B to C 40° 33' 14.00" — 0.46 40° 33' 13.54." Station C to D 97° 10' 16.00" — 15.92 97° 10' 00.08" Station D to A 176°40' 00.00" +11.47 176°40' 11.47" The angle as measured between center of signal and the first station to the right, station A, is 23° 07' 10", and distance from instrument to center of signal is 1.43 m. . The logarithms of distance, in meters, from station S to the other stations sighted, as computed with the anudjusted angles or measured from a good map, were found to be: Station S to A = 4.29846 Station S to B = 4.40804 Station S to C = 4.43266 Station S to D = 4.36725 The computation may be put in the following form: Stations A B C D Angle Signal to. . . . . . . . . . . 23° 07' 10" | 68° 43' 40" | 109° 16' 54"| 206° 27' 10" log 1.43 m. . . . . . . . . . . . . . . 0.15534 0.15534 0.15534 0.15534 colog sin 1". . . . . . . . . . . . . . 5.31443 5.31443 5.31443 5.31443 log sin angle. . . . . . . . . . . . . . 9,59400 9.96935 9.97493 9.64881 Colog distance sta. S to . . 5.70154 5.59196 5.56734 5.63275 Log corrections. . . . . . . . . . . +0.76531 +1.03.108 || --1.01.204 || –0.75133 Correction in sec. . . . . . . . . . +5.83" +10.74" +10.28" —5.64" It should be especially noted:— (a) That the sign for any correction is the same as that for the sine of the angle. The sign of any correction will therefore be positive from 0 to 180°, and negative from 180 to 360°. * (b) The correction for any angle will be the difference between the corrections for the two lines bounding it, always taking the lines in order of Y-azimuth. (c) The general rule is to change the sign of the first cor- rection, in order of Y-azimuth, and add algebraically to the second. The sum will give the correction in seconds to be applied to the angle. INTERSECTION 185 The corrections may be conveniently tabulated as below. Sides Angle Corrections Sum A and B ASB —5.83-H10.74 +4.91" Proof B and C BSC — 10.74-H 10.28 —0.46" +4.91 0.46 C and D CSD | – 10.28— 5.64 — 15.92" + 11.47 15.92 D and A DSA +5.64-H 5.83 | +11.47" + 16.38 = 16.38 If a line takes a plus correction for the side of one angle it will readily be seen that this same line will take the same minus correction for the adjoining angle. It is therefore well to check the work by seeing that the positive and negative cor- rections balance. - These corrections are then applied to their appropriate angles as will be noted in the “reduction to center” column above. - As the horizon was closed to 360° before reduction to center it should remain so after the corrections have been applied. This formula and method may be used also when a station is occupied and a point sighted where the signal and station mark bear a similar relation to each other as the instrument and signal does in this problem. This reduction is known as “swing” and is the correction necessary to change the point- ing from the signal or point sighted to the station mark. Whether the computed swing is to be added or subtracted from a given angle will be readily seen from the sketch showign the conditions which exist between the station occupied, the signal sighted and the station mark or center of station. 2. U. S. METHOD OF INTERSECTION On account of the extreme accuracy required in determining the coordinates of points to be used by the Heavy Artillery it is not sufficient simply to determine the coordinates of an unknown point by triangulation from a single base line. The work must be checked by determining the coordinates by a different method or by using another base line and computing them again by the same method. In this chapter the method of locating a point by inter- section from two base lines will be discussed. For con- venience the two connected base lines will be taken up although it will readily be seen that the method is applicable to two or more independent base lines. By using a plane table the 186 ORIENTATION FOR HEAVY (COAST) ARTILLERY unknown point can be located by intersection if the plane table is set up and accurately located at two or more stations that have previously been plotted. (See Chapter on “Plane Table.”). In this case the coordinates would have to be read from the map and unless the map is drawn to a very large scale, which would be impossible, the coordinates as scaled would be of no value except as a rough check on the mathematical determination that will now be given. as ſº - VIII V 95. º |\ LT * | / - ſº. A < Pr 8/ … CZ alº 80000 $ S § St § § Š s t Fig. II.-FIGURE FOR PROBLEM It is assumed that the unknown point H (see Fig. II) is visible from three stations, K, L, M, whose coordinates are known. With a transit the angles a, b, c and d are measured by occupying the three known stations. The length and Y-azimuth of “r” and “s” are calculated from the coordinates of K, L and M. Angle “e” = 180°– (a+b); “f” = 180°-c-H d) From the Law of Sines: dº - In triangle KLH. r sin b KH = —: S11) 62 INTERSECTION 187 In triangle LHM. In triangle KJH. Angle HKJ = Y-azimuth (VI) of r— Za. HJ = AXs = P(H sin HKJ; and JK = AY = KH cos HKJ. (1) In triangle HNM. Angle NMH = 180°–[Y-azimuth (V.) of s-- Zd HN = AXm = HMsinNMH, and NM = AYm = HMcosNMH. (2) Two sets of coordinates can now be obtained from equa- tions 1, 2: From equation (1) Xn = Xk-H AX, Yh = Y,+ AY, From equation (2) Xn = Xm – AXm Yh + Ym-H AYm - The arithmetic mean of the X and Y coordinates of the point H will be taken as the coordinates of H. Eacample: Given the coordinates of three points, K, L, M, as follows: R L M X = 110750 115500 118250 Y = 80500 - 82500 81750 . A transit is set at the three points and the following angles measured to a point, H. (See Fig. II.) - Angle a = 23° 34' 30" b = 128° 36' C = 89° 29' 8" d = 57° 31' 32" Required the coordinates of the point H. Chapter II deals with the computations of Y-azimuth and the distance between two points whose coordinates are known; therefore the computations to determine r, s, and Y-azimuth of KL and LM will not be given: r = 5154 meters; S = 2851 meters the Y-azimuth of KL = 67° 10'; the Y-azimuth of LM = 105° 15' 8". e = 180°–a–b f = 180°– c – d a = 23° 34' 30" C = 89° 29' 8" b = 128° 36' = 57° 31' 32" 152° 10' 30" 147° 0' 40" 179° 59' 60” 179° 59' 60" C = 27° 49' 30" f = 32° 59' 20" KH =! sin b MH =5 sin c sin e sin f log 5154 = 3.712144 log 2851 = 3.454997 log sin 128° 36' =9.892940 log sin 89°29' 8" = 9.999932 colog sin 27° 49' 30" = .330895 colog sin 32° 59' 20" = .264021 - log RH = 3.935979 - log MIH = 7.319000 188 -ORIENTATION FOR HEAVY (COAST) ARTILLERY ZJKH =Y-azimuth of KL– Za ZNMH = 180°–Y-azimuth of LM — Zd Wr = 67° 10' Ve = 105° 15' 8" - a = 23° 34' 30" d = 57° 31' 32" 43° 35' 30" = Z.JECH 162°46’40” 179° 59' 60” ZGLH = Y-azimuth LM — Zc 17° 13' 20" = Z NMH Ve = 105° 15' 8" C = 89° 29' 8" 15° 46' 0" = Z GLH In A JRH In A MNH A Xk = 5950.06 A Xm = 1550.27 log AXk =3774522 log = AXm =3.190407 log sin 43° 35' 30" =9.838543 log sin 17° 13' 20" =9.471407 log KH = 3.935979 log MH = 3.719000 log cos 43° 35' 30" =9.859902 log cos 17° 13' 20" =9.980078 log AY =3.795881 log AYm = 3.699078 AYK = 6250.00m AYm = 5000.24m X =X,+AX =110750 - - 5950.06 116700.06m Xh =Xm — AXm = 118250 - 1550.27 116699.73 2|233399.79 116699.90 Yh = Yk+ AYK = 80500 6250 86750.00 Yh =Ym + AYm =81750 5000.24 86750.24 2|173500.24 86750.12 (Adopted Coordinates of H) X = 116699.90 Y = 86750.12 3. FRENCH METHOD OF INTERSECTION Statement of the Problem.—Having sighted an unknown point from several points whose coordinates are known, to compute the coordinates of the unknown point. The method is to find an approximate point by a graphic plot, and then to compute the data required to construct a plot on a large scale around the approximate point. From this large scale plot the exact location of the point can be obtained. To Find the Approacimate Point.—On drawing paper divided into squares, plot the known points on a scale of 1:20000. With a protractor draw the lines representing the sights from each known station to the unknown station. The Y-azimuths of these sights may be found by astronomical observations or by determining a terrestrial Y-azimuth as explained in the INTERSECTION 189 Chapter on “Meridian Determination.” The coordinates of the intersection of the sights as read from the plot will be used as the coordinates of the approximate point. Compute the Y-azimuths of the lines joining the known stations to the approacimate point, using the coordinates at the approx- imate point as read from the map and the coordinates of the known station. Find the difference “do” of the computed Y-azimuths and the true Y-azimuths. Use the formula d()=.W – Woomputed, where W is the true Y-azimuth obtained by one on the methods mentioned above and “V computed” is the Y-azimuth com- puted from the coordinates of a known point and the coordi- nates of the approximate point. Compute the data necessary to construct a plot on a large scale around the approacimate point. This plot will be made up of the loci which should intersect at the true point, that is to say, the lines representing the sights made to the point. These lines may be drawn knowing; a. Their distance from the approximate point. b. Their direction. & The distance from the approximate point to the line which represents the sight is given by the formula: Q = D sin d0; where D represents the distance computed from coordinates from the approximate point to the station from which it has been sighted. If the angle d0 is very small q = D sin 1' (d0). e Let S = sensibility of the line = displacement of the line for a variation in d0 of one minute. then, S= D sin 1'; and q = Sq0. The direction of the line which represents the sight has already been obtained. It is the true y-azimuth of the sight. To construct a large scale plot (for example 1:100) around the approacimate point. Assume the approximate point at the origin of the axis of x and y, and draw the lines which represent the sights. The direction of the sights and the distances from the approximate points are known. Take q in the proper direction, noting that the line is to the right or left of the approximate point (viewed from the known station) according as the true Y-azimuth is larger or smaller than the computed Y-azimuth. As a rule the lines represent- ing the sights will not intersect exactly at a common point, but a small triangle of error will remain. In locating the true point take into account the sensibility 190 ORIENTATION FOR HEAVY (COAST) ARTILLERY of each line, S = q/d0 and also give less weight to a line from a station whose coordinates may be doubtful and at which the different values of Vo are inconsistent. After the true point is plotted, scale from the plot the differ- ence of coordinates from the approximate point and add these differences with the propersigns to the approximate coordinates. Note.—The plot is accurate, whatever may be the distance from the approximate point to the true point, if the formula q = D sin d0 is used. However, for differences of (d0) smaller than three grades, the formula q = D sin 1' d0 may be used. Eacample: 445000 %7 Kea, & / / N 3 / - - > Z — / _T 44/ e / ~e? LT 4. § AC §440000 R. § R. S. NS § Ti-kº 443 442 s Fig. III.-PLOT OF POINTS ON A 1:20,000 scALE F The point H has been sighted from three known stations, K, L and M. (See Pig. III.) - Station Coordinates Vo Reading on H X y L 29,010 441,344 31.1.181 g 96.775g M 32,423 442,474 297.457g 38.837g K 26,608 440,566 8.440g 31.480g Plot the points L, M, K, on coordinate paper to a scale of 1 to 20,000 and construct the approximate location of H. The coordinates of this point as scaled from the plot are found to be X approx. = 29,395 m. Y approx. =444,417 m. INTERSECTION 191 Using these coordinates and the coordinates of L, the length and Y-azimuth of LH, approximate, are calculated. LH approx. = 3098 m. Computed Y-azimuth of LH approx. = 7.9358 Vo-HReading = W 31.1.181+96.775 = 7.9568 V computed = 7.935 d0= 021g = 2\.1 S = D sin 1\ = 3098 sin 1\ = q=S d0=.5×2".1 = MH approx. =3598 m. V computed of MH =336.31& Vo-HReading = W 297,457+38.837 =336.294& V computed =336.319 .5 m. 1.0 m. -ms- d0= .025g = 2\.5 S = D sin 1 =3598 sin 1'= .56 m. q=S d0= .56×2.5 = 1.4 m. KH approx. = 4754 m. V computed =39.882& Vo-H Reading = W 8.440+31.480 = 39.920& V computed = 39.882 d0= .038g = 3\.8 S = D sin 1\ = 4754 sin 1\ = 0.7 m. q =S d0= 0.7×3.8 = 2.8 m. y 24/79/ox. !. / N N N sº / - `s / - - | N 2 77ve ſax -t/0 TSS-Ao/7/lay --27 Z | SQ V | > / G|| / Jazz/€ /:/00 Fig. IV.-LARGE SCALE PLOT 192 ORIENTATION FOR HEAVY (COAST) ARTILLERY In Fig. IV the origin is taken as the approximate point and the line L is drawn to the right of the origin since the true Y-azimuth is greater than the computed Y-azimuth. It is drawn at an angle of 7.9568 (Y-azimuth of sight from L) with the y axis and at a distance of q = 1.0 m from the origin. As the scale is 1 to 100 the distance on the plot will be 1.0 cm. In a similar manner the data is computed for the sights from K and M and the lines representing these sights are drawn on the plot. The lines instead of intersecting at a point form a small triangle of error ABC. In locating the point dotted lines are drawn parallel to the sights L, K, M inside of the triangle of error and at distances from them proportional to the sensitiveness, S, of the respective sights. The intersection of the dotted lines is taken as the true point. Measuring the distances of the true point from the x and y axis on the large scale plot the increments to be added algebraically to the coordinates of the approximate point are found to be dx= +1 and dy = -2.7 Approximate Point x =29395.0 y =444417.0 dx= +1.0 dy = —2.7 True Point X = 29396.0 m. Y = 444414.3 m. (XHAPTER XI RESECTION 1. TRIGONOMETRIC SOLUTION 2. U. S. METHOD 3. RELEVEMENT In case three or more points that can be seen from any given unknown point have been plotted on a plane table, the unknown point can be occupied and its position located on the plane table by Resection, as described in Chapter VI. Because of the small scale necessary in plane table work of this character and the errors inherent in small scale graphic solutions, the coor- dinates of a point as determined by plane table are not reliable closer than 10 or 20 meters. This is not sufficiently accurate for the heavy artillery, and in general the plane table can only be used to check results obtained by more accurate methods. If a transit is set up at the unknown point and the angles between lines to three or more known points are accurately measured, the position of the unknown point can be accurately computed, its accuracy depending on the care taken in measur- ing the angles, the accuracy of the coordinates of the known points, and the care used in the computations. This is called the “Three Point Problem,” or “Resection.” It is merely the reverse of Intersection. In Intersection, only two known points are necessary, but in Resection three are required, unless the true orientation is known. There are several methods of making this determination, but only the three mentioned at the beginning of this chapter will be considered here. All of these methods are based on the relations brought out under the heading “Graphic Solutions,” and illustrated in Fig. IX, at the end of Chapter VI. These relations are as follows: The angle measured at the unknown point between lines to two known points determines a circle passing through those three points (two known, one unknown). The angle between lines to the two known points is the same at any point on that circumference and is one-half the central angle subtended by the chord joining the two known points. If the plane table or transit is oriented, only two known points need be used; otherwise three are necessary, and more are often used. The unknown point is at the intersection of the circles drawn through two or more pairs of known points. 194 ORIENTATION FOR HEAVY (COAST) ARTILLERY The so-called “Trigonometric Solution” is easy to under- stand, but is rather long. The “U. S. Method” is more difficult to understand, but somewhat shorter, and in case the three point problem is to be solved frequently, it is the better method. Both of them are mathematical solutions. “Releve- ment” is a French method which combines the plane table graphic Solution and some features of the mathematical solu- tions, and is particularly adapted for use with quadrillage. In any case, if the unknown point is on a circle through the three known points, the problem is indeterminate, and if it is too close to that circle, the solution is not accurate. 1. TRIGONOMETRIC SOLUTION Given three visible known points, A, B and C (see Fig. I), and an unknown point, P, which is occupied with a transit, three possible cases may arise, viz.: 1. When the unknown point is inside the triangle formed by the three known points; 2, when it and the known point C are on the same side of the line AB; and 3, when they are on opposite sides. The fol- lowing solution is the same for all three cases: Case-// Case-/// Fig. I.-TRIGONOMETRIC SOLUTION 1. Plot the points A, B and C from their coordinates and estimate the position of P. Draw a circle through A, B and P. Draw the lines PA, PB, PC, AD and BD, D being the second intersection of PC with the circle. (See Fig. I.) Z DAB = Z DPB = or Z DAB = Z DPB = 3 As angles having their vertices in the circumference of a circle and subtending the same arc are equal. 2. In A ADB; AB, o, and 8 are known. Compute AD and BD by using law of sines. RESECTION 195 DA BD AB AB Sin 3 Sin & Sin ADB Sin (180–a–3) 3. In A ADC: Z CAD = Z BAC = a AC and AD are known. Compute ZACD using tangent formula: AC+AD tan J/3 (ZADC-H ZACD) AC–AD T tan J/3 (ZADC — ZACD) 4. In A ACP: AC, ZAPC and ZACP are known. Compute AP or CP using law of sines: AP CP AC Sin ACPTSin CAPT Sin 3 5. Compute the coordinates of P from A or C knowing AP Or PC. 6. Check by solving BDC and computing the coordinates of P from C or B. EXAMPLE OF A THREE-POINT PROBLEM SOLVED TRIGONOMETRICALLY 194, ooo 193, Ooo 192, O Oo 191, Ooo 19 C), C C C, 39 i., ooo 3ea, Ooo 383, oco 3 8 a., Coo Fig. II.-ILLUSTRATION OF EXAMPLE 196 ORIENTATION FOR HEAVY (COAST) ARTILLERY Given: Required A B C P X 381,121 384,045 383,115 y 191,618 193,392 192,110 ZAPC = 3 = 47° 3’.5 A BPC = 0 = 26° 17'.5 X y X y B =384,045 193,392 B=384,045 193,392 A=381,121 191,618 C=383,115 192,110 AK = 2,924 BIK = 1,774 - log BK = 3.248954 log AK = 3.465977 |. log tan BAK = 9.782977 Z BAK = 31° 14'44" g log AK = 3.465977 log cos BAK = 9.931942 log AB = 3.534035 AB = 3420. 07 X y C =383,115 192,110 A =381,121 191,618 AM = 1,994 CM = 492 log CM = 2.691965 log AM = 3.2997.25 log tan CAM = 9.392240 Z CAM = 13° 51' 36” log AM = 3.299725 log cos CAM = 9.987167 log AC = 3.312558 AC = 2053.80 ..º. In A ADC ZBAFC = 31° 14'44" Z CAM = 13° 51' 36" ZBAC = 1792.3' 08" o, = 269 17' 30" ZDAC = 43°40'38" 180° 00' 00" ADC-HDCA = 136°19'22" J% (ADC-HDCA) = 68 09'41" AD+-AC=4667.02 AD = 2613, 22 AC = 2053.80 AD —AC = 559.42 In A ADC - AD+AC tan 9/3 (ADC+DCA) | AD-AG-tan J. (ADCEDCA) CL = 930 BL = 1,282 log BL = 3. 107888 log CL = 2.968483 log cos CBL = 0. 139405 Z CBL = 35°57'30" log BL = 3. 107888 log cos CBL = 9.908187 log CB = 3. 199701 AB = 1583.80 In A ABD: ZADB = 180°– (a +3) Cy = 26° 17. 30" 6 = 47° 03' 30" Z ADB = 106° 39' 0" 180° 00' 00" AB = AD – BD sin ADB - sin 8 sin o. log AB = 3.534035 log sin ADB = 9.98.1399 3. 552636 log sin 6 = 9.864540 log AD = 3.417176 AD = 2613. 22 3. 552636 log sin o. = 9.646346 log BD = 3. 198982 BD = 1581. 18 In A BDC - Z ABL = 58° 45' 16" Z CBL = 350 57' 30" ZABC = 229.47° 46" 6 = 47° 03' 30" ZDBC = 69° 51' 16" 180° 00' 00" BDC+DCB = 110° 08' 44” J% (BDC+DCB) = 55° 04' 22" CB+BD = 3164.98 CB = 1583.80 BD = 1581. 18 CB – BD = 2.62 In A BDC CB+BD tan 3% (BDC+DCB) CBEED ~tan Já (BDCEDCB) RESECTION 197 log tan M. (ADC+DCA) = 0.397128 log tan 4 (BDC+DCB) = 0.155948 log (AD–AC) = 2.747738 log (CB – = 0.418301 3.144861 0. 574.249 log (AD+AC) = 3.669040 log (CB+BD) = 3.500236 log tan Vá (ADC–DCA) = 9.475821, log tan 3% (BDC —DCB) = 7.074013 }% (ADC–DCA) = 16° 39' 08" }% (BDC — DCB) = 0° 04'05" }% (ADC+ACD) = 68 09'41" % (BDC+DCB) = 55° 04' 22" ZACD = 84° 48'49" Z BCD = 55°00' 17" 180° 00' 00" 180°00' 00" ZACP = 95 11’ 11” Z BCP = 124 59' 43” In A ACP In A BCP ZACP = 95° 11’ 11” Z BCP = 124° 59'43" ZAPC (3) = 47° 03' 30" ZCPB (a) = 26°17'30" ZCAP = 37° 45' 19° Z CBP = 28°42'47" 180° 00' 00" 180° 00' 00" AC CP AP CB___CP BP sin 6 Tsin CAPTsin ACP sin of Tsin CBP sin BCP log AC = 3.312558 log CB = 3. 199701 log sin 6 = 9.864540 log sin o. = 9.646346 3.448018 3. 553355 log sin ACP = 9.998.218 log sin BCP = 9.913516 log AP = 3.446236 log BP = 3.466871 3.448018 3. 553355 log sin CAP = 9.786958 log sin CBP = 9.681624 log CP = 3.234976 (check) log CP = 3.234979 Coordinates of P from A Coordinates of P from C ZCAP = 37° 45' 19" Z CBL = 35°57'30" ZCAM = 13° 51' 36” ZCBP = 28°42'47" Z MAP = 23°53'43" ZPBL = 7° 14'43" - Ay = 1131.79 Ay =2906. 56 log Ay = 3.053762 log Ay = 3.463380 log sin MAP = 9.607526 log cos PBL = 9.996509 log AP = 3.446236 log BP = 3.466871 log cos MAP = 9.961102 log sin PBL = 9.100774 log Ax = 3.407338 log Ax = 2.567645 Ax = 2554.68 - Ax = 369. 53 X y X y A 381,121 191,618 B 384,045 193,392 A+ 2,554. 7 – 1,131.8 A — 369.5 — 2,906.6 P 383,675.7 190,486.2 P. 383,675.5 190,485.4 Coordinates of P & Mean Values x=383,675.6 y = 190,485.8 198 ORIENTATION FOR HEAVY (COAST) ARTILLERY 2. U. S. METHOD The trigonometric relations that exist between the different triangles have been reduced to certain formulas that can be used to solve the three point problem. The derivation of these formulas is given below, being taken from Artillery Notes No. 11. Standard computation forms have been designed to furnish a convenient record and to facilitate the work. On the following pages is an example of this method, the initial data being the same as that used in the example of the Trigonometric solution. A comparison of the two will show that the U. S. Method is somewhat shorter, but because of the complicated formulas, is difficult to remember. On the other hand the trigonometric solution can easily be worked out for any given problem. - From the final position of the unknown station P the Y-azimuths of the lines from P to the known points can be computed. They can also be found from the angles used in the computations and the Y-azimuths of the lines joining the known points. - Additional known points may be sighted and an extra check thus obtained on the solution. If the coordinates of P as obtained from two or more solutions based on different known points (when more than 3 points are used) differ only slightly, the mean value should be taken, but if they differ widely there is probably an error in the initial data of the computations. In case there is any doubt as to the accuracy of the coordinates of any of the known points, additional points should be sighted and the mean value determined. Where the lengths of the lines joining the known points vary widely a weighted mean should be used. - Fig. III.-PROOF OF FORMULAS RESECTION 199 Derivation of Formulas.- Let Angle CAP= q. Let G = b + q' {{ {{ CBP = q.' = 360°– o – 8– (ACP + BCP) “ Line AC =b =360°–ACB — (a+8) {{ « BC = 8, Note.—In third case the angle ACB is the exterior angle at C. It must always be considered as the angle inside the quadrilateral ACBP. sin 6 CP sin q _CP From the law of Sines, te = TT all CI T. sin 6 b SII) Cy 8, CP b sin d a sing,' a sin (G — p) a sin G cos? — a sin b cos G sin 3 T sin a sin a - sin o. Considering the second and last expression b sin q sin o. = a sin G sin 3 cos p – a cos G sin 8 sin (b Dividing by sin q b sin o. = a sin G sin 8 cot p – a cos G sin 8 b sin o-Ha cos G sin 3 a sin G sin 8 . . . COt G, . cot G (b sin o-Ha cos G sin 3) Multip lying by cot G cot G a sin G sin 8 - ſ b sin o. a cos G sin 8 } l cº a sin G sin st º G a sin G sin 6 - b sin o. I. cot q = COt G a sin 8 cos G+1 ſ In similar manner / a sin 3 l II. cot º' = cot G lbsin a cos G+1 ſ sinſ 180°– (q)+3)] AP Solving, cot q = Cot G From the law of Sines, in AAPC; º = Sin 6 b b sin [180°– © III. AP–ººl * * similarly, in ABPC; IV. BP=* sin (180°-(º-Fo) SII) Cy Eacample: This example is worked out with the above formulas and arranged according to a standard computation form. Given A { x=381,121 y = 191,618 B { x=384,045 y = 193,392 C [ x=383,115 M..........] ſ APC = 8 = 47° 3'.5 Obser ved { BPC = 0 = 26° 17.5 200 ORIENTATION FOR HEAVY (COAST) ARTILLERY To Find for point P X = y = Draw a figure representing the three points, lettered from left to right A, C, B, respectively, as seen from the point P, the position occupied. The side AC, letter b, and the side CB, letter a. The angles APC and CPB letter 8 and of respectively, and angles CAP and CBP letter q and q, respectively. Through P and C draw lines parallel to the X-axis, and through A and B lines parallel to the Y-axis. The intersection of the lines through C and B, letter K, through C and A, letter M.; through A and P, letter T; and through P and B, letter W. B | 3520OO Fig. IV.-ILLUSTRATION OF EXAMPLE Ye = 1921.10 Xe = 3 Ya = 191618 XA = 381.121 AM = 492 MC = 1.994 In A MAC; AM=492 Mº-º: MCA = ***. tan MC log AM = 2.691965 (—) log MC =3.299725 log tan MCA =9.392.240–10 MCA = 13° 51’.6 MAC = 76° 87.4 - AM sin MCA log AM = 2.691965 (—) log sin MCA =9.379405–10 log b =3.312560 b = 2053.8 Y, -193392 x = 384,045 Ye = 192.110 Xe = 383.115 BK = 1.282 CK = 930 In A KCB; CK=930 #-12sº tan KCB = **** an KC CK log BK =3.107888 (—) log CK=2.968483 log tan KCB = .139405 KCB = 54° 2'.5 IKBC = 35° 57.5 BK ** sin KCB log BK =3.107888 . (—) log sin KCB =9.908187–10 log a =3.199701 a = 1583.8 RESECTION 201 ZACB = 180°-EMCA +KCB or +ACB+KCB = 220° 10'.9 ZACB must always be taken inside quadrilateral ACBP. NoTE.—The proper signs must be determined from the figure. G =q-i-p' =360°–(3+a+ACB)=66°28'.1 — eat ſ b sin o. l I. cot q = cot G{#s ſ log b =3.312560 log sin a = 9.646346–10 log b sin o. = 2.958906 log a = 3.199701 log sin 3 =9.864539–10 log cos G =9.601251–10 log a sin 8 cos G = 2.665491 log b sin o. = 2.958906 (—) log a sin 3 cos G = 2.665491 b sin o. \ - los (; H = 2 Og a sin 3 cos G ſ 934.15 b sin o. - a sin 6 cos a = 1.9652 (+) 1.0000 ſ b sin o. \ =n= lasing cos a-Fl j =q 2.9652 log q = .472054 log cot G =9.638958–10 log cot q = .111012 II, cotº-cot G (Hºrs cot ºp' = cot b sino, cos G log a =3.199701 log sin 3 =9.864539–10 log a sin 8 = 3.064240 log b =3.312560 log sin o. =9.646346–10 log cos G =9.601251–10 log b sin of cos G = 2.560157 log a sin 8 = 3.064240 (—) log b sino, cos G = 2.560157 log { a sin 6 b sin of cos G a sin 3 b sin of cos G=3.1921 (+) 1.0000 } = .504083 ſ a sin 3 l / -*-*. -: = 4. 2 insii. 5t" j q' = 4.1921 log q' = .622432 log cot G =9.638958–10 log cot * = .261390 b 1 q = 37° 45'.3 tºº. 42'.8 - 9 — e 180°– (d.' III. AP=" tº [ ; fºre |IV. BP=tº [ ** +o)] 180°– (p+8) = ZACP =r 180°– (p’-Ho) = ZBCP =r' = 95° 117.2 = 124° 59'.7 log b =3.312560 log a =3.199701 log sin r =9.998.218–10 log sin r" =9.913391–10 colog sin 6 = . 135461 colog sin o. = .353654 log AP = 3.446239 log BP = 3.466746 AP = 2794.1 BP = 2920.2 In A APT \ In A WPB \ _ ſ 180°-EMAC==q, \ ſ 180°-i-KBC+q,' ZPAT* = { or-i-MAC+q, ſ T Z WBP+ = { or-i-KBC+q,' ſ S = 66° 67.3 S’ = 7° 14'.7 AT = AP cos S BW = BP COS S' log AP=3.446239 log cos S = 9.607521–10 log AT = 3.053760 AT = 1131.8 TP = AP Sin S log AP = 3.446239 log sin S = 9.961084–10 log TP=3.407323 TP = 2554.6 *Xa--TP=XP =381,121+2554.6 =383,675.6 log BP=3.466746 log cos S' =9.996519–10 log BW =3.463265 BW = 2905.8 PW = BP Sin S' log BP=3.466746 log sin S' =9.100758–10 log PW=2.567504' PW =369.4 *Xb==PW =XP =384,045–369.4 =383,675.6 1) ſ 202 ORIENTATION FOR HEAVY (COAST) ARTILLERY *Ya==AT = Y, - 191,618–1131.8 *Yi,4-BW = Y p = 193,392–2005.8 = 190,486.2 +. = 190,486.2 Mean Xp =383,675.6 Mean Yp = 190,486.2 *When + occurs in a formula the proper sign to use must be determined from the figure for each special case. 3. RELEVEMENT—FRENCH METHOD As in intersection, the French have developed a method of resection, called Relevement, which is a combination of the graphic plane table solutions and the accurate mathematical Solutions. It attains the accuracy of the latter, but requires less work, and is well adapted for use with quadrillage because it reduces the effect of errors in the coordinates of the known points. It permits any number of known points to be brought into the solution, thereby strengthening the result and attain- ing to some extent the accuracy of a least square adjustment. The description of relevement is necessarily long, but if it is clearly understood it can be used quite rapidly. When more than three known points are used it is shorter than either of the mathematical solutions. Field Work.-A transit is set up at the unknown point with its line of sight, when the verniers read zero (W, line), directed at one of the known points or at any random object. The telescope is directed at each of the known points in turn and the verniers are read. Each of these readings measures the angle between the line to the corresponding point and the V, line. Computations.—The known points are plotted on a small scale (say 1:20,000) and the unknown point is located graph- ically by means of the various transit readings. Its coor- dinates are scaled from the plot, but are only approximate. The point they represent is called the “approximate point.” From its coordinates and those of the known points the Y-azi- muths of the rays from it to the various known points are computed. From these approximate Y-azimuths and the cor- responding transit readings a mean value of the Y-azimuth, V, is deduced. From this and the transit readings the Y-azi- muths of the probable rays to the true point are computed. The vicinity of the approximate point is plotted on a large scale, showing these probable rays to the true point. They form a “Chapeau” of error. By changing V, slightly the chapeau is reversed or eliminated and the true point found. The detailed procedure, divided into nine steps is as follows: 1. Determine graphically the approacimate coordinates of the RESECTION - 203 unknown point. This is done by plotting the known stations from their coordinates on a sheet of coordinate paper, using a scale of 1 to 20,000 (1 mm. = 20 m.). The sheet should be divided into 5 cm. Squares representing 1000 m. squares on the ground. With a transit set up at the unknown point measure by repetition the angles between the lines to the known points. Using extreme care locate the unknown point on the map by one of the graphical solutions of the three point problem. Scale the distances of the unknown point determined graph- ically to the nearest grid lines and in this way determine its approximate coordinates. The approximate point thus ob- tained is called X. 2. Compute the approacimate orientation. The Vo of the transit at the unknown station is determined by one of the following methods. However, the orientation of any line through the unknown point may be determined, for if the orientation of one line is known the Y-azimuth of any line through the same point can be determined by measuring with the transit the angle between the two lines. (a) By compass. This is very inaccurate and should be used only in case of an emergency. (b) By computing the Y-azimuth of the line from the un- known point to the most distant known point. This will give a result sufficiently accurate for a computation by Releve- ment provided the known point is 1000 m. to 2000 m. distant. (c) By observation on the Sun or Polaris. Making an observation on Polaris is the most accurate method known for determining the Y-azimuth of a line, but on account of atmos- pheric conditions or for lack of time this method is often impracticable. Due to the inaccuracy of the methods em- ployed in making a solar observation the value of V, thus obtained may be in error from 1 to 3 minutes. (d) By observation on known terrestrial points. This method, which is explained below, is more accurate than the method involving a solar observation, provided the values of V, shown in the calculations agree closely. However, with inconsistent values of V, the Y-azimuth determined by solar observation should be used. A method of computing V, from a point whose coordinates are known is given in the chapter on “Meridian Determination,” and the method of computing an approximate V., from a point whose coordinates are only ap- proximately known will be found very similar to it. It is always possible to compute an approximate orientation 204 ORIENTATION FOR HEAVY (COAST) ARTILLERY by computing the Y-azimuths of the lines joining the approxi- mate point to several distant known points, using the formula Vo-V computed—Reading. A clear conception of the mean- ing of V, may be had if the transit is understood to be directed on some distant known point on the horizon with the vernier set at zero. With the lower limb clamped, the V, is the Y-azi- muth of the line of sight when the vernier reads zero. In other words it is the Y-azimuth of the zero line on the lower limb of the transit. V computed is the Y-azimuth of the lines connecting the approximate point to the known points, com- puted from their coordinates. This method of calculating a Y-azimuth is given under “Cartography of French Maps.” “Reading” refers to the reading of the vernier when the tele- | l § Š s Q5 -Q N--> ~J N C N \ 3- \ \ \, \ \, \ \ \, \ \ / \ |\ \ \ / \\\\\ / \ \ \ / \ \ \ \ / \ \ A \, \ / \ \ \ \ \ | \ \ \ \ \ | \ i l | | | | | | | ! i ! : | | | | | | l | | | | l | | | | | \ | | | | | \ | | | | | / ! \ / / ! / | / / / / / 09 / / / / T / / / / Aſ /X / / / \\ / / º// © @A / / ^{9 2’ O Fig. V.-DETERMINATION OF APPROXIMATE Wo RESECTION 205 scope is directed at a known point, or in other words it is the angle between the V, line and the line to the known point sighted on. (See Fig. V.) XO is the V, line. Suppose the telescope is directed to the point M, the reading on the vernier would then be the angle OXM, which, added to the Y-azimuth of V, would give the Y-azimuth of XM. Or, if the Y-azimuth of XM has been com- puted, by subtracting the value of the angle OXM (Reading) we obtain the Y-azimuth Vo. The Y-azimuth of V, may in this way be computed using each point separately. The dif- ferent values found will differ slightly and the mean of these values of Vo will be taken as the true value. The approximate determination of Wo from the approximate coordinates of the transit point is illustrated in the following example taken from a French Bulletin: The known points sighted, with their transit readings and coordinates are as follows: Point Reading a – Coordinates — y Cote = ( 50.399 44,875 461,187 Malmy = M 106.50g 49,989 464,141 Acacia = A 365.10 51,507 459,580 Berzieux = B 39.69g 48,688 462,438 The first step is to plot these points accurately on as large a scale as practicable. This has been done in Fig. V and the transit point located by a graphical method. Its coordinates as scaled from the diagram are x = 50,707, y = 463,785. These may be several meters in error, but can be used for an C M A B 44,875 49,989 51,507 48,688 50,707 50,707 50,707 50,707 AX —5,832 –718 —800 –2,019 461,187 464,141 459,580 462,438 463,785 463,785 463,785 463,785 Ay –2,598 +356 –4,205 — 1,347 Log Ax 3. 76582 2.85612 2.90309 3.30514 Log Ay 3.41464 2. 551.45 3. 62377 3. 12937 Log tan v 0.351.18 0.30467 9.27932 0.17577 V 73. 320g 70. 6969. 11 .969g 62. 545g V 273. 320g 329, 304% 188. 031 g 262.545& Reading 50.39% 106. 50g 365. 10g 39.69% Approx. Vo 222.930g 222.804& 222,931 g 222. 855g 206 ORIENTATION FOR HEAVY (COAST) ARTILLERY) Approx. Vo = V com – Reading Mean value of Approx. Vo =222.88% approximate determination of V, which is similar to the deter- mination in the method given in the chapter on “Meridian Determination,” when the coordinates of P were accurately known. The computations above: In this case, because the scaled coordinates of P have a large probable error, a corresponding error will appear in each value of V, that is based thereon, and it is not worth while to take a weighted mean. The arithmetic mean, 222.88%, is more reliable than any individual value, although it may be 20 minutes in error. - 3. Compute Y-azimuths of Limes to Known Points.-The Y-azimuths of the lines to the known points are found by the formula: V =Vo-H Reading XB = Wo-HReading to B =222.88+ 39.69 = 262.578 XC =Vo-HReading to C =222.88-|- 50.39 =273.27% XM =Vo-H Reading to M =222.88--106.50 =329.38% XA =Vo-HReading to A =222.88-|-365.10 = 187.98% (A Y-azimuth of 587.98% is the same as 587.98–400 = 187.98%.) 4. Compute Data Necessary to Plot Vicinity of Approacimate Point on a Scale of 1 to 100. In Fig. V the lines XB, XC, XM and XA are known as reverse sights if considered as being drawn to the unknown station. From plane table work, we know they would inter- sect at one point which would be the point sought, provided all coordinates and the orientation were accurate. This condition is not to be expected and instead a figure called a “chapeau" will be formed by the reverse sights, varying in size depending on the accuracy of work, being very small if the errors in the work are small. Using a scale of 1 to 20,000 (1 mm. = 20 m.) in plotting the points, the reverse sights may appear to inter- sect in a point on the map, which point, in reality, may be 10 to 20 meters distant from the actual location of the approx- imate point. By constructing a large scale map (1 to 100), the location of the point of intersection of the reverse rays can be determined within .1 or .2 of a meter. In drawing a map of this size it will be impossible to plot the known stations and only a small area around the approx- imate point can be shown. To construct this map it is neces- sary to know the following: (a) The distance “q” from the reverse sight to the approximate point. (b) The Y-azimuth of the reverse sight. RESECTION 207 (c) The position of the reverse sight with reference to the approximate point, that is, whether it passes to the right or left of the approximate point. * (a) The Distance “q.” This distance depends on the angle d0 between the line from the approximate point to the known station and the reverse sight, and the length of the reverse sight. (See Fig. VI.) S$ N. SS SS <3 § SS3- S N & SS *~ N. ^ N Qly SS < § N SS a/O $ Ş N S. | SS \ `N \ 9 \\ \ (ſ N \ C/?doeavs -º >~a _2^ _2^ d'O _2~ 2^ _2^T 2^ ~~ / _2~ 0 2^ * 0